The expression 14p - 28 factored using the GCF is

Answer:

Step-by-step explanation:

I'm not sure how correct I am about these questions, but this is what I got:

13.x=-9

14.x=8

15.x=-2

16.x=5

17.x=-1

18.x=1.5

Answer:

No

Step-by-step explanation:

A function can have only  output for each input.  The input 3 has two outputs 3 and 5.  

The input 4 has two outputs 4 and 6.

Answer:

A. 8/3

Step-by-step explanation:

Type each fraction into a calculator. (or use long division if you aren't allowed a calculator. I can't explain long division in a brainly comment there isn't enough flexibility)

8/3=2.666666

6/4=1.5

12/5=2.4

14/8=1.75

Answer:

A. 8/3

Step-by-step explanation:

1. Let x = 2.666667 - equation (1)

2. The repeating digit is 6.

3. Place the repeating digit to the left of the decimal point.

In this case, move the decimal point 1 place to the right by multiplying it by 10.

Thus,

(x = 2.666667) * 10

10x = 26.66667 - equation (2)

4. Subtract Eq.(1) from Eq.(2)

10x - x = 26.66667 - 2.666667

9x = 24

divide both sides by 9

x = 24/9 = 8/3

I Hope This Helped! :) <3

Brainliest?

Answer:

Total is 3

Step-by-step explanation:

AI-generated answer

Let's start by finding out how many marbles John had initially. We can do this by using the information given in the problem.

Let the original number of marbles be x.

John gave away 3/4 of his marbles, which means he has 1/4 of the original number of marbles left. We can express this as:

1/4 x = the number of marbles John has left

If we solve for x, we get:

4/1 * 1/4 x = 4/1 * the number of marbles John has left

x = 4 * the number of marbles John has left

Now we know that John had 4 times the number of marbles he has left.

Next, John receives another bag of marbles containing 2/4 (which is the same as 1/2) of the original number of marbles.

We can express this as:

1/2 x = the number of marbles in the new bag

To find the total number of marbles John has now, we can add the number of marbles he has left to the number of marbles in the new bag:

Total number of marbles = the number of marbles John has left + the number of marbles in the new bag

Total number of marbles = 1/4 x + 1/2 x

Total number of marbles = (1/4 + 1/2) x

Total number of marbles = (3/4) x

We know that x = 4 times the number of marbles John has left, so we can substitute this into the equation:

Total number of marbles = (3/4) * 4 * the number of marbles John has left

Total number of marbles = 3 * the number of marbles John has left

Therefore, the total number of marbles John has now is 3 times the number of marbles he has left.

Tell me in the commets if you didn't understand a word or something in the equation. :)

Step-by-step explanation:

12 - 6.78 = 5.22 gallons

so, there were still 5.22 gallons in the tank.

Answer:

30 - (x + 8)

Step-by-step explanation:

"Sum of a number and 8" = x + 8

The sum of a number and 8 subtracted from 30 can be expressed as n - 22.

One mathematical expression makes up a term. It might be a single variable (a letter), a single number (positive or negative), or a number of variables multiplied but never added or subtracted. Variables in certain words have a number in front of them. A coefficient is the number used before a phrase.

Given:

A phrase: The sum of a number and 8 subtracted from 30.

Let n be the number.

Then the sum of a number and 8 can be expressed as,

n + 8.

The expression subtracted from 30.

That means,

n + 8 - 30,

= n - 22

Therefore, the expression is n - 22.

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The οnly sοlutiοn is sinθ = 0, θ = kπ, where k is any integer.

Trigοnοmetric functiοns are mathematical functiοns that relate tο the angles and sides οf a right-angled triangle.  These functiοns can be used tο calculate the relatiοnships between the sides and angles οf a triangle.

1a) Using inverse tangent functiοn,

θ = tan^{-1}(-2/3) ≈ -0.93 + kπ οr 2.21 + kπ, where k is any integer.

1b) Using cοsine functiοn,

\(2cos^{2}\theta - 1 = 0\)

\(cos^{2}\theta= 1/2\)

cοsθ = ±√(1/2) = ±1/√2

Sο, θ = π/4 + kπ/2 οr 3π/4 + kπ/2, where k is any integer.

1c) Rearranging the equatiοn, we get

\(sin^{2}\theta - 6sin\theta- 7 = 0\)

Using the quadratic fοrmula,

sinθ = [6 ± √(36 + 28)]/2 = 3 ± √19

Since -1 ≤ sinθ ≤ 1, the οnly sοlutiοn is

sinθ = 3 - √19

\(θ = sin^{(-1)(3 - \sqrt{19})} \approx 0.47 + 2k\pi\) οr π - 0.47 + 2kπ, where k is any integer.

1d) Factοring οut sinθ frοm the equatiοn, we get

sinθ(cοsθ - 7) = 0

Sο, either sinθ = 0 οr cοsθ = 7. Since -1 ≤ sinθ, cοsθ ≤ 1, the οnly sοlutiοn is

cοsθ = 7 has nο real sοlutiοn, sο the οnly sοlutiοn is

sinθ = 0

θ = kπ, where k is any integer.

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a. Standard Score: -2.8, Percentile: 2.1%

b. Standard Score: -1.2, Percentile: 15.9%

c. Standard Score: 0.2, Percentile: 50.2%

The purpose of Lend-Lease was to provide military aid to countries fighting against the Axis powers during set  World War II.

The purpose of Lend-Lease was to provide military aid to countries fighting against the Axis powers during World War II. The program was enacted by the United States in 1941 and allowed the US to provide war materials to its allies without requiring repayment. It was a major factor in the Allied victory, as it allowed the US to supply its allies with much needed war material and resources. The US provided a variety of goods, including food, oil, weapons, and tanks. It also supplied the Soviet Union with millions of tons of military equipment and supplies. Lend-Lease was instrumental in helping the Allies win the war, as it allowed them to gain a huge advantage over the Axis powers by providing essential supplies and resources.

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Answer:

Blank space= 1.96

To solve this equation you: divide both sides of the equation into -5:

The value of all the given expression are as follow:

a. Absolute value of -3 / 2 is equal to 3 /2.

b. The value of 32^4 is equal to 1048576.

c. The value ( 32 )^ 1/4 power is equal to (2)^5/4.

d. Value of 4^2 is 16

As given in the question,

Simplification of the given expressions are :

a. The absolute value of ( -3 / 2 )is

| - 3 / 2 | = ( 3/2 )

b. The value of the expression 32^4  is:

32^4

= 32 × 32 × 32 × 32

=  1048576

c. The value of the given expression ( 32 ) ^ 1/4 :

( 32 ) ^ 1/4

= ( 2⁵) ^ 1/4

= 2^(5/4)

d. Value of 4^2 is

4^2

= 4 × 4

= 16

Therefore, the value of the given expression is given by :

a. Absolute value of -3 / 2 is equal to 3 /2.

b. The value of 32^4 is equal to 1048576.

c. The value ( 32 )^ 1/4 power is equal to (2)^5/4.

d. Value of 4^2 is 16

The complete question is:

What is the absolute value of -3/2 ?

what is the value of 32^4?

what is the value of 32 to the one - fourth power?

what is the value of 4^2?

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Answer:

-2

Step-by-step explanation:

9+n/4= -15

cross multiply

9+4-15=n

13-15=n

n=-2

Independent and dependent variables are interdependent.

Dependent Variable: The term "dependent variable" refers to the variable that is being measured or tested in an experiment.

The results of the participants' tests, for instance, would be the dependent variable in a study looking at how tutoring affects test scores because that is what is being measured.

If you keep in mind that the dependent variable depends on the independent variable, finding it can be simpler.

This isn't the same as an experiment's independent variable, which is a variable that can stand on its own. The dependent variable (test results), however, may alter depending on the independent variable (tutoring).

The unrelated factor

Because the experimenters are allowed to change the independent variable as necessary, it is called a "independent" variable.

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6x = 12

17 – x = 11

x ÷ 2 = 3

5 + x = 11

We are given –

In case of 1st equation –

\(\qquad\) \(\twoheadrightarrow\bf 6 \times x = 6 × 6 \)

\(\qquad\) \(\twoheadrightarrow\sf 6\times x = 12 \)

\(\qquad\) \(\purple{\twoheadrightarrow\bf L.H.S = R.H.S}\)

In case of 2nd equation –

\(\qquad\) \(\twoheadrightarrow\bf 17 – x = 11 \)

\(\qquad\) \(\twoheadrightarrow\sf 17-x = 17-6 \)

\(\qquad\) \(\twoheadrightarrow\sf 17-x = 11 \)

\(\qquad\) \(\purple{\twoheadrightarrow\bf L.H.S = R.H. S} \)

In case of 3rd equation –

\(\qquad\) \(\twoheadrightarrow\bf\dfrac{x }{2} = 3\)

\(\qquad\) \(\twoheadrightarrow\sf \dfrac{x}{2}=\cancel{ \dfrac{6}{2}}\)

\(\qquad\) \(\twoheadrightarrow\sf \dfrac{x} {2}=3\)

\(\qquad\) \(\purple{\twoheadrightarrow\bf L.H.S=R.H.S}\)

In case of 4th equation –

\(\qquad\) \(\twoheadrightarrow\bf \dfrac{19}{ 3} = x\)

\(\qquad\) \(\twoheadrightarrow\sf \cancel{\dfrac{19}{ 3} }= x\)

\(\qquad\) \(\twoheadrightarrow\sf 6.33= x\)

\(\qquad\) \(\purple{\twoheadrightarrow\bf L.H.S≠R.H.S}\)

In case of 5th equation –

\(\qquad\) \(\twoheadrightarrow\bf 5 + x = 11\)

\(\qquad\) \(\twoheadrightarrow\sf 5+ x = 6 +5 \)

\(\qquad\) \(\twoheadrightarrow\sf 5+x= 11\)

\(\qquad\) \(\purple{\twoheadrightarrow\bf L.H.S=R.H.S}\)

Answer:

Answer is derived according to the procedure of calculating LCM of any two numbers

Step-by-step explanation:

If you have any other questions

ask in comments

\(\boxed{\large{\bold{\textbf{\textsf{{\color{blue}{Answer}}}}}}:)}\)

\(x^2-y^2-1-2y \\\\x^2-(y^2+2y+1)\\\\x^2-(y+1)^2\\\\(x)^2-(y+1)^2\\\\(x+y+1)(x-y-1)\)

\(\\\\\)

\( y^2-1-x^2-2x\\\\y^2-(x^2+2x+1)\\\\y^2-(x+1)^2\\\\(y)^2-(x+1)^2\\\\(y+x+1)(y-x-1) \)

According to the question,

we have to find the LCM

Answer:

Step-by-step explanation:

a + b)^6 will have 7 terms so you want row 6 of the triangle 1 6 15 20 15 6 1

so (a + b)^6 = a^6 + 6a^(5)b + 15a^(4)b^2 + 20a^(3)b^3 + 15a^(2)b^4 + 6ab^5 + b^6

given a = d and b = -5y

∴ (d − 5y)^6 = d^6 + 6d^(5)(-5y) + 15d^(4)(-5y)^2 + 20d^(3)(-5y)^3 + 15d^(2)(-5y)^4 +

Answer:

all whole numbers

all whole-number multiples of 125

Step-by-step explanation:

The domain and the range of a function is the set of input and output values of the function.

Let the number of tickets be x, and the revenue be y.

So, the revenue function will be:

\(\mathbf{y = 125x}\)

The number of tickets cannot be less than 0.

So, the domain of the revenue function is:

\(\mathbf{Domain = [0,\infty)}\)

The above means that, the domain is the set of all whole numbers

Similarly, the revenue cannot be less than 0.

So, the range of the revenue function is:

\(\mathbf{Range = [0,\infty)}\)

The above means that, the range is also the set of all whole numbers (in multiples of 125)

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Answer:

slope = 7/5

y-int = -3

Step-by-step explanation:

this equation is in slope-intercept form. in thsi form, the slope will always be the coefficient of x, and the y-intercept will always be the last constant, or the "b" term (dont forget to include the negative!)

Answer:

B

Step-by-step explanation:

The open end is always going to be by the larger number.

Answer:

B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.

HAHAHA

Step-by-step explanation:

The final ten digits are 27, 81, 43, 29, 87, 61, 83, 49, 47, with the pattern repeating every ten steps.

Let us calculate the value of t3:

t1 = 3^3 = 27

t2 = (3^3)

^3 = 27^3 = 19,683

t3 = (27^3)

^3 = 19,683^3

Because exponentiation is a repeated multiplication, we can calculate the last two digits of t3 by dividing each intermediate result by 100 and taking the remainder.

For instance, the final two digits of 273 are:

(27 * 27) % 100 = 729 % 100 = 29

(27 * 29) % 100 = 783 % 100 = 83

(83 * 29) % 100 = 2427 % 100 = 27

Therefore, the last two digits of t3 = ((3^3)^3)^3 are 27.

To demonstrate that the last ten digits are the same for all k > 10, consider the pattern of the last two digits as we continue calculating tn:

t3 = 27

t4 = (3 * 27) % 100 = 81

t5 = (3 * 81) % 100 = 43

t6 = (3 * 43) % 100 = 29

t7 = (3 * 29) % 100 = 87

t8 = (3 * 87) % 100 = 61

t9 = (3 * 61) % 100 = 83

t10 = (3 * 83) % 100 = 49

t11 = (3 * 49) % 100 = 47

Every 10 steps, the last two digits repeat in a cycle. As a result, for all k > 10, the last ten digits of tk are the same. The final ten digits are 27, 81, 43, 29, 87, 61, 83, 49, 47, with the pattern repeating every ten steps.

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The binomial can be factored as\(20p^2(p + 1)\) by factoring out the common factor of\(20p^2\)from both terms.

An expression is a combination of numbers, symbols, and operators that represents a mathematical quantity or relationship. It can be a single number, a variable, or a combination of these with arithmetic, algebraic, or other mathematical operations.

To factor a binomial means to express it as the product of two or more simpler expressions. In this case, we have a binomial expression \(20p^3 + 20p^2\), which contains two terms that have a common factor of \(20p^2.\)

To factor out this common factor, we can use the distributive property of multiplication, which tells us that a(b+c) = ab + ac. Applying this property to the given expression, we can write:

\(20p^3 + 20p^2 = 20p^2(p + p)\)

Notice that we can factor out a p from the parentheses, giving:

\(20p^2(p + 1)\)

This is the factored form of the given binomial expression. It is simpler than the original expression because it contains only two factors, whereas the original expression had three terms.

Therefore, The binomial can be factored as\(20p^2(p + 1)\) by factoring out the common factor of\(20p^2\)from both terms.

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Answer:

0.6cm

Step-by-step explanation:

25 : 1

1 : 0.04

15 : 0.6

Answer to the question:

112 bags.

Step-by-step explanation:

\(one \: bag \: of \: rice \: = \frac{5}{8} \)

\(70 \div \frac{5}{8} = 112\)

So 112 bags that weight 5/8kg can be contained in a bag of 70kg.

Hope this helps!

Coordinate of C;

\(( \frac{(1 - 3)}{2} , \frac{(2 - 4)}{2} )\)

apply the formulae, replace the variables with the given values.

Slope;

\(m = \frac{(4 - 2)}{(3 - 1)} \)

again, apply the formulae, replace the variables with the given values.

calculate it urself, ive done enough

Answer:

Answers below in bold.

Step-by-step explanation:

Midpoint formula:

\((\frac{1+3}{2} , \frac{4+2}{2} )\)=

\((\frac{4}{2} , \frac{6}{2} )=\)

(2, 3)

Point C is on the point (2, 3)

Slope:

\(\frac{4-2}{3-1} =\)

\(\frac{2}{2}\)=

1

The slope is going at y=x+1

Answer:

  (fg)(x) = x^2 -2x -8

Step-by-step explanation:

(fg)(x) = f(x)·g(x) = (x +2)(x -4)

  = x(x -4) +2(x -4) = x^2 -4x +2x -8

  = x^2 -2x -8 . . . . matches the 3rd choice

Answer:

\(\displaystyle x_1=\frac{5+\sqrt{13}}{2}\approx4.3\text{ and } x_2=\frac{5+\sqrt{13}}{2}\approx0.7\)

Step-by-step explanation:

We are given:

\(x^2-5x+3=0\)

And we want to solve this via completing the square.

First, we will subtract 3 from both sides. This yields:

\(x^2-5x=-3\)

Next, we will factor out the leading coefficient from the left.

In this case, the leading coefficient is simply 1 so we can leave it as is.

Next, we want to add a constant that is half of the b coefficient squared.

In this case, b = -5.

Half of that is -5/2.

Squaring yields 25/4.

So, we will add 25/4 to both sides. Since our leading coefficient is 1, we don't need to multiply by anything when we add it on the right. Hence:

\(\displaystyle x^2-5x+\frac{25}{4}=-3+\frac{25}{4}\)

The left side constitutes a perfect square trinomial as shown:

\(\displaystyle (x)^2-2\Big(\frac{5}{2} \Big)(x)+\Big(\frac{5}{2}\Big)^2=-\frac{12}{4}+\frac{25}{4}\)

Factor and subtract:

\(\displaystyle \Big(x-\frac{5}{2}\Big)^2=\frac{13}{4}\)

Taking the square root of both sides gives:

\(\displaystyle x-\frac{5}{2}=\pm\frac{\sqrt{13}}{2}\)

Hence:

\(\displaystyle x=\frac{5}{2}\pm\frac{\sqrt{13}}{2}}=\frac{5\pm\sqrt{13}}{2}\)

Approximate:

\(\displaystyle x_1=\frac{5+\sqrt{13}}{2}\approx4.3\text{ and } x_2=\frac{5-\sqrt{13}}{2}\approx0.7\)

Answer:

(x-7)^2 + (y+3)^2 = 7

Step-by-step explanation:

The equation of a circle is

(x-h)^2 + (y-k)^2 = r^2  where (h,k) is the center and r is the radius

(x-7)^2 + (y- -3)^2 = (sqrt(7))^2

(x-7)^2 + (y+3)^2 = 7