the human eye has three types of cones cells. damage to any one of the types of cone cells doesn't cause total blindness because of the
A. presence of rod cells
B. other two functional Cone cells
C. presence of optic nerves
​

Explanation:

you can watch this video and understand

The limiting reagent here is the Hydrogen gas

Limiting reagents are substances that are completely used up or consumed  in a chemical reaction, they are also referred to as limiting reactants as well. According to stoichiometry of chemical reactions a fixed amount are reactants are supposed to react with each other in order to complete the chemical reaction, and if some reagent is less in amount for the reaction then it is considered as limiting reagents.

In the above given reaction we can see that 3 moles of Hydrogen gas are required to react with one mole of 1 mole of Nitrogen gas to form 2 moles of Ammonia. But if in case in the reaction only 2 moles of Hydrogen are available with 1 mole of Nitrogen.

In that case we cannot use the whole quantity of Nitrogen, because the whole amount of Nitrogen requires 3 moles of Hydrogen and we have just 2 mole.

Hence we can say that the Hydrogen gas is limiting the reaction and therefore it is called as the limiting reagent

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Radial symmetry is a type of body symmetry where each plane that passes through the centre splits the body into two equally sized halves.

The capacity of an animal's body plan to be divided along a line that divides the animal's body into nearly identical right and left halves is known as bilateral symmetry. Arrangement of identical pieces in a circle around a central axis is a type of symmetry.

The organism can be divided into additional planes with identical parts in radial symmetry. In biradial symmetry, the organism can be divided solely in two planes rather than all three as in radial symmetry.

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When \(CO_{2}\) and \(H_{2} CO_{3}\) are both horizontal lines, the rate of the forward reaction is the same as the rate of the reverse reaction. The reaction is occurring at equilibrium, with no net change in the concentrations of reactants and products over time.

When the concentration of carbon dioxide \(CO_{2}\) and the concentration of carbonic acid \(H_{2} CO_{3}\) are both horizontal lines, it indicates that their concentrations remain constant over time. In such a scenario, the rate of the forward reaction is the same as the rate of the reverse reaction. A horizontal line on a concentration-time graph suggests that the concentrations of the reactants and products are not changing, implying that the reaction has reached equilibrium. At equilibrium, the rate of the forward reaction equals the rate of the reverse reaction. This is a fundamental principle of chemical equilibrium, described by the principle of microscopic reversibility.

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1) When a solution of AgNO3 and NaCl  are mixed, a double replacement reaction occurs, resulting in the formation of AgCl and NaNO3.

The solubility product constant (Ksp) for AgCl is given as 1.77 ×\(10^{-10\). Since Ksp is very small, it indicates that AgCl has low solubility in water. When AgNO3 and NaCl are mixed, AgCl will precipitate out of the solution until it reaches saturation, forming a saturated solution of AgCl.

2) To calculate the pH of the buffer solution, we need to consider the dissociation of pyruvic acid and the conjugate base, sodium pyruvate (CH3COCOO⁻).

CH3COCOOH ⇌ CH3COCOO⁻ + H⁺

The Ka value for pyruvic acid is given as 4.1 × \(10^{-3\).

Since the concentrations of pyruvic acid and sodium pyruvate are given, we can assume that the initial concentration of H⁺ is negligible compared to the concentrations of pyruvic acid and sodium pyruvate.

Using the Henderson-Hasselbalch equation:

pH = pKa + log([A⁻]/[HA])

Substituting the values into the equation:

pH = -log(4.1×10–3) + log(0.0507/0.0527)

pH = -log(4.1×10–3) + log(0.0507) - log(0.0527)

pH = -(-2.39) + (-1.293) - (-1.276)

pH = 2.39 + 1.293 + 1.276

pH ≈ 4.96

Therefore, the pH of the buffer solution is approximately 4.96.

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Answer:

The Percentage concentration of acetic acid = 1.39 %

Explanation:

Density of acetic acid solution = 1.05 g/mL

Volume of acetic acid solution = 0.1 L = 100 mL

From the formula, Density = mass / volume; mass = density × volume

Mass of acetic acid solution = 1.05 g/mL × 100 mL = 105 g

Molar concentration of acetic acid solution = 0.243 mol/L

Molar mass of acetic acid, CH₃COOH = (12 × 2 + 1 ×4 + 16 ×2) = 60 g/mol

From the formula, mass concentration = molar concentration × molar mass

Mass concentration of acetic acid, CH₃COOH = 0.243 mol/L × 60 g/mol = 14.58 g/L

In one liter of acetic acid solution, there are 14.58 g of acetic acid. Therefore, in 0.1 L, there will be 14.58 × 0.1 = 1.458 g of acetic acid.

Percentage concentration of acetic acid = mass of acetic acid / mass of acetic acid solution × 100%

Percentage concentration of acetic acid = (1.458 / 105) × 100% = 1.39 %

The Percentage concentration of acetic acid = 1.39 %

Answer:

Melted ionic compounds have freely moving ions while solid ionic compounds do not.

Explanation:

A melted ionic compound has freely moving ions where electrons can be   transfered because the elements of the ionic compounds have broken there bonds and have dissociated into their ions. Compared to a solid ionic compound where it's still in the crystal lattice and the elements will stick in place and the ions will not move because it's in a solid state and they haven't dissocated into their ions.

Answer:

Explanation:

You can do this by doing dimensional analysis.

The first step is to change grams to mg

1000 mg = 1 gram

So the fraction will look like this

1.03 g * 1000 mg/ 1 gram = 1030 mg (the grams cancel out)

Now move onto the volume. The volume is actually 1 cm^3. This becomes 1 cm^3 / 1000 mm^3

So the answer becomes

1030 mg / cm^3 * ( 1 cm^3/1000 mm^3) The cm^3 cancel out

1030 mg / 1000 mm^3

1.030 mg/ mm^3

3.16 µg of Polonium 210 is needed as LD50 for the victim.

The Lethal dose 50 (LD50) of Polonium is 0.045 micrograms (µg) per kilogram (kg) of body weight. The average weight of an adult is 70 kg.

LD50 dose of Polonium = 0.045 µg/kg × 70 kg = 3.15 µg

Assuming the Polonium isotope has a purity of 100%, the atomic mass of Polonium (Po) 210 is 210,

the molar mass of Polonium is:

Molar mass (Po) = 210 g/mol

Moles of Polonium = LD50 dose / molar mass = 3.15 × 10-6 g / 210 g/mol = 1.5 × 10-8 mol

The mass of Polonium needed to deliver an LD50 dose to the victim is:

Mass of Polonium = Moles × Molar mass = 1.51 × 10-8 mol × 210 g/mol = 3.16 × 10-6 g = 3.16 µg

Therefore, 3.16 µg of Polonium is needed to deliver an LD50 dose to the victim.

Note: The mass is given in micrograms, not milligrams or grams. Therefore, the answer should also be in micrograms.

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Answer:

Bones

Explanation:

Standardizing a sodium hydroxide solution is necessary because NaOH reacts with atmospheric carbon dioxide to form sodium carbonate and water, reducing the accuracy of its concentration.

We standardize a sodium hydroxide (NaOH) solution, which means we determine its exact concentration, because NaOH is a strong base that reacts with atmospheric carbon dioxide (CO₂) to form sodium carbonate (Na₂CO₃) and water (H₂O):

2NaOH (aq) + CO₂ (g) → Na₂CO₃ (aq) + H₂O (l)

This reaction reduces the concentration of NaOH in the solution, making it less accurate for titrations or other chemical analyses. Standardizing the NaOH solution involves titrating it with a known concentration of an acid, such as hydrochloric acid (HCl), using an appropriate indicator to determine the exact concentration of NaOH.

During the titration, the acid and base react in a 1:1 ratio according to the balanced chemical equation:

HCl (aq) + NaOH (aq) → NaCl (aq) + H₂O (l)

The endpoint of the titration is reached when all the HCl has reacted with the NaOH, and the solution becomes neutral. An indicator, such as phenolphthalein, is used to signal the endpoint of the titration, where the indicator changes color from pink to colorless. The volume of acid required to reach the endpoint is measured, and the concentration of NaOH is calculated using stoichiometry.

Standardizing the NaOH solution ensures that its concentration is accurately known, allowing it to be used in subsequent chemical reactions or analyses. It is important to standardize the NaOH solution periodically, as the concentration can change over time due to factors such as atmospheric carbon dioxide absorption, water absorption, or contamination.

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Answer: Selenium (Se)

Explanation:

Selenium is the 34th element on the periodic table and is a reactive nonmetal. It has a molar mass of 78.971g or when rounded 79g. generally room temperature is considered 68 - 72° F or 20 - 22° C and between this range Selenium is a solid.

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Two possible sources of systematic (determinate) error in the experiment are; Incorrect calibration of volumetric glasswareIncorrect mass of NaCl

To calculate the concentration of NaCl in the resulting solution in mg/L NaCl, we can use the formula; Concentration (mg/L) = (Mass of solute ÷ Volume of solution in L) × 1000 g / 1 mg NaCl is present in the stock solution of 25 mL. So, the mass of NaCl in the solution would be;0.0842 g ÷ 25 mL = 0.00337 g/mL. Now, in the resulting solution, a 1.00 mL aliquot of the stock solution is transferred to a 50.00 mL volumetric flask and diluted to volume. Therefore, the volume of the resulting solution is 50.00 mL. We will substitute these values in the formula, Concentration (mg/L) = (0.00337 g/mL ÷ 50 mL) × 1000 g / 1 mg concentration (mg/L) = 67.4 mg/L. Therefore, the concentration of NaCl in the resulting solution in mg/L NaCl is 67.4 mg/L.7.  Concentration = 67.4 mg/LTolerance = 4.28 mg/LTotal concentration = 67.4 + 4.28 mg/L = 71.68 mg/LWe round off this value to one decimal place; Total concentration = 71.7 mg/LTherefore, the concentration of NaCl in the resulting solution using propagation of error through the calculation is 67.4+0.4 mg/L.8. Two possible sources of random (indeterminate) error in the experiment are; Errors in temperature measurement. Errors in measurement of water volume. Two possible sources of systematic (determinate) error in the experiment are; Incorrect calibration of volumetric glasswareIncorrect mass of NaCl.

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Answer:

Chemical bonds hold molecules together and create temporary connections that are essential to life.

Explanation:

Chemical Bonding refers to the formation of a chemical bond between two or more atoms, molecules, or ions to give rise to a chemical compound. These chemical bonds are what keep the atoms together in the resulting compound.

Answer:

Chemical bonds hold molecules together and create temporary connections that are essential to life.

Explanation :

A chemical bond is a lasting attraction between atoms, ions or molecules that enables the formation of chemical compounds. The bond may result from the electrostatic force between oppositely charged ions as in ionic bonds or through the sharing of electrons as in covalent bonds.

The 85th percentile of blood pressure readings is approximately 137.64. a. To calculate the z-score for a blood pressure reading of 140, we can use the formula:

z = (x - μ) / σ

where x is the value (140 in this case), μ is the mean (121), and σ is the standard deviation (16).

Substituting the values into the formula:

z = (140 - 121) / 16

z ≈ 1.19 (rounded to two decimal places)

b. To find the proportion of Canadians with high blood pressure, we need to calculate the area under the normal distribution curve for values above 140. This can be done by finding the cumulative probability using the z-score.

Using a standard normal distribution table or a calculator, we can find that the cumulative probability corresponding to a z-score of 1.19 is approximately 0.881.

Therefore, the proportion of Canadians with high blood pressure is approximately 0.881 (rounded to four decimal places).

c. To find the proportion of Canadians with systolic blood pressure in the range from 100 to 140, we need to calculate the area under the normal distribution curve between these two values.

Using the z-scores corresponding to 100 and 140, we can find the cumulative probabilities for each value. The cumulative probability for a z-score of -1.25 (corresponding to 100) is approximately 0.105, and the cumulative probability for a z-score of 1.19 (corresponding to 140) is approximately 0.881 (as calculated in part b).

The proportion with systolic blood pressure between 100 and 140 is the difference between these two probabilities:

Proportion = 0.881 - 0.105 ≈ 0.776 (rounded to four decimal places)

d. The 85th percentile represents the value below which 85% of the blood pressure readings fall. To find the 85th percentile, we need to determine the z-score that corresponds to an area of 0.85 under the normal distribution curve.

Using a standard normal distribution table or a calculator, we can find that the z-score corresponding to an area of 0.85 is approximately 1.04.

To find the actual blood pressure reading at the 85th percentile, we can use the z-score formula:

x = μ + (z * σ)

Substituting the values:

x = 121 + (1.04 * 16)

x ≈ 137.64

Therefore, the 85th percentile of blood pressure readings is approximately 137.64.

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When HBr is added to an alkene, the major product obtained is the alkyl halide.

The specific product formed depends on the nature of the alkene and the conditions of the reaction. The reaction proceeds through electrophilic addition, where the carbocation acts as an electrophile, and the HBr molecule acts as a nucleophile.

The addition of HBr to an alkene happens through the Markovnikov addition. The nucleophilic \(Br^{-}\) ion adds to the carbon atom bearing the most hydrogen atoms, leading to the formation of an alkyl halide with the halogen (Br) attached to the more substituted carbon. This is known as the Markovnikov addition. This reaction occurs with more stable carbocations.

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Answer:

Zinc (Zn) will safely react with dilute sulphuric acid.

Explanation:

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Answer: no water

Explanation:

Answer:

a substance that is a crystalline compound, contains no water

(A)This reaction does not increase the solubility of iron(II) carbonate.

(B) In this reaction it has no effect on how soluble it is.

(C) In this reaction it doesn't directly affect FeCO₃, it has no effect on how soluble it is.

(D)In this reaction it has no effect on how soluble it is.

(E)This reaction does not increase the solubility of iron(II) carbonate.

Therefore, the reaction that does not increase the solubility of iron(II) carbonate is reaction A) \(Fe^{2+\) (a q) + OH- (a q) « Fe OH+ (a q).

Let's analyze each reaction and its impact on the concentration of \(CO_(3)^{2-}\) ions:

A) \(Fe^{2+}\)(a q) + OH- (a q) « Fe OH+ (a q)

FeOH+ is produced during this reaction, although it has no direct impact on how soluble FeCO₃ is. It has nothing to do specifically with the precipitation or dissolution of FeCO₃.

B) \(CO_(3)^{2-}(a q) + H^+ (a q)\) ⇒ \(HCO^{3-}\) (a q)

In this process, \(CO_3^{2-}\) ions are changed into \(HCO^{3-}\)ions. Since it doesn't directly affect \(FeCO_3\), it has no effect on how soluble it is.

C) \(HCO^{3-} (a q) + H^+ (a q)\) « \(H_2 CO_3\) (a q)

In this process, bicarbonate ions \((HCO^{3-})\) are converted into carbonic acid \((H_2CO_3\). Since it doesn't directly affect FeCO₃, it\(H_2O\) has no effect on how soluble it is.

D) \(H_2CO_3(a q)\)« \(CO_2\) (g) + \(H_2O\) (l)

In this process, carbonic acid \((H_2CO_3\)) is transformed into water () and carbon dioxide (\(CO_2\)) gas. Since it doesn't directly affect FeCO₃, it has no effect on how soluble it is.

E) \(Fe OH^+ (a q) + OH^-\) «\(Fe(OH)_2\) (s)

This reaction involves the precipitation of \(Fe(OH)_2\) (iron(II) hydroxide) from Fe OH+ ions and OH- ions. It consumes OH- ions and reduces their concentration. It does not directly affect the concentration of \(CO_3^{2-}\)ions. Therefore, this reaction does not increase the solubility of iron(II) carbonate.

Based on the analysis, the reaction that does not increase the solubility of iron(II) carbonate is reaction A) \(Fe^{2+ }(a q) + OH^- (a q)\)« \(Fe OH^+\) (a q).

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Answer:

\({ \rm{Pb_{3}( PO_{3})_{2} + 3K_{2}CO _{3} →2 K_{3} PO_{3} + 3PbCO_{3}}}\)

Azides, cyanides, hydrides, perchlorates, and sulfides are typically reactive reducing agents or oxidizing agents, which can donate or accept electrons and undergo chemical reactions. Therefore the correct option is option D.

Depending on the particular chemical, a different class of compounds may be incompatible with them.

Therefore the correct option is option D.

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The concentration of HNO3 is 0.10 M. This is determined by using the volume and concentration of NaOH used in the titration and applying the stoichiometry of the reaction between HNO3 and NaOH.

In a titration, the goal is to determine the concentration of an unknown solution by reacting it with a known solution of a different substance. In this case, \(HNO_3\)is being titrated with NaOH. The balanced equation for the reaction between \(HNO_3\)and NaOH is:

\(HNO_3 + NaOH\) -> \(NaNO_3 + H_2O\)

From the equation, we can see that the stoichiometry of the reaction is 1:1 between \(HNO_3\)and NaOH. This means that for every mole of  one mole of NaOH is required to reach equivalence.

Given that 0.20 L of 0.2 M NaOH is used, we can calculate the number of moles of NaOH:

moles of NaOH = volume of NaOH (L) × concentration of NaOH (M)

            = 0.20 L × 0.2 M

            = 0.04 moles

Since the stoichiometry is 1:1, the number of moles of \(HNO_3\)is also 0.04 moles. To determine the concentration of HNO3, we divide the moles of \(HNO_3\) by the volume

concentration of \(HNO_3\)= moles of \(HNO_3\)/ volume of \(HNO_3\)

                    = 0.04 moles / 0.24 L

                    = 0.1667 M

Rounding to an appropriate number of significant figures, the concentration of \(HNO_3\)is approximately 0.10 M.

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To determine the number of grams of oxygen in 6.4 moles of Al(ClO4)3, we need to consider the chemical formula and the molar mass of Al(ClO4)3.

The molar mass of Al(ClO4)3 can be calculated by adding up the atomic masses of its constituent elements:

Al: 26.98 g/mol

Cl: 35.45 g/mol

O: 16.00 g/mol (there are 4 oxygen atoms in each perchlorate ion, ClO4⁻)

Molar mass of Al(ClO4)3 = (26.98 g/mol) + 3*(35.45 g/mol) + 4*(16.00 g/mol)

= 26.98 g/mol + 106.35 g/mol + 64.00 g/mol

= 197.33 g/mol

Now, we can use the molar mass to convert moles of Al(ClO4)3 to grams of oxygen:

Moles of Al(ClO4)3 = 6.4 mol

Molar mass of Al(ClO4)3 = 197.33 g/mol

Grams of oxygen = Moles of Al(ClO4)3 * (4 moles of O / 1 mole of Al(ClO4)3) * (16.00 g/mol)

= 6.4 mol * 4 * 16.00 g/mol

= 409.6 g

Therefore, there are 409.6 grams of oxygen in 6.4 moles of Al(ClO4)3.

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Answer: In the reaction 2H2S + 3O2 → 2H2O + 2SO2, the oxidation state of sulfur changes from -2 in H2S to +4 in SO2. This means that sulfur is oxidized, and oxygen is reduced.

Explanation:

The oxidation state of an element is the number of electrons that an atom loses or gains when it forms a chemical bond. In H2S, the sulfur atom has an oxidation state of -2 because it has lost two electrons to the hydrogen atoms. In SO2, the sulfur atom has an oxidation state of +4 because it has gained four electrons from the oxygen atoms.

The oxidation state of oxygen changes from 0 in O2 to -2 in H2O and SO2. This means that oxygen is reduced, and sulfur is oxidized. In O2, the oxygen atoms are not bonded to any other atoms, so they have an oxidation state of 0. In H2O and SO2, the oxygen atoms have an oxidation state of -2 because they have gained two electrons from the hydrogen and sulfur atoms, respectively.

Element Oxidation state in H2S         Oxidation state in SO2        Oxidation state in H2O

Sulfur                      -2   +4       +4

Oxygen                       0   -2       -2

Hydrogen              +1   +1       +1

Answer: hewo, there! your answer is Below

CH4(g) + 2O2(g) CO2(g) + 2H2O(g) + 802 kJ/mol

Explanation:

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The reaction \(CH_{4} (g)+2O_{2}\) → \(CO_{2}(g) +2H2_{O} (g)+802kJ/mol\)

shows combustion reaction of methane in which energy 802 KJ/mol energy produces.

A combustion reaction occurs when a substance combines with oxygen gas and produces energy in the form of light and heat. One of the reactants in combustion reactions must be oxygen. Water vapor is produced when hydrogen gas is burned.

It can be seen that this reaction give carbon di-oxide and water hence, combustion reaction will show this reaction.

\(CH_{4} (g)+2O_{2}\) → \(CO_{2}(g) +2H2_{O} (g)+802kJ/mol\)

the correct answer will be option (c).

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Answer:

It's an element.

Explanation:

Au is gold. An "element " on the periodic table. Trust me. Im 100% sure.

Explanation:

gold is an element

{au 79 is the atomic number}

A battery is a device that converts chemical energy into electrical energy through a process known as an electrochemical reaction.

When a battery is connected to a circuit, the electrochemical reaction causes a flow of electrons from the anode to the cathode, generating an electric current that can power a device.

The metal chosen for the anode must be capable of losing electrons easily, while the metal chosen for the cathode must be capable of accepting electrons. The choice of metals can also affect the voltage and capacity of the battery, as well as its overall efficiency.

In general, the metals used in a battery should have a large difference in their electronegativity values, which determines how easily an atom can attract electrons. Common metals used in batteries include zinc, lithium, nickel, and cadmium.

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Answer:

6 × 10^23 atoms

Explanation:

This is because Avogadro's number aka 6.02 x 10^23 is applicable to every element and is the number of atoms in any 1 mole of an element. The answer 6 x 10^23 is closest to 6.02 x 10^23 because the 6.02 was rounded to just 6. Hope this helps :)

Answer:

The answer is D)

Explanation:

6 X 10^23

Answer:

Explanation:

-"If he wanted to keep 'em after he was dead, a wicked old screw," pursued the woman, "why wasn’t he natural in his lifetime? If he had been, he'd have had somebody to look after him when he was struck with Death, instead of lying gasping out his last there, alone by himself."

This is showing that if he hadn't be so selfish and righteous, then he would not have been alone to die without anyone there to help or comfort him.  In the line, "why wasn't he natural in his life?", is asking why he wasn't a nice person.  Why didn't he help others.  If he had helped others, he would not have been so alone.A story set during a major battle, as both have a sudden rush of events.