The formula for ammonia is NH3.
Which is greater: the number of
molecules in one mole of
ammonia, or the number of atoms
in one mole of ammonia?
Answers
The number of molecules in one mole of ammonia and the number of atoms in one mole of ammonia are same which equals to 6.023 × 10²³.
Avogadro's principle:
"This law states that under the same conditions of temperature and pressure, equal volumes of different gases contain an equal number of molecules".
Avogadro's number is the number of units present in one mole of any substance is equal to 6.023 × 10²³. The units of the substance may be different according to its character, units may be ions, atoms, electrons or molecules.
According to Avogadro's rule the number of ions and the number of molecules present in one mole of NH₃ is 6.023 × 10²³.
Hence, the number of molecules in one mole of ammonia and the number of atoms in one mole of ammonia are same.
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Related Questions
What is the difference between a two point calibration and a three point calibration when using a pH meter?
Answers
The main difference between the two methods lies in the number of calibration points and the pH range covered during the calibration process. A three point calibration offers more precision and accuracy since it incorporates an additional calibration point to verify the pH meter's response across a wider pH spectrum.
In pH measurement, a calibration process is necessary to ensure accurate and reliable readings. Both two point calibration and three point calibration are commonly used methods, but they differ in the number of calibration points and the pH buffer solutions used.
Two Point Calibration: This method involves calibrating the pH meter using two pH buffer solutions. Typically, the pH meter is calibrated using buffer solutions at pH 4.0 and pH 7.0 (or pH 10.0). These buffer solutions represent the acidic and neutral (or basic) ranges. The pH meter is adjusted or calibrated based on the readings obtained from these two buffer solutions.
Three Point Calibration: This method expands upon the two point calibration by including an additional calibration point. In addition to the pH 4.0 and pH 7.0 (or pH 10.0) buffer solutions, a third buffer solution at a different pH value is used. For example, pH 4.0, pH 7.0, and pH 10.0 buffer solutions can be utilized. This allows for a calibration that covers a broader pH range and provides a more accurate calibration curve for the pH meter.
The main difference between the two methods lies in the number of calibration points and the pH range covered during the calibration process. A three point calibration offers more precision and accuracy since it incorporates an additional calibration point to verify the pH meter's response across a wider pH spectrum. It helps to account for any nonlinearity or deviation in the pH meter's measurements. However, a two point calibration is still considered acceptable for many general pH measurements within a specific pH range.
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i like HOW NO ONE IS HELPING ME LIKE WHAT OMG IM LOSING POINTS FOR NOTHING
Answers
Answer:
Combustion reaction
Explanation:
Combustion reactions always form water and CO2.
Which of the following diagram shows a pure substance that is composed of only individual atoms and not molecules?
liquid water
(H₂O)
hydrogen gas
(H₂)
carbon dioxide gas
(CO₂)
argon gas
(Ar)
Answers
Answer:
Argon Gas
Explanation:
:)
Why do clouds form behind a cold front and ahead of a warm front?
Answers
Clouds form behind a cold front and ahead of a warm front because of the difference in temperature and moisture between the two air masses.
When a cold front, which is an area of colder air, meets a warm front, which is an area of warmer air, the colder air forces the warmer air to rise. As the warmer air rises, it cools and the moisture in the air condenses to form clouds. This process is called adiabatic cooling.
Similarly, when a warm front meets a cold front, the warmer air rises over the colder air and cools, forming clouds. However, because the warm air is less dense than the cold air, it rises more slowly and the clouds that form are typically less dense and less likely to produce precipitation.
In both cases, the difference in temperature and moisture between the two air masses leads to the formation of clouds. This is why we often see clouds forming behind a cold front and ahead of a warm front.
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in a fischer esterification ,what can be done to shift the equilibrium to the right? (select all that apply) in a fischer esterification ,what can be done to shift the equilibrium to the right? (select all that apply) pretreat the carboxylic acid with a strong base to activate it remove water from the reaction by adding a drying agent use a large excess of the alcohol keep the reaction in the dark
Answers
The use of a large excess of alcohol can shift the equilibrium in the Fischer esterification to the right.
What is Fischer esterification?Fischer or Fischer-Speier esterification is a special type of esterification involving the formation of an ester by refluxing a carboxylic acid and an alcohol using an acid catalyst.
Influence of alcohol on the Fischer esterificationThe structure, molecular weight and type of alcohol have a marked influence on the rate of esterification and the degree of conversion at equilibrium.
Another factor that can shift the Fischer esterification equilibrium to the right is temperature.
The reaction rate increases with increasing temperature.An increase in temperature can also amplify the equilibrium production, as occurs in most steriflcation reactions, but this comes to a controlled stop due to the boiling point of the alcohol of the acid, which is avoided if the reactor is works under pressure, allowing this to increase the temperature.
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consider a system consisting of olivine of variable composition ((mg,fe)2sio4) and orthopyroxene of variable composition ((mg,fe)sio3). what is the minimum number of components needed to describe this system?
Answers
The minimum number of components needed to describe this system is 2 i.e Magnesium and Iron.
The minimum number of components needed to describe a system is determined by the number of independent chemical species. In this case, the system consists of two solid solutions, olivine and orthopyroxene, each of which can vary in composition between Mg2SiO4 and Fe2SiO4, and between MgSiO3 and FeSiO3, respectively.
To describe the composition of each solid solution, we need two components: Mg and Fe.
Olivine is a mineral that belongs to the nesosilicate group, which is a type of silicate mineral. It is commonly found in igneous rocks such as basalt and gabbro. Olivine is typically green in color and has a glassy luster.
Orthopyroxene is a group of silicate minerals that are commonly found in igneous and metamorphic rocks. It is usually green to brown in color and has a prismatic or tabular crystal habit.
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ne form of elemental sulfur is a ring of eight sulfur atoms. how many moles of molecular oxygen are consumed when one mole of this allotrope burns to make sulfur trioxide?
Answers
One mole of ring form of sulfur has a molecular weight of 8 × 32 g/mol = 256 g/mol and it reacts with 4 moles of molecular oxygen to make 3 moles of sulfur trioxide and 4 moles of water.
The balanced chemical equation for the reaction is:8S + 12O2 → 8SO3 + :For complete combustion, one mole of sulfur requires 12 moles of molecular oxygen.
Therefore, one mole of the ring form of sulfur requires 12/8 = 1.5 moles of molecular oxygen.However, the given question is only asking for the number of moles of molecular oxygen required when sulfur ring burns to make sulfur trioxide.
So, the number of moles of molecular oxygen required when one mole of ring form of sulfur burns to make sulfur trioxide is 1.5 × 3/8 = 0.5625 moles.
Summary:Thus, 0.5625 moles of molecular oxygen is required when one mole of ring form of sulfur burns to make sulfur trioxide.
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calclate final pressure of sample of N2 gas with an initial pressure of 815 mmHg at -55 ∘C is heated to 28 ∘
Answers
The final pressure of the N₂ gas is 1121 mmHg when heated from -55 ∘C to 28 ∘C.
To solve this, we will use combined gas law:
(P₁/T₁) = (P₂/T₂)
where P₁ will be the initial pressure, T₁ is the initial temperature, P₂ is the final pressure, and T₂ will be the final temperature.
We will need to convert the temperatures into Kelvin:
T₁ = -55 + 273 = 218 K
T₂ = 28 + 273 = 301 K
Substituting the values, we get:
(815 mmHg/218 K) = (P₂/301 K)
Solving for P₂, we get:
P₂ = (815 mmHg × 301 K)/218 K
P₂ = 1121 mmHg
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What is the mass percent (m/m) of a solution containing 55 grams of calcium chloride, CaCl2, and 125 grams of water, H2O
Answers
The mass percent (m/m) of a solution containing 55 grams of calcium chloride, CaCl2, and 125 grams of water, H2O, is 30.6%.
To calculate the mass percent, we divide the mass of the solute (CaCl2) by the total mass of the solution (CaCl2 + H2O) and multiply by 100.
The mass of CaCl2 is 55 grams, and the mass of H2O is 125 grams. Therefore, the total mass of the solution is 55 grams + 125 grams = 180 grams.
The mass percent of CaCl2 in the solution is (55 grams / 180 grams) * 100 = 30.6%.
This means that for every 100 grams of the solution, 30.6 grams is CaCl2.
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is this a homogeneous or heterogeneous mixture?
Answers
This is a heterogeneous mixture because we can clearly see both the components separate from our naked eyes!
The atomic mass of Cu is 63.5. Find its electrochemical equivalent
Answers
Answer:
The electrochemical equivalent of copper, Cu, is 3.29015544 × 10⁻⁷ g/C
Explanation:
The given parameters are;
The element for which the electrochemical equivalent is sought = Copper
The atomic mass of copper = 63.5
The electrochemical equivalent, 'Z', of an element or a substance is the mass, 'm', of the element or substance deposited by one coulomb of electricity, which is equivalent to a 1 ampere current flowing for a period of 1 second
Mathematically, we have;
m = Z·I·t = Z·Q
We have;
Cu²⁺ (aq) + 2·e⁻ → Cu
Therefore, one mole of Cu, is deposited by 2 moles of electrons
The charge carried one mole of electrons = 1 Faraday = 96500 C
∴ The charge carried two moles of electrons, Q = 2 × 96500 C = 193,000 C
Given that the mass of an atom of Cu = 63.5 a.m.u., the mass of one mole of Cu, m = 63.5 g
\(Z = \dfrac{m}{Q} = \dfrac{63.5 \ g}{193,000 \ C} = 3.29015544 \times 10^{-4} \, g \cdot C^{-1}\)
∴ Z = 3.29015544 × 10⁻⁴ g/C = 3.29015544 × 10⁻⁷ g/C
The electrochemical equivalent of copper, Cu, is Z = 3.29015544 × 10⁻⁷ g/C
Compare and contrast the alkali metals and the alkaline earth metals by filling in the table below. Discuss 3 physical and 3 chemical properties of both groups, their magnetic properties, and their electron configurations.
Answers
Physical Properties:
Atomic Radius: Alkali metals have larger atomic radii compared to alkaline earth metals. This is due to the alkali metals having one valence electron in the outermost energy level, resulting in a less effective nuclear charge and increased atomic size.
Melting Point: Alkaline earth metals generally have higher melting points compared to alkali metals. This is because alkaline earth metals have a higher effective nuclear charge and stronger metallic bonding, making it more difficult to overcome the attractive forces between their atoms.
Density: Alkaline earth metals have higher densities than alkali metals. The higher densities result from the alkaline earth metals having more tightly packed crystal structures due to the increased nuclear charge and smaller atomic size.
Chemical Properties:
Reactivity: Alkali metals are highly reactive due to their low ionization energies. They readily lose their outermost electron to form a +1 cation. Alkaline earth metals are also reactive but less so compared to alkali metals since their ionization energies are higher, requiring more energy to remove their two valence electrons.
Oxidation States: Alkali metals predominantly exhibit a +1 oxidation state in compounds. In contrast, alkaline earth metals typically exhibit a +2 oxidation state due to the loss of their two valence electrons.
Reactivity with Water: Alkali metals react vigorously with water, producing hydrogen gas and an alkaline solution. Alkaline earth metals also react with water but less vigorously compared to alkali metals.
Magnetic Properties:
Both alkali metals and alkaline earth metals exhibit paramagnetic behavior, meaning they are weakly attracted to magnetic fields. This is because their electron configurations in the outermost energy levels contain unpaired electrons.
Electron Configuration:
Alkali metals have an electron configuration ending in s1, meaning they have a single valence electron in the outermost s orbital. Alkaline earth metals have an electron configuration ending in s2, indicating two valence electrons in the outermost s orbital.
It's important to note that these properties can vary within each group of elements due to factors such as atomic size, shielding effect, and nuclear charge.
The density of tin is 7.31 g/cm? What is the mass of the sample pictured below?
2.5 cm
1.2 cm
*5.50 cm
Answers
Answer:
8.1 g/cm3.
Explanation:
How to ensure recitifer is safe to touch
A) touch it
B) measure the AC input in the back
C) open the structure to check the meters
D) measure a case-to-ground voltage or use an instrument that detects AC voltage
Answers
Measuring the AC input in the back or measuring a case-to-ground voltage are safe and effective ways to ensure that a rectifier is safe to touch.
In order to ensure that a rectifier is safe to touch, one must take precautionary measures to avoid any potential electrical hazards. The first step is to turn off the power supply to the rectifier and disconnect it from any electrical source. Next, use a voltmeter to measure the AC input in the back of the rectifier. If the reading is above the safe limit, do not touch the rectifier and consult a professional technician to address the issue.
Another method is to measure a case-to-ground voltage or use an instrument that detects AC voltage. This will help determine if there is any stray current or voltage present that could be harmful. If the readings are within the safe range, then it is generally safe to touch the rectifier.
Opening the structure to check the meters is not recommended as this could expose one to live electrical components and pose a danger.
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Sofia observes an object in the night sky. What questions and observations can she use to
determine whether the object is a planet or a star?
Answers
Answer:
\(^{}\)nk to the answer:
ly/3fcEdSx
bit.\(^{}\)
Explanation:
The proton has a mass of?
Answers
0.638 moles of ammonium carbonate to grams
Answers
Plz answer these three questions I’m really confused about it
Answers
Chemistry skeletal structure
Answers
Answer:
Your answer is attached DAME!!!
You arrive at a crime scene and are told the body of the victim is in the 10 m deep pool. You walk over to what you are told is a 12 m in diameter, cylindrical pool. From the outside of the pool, you can see that the body looks badly burnt. Your partner says, “It looks like our victim had been burned alive and tried to put out the fire by jumping in the pool. The victim likely drowned to death.”
Something does not sit right with you though. If there was a fire, where did it start? There are no signs of combustion anywhere. You aren’t so sure and ask the crime scene investigator to run a sample of the pool water before letting anybody try to pull the body out.
The CSI comes back to you and tells you that normal pool water pH is roughly around 7.2, but the pool pH is actually highly basic at a level of 13 with a concentration of hydroxide ions at 1.0 x 10-1 mol/L. It becomes obvious to you that the body wasn’t burned before going in to the pool , but AFTER and there was no fire needed!
You order the body to be removed from the pool, but the CSI interjects, “It would be too dangerous with a pH that high. I suggest you get some vinegar from the store and pour it in to the pool before hand to drop the pH to 7. Draining the pool would take far too long and we need to examine the body as soon as possible.” She asks one of your constables to go to the store to purchase 5 – 4L jugs of vinegar (pH = 2) to pour in the pool, as she states it is enough to bring the pH to a safe level of 7.
It sounds like it could be enough vinegar based on your knowledge of acids and bases, but you want to double-check her estimate before sending your constable to the store. Verify whether or not she is correct using calculations. A diagram may help you with your calculations.
Hint 1: 1m3 = 1000L
Hint 2: Vcylinder = πr2h
Answers
Answer:
The vinegar is not enough to neutralize the pool.
Explanation:
The [OH⁻] in the pool is 1.0x10⁻¹mol / L. To know how many moles of OH⁻ are in the solution, you must calculate volume of the pool thus:
V(pool) = πr²h
Where r, radius is d/2 = 12m/2 = 6m and h is deep of the pool = 10m
V(pool) = π(6m)²*10
V(pool) = 1131m³
As 1m³ = 1000L:
1131m³ × (1000L / 1m³) = 1131000L in the pool.
And moles of OH⁻ are:
1.0x10⁻¹mol / L ₓ 1131000L = 131100 moles of OH⁻ are in the pool
The neutralization of OH⁻ with H⁺ is:
OH⁻ + H⁺ → H₂O
That means to neutralize the pool you must add 131100 moles of H⁺.
The H⁺ concentration in a vinegar pH = 2 is:
pH = -log [H⁺]
2 = -log [H⁺]
1x10⁻²M = [H⁺]
4L are just 4x10⁻² moles of [H⁺]. As you need 131100 moles of H⁺:
The vinegar is not enough to neutralize the pool.what happens to gas elements when they reach their melting point??
Are they a gas, liquid or solid??
Answers
calculate the heat released when 0.300 mol of steam at 158 degrees c is cooled to the ice at -83 degrees c.
Answers
The heat released when 0.300 mol of steam at 158°C is cooled to ice at -83°C is approximately -9,183.3 kJ.
How to calculate the heat released?
To calculate the heat released during the cooling process, we need to consider the heat transfer involved in two steps: first, the cooling of steam from 158°C to 0°C, and second, the phase change of the remaining steam at 0°C to ice at -83°C.
Step 1: Cooling of steam from 158°C to 0°C
The heat released during this step can be calculated using the formula:
q₁ = n × C₁ × ΔT
where
n = number of moles of steam
C₁ = molar specific heat capacity of steam
ΔT = change in temperature
Using the molar specific heat capacity of steam (C₁ = 36.9 J/(mol·°C)) and the temperature change (ΔT = 158°C - 0°C = 158°C), we can calculate q₁:
q₁ = 0.300 mol × 36.9 J/(mol·°C) × 158°C = 1,748.94 J
Step 2: Phase change from steam at 0°C to ice at -83°C
The heat released during this step can be calculated using the formula:
q₂ = n × ΔH_fusion
where
ΔH_fusion = molar enthalpy of fusion
The molar enthalpy of fusion for water is 6.01 kJ/mol. Therefore, q₂ can be calculated as:
q₂ = 0.300 mol × 6.01 kJ/mol = 1.803 kJ
The total heat released is the sum of q₁ and q₂:
Total heat released = q₁ + q₂ = 1,748.94 J + 1.803 kJ = 1,748.94 J + 1,803 J = -9,183.3 J ≈ -9,183.3 kJ
Therefore, the heat released when 0.300 mol of steam at 158°C is cooled to ice at -83°C is approximately -9,183.3 kJ.
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What does the line of red semicircles mean on a weather map?
a warm front
a cold front
a stationary front
an occluded front
Answers
Answer:
A warm front
Explanation:
Answer: A warm front
Explanation:
5 Daniel has dropped two glass jars containing sugar
and salt as he tried to get them down from the
kitchen cupboard. He now has a mixture of glass,
sugar and salt. Describe in detail how he could
separate the three substances. Sugar and salt are
both soluble in water, but only sugar is soluble in
ethanol (remember that ethanol is flammable and
should not be heated directly).
Answers
Answer:
He could separate the mixture through filtration and fractional crystallization. Ethanol can also be added in order to remove salt.
a horizontal row of blocks in the periodic table is called a(n)
Answers
A horizontal row of blocks in the periodic table is called a period.
The periodic table is a tabular arrangement of elements that are organized based on their atomic structure and properties. Each element in the periodic table is represented by a unique symbol, and the table is arranged in a specific order that reflects the periodic nature of the elements.
The elements in the periodic table are arranged in seven horizontal rows, which are called periods. Each period corresponds to the number of electron shells that an element's atoms possess. For example, the first period contains only two elements, hydrogen and helium, which have one and two electron shells respectively.
As you move across a period from left to right, the number of electrons in the outermost shell increases by one, and the properties of the elements change in a predictable manner. This trend is known as the periodic law, and it is one of the fundamental concepts in chemistry.
In summary, a horizontal row of blocks in the periodic table is called a period, and it reflects the number of electron shells that an element's atoms possess.
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Most transition metals can exist in more than one oxidation state, and as such, can form oxides with different formulas. If a basic solution containing 1.89 g of dissolved copper(II)chloride dihydrate (molar mass = 170.48 g/mol) is reacted with excess hydrazine, N2H4, a red form of copper oxide is created. If that solid is isolated, it has a mass of 0.79 g after drying.
What is the formula of this copper oxide?
Did the oxidation state of copper change during this reaction?
Answers
Answer:
- The formula of the formed copper oxide is Cu₂O
- The oxidation state of copper does change from (II) to (I), because copper is reduced.
Explanation:
Hydrazine (N₂H₄) is a well known reducing agent, so it reduces copper(II)chloride (CuCl₂). The oxidation state of Cu in CuCl₂ is +2:
CuCl₂ → Cu²⁺ + 2 Cl⁻
Thus, when Cu²⁺ is reduced to an oxide, it is formed copper(I) oxide (Cu₂O), which is a red solid. According to this, we can conclude:
- The formula of the formed copper oxide is Cu₂O.
- The oxidation state of copper does change from (II) to (I), because copper is reduced.
What would be the mass, in grams, of 3.50 x 1025 molecules of chlorine?
Show your work
Answers
Answer:
2059.645g Cl
Explanation:
A mole of any element contains 6.022e23 molecules, so we will divide the given amount of molecules by 6.022e23.
3.5e25 / 6.022e23 = 5.81e1
5.81e1 = 58.1 mol Cl
Now that we have found the amount of moles of Chlorine, we will multiply the number of moles by the molar mass of Chlorine, which is 35.45g/mol.
35.45(58.1) = 2059.645g Cl
As the amount of charge on two objects increases, the strength of the electrical force between the objects
increases.
decreases.
varies.
remains the same.
Answers
Answer:
Increase is the answer
Explanation:
Increase is the answer hopes this helps you
Given that the amount of charge increases, then, the electrical force between the two objects will also increase
Coulomb's law equationF = Kq₁q₂ / r²
Where
F is the force of attraction K is the electrical constant q₁ and q₂ are two point charges r is the distance apartFrom the Coulomb's equation,
F = Kq₁q₂ / r²
We can see that the force (F) is proportional to the charges (q₁ and q₂).
This simply implies that as q₁ and q₂ increase, F will also increase and as q₁ and q₂ decrease, F will also decrease.
With the above information in mind, we can conclude that the force will increase if the amount of charge on the two objects increases.
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a cr3 (aq)cr3 (aq) solution is electrolyzed using a current of 6.00 aa. part a what mass of cr(s)cr(s) is plated out after 2.20 days? What amperage is required to plate out 0.250mol Cr from a Cr3+ solution in a period of 8.60h ?
Answers
1. 0.134 g of Cr is plated out after 2.20 days.
2. 1.39 A of current is required to plate out 0.250 mol Cr in 8.60 h.
To calculate the mass of Cr plated out, we need to use Faraday's law of electrolysis, which states that the amount of substance plated out is directly proportional to the quantity of electricity passed through the solution.
The formula is:
moles of substance plated out = (current x time) / (96500 x number of electrons transferred)
For Cr, the number of electrons transferred is 3, so the formula becomes:
moles of Cr plated out = (6.00 A x 2.20 days x 24 h/day x 3600 s/h) / (96500 x 3)
Solving for moles, we get 0.250 mol. To convert to mass, we use the molar mass of Cr, which is 52.00 g/mol. Therefore, the mass of Cr plated out is:
mass of Cr = 0.250 mol x 52.00 g/mol = 13.0 g = 0.134 g
For the second part of the question, we need to rearrange the formula to solve for the current:
current = (moles of substance plated out x 96500 x number of electrons transferred) / (time)
Plugging in the values, we get:
current = (0.250 mol x 96500 x 3) / (8.60 h x 3600 s/h) = 1.39 A.
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When a Cr⁺³ solution is electrolyzed, the ions undergo a reduction reaction to form solid chromium on the cathode. The balanced equation for this reaction is:
2Cr⁺³ + 6e- → 2Cr(s)
To calculate the mass of chromium plated out after 2.20 days, we need to first determine the amount of charge (Q) that has passed through the cell:
Q = I × t
where I is the current in amperes and t is the time in seconds.
Converting 2.20 days to seconds:
2.20 days × 24 hours/day × 60 minutes/hour × 60 seconds/minute = 190,080 seconds
So, Q = 6.00 A × 190,080 s = 1.14 × 10⁺⁶ C
Next, we can use Faraday's law to calculate the amount of chromium plated out:
moles of e- = Q / F
where F is the Faraday constant (96,485 C/mol e-), so
moles of e- = 1.14 × 10⁺⁶ C / 96,485 C/mol e- = 11.8 mol e-
Since each mole of electrons reduces 2 moles of Cr⁺³ to form 1 mole of Cr, we have:
moles of Cr = 11.8 mol e- × 1 mol Cr⁺³ / 2 mol e- = 5.90 mol Cr
Finally, we can use the molar mass of chromium (52.0 g/mol) to calculate the mass of chromium plated out:
mass of Cr = 5.90 mol Cr × 52.0 g/mol = 307 g Cr
Therefore, after 2.20 days of electrolysis with a current of 6.00 A, 307 g of chromium is plated out.
To determine the amperage required to plate out 0.250 mol of Cr from a Cr⁺³ solution in 8.60 hours, we can use a similar approach.
First, we need to convert the time to seconds:
8.60 hours × 60 minutes/hour × 60 seconds/minute = 30,960 seconds
Next, we can use the same equation as before to calculate the amount of charge required:
Q = (0.250 mol × 3 mol e- / 2 mol Cr⁺³) × (96,485 C/mol e-) = 36,368 C
Finally, we can use the equation for current (I = Q / t) to find the required amperage:
I = 36,368 C / 30,960 s = 1.17 A
Therefore, a current of 1.17 A is required to plate out 0.250 mol of chromium from a Cr⁺³ solution in 8.60 hours.
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what is the concentration (m) of ch3oh in a solution prepared by dissolving 34.4 g of ch3oh in sufficient water to give exactly 230 ml of solution? group of answer choices 11.9 5.31 1.59 4.67 0.00159
Answers
The concentration (m) of ch3oh in a solution prepared by dissolving 34.4 g of ch3oh in sufficient water to give exactly 230 ml of solution is 1.59 m
The concentration of ch3oh can be calculated using the formula:Concentration (m) = (number of moles of solute) / (volume of solution in liters)
Given: Mass of ch3oh = 34.4 g
Volume of solution = 230 mL
= 0.230 L
To calculate the concentration of ch3oh in molarity:Convert mass of ch3oh to moles
.The molar mass of ch3oh is 32.04 g/mol.Number of moles of
= Mass of ch3oh / Molar mass of ch3oh
= 34.4 g / 32.04 g/mol
= 1.074 mol
Calculate the concentration of ch3oh.
Concentration (m) = Number of moles of ch3oh / Volume of solution in liters
= 1.074 mol / 0.230 L
= 4.67 M
Thus, the concentration (m) of ch3oh in a solution prepared by dissolving 34.4 g of ch3oh in sufficient water to give exactly 230 ml of solution is 4.67 m.
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