The forces acting on a child sitting in a seat are described
by the free-body diagram shown.
What is the net force acting on the child?
0-100 N
Ο ΟΝ
Fx = 100 N
O 100 N
200N
F, = -100 N

Answers

Answer 1

Answer:

F-net = 0 N

Explanation:

When there is an unmoved object, we know that there is always a gravitational force present on the object that pushes it down on the ground. But according to Newton's 3rd law (there is always an equal and opposite force for any action), there is a force acting on the child to keep it from falling.


Related Questions

If a scientist wants to figure out how old a rock layer is, would it be useful to use a substance that takes a long time to break down (has a long half life), or a substance that breaks down quickly?

A.A substance that breaks down slowly, because then there won't be enough left to measure

B.A substance that breaks down slowly, because then there will be enough left to measure.

C.A substance that breaks down quickly, so it will be all gone and we'll know it's old

Answers

Answer:

B.

Explanation:

This is because if it has a long half-life then there will be enough rock left to be able to determine the age of the rock. It is not A. because if it has a long half-life there would be part of the substance left to determine the age. It is not C. because in order to study the substance, there must first be a substance left to study.

Hope this helps!

La alegría es la vacuna para eliminar la tristeza, pero para obtenerla, ¿qué se debe hacer? Explica:​

Answers

Solo estar con los que amamos nuestras familias nos asen feliz y sonreír


What is the momentum of an 80 kg runner moving at the speed of 2.5 m/s? Use the
exact value you obtain in a calculator.____kgm/s

Answers

Answer:

200 kgm/s

Explanation:

momentum = mass x velocity

The respiratory system - 2/3

6. what component of the respiratory system is commonly known as the windpipe?

pharynx
trachea
epiglottis
cricoid cartilage

7. which type of lung disease are people of all ages, young and old, equally susceptible to?

pneumonia
bronchitis
asthma
copd

8. the respiratory system's responsibilities include not just oxygen intake but also waste removal

true or false

9. the largest component of the lower respiratory system is the lungs

true or false

10. if a lining is ciliated, what is it covered in?

mucous
hair
skin
grooves

Answers

The answers to the respiratory questions are listed below:

6). Trachea7).  Pneumonia8). True 9).  False10). Hair

Meaning of a respiratory system

A respiratory system is a biological system found in both plants and animals, which includes organs and structures used for exchanging gas between the organisms and its environments.

A respiratory system is a network or chain or organs and tissues that enables breathing.

In conclusion, the respiratory system is one that is very important to understand.

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The refractive index of medium ‘X’ with respect to medium ‘Y’ is 2/3 and
refractive index of medium ‘Y’ with respect to medium ‘Z’ is 4/3. Find the refractive
index of medium ‘Z’ with respect to medium ‘X’.

Answers

To find the refractive index of medium 'Z' with respect to medium 'X' (n(Z/X)), we can use the formula:

n(Z/X) = n(Z/Y) * n(Y/X)

Given:

n(X/Y) = 2/3

n(Y/Z) = 4/3

Plugging these values into the formula, we get:

n(Z/X) = (4/3) * (2/3)

To simplify the expression, we multiply the numerators and denominators:

n(Z/X) = (4 * 2) / (3 * 3)

= 8 / 9

Therefore, the refractive index of medium 'Z' with respect to medium 'X' is 8/9.

Help please!!!

Do you think we always see the same side of the Moon?

Answers

Answer:

yess

Explanation:

"The Moon orbits Earth once every 27.3 days and spins on its axis once every 27.3 days. This means that although the Moon is rotating, it always keeps one face toward us. Known as “synchronous rotation,” this is why we only ever see the Moon's nearside from Earth."

The earth rotates once per day about an axis passing through the north and south poles, an axis that is perpendicular to the plane of the equator. Assuming the earth is a sphere with a radius of 6.38 106 m, determine the speed and centripetal acceleration of a person situated at each of the following.(a) the equatorm/sm/s^2(b) a latitude of 63.0° north of the equatorm/sm/s^2

Answers

a) The speed and centripetal acceleration of a person situated at the equator is 463.3 m/s and 3.39 m/s^2.

b)  The speed and centripetal acceleration of a person situated at the latitude of 63.0° north of the equator is 308.5 m/s and 2.06 m/s^2

(a) At the equator, a person is situated at a distance of 6.38 x 10^6 meters from the center of the Earth, and the radius of the Earth is the same at this point. The speed of the person can be calculated using the formula:

v = ωr

where ω is the angular velocity of the Earth, and r is the distance from the center of the Earth. The angular velocity of the Earth can be calculated as the angle swept per unit time, which is 2π radians per day or 7.27 x 10^-5 radians per second.

Substituting these values, we get:

v = 7.27 x 10^-5 x 6.38 x 10^6

v = 463.3 m/s

The centripetal acceleration can be calculated using the formula:

a = v^2/r

Substituting the values, we get:

a = (463.3)^2/6.38 x 10^6

a = 3.39 m/s^2

(b) At a latitude of 63.0° north, the person is situated at a distance of r = 6.38 x 10^6 x cos(63.0°) from the center of the Earth. The speed of the person can be calculated using the same formula as before:

v = ωr

Substituting the values, we get:

v = 7.27 x 10^-5 x 6.38 x 10^6 x cos(63.0°)

v = 308.5 m/s

The centripetal acceleration can be calculated using the same formula as before:

a = v^2/r

Substituting the values, we get:

a = (308.5)^2/(6.38 x 10^6 x cos(63.0°))

a = 2.06 m/s^2

In summary, the speed and centripetal acceleration of a person situated at the equator and a latitude of 63.0° north of the equator can be calculated using the formulas v = ωr and a = v^2/r, where ω is the angular velocity of the Earth, r is the distance from the center of the Earth, and v is the speed of the person.

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How far is the sun, alpha centauri A, Sirius B, Bernard's Star, Sirius A, and Proxima Centauri from the earth in light years

Answers

The distance of sun, alpha centauri A, Sirius B, Bernard's Star, Sirius A, and Proxima Centauri from the earth is 1.578 * \(10^{-5}\), 4.367, 8.611, 5.978, 8.611 and 4.264 light years.

The distance of the planet Earth from other celestial bodies are as mentioned below:

Sun = 1.578 * \(10^{-5}\) Light yearsAlpha Centauri A = 4.376 Light yearsSirius B = 8.611 Light yearsBernard's Star = 5.978 Light yearsSirius A = 8.611 Light yearsProxima Centauri = 4.264 Light years

A light year is measure of distance. It is distance covered by a light particle in a period of one year. Light travels at the speed of 3 * \(10^{8}\) m / s. So one light year will be equal to a distance of 9.46 trillion kilometers.

Therefore, the distance from Earth to

Sun = 1.578 * \(10^{-5}\) Light yearsAlpha Centauri A = 4.376 Light yearsSirius B = 8.611 Light yearsBernard's Star = 5.978 Light yearsSirius A = 8.611 Light yearsProxima Centauri = 4.264 Light years

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How much work is required to lift a 35-kg object from the ground 3.0-m into the air?
Also; How much Gravitational Potential Energy did the object gain?

Answers

The amount of work required to lift the object is 1029 J. And the amount of potential energy gained by the object is 1029 J.

What is work?

Work can be defined as the product of force and distance. The s.i unit of work is Joules (J).

To calculate the amount of work required to lift the object, we use the formula below.

Formula:

W = mgh........... Equation 1

Where:

P.E = work required to lift the objectm = mass of the objecth = height of the objectg = acceleration due to gravity

From the question,

Given:

m = 35 kgh = 3 mg = 9.8 m/s²

Substitute these values into equation 1

W = 35×3×9.8W = 1029 J.

The amount of gravitational potential energy gained by the object is the same s the amount of work required to lift the object

Therefore,

P.E = W = 1029 J

Hence, The amount of work required to lift the object is 1029 J. And the amount of potential energy gained by the object is 1029 J.

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Use DeMorgan's Theorem, as well as any other applicable rules of Boolean algebra, to simplify the following expression so there are no more complementation bars extending over multiple variables: \[ \

Answers

The expression to be simplified is, A + BC + ABCD. Using De Morgan's theorem, we can convert complementation bars extending over multiple variables into complementation bars over single variables. The De Morgan's theorem states that the complement of a product is equal to the sum of complements. De Morgan's Theorem:

 1.   (AB) = A + B2.  (A + B) = A B The steps to simplify the given expression using De Morgan's theorem are as follows: A + BC + ABCD = A + (BC + ABCD) = A + (BC). (ABCD) = A + (B + C) (A + B + C + D) = A + AB + AC + BC + BD = A + AC + BC + BD.

Hence, the simplified expression is A + AC + BC + BD. Thus, using DeMorgan's Theorem and other applicable rules of Boolean algebra, the given expression is simplified to A + AC + BC + BD.

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A car traveled 140 km from El Paso, TX to Dallas, TX in 2 hours. What was the car’s average speed in seconds?

Answers

Answer:

Explanation:

first get the velocity value in km/h

140/2=70km/h

to change the value (kilometers per hour) to meters per second divide by 3.6

70/3.6=19.44m/s

A 0.5 kg block slides along a horizontal frictionless surface at 2 m/s. it is brought to rest by compressing a very long spring of spring constant 800 n/m. the maximum spring compression is:

Answers

The maximum spring compression is: 0.05 m

We know that, Spring energy = Kinetic energy + Potential energy

i.e. \(\frac{1}{2} kx^{2} = \frac{1}{2} mv^{2} + mgh\)

where, k  = spring constant = 800 n/m

           m = mass of object = 0.5 kg

            v = velocity of object = 2m/s

            x = spring compression

Since it is brought to rest, it means it was in motion and it's potential energy was 0 , i.e. mgh = 0

Putting this values in above equation we get, x = 5 cm = 0.05 m

So, the maximum spring compression is: 0.05 m

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The distance a toy car travels over time is shown in the graph.
Motion of a Toy Car
Distance (m)
Time (1)
Which table best shows the average speed of the toy car at different time intervals?
А
Time (s)
Time (5)
Average
Speed (m/s)
1.0
Average
Speed (m/s)
2.0
0-2
0-2
2-4
0.5
2-4
3.0
4-6
0
4-6
3.0
Time (s)
Average
Speed (m/s)
Time (s)
Average
Speed (m/s)
0-2
2.0
1.0
2-4
0.75
2-4
0.75
4-6
0.75
4-6
0

Answers

Answer:

a toy car speed is about 2.5 to 3.5 mph

pls help me 6th grade science

pls help me 6th grade science

Answers

Answer: B

Explanation: Cause the energy is stored  as soon as the the car goes up the hill of the track gravity pulls the car down making it go at high speeds

Answer:

B. Its potential energy increases

Explanation:

As the car goes up, the potential energy increases. When it goes down the first hill, its kinetic energy will increase.

Activity: Solve each problem involving acceleration. Be sure to show all solutions and to use the correct units. 1. While traveling along a highway a driver slows from 45 m/s to 15 m/s in 12 seconds. What is the automobile's acceleration? 2. A biker accelerates at a rate of 7 m/s2. How long will it takes the biker to reach a speed of 18 m/s?

Answers

Answer:

1. a = - 2.5 m/s²

2. t = 2.57 s

Explanation:

1.

The acceleration of the driver can be found using the first equation of motion:

\(v_f = v_i + at\)

where,

vf = final speed = 15 m/s

vi = initial speed = 45 m/s

a = acceleration = ?

t = time = 12 s

Therefore,

\(15\ m/s = 45\ m/s +a(12\ s)\\\\a = \frac{15\ m/s-45\ m/s}{12\ s}\)

a = - 2.5 m/s²

negative sign indicates deceleration

2.

The time taken by the biker to accelerate can be found by using the first equation of motion again:

\(v_f = v_i + at\)

where,

vf = final speed = 18 m/s

vi = initial speed = 0 m/s

a = acceleration = 7 m/s²

t = time = ?

Therefore,

\(18\ m/s = 0\ m/s +(7\ m/s^2)t\\\\t = \frac{18\ m/s}{7\ m/s^2}\)

t = 2.57 s

if a light wave hits a smooth surface at an angle of incidence of 40 degrees the angle of reflection is

Answers

According to the law of reflection, when a light wave hits a smooth surface, the angle of reflection is equal to the angle of incidence. Therefore, if the angle of incidence is 40 degrees, the angle of reflection will also be 40 degrees.

The law of reflection states that the angle of incidence (the angle between the incident light ray and the normal to the surface) is equal to the angle of reflection (the angle between the reflected light ray and the normal to the surface). This law holds true for smooth surfaces, such as mirrors or still water.

In this case, when a light wave hits a smooth surface at an angle of incidence of 40 degrees, the angle of reflection will also be 40 degrees. The incident light ray and the reflected light ray will be on opposite sides of the normal to the surface, forming an equal angle with it.

Understanding the law of reflection is crucial in various applications, including optics, image formation, and the study of light behavior. It allows us to predict and analyze the behavior of light rays when they encounter reflective surfaces, enabling us to understand how images are formed and how light interacts with different materials.

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Question 2 (1 point) ✓ Saved
(3.03.b_Q2) NOTE: The same story problem is used for questions 1 - 5: In a
piston/cyclinder gas container, the piston starts with a inside gas volume of 3.0 cc
and a pressure of 0.8 atmosphere at room temp. The piston is pushed into the
cylinder, reducing the volume to 1.0 cc. The piston/cylinder is left to equilibrate
back to room temp before measuring the final pressure.
Which gas law formula should be used to solve this opportunity?
constant volume, initial P/T = final P/T
constant temperature, initial PV = final PV
constant pressure, initial V/T = final V/T
density = mass/volume

Answers

Answer:

The gas law formula that should be used to solve the opportunity is;

Constant temperature, initial P·V = final P·V

Explanation:

From the question we have;

The initial volume of the cylinder, v₁ = 3.0 cc

The initial pressure of the gas in the cylinder, p₁ = 0.8 atm

The initial temperature of the gas in the cylinder, T₁ = Room temperature

The final volume of the cylinder, v₂ = 1.0 cc

The final pressure of the gas in the cylinder = p₂

The final temperature of the gas in the cylinder, T₂ = Room temperature

The gas law formula that should be used to solve the opportunity is Boyle's law which states that at constant pressure the pressure, of a given mass of gas is inversely proportional to the volume of the gas

Mathematically, Boyle's law can be expressed as follows;

P ∝ V

∴ P₁·V₁ = P₂·V₂

Which gives;

Constant temperature, initial P·V = final P·V

A note of frequency 200Hz has a velocity of 400m/s. What is the wave length of the note ​

Answers

\(\lambda=\frac{v}{f}=\frac{400}{200}=2[m]\)

When energy is transferred between earth's system, some energy is lost to the surroundings in the form of _____________________. (select all that apply)

Answers

When energy is transferred between earth's system, some energy is lost to the surroundings in the form of

-light

-movement

-heat

-vibration

What is energy in earth's system?

Only a few factors account for the majority of the energy in the Earth system: solar energy, gravity, radioactive decay, and the rotation of the Earth. Many surface processes, including winds, currents, the hydrologic cycle, and the entire climate system, are powered by solar energy. Rivers and other materials flow downhill due to gravity, which also causes tides (due to the Moon's gravitational pull). The Earth's interior is heated by radioactive decay, while air and water currents are influenced by the forces of rotation.

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An object with a mass of 10kg accelerates 16 m/s2 when an unknown force is
applied to it. What is the amount of force?
160 N
9.8 m/s2
165.8 kg
1.6 N

Answers

Answer:

The answer is 160 N

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 10 × 16

We have the final answer as

160 N

Hope this helps you

for which colour of light is. the index of refraction of glass largest​

Answers

Answer:

don't know sorry for the irreverent answer..

Answer:

The index of refraction varies with frequency, it doesn't change as light travels from one medium to another, As violet colour has the shortest wavelength and so the refractive index is maximum for it.

how can we take advantage of waste materials​

Answers

Answer:

we can incinerate waste materials and use the product as fuel rather than dumping them. It may produce carbon dioxide but we can create a machine that can convert carbon into energy.

You are driving on a freeway posted for 65 mph. Traffic is heavy and moving at 35 mph. The best speed for you vehicle is most likelyA. 25 mphB. 30 mphC. 35 mph

Answers

Based on the information provided, the best speed for the vehicle would be around 30 mph. So, correct option is B.

Given the scenario, it is clear that traffic is heavy, and the speed of the vehicles is considerably less than the posted speed limit. It is important to maintain a safe and efficient speed to avoid accidents and to ensure smooth traffic flow.

This speed is a balance between moving too slowly and causing traffic disruptions and moving too fast, which can lead to unsafe conditions.

Driving at 25 mph may cause disruptions in traffic flow, and driving too slowly can be dangerous, especially on a busy freeway. On the other hand, driving at 35 mph may be too fast for the surrounding vehicles, leading to unsafe conditions and an increased risk of accidents.

Overall, the best course of action is to maintain a speed of around 30 mph, which allows for efficient traffic flow and minimizes the risk of accidents.

So, correct option is B.

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why decomposition of sugar on heating is an irreversible change.

Answers

Answer:

The heat of formation of the products of the heating of sugar, which is caramel is higher and due to the new complexes formed such there is increased change in free energy between the products and the reactants of the sucrose decomposition by heating, making the reaction is irreversible

Explanation:

Sugar, also known as sucrose, C₁₂H₂₂O₁₁, is a disaccharide made up two monosaccharides, fructose, C₆H₁₂O₆, and glucose, C₆H₁₂O₆ joined together by a glycosidic covalent bond as such the molecule of sugar has one less molecule of H₂O than the fructose and the glucose it is made of which on heating the sugar the glycosidic bonds break and due to deficiency in the amount of H₂O the fructose and glucose combine with themselves to form caramel which has a much lower hydrogen and oxygen proportion such as C₂₄H₂₆O₁₃, which is darker and contains free radicals making caramel sticky.

Therefore, the heat of formation of the caramel is higher and due to the formation of the complexes there is increased change in free energy between the products than the reactants of the decomposition of sugar by heating, therefore, the reaction is irreversible.

A uniform plank of length 5 m and weight 225 N rests horizontally on two supports with 1.1 m of the plank hanging over the right support. To what distance can a person weighing 450 kg walk, on the overhanging part of the plank, before it just begins to tip?

Answers

Answer: The plank will tip when the torque due to the weight of the person is greater than the torque due to the weight of the plank. The torque is given by the product of the force and the perpendicular distance to the pivot point (the left support).

Let x be the distance the person walks on the overhanging part of the plank, and let y be the perpendicular distance from the right support to the center of mass of the plank. Then:

y = (1/2) * 5 = 2.5 m (since the center of mass of a uniform plank is at its midpoint)

The weight of the plank is 225 N, acting at its center of mass, so the torque due to the weight of the plank is:

T_plank = 225 N * 2.5 m = 562.5 Nm

The weight of the person is 450 kg * 9.81 m/s^2 = 4414.5 N, acting at the end of the overhanging part of the plank. The perpendicular distance from the right support to the person is (1.1 - x) m. So the torque due to the weight of the person is:

T_person = 4414.5 N * (1.1 - x) m

The plank will just begin to tip when T_person = T_plank. Solving for x:

4414.5 N * (1.1 - x) m = 562.5 Nm

4845.95 N - 4414.5 Nx = 562.5 Nm

4414.5 Nx = 4283.45 Nm

x = 0.9704 m

Therefore, the person can walk a distance of 0.9704 m on the overhanging part of the plank before it just begins to tip.

Explanation:

If you began a trip at 60° west, 20° north and traveled 120° farther west and 50° south, your new position would be _______________________.

Answers

If you start at 60° west and 20° north and travel 120° west and 50° south, your new position would be approximately 180° west and 30° south.

Starting at 60° west and 20° north, moving 120° west means you will end up at 180° west, as you have traveled halfway around the globe in terms of longitude. The latitude remains unchanged since you did not move north or south. Then, traveling 50° south from the starting point takes you to 20° south. Therefore, your new position would be approximately 180° west and 30° south.

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Use the following information to calculate the gradient of River X. If the vertical change is 20 meters in 1 kilometer, then the gradient expressed in m/km is ______.

Answers

The gradient of River X expressed in m/km is 20 m/km.

Why do we compute gradient?

Any line or curve's gradient will reveal the pace at which one variable is changing in relation to another. In all mathematical fields, this idea is crucial.

By dividing the difference between the -coordinates by the difference between the -coordinates, the gradient of a line is calculated. This can also be referred to as the vertical divided by the horizontal or the change in divided by the change in.

A river's gradient is a measurement of how steeply it declines over a specific distance.

Gradient = vertical change / horizontal distance = 20 meters / 1 kilometer = 20 m/km

Therefore, the gradient of River X expressed in m/km is 20 m/km.

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Refer to Figure 22-15 to answer the following
questions.
a. What should the ammeter reading be?
b. What should the voltmeter reading be?
c. How much power is delivered to the resistor?
d. How much energy is delivered to the resistor
per hour?

Refer to Figure 22-15 to answer the followingquestions.a. What should the ammeter reading be?b. What

Answers

a. The ammeter reading should be I = V/R = 27V/9ohm = 3A.

b. The voltmeter reading should be 27V, since it is connected in parallel with the battery and measures the voltage across it.

c. The power delivered to the resistor can be calculated using P = VI = (I^2)*R = (3A)^2 * 9ohm = 27W.

d. The energy delivered to the resistor per hour can be calculated using E = Pt = 27W * 1 hour = 27 Wh.

What is an ammeter?

An ammeter is a measuring instrument used to measure electric current flowing through a circuit. It is typically connected in series with the circuit so that all the current flowing in the circuit passes through the ammeter. Ammeters can be analog or digital, and they are designed to measure different ranges of current. They are an essential tool for diagnosing and troubleshooting electrical problems, and they are commonly used in industrial, commercial, and residential applications.

What is a voltmeter?

A voltmeter is a measuring instrument used to measure the electric potential difference (voltage) between two points in an electrical circuit. It is typically connected in parallel with the circuit component or circuit section whose voltage is to be measured. When a voltage is present in the circuit, the voltmeter displays the measured value in volts, which can help to determine the performance or condition of the circuit.

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a. The ammeter reading should be I = V/R = 27V/9ohm = 3A.

b. The voltmeter reading should be 27V, since it is connected in parallel with the battery and measures the voltage across it.

c. The power delivered to the resistor can be calculated using P = VI = (I^2)*R = (3A)^2 * 9ohm = 27W.

d. The energy delivered to the resistor per hour can be calculated using E = Pt = 27W * 1 hour = 27 Wh.

What is an ammeter?

An ammeter is a measuring device used to determine the amount of electric current passing through a circuit. It is usually wired in series with the circuit so that all current passing through it goes through the ammeter. Ammeters can be analogue or digital, and they are used to detect various current levels. They are an indispensable instrument for diagnosing and troubleshooting electrical issues, and they are widely used in industrial, business, and domestic settings.

A voltmeter is a measuring device used to determine the difference in electric potential (voltage) between two locations in an electrical circuit. It is usually linked in parallel with the circuit component or portion whose voltage is to be measured. When a voltage is present in the circuit, the voltmeter shows the measured value in volts, which can aid in determining the circuit's performance or state.

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Let's Review
nerves.
1. Name the three main types of muscles:.
and
2. Which two types are involuntary muscles? Cardiac muscle and
Smooth
Muscle
3. Which type of muscle is attached to bones?
4. What special set of nerves controls smooth muscles?
5. Where in the body is cardiac muscle found?
6. What is the connective tissue that attaches muscles to bones?
7. The
is where the muscle is connected to the nonmoving bone.
is where the muscle is attached to the moving bone.
8. The.
9. Name two activities that are carried out by involuntary muscles.
10. Name three activities that are carried out by voluntary muscles..
LESSONS ON THE HUMAN BODY

Answers

1. The three main types of muscles are skeletal muscle, cardiac muscle, and smooth muscle.

2. The two types of muscles that are involuntary are cardiac muscle and smooth muscle.

3. Skeletal muscle is the type of muscle that is attached to bones.

4. Smooth muscles are controlled by the autonomic nervous system.

5. Cardiac muscle is found in the walls of the heart.

6. The connective tissue that attaches muscles to bones is called tendons.

7. The point where the muscle is connected to the nonmoving bone is called the origin, while the point where the muscle is attached to the moving bone is called the insertion.

8. The muscular system works in coordination with the skeletal system to allow movement, maintain posture, and generate body heat.

9. Two activities that are carried out by involuntary muscles are digestion (smooth muscles in the digestive tract) and regulation of blood pressure (smooth muscles in blood vessels).

10. Three activities that are carried out by voluntary muscles are walking, writing, and lifting weights. Voluntary muscles are under conscious control, allowing us to perform intentional movements.

1. The three major muscle types are skeletal muscle, cardiac muscle, and smooth muscle.

2. Two involuntary muscles are cardiac muscle and smooth muscle.

3. Skeletal muscles are muscles that are attached to bones.

4. Smooth muscle is controlled by the autonomic nervous system.

5. Myocardium lies in the walls of the heart. 6. The connective tissue that connects muscles to bones is called tendons.

7. The point where a muscle connects to a non-moving bone is called the origin, and the point where a muscle connects to a moving bone is called the insertion point.

8th place. The muscular system works in tandem with the skeletal system to enable movement, maintain posture, and generate body heat.

9. Two activities performed by involuntary muscles are digestion (smooth muscle of the gastrointestinal tract) and blood pressure regulation (smooth muscle of the blood vessels).

10. The three activities performed by voluntary muscles are walking, writing and weightlifting. Voluntary muscles are under conscious control and allow us to perform purposeful movements.  

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a plane is sitting on a runway, awaiting takeoff. on an adjacent parallel runway, another plane lands and passes the stationary plane at a speed of 45 m/s. the arriving plane has a length of 36 m. by looking out the window (very narrow), a passenger on the stationary plane can see the moving plane. for how long a time is the moving plane visible?

Answers

The moving plane is visible for 0.8 second.

What is speed?

Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity. SI unit of speed be meter/second and CGS unit of speed be cm/s.

Given that:

Another plane lands and passes the stationary plane at a speed: v =  45 m/s.

length of the arriving plane be : L = 36 m.

So, Time the moving plane remains visible be: t = L/v = 36/45 s = 0.8 second.

Hence, the moving plane is visible for 0.8 second.

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