Answer:
Step-by-step explanation:
16 cm / 10 days = 1.6 cm/day
10 days / 16 cm = 0.625 days/cm
A marathon runner travels 2/3 in 10 minutes. What is the runners rate in miles per hour ?
The runner's rate in miles per hour is D * 4/3 miles per hour.
Describe Distance?Distance is a measure of the physical space between two objects or points. It is the length of the shortest path between two points in space. Distance can be measured in different units, such as meters, kilometers, miles, feet, or inches, depending on the scale of the objects or the purpose of the measurement.
In geometry, the distance between two points in a Euclidean space can be calculated using the Pythagorean theorem or the distance formula. The distance formula is expressed as:
d = sqrt((x2 - x1)^2 + (y2 - y1)^2)
where d is the distance between two points (x1, y1) and (x2, y2) in a two-dimensional plane. This formula can be extended to three dimensions by adding a third term to the equation.
Distance can also be calculated using other methods, such as GPS (Global Positioning System) or by measuring the time it takes for an object to travel from one point to another, using the speed of light or sound.
In everyday life, distance is a fundamental concept used in various contexts, such as navigation, transportation, sports, and communication. It plays a significant role in determining the time and effort required to travel between two points and is often used as a basis for making decisions.
We can use the formula:
rate = distance / time
where distance is the distance traveled by the runner and time is the time taken to travel that distance.
Given that the runner travels 2/3 of the marathon distance in 10 minutes, we can find the total distance of the marathon by dividing the distance traveled by 2/3:
total distance = distance traveled / (2/3) = distance traveled * 3/2
Let's denote the total distance of the marathon as D. Then:
D = distance traveled * 3/2
distance traveled = D * 2/3
We know that the time taken to travel 2/3 of the distance is 10 minutes. Let's convert this to hours:
10 minutes = 10/60 hours = 1/6 hours
Now we can calculate the runner's rate:
rate = distance / time = (D * 2/3) / (1/6) = (D * 4/3) / 1 = D * 4/3
So the runner's rate in miles per hour is D * 4/3 miles per hour.
Note that we don't have a specific value for the total distance D of the marathon, so we cannot give a numerical answer. We can only express the runner's rate in terms of D as:
runner's rate = D * 4/3 miles per hour
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Find the measure of the missing angles.
Answer:
153* for both
Step-by-step explanation:
This makes a circle, which is 360*. One angle is given, and it is 27*. If the angle on the opposite side is the same, the total degrees so far would be 54.
Say b and c were equal. Then, the remaining 306* would be split even among them. 306/2 is 153.
Therefore, 153* is the correct answer.
Hope I helped!!!
PLEASE HELP!!!!!!!!!!!!
Answer:
the school block me
Step-by-step explanation:
from seinge this image
13. security y has the following returns over five years: 3%, 6%, 0%, 6%, and 3%. what is the arithmetic mean (average) return and the standard deviation (sample) for security y?
The arithmetic mean return is 3.6%, and the standard deviation is 2.14%.
To find the arithmetic mean, we add up the five returns and divide by the number of returns (in this case, 5):
(3% + 6% + 0% + 6% + 3%) / 5 = 3.6%
To find the standard deviation, we first need to find the variance. We can do this by taking each return, subtracting the mean return (3.6%), squaring the result, summing these values, and dividing by the number of returns minus 1 (4 in this case):
((3% - 3.6%)^2 + (6% - 3.6%)^2 + (0% - 3.6%)^2 + (6% - 3.6%)^2 + (3% - 3.6%)^2) / 4 = 0.046
The standard deviation is the square root of the variance:
√0.046 = 0.214 or 2.14%
Therefore, the arithmetic mean return for security y is 3.6%, and the standard deviation (sample) is 2.14%.
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Which is the slope-intercept equation of the line (-2,2) and (0,-4)?
Answer:
y=3x-4
Step-by-step explanation:
in a marketing study, 100 consumers were asked to select the best digital music player from the ipod touch, sony walkman, and the zune hd. to summarize the consumer responses with a frequency table, how many classes would the frequency table have?
The frequency table would have three classes, one for each digital music player option.
When summarizing the consumer responses with a frequency table, the frequency table would have 3 classes.
Frequency table:
A frequency table is a statistical tool that is used to organize raw data in a clear and concise manner.
It is a way of representing the information contained in the data so that it can be easily interpreted and analyzed.
A frequency table is often used to summarize categorical data, such as the data collected in a marketing study like the one mentioned in the question.
The marketing study in this question involved asking 100 consumers to select the best digital music player from three options:
the iPod Touch, Sony Walkman, and Zune HD.
To create a frequency table from this data, we would need to count the number of times each option was chosen by the consumers.
This can be done by grouping the data into classes, which are categories that are created based on the values in the data.
For this particular study, there are only three options to choose from, so there are only three possible classes:
iPod Touch, Sony Walkman, and Zune HD. We would simply count the number of times each option was chosen and record it in the appropriate class.
The resulting frequency table would look something like this: Digital Music Player Frequency i Pod Touch 45 Sony Walkman 28 Zune HD27
Total 100
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I need help with this question
The length of the legs of the right triangle are 2.83 units.
How to find the side of a right triangle?A right tangle triangle is a triangle that has one of its angles as 90 degrees. The sum of angles in a triangle is 180 degrees.
Therefore, the legs of the triangle can be found using trigonometric ratios.
Hence,
sin 45 = opposite / hypotenuse
sin 45 = a / 4
cross multiply
a = 4 × 0.70710678118
a = 2.83 units
Therefore,
cos 45 = b / 4
cross multiply
b = 0.70710678118 × 4
b = 2.82842712475
b = 2.83 units
Therefore, the legs are 2,83 units
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insert 3 rational numbers between -1 and -2/3
Answer
-0.5; -0.9;-0.66049345252453235
Step-by-step explanation:
math
Help please!!!
12x + 6y= 162
2x + 10y= 126
Solve using system of equations. Show all work
Answer:
(8, 11)
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDASEquality PropertiesAlgebra I
Solving systems of equations using substitution/eliminationStep-by-step explanation:
Step 1: Define systems
12x + 6y = 162
2x + 10y = 126
Step 2: Simplify systems
2x + y = 27
x + 5y = 63
Step 3: Rewrite systems
2x + y = 27
x = 63 - 5y
Step 4: Solve for y
Substitute in x: 2(63 - 5y) + y = 27Distribute 2: 126 - 10y + y = 27Combine like terms: 126 - 9y = 27Isolate y term: -9y = -99Isolate y: y = 11Step 5: Solve for x
Define equation: x + 5y = 63Substitute in y: x + 5(11) = 63Multiply: x + 55 = 63Isolate x: x = 8Answer:
x = 8 and y = 11
Step-by-step explanation:
solve for y
12x + 6y = 162
-12x -12x
6y = 162 - 12x
/6 /6
y = 27 - 2x
substitute
2x + 10(y) = 126
2x + 10(27 - 2x) = 126
2x + 270 - 20x = 126
-18x + 270 = 126
-270 -270
-18x = -144
-18 -18
x = 8
substitute again:
y = 27 - 2(x)
y = 27 - 2(8)
y = 27 - 16
y = 11
The price of a factory machine is R900000 but depreciates at 5% per annum. Calculate the depreciated value of the machine after 6 years if: 4.5.1 the depreciation is at simple interest rate. (3) 4.5.2 the depreciation is at compound interest rate. (3) 4.6 The rate of inflation is at 6% per annum compounded annually. Determine the price of the new machine in 4.5 after 6 years. Hence calculate how much extra needs to be paid if the machine in 4.5.2 is traded in.
So, if the machine in 4.5.2 is traded in, approximately R615,060 extra needs to be paid.
To calculate the depreciated value of the machine after 6 years, we can use both simple interest and compound interest.
4.5.1 Depreciation at simple interest rate:
The formula for simple interest is:
Depreciated value = Initial value - (Initial value * depreciation rate * time)
In this case, the initial value is R900,000, the depreciation rate is 5% (or 0.05), and the time is 6 years. Plugging in these values into the formula, we get:
Depreciated value = R900,000 - (R900,000 * 0.05 * 6) = R900,000 - R270,000 = R630,000
So, the depreciated value of the machine after 6 years, with simple interest depreciation, is R630,000.
4.5.2 Depreciation at compound interest rate:
The formula for compound interest is:
Depreciated value = Initial value * (1 - depreciation rate)^time
Again, the initial value is R900,000, the depreciation rate is 5% (or 0.05), and the time is 6 years. Plugging in these values into the formula, we get:
Depreciated value = R900,000 * (1 - 0.05)^6 = R900,000 * 0.95^6 ≈ R900,000 * 0.7351 ≈ R661,590
So, the depreciated value of the machine after 6 years, with compound interest depreciation, is approximately R661,590.
4.6 To determine the price of the new machine in 4.5 after 6 years, we need to take into account the rate of inflation, which is 6% compounded annually. This means that the price of the new machine will increase by 6% each year.
To calculate the price of the new machine, we can use the formula for compound interest:
New price = Initial price * (1 + inflation rate)^time
In this case, the initial price is R900,000, the inflation rate is 6% (or 0.06), and the time is 6 years. Plugging in these values into the formula, we get:
New price = R900,000 * (1 + 0.06)^6 ≈ R900,000 * 1.4185 ≈ R1,276,650
So, the price of the new machine after 6 years, with the 6% inflation rate, is approximately R1,276,650.
To calculate how much extra needs to be paid if the machine in 4.5.2 is traded in, we need to subtract the depreciated value of the machine in 4.5.2 from the price of the new machine.
Extra payment = Price of new machine - Depreciated value of machine in 4.5.2
Plugging in the values, we get:
Extra payment = R1,276,650 - R661,590 ≈ R615,060
So, if the machine in 4.5.2 is traded in, approximately R615,060 extra needs to be paid.
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Below is the graph of a polynomial function F with real coefficients. Use the graph to answer the following questions about F. All local extrema of F are shown in the graph. (For the last question, the multiple choice answers are ‘4,5,6,7,8,9’ I am allowed to choose more than one if needed)
Given below is the graph of a polynomial function F with real coefficients. Use the graph to answer the following questions about F. All local extrema of F are shown in the graph, and to identify them as well as the number of local extrema of F.
Here is the given graph of the polynomial function F: Graph of the polynomial function F From the graph, the number of local extrema of F is 5.
The local extrema are marked in the graph as shown in the figure below: Marked local extrema on the polynomial function F from the graph.
The x and y-coordinates of each local extrema are as follows:
Local Extrema (0, -3), Local Extrema (1, -2), Local Extrema (2, 1), Local Extrema (3, 2), Local Extrema (5, -1).
Therefore, the local extrema of F are (0, -3), (1, -2), (2, 1), (3, 2), and (5, -1).
The local extreama are 5.
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Karey is prescribed 600 mg of a medication that decays at a rate of 40% per day, d, according to the equation mc020-1. Jpg, where m is the amount of medication remaining in his body. Noelle takes the same medication five days earlier. The number of milligrams of medication in Noelle’s body is about what percentage of the number of milligrams in Karey’s body at any time after they have both taken the medication? 3. 0% 7. 8% 12. 9% 46. 7%.
The number of milligrams of medication in Noelle's body is approximately 12.9% of the number of milligrams in Karey's body at any time after they have both taken the medication. This percentage can be calculated by considering the decay rate of the medication over time.
1. The equation m c 020-1. jpg represents the decay of medication in Karey's body. Let's assume t represents the number of days since they both took the medication. According to the equation, the amount of medication remaining in Karey's body at any given time can be calculated using the formula m = 600 (1 - 0.4)t.
2. Since Noelle took the medication five days earlier, we can consider her time as t - 5. Thus, the amount of medication remaining in Noelle's body at any given time is m = 600 (1 - 0.4)(t-5).
3. To find the percentage of medication in Noelle's body compared to Karey's, we divide the amount of medication in Noelle's body by the amount in Karey's body and multiply by 100. Therefore, the percentage is given by (m / 600) * 100.
4. Simplifying the equation, we get (600 * (1 - 0.4)(t-5) / 600) 100. By simplifying further, we find that the percentage is equal to (1 - 0.4)(t-5) 100. Since the value of (1 - 0.4)(t-5) remains constant over time, it is approximately equal to 0.129.
5. Therefore, Noelle has approximately 12.9% of the number of milligrams of medication in Karey's body at any time after they have both taken the medication.
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Answer: C
Step-by-step explanation: its right.. if not ill eat my hat
Kim is playing an online trivia game. She has 25 points and earns 1 each correct answer. She will advance to the next round if her score is over 34 points. A. 25x+>34 B. 1x+34 34 C.1x+25 34
25x+>34 is the correct answer.
The correct answer is option A.
What is an example of an equation?
An equation is a mathematical declaration this is made up of two expressions linked through the same sign. As an example, 3x – five = 16 is an equation. solving this equation, we get the cost of the variable x as x = 7.
What is a word problem in maths?A word problem in maths is a maths question written as one sentence or more that requires children to apply their maths knowledge to a 'real-life' scenario.
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Solve 3 (3 - 3x) +4= -5.
Answer:
x=2
Step-by-step explanation:
3 (3 - 3x) +4= -5
Subtract 4 from each side
3 (3 - 3x) +4-4= -5-4
3 (3 - 3x)= -9
Divide by 3
3/3 (3 - 3x) = -9/3
3-3x = -3
Subtract 3 from each side
3-3x-3 = -3-3
-3x = -6
Divide by -3
-3x/-3 = -6/-3
x = 2
Question 10
The price of one share of a stock fell 4 dollars each day for 8
days. How much value did one share of the stock lose after 8
days?
A shopper buys cat food in bags of 3 lbs. Her cat eats 34 lb each week. How many weeks does one bag last?
Multiply your answer in the first question (the number of weeks) by 34.
The table shows the relationship between the wait time in minutes and the number of people in line. Is there a direct variation? If so, what is the constant of proportionality (k)? *
1. No, there is no direct variation
2. Yes, there is a direct variation; k = 13 minutes per person
3. Yes, there is a direct variation; k = 17 minutes per person
4. Yes, there is a direct variation; k = 20 minutes per person
5. Other:
Answer:
the variation is 1:20 or 1 to 20
Step-by-step explanation:
4 to 80
8 to 160
12 to 240
16 to 320
4,8,12,16
80,160,240,320.
they are all equal because if we take
4 x 20 = 80
8 x 20 = 160
12 x 20 = 240
16 x 20 =320
You need to compute the 99% confidence interval for the population mean. How large a sample should you draw to ensure that the sample mean does not deviate from the population mean by more than 1.3
To compute the 99% confidence interval for the population mean, you need to determine the appropriate sample size to ensure that the sample mean does not deviate from the population mean by more than 1.3. The key terms involved in this process are the confidence interval, sample size, population mean, and sample mean.
The confidence interval represents the range within which the population parameter (in this case, the population mean) is likely to fall, given a certain level of confidence. A 99% confidence interval means that you are 99% confident that the true population mean falls within the specified range.
To calculate the required sample size, you will need to use the formula for the margin of error (E), which is E = (Zα/2 * σ) / √n, where Zα/2 is the critical value associated with the desired level of confidence (99%), σ is the population standard deviation, and n is the sample size.
Since you want the sample mean to not deviate from the population mean by more than 1.3, you will need to set E = 1.3 and solve for n. After finding the critical value for a 99% confidence interval (which is approximately 2.576) and assuming you know the population standard deviation, you can plug these values into the formula and solve for n.
By doing this, you will be able to determine the appropriate sample size to ensure that the 99% confidence interval for the population mean is within 1.3 units of the sample mean.
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the answer pleaseee :(
Find the slope of the line through (-0.5,0.5) , perpendicular to y=-2 x-4
The given line has a slope of -2. The negative reciprocal of -2 is 1/2.
So, the slope of the line perpendicular to y=-2x-4 is 1/2.
To find the slope of a line perpendicular to another line, we need to take the negative reciprocal of the slope of the given line.
The given line has a slope of -2.
The negative reciprocal of -2 is 1/2.
So, the slope of the line perpendicular to
y=-2x-4 is
1/2.
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An investor has an account with stock from two different companies. Last year, his stock in Company A was worth $2500 and his stock in Company B was worth $3600. The stock in Company A has increased 23% since last year and the stock in Company B has increased 14%. What was the total percentage increase in the investor's stock account? Round your answer to the nearest tenth (if necessary).
well, let's take a peek, let's increase A by 23% and B by 14%
\(\begin{array}{|c|ll} \cline{1-1} \textit{\textit{\LARGE a}\% of \textit{\LARGE b}}\\ \cline{1-1} \\ \left( \cfrac{\textit{\LARGE a}}{100} \right)\cdot \textit{\LARGE b} \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{23\% of 2500}}{\left( \cfrac{23}{100} \right)2500}\implies 575~\hfill \stackrel{2500+575 }{\text{\LARGE 3075}} \\\\\\ \stackrel{\textit{14\% of 3600}}{\left( \cfrac{14}{100} \right)3600}\implies 504\hspace{5em}\stackrel{ 3600+504 }{\text{\LARGE 4104}}\)
so he had a stock of 2500 + 3600 = 6100, now it ballooned to 3075 + 4104 = 7179, so it increased by 7179 - 6100 = 1079.
if we take 6100(origin amount) as the 100%, what is 1079 off of it in percentage?
\(\begin{array}{ccll} Amount&\%\\ \cline{1-2} 6100 & 100\\ 1079& x \end{array} \implies \cfrac{6100}{1079}~~=~~\cfrac{100}{x} \\\\\\ 6100x=107900\implies x=\cfrac{107900}{6100} \implies x= \cfrac{1079}{61}\implies {\Large \begin{array}{llll} x\approx 17.7 \end{array}}\)
2. We classify students at the entirely hypothetical University of Chocolate Libation (UChL) into two classes: those who are enrolled in a degree programme in statistical science (whose number we denote by X ) and those who do not. There are two degree programmes available in statistical science: Statistics, Economics and Finance (abbreviated to SEF) and Economics and Statistics (abbreviated to ES). Each student enrolled in a degree programme in statistical science chooses independently at random which of these two degree programmes to follow, with probability p∈(0,1) of following SEF. The number of students on SEF is denoted by Y and the number of students on ES is denoted by Z so that X=Y+Z. (a) Suppose that X∼Poi(λ) for a parameter λ>0. Compute Cov(X,Y) as well as corr(X,Y). [TYPE:] For both the covariance and the correlation, decide whether they depend on the parameter λ and provide an intuitive reasoning explaining IP: STAT0005, 2022-2023 15 your finding. Your explanation should provide an interpretation of the parameter λ (you may find it easier to type "lambda" rather than use the Greek letter) in the context of the question and from there explain its impact on the covariance and correlation. You should write at least four sentences and at most half a page. (b) Instead of assuming that X follows a Poisson distribution, assume that the total number of students at UChL is known to be n∈N. Each of these n students chooses independently to enroll in a degree programme in statistical science with probability r∈(0,1), independently. Find the joint distribution of Y,Z and the number W of students at UChL who do not enroll in a degree programme in statistical science. Compute corr(X,Y). For which limiting value of r does this correlation agree with the one computed in the previous part? 3. Consider the following marginal and conditional pdfs: fV(v)fW\V(w∣v)={αv−2e−v20 if v<−1 or v>1 otherwise ={v2e−wv20 if w>0 otherwise Here, α is a normalization constant. (a) Obtain E[W∣V=v] for ∣v∣>1. Justify your steps. (b) Show that corr(V,W)=0. Justify your steps. (c) Decide whether V and W are independent. Justify your decision carefully.
Both Cov(X,Y) and corr(X,Y) do not depend on the parameter λ.
To compute Cov(X,Y), we first need to compute E(X), E(Y), and E(XY). Since X ∼ Poisson(λ), we have E(X) = λ.
Now, let's compute E(Y). We know that Y represents the number of students on SEF, and each student chooses to follow SEF with probability p.
Therefore, Y follows a binomial distribution with parameters X and p. Hence, E(Y) = X * p.
Next, let's compute E(XY). Since X and Y are independent, we have-
\(E(XY) = E(X) * E(Y)\)
\(= λ * X * p.\)
Now, we can compute Cov(X,Y) using the formula:
\(Cov(X,Y) = E(XY) - E(X) * E(Y).\)
Substituting the values we obtained, we have-
\(Cov(X,Y) = λ * X * p - λ * X * p\)
= 0.
Moving on to compute corr(X,Y), we need to compute Var(X) and Var(Y) first.
Since X ∼ Poisson(λ), we have Var(X) = λ.
For Y, since it follows a binomial distribution with parameters X and p, we have
\(Var(Y) = X * p * (1 - p)\).
Now, we can compute corr(X,Y) using the formula:
\(corr(X,Y) = Cov(X,Y) / sqrt(Var(X) * Var(Y)).\)
Substituting the values we obtained, we have-
\(corr(X,Y) = 0 / sqrt(λ * X * p * X * p * (1 - p))\)
= 0.
Therefore, both Cov(X,Y) and corr(X,Y) do not depend on the parameter λ.
(b) Assuming that the total number of students at UChL is known to be n, we can find the joint distribution of Y, Z, and the number W of students who do not enroll in a degree program in statistical science.
Since each student independently chooses to enroll in a degree program with probability r, the number of students on SEF, Y, follows a binomial distribution with parameters n and r.
Similarly, the number of students on ES, Z, follows a binomial distribution with parameters n and (1 - r).
Hence, the joint distribution of Y and Z is given by P(Y=y, Z=z)
\(= C(n,y) * r^y * (1-r)^(n-y) * C(n-z, z) * (1-r)^z * r^(n-z),\)
Where C(n,y) represents the number of combinations of choosing y items from a set of n items.
To compute corr(X,Y), we can use the relationship that corr(X,Y) = corr(Y + Z, Y)
\(= corr(Y, Y) + corr(Z, Y) + 2 * sqrt(corr(Y, Z) * corr(Y, Y)).\)
Since Y and Z are independent, corr(Y, Z) = 0.
We already computed corr(Y, Y) in part (a), and it is 0.
Hence,
\(corr(X,Y) = corr(Y, Y) + corr(Z, Y) + 2 * sqrt(corr(Y, Z) * corr(Y, Y))\)
= 0 + 0 + 2 * sqrt(0 * 0) = 0.
Therefore, the correlation computed in this part, corr(X,Y), agrees with the correlation computed in part (a), which is also 0.
The correlation between X and Y, corr(X,Y), remains 0 regardless of the parameter values λ and r.
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The expression 7h + 1.50d can be used to find the total earnings after h hours and d deliveries have been made. How much will Sally make after working 10 hours and making 3 deliveries?
Group of answer choices
Answer:
$74.5
Step-by-step explanation:
7(10) + 1.50(3) =
70 + 4.5 = 74.5
If my answer is incorrect, pls correct me!
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a 2-kg block slides down a 3-meter-long, frictionless 30° incline. if the block started from rest at the top of the incline, with what speed does it reach the bottom?
The block reaches the bottom of the incline with a speed of approximately 7.66 m/s.
The acceleration of the block is given by
a = g sin 30 = 9.8 m/s² × 0.5 = 4.9 m/s²
Where g is the acceleration due to gravity.
The distance travelled by the block is given by
d = 3 m
The initial velocity of the block, u = 0
Using the kinematic equation, v² = u² + 2as
The final velocity of the block,v is given by
v = sqrt(2 × 4.9 × 3) ≈ 7.66 m/s
Therefore, the block reaches the bottom of the incline with a speed of approximately 7.66 m/s.
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kingcade corporation keeps careful track of the time required to fill orders. data concerning a particular order appear below: hours wait time 20.0 process time 2.8 inspection time 1.8 move time 3.7 queue time 10.8 the throughput time was: group of answer choices 8.3 hours 19.1 hours 30.8 hours 39.1 hours
The throughput time for the particular order was option (d) 39.1 hours.
Throughput time is the total amount of time required for a product or service to move through a production or service delivery system, including all the time spent in processing, waiting, inspection, movement, and queuing.
The throughput time can be calculated as the sum of all the times involved in the process, including the waiting time, processing time, inspection time, move time, and queue time. Therefore:
Throughput time = Wait time + Process time + Inspection time + Move time + Queue time
Throughput time = 20.0 + 2.8 + 1.8 + 3.7 + 10.8
Throughput time = 39.1 hours
Therefore, the correct option is (d) 39.1 hours
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Please help ASAP!!!!
1+1=
2+2=
3+3=
4+4=
4163123 x 418247 =
please help
Answer:
2
4
6
8
1.7412137e+12
Step-by-step explanation:
the first 4 are basic addition and the last one I put into calculator and it came up with that
A Circular pie with a diameter of 10” Is cut into six equal pieces. What is the surface area of two slices of pie?
To solve this question, let's find the surface area of the entire pie and then divide it by 6 for each slice.
The area of a circle is pi*r^2. We are given the diameter, so divide that by 2 to get the radius.
Now that you have the area, divide by 6. That is the area of each slice. The problem asks for the area of 2 slices though, so multiply that by 2.
15 = 15
True
15 = 18 - 3
15 + 3 = 11 + 7
15 + 3 = 15 + 13
Answer:
15 = 18 - 3 and 15 + 3 = 11 + 7 are true
Step-by-step explanation:
.−64a3+48a2−12a+1
factorise