The law of ________________________ states that charges are not created or destroyed. They are transferred.

The electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.

To find the electric field strength at a distance 1.20 m on the x-axis, we can use Coulomb's law:

\($$F=k\frac{q_1q_2}{r^2}$$\)

where F is the force between two charges, q1 and q2 are the magnitudes of the charges, r is the distance between the charges, and k is the Coulomb constant.For a single point charge q located at the origin of the x-axis, the electric field E at a distance r is given by:

\($$E=\frac{kq}{r^2}$$\)  where k is the Coulomb constant.

So, let's calculate the electric field due to each charge separately and then add them up:

For the +2.0 C charge at x = 0, the electric field at a distance of 1.20 m is:\($$E_1=\frac{kq_1}{r^2}=\frac{(9\times10^9)(2.0)}{(1.2)^2}N/C$$\)

For the -3.0 C charge at x = 0.40 m, the electric field at a distance of 1.20 m is:

\($$E_2=\frac{kq_2}{r^2}\)

\(=\frac{(9\times10^9)(-3.0)}{(1.20-0.40)^2}N/C$$\)

The negative sign indicates that the direction of the electric field is opposite to that of the positive charge at x = 0.

To find the net electric field, we add the two electric fields\(:$$E_{net}=E_1+E_2$$\)

Substituting the values of E1 and E2:

\($$E_{net}=\frac{(9\times10^9)(2.0)}{(1.2)^2}-\frac{(9\times10^9)(3.0)}{(0.8)^2}N/C$$E\)

net comes out to be -1.5×10⁴ N/C.

Therefore, the electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.

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(a) The magnitude of the total force provided by both posts is 1,068.2 N.

(b) The force the post that is closest to the painter push upward on the board is 710.9 N.

The magnitude of the total force provided by both posts is calculated as follows;

sum of the upward force = sum of downward force

total upward force provided by the post = weight of boar + weight of the painter

total upward force provided by the post = (27 x 9.8) + (82 x 9.8)

total upward force provided by the post = 1,068.2 N

The force the post that is closest to the painter push upward on the board is calculated as follows;

the total downward weight is distributed as follows;

= ¹/₂ (weight of board) + (5.5 - 1.55) / (5.5) x (weight of the painter)

= 0.5 (27 kg x 9.8 m/s²)  +  0.72 (82 kg  x 9.8 m/s²)

= 710.9 N

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When an electron approaches a positively charged nucleus, it experiences an electrostatic attraction due to the opposite charges of the two particles.

As the electron gets closer to the nucleus, the electrostatic attraction becomes stronger, and the electron's kinetic energy decreases. At the same time, the electron's potential energy decreases as it moves from a region of high potential energy (far from the nucleus) to a region of lower potential energy

This electrostatic attraction is governed by Coulomb's law, which states that the force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

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Answer:

273,000 Astronomical Units.

Explanation:

4.3 light years = 40,850,000,000,000 kilometeres, 4.3 x 9,500,000,000,000.

Convert kilometers to astronomical unit:

149,597,870 kilometers = 1 AU, convert unit.

40,850,000,000,000 divided by 149,597,870 = 273,065.385222 or approx. 273,000 AU.

Explanation:

Some Uses of Electromagnetic waves :

(A) Microwaves

(B) X - Rays (produced by slowing fast moving electrons)

(C) Radio Waves

Answer:

^ correct

Explanation:

Option A on edge 2020

The oscillation angular frequency of a drop with half of the first drop's radius is 4ω

Surface tension is the tension force exerted on an object by the surface of a liquid.

Angular frequency is the frequency of oscillation of a rotating object. It is given in rad/s.

Given that

Since the energy of the drop is conserved, using the law of conservation of angular momentum, we have

Iω = I'ω' where

So, Iω = I'ω'

Making ω' subject of the formula, we have

ω' = Iω/I'

ω' = mr²ω/mr'²

ω' = r²ω/r'²

Given that the drop is half of the first drop's radius, r' = r/2

So, ω' = r²ω/r'²

ω' = r²ω/(r/2)²

ω' = r²ω/r²/4

ω' = 4ω

So, the oscillation angular frequency of a drop with half of the first drop's radius is 4ω

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Answer:

Answer: Diamond has a refractive index of 2.42 which means that the speed of light in diamond will reduce by a factor of 2.42 as compared to its speed in the air. In other words, the speed of light in diamond is 1/2.42 times the speed of light in vacuum.

Answer:

The refractive index of a material is a measure of how much a material bends light as it passes through it. The refractive index of a material is defined as the ratio of the speed of light in a vacuum to the speed of light in the material. A refractive index of 2.42 for diamond means that light travels through diamond at about 42% slower than it does in a vacuum. This high refractive index is due to the high density and strong chemical bonds of the carbon atoms in diamond. This high refractive index gives diamond its characteristic brilliance and fire, and makes it

Answer:

injecting

Explanation:

In a space with hyperbolic geometry, the behavior of parallel lines differs from that of Euclidean geometry.

In hyperbolic space, parallel lines diverge from each other as they extend further.If two initially parallel flashlight beams traverse billions of light-years of space in a hyperbolic geometry, they will gradually diverge from each other. The divergence between the beams will increase as they travel a greater distance.

This phenomenon is a consequence of the non-Euclidean geometry of space. In hyperbolic space, the curvature causes parallel lines to "spread out" or diverge. The extent of the divergence will depend on the specific curvature of the space and the distance traveled.

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This implies that stopping distance and impact force grow as a function of speed. The best ways to improve manoeuvrability and lessen crash severity are to drive at an appropriate pace and to slow down as soon as you spot dangers in front of you.

Keep in mind that stopping distance increases with speed; at 50 mph, it is four times longer than at 25 mph, and at 75 mph, the force of impact is nine times greater.

When your car expends or absorbs energy to speed up or slow down, you may feel a pull or a jolt, called impulse. Impulse increases as the energy or force increases, and increases as the duration of the force decreases. You'll feel a harder jolt if you speed up or slow down suddenly.

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Answer:

187N

Explanation:

weight = mass * gravity

weight = 50 * 3.7

weight = 187N

The new angle of deflection of the north pole of the compass needle compare to its initial deflection is smaller.

The new angle of deflection north pole becomes smaller

The angle of deflection is the angle formed when an object changes course from its original course of direction or target.

The angle of deflection of a particular particle is directly proportional to its charge to mass ratio as it passed through an electric field.

As the wire is continuously being lowered farther from the compass, the angle of deflection of the north pole continues to become smaller when compared to its initial deflection.

Therefore, the new angle of deflection of the north pole of the compass needle compare to its initial deflection is smaller.

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Answer:

B

Explanation:

Speed is distance divided by time.

Answer:

168 Hz

Explanation:

The Doppler equation describes how sound frequency depends on relative velocities:

fr = fs (c + vr) / (c + vs),

where fr is the frequency heard by the receiver,

fs is the frequency emitted at the source,

c is the speed of sound,

vr is the velocity of the receiver,

and vs is the velocity of the source.

Note: vr is positive if the receiver is moving towards the source, negative if away.

Conversely, vs is positive if the receiver is moving away from the source, and negative if towards.

Given:

fs = 164 Hz

c = 343 m/s

vr = -15 m/s

vs = -23 m/s

fr = fs (c + vr) / (c + vs)

fr = 164 Hz (343 m/s − 15 m/s) / (343 m/s − 23 m/s)

fr = 168 Hz

In ohmic resistors, the potential difference (V) is directly proportional to the current (I) and the resistance (R) of the material and in non-ohmic resistors, the relationship between potential difference, current, and resistance is not linear.

(1) In the case of ohmic resistors, the current and resistance behave according to Ohm's law, which states that the potential difference (V) across a resistor is directly proportional to the current (I) passing through it and the resistance (R) of the material. Mathematically, it is represented as V = IR. As the potential difference increases, the current also increases proportionally, assuming the resistance remains constant.

In the case of non-ohmic resistors, the relationship between potential difference, current, and resistance is not linear, meaning Ohm's law does not apply. Examples include diodes, thermistors, and varistors. In these cases, the resistance may change with factors like temperature or the applied voltage, leading to a nonlinear relationship between current and potential difference.

(0.5) In a single-loop circuit with a battery, two wires, and a 10 Ohm resistor, the current flowing through the circuit is the same for all elements since it is a series circuit. This is due to Kirchhoff's current law, which states that the total current entering a junction must be equal to the total current leaving the junction. As there is only one path for current flow in this circuit, the current remains constant across all elements.

(0.5) Using Ohm's law (V=IR), we can relate the physical quantities of the circuit elements. For the 10 Ohm resistor, the potential difference across it is the product of the current and resistance (V_R = I * 10 Ohms). For the ohmic wires, the potential difference across each wire is the product of the current and their respective resistances (V_W1 = I * R_W1 and V_W2 = I * R_W2). The total potential difference across the circuit (V_total) is the sum of potential differences across each element: V_total = V_R + V_W1 + V_W2.

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Answer:

Also, you could do this for the groups:

Group 1- creatures with scales

Group 2- creatures with fur

Group 3- creatures with feathers

For 4 groups you could possible do:

Group 1- no legs

Group 2- 2 legs with wings

Group 3- 2 legs without wings

Group 4- 4 legs

Answer:

The pushing force and the skier's mass

(A) is correct option.

Explanation:

Given that,

Mass = 64 kg

Weight = 608 N

Velocity = 21 m/s

Forward force = 45 N

We need to calculate the reaction force of the snow pushing  on the skier

Using given data,

The reaction force of the snow pushing  on the skier is equal to the pushing force and the skier's mass.

Hence, The pushing force and the skier's mass

(A) is correct option.

The two key events in skiing are the air friction (air resistance) that pushes on a skier's body and the friction between the ski base and the snow. Thus, option A is correct.

A thin lubricating water layer produced while skiing can be used to explain the low sliding friction between skis and snow. For sliding to take place, this extremely thin water film is necessary.

While numerous frictional forces work to counter the skier's motion, gravity acts to speed the skier down the hill. Downhill skiing heavily relies on reducing friction.

Therefore, forces from snow reactions, friction, and gravity. Skiers are subject to these factors. In order to maintain equilibrium, a skier must control these pressures through both proactive and defensive actions.

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Answer:

9)a

10) I think true

11)b

Explanation:

9)a. because it's told that the car is slowing down, the sum of the forces that are towards left, should be more than the ones that are towards right. if the car was gaining speed, "b" would have been correct. and if it was told that the car is moving without a change in the speed, "c" would have been correct.

10) if a moving object has a change of speed or direction, it would have an acceleration. now if a moving object experiences an unbalanced force, it'd either slow down, gain speed or change direction, and in all of the three possibilities it'd have an acceleration.

11) upward and downward forces are equal, and the sum of them would be 0N(because they have opposite directions). so they negate each other.

and the rightward force is 5N more than the leftward force. so the Net Force would be 5N.

-30+30-10+15=5N

if it is unclear or you need more explanation, ask freely.

The energy of a photon is given by the equation E = hf, where h is Planck's constant and f is the frequency of the photon. Substituting the given values, we get:

E = (6.6 x 10^-34 J s) x (4 x 10^4 Hz)
E = 2.64 x 10^-29 J

Therefore, the energy of a photon with a frequency of 4 x 10^4 Hz is 2.64 x 10^-29 Joules.

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Answer:

i think it A sorry if i get it wrong but it should be A

Explanation:

Answer:

6.002

6.020

6.023

6.302

Explanation:

Answer:

t = 3.01 s

Explanation:

In order to calculate how long it takes to the object to fall to the ground, you use the following formula, for the calculation of the height:

\(y=y_o-v_ot-\frac{1}{2}gt^2\)    (1)

yo: height of the building = 105 m

vo: initial velocity of the body = 20m/s

g: gravitational acceleration = 9.8m/s^2

t: time = ?

To find the time t, you take into account that when the body arrives to the ground the height is zero, that is, y = 0.

You replace the values of all parameters in the equation (1), and you obtain a quadratic polynomial for t:

\(0=105-20t-\frac{1}{2}(9.8)t^2\\\\0=-4.9t^2-20t+105\)

Next, you use the quadratic formula to get the roots of the polynomial:

\(t_{1,2}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\)

a = -4.9

b = -20

c = 105

\(t_{1,2}=\frac{-(-20)\pm\sqrt{(-20)^2-4(-4.9)(105)}}{2(-4.9)}\\\\t_1=3.01s\\\\t_2=-7.09s\)

You choose the positive value t1, because it has physical meanning.

Hence, the body takes 3.01s to arrive to the ground

(i) The hydraulic gradient is 0.45.

(ii) The flow rate is approximately 0.00000167 cubic meters per second.

(iii) The hydraulic conductivity is approximately 0.000037 meters per second.

(i) Hydraulic gradient:

The hydraulic gradient (i) can be calculated by dividing the head difference (h) by the distance (L) between the manometer tappings:

i = h / L

Given:

Head difference (h) = 45 mm

Distance between manometer tappings (L) = 100 mm

Converting the units to meters:

h = 45 mm / 1000 = 0.045 m

L = 100 mm / 1000 = 0.1 m

Substituting the values into the formula:

i = 0.045 m / 0.1 m = 0.45

(ii) Flow rate:

The flow rate (Q) can be calculated using the equation:

Q = (V / t) / A

Where V is the quantity of water collected, t is the duration of the test, and A is the cross-sectional area of the test sample.

Given:

Quantity of water collected (V) = 500 ml = 0.5 L

Duration of test (t) = 300 seconds

Diameter of test sample (d) = 100 mm

Converting the units to meters:

V = 0.5 L = 0.5 / 1000 = 0.0005 m³

t = 300 seconds

d = 100 mm / 1000 = 0.1 m

Calculating the cross-sectional area (A) using the formula for the area of a circle:

A = π * (d/2)^2

Substituting the values:

A = π * (0.1/2)^2 = π * 0.005^2 = 0.00007854 m²

Substituting the values into the formula for flow rate:

Q = (0.0005 m³ / 300 s) / 0.00007854 m²

Calculating the flow rate:

Q = 0.00000167 m³/s

(iii) Hydraulic conductivity:

The hydraulic conductivity (K) can be calculated using Darcy's Law:

K = Q / (A * i)

Given the values we calculated:

Q = 0.00000167 m³/s

A = 0.00007854 m²

i = 0.45

Substituting the values into the formula:

K = 0.00000167 m³/s / (0.00007854 m² * 0.45)

Calculating the hydraulic conductivity:

K ≈ 0.000037 m/s

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The energy difference between the staggered and eclipsed populations of ethane depends on various factors such as bond length, bond angle, and bond energy.

In general, the energy difference between these two populations is proportional to the difference in their molecular structure.]

If the difference in molecular structure between the staggered and eclipsed populations of ethane had only been 30-fold instead of the almost three orders of magnitude, it would result in a proportionally smaller energy difference between them. However, without more specific information about the specific molecular structure and bond energies involved, it is not possible to determine the exact energy difference.

In general, it's important to note that the magnitude of the energy difference between the staggered and eclipsed populations of ethane can be influenced by various factors such as temperature, pressure, and the presence of other molecules. These factors can affect the magnitude of the energy difference and make it difficult to determine an exact value.

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A satellite in a circular orbit has a centripetal acceleration of 8. 89 m/s and tangential speed of 7.76 x 10³ m/s. The altitude of the satellite is  3.936 x 10 ⁵ m

The formula for the centripetal acceleration is given by:

a = v²/R

Where:

v = tangential speed

R = radius from the center of rotation.

In the given problem:

a = 8.89 m/s²

v = 7.76 x 10³ m/s

Let h = altitude of the satellite, then

R = earth's radius + h

R = 6.38 x 10⁶ + h

Plug these parameters into the formula:

8.89 = (7.76 x 10³)²/ ( 6.38 x 10⁶ + h)

8.89 h = 60.2176 x 10⁶ -  56.7182 x 10⁶

h = 3.936 x 10 ⁵ m

Hence, the altitude of the satellite is 3.936 x 10 ⁵ m

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The equilibrant force of the two given forces is 14.14 N.

The given parameters:

The equilibrant force of the two given forces is calculated as follows;

\(F = \sqrt{F_1 ^2 + F_2 ^2} \\\\F = \sqrt{(10)^2 + (10)^2} \\\\F = 14.14 \ N\)

Thus, the equilibrant force of the two given forces is 14.14 N.

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Answer:

Acceleration is the rate of change of velocity. Usually, acceleration means the speed is changing, but not always. When an object moves in a circular path at a constant speed, it is still accelerating, because the direction of its velocity is changing.