The football team has a total of 20 jerseys. There are 8 ​medium-sized jerseys. What percent of the jerseys are​ medium-sized jerseys?

Answer:

We first need to know what X & Y is...

Step-by-step explanation:

Answer:

Train A is travelling at a speed of 12.857 miles per hour and train B at a speed of 9.643 miles per hour.

Step-by-step explanation:

Let suppose that train A begins in position \(x = 0\,mi\) and the train B in position \(x = 1.5\,mi\), if \(v_{B} = \frac{3}{4}\cdot v_{A}\) and both trains move at constant speed, then we have  the following kinematic equations:

Train A

\(x_{A} = x_{A,o}+v_{A}\cdot t\) (1)

Train B

\(x_{B} = x_{B,o}-v_{B}\cdot t\) (2)

If both trains meet each other, then \(x_{A} = x_{B}\). If we know that \(x_{A,o} = 0\,mi\), \(x_{B,o} = 1.5\,mi\), \(v_{B} = \frac{3}{4}\cdot v_{A}\) and \(t = \frac{1}{15}\,h\), then we have the following expression:

\(x_{A,o}+v_{A}\cdot t = x_{B,o}-v_{B}\cdot t\)

\(x_{A,o} + v_{A}\cdot t = x_{B,o} - \frac{3}{4}\cdot v_{A}\cdot t\)

\(\frac{7}{4}\cdot v_{A}\cdot t = x_{B,o}-x_{A,o}\)

\(v_{A} = \frac{4\cdot (x_{B,o}-x_{A,o})}{7\cdot t}\)

\(v_{A} = 12.857\,\frac{mi}{h}\)

Then, the speed of the train B is:

\(v_{B} = 9.643\,\frac{mi}{h}\)

Train A is travelling at a speed of 12.857 miles per hour and train B at a speed of 9.643 miles per hour.

a. The probability of demand exceeding 150 saws in any given week is approx 0.0475 or 4.75%.     b. The probability of demand being less than 50 saws in any given week is approx 0.0475 or 4.75%.

To calculate the probabilities using the normal distribution, we follow these steps:

a. Probability of demand exceeding 150 saws:
Step 1: Calculate the z-score using the formula: z = (x - mean) / standard deviation
  z = (150 - 100) / 30 = 1.67 (rounded to two decimal places)

Step 2: Find the area under the normal curve to the right of the z-score.
  P(X > 150) = 1 - P(X ≤ 150)
  Using a standard normal distribution table or calculator, we find the area to the left of 1.67, which is approximately 0.9525.

  P(X > 150) ≈ 1 - 0.9525 = 0.0475

Therefore, the probability that demand in any given week will exceed 150 saws is approximately 0.0475 or 4.75%.

b. Probability of demand being less than 50 saws:
Step 1: Calculate the z-score: z = (50 - 100) / 30 = -1.67 (rounded to two decimal places)

Step 2: Find the area under the normal curve to the left of the z-score.
  P(X < 50) = P(X ≤ 50)
  Using the standard normal distribution table or calculator, we find the area to the left of -1.67, which is approximately 0.0475.

  P(X < 50) ≈ 0.0475

Therefore, the probability that demand in any given week will be less than 50 saws is approximately 0.0475 or 4.75%.

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Answer:

44

Step-by-step explanation:

39-(-15)= 39 + 15 = 44

The length of the hip on a hip roof rises 1.5 feet vertically.

The hip roof has a slope of 6 inches per foot ( hip slope factor = 1.5) and a hip run of 14 feet

Length of hip = (square root of (hip run squared + (hip slope factor x roof span squared)))
Plugging in the given values, we get:
Length of hip = (square root of (14 squared + (1.5 x 14 squared)))
Length of hip = (square root of (196 + 294))
Length of hip = (square root of 490)
Length of hip = 22 feet (rounded to the nearest whole number)
Therefore, the correct answer is C. 22.
It's important to note that the hip slope factor is a value used to calculate the actual slope of the hip, which is typically steeper than the pitch of the roof. In this case, the hip slope factor of 1.5 means that for every foot of horizontal run, the hip rises 1.5 feet vertically.

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True. A pictogram is a visual representation of data or information that uses pictures or symbols to convey meaning.

In the context of a construction project, a pictogram can be used to track the progress of the project towards completion. The pictogram can show the percentage of completion, the milestones achieved, and the remaining tasks to be completed.

It can also be used to indicate any potential delays or issues that need to be addressed. By using a pictogram, the project team can easily communicate the progress of the construction project to stakeholders who may not be familiar with technical details or industry jargon.

Additionally, the use of a pictogram can make it easier for the team to identify areas that require attention and adjust their plans accordingly. Overall, the use of a pictogram can be a valuable tool in tracking the progress of a construction project and ensuring that it stays on track to meet its goals within the specified timeframe.

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Answer:

y=  -5.6

Step-by-step explanation:

Answer:

-8 and 3, or -3 and 8

Step-by-step explanation:

xy = -24

x - y = 11

x = y + 11

y(y + 11) = -24

y^2 + 11x + 24 = 0

(y + 8)(y + 3) = 0

y = -8 or y = -3

x = 3 or x = 8

the numbers are -8 and 3, or -3 and 8

According to the Triangle Inequality Theorem, the sum of the lengths of two sides of a triangle is greater than the length of the third side of the triangle.

In this case, you know the lengths of two sides of the triangle, and you also know that "x" represents the length of the third side. Then, you can set up the following:

Solving the inequality, you get:

You can rewrite it as:

Hence, the answer is:

Answer:

-------------------------

Each coordinate of the midpoint is the average of endpoints:

Therefore M is (13, 14).

The demand function for the marginal revenue function is p(x) = 0.02x² - 0.025x + 138.

Define Marginal revenue

Marginal revenue is a central concept in microeconomics that describes the additional total revenue generated by increasing product sales by 1 unit.

Given expression is,

R′(x) = 0.06x² − 0.05x + 138

To make R'(x) to R(x) just integrate R'(x),

R(x) = ∫ R'(x) dx

      = ∫ (0.06x² − 0.05x + 138) dx

      =  0.06x³/3 − 0.05x²/2 + 138 x  + C

We get, R(x) = 0.02x³ − 0.025x² + 138 x  + C

It's given, the revenue is 0 means no items sold so R(0) = 0.

Now, put x = 0 and find C

R(0) = 0.02(0)³ − 0.025(0)² + 138 (0)  + C

   0 = 0 + C

C = 0

So, R(x) = 0.02x³ − 0.025x² + 138 x, since C = 0

Now, take x common from R(x) will give us,

R(x) = x( 0.02x² − 0.025x + 138 )

so, R(x) = x p(x)

so, p(x) = 0.02x² − 0.025x + 138

Hence, the demand function for the marginal revenue function is p(x) = 0.02x² - 0.025x + 138.

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The correct answer is option (b) No, the statement does not represent an exponential function, h(t) = -4.9t² + 18t + 40 is a quadratic function and not an exponential function.

An exponential function is a mathematical function in which the variable is in the exponent. Exponential functions follow the form f(x) = a^x, where a is the base and x is the exponent.

The given statement is h(t) = -4.9t² + 18t + 40, which does not represent an exponential function. The value of t is not in the exponent in this case. Instead, it's a quadratic equation, which is in the form of h(t) = at² + bt + c.

Therefore, the correct answer is option (b) No, the statement does not represent an exponential function.

Explanation:

An exponential function can also be represented by the general form y = ab^x, where b > 0 and b ≠ 1. When plotted on a graph, the curve of an exponential function rises or falls at an increasing rate, depending on whether b is greater than or less than 1, respectively.

A quadratic equation is an equation of the form ax² + bx + c = 0, where a ≠ 0, and x represents a variable. Quadratic equations are second-degree equations, which means the highest exponent of the variable is two.

Therefore, h(t) = -4.9t² + 18t + 40 is a quadratic function and not an exponential function.

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See attached for a sketch of some of the cross sections.

Each cross section has area equal to the square of the side length, which in turn is the vertical distance between the curve y = √(x + 1) and the x-axis (i.e. the distance between them that is parallel to the y-axis). This distance will be √(x + 1).

If the thickness of each cross section is ∆x, then the volume of each cross section is

∆V = (√(x + 1))² ∆x = (x + 1) ∆x

As we let ∆x approach 0 and take infinitely many such cross sections, the total volume of the solid is given by the definite integral,

\(\displaystyle \int_{-1}^1 (x+1) \, dx = \left(\frac{x^2}2 + x\right) \bigg|_{-1}^1 = \boxed{2} ~~~~ (B)\)

There are 21,600 possible groups that the teacher can form.

Combinations is a method of counting the number of ways to select a specific number of items from a larger set without regard to their order.

Specifically, the problem involves finding the number of ways to select three boys and two girls from a group of twenty students.

C(20, 3) * C(17, 2)

Here we have

A teacher wishes to divide her class of twenty students into four groups, each of which will have three boys and two girls.

Assume that there are two equal number of boys and girls

Now we need to choose 3 boys out of 10 and 2 girls out of 10 for each group, as there are 10 boys and 10 girls in the class.

We can do this in the following way:

Number of ways to choose 3 boys out of 10 = C(10,3) = 120

Number of ways to choose 2 girls out of 10 = C(10,2) = 45

Hence,

The number of ways to form a group of 3 boys and 2 girls

= 120 × 45 = 5400

Since we need to form 4 such groups,

The total number of possible groups that the teacher can form is:

=> 4 × 5400 = 21600

Therefore,  

There are 21,600 possible groups that the teacher can form.

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Answer:

all we need to do is keep on adding 1/4 until you get to 1 1/2 its lik dividing to how muc times con 1/4 go into 1 1/2. so you run 7 laps

this is you answer

Step-by-step explanation:

example: at home you walk around your yard and you walked 4 1/2 miles. and yard is 1/2 of a mile. 1/2+1/2+1/2+1/2+1/2+1/2+1/2+1/2+1/2=4 1/2

so 1/2 can go into 4 1/2 9 times.

Therefore, the due date of the note is August 9 adding the number of days in the note's term to the note's date adding the number of days in the note's term to the note's date.

To determine the due date of the note, we need to add the number of days in the note's term to the note's date.

Given:

Note term: 120 days

Note date: April 9

To find the due date, we add 120 days to April 9.

April has 30 days, so we can calculate the due date as follows:

April 9 + 120 days = April 9 + 4 months = August 9

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The pressure change is an illustration of an arithmetic progression.

The atmospheric pressure at 50000 feet is 11.3 kPa

The given parameters are:

\(\mathbf{a = 101.3}\) --- the first term

\(\mathbf{d = -1.8 per 1000}\) -- common difference

At 50000 feet, the number of increment in altitude is

\(\mathbf{n = \frac{50000}{1000}}\)

\(\mathbf{n = 50}\)

So, the atmospheric pressure at 50000 feet is:

\(\mathbf{T_{50} = 101.3 - 1.8 \times 50}\)

\(\mathbf{T_{50} = 101.3 - 90}\)

\(\mathbf{T_{50} = 11.3}\)

Hence, the atmospheric pressure at 50000 feet is 11.3 kPa

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The Area of Trapezium is 50, 267 mm².

We have,

base 1 = 224 mm

base 2 = 77 mm

Height = 334 mm

Now, Area of Trapezium

= 1/2 (Sum of parallel side) x height

= 1/2 (224 + 77) x 334

= 1/2 x 301 x 334

= 50, 267 mm²

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Answer: Its the 4th choice

Step-by-step explanation:

-12 + 8 = -4

Answer:

-12 +8

Step-by-step explanation:

-12/-3 = positive 4

5 - -9 = 5+9 = 14

(-2) ^ = -2 * -2 =4

-12 +8 = -4

Answer:

Convergent

Step-by-step explanation:

One method to determine if  \(\displaystyle \sum^\infty_{k=1}ke^{-k^2}\)is convergent or divergent is the Integral Test.

Suppose that the function we use is \(f(x)=xe^{-x^2}\). Over the interval \([1,\infty)\), the function is always positive and continuous, but we also need to make sure it is decreasing before we can proceed with the Integral Test.

The derivative of this function is \(f'(x) = e^{-x^2}(1-2x^2)\), so our critical points will be \(\displaystyle x=\pm\frac{1}{\sqrt{2}}\), but we can drop the negative critical point as we are starting at \(k=1\). Using some test points, we can see that the function increases on the interval \(\bigr[0,\frac{1}{\sqrt{2}}\bigr]\) and decreases on the interval \(\bigr[\frac{1}{\sqrt{2}},\infty\bigr)\). Since the function will eventually decrease, we can go ahead with the Integral Test:

\(\displaystyle \int_{{\,1}}^{{\,\infty }}{{x{{{e}}^{ - {x^2}}}\,dx}} & = \mathop {\lim }\limits_{t \to \infty } \int_{{\,1}}^{{\,t}}{{x{{{e}}^{ - {x^2}}}\,dx}}\hspace{0.5in}u = - {x^2}\\ & = \mathop {\lim }\limits_{t \to \infty } \left. {\left( { - \frac{1}{2}{{{e}}^{ - {x^2}}}} \right)} \right|_1^t\\ & = \mathop {\lim }\limits_{t \to \infty } \left( {-\frac{1}{2}{{e}}^{ - {t^2}}-\biggr(-\frac{1}{2e}\biggr)}} \right) = \frac{1}{2e}\)

Therefore, since the integral is convergent, the series must also be convergent by the Integral Test.

The difference quotient of f(x) is \(\frac{-\frac{1}{h}+ 5}{5x+ h -12}\) .

According to the given question.

We have a function

f(x) = -1/(5x -12)

As we know that, the difference quotient is a measure of the average rate of change of the function over and interval.

The difference quotient formula of the function y = f(x) is

[f(x + h) - f(x)]/h

Where,

f(x + h) is obtained by replacing x by x + h in f(x)

f(x) is a actual function.

Therefore, the difference quotient formual for the given function f(x)

= [f(x + h) - f(x)]/h

= \(\frac{\frac{-1}{5(x+h)-12} -\frac{-1}{5x-12} }{h}\)

= \(\frac{\frac{-1}{5x + 5h -12}+\frac{1}{5x-12} }{h}\)

= \(\frac{\frac{-1+5h}{5x + 5h-12} }{h}\)

= \(\frac{-1+5h}{(5x +h-12)(h)}\)

= \(\frac{-1+5h}{5xh + h^{2} -12h}\)

= \(\frac{h(-\frac{1}{h}+5) }{h(5x+h-12)}\)

= \(\frac{-\frac{1}{h}+ 5}{5x+ h -12}\)

Hence, the difference quotient of f(x) is \(\frac{-\frac{1}{h}+ 5}{5x+ h -12}\) .

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In summary, the Fourier coefficients for the periodic function y(t) = -3 on the interval -5 ≤ t ≤ 5 are:

c₀ = -3 (DC component)

cₙ = 0 for n ≠ 0 (other coefficients)

To find the Fourier coefficients of the periodic function y(t) = -3 on the interval -5 ≤ t ≤ 5, we can use the formula for Fourier series coefficients:

cn = (1/T) ∫[t₀-T/2, t₀+T/2] y(t) \(e^{(-i2\pi nt/T)}\) dt

where T is the period of the function and n is an integer.

In this case, the function y(t) is constant, y(t) = -3, and the period is T = 10 (since the interval -5 ≤ t ≤ 5 spans 10 units).

To find the Fourier coefficient c₀ (corresponding to the DC component or the average value of the function), we use the formula:

c₀ = (1/T) ∫[-T/2, T/2] y(t) dt

Substituting the given values:

c₀ = (1/10) ∫[-5, 5] (-3) dt

  = (-3/10) \([t]_{-5}^{5}\)

  = (-3/10) [5 - (-5)]

  = (-3/10) [10]

  = -3

Therefore, the DC component (c₀) of the Fourier series of y(t) is -3.

For the other coefficients (cₙ where n ≠ 0), we can calculate them using the formula:

cₙ = (1/T) ∫[-T/2, T/2] y(t)\(e^{(-i2\pi nt/T) }\)dt

Since y(t) is constant, the integral becomes:

cₙ = (1/T) ∫[-T/2, T/2] (-3) \(e^{(-i2\pi nt/T)}\) dt

  = (-3/T) ∫[-T/2, T/2] \(e^{(-i2\pi nt/T)}\) dt

The integral of e^(-i2πnt/T) over the interval [-T/2, T/2] evaluates to 0 when n ≠ 0. This is because the exponential function oscillates and integrates to zero over a symmetric interval.

all the coefficients cₙ for n ≠ 0 are zero.

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Answer:(3,-5)(5,7) instrumentate in inclination countercheck form. correspondingly characterization forethoughtfulness

Step-by-step explanation:(3,-5)(5,7) instrumentate in inclination countercheck form. correspondingly characterization forethoughtfulness (3,-5)(5,7) instrumentate in inclination countercheck form. correspondingly characterization forethoughtfulness

Answer:

Me need my points :D                    

Step-by-step explanation:

Step-by-step explanation:

Given vertices (-2,3),(2,4),(3,4)

\( {x}^{1} + {x}^{2} + {x}^{3} \div 3 \\ {y}^{1} + {y}^{2} + {y}^{3} \div 3 \\ - 2 + 2 + 3 \div 3 \: + 4 +4 \\ 3 \: upon \: 3 \: and \: 11 \div 3\)

this is the answer sharon

Answer:

√6(x−11)/6

Step-by-step explanation:

f^−1(x)=√6(x−11)/6

Answer:114Step-

Step-by-step explanation:

Answer: x = 114Step-by-step explanation:Angle A is equivalent to angle D because of the properties of parallelograms. So we know angle A is 66 degrees. Angles C and B also have the same measure because they are opposite angles. The sum of all four angle measures is 360 degrees. Therefore, you can write this equation:m<A + m<B + m<C + m<D = 360 Step 1) plug in the degree measure of each angle that you know. (I will represent angle C with “x”)66 + m<B + x + 66 = 360(We know that the m<B is the same as m<C, so we can plug in “x” for m<B)66 + x + x + 66 = 360(x + x is the same as 2x)66 + 2x + 66 = 360(66 + 66 = 132)132 + 2x = 360Step 2) solve for x by continuing with this equation: 132 + 2x = 360(Subtract 132 from both sides)2x = 228(Divide by 2 on both sides)x = 228/2(228/2 equals 114)x = 114Check:Add all four angle measures. It should add up to 360.66 + 114 + 114 + 66180 + 114 + 66294 + 66360Yay it worked! FYI: the angles that are across from each other in a parallelogram are always congruent. The sides that are opposite (across from) each other are also congruent. All 4 angles in a parallelogram will add up to 360 degrees. This info will help when you’re solving for the sides or angles of a parallelogram. Good luck!

Answer:

The equation for this is 15÷n+1

Step-by-step explanation:

Hope this helps!