the ideal efficiency of a heat engine between 2950k and 318k is

Answer:

I can msg it toyou

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Explanation:

Answer:

O- to track how fast a heart beats

Explanation:

Answer:

Like other emissions resulting from fossil fuel combustion, aircraft engines produce gases, noise, and particulates, raising environmental concerns over their global effects and their effects on local air quality.[2]Jet airliners contribute to climate change by emitting carbon dioxide (CO2), the best understood greenhouse gas, and, with less scientific understanding, nitrogen oxides, contrails and particulates. Their radiative forcing is estimated at 1.3–1.4 that of CO2 alone, excluding induced cirrus cloud with a very low level of scientific understanding. In 2018, global commercial operations generated 2.4% of all CO2 emissions.

Between 1940 and 2018, aviation CO2 emissions grew from 0.7% to 2.65% of all CO2 emissions.[1]

Jet airliners have become 70% more fuel efficient between 1967 and 2007, and CO2 emissions per Revenue Ton-kilometer (RTK) in 2018 were 47% of those in 1990. In 2018, CO2 emissions averaged 88 grams of CO2 per revenue passenger per km. While the aviation industry is more fuel efficient, overall emissions have risen as the volume of air travel has increased. By 2020, aviation emissions were 70% higher than in 2005 and they could grow by 300% by 2050.

Aircraft noise pollution disrupts sleep, children's education and could increase cardiovascular risk. Airports can generate water pollution due to their extensive handling of jet fuel and deicing chemicals if not contained, contaminating nearby water bodies. Aviation activities emit ozone and ultrafine particles, both of which are health hazards. Piston engines used in general aviation burn Avgas, releasing toxic lead.

Aviation's environmental footprint can be reduced by better fuel economy in aircraft or Air Traffic Control and flight routes can be optimised to lower non-CO2 effects on climate from NO

x, particulates or contrails. Aviation biofuel, emissions trading and carbon offsetting, part of the ICAO's CORSIA, can lower CO2 emissions. Aviation usage can be lowered by short-haul flight bans, train connections, personal choices and aviation taxation and subsidies. Fuel-powered aircraft may be replaced by hybrid electric aircraft and electric aircraft or by hydrogen-powered aircraft.

Wavelength of the electron is 6.28 x 10^(-11) m. The energy of the electron is 3.51 electron volts in energy.

(b) The wavefunction can be represented as ψ(x) = A cos(kx - ωt) where k is the wavenumber.

The wavelength of the electron is given by

λ = 2π/k

Therefore, λ = 2π/(10^10)

Therefore, λ = 6.28 x 10^(-11) m

(ii) The momentum of the electron can be calculated using the de Broglie relation:

p = hk, where h is Planck's constant and k is the wavenumber of the electron.

Therefore, p = h/λ

Therefore, p = 6.626 x 10^(-34)/(6.28 x 10^(-11))

Therefore, p = 1.05 x 10^(-23) kg m/s

(iii) The energy of the electron is given byE = (p^2)/(2m)

where m is the mass of the electron

Therefore, E = (1/2)(9.11 x 10^(-31))(1.05 x 10^(-23))^2

Therefore, E = 5.62 x 10^(-10) Joules

To convert Joules to electron volts, divide by 1.6 x 10^(-19)

Therefore, E = 3.51 eV

Therefore, the energy of the electron is 3.51 electron volts in energy.

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Given

A massive light hangs over the table in Jeremy's dining room. The light is supported by four strong chains which make an angle of 72° with the horizontal.

The force in each chain is F=36.4 N.

To find

The mass of the light in kg

Explanation

Let the mass of the light be m

The weight of the light acts downwards.

To balance thisi force the force on the string vertically upward is considered

In equillibrium

Conclusion

The mass of the light is 13.84 kg

Condensation in a longitudinal wave corresponds to the compression part of a transverse wave.

The compression part of a wave is where the particles of a medium are pushed together, while the rarefaction part is where the particles of the medium are spread apart. Longitudinal waves are waves in which the displacement of the medium is in the same direction as the propagation of the wave. In a longitudinal wave, compression corresponds to the crest of the wave, while rarefaction corresponds to the trough. This is different from a transverse wave, in which the displacement of the medium is perpendicular to the propagation of the wave.

In a transverse wave, the compression corresponds to the highest point of the wave, while rarefaction corresponds to the lowest point of the wave. Condensation in a longitudinal wave is where the particles of the medium are pushed together, while rarefaction is where the particles of the medium are spread apart. This is due to the alternating pattern of high and low-pressure regions that make up the wave. In a longitudinal wave, the regions of high pressure correspond to compression, while the regions of low pressure correspond to rarefaction.Overall, the compression part of a transverse wave corresponds to condensation in a longitudinal wave, while the rarefaction part of a transverse wave corresponds to a rarefaction in a longitudinal wave.

In conclusion, condensation in a longitudinal wave corresponds to the compression part of a transverse wave. The compression part of a wave is where the particles of a medium are pushed together, while the rarefaction part is where the particles of the medium are spread apart. This is due to the alternating pattern of high and low pressure regions that make up the wave.

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The voltage across capacitor 2 is   \(\frac{V}{2}\).

Capacitance:

Two conductors that are separated by an insulating material have the capacity to store charge. This is referred to as capacitance.

Capacitance is, by definition, the ratio of the voltage across its plates to the charge on one of its plates.

Mathematically,

                       \(C=\frac{Q}{V}\)

When Gauss' Law is applied to a closed surface enclosing one of the parallel-plate capacitors, it can be demonstrated that the geometry and material used to fill the space between the plates determine simply how much capacitance is present:

                       C = ∈*A/d

Where,

           A is the capacitor's area, d is the distance between the plates, and ∈ the dielectric constant of the substance between them.

Let's call  C₁, the capacitor of area A, and C₂, the one of area 2*A.

So, we can write the following expression:

C₂ = ∈*2*A / d = 2* (∈*A/d) = 2* C₁

If Q remains constant, we can write the following equality:

⇒ Q = C₁*V = 2*C₁*V₂

Solving for   \(V_{2}\), we have:          

                       \(V_{2}=V/2\)

If the value of the capacitance is doubled, in order to keep Q constant, V₂ must be half of V.

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a. There is a charge of 3.0 Coulombs on each plate.

b. There are approximately \(1.87 * 10^{19}\) excess electrons on the negative plate.

We can use the formula relating charge, capacitance, and voltage for a capacitor:

Q = C * V,

where Q is the charge, C is the capacitance, and V is the voltage.

(a) Since you have two 1.5-volt batteries connected to the capacitor, the total voltage across the capacitor is the sum of the voltages of the batteries:

\(V_{total} = V_1 + V_2 = 1.5 V + 1.5 V = 3 V\).

Using the formula Q = C * V, we can calculate the charge on each plate:

Q = 1.0 F * 3 V = 3.0 Coulombs.

Therefore, on each plate, there is a 3.0 Coulomb charge.

(b) To determine the number of excess electrons on the negative plate, we need to consider the relationship between charge and the elementary charge (e):

Q = n * e,

where Q is the charge, n is the number of excess electrons, and e is the elementary charge (approximately \(1.602 * 10^{-19}\) Coulombs).

From part (a), we know that the charge on each plate is 3.0 Coulombs. Setting this equal to the number of excess electrons multiplied by the elementary charge, we have:

\(3.0 C = n * (1.602 * 10^{-19} C)\)

Solving for n, we get:

n = (3.0 C) / \((1.602 * 10^{-19} C)\) ≈ \(1.87 * 10^{19\) excess electrons.

Therefore, on the negative plate, there are roughly \(1.87 * 10^{19}\) more electrons.

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The complete question is:

(a) Suppose you charge a 1.0 F capacitor with two 1.5 volt batteries. How much charge was on each plate?

(b) How many excess electrons were on the negative plate?

The change in internal energy is 10 J.

Given,

Cross-sectional area, A = 0.10 m²

Pressure of gas, P = 8000 N/m²

Displacement, s = 4 cm = 0.04 m

Heat transferred, H = 42 J

To find,

Change in internal energy =?

We know that, as per Law of thermodynamics,

Change in internal energy = Heat - Work

Force = pressure × area

          = 8000 × 0.10

          = 800 N

Work = Force × Displacement

         = 800 × 0.04

         = 32 J

Change in internal energy = Heat - Work

                                            = 42 - 32

                                            = 10 J

Hence, the change in internal energy is 10 J.

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Answer:

Good one

Explanation:

Hydrogen has the highest thermal conductivity of any gas.

You can change the volume, pressure, or temperature of a gas.

Change the volume of a gas to raise or lower the temperature. As the temperature increases, the gas expands and increases in volume. Conversely, as the temperature decreases, the volume of the gas decreases. As the temperature increases, the volume of the gas increases. Conversely increasing the pressure will decrease the volume of the gas.

Reducing the gas volume increases the gas pressure. An example of this is when gas is trapped inside a cylinder by a piston. When the piston is pushed in, the volume occupied by the gas decreases, so there is less room for gas particles to move. The relationship between pressure and volume Boyle's Law. As the pressure of a gas increases the gas particles are pushed together thus decreasing the volume of the gas.

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Answer:

Explanation:

Yes it can give them a stroke when it's really hot outside. Or give them cancer.

Answer:

yes

Explanation:

if you get to close or severe sun cancer

=> 1200 000 mg

We know that,

1 kg = 1000 g

1 g = 1000 gm

then,

1.2kg = 1.2 × 1000 g = 1200 g

1200 g = 1200 × 1000 mg

Answer:

Since light does not actually pass through this point, the image is referred to as a virtual image. Observe that when the object in located in front of the focal point of the converging lens, its image is an upright and enlarged image that is located on the object's side of the lens.

Explanation:

Answer:

The body has negative acceleration PR a deceleration.

Explanation:

HOPE THAT THIS IS HELPFUL.

HAVE A GREAT DAY.

Answer:

it is a sedimentary rock

In order to avoid injury to driver, The force constant of this spring should be 73.82 N/m

Calculation of force constant to this spring:

Here  

vertical drop is 15 m.

mass of the car, m= 113 kg

gravitational acceleration, g= -9.8 m/s^2

spring compression before car stops, x= 3.0 m

In order to avoid injury to the driver,

we need to use Hooke's law and Newton's second law:

F(net) = F(x)

m*a=-k*x

here a=g

k= -(m*g) / x

here k is force constant of this spring

substituting the values we get,

k = -(113* -9.8) / (15)

k = 73.8266 N/m

Hence,  the force constant of this spring should be 73.82 N/m

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Answer:

a

Explanation:

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At a depth of 500 meters in the mine, the estimated vertical stress is 13.5 MPa, and the estimated horizontal stress is 11.57 MPa. Specific details to consider are Chalk Strength, Chalk Permeability, Chalk Heterogeneity.

Before proceeding with the excavation of the cavern beneath the sea, the main geological information that would be important to have includes the properties and characteristics of the chalk formation. Some specific details to consider are:

a) Chalk Strength: It is essential to determine the strength and stability of the chalk formation to ensure that it can support the excavation without collapsing or experiencing excessive deformation. This would involve assessing parameters such as the cohesion, friction angle, and compressive strength of the chalk.

b) Chalk Permeability: Understanding the permeability of the chalk is crucial, especially since the cavern will be beneath the sea. The permeability will impact the water flow within the chalk and may affect stability, seepage, and potential groundwater inflow into the excavation.

c) Chalk Heterogeneity: Chalk formations can exhibit variations in their composition, including the presence of layers or discontinuities such as faults or joints. Understanding the geological structure and heterogeneity of the chalk will help in assessing the potential for rock mass instability, water ingress, or the presence of other geological hazards.

To estimate the vertical and horizontal in-situ stresses at a depth of 500 meters in the mine, we can use the principles of rock mechanics and consider the given parameters.

Vertical Stress:

The vertical stress is the stress component acting vertically downward due to the weight of the overlying rock. It can be calculated using the average unit weight of the rock and the depth.

Vertical Stress = Unit Weight of Rock × Depth

Vertical Stress = 27 kN/m³ × 500 m

Vertical Stress = 13,500 kN/m² or 13.5 MPa

Horizontal Stress:

The horizontal stress can be estimated using the in-situ stress ratio, which is influenced by Poisson's ratio. The relationship between the horizontal and vertical stresses can be expressed as:

Horizontal Stress = Vertical Stress × (2 × Poisson's Ratio) / (1 - Poisson's Ratio)

Horizontal Stress = 13.5 MPa × (2 × 0.3) / (1 - 0.3)

Horizontal Stress = 13.5 MPa × 0.6 / 0.7

Horizontal Stress = 11.57 MPa

Therefore, at a depth of 500 meters in the mine, the estimated vertical stress is 13.5 MPa, and the estimated horizontal stress is 11.57 MPa.

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Answer:

Decreases by \($3.6 \times 10^{-3}$\) times

Explanation:

The intensity of a sound is defined as the energy of the sound that is flowing in an unit time through the unit area which is in the direction that is perpendicular to the direction of the sound waves movement.

The intensity of energy is described by the inverse square law. It states that the intensity varies inversely with the distance square of the distance.

In other words, the sound intensity decreases as inversely proportional to the squared of the distance.  i.e. \($\frac{1}{r^2}$\)

In the context when the distance was 3 m, the intensity of the sound was = \($\frac{1}{9}$\)

But when the distance became 6 cm or 0.06 m, the sound intensity decreases by =  \($\frac{1}{0.06^2}$\)

                       = \($3.6 \times 10^{-3}$\) times

Water speeds up as it flows from a large-diameter section to a small-diameter section in a horizontal pipe due to the principle of conservation of mass and the continuity equation.

When water flows through a horizontal pipe, the principle of conservation of mass states that the mass of water entering a section must equal the mass of water exiting that section. According to the continuity equation, which is derived from this principle, the product of the cross-sectional area and velocity of the water must remain constant along the pipe.

As the pipe narrows and the cross-sectional area decreases, the continuity equation implies that the velocity of the water must increase to maintain the constant mass flow rate. This is known as the principle of continuity.

To illustrate, consider a pipe with a larger diameter. In this wider section, the cross-sectional area is greater, allowing the water to occupy a larger volume. As the water flows into a smaller-diameter section, the same amount of water must pass through a smaller area, resulting in an increase in velocity to compensate for the reduced area. This phenomenon is known as the Venturi effect.

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Answer:The object has negative acceleration and eventually stops.

Explanation:

Answer:not sure

Explanation:

Sorry:(

Decrease

The mathematical relationship between heat, internal energy and work done by the system is given as:

△U = Q + W

where △U is the change in the internal energy

W is the workdone by the system

Q is the heat energy in the system

Since the workdone by the system is negative, when a system does work, there is a depletion in the amount of energy possessed by the system.

Due to this loss of energy by the system as a result of the workdone, the internal energy decreases.

The statement is True.

Weight lifting is an example of anaerobic exercise. Anaerobic exercise involves short bursts of intense physical activity that do not require significant amounts of oxygen.

Weight lifting typically involves lifting heavy weights for a short period of time, which requires the muscles to produce energy without oxygen.

During anaerobic exercise, the body relies on stored sources of energy, such as creatine phosphate and glycogen, rather than oxygen, to fuel the muscles.

Therefore, weight lifting is considered an example of anaerobic exercise.

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When light travels in a certain medium and falls on the surface of another medium a part of it turns back in the same medium This phenomenon is called Reflection.

A wavefront may alter its course at an interface between two different media and return to the first medium, a phenomenon known as reflection. Common examples are the reflection of light, sound, and water waves.

Reflection of light refers to the occurrence where light strikes an item and bounces back off its surface. Examples: using a flat mirror to reflect. by a spherical mirror's reflection. There are essentially two types of reflection that apply to light. While diffuse reflection is caused by rough surfaces that tend to reflect light in all directions, specular reflection is described as light reflected off a smooth surface at a specific angle.

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Answer: Heat for making hot water

Heating buildings and cooking.

To generate electricity with solar cells or heat engines, and to take the salt away from sea water.

Explanation:

Answer:

The air was blew into the balloon, which means that it was above room temperature. The space between particles is warm are far apart, so the air in the balloon is fully spaced out.

If you were to place the balloon inside of a freezer, then the space between the particles would close in and cause the balloon to shrink, similar to the picture below.

I hope this helped & Good Luck <3!!

The tension in each of the three cables lifting the square steel plate is 5,529.6 N.

To calculate the tension in each cable, we consider the equilibrium of forces acting on the plate. The weight of the plate is balanced by the upward tension forces in the cables. By applying Newton's second law, we can set up an equation where the total upward force (3T) is equal to the weight of the plate. Solving for T, we divide the weight by 3 to find the tension in each cable. Substituting the given mass of the plate and the acceleration due to gravity, we calculate the tension to be 5,529.6 N. This means that each cable must exert a tension of 5,529.6 N to lift the plate while keeping it horizontal.

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