The graph of a nonlinear function is shown on the coordinate plane. In the graph, y is a function of x. When the input of the function is -3, what is the output of the function?

Answer:

x=30

Step-by-step explanation:

36/12=3

3*10=30

Answer:

We know that the constant is 3, the problem it is asking is what is the value of x and that the constant can be a decimal if you are finding the constant from smallest to largest or a whole number if you are going from largest to smallest.

Step-by-step explanation:

1 & 2: to find the constant you can divide 36 by 12 to get 3 then multiply 10 by 3 to get x which is 30.

3: smallest to largest=0.3

largest to smallest=3

Hope this helps!!! :)

Answer: Given that Li is making beaded necklaces for each necklace, she uses 27 spacers, plus 5 beads per inch of necklace length.

The equation to find how many beads Li needs for each necklace can be obtained as follows:

A. The input variable is the number of inches of the necklace length (x).

B. The output variable is the number of beads Li needs for each necklace (y).

C. The required equation is given by

y = 5x

Step-by-step explanation:

Answer:

140

Step-by-step explanation:

80 Divied by 4 is 20

SO Each Pair Is 20

7 x 20 = 140

Answer:

140

Step-by-step explanation:

It would be $20 a pair.

\( \large \bf \implies{15}\)

\(\bf \longrightarrow((2 + 4 \times 2) - 5) \times 3\)

Step 1) ; Calculate the product or quotient

\(\bf \longrightarrow((2 + 8) - 5) \times 3\)

Step 2) ; Calculate the sum or difference

\(\bf \longrightarrow(10 - 5) \times 3\)

Step 3) : Calculate the sum or difference

\(\bf \longrightarrow5 \times 3\)

Step 4) : Calculate the product or quotient

\(\bf \longrightarrow15\)

Answer:

V ≈ 56.55 cm³

Step-by-step explanation:

the volume (V) of a cone is calculated as

V = \(\frac{1}{3}\) πr²h ( r is the radius and h the height )

here r = 3 and h = 6 , then

V = \(\frac{1}{3}\) π × 3² × 6

   = \(\frac{1}{3}\) π × 9 × 6

   = \(\frac{1}{3}\) π × 54

   = π × 18

   = 18π

   ≈56.55 cm³ ( to the nearest hundredth )

The value of the function F(3) = 44.

To evaluate the given function, F(x) = 4x² + 5x - 7, for a value of x, substitute the value of x into the function and simplify.

Substituting the value of t for x in the function gives F(t) = 4t² + 5t - 7.

To evaluate F(t), you will need to substitute t into the function and then simplify your result.

So, the answer is option (D) 4t² - 23t + 2.

The steps involved in evaluating F(x) = 4x² + 5x - 7 for a value of x are given below:

Substitute t for x in the function as follows: F(t) = 4t² + 5t - 7

Simplify the expression for F(t) by substituting the value of t in the expression.

For instance, if t = 3, then we substitute 3 for t in the expression to get: F(3) = 4(3)² + 5(3) - 7 = 4(9) + 15 - 7 = 36 + 8 = 44Therefore, F(3) = 44.

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Answer:

17.2

hi, how is your day?

Answer: 17.2

Step-by-step explanation:

True. BCNF (Boyce-Codd Normal Form) decomposition guarantees that we can still verify all original functional dependencies (FDs) without needing to perform joins.

BCNF decomposition ensures that the resulting relations have no non-trivial FDs that violate BCNF, which means all FDs in the original relation are preserved in the decomposed relations. Therefore, we can still verify all original FDs in the decomposed relations without the need to perform joins.

The statement "BCNF decomposition guarantees that we can still verify all original FDs without needing to perform joins" is true. BCNF (Boyce-Codd Normal Form) decomposition ensures the preservation of all original functional dependencies (FDs) without requiring additional join operations.

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Answer:

3rd one

Step-by-step explanation:

Answer:

Step-by-step explanation:

They are different numbers:

0.269 + 50.9 = 51.169

0.26 + 50.9 = 51.16

The point (9, -7) is the only solution to the system of linear inequalities given.

To determine which point would be a solution to the system of linear inequalities, let's substitute the given points into the inequalities and see which point satisfies both inequalities.

The system of linear inequalities is:

y > -4x + 6

y > (1/3)x - 7

Let's test each given point:

For the point (9, -7):

Substituting the values into the inequalities:

-7 > -4(9) + 6

-7 > -36 + 6

-7 > -30 (True)

-7 > (1/3)(9) - 7

-7 > 3 - 7

-7 > -4 (True)

Since both inequalities are true for the point (9, -7), it is a solution to the system of linear inequalities.

For the point (-12, -2):

Substituting the values into the inequalities:

-2 > -4(-12) + 6

-2 > 48 + 6

-2 > 54 (False)

-2 > (1/3)(-12) - 7

-2 > -4 - 7

-2 > -11 (False)

Since both inequalities are false for the point (-12, -2), it is not a solution to the system of linear inequalities.

For the point (12, 1):

Substituting the values into the inequalities:

1 > -4(12) + 6

1 > -48 + 6

1 > -42 (True)

1 > (1/3)(12) - 7

1 > 4 - 7

1 > -3 (True)

Since both inequalities are true for the point (12, 1), it is a solution to the system of linear inequalities.

For the point (-12, -7):

Substituting the values into the inequalities:

-7 > -4(-12) + 6

-7 > 48 + 6

-7 > 54 (False)

-7 > (1/3)(-12) - 7

-7 > -4 - 7

-7 > -11 (True)

Since one inequality is true and the other is false for the point (-12, -7), it is not a solution to the system of linear inequalities.

In conclusion, the point (9, -7) is the only solution to the system of linear inequalities given.

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The position of the mass after t seconds is: x(t) = 1.41 * cos(1.77 * t) meters. We can calculate it in the following manner.

The force constant of the spring can be calculated using the formula:

F = -kx

Where F is the force applied, x is the displacement from the equilibrium position, and k is the force constant.

Rearranging the formula, we get:

k = -F/x

Substituting the given values, we get:

k = -10 N / 0.4 m = -25 N/m

The equation of motion for the mass attached to the spring is:

mx'' + kx = 0

Where m is the mass of the object, x'' is the second derivative of displacement with respect to time, and k is the force constant of the spring.

Substituting the given values, we get:

8x'' + (-25)x = 0

This is a second-order homogeneous differential equation with constant coefficients, and its general solution is:

x(t) = A cos(5t) + B sin(5t)

Where A and B are constants determined by the initial conditions.

To find A and B, we use the initial displacement and velocity:

x(0) = 0
x'(0) = 2.5 m/s

Substituting these values into the equation of motion, we get:

x(0) = A cos(0) + B sin(0) = 0
x'(0) = -5A sin(0) + 5B cos(0) = 2.5

From the first equation, we get:

B = 0

Substituting this into the second equation, we get:

A = 0.5

Therefore, the equation of motion for the mass attached to the spring is:

x(t) = 0.5 cos(5t)

The position of the mass after t seconds is given by this equation, so we can substitute any value of t to get the position:

x(t) = 0.5 cos(5t)

For example, after 1 second, the position of the mass is:

x(1) = 0.5 cos(5) = -0.354 meters (rounded to three decimal places)
To find the position of the mass after t seconds, we need to determine the spring constant (k) and the amplitude (A) of the oscillation.

1. Calculate the spring constant (k) using Hooke's Law:
F = k * x
10 N = k * 0.4 m
k = 25 N/m

2. Calculate the angular frequency (ω) using the mass (m) and spring constant (k):
ω = sqrt(k/m)
ω = sqrt(25 N/m / 8 kg)
ω = 1.77 rad/s

3. Calculate the amplitude (A) using the initial velocity (v₀) and angular frequency (ω):
v₀ = ω * A
2.5 m/s = 1.77 rad/s * A
A = 1.41 m

Now, we can find the position of the mass after t seconds using the equation for simple harmonic motion:
x(t) = A * cos(ω * t)

So, the position of the mass after t seconds is:
x(t) = 1.41 * cos(1.77 * t) meters

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a. residual is much larger than the rest of the residual values.

In regression analysis, an outlier refers to an observation that significantly deviates from the expected pattern or trend of the data. Specifically, it is an observation whose residual (the difference between the observed value and the predicted value) is much larger than the residuals of the other observations.

Outliers can have a considerable impact on the regression model, affecting the estimated coefficients and overall model fit. It is important to identify and assess outliers to determine if they are influential or if they should be treated or removed to ensure the reliability and validity of the regression analysis.

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Answer:

points

Step-by-step explanation:

Answer:please correct me if I’m wrong but I believe Part A for the slopes are…

1.3/1 or 3

2.-3

3.9/5

4.4/3

Step-by-step explanation:

It’s going up 3 and “running” 1 and it’s positive since the line is going up.

Y2-y1. -16-2

————= ————=-18/6=-3

X2-x1. 8-2

You’re just finding the slope

Solve for it. If further explanation is needed please tell me.

A.

1. 9/5

2. -1/5

3. ? (no question)

4. 4 or 4/1

B.

5. y = 1x + 4

6. -2x + 3

7. -1/5x + 2

8. -4x + 2

I'm not sure about 5-8 the wording of the questions are confusing.

The monthly payment for a salary loan of 70,000 pesos at a 10% annual interest rate compounded monthly for 18 months is approximately 4,530.79 pesos.

To calculate the monthly payment for the salary loan, we can use the formula for the equal payment amount in an amortizing loan:

Payment = (Principal * Monthly Interest Rate) / (1 - (1 + Monthly Interest Rate)^(-n))

Where:

Principal = 70,000 pesos (loan amount)

Monthly Interest Rate = Annual Interest Rate / 12 = 10% / 12 = 0.0083333

n = number of payments (18 months)

Let's calculate the payment amount:

Payment = (70,000 * 0.0083333) / (1 - (1 + 0.0083333)^(-18))

Payment = 4,530.79 pesos

Therefore, the monthly payment for the salary loan is approximately 4,530.79 pesos.

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a) It will take approximately 46.39 quarters (or 11.5975 years) to double the initial investment. b) After 10 years, the account has grown by approximately $6,449.41 at a rate of 6% compounded quarterly.

a) To find out how long it will take for the initial investment to double, we can set up the equation:

\(2P_o = P_o(1.015)^t\)

Dividing both sides by Po and simplifying, we get:

\(2 = (1.015)^t\)

Taking the logarithm (base 10 or natural logarithm) of both sides, we have:

log(2) = t * log(1.015)

Solving for t:

t = log(2) / log(1.015)

Using a calculator, we find:

t ≈ 46.39

Therefore, it will take approximately 46.39 quarters (or 11.5975 years) for the initial investment to double.

b) To calculate the rate of account growth after 10 years, we need to evaluate the value of P(t) at t = 10:

\(P(10) = P_o(1.015)^{10\)

Substituting the given values:

\(P(10) = $10,000(1.015)^{10\)

Using a calculator, we find:

P(10) ≈ $16,449.41

The growth in the account over 10 years is approximately $16,449.41 - $10,000 = $6,449.41.

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Answer:

89.28

Step-by-step explanation:

First lets find 7% of 96

96 x 0.07 = 6.72

then subtract 6.72 from 96

96-6.72=89.28

The requried, a number that is 7% smaller than 96 is approximately 89.28.

To find a number that is 7% smaller than 96, we need to calculate 7% of 96 and then subtract that value from 96.

Calculate 7% of 96.

7% of 96 = (7/100) * 96 = 0.07 * 96 = 6.72

To get a number that is 7% smaller than 96, we need to subtract the value we found in Step 1 from 96. subtract the calculated value from 96.

Number = 96 - 6.72 = 89.28

Therefore, a number that is 7% smaller than 96 is approximately 89.28.

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Answer:

i can help you

any time u want

Answer:

i am not perfect in math but i always trying to help you

Answer:

\(\huge\boxed{A.\ f^{-1}(x)=\dfrac{x-3}{5}}\)

Step-by-step explanation:

\(f(x)=5x+3\to y=5x+3\\\\\text{exchange}\ x\ \text{with}\ y\\\\5y+3=x\\\\\text{solve for}\ y\\\\5y+3=x\qquad|\text{subtract 3 from both sides}\\\\5y+3-3=x-3\\\\5y=x-3\qquad|\text{divide both sides by 5}\\\\\dfrac{5\!\!\!\!\diagup y}{5\!\!\!\!\diagup}=\dfrac{x-3}{5}\\\\y=\dfrac{x-3}{5}\to f^{-1}(x)=\dfrac{x-3}{5}\)

Step-by-step explanation:

the area of a triangle

baseline × height / 2

in our case

baseline × height / 2 = 60 in²

height = 6×baseline - 16

baseline × (6×baseline - 16) / 2 = 60

baseline × (3×baseline - 8) = 60

3×baseline² - 8×baseline = 60

baseline = x

3x² - 8x - 60 = 0

general solution to a quadratic equation is

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case

a = 3

b = -8

c = -60

x = (8 ± sqrt(64 - 4×3×-60))/(2×3) =

= (8 ± sqrt(64 + 720))/6 = (8 ± sqrt(784))/6 =

= (8 ± 28)/6

x1 = (8 + 28)/6 = 36/6 = 6

x2 = (8 - 28)/6 = -20/6 = -10/3

x2 as a negative number is not a valid solution for a length in a geometric shape.

so, x = 6 in is our solution for the baseline.

height = 6x - 16 = 6×6 - 16 = 36 - 16 = 20 in

base = 6 in

Answer: (0,0),(0,4), and (5,0)

Step-by-step explanation:

It is easy to find lengths of horizontal and vertical segments and distances from (0,0) so always place one vertex at the origin and one or more sides on an axis.

This answer has an x intercept and y intercept.

Answer:

check the attachment

The simplified Boolean expression for F = A'C(A'BD)' + A'BC'D' + AB'C is F = A'B + AB'C.

To simplify the given Boolean expression, we can use Boolean algebra laws and rules. Let's break down the simplification step by step:

Distributive Law: Apply the distributive law to the first term A'C(A'BD)' = A'CA'D' + A'CB'D'.

This simplifies to A'D' + A'CB'D'.

Distributive Law: Apply the distributive law to the second term A'BC'D' = A'BC'D'.

This remains unchanged.

Combining like terms: Combine the terms A'D' and A'CB'D'. They share the factor A'D', so we can write them as A'D' + A'CB'D' = A'D'(1 + CB').

This simplifies to A'D'.

Combining like terms: Combine the terms A'BC'D' and A'D'. They both have the factor A'D', so we can write them as A'BC'D' + A'D' = A'D' + A'BC'D'.

This simplifies to A'D'.

Combining like terms: Combine the simplified terms A'D' and AB'C. They share the factor A', so we can write them as A'D' + AB'C = A'(D' + BC).

This simplifies to A'B + AB'C.

Therefore, the simplified Boolean expression for F is F = A'B + AB'C.

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In Euclidean geometry, opposite sides and angles of a parallelogram are congruent, a property not shared in non-Euclidean planes. The opposite sides and opposite angles of a parallelogram in a Euclidean plane are congruent.

In a general Hilbert plane, opposite sides of a parallelogram need not be congruent. This is because non-semi-Euclidean planes such as the Saccheri and Lambert quadrilaterals do not satisfy the Euclidean parallel postulate. However, in a plane that satisfies the Euclidean parallel postulate, opposite sides and opposite angles of a parallelogram are congruent.

The Euclidean parallel postulate states that given a line and a point not on that line, there is only one line that passes through that point and does not intersect the original line. This means that in Euclidean geometry, parallel lines never meet. Therefore, in a Euclidean plane, we can construct parallelograms by drawing two parallel lines and then connecting them with other segments.

Let ABCD be a parallelogram in a Euclidean plane. Draw diagonal AC, which divides the parallelogram into two congruent triangles, ΔABC and ΔADC. Since ΔABC and ΔADC share the side AC, we have AB = CD and BC = DA by the Side-Side-Side (SSS) congruence criterion.

Similarly, since opposite sides of a parallelogram are parallel and thus form alternate interior angles, we have ∠A = ∠C and ∠B = ∠D by the Alternate Interior Angles Theorem. Therefore, opposite sides and opposite angles of a parallelogram in a Euclidean plane are congruent.

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Step-by-step explanation:

\(\large\underline{\sf{Solution-}}\)

Given expression is

\(\rm :\longmapsto\:tan75\degree + cot75\degree \)

Consider

\(\rm :\longmapsto\:tan75\degree \)

\(\rm \:  =  \: tan(45\degree + 30\degree )\)

\(\rm \:  =  \: \dfrac{tan45\degree + tan30\degree }{1 - tan45\degree \times tan30\degree } \)

\(\rm \:  =  \: \dfrac{1 + \dfrac{1}{ \sqrt{3} } }{1 - 1 \times \dfrac{1}{ \sqrt{3} } } \)

\(\rm \:  =  \: \dfrac{1 + \dfrac{1}{ \sqrt{3} } }{1 - \dfrac{1}{ \sqrt{3} } } \)

\(\rm \:  =  \: \dfrac{ \sqrt{3} + 1 }{ \sqrt{3} - 1} \)

On rationalizing the denominator, we get

\(\rm \:  =  \: \dfrac{ \sqrt{3} + 1 }{ \sqrt{3} - 1} \times \dfrac{ \sqrt{3} + 1 }{ \sqrt{3} + 1 } \)

\(\rm \:  =  \: \dfrac{ {( \sqrt{3} + 1)}^{2} }{ {( \sqrt{3}) }^{2} - {(1)}^{2} } \)

\(\rm \:  =  \: \dfrac{3 + 1 + 2 \sqrt{3} }{3 - 1} \)

\(\rm \:  =  \: \dfrac{4+ 2 \sqrt{3} }{2} \)

\(\rm \:  =  \: \dfrac{2(2+ \sqrt{3} )}{2} \)

\(\rm \:  =  \: 2 + \sqrt{3} \)

\(\rm\implies \:\boxed{\tt{ tan75\degree = 2 + \sqrt{3} \: }}\)

Now,

\(\rm :\longmapsto\:cot75\degree \)

\(\rm \:  =  \: \dfrac{1}{tan75\degree } \)

\(\rm \:  =  \: \dfrac{1}{2 + \sqrt{3} } \)

On rationalizing the denominator, we get

\(\rm \:  =  \: \dfrac{1}{2 + \sqrt{3} } \times \dfrac{2 - \sqrt{3} }{2 - \sqrt{3} } \)

\(\rm \:  =  \: \dfrac{2 - \sqrt{3} }{ {(2)}^{2} - {( \sqrt{3}) }^{2} } \)

\(\rm \:  =  \: \dfrac{2 - \sqrt{3} }{4 - 3} \)

\(\rm \:  =  \: 2 - \sqrt{3} \)

\(\bf\implies \:\boxed{\tt{ cot75\degree = 2 - \sqrt{3} \: }}\)

Now, Consider

\(\rm :\longmapsto\:tan75\degree + cot75\degree \)

\(\rm \:  =  \: 2 + \sqrt{3} + 2 - \sqrt{3} \)

\(\rm \:  =  \: 4\)

Hence,

\(\rm\implies \:\boxed{\tt{ tan75\degree + cot75\degree = 4 \: }}\)

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

\(\rm :\longmapsto\:tan75\degree + cot75\degree \)

\(\rm \:  =  \: tan75\degree + \dfrac{1}{tan75\degree } \)

\(\rm \:  =  \: \dfrac{ {tan}^{2}75\degree + 1}{tan75\degree } \)

\(\rm \:  =  \: \dfrac{1}{\dfrac{tan75\degree }{1 + {tan}^{2} 75\degree } } \)

\(\rm \:  =  \: \dfrac{2}{\dfrac{2tan75\degree }{1 + {tan}^{2} 75\degree } } \)

We know,

\(\rm :\longmapsto\:\boxed{\tt{ \frac{2tanx}{1 + {tan}^{2} x} = sin2x}}\)

\(\rm \:  =  \: \dfrac{2}{sin150\degree } \)

\(\rm \:  =  \: \dfrac{2}{sin(180\degree - 30\degree )} \)

\(\rm \:  =  \: \dfrac{2}{sin30\degree } \)

\(\rm \:  =  \: 2 \times 2\)

\(\rm \:  =  \: 4\)

Hence,

\(\rm\implies \:\boxed{\tt{ tan75\degree + cot75\degree = 4 \: }}\)

Answer:

Yes i think you did it right because its +3 - 2