the loadability of a short line is determined by a. steady-state stability limit b. thermal limit c. voltage-drop limit
Answers
Thermal limit establishes a short line's loadability.
What are the elements that restrict the loading capacity?What Constrains the Capability of Loading? Thermal: The ground clearance, conductor condition, ambient temperature, wind speed, and wind direction all affect an overhead line's thermal capacity. Due to the unstable environment and the history of loading, it may vary by a factor of 2 to 1.
What can we do to improve line loadability?By moving the blinder closer to the origin, the increase in loadability can be controlled. Only when the measured impedance falls between the relay's mho characteristic and the two blinders will the relay trip. Along the load line, the increase in loadability can be measured.
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Related Questions
How do electrical field lines indicate the strength of an electric field?.
Answers
Answer:
The amount of lines that are perpendicualr to the area and are closer together.
Explanation:
Imagine a ripple of water. closer to the source of ripple the rings are closer together. The further away from the ripple the rings spread out and there is more time inbetween each ripple. Same wit an electric field. The more lines closer together means the stronger the field. The furth the lines are form each other mean a less strong field.
Which electrode uses a whip technique and why
Answers
Answer:
STICK SKILL DRILL...
Explanation:
The skill drill uses a Whip and Pause technique.The reason for whip and pause is that 6010 electrodes are fast freezing electrodes and the momentary whips allow the puddle to solidify a bit ..Length of Art..Too long an arc causes problems so try to keep the arc equal to or shorter than diameter of electrode.
Java problem -Instructions: Create a public doubleValue() method in the Rational class. Include a structured comment block to document the method’s API. Once you added the method all the test below in the main function should print "passed" and not "failed". Do not change the main method.format of the method:>public abstract double doubleValue()Returns the value of the specified number as a double. This may involve rounding.Returns:the numeric value represented by this object after conversion to type double.>------------------------------------------import java.util.Objects;public class Rational {float p1;float p2;public Rational(float p1, float p2) {this.p1 = p1;this.p2 = p2;}public float getP1() {return p1;}public float getP2() {return p2;}public boolean equals(Object o) {if (this == o) return true;if (o == null || getClass() != o.getClass()) return false;Rational rational = (Rational) o;return Float.compare(rational.p1, p1) == 0 && Float.compare(rational.p2, p2) == 0;}public int hashCode() {return Objects.hash(p1, p2);}public static void main(String[] args) {Rational rational12 = new Rational(1, 2);Rational rational23 = new Rational(2, 3);System.out.println("Test rational12 equals another Rational(1,2): " +(rational12.equals(new Rational(1, 2)) ? "passed" : "failed"));System.out.println("Test rational12 not equals rational23: " +(! rational12.equals(rational23) ? "passed" : "failed"));System.out.println("Test rational12 < rational23 as doubles: " +(rational12.doubleValue() < rational23.doubleValue() ?"passed" : "failed"));}}
Answers
An intent is a general statement of a task to be carried out. It can be used with context. Start Service (Intent) or context. bind Service(Intent, Service Connection, int) to interact with a background Service as well as broadcastIntent to transmit an intent to any interested Broadcast Receiver components.
A facility for late runtime binding between the code in several apps is provided by an intent. It serves as the glue connecting activities when they are launched, which is where it is most useful. Essentially, it is a passive data structure that contains an abstract description of an action that has to be taken. The following are the main details of an intent: action: The overarching activity that needs to be carried out, such as ACTION VIEW, ACTION EDIT, ACTION MAIN, etc.
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The code requires switches to be
installed at
entrance to a room.
A. every
B. every other
C.Only one
Answers
The code requires switches to be installed at every entrance to a room.
What is every?In English language, every can be defined as a determiner and it is typically used before a singular noun while referring to each of the members of a set without exception.
In this context, every is the most appropriate word to use in filling the blank because entrance is a singular noun while the room is a set.
Therefore, the code requires switches to be installed at every entrance to a room.
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Refrigerant 134a vapor in a piston-cylinder assembly undergoes a process at constant pressure from an initial state at 8 bar and 50°C to a final state at which the refrigerant is saturated vapor. For the refrigerant, determine the work and heat transfer, per unit mass, each in kJ/kg. Any changes in kinetic and potential energy are negligible.
Answers
Answer:
- Work done is 2.39 kJ
- heat transfer is 20.23 kJ/kg
Explanation:
Given the data in the question;
First we obtain for specific volumes and specific enthalpy from "Table Properties Refrigerant 134a;
Specific Volume v₁ = 0.02547 m³/kg
Specific enthalpy u₁ = 243.78 kJ/kg
Specific Volume V₂ = 0.02846 m³/kg
Specific enthalpy u₂ = 261.62 kJ/kg
p = 8 bar = 800 kPa
Any changes in kinetic and potential energy are negligible.
So we determine the work done by using the equation at constant pressure
]Work done W = p( v₂ - v₁ )
we substitute
W = 800 kPa( 0.02846 m³/kg - 0.02547 m³/kg )
W = 800 kPa( 0.00299 m³/kg )
W = 2.39 kJ
Therefore, Work done is 2.39 kJ
Heat transfer;
using equation at constant pressure
Heat transfer Q = W + ( u₂ - u₁ )
so we substitute
Q = 2.392 kJ + ( 261.62 kJ/kg - 243.78 kJ/kg )
Q = 2.392 kJ + 17.84 kJ/kg )
Q = 20.23 kJ/kg
Therefore, heat transfer is 20.23 kJ/kg
What does it mean when it says technology is A dynamic process
Answers
Answer:
It studies the process of technological change. Under the field of Technology Dynamics the process of technological change is explained by taking into account influences from "internal factors" as well as from "external factors
Explanation:
Multiple Choice question. Selected the correct answer.
10. Which of the following is NOT a metal used for producing exhaust manifolds?
A. Cast iron.
B. Aluminium.
C. Heavy-gauge sheet metal.
D. Stainless steel.
Answers
Answer:
C. Heavy-gauge sheet metal.
Explanation:
Exhaust manifolds are typically made from cast iron, aluminum, or stainless steel, which are strong and durable materials that can withstand the high temperatures and pressures found in vehicle exhaust systems.
Heavy-gauge sheet metal is a type of metal, but it is not typically used for this application because it may not have the necessary strength and durability.
A 4 stroke over-square single cylinder engine with an over square ratio of 1.1,the displacement volume of the engine is 245cc .The clearance volume is 27.2cc the bore of this engine is ?
Answers
Answer:
10.007
Explanation:
Assuming we have to find out the compression ratio of the engine
Given information
Cubic capacity of the engine, V = 245 cc
Clearance volume, V_c = 27.2 cc
over square-ratio = 1.1
thus,
D/L = 1.1
where,
D is the bore
L is the stroke
Now,
Volume of the engine V =\(\frac{\pi}{4} D^2L\)
plugging values we get
245 = \(\frac{\pi}{4} D^3/1.1\)
Solving we get D =7 cm
therefore, L= 7/1.1 =6.36 cm
Now,
the compression ratio is given as:
r =(V+V_c)/V_c
on substituting the values, we get
r = (245+27.2)/27.2 =10.007
Hence, Compression ratio = 10.007
A quiz contains 10 questions. There are four possible answers for each question.In how many ways can a student answer the questions on the test if the student can leave answers blank?
Answers
Answer:
Simple In one way. That is if he left it blank
a coil of 400 turns is wound uniformely on ring of non magnetic material. the ring has a mean circumference of 50cm and uniformly cross-sectional area of 2.5 cm. if the current in the coil is 5A, determine the magnetic field strength.
Answers
To determine the magnetic field strength, we need to use the formula B = μ₀ * n * I, where B is the magnetic field strength, μ₀ is the permeability of free space (4π × 10⁻⁷ T m/A), n is the number of turns per unit length, and I is the current in the coil.
First, let's find the number of turns per unit length. Since the coil has 400 turns and is wound uniformly on the ring, the number of turns per unit length is simply 400/50 = 8 turns/cm.
Next, we can find the cross-sectional area of the coil by multiplying the mean circumference by the cross-sectional area of the ring. Thus, the cross-sectional area of the coil is 50 cm * 2.5 cm = 125 cm².
Now we can plug in the values into the formula to get:
B = μ₀ * n * I
B = 4π × 10⁻⁷ T m/A * 8 turns/cm * 5A
B = 1.0 × 10⁻⁴ T
Therefore, the magnetic field strength is 100 µT (microtesla), which is the same as 0.1 mT (millitesla) or 1 gauss (G). The answer is 100, but the unit should be specified.
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Which is a common refrigerant for domestic air conditioners?
Answers
Answer:
Explanation:
The most common HFC used in air conditioners is R-410A. This refrigerant is better than R-22 in terms of “Ozone Depletion” potential and energy efficiency, but it still causes global warming. A few more HFCs that are commonly used are: R-32 in Air Conditioners and R-134A in refrigerators.
Answer:
The most common refrigerants used for air conditioning over the years include
Explanation:
The most common refrigerants used for air conditioning over the years include.
A_____AH mean that the energy i____from a reaction taken deleted aborbed poitive negative
Answers
The increase in energy from a reaction that was taken, deleted, aborted, positive, or negative is indicated by the change in enthalpy.
The quantitative characteristic that is transferred to a body or to a physical system in physics is energy, which is visible in the performance of labor as well as in the form of heat and light. Energy is a resource that is conserved; it can only be changed from one form to another and cannot be created or destroyed, according to the law of conservation of energy. The unit of measurement for energy in the International System of Units is the joule. Common types of energy include the kinetic energy of an object in motion, the potential energy held by an object, the elastic energy held in a solid object, the chemical energy related to chemical reactions, the radiant energy carried by electromagnetic radiation, and the internal energy held within a thermodynamic system.
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64º26’18’’ + 195º57’12,75’’ – 100º55’35’’
Answers
Answer:
I can help you with your calculation.
To add and subtract angles in degrees, minutes, seconds (DMS) form, you need to follow these steps12:
Align the angles so that the degrees, minutes, and seconds are in the same column.
Add or subtract the seconds first. If the result is more than 60 or less than 0, adjust the minutes accordingly.
Add or subtract the minutes next. If the result is more than 60 or less than 0, adjust the degrees accordingly.
Add or subtract the degrees last.
Using this method, your calculation can be done as follows:
64º26’18’’ + 195º57’12,75’’ – 100º55’35’’ = 64º26’18’’ + 195º57’12.75’’ – 100º55’35’’ = 159º83’30.75’’ – 100º55’35’’ = 159º83’(30.75 - 35)’’ – 100º55’0’’ = 159º82’55.75’’ – 100º55’0’’ = 159º(82 - 55)’55.75’’ – 100º0’0’’ = 159º27’55.75’’ – 100º0’0’’ = (159 - 100)º27’55.75’’ = 59º27’55.75’’
Therefore, the answer is 59º27’55.75’’. I hope this helps!
Explanation:
A nutrunner on the engine assembly line has been faululing for low torque. (A nutrunner is an automated machine that automatically torques bolts to a specified condition.) When the fault odcurs, the line stops until someone can investigate or correct the issue. This has been a problem for the past two weeks, and all employees on the assembly line are having to work overtime each day to make up for the lost time from the nutrunner issues. Please explain and visualize the process you would take to solve or improve this problem.
Answers
A nutrunner on the engine assembly line has been failing for low torque. process includes identifying the root cause of the fault, and optimizing the nut runner's performance.
The first step would be to investigate the cause of the low torque issue in the nut runner. This may involve examining the machine, reviewing maintenance records, and gathering data on when and how the fault occurs. Once the root cause is identified, corrective actions can be taken. This may include repairing or replacing faulty components, recalibrating the nut runner, or updating software/firmware.
To prevent future occurrences, implementing a preventive maintenance program is crucial. Regular inspections, scheduled maintenance tasks, and performance testing can help identify and address potential issues before they lead to line stoppages. Additionally, providing thorough training to operators and maintenance staff on nutrunner operation, maintenance procedures, and troubleshooting techniques can contribute to quicker resolution of faults and reduce downtime.
Continuous monitoring of the nutrunner's performance is essential to ensure it operates within specified tolerances. This can be done through real-time data collection and analysis, including torque measurement and trend analysis. By closely monitoring the nutrunner's performance, any deviations or anomalies can be detected early, allowing for proactive interventions.
Overall, a systematic approach that combines investigation, preventive maintenance, employee training, and continuous monitoring can help solve the problem of the faulty nutrunner and improve the efficiency and productivity of the assembly line.
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while viewing a site plan, you notice that the contour lines have elevation numbers that increase toward the middle. this would indicate a
Answers
while viewing a site plan, you notice that the contour lines have elevation numbers that increase toward the middle. this would indicate a hill
On your map, contour lines indicate the height above sea level at various locations. On a map, the relief depicts the elevational difference between two places. You may calculate the relief or elevation change between two points by removing the elevation differences between them.
On a topographic map, a contour line is a line drawn to denote a dip or elevation of the ground. The vertical separation or elevation difference between contour lines is known as a contour interval. Every fifth contour line has an index contour, which is a bolder or thicker line.
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Determine the critical load if the bottom is fixed and the top is pinned. ewew = 1. 6 ×(10)3ksi×(10)3ksi ,σyσy = 5 ksiksi
Answers
Critical load Fcr or buckling load is the value of load that causes the phenomenon of change from stable to unstable equilibrium state.
With that beign said, first it is neessary to calculate the moment of inercia about the x-axis:
\(Ix= \frac{db^3}{12}\\ Ix = \frac{2.(4)^3}{12} = 10.667in\)
Then it is necessary to calculate the moment of inercia about the y-axis:
\(Iy = \frac{db^3}{12}\\ Iy = \frac{4.(2)^3}{12} = 2.662in\)
Comparing both moments of inercia it is possible to assume that the minimun moment of inercia is the y-axis, so the minimun moment of inercia is 2662in.
And so, it is possible to calculate the critical load:
\(Pc\gamma = \frac{2046\pi ^2E.I}{L^2} \\Pc\gamma= \frac{2046.\pi ^2.(1,6.10^3.10^3).2662}{(10.12)^2} \\Pc\gamma= 5983,9db\)
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Given a hash table size of 100, a key in the range 0 to 9999, and using the binning hash function, what slot in the table will 7668 hash to?
Answers
The binning hash function maps a key to a slot by dividing the key by the hash table size and taking the remainder. In this case, the hash table size is 100, so we need to compute:
7668 % 100 = 68
The binning hash function divides the range of keys into several "bins" or "slots" and maps each key to the corresponding slot. In this case, the range of keys is 0 to 9999 and the hash table size is 100, which means there are 100 slots in the hash table.
To determine which slot a key hashes to using binning, we first divide the range of keys into 100 bins of size 100 each. The first bin corresponds to keys 0-99, the second bin corresponds to keys 100-199, and so on. The last bin corresponds to keys 9900-9999.
To hash the key 7668, we first determine which bin it falls into. Since 7668 is between 7600 and 7699, it falls into the 76th bin. Since the bins are numbered starting from 0, the 76th bin corresponds to slot number 75 in the hash table (remember that we are counting from 0). Therefore, 7668 hashes to slot number 75 in the hash table.
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When the process is in control but does not meet specification which type of error is it?
Answers
When the process is in control but does not meet specification, it is referred to as a special cause error.
What is the term for a process in control but not meeting specification?In statistical process control, a process is considered to be in control when it operates within the defined limits and shows only random variations. However, when a process is in control but does not meet the desired specifications, it indicates the presence of a special cause error.
Special cause errors are attributed to specific factors or events that cause the process to deviate from the expected outcome. These errors are typically unpredictable and require investigation and corrective action to bring the process back within the desired specifications.
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A circuit has two resistors in parallel, each resistor is 6 ohms. This circuit is connected to a single resistor of 6 ohms, to form a series-parallel circuit. What is the total resistance of the circuit?
Answers
The tatal resistance of the series-parallel circuit with two resistor connected in parallel which combination is connected in series to a single resistor is 9 ohms.
What is a resistance?
This can be defined as the opposition to current flow in a circuit.
To calculate the total resistance, first we need to find the total resistance of the parallel resistor.
For parallel,
R' = (R₁R₂)/(R₁+R₂)............Equation 1Where:
R' = Total resistance of the parallel resistor.
From the question,
Given:
R₁ = 6 ohmsR₂ = 6 ohmsSubstitute these values into equation 1
R' = (6×6)(6+6)R' = 3 ohms.Finally, we combine the effective parallel resistance in series to the single resistance to the the total resistance of the circuit.
Rt = R'+R₃.................. Equation 2Where:
Rt = Total resistance of the circuit.From the question,
R' = 3 ohmsR₃ = 6 ohmsSubstitute these values into equation 2
Rt = 3+6Rt = 9 ohms.Hence, the total resistance of the circuit is 9 ohms.
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Pls answer and I will give a like!
Answers
Answer:
a
Explanation:
live parts of electric equipment operating at 50 volts or more must be:
Answers
Live parts of electric equipment operating at 50 volts or more must be:
Guarded: Live parts must be effectively guarded to prevent accidental contact by personnel or unauthorized individuals. Guards can be physical barriers, enclosures, or insulation.
Insulated: Live parts must be insulated with suitable materials to prevent electrical shock hazards. Insulation helps to contain the electrical current within the equipment and prevents direct contact with conductive surfaces
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Discuss in detail the manners of interaction with opposite gender
Answers
Answer:
8 Tips on Better Communication with the Opposite Sex
Put emotions away. Ladies, this one is more aimed at us, for the most part. ...
Forget your pride. In discussions, especially these days, people always want to be the one that prevails. .
Put yourself in their shoes. .
Listen. ...
Respond. ...
Actually communicate. ...
Be detailed. ...
Don't communicate too much.
Explanation:
An aquifer yields the following results from pumping at 0.61m diameter well at 0.303m/s: s= 0.98 in 8 min; s= 3.87 in 24h. Determine its transmissivity.
Answers
The transmissivity of the aquifer is approximately 651.4 m2/s as per the given data.
What is transmissivity?Transmissivity is the amount of water that moves through an aquifer at a given velocity and hydraulic gradient.
To determine the transmissivity of the aquifer, we can use the Theis equation:
Q = 2πT[(s2 - s1)/ln(r2/r1)]
where:
Q = pumping rate (m3/s)
T = transmissivity (m2/s)
s2 = initial drawdown (m) after time t2 (s)
s1 = final drawdown (m) after time t1 (s)
r2 = distance from the well to the outer boundary of the aquifer (m)
r1 = distance from the well to the inner boundary of the aquifer (m)
First, we need to convert the given data to SI units:
0.61 m diameter well = 0.2935 m radius well
s1 = 0.98 in = 0.0249 m
s2 = 3.87 in = 0.0983 m
t1 = 0 s (initial drawdown)
t2 = 8 min = 480 s
r1 = 0 m (well)
r2 = unknown
So,
Pumping rate = \(\pi r^2v\) = π\((0.2935 m)^2\)(0.303 m/s) = 0.0267 m3/s
Substituting the values into the Theis equation and solving for T:
0.0267 = 2πT[(0.0983 - 0.0249)/ln(r2/0)]
r2 = 26.68 m
T = 651.4 m2/s
Therefore, the transmissivity of the aquifer is approximately 651.4 m2/s.
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True or false It is legal to pass in Florida when approaching within 100 feet of or traversing any railroad crossing grade croead
Answers
What is the output? for num in range(3): print (num + 5)
Answers
Answer: 5 6 7
Explanation:
you can run this in python and get this result
The output for the given program is: 5 6 7
What is Python Programming Language?This refers to the high-level language that was created and is used for data structures due to its OOP (object-oriented programming).
Hence, this python code asks for an array of numbers in the range of 3 and when that is found, it should make a display of the number and increment it.
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Determine whether or not it is possible to cold work steel so as to give a minimum Brinell hardness of 225 and at the same time have a ductility of at least 12%EL. Justify your decision
Answers
Answer:
First we determine the tensile strength using the equation;
Tₓ (MPa) = 3.45 × HB
{ Tₓ is tensile strength, HB is Brinell hardness = 225 }
therefore
Tₓ = 3.45 × 225
Tₓ = 775 Mpa
From Conclusions, It is stated that in order to achieve a tensile strength of 775 MPa for a steel, the percentage of the cold work should be 10
When the percentage of cold work for steel is up to 10,the ductility is 16% EL.
And 16% EL is greater than 12% EL
Therefore, it is possible to cold work steel to a given minimum Brinell hardness of 225 and at the same time a ductility of at least 12% EL
The steel shaft has a diameter of 40 mm and is fixed at its ends A and B . If it is subjected to the couple determine the maximum shear stress in regions AC and CB of the shaft. G st = 75 GPa.
Q6/
Answers
Answer:
See explanation.
Explanation:
Since no figure was given I solved a problem that was similar to the one you described that I worked in my mechanics of materials class. The method should be very similar for your figure. See attached image for my work.
If it is subjected to the couple determine the maximum shear stress in regions AC and CB of the shaft. G st = 75 GPa. Than the answer will be 52Mpa.
What we need to perform?We need to perform a two step process to obtain the maximum shear stress on the shaft. For the solid shaft,
P=2×pi×N×T/60 or T=60×p/2×pi×N
Where P=power transmitted by the shaft=50×10³W
N=rotation speed of the shaft in rpm=730rpm
Pi=3.142
T is the twisting moment
By substituting the values for pi, N and P, we get
T=654Nm or 654×10³Nmm
Also, T=pi×rho×d³/16 or rho=16×T/pi×d³
Where rho=maximum shear stress
T = twisting moment=654×10³Nmm
d= diameter of shaft= 40mm
By substituting T, pi and d
Rho=52Mpa
b. For a hollow shaft, the value for rho is unknown
T=pi×rho(do⁴-di⁴/do)/16
Rho=T×16×do/pi×(do⁴-di⁴)
Where
T= twisting moment=654×10³Nmm gotten above
do=outside shaft diawter=40mm
di= inside shaft diameter =30mm
Pi=3.142
Substituting values for pi, do, di and T.
Rho=76Mpa
Therefore, If it is subjected to the couple determine the maximum shear stress in regions AC and CB of the shaft. G st = 75 GPa. Than the answer will be 52Mpa.
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How much work, in Newtons, is required to lift a 20.4-kg (45lb) plate from the ground to a stand that is 1.50 meters up?
ASAP PLS
Answers
Answer:
Explanation:
Work, U, is equal to the force times the distance:
U = F · r
Force needed to lift the weight, is equal to the weight: F = W = m · g
so:
U = m · g · r
= 20.4kg · 9.81 \(\frac{N}{kg}\) · 1.50m
= 35.316 \(\frac{N}{m}\)
= 35.316 W
Please fix I keep getting this when I run it in the cygwin terminal
/usr/lib/gcc/x86_64-pc-cygwin/7.4.0/../../../../x86_64-pc-cygwin/bin/ld: /usr/lib/gcc/x86_64-pc-cygwin/7.4.0/../../../../lib/libcygwin.a(libcmain.o): in function `main':
/usr/src/debug/cygwin-3.1.7-1/winsup/cygwin/lib/libcmain.c:37: undefined reference to `WinMain'
/usr/src/debug/cygwin-3.1.7-1/winsup/cygwin/lib/libcmain.c:37:(.text.startup+0x82): relocation truncated to fit: R_X86_64_PC32 against undefined symbol `WinMain'
collect2: error: ld returned 1 exit status
#include
#include "work4_support.h"
extern unsigned int result;
extern unsigned int first;
extern unsigned int second;
void printBinary(unsigned int x)
{
char i;
char index;
int mask;
if(x >= SIXTEENBITMAX)
{
mask = TWENTYFOURBITMASK;
index = BITSLARGE;
}
else if(x >= MAXSMALL);
{
}
void russMult(unsigned int x, unsigned int y)
{
}
char promptUser()
{
}
void banner(void)
{
printf("Banner\n");
}
}
Answers
The error message "undefined reference to `WinMain'" occurs because the linker, ld.exe, expects to find a WinMain function and can’t find it. Therefore, the application terminates with an error. When creating a graphical application using the Win32 API in Visual C++, you must define a WinMain function as the main entry point.
Fixing the error "undefined reference to `WinMain'"The issue arises because the WinMain function is defined in the Windows API library, which is not included by default in Cygwin.The problem can be resolved by adding -mwindows to the command line when linking the application.
Here is the revised code snippet to solve the issue:```#include #include "work4_support.h"extern unsigned int result;extern unsigned int first;extern unsigned int second;void printBinary(unsigned int x) {char i;char index;int mask;if (x >= SIXTEENBITMAX) {mask = TWENTYFOURBITMASK;index = BITSLARGE;} else if (x >= MAXSMALL);{}void russMult(unsigned int x, unsigned int y) {}char promptUser() {}void banner(void) {printf("Banner\n");}int WINAPI WinMain(HINSTANCE hInstance, HINSTANCE hPrevInstance, LPSTR lpCmdLine, int nShowCmd){MessageBox(NULL,"Hello world!", "My program", NULL);return 0;}```
The error message "undefined reference to `WinMain'" is a common problem when building an executable with Cygwin. The problem is solved by adding the -mwindows option when linking the executable.
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Torque is expressed in pounds per foot (lbs.-ft).
Group of answer choices
True
False