The following is the capital structure of k co ltd.

ordinary share capital

100,000 shares at shillings10 1,000,000

share premium 500,000

retained earnings 800,000

total capital employed 2,300,000

k co. ltd intends to declare a stock dividend of 10% on its ordinary shares such

that it will give 1 share for 10 at shillings 10.

required

1) compute the number of new ordinary shares arising out of this issue. (3 marks)

2) prepare different accounts arising out of this issue. (5 marks)

3) show the new capital structure after this issue. (7 marks)

Answer:

x=2

Step-by-step explanation:

i would set up a system of equation using the pythagorean theorem:

1^2+x^2=z^2

4^2+x^2=y^2

Add up these equations to get:

17+2x^2=y^2+z^2

But notice that

y^2+z^2=5^2

So you can substitute

17+2x^2=25

2x^2=8

x^2=4

x=2

:)

Answer:

Step-by-step explanation:

\(5) 5\frac{11}{12}+3\frac{5}{6}=5+\frac{11}{12}+3+\frac{5}{6}\\\\ =8 +\frac{11}{12}+\frac{5*2}{6*2}\\\\= 8 +\frac{11}{12}+\frac{10}{12}\\\\=8 +\frac{11+10}{12}\\\\= 8+\frac{21}{12}\\\\=8+ 1\frac{9}{12}\\\\= 9\frac{9}{12}\)

Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

If the problem is (-7)^2 then you multiply -7 *-7

If the problem is -(7) ^2 then you multiply -1*7*7

Answer: FALL OUT OF THE TREE

A plot that will present the information that will highlight how many trees are in a range of heights, such as 60–64, 65–69, etc. : histogram

In this question, we have been given the tree heights recorded on a school campus.

A science teacher wants to choose a data display that will highlight how many trees are in a range of heights, such as 60–64, 65–69, etc.

We need to find a correct plot that will present the information in this way.

We know that in bar charts, each bar represents one value(category). And  in a histogram, each bar will represent a continuous data

Therefore, a plot that will present the information that will highlight how many trees are in a range of heights, such as 60–64, 65–69, etc. : histogram

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Answer:

Step-by-step explanation:

A plot that will display information highlighting the number of trees in a range of heights, such as 60-64, 65-69, and so on: histogram

We were provided the tree heights reported on a school grounds in this question. A science instructor needs to select a data presentation that will show how many trees are in a given height range, such as 60-64, 65-69, and so on. We must find a suitable plot to portray the data in this manner. We know that each bar on a bar chart represents one value (category). And each bar in a histogram represents continuous data.

Yes, it does have a circuit. This is because a connected graph with nine vertices and twelve edges is guaranteed to have at least one circuit.

A circuit is a path that starts and ends at the same vertex while visiting all other vertices exactly once. A connected graph with n vertices and 2n edges is guaranteed to have at least one circuit. This is because each edge in the graph contributes to two paths (one in each direction), and the total number of paths must be equal to the number of edges. Since a graph with nine vertices and twelve edges has more edges than vertices, it is guaranteed to have at least one circuit. Therefore, the graph does indeed have a circuit.

The complete question is : a connected graph has nine vertices and twelve edges. does it have a circuit? why or why not? the graph has a circuit because a connected graph with n vertices and 2n edges is guaranteed to have at least one circuit.

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Hence, the correct match of probabilities with their corresponding situations is given by option 4.

To match the probabilities with their corresponding situations, we can utilize the formulas given below:

\(P(A ∩ B) = P(A) x P(B|A)P\)(2 aces) =\((4/52) x (3/51) = 1/221\)

P(heart and club) =\((13/52) x (13/51) = 169/2652\)P(spade and ace of hearts) = 0P(2 of the same card) = (1/52) + (3/51) + (2/50) + (1/49) + (4/48) + (3/47) + (2/46) + (1/45) = 20/663P(red card and four of spades) = (16/52) x (1/51) = 4/663

Therefore, the probabilities with their corresponding situations are:3: P(spade and ace of hearts) = 0 (Not possible as Ace of hearts is not spade)

4: P(2 aces) = 1/2211: P(heart and club) = 169/26521: P(heart and club) = 169/26522: P(red card and four of spades) = 4/663

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Answer:

a. 6x^2

b. 70x^2

c. -360s^2

d. -60x^2

Step-by-step explanation:

3.19,3.51,3.72,3.93

Step-by-step explanation:

3.19=3.2

3.51=3.5

3.72=3.7

3.93=3.9

you take over the number kn the tenth .... if its 1 234 you round down and if its 5 or more you round up... simple

Answer:

Yes

Step-by-step explanation:

Answer:

b is the right answer

Step-by-step explanation:

Answer:

=5x²+21x+18

Step-by-step explanation:

Answer: (x+3)(5x+6)

=(x+3)(5x+6)

=(x)(5x)+(x)(6)+(3)(5x)+(3)(6)

=5x2+6x+15x+18

=5x2+21x+18

Step-by-step explanation:

I hope this helps plz tell me if its wrong so i can fix it.

Answer:

Step-by-step explanation:

No, because 9 > 3+4

Step-by-step explanation:

\(\large\underline{\sf{Solution-}}\)

\(\rm :\longmapsto\:\dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg)\)

Let assume that

\(\rm :\longmapsto\:y = {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg)\)

We know,

\(\boxed{\tt{ {cosec}^{ - 1}x = {sin}^{ - 1}\bigg( \dfrac{1}{x} \bigg)}}\)

So, using this, we get

\(\rm :\longmapsto\:y = sin^{ - 1} \bigg( \dfrac{2x}{1 + {x}^{2} } \bigg)\)

Now, we use Method of Substitution, So we substitute

\( \red{\rm :\longmapsto\:x = tanz \: \rm\implies \:z = {tan}^{ - 1}x}\)

So, above expression can be rewritten as

\(\rm :\longmapsto\:y = sin^{ - 1} \bigg( \dfrac{2tanz}{1 + {tan}^{2} z} \bigg)\)

\(\rm :\longmapsto\:y = sin^{ - 1} \bigg( sin2z \bigg)\)

\(\rm\implies \:y = 2z\)

\(\bf\implies \:y = 2 {tan}^{ - 1}x\)

So,

\(\bf\implies \: {cosec}^{ - 1}\bigg( \dfrac{1 + {x}^{2} }{2x} \bigg) = 2 {tan}^{ - 1}x\)

Thus,

\(\rm :\longmapsto\:\dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg)\)

\(\rm \:  =  \: \dfrac{d}{dx}(2 {tan}^{ - 1}x)\)

\(\rm \:  =  \: 2 \: \dfrac{d}{dx}( {tan}^{ - 1}x)\)

\(\rm \:  =  \: 2 \times \dfrac{1}{1 + {x}^{2} } \)

\(\rm \:  =  \: \dfrac{2}{1 + {x}^{2} } \)

Hence,

\( \purple{\rm :\longmapsto\:\boxed{\tt{ \dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg) = \frac{2}{1 + {x}^{2} }}}}\)

Hence, Option (d) is correct.

4-p=-4p+4

4-p+4p-4

3p

Step-by-step explanation:

that iw the answer

Answer:

12 pens

Step-by-step explanation:

Let the variable that can be used to determine the number of pens that Kamila bought be represented by n.

Price of a notebook = $1.59

Price a pen = $0.29

Total amount spent = $5.07

But,

1.59 + 0.29 n = 5.07

So that,

0.29 n = 5.07 - 1.59

0.29 n  = 3.48

n = \(\frac{3.48}{0.29}\)

  = 12

Therefore, Kamila bought 12 pens.

Given the following information: Five years ago, someone used her $40,000 saving to make a down payment for a townhouse in RTP. The house is a three-bedroom townhouse and sold for $200,000 when she bought it. After paying down payment, she financed the house by borrowing a 30-year mortgage.

Mortgage interest rate is 4.25%. Right after closing, she rent out the house for $1,800 per month. In addition to mortgage payment and rent revenue, she listed the following information so as to figure out investment return: 1. HOA fee is $75 per month and due at end of each year 2. Property tax and insurance together are 3% of house value 3. She has to pay 10% of rent revenue for an agent who manages her renting regularly 4. Her personal income tax rate is 20%. While rent revenue is taxable, the mortgage interest is tax deductible. She has to make the mortgage amortization table to figure out how much interest she paid each year 5. In the last five years, the market value of the house has increased by 4.8% per year 6.

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The rule to translate triangle ABC to triangle A'B'C' is (x + 5, y - 5).

To find the rule that translates triangle ABC to triangle A'B'C', we need to determine the translation vector (a, b) that moves each vertex of triangle ABC to its corresponding vertex in triangle A'B'C'.

Let's calculate the translation vector by subtracting the coordinates of a vertex in triangle ABC from its corresponding vertex in triangle A'B'C'.

Translation vector for vertex A:

(a, b) = (4 - (-1), -3 - 2) = (5, -5)

Translation vector for vertex B:

(a, b) = (10 - 5, -8 - (-3)) = (5, -5)

Translation vector for vertex C:

(a, b) = (2 - (-3), -5 - 0) = (5, -5)

Since the translation vector is the same for all vertices, we can conclude that the rule to translate triangle ABC to triangle A'B'C' is (x + 5, y - 5).

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The answer is -6 :)

1. Add 40 to both sides of the equation.

-8x-40=8

-8x-40+40=8+40

2. Add the numbers.

-8x=48

3. Divide both sides of the equation by the same term.

-8x=48

\(\frac{-8x}{-8}\)=\(\frac{48}{-8}\)

4. Cancel terms that are in both the numerator and denominator and divide the numbers.

x=-6

hope this helped! :)

Answer:

136 = 9x+10 (alternate interior angles for parallel lines m and n)

9x = 126

x = 14

Step-by-step explanation:

Stop by my you tube channel "Sciency Sergei". You may suggest a topic to discuss or problem to solve.

Based on the provided information of speed, A) Beth gets to San Francisco first. B) The first to arrive has to wait for 20 minutes for the second to arrive.

A) To find out who gets to San Francisco first, we need to calculate the time it takes for each of them to travel the distance of 400 miles.

For Brian, we use the formula time = distance / speed:

time = 400 miles / 50 mph = 8 hours

So Brian will arrive in San Francisco at 4:00 p.m. (8:00 a.m. + 8 hours).

For Beth, we use the same formula:

time = 400 miles / 60 mph = 6.67 hours

So Beth will arrive in San Francisco at 3:40 p.m. (9:00 a.m. + 6.67 hours).

Therefore, Beth gets to San Francisco first.

B) To find out how long the first to arrive has to wait for the second, we subtract the arrival time of the first from the arrival time of the second:

wait time = 4:00 p.m. - 3:40 p.m. = 0.33 hours = 20 minutes

So the first to arrive has to wait for 20 minutes for the second to arrive.

Note: The question is incomplete. The complete question probably is: Brian leaves Los Angeles at 8:00 a.m. to drive to San Francisco, 400 miles away. He travels at a steady speed of 50 mph. Beth leaves Los Angeles at 9:00 a.m. and drives at a steady speed of 60 mph. A) Who gets to San Francisco first? B) How long does the first to arrive have to wait for the second?

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The x-intercepts of the resulting parabola are (6, 0) and (-12, 0).

To find the x-intercepts of a parabola, we need to determine the values of x when y is equal to zero. In the given equation, y = (2-6)(z+12), we have y set to zero.

Setting y to zero:

0 = (2-6)(z+12)

Simplifying the equation:

0 = -4(z+12)

To solve for z, we divide both sides of the equation by -4:

0 / -4 = (z+12)

0 = z + 12

Subtracting 12 from both sides:

z = -12

So, one x-intercept of the parabola is (-12, 0).

To find the second x-intercept, we can substitute a different value for z. Let's substitute z = 6 into the equation:

0 = -4(6+12)

0 = -4(18)

0 = -72

Since the equation evaluates to zero, z = 6 is another x-intercept of the parabola.

Therefore, the x-intercepts of the resulting parabola are (6, 0) and (-12, 0).

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Answer:

D=1.22g/cubic cm

Step-by-step explanation:

D=M/V

$149.60 that's what he will have left

A linear function is a mathematical function where each variable has its own term and is raised to the first power.

Given that,

We have to say a mathematical function in which each variable appears in a separate term and is raised to the first power is known as a

We know that,

A linear function is a mathematical function where each variable has its own term and is raised to the first power.

In the coordinate plane, a linear function represents a straight line. Because it is a straight line in the coordinate plane, the equation y = 3x - 2 serves as an illustration of a linear function. Because f can be used in place of y, this function can be written as f(x) = 3x - 2. (x).

Therefore, A linear function is a mathematical function where each variable has its own term and is raised to the first power.

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I will win about $ 59.

This is a question of permutations and combinations.

We know that,

Probability of getting two non face cards = \(\frac{^{40}C_2}{{^{52}C_2}}\) = 10/17

Probability of not getting two non face cards = 1 - (10/17) = 7/17

Hence, we can write,

Money I will get = (7/17)*50*20 =  $ 411.764

Money I'll have to pay = (10/17)*30*20 = $ 352.94

We know that,

Money left with me = Money I will get - Money I'll have to pay

Hence, we can write,

Money left with me =   $ 411.764 - $ 352.94

Money left with me =  58.824 ≈ $ 59

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Answer:

-6

Step-by-step explanation:

To find the slope the the formula is y=mx+b

m means slope so -6 is the slope

Douglas McGregor believed that the Theory X assumptions were appropriate for traditional and authoritarian organizations.

Theory X is a management theory developed by Douglas McGregor, a management professor, and consultant. It is based on the idea that individuals dislike work and will avoid it if possible. As a result, they must be motivated, directed, and controlled to achieve organizational goals. The assumptions of Theory X are as follows:

Employees dislike work and will try to avoid it whenever possible. People must be compelled, controlled, directed, or threatened with punishment to complete work. Organizations require rigid rules and regulations to operate effectively. In conclusion, Douglas McGregor believed that Theory X assumptions were appropriate for traditional and authoritarian organizations.

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Answer:

11:43 am

Step-by-step explanation:

Given data

Time of arrival= 11:19 am

We are told that she spent 24 minutes in the store

Based on this, we can estimate the time she left the store

The time she left

=11:19+ 24

=11:43 am

Hence she left 11:43 am