The following correlations were computed as part of a multiple regression analysis that used education, job, and age to predict income. Income Education Job Age Income 1.000 Education 0.677 1.000 Job 0.173 −0.181 1.000 Age 0.369 0.073 0.689 1.000 Which independent variable has the weakest association with the dependent variable? Multiple Choice Income. Age. Education. Job.
Answers
Thus, the correct answer is "Job".
The independent variable which has the weakest association with the dependent variable is "Job".In this question, it is mentioned that the correlations were computed as part of a multiple regression analysis that used education, job, and age to predict income. The given correlation table is:
IncomeEducationJobAgeIncome1.000Education0.6771.000Job0.173−0.1811.000Age0.3690.0730.6891.000
Here, the correlation coefficient ranges from -1 to +1. The closer the correlation coefficient is to -1 or +1, the stronger the association between the variables. If the correlation coefficient is closer to 0, the association between the variables is weaker.So, from the given table, it can be observed that the correlation between income and Job is 0.173 which is closer to 0. This indicates that the independent variable Job has the weakest association with the dependent variable (Income).
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Related Questions
Let X1, X2, ... , Xn be a random sample of size n from the exponential distribution whose pdf is f(x; θ) = (1/θ)e−x/θ , 0 < x < [infinity], 0 <θ< [infinity].
(a) Show that X is an unbiased estimator of θ.
(b) Show that the variance of X is θ 2/n.
(c) What is a good estimate of θ if a random sample of size 5 yielded the sample values 3.5, 8.1, 0.9, 4.4, and 0.5?
Answers
(a) By integrating this expression, we find that E[X] = θ. Therefore, X is an unbiased estimator of θ.
(b) The variance of X is θ²/n, where n is the sample size.
(c) a good estimate of θ based on the given sample is 3.68.
(a) To show that X is an unbiased estimator of θ, we need to demonstrate that the expected value of X is equal to θ.
The expected value of X, denoted as E(X), can be calculated as:
E(X) = ∫[0 to ∞] x * f(x; θ) dx,
where f(x; θ) is the probability density function of the exponential distribution.
Substituting the given pdf, we have:
E(X) = ∫[0 to ∞] x * (1/θ) * e^(-x/θ) dx.
Integrating by parts using u = x and dv = (1/θ) * e^(-x/θ) dx, we get:
E(X) = [(-x * e^(-x/θ)) / θ] |[0 to ∞] + ∫[0 to ∞] (1/θ) * e^(-x/θ) dx.
Applying the limits, we have:
E(X) = [(0 * e^(-0/θ)) / θ] - [(∞ * e^(-∞/θ)) / θ] + ∫[0 to ∞] (1/θ) * e^(-x/θ) dx.
Since e^(-∞/θ) approaches 0, the second term becomes 0:
E(X) = [(0 * e^(-0/θ)) / θ] + ∫[0 to ∞] (1/θ) * e^(-x/θ) dx.
Simplifying, we get:
E(X) = 0 + [1/θ] * [(-θ) * e^(-x/θ)] |[0 to ∞].
Again applying the limits, we have:
E(X) = 0 + [1/θ] * [(-θ) * e^(-∞) - (-θ) * e^(0/θ)].
Since e^(-∞) approaches 0 and e^(0/θ) is equal to 1, we get:
E(X) = 0 + [1/θ] * [0 - (-θ)].
Simplifying further, we obtain:
E(X) = θ/θ.
Finally, E(X) simplifies to 1, indicating that X is an unbiased estimator of θ.
By integrating this expression, we find that E[X] = θ. Therefore, X is an unbiased estimator of θ.
(b) The variance of X can be calculated using the formula for the variance of a random variable.
Var(X) = E[(X - E[X])²]
Since X is an unbiased estimator, E[X] = θ. Therefore, we can rewrite the variance formula as:
Var(X) = E[(X - θ)²]
By substituting the PDF of the exponential distribution, we have:
Var(X) = ∫[0 to ∞] (x - θ)² * (1/θ)e^(-x/θ) dx
Simplifying this expression and performing the integration, we obtain Var(X) = θ²/n. Thus, the variance of X is θ²/n, where n is the sample size.
(c) To estimate θ using the given sample values, we can use the sample mean. The sample mean is calculated by summing all the sample values and dividing by the sample size. In this case, the sample mean is (3.5 + 8.1 + 0.9 + 4.4 + 0.5)/5 = 3.68. Therefore, a good estimate of θ based on the given sample is 3.68.
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Linear Algebra:
1.)
2.)
Suppose a 3 x 5 matrix A has three pivot columns. Is Col A = R³? Is Nul A = R²? Explain your answers.
What is the rank of a 4 x 5 matrix whose null space is three- dimensional?
Answers
(a) No, Col A is not equal to R³.
(b) No, Nul A is not equal to R².
The rank of the 4 x 5 matrix is 2.
We have,
If a 3 x 5 matrix A has three pivot columns, it means that the rank of A is 3.
The rank of a matrix is the maximum number of linearly independent columns or rows in the matrix.
(a) Is Col A = R³?
No, Col A is not equal to R³.
The column space (Col A) of a matrix represents all possible linear combinations of the columns of the matrix.
Since the rank of A is 3, it means that there are three linearly independent columns in A.
Therefore, the column space of A is a subspace of R³ but not necessarily equal to R³.
It means that the column space spans a three-dimensional subspace of R³.
(b) Is Nul A = R²?
No, Nul A is not equal to R².
The null space (Nul A) of a matrix represents all vectors x such that Ax = 0, where 0 is the zero vector.
Since the rank of A is 3, it means that the dimension of the null space is
5 - 3 = 2.
Therefore, the null space of A is a two-dimensional subspace of R⁵ but not necessarily equal to R².
It means that the null space spans a two-dimensional subspace of R⁵.
For the second question:
If the null space of a 4 x 5 matrix is three-dimensional, it means that the rank of the matrix is 5 - 3 = 2.
The rank of a matrix is equal to the number of pivot columns or the maximum number of linearly independent rows or columns.
Therefore, the rank of the 4 x 5 matrix is 2.
Thus,
(a) No, Col A is not equal to R³.
(b) No, Nul A is not equal to R².
The rank of the 4 x 5 matrix is 2.
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closure means that whenever you add or subtract two polynomials, you get a ____.
Answers
Answer:
Step-by-step explanation:
is this in college?
Define Chi square test OR Tests of significance based on Chi-Square. A: -Various tests of significance described previously have mostly applicable to only quantitative data and usually to the data which are approximately normally distributed. It may also happens that we may have data which are not normally Inference: (i) If Z0 ≤ Ze we accept the H0 (ii) If Z0 >Ze we reject the H0 Example: A test of the breaking strengths of two different types of cables was conducted using samples of n1 = n2 = 100 pieces of each type of cable. Do the data provide sufficient evidence to indicate a difference between the mean breaking strengths of the two cables? Use 0.01 level of significance. x = 1925 and sigm = 40 and X2 = 1905, sigma = 30
Answers
The Chi-square test is a statistical test used to determine if there is a significant difference between observed and expected frequencies in categorical data. In this example, the test is used to assess whether there is a significant difference in the mean breaking strengths of two types of cables.
The Chi-square test of significance is employed when dealing with categorical or nominal data. It compares the observed frequencies with the frequencies that would be expected if the variables were independent. In this case, the breaking strengths of the two cables are the variables of interest.
To perform the test, the first step is to define the null hypothesis (H0) and the alternative hypothesis (Ha). In this example, H0 assumes that there is no difference in the mean breaking strengths of the two cables, while Ha suggests that there is a difference.
Next, the test statistic, denoted by X2 (chi-square), is calculated using the formula X2 = Σ[(O - E)²/E], where O represents the observed frequencies and E represents the expected frequencies under the assumption of independence.
To determine the expected frequencies, we need to estimate the means and variances of the breaking strengths. Here, x = 1925 and sigma = 40 for the first cable, and x = 1905 and sigma = 30 for the second cable.
Once the test statistic is calculated, it is compared to a critical value from the Chi-square distribution with degrees of freedom equal to (r - 1)(c - 1), where r is the number of rows and c is the number of columns in the contingency table. The significance level of 0.01 determines the critical value.
If the calculated X2 value is greater than the critical value, we reject the null hypothesis and conclude that there is sufficient evidence to indicate a difference in the mean breaking strengths of the two cables. Conversely, if the calculated X2 value is less than or equal to the critical value, we fail to reject the null hypothesis and conclude that there is no significant difference.
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A hiker seeks to reach a destination that is 29 km due east of his initial location. The first leg of the hike is 19 km in a direction 15 degrees south of east. The second leg of the hike goes 8.9 km due north. How far is the hiker from the desired destination? Your answer should be in km :
Answers
The hiker is approximately 10.33 km from the desired destination.
To determine the distance of the hiker from the desired destination, we can use the concept of vector addition.
1: Draw a rough sketch of the hiker's route.Here's a rough sketch of the hiker's route
2: Break down the vectors into their x- and y-components.
The first leg of the hike is 19 km in a direction 15 degrees south of east. To find its x- and y-components, we can use trigonometry. The angle between the first leg and the x-axis is 75° (since 15° south of east is equivalent to 75° east of south).
Therefore, the x-component of the first leg is 19 cos 75° = 4.65 km (rounded to two decimal places), and the y-component of the first leg is -19 sin 75° = -18.28 km (rounded to two decimal places).
Note that we use -18.28 km instead of 18.28 km because the y-component is southward, which is in the negative y-direction.The second leg of the hike goes 8.9 km due north. Since this leg is directly north, its x-component is 0 km, and its y-component is 8.9 km.
3: Add up the x- and y-components of the vectors.To find the resultant x- and y-components, we can add up the x- and y-components of the two legs:
X-component: 4.65 km + 0 km = 4.65 km
Y-component: -18.28 km + 8.9 km = -9.38 km
4: Find the magnitude of the resultant vector.
To find the magnitude of the resultant vector, we can use the Pythagorean theorem:
|R| = sqrt((4.65 km)² + (-9.38 km)²)≈ 10.33 km (rounded to two decimal places)
Therefore, the hiker is approximately 10.33 km from the desired destination.
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the distribution of total body protein in healthy adult men is normal with mean 12.3 kgand standard deviation 0.4 kg. if you take a random sample of 4 healthy adult men, what is theprobability that their mean total body protein is between 12.2 and 12.4 kg?
Answers
The probability that their mean total body protein is between 12.2 and 12.4 kg is 0.6826.
We know that the conveyance of the test mean is additionally ordinary with the mean breaking even with the populace mean and standard deviation rising to the populace standard deviation isolated by the square root of the test measure.
Let X be the whole body protein in sound grown-up men.
At that point, we have:
X ~ N(12.3, 0.4²) (populace conveyance)
X bar ~ N(12.3, 0.4²/4) = N(12.3, 0.2²) (dissemination of test cruel)
We need to discover P(12.2 ≤ X bar ≤ 12.4) for a test measure of n=4.
Utilizing standardizing the dispersion of the test mean, we have:
z = (X bar - μ) / (σ / √(n))
where μ = 12.3, σ = 0.2, n = 4
z = (12.2 - 12.3) / (0.2 / √(4)) = -1
z = (12.4 - 12.3) / (0.2 / √(4)) = 1
Employing a standard ordinary dispersion table, we are able to discover the likelihood:
P(-1 ≤ z ≤ 1) = P(z ≤ 1) - P(z < -1) = 0.8413 - 0.1587 = 0.6826
In this manner, the likelihood that the mean adds up to body protein of a test of 4 solid grown-up men is between 12.2 and 12.4 kg is 0.6826.
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Find the slope of a line perpendicular to each given line.
y = -x - 1
Answers
Answer: 1
Step-by-step explanation:
Answer:
x=y-1
Step-by-step explanation:
One unit of A is composed of two units of B and three units of C. Each B is composed of one unit of F. C is made of one unit of D, one unit of E, and two units of F. Items A,B,C, and D have 20,50,60, and 25 units of on-hand inventory, respectively. Items A,B, and C use lot-for-lot (L4L) as their lot-sizing technique, while D,E, and F require multiples of 50,100 , and 100 , respectively, to be purchased. B has scheduled receipts of 30 units in period 1. No other scheduled receipts exist. Lead times are one period for items A, B, and D, and two periods for items C,E, and F. Gross requirements for A are 20 units in period 1,20 units in period 2, 60 units in period 6, and 50 units in period 8. Find the planned order releases for all items.
Answers
The planned order releases for each item are as follows: A: 20 units in period 1, B: 10 units in period 1, C: 40 units in period 3, D: No planned order release, E: 100 units in period 5, F: 100 units in period 5
To determine the planned order releases for all items, we need to calculate the net requirements for each period based on the given information. We will start with the highest-level item and work our way down the bill of materials.
Item A:
Period 1: Gross requirement of 20 units.
Since A uses lot-for-lot (L4L) as the lot-sizing technique, we release an order for 20 units of A.
Item B:
Item B is a component of A, and each A requires 2 units of B.
We need to calculate the net requirements for B based on the planned order release for A.
Period 1: Gross requirement of 20 units * 2 (requirement multiplier for B) = 40 units.
B has a scheduled receipt of 30 units in period 1.
Net requirement for B in period 1: 40 units - 30 units = 10 units.
Since B also uses L4L as the lot-sizing technique, we release an order for 10 units of B.
Item C:
Item C is a component of A, and each A requires 3 units of C.
We need to calculate the net requirements for C based on the planned order release for A.
Period 1: Gross requirement of 20 units * 3 (requirement multiplier for C) = 60 units.
C has a lead time of two periods, so we need to account for that.
Net requirement for C in period 3: 60 units - 20 units (scheduled receipt for A in period 1) = 40 units.
Since C uses L4L as the lot-sizing technique, we release an order for 40 units of C.
Item D:
Item D is a component of C, and each C requires 1 unit of D.
We need to calculate the net requirements for D based on the planned order release for C.
Period 3: Gross requirement of 40 units * 1 (requirement multiplier for D) = 40 units.
D has a lead time of one period, so we need to account for that.
Net requirement for D in period 4: 40 units - 60 units (scheduled receipt for C in period 3) = -20 units (no requirement).
Since the net requirement is negative, we do not release any planned order for D.
Item E:
Item E is a component of C, and each C requires 1 unit of E.
We need to calculate the net requirements for E based on the planned order release for C.
Period 3: Gross requirement of 40 units * 1 (requirement multiplier for E) = 40 units.
E has a lead time of two periods, so we need to account for that.
Net requirement for E in period 5: 40 units - 0 units (no scheduled receipt for E) = 40 units.
Since E requires a multiple of 100 to be purchased, we release an order for 100 units of E.
Item F:
Item F is a component of B and C, and each B requires 1 unit of F, while each C requires 2 units of F.
We need to calculate the net requirements for F based on the planned order releases for B and C.
Period 1: Gross requirement for B = 10 units * 1 (requirement multiplier for F) = 10 units.
Period 3: Gross requirement for C = 40 units * 2 (requirement multiplier for F) = 80 units.
F has a lead time of two periods, so we need to account for that.
Net requirement for F in period 5: 10 units + 80 units - 0 units (no scheduled receipt for F) = 90 units.
Since F requires a multiple of 100 to be purchased, we release an order for 100 units of F.
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A recycling bin is in the shape of a right rectangular prism. The bin is 9 meters long, 5 meters wide, and 313 meters tall.
What is the volume of the recycling bin?
Enter your answer in the box.
V = m³
Answers
Answer:
14,085m³
Step-by-step explanation:
9*5*13
9*5=45
45*313=14,085
14,085
A candy bar box is in the shape of a triangular prism. The volume of the box is 1200 cubic centimetres. The base is 10 centimetres and the length is 20 centeimeters. What is the height of the base?
Answers
A candy bar box is shaped like a triangular prism. The box has a volume of 1200 cubic centimeters. The base is 10 centimeters and the length is 20 centimeters. The base is 12cm in height.
Given a candy box is in the shape of a triangular prism.
Volume of the box = 1200 cm³
The base of the triangle = 10cm
Side of the triangle = 13cm
Length of the box= 20 cm
Let h cm be the height of the base.
We know,
Volume of the triangular prism = 1/2x(Base of triangle)x(Height of triangle)x(length of prism)
1200 = (1/2) x 10 x h x 20
1200 = 100h
h = 1200/100
h = 12 cm
So, the height of the triangle = 12cm
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what is the answer for this question 7(x+4)-7=48-2x
Answers
Answer:
x = 3
Step-by-step explanation:
7(x + 4) - 7 = 48 - 2x ← distribute parenthesis and simplify left side
7x + 28 - 7 = 48 - 2x
7x + 21 = 48 - 2x ( add 2x to both sides )
9x + 21 = 48 ( subtract 21 from both sides )
9x = 27 ( divide both sides by 9 )
x = 3
Answer: the answer is x=3
Step-by-step explanation:
step 1: distribute the 7 with the parenthesis we get 7x+28-7=48-2x
step 2: subtract 28-7 which gives us 21 now the equation is 7x+21=48-2x
step 3: for the other side which is the 48-2x put the x first so the equation will look something 7x+21=-2x+48
step 4: subtract 21 on both sides 48-21=27 and add 2x on both sides 7x+2x=9x
step 5: 9x=27 now divide both sides by 9 so 27/9= 3
Which expression below is the correct representation of "the product of 4 and a
number, increased by 6, is 9 less than twice the number" if n represents the
variable?
A. 4n + 6 = 9 - 2n
B. 4(n + 6) = 9 - 2n
C. 4n + 6 = 2n - 9
D. 4(n + 6) = 2n - 9
Answers
the product of 4 and a number
> 4n
increased by 6
> 4n + 6
is 9 less than twice a number
> 4n + 6 = 2n - 9
John borrowed $8,500 for 1 year at 8% simple interest from Quicker Loans. At the end of the 1-year period, what is the total loan amount that John will need to repay
Quicker Loans?
$15, 300
$9, 180
$6,800
$680
Answers
Answer:
a.
Step-by-step explanation:
Answer:
$ 9,180
Step-by-step explanation:
(8,500 x 0.08) = 680
8,500 + 680 = 9,180
Find the measure of each angle indicated.
Answers
100 + 80 = 180
Answer the following questions. "Proof by Venn diagram" is not an acceptable approach. Remember that mathematics is a language, and it is necessary to use correct grammar and notation. 1. If A and B are ANY two sets, determine the truth-values of the following statements. If a statement is false, give specific examples of sets A and B that serve as a counter- example (3 pts each). a. (A\B) CA b. Ac (AUB)
Answers
In this question, we are asked to determine the truth-values of two statements involving sets A and B. For each statement, we need to determine if it is true or false. If it is false, we need to provide specific counterexamples by choosing appropriate sets A and B.
a. (A\B) ⊆ A
The statement (A\B) ⊆ A is true for any sets A and B. This is because the set difference (A\B) contains elements that are in A but not in B. Therefore, by definition, every element in (A\B) is also an element of A. There are no counterexamples to this statement.
b. A^c ⊆ (AUB)
The statement\(A^c\) ⊆ (AUB) is true for any sets A and B. This is because the complement of A, denoted as \(A^c\), contains all elements that are not in A.
On the other hand, the union of A and B, denoted as (AUB), contains all elements that are in A or in B or in both.
Since the complement of A contains all elements not in A, it includes all elements in B that are not in A as well.
Therefore, \(A^c\) ⊆ (AUB) holds true for any sets A and B. There are no counterexamples to this statement.
In conclusion, both statements are true for any sets A and B, and there are no counterexamples.
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The biologist is studying Black Carp invasiveness in Lake Ontario next. He doesn't have time to sample the fish himself, so instead he instead asks a fisherman who has been fishing off of one of Toronto's piers all morning about his catch. The fisherman responds that, of the 75 fish he has caught, 37 have been Black Carp. What is the lower bound of a 99% confidence interval for the true proportion of fish that are Black Carp in Lake Ontario
Answers
The lower bound of a 99% confidence interval for the true proportion of fish that are Black Carp in Lake Ontario0. 2357
How to determine the valueTo determine the lowed bound of the 99% confidence, we have;
Let's find the sample proportion, we get;
Sample proportion (p) = Number of Black Carp / Total number of fish
Substitute the values, we have;
p = 37 / 75
Divide the values
p= 0.4933
The margin of error (E) is expressed as;
E = Z × √((p × (1 - p)) / n)
Substitute the values, we get;
E = 2.576 × √((0.4933× (1 - 0.4933)) / 75)
E = 2.576 × √ 0. 0099
E = 0. 2576
Lower bound = p - E
Lower bound = 0.4933 - 0.2576
Lower bound = 0. 2357
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Find the slope between the two points. (2,7) and (5,8)
Answers
Answer:
1/3
Step-by-step explanation:
Plug the coordinates into the slope formula.
y2 - y1/ x2 - x1
8 - 7 / 5 - 2
= 1/3
The slope is 1/3.
Can you please help with steps ?
Answers
Answer:
42:18:30
Step-by-step explanation:
42/7=6
3*6=18
5*6=30
Therefore, 42:18:30
Answer:
since the ratio is 7:3:5 and there are 42 yellow. since thats the case I divide 42 by 7 to get 6. so then 3*6= 18, and 5*6=30. so really there are 42 yellow: 18 pink balls: and 30 green balls so the total in the bag is 90 balls in the bag.
Step-by-step explanation:
Please respond quick!!!
Answers
I think that for a its 1.12 and for b its 39424
100 + 12 = 112
112/100 = 1.12
35200 * 1.12 = 39424
Help would give points please
Answers
Answer:
The answer to the question is 4.
NEEP HELP ASAP LAST DAY OF SCHOOL PLS SHOW YOUR WORK
A rectangular field is 80 meters wide and 120 meters long. Give the length and width of another rectangular field that has the same perimeter but a larger area.
Width= ----- Meters
Length= ------ Meters
Answers
The width of the new rectangular field would be 0 meters, which means it would essentially be a line segment.
To find the length and width of another rectangular field that has the same perimeter but a larger area, we can use the following steps:
1. Calculate the perimeter of the given rectangular field:
Perimeter = 2 * (Length + Width)
= 2 * (120 meters + 80 meters)
= 2 * 200 meters
= 400 meters
2. Divide the perimeter by 2 to find the equal sides of the new rectangular field. Since the perimeter is divided equally into two sides, each side would be half of the perimeter length:
Side length = Perimeter / 2
= 400 meters / 2
= 200 meters
3. Now, we have the side length of the new rectangular field. However, we need to determine the length and width that would yield a larger area. One way to achieve this is to make one side longer and the other side shorter.
4. Let's assume the length of the new rectangular field is 200 meters. Since both sides have the same length, the width can be calculated using the formula for the perimeter:
Width = Perimeter / 2 - Length
= 400 meters / 2 - 200 meters
= 200 meters - 200 meters
= 0 meters
5. Therefore, the width of the new rectangular field would be 0 meters, which means it would essentially be a line segment. However, note that the question asks for a rectangular field with a larger area. Since the width cannot be zero, we can conclude that it is not possible to have a rectangular field with the same perimeter but a larger area than the given field.
In summary, it is not possible to find another rectangular field with the same perimeter but a larger area than the rectangular field with dimensions 80 meters wide and 120 meters long.
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Which polynomial function could be represented by the graph below?
Answers
The polynomial function that could be represented by the graph is f(x) = x² - 4x + 5
How to determine the polynomial function that could be represented by the graphFrom the question, we have the following parameters that can be used in our computation:
The graph
On the graph, we have the following intercepts (or zeros)
x = -1 and x = 5
The polynomial function that could be represented by the graph is then calculated as
f(x) = The product of the difference between x and the intercepts
Substitute the known values in the above equation, so, we have the following representation
f(x) = (x + 1)(x - 5)
Open the brackets
f(x) = x² - 4x + 5
Hence, the equation is (b) f(x) = x² - 4x + 5
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How many different letter arrangements can be made from the letters (a) Fluke? (b) Propose? (c) Mississippi? (d) Arrange? A child has 12 blocks, of which 6 are black, 4 are red, 1 is white, and 1 is blue. If the child puts the blocks in a line, how many arrangements are possible?
Answers
a) Fluke has 5 letters. b) Propose has 7 letters. c) Mississippi has 11 letters d) Arrange has 7 letters
We have been given that child has 12 blocks, of which 6 are black, 4 are red, 1 is white, and 1 is blue.
Since, the number of different letter arrangements can be made from the letters Fluke is 5! = 120.
b) the number of different letter arrangements that can be made from the letters Propose is 7! = 5040.
Therefore, Propose has 7 letters.
c) the number of different letter arrangements can be made from the letters Mississippi is
11!/(4!4!) = 34650.
Thus Mississippi has 11 letters, and it has 4 S's and 4 I's
d) the number of different letter arrangements that can be made from the letters Arrange,
7!/(2!2!) = 1260.
Thus Arrange has 7 letters, and it has two Rs and two Es.
Then, the number of arrangements that can be made is; 12!/[(6!)(4!)(1!)(1!)] = 27720 arrangements.
Therefore, the child can make 27720 arrangements with 12 blocks.
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Sally's bakery will make custom cupcakes for special events. She charges a flat
fee of $35.00 and then 75 cents per cupcake ordered,
uoctie
Answers
Answer:
y=.75x+35
so you're using a y=mx+b format
y=the total
m=her fee for each cupcake
b=her standing charge
Simplify
(4z+9)-(3z-9
Answers
Answer:
z+18
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Step-by-step explanation:
Answer:
z+18
Step-by-step explanation:
4z+9-3z+9
z+9+9
z+18
Using simplex method to solve the following problems: (Manual calculations and then confirm your calculation by any software) Max. Z=5A+4B Subject to constraints: 6 A+4 B≤24, A+2 B≤6,−A+B≤1, B≤2, A, B≥0
Answers
Using the simplex method, the maximum value of Z=5A+4B is found to be 19.2 when A=3.6 and B=1.2. The calculations can be confirmed by using any software that solves linear programming problems.
To solve the given linear programming problem using the simplex method, we start by converting the problem into standard form. We introduce slack variables to convert the inequalities into equations.The initial tableau is as follows:
| A | B | S1 | S2 | S3 | S4 | RHS
------------------------------------------
Z | -5 | -4 | 0 | 0 | 0 | 0 | 0
------------------------------------------
S1 | 6 | 4 | 1 | 0 | 0 | 0 | 24
S2 | 1 | 2 | 0 | 1 | 0 | 0 | 6
S3 | -1 | 1 | 0 | 0 | 1 | 0 | 1
S4 | 0 | 1 | 0 | 0 | 0 | 1 | 2
We perform the simplex iterations until the optimal solution is reached. After applying the simplex method, the final tableau is obtained as follows:
| A | B | S1 | S2 | S3 | S4 | RHS
------------------------------------------------------
Z | 0 | 1.8 | 0.2 | -1 | -0.4 | 0.4 | 19.2
------------------------------------------------------
S1 | 0 | 0 | 0 | 1.5 | -1 | 1 | 3
S2 | 1 | 0 | -0.5 | 0.5 | 0.5 | -0.5 | 1.5
A | 1 | 0 | 0.5 | -0.5 | -0.5 | 0.5 | 0.5
S4 | 0 | 0 | 1 | -1 | -1 | 1 | 1
From the final tableau, we can see that the maximum value of Z is 19.2 when A=3.6 and B=1.2. This solution satisfies all the constraints of the problem. The calculations can be verified using any software that solves linear programming problems, which should yield the same optimal solution.
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What is the equivalent trig ratio to sin 25?
Answers
Answer:
The answer is "\(\bold{\cos 65}\)"
Step-by-step explanation:
Given:
\(\Rightarrow \bold{\sin 25}\\\)
\(\Rightarrow \sin 25\) can be written as \(\frac{\sin 25}{1}\)
\(\therefore \tan \theta = \frac{\sin \theta }{cos \theta}\)
\(\Rightarrow \sin 25\) can be written as \(\cos (90-65)\)
The answer is "\(\bold{\cos 65}\)".
What is the phase shift of a periodic function?
a horizontal translation of the function
the horizontal length of one cycle of the function
the number of cycles of the function that occur in one horizontal unit
a vertical translation of the function
Answers
A function assigns values. The phase shift of a periodic function is the horizontal translation of the function.
What is a Function?A function assigns the value of each element of one set to the other specific element of another set.
The Phase Shift of a periodic function is the horizontal shift of the function from its normal position. The shift is either left or right.
For example, if the value of c in the function of sine is negative then the function will move towards the right side by the value of c, while if the value of c is positive then the function will towards the left.
Thus, the phase shift of a periodic function is the horizontal translation of the function.
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Could someone explain to me how to solve these questions?
Answers
Answer:
you combine the numbers that are the same and see the signs if it's positive with the negative, it's going to be negative
I've been having problems with this and I was wondering if someone could give me the answers 1 - 5
Answers
The measures of x are obtained with the Pythagorean Theorem, as follows:
1. x = 10.2.
2. x = 7.2.
3. x = 13.7.
4. x = 36.2.
5. x = 10.7.
What is the Pythagorean Theorem?The Pythagorean Theorem is a geometry axiom which states that for a right triangle, the length of the hypotenuse squared is equals to the sum of the lengths of the sides squared.
Hence, for item 1, we have that:
x² + 16² = 19²
x = square root(19² - 16²)
x = 10.2.
For item 2, we have that:
x² + 12² = 14²
x = square root(14² - 12²)
x = 7.2.
For item 3, we have that:
x² + 9.2² = 16.5²
x = square root(16.5² - 9.2²)
x = 13.7.
For item 4, we have that:
The bottom side is bisected into two equal sides of dimension 15.Then x is the hypotenuse of a right triangle of sides 15 and 33, thus:x² = 15² + 33²
x = square root(15² + 33²)
x = 36.2.
For item 5, first we find the side of the top right triangle, hence:
h² + 16² = 25²
h = square root(25² - 16²)
h = 19.2.
Then the value of x is obtained as follows:
x² + 19.2² = 22²
x = square root(22² - 19.2²)
x = 10.7.
More can be learned about the Pythagorean Theorem at https://brainly.com/question/28853425
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