the international space station is in a 260-mile-high orbit. what is the station's orbital speed? the radius of earth is 6.37×106m , its mass is 5.98×1024kg. orrbital period

Answer:

When a spring is stretched or compressed, so that its length changes by an amount x from its equilibrium length, then it exerts a force F = -kx in a direction towards its equilibrium position. The force a spring exerts is a restoring force, it acts to restore the spring to its equilibrium length.

Explanation:

Hope This Helps!

A force is generated when a spring is stretched or compressed due to change in position against its normal state.

When a spring is stretched or compressed, so that its length changes by an amount x from its original length. After releasing it, it exerts a force F = -kx in a direction towards its original position. The force a spring exerts is a restoring force, it acts to restore the spring to its equilibrium length.

In conclusion, a force is generated when a spring is stretched or compressed due to change in position against its normal state.

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Answer:

The correct answer to the following question will be "2.7 m".

Explanation:

The given values are:

Velocity, v = 16 m/s

mass, m = 0.27 kg

Mechanical energy, M.E = 41.70 J

g = 9.8 m/s²

As we know,

Kinetic energy, \(K=\frac{mv^2}{2}\)

Potential energy, \(U=m.g.h\)

Now, the total mechanical energy will be:

⇒  \(\frac{mv^2}{2}+U\)

⇒  \(41,71 \ kg.m^2/s^2\)

Now,

⇒  \(h=\frac{E-(\frac{mv^2}{2})}{mg}\)

On putting the estimated values, we get

⇒    \(=\frac{41.70-(\frac{0.27(16)^2}{2})}{0.27\times 9.8}\)

⇒    \(=\frac{41.70-(\frac{0.27\times 256}{2} )}{2.64}\)

⇒    \(=\frac{41.70-34.56}{2.64}\)

⇒    \(=\frac{7.14}{2.64}\)

⇒    \(=2.7 \ m\)

Answer:

2.7 m

Explanation:

The answer is time for this trip would elapse on a clock on board the spaceship is \(1.02 \times 10^{8} secends\)

\(V_{0}=0.800 \mathrm{C}\)

Distance from Earth (x)=4.30 light-years

Time req. to do in earth frame of reference \($=\frac{4.30 \text { light years }}{0.800 \mathrm{c}}$\)

\($=\frac{4.3 \times 9.46 \times 10^{15} \mathrm{M}}{0.8 \times 3 \times 10^{8} \mathrm{~m} / \mathrm{s}}$\)

\($=1.695 \times 10^{8}$\) seconds

proper time  = Time in earth's reference\($\sqrt{1-\frac{v^{2}}{C^{2}}}$\)

\(=1.698 \times 10^{8} \times 0.6=1.02 \times 10^{8} secends\)

What is Space contraction?

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The planetesimals, which are small bodies that eventually formed into larger objects such as planets, are believed to have formed last in our solar system.

Our solar system formed around 4.6 billion years ago from a cloud of gas and dust, known as the solar nebula. The sun formed first from the dense, hot center of the nebula. As the sun formed, it began to emit heat and radiation, which caused the remaining gas and dust to begin to condense and form into small objects known as planetesimals.

As these planetesimals collided and merged, they grew larger and larger, eventually forming the inner planets, such as Mercury, Venus, Earth, and Mars. The outer planets, such as Jupiter and Saturn, also formed from the collision and merger of planetesimals, but they formed later in the process.

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Your question seems incomplete, but I assume the question was:

"Which object(s) formed last in our solar system?

the sun

the solar nebula

the inner planets

the planetesimals."

The percentage of mechanical energy lost in each cycle of the lightly damped oscillator is approximately 0.00001111%, which can be considered negligible.

In a lightly damped oscillator, the percentage of mechanical energy lost per cycle can be determined using the formula:

Energy loss percentage = (1 - sqrt(R^2 + (1 - R^2)^2)) * 100

where R is the ratio of amplitude in one cycle to the amplitude in the previous cycle.

Given that the amplitude of the oscillator decreases by 2.80% during each cycle, we can calculate the value of R:

R = 1 - 0.028

R = 0.972

Now we can substitute this value into the formula to find the percentage of mechanical energy lost per cycle:

Energy loss percentage = (1 - sqrt(0.972^2 + (1 - 0.972^2)^2)) * 100

Energy loss percentage ≈ (1 - sqrt(0.944784 + 0.055215776)) * 100

Energy loss percentage ≈ (1 - sqrt(0.999999776)) * 100

Energy loss percentage ≈ (1 - 0.9999998889) * 100

Energy loss percentage ≈ 0.0000001111 * 100

Energy loss percentage ≈ 0.00001111

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The use of machines with a mechanical advantage greater than 1 allows us to lift heavier loads with less force, but it also requires us to do more work over a longer distance.

When using a machine with a mechanical advantage greater than 1, you must apply a smaller force over a longer distance in order to lift a load. This is because the machine reduces the amount of force needed to lift the load, but it increases the distance over which that force must be applied.

This is known as the principle of work and energy conservation, which states that the amount of work done on a system is equal to the amount of work done by the system.

For example, if you are using a lever to lift a heavy object, the lever will increase the force applied to the object, but it will also require you to move the lever over a greater distance.

So, in order to take advantage of the lever's mechanical advantage, you must apply a smaller force over a greater distance to move the load. This requires more work on your part, but the work is spread out over a longer distance, which may make it easier to accomplish.

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Answer:

B. A hill 70ft tall.

Explanation:

Ai. The period of the wave is 0.04 s.

Aii. The frequency of the wave is 25 Hz

B. The wave speed is 15 m/s

i. How to determine the period

We can obtain the period of the wave as illustrated below:

Period = t / n

Period = 0.04 / 1

Period = 0.04 s

Thus, the period of the wave is 0.04 s

ii. How to determine the frequency

The frequency of the wave can be obtained as illustrated below:

f = 1 / T

f = 1 / 0.04

f = 25 Hz

Thus, the frequency of the wave is 25 Hz

v = λf

v = 0.6 × 25

v = 15 m/s

Thus, the wave speed is 15 m/s

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The given statement that “rate of crystallization is higher when a solution is more saturated" is true.However, we must first understand the meaning of "crystallization" and "saturation" before answering the question.The process by which a solid forms from a liquid or gas phase is known as crystallization.

A solution is saturated if it contains the maximum quantity of solute that may dissolve in the solvent at a particular temperature and pressure. A solution can be classified as unsaturated if it contains less than the saturation level, and supersaturated if it contains more than the saturation level. What is the relationship between crystallization and saturation.

When a solution reaches its saturation point, the solute is no longer soluble in the solvent. As a result, any extra solute added to the solution will form crystals. Furthermore, when a solution is highly saturated, the crystals will form at a faster rate than when it is not as concentrated. As a result, the statement "rate of crystallization is higher when a solution is more saturated" is true.

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Answer:

B.Smooth, wide shape with a curved edge

Answer:

the most important effect of the gravitational force is the change in the tide.

Explanation:

The gravitational force between the Moon and the Earth is given by

        F = G m M / r2

where m is the mass of the Moon, M the mass of the Earth, and r the distance between the two.

The magnitude that changes in this formula is the distance between the Moon and the Earth, due to the lunar rotation, at the points of maximum approach in the periods of high tide and in the periods of greater distance the tide is low.

It should be mentioned that the earth's crust is also affected, but its movement is much less than that of water, which is why in almost all cases it is taken as fixed.

Lately it has also been analyzed that the Earth-Moon structure creates greater stability in the rotation of the two bodies.

Consequently the most important effect of the gravitational force is the change in the tide.

Answer:

200 meters+1000 meters+800 meters=2000 meters or 2km

Explanation:

1km=1000m

Answer:

m = 3 kg

Explanation:

It is given that,

Initial speed of a ball is 5 m/s, u = 5 m/s

Final speed of a ball is 4 m/s, v = 4 m/s (as it bounces)

Impulse provided by the wall is -3 N-m (impulse is provided in opposite direction)

We need to find the mass of the ball. Impulse provided to an object is given by the change in its momentum as :

J = m(v-u)

m is mass of the ball

\(m=\dfrac{J}{(v-u)}\\\\m=\dfrac{-3}{(4-5)} \\\\m=3\ kg\)

So, the mass of the ball is 3 kg.

Answer:

Explanation:

Acceleration is the time rate of change, or the rate, of the velocity. Therefore, the slope y/x of a speed vs time graph would give the acceleration. If the acceleration is said to be positive, the graph would be a straight line that is at a constant increase over time.

Answer:

The answer is D. They are a mass.

Answer:

“they have mass” because if they don’t have mass they can’t exert force even if they have speed if they have no mass they can’t do anything or exert force

Explanation:

Two locomotives with a speed of 150 km/h each, reach the other in: 1.9 min

The formula of reach time and procedure we will use to solve this problem is:

Tr = x/(v2+v1)

Where:

Information about the problem:

Applying the reach time formula we get:

Tr = x/(v2+v1)

Tr =  9.5 km/(150 km/h + 150 km/h)

Tr = 9.5 km/(300 km/h)

Tr = 0.032 h

By converting the time units from (h) to (min) we have:

0.032 h * (60 min / 1h) = 1.9 min

It is a physical quantity that indicates the displacement of a mobile per unit of time, it is expressed in units of distance per time, for example (miles/h, km/h).

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The abbreviation for the SI unit for electric potential is V.

This is defined as the amount of work energy needed to move a unit of electric charge from one point to another in an electric field.

Electric potential =  Energy/ Charge

The unit of electric potential is either Joules per coulomb or Volts(V) which makes option A the most appropriate choice.

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Answer:

V

Explanation:

a bee whispered me the answer

Answer:

Is this a true and false statement?

Explanation:

Answer:

Explanation:

20890

The circuit has a constant gain of 1 for high frequencies, implying that it acts as a low-pass filter. To find the frequency response function H(w) for the given circuit, we need to determine the transfer function H(w) = V0(w) / Vi(w), where V0(w) is the output voltage and Vi(w) is the input voltage in the frequency domain.

L = 1 H (inductance)

R = 3.9 KΩ (resistance)

The circuit can be represented by the following equation:

H(w) = (jwL + R) / (jwL + R + 1)

To sketch the magnitude of the frequency response function H(w), we need to plot the magnitude |H(w)| as a function of frequency w.

Taking the magnitude of the transfer function, we have:

|H(w)| = |(jwL + R) / (jwL + R + 1)|

Next, let's analyze the type of ideal filter approximated by this circuit. We can examine the transfer function to determine the filter characteristics.

From the transfer function:

H(w) = (jwL + R) / (jwL + R + 1)

As w approaches infinity, the jwL term dominates the transfer function, and the transfer function becomes:

H(w) ≈ jwL / jwL = 1

This indicates that the circuit has a constant gain of 1 for high frequencies, implying that it acts as a low-pass filter. It allows low-frequency signals to pass through relatively unattenuated while attenuating high-frequency signals.

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Answer: a. -720m/s^2

b. Yes, airbags will deploy

Explanation:

The formula for acceleration is:

= (Final velocity - Initial velocity)/Time

Final velocity = 0m/s

Initial velocity = 36m/s

Time taken = 0.05s

= (Final velocity - Initial velocity)/Time

= (0 - 36)/0.05

= -36/0.05

= -720m/s^2.

Since it's negative, it shows that there was a deceleration.

2. Yes the airbag will deploy since the acceleration gotten is more than -600 m/s^2.

Option C) is correct in determining its mass from its gravitational pull on a spacecraft, satellite, or planet. Knowing the mass and size of an asteroid allows us to calculate its density.

Option A) is incorrect because reflectivity only tells us about the asteroid's surface properties, not its density. Option B) is incorrect because brightness variations during rotation do not give us enough information to determine density. Option D) and E) are methods of studying asteroids but are not directly related to determining density.

Knowing the size of an asteroid alone is not enough to determine its density, as different materials can have different densities at the same size. By measuring the gravitational pull of the asteroid on a spacecraft, satellite, or planet, we can determine its mass. Once we have the mass and the size, we can calculate the asteroid's density. Methods such as radar mapping and spectroscopic imaging can provide additional information about the asteroid's composition, but they are not directly used to determine its density.

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C) calculating its mass based on the gravitational attraction it exerts on a satellite, planet, or spacecraft.

We can determine an asteroid's mass by observing the gravitational pull it has on a neighbouring body, like a planet, satellite, or spacecraft. We can determine the asteroid's density once we know its mass and size. The gravitational force of an object will be stronger the denser it is. As a result, an asteroid must be denser the more massive it is for a given size.

The density of an asteroid can be determined using this method, which is especially helpful for small or erratic-shaped asteroids that are challenging to see using other techniques like radar mapping or spectroscopic imaging. Additionally, it can offer crucial details on the asteroid's makeup and structure, which can aid researchers in understanding the asteroid's formation and evolution.

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The initial horizontal velocity v0 of the object can be expressed in terms of the spring constant k, the compression of the spring x, and the mass m of the object as:

v0 = √(k\(x^{2}\)/m)

Let's assume an object of mass m is placed on a spring with spring constant k and compressed by a distance x. When the spring is released, it will exert a force on the object in the upward direction, and the object will begin to move upward.

At the moment the object loses contact with the spring, the spring potential energy stored in the spring will be converted into kinetic energy of the object. This means that the spring potential energy must be equal to the kinetic energy of the object.

The spring potential energy can be expressed as

U = 1/2 k\(x^{2}\)

The kinetic energy of the object can be expressed as

K = 1/2 m\(v_{0} ^{2}\)

Where v0 is the initial horizontal velocity of the object.

Setting U equal to K, we get

1/2 k\(x^{2}\) =  1/2 m\(v_{0} ^{2}\)

Solving for v0, we get:

v0 = √(k\(x^{2}\)/m)

Therefore, the initial horizontal velocity v0 of the object can be expressed in terms of the spring constant k, the compression of the spring x, and the mass m of the object as:

v0 = √(k\(x^{2}\)/m)

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Explanation:

Average velocity = displacement / time

v = (25 m − 2 m) / 4.5 s

v = 5.11 m/s

Answer:

The distance the box traveled down the plane is 19.28 m

Explanation:

The angle of repose, α, is given by the relation;

tan⁻¹(μ) = α

tan⁻¹(0.1) = 5.7°

Therefore, we have;

M·g·sin(θ) - μ·N = M·a

Where:

M = Mass of the box = 10 kg

g = Acceleration due to gravity = 9.81 m/s²

θ = Angle of inclination of the plane = 30°°

μ = Coefficient of friction = 0.1

a = Acceleration of the box along the incline plane

N = Normal force due to the weight of the box = M·g·cos(θ)

10 × 9.81 × sin30 - 0.1 × 9.81 × cos(30)  = 10 × a

48.2 = 10 ×a

a = 48.2/10 = 4.82 m/s²

The distance, s, traveled by the box is given by the relation;

s = u·t + 1/2×a·t²

Where:

u = Initial velocity = 0 m/s

t = Time of motion = 2.0 s

∴ s = 0×2 + 1/2 × 4.8 × 2² = 19.28 m

The box traveled 19.28 m down the plane.

The distance that the box travels down the plane is 8.1 m.

The given parameters;

The acceleration of the box is calculated as follows;

\(\Sigma F_{net} = ma\\\\mgsin\theta - \mu mg cos\theta = ma\\\\gsin\theta - \mu g cos\theta = a\\\\g(sin\theta - \mu cos \theta ) = a\\\\9.8(sin30 \ - \ 0.1\times cos 30) = a\\\\9.8(0.413) = a\\\\4.05 \ m/s^2 = a\)

The distance traveled by the box down the plane is calculated as follows;

\(s= ut + \frac{1}{2} at^2\\\\s = 0 + \frac{1}{2} \times 4.05 \times 2^2\\\\s = 8.1 \ m\)

Thus, the distance that the box travels down the plane is 8.1 m.

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Answer:

127.12 m/s

Explanation:

From the question,

Kinetic energy of the bowling ball = Kinetic energy of the ping pong ball

1/2mv² = 1/2m'v'²

Where m = mass of the bowling ball, v = velocity of the bowling ball, m' = mass of the ping pong ball v' = velocity of the ping pong ball

make v' the subject of the equation

v' = √(mv²/m')................ Equation 2

Given: m = 7.0 kg, v = 2.45 m/s, m' = 2.60 g = 0.0026 kg

Subtitute into equation 2

v' = √[(7×2.45²)/0.0026]

v' = √16160.57

v' = 127.12 m/s

The size of force slowing the car down is 22.2 m.

What is acceleration due to friction?

The formula is a = F/ m.

This comes from Newton's Second Law.

Like we know that friction is included here, we need to derive the formula according to the situation, a = (F – Ff) / m. Here friction will accelerate the object more.

The force of static friction is what pushes your car forward.

The engine provides the force to turn the tires which, in turn, pushes backwards against the road surface.

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