The local garden store sells bags of mulch for $4.98 each and will deliver the bags for a fee of $15 if Amber purchases 15 bags and has them delivered what is the total amount that Amber will pay?

If the price of 1 cubic foot of hay is $10 then the money needed is $15.

Given the price of 1 cubic foot of hay be $10 and the amount of hay be $1.50.

We are required to find the amount of money needed to buy the hay.

We know that the amount of money that can be spend on something is the product of price of one unit and number of units.

Product is the result when two numbers are multiplied with each other.

Total money =Price of 1 cubic foot*$1.50

=10*1.50

=$15

Hence if the price of 1 cubic foot of hay is $10 then the money needed is $15.

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Question is incomplete, the right question is as under:

1.5 cubic foot hay is required to fill a room completely. Calculate the amount we have to pay to fill the room completely if the price of 1 cubic foot is $10?

Answer:

the probability that the two committees have at least one member in common is approximately 0.3622.

Step-by-step explanation:

To find the probability that two committees have at least one member in common, we can use the complement rule, which states that the probability of an event happening is 1 minus the probability of the event not happening.

Let A be the event that the two committees have no members in common. To calculate the probability of A, we can first find the number of ways to choose three people out of 20 without any overlap, and then use this to find the total number of ways to choose two committees of three people each without any overlap:

Number of ways to choose 3 people out of 20 without overlap:

C(20,3) = (201918)/(321) = 1140

Number of ways to choose 3 people out of 20 with overlap:

C(20,3) - C(2,1)C(17,2) = 1140 - 2(2*136) = 680

The first term is the total number of ways to choose 3 people out of 20, and the second term is the number of ways to choose 3 people out of 20 such that one particular person is included. We multiply by 2 because there are two committees.

The total number of ways to choose two committees of three people each without any overlap is:

C(20,3) * C(17,3) = (1140*680) = 775200

Therefore, the probability that the two committees have no members in common is:

P(A) = 775200 / (C(20,3)*C(17,3)) = 0.6378

So the probability that the two committees have at least one member in common is:

P(at least one member in common) = 1 - P(A) = 1 - 0.6378 = 0.3622

Therefore, the probability that the two committees have at least one member in common is approximately 0.3622.

Step-by-step explanation:

the domain of the function = (-oo , oo)

There is not enough evidence to conclude that the mean time in changing a muffler is less than 13 minutes.

To determine whether there is enough evidence to conclude that the mean time in changing a muffler is less than 13 minutes, we can conduct a one-sample t-test with the following hypotheses:

Null hypothesis: The true mean time in changing a muffler is equal to 13 minutes.

Alternative hypothesis: The true mean time in changing a muffler is less than 13 minutes.

Use the formula to calculate the test statistic,

\(t = \dfrac{(x - \mu)} { \dfrac{s} { \sqrt{n}}}\)

where x is the sample mean, μ is the hypothesized population mean (13 minutes), s is the sample standard deviation, and n is the sample size (6).

Plugging in the numbers, we get:

t = (12.3 - 13) / (2.3 / √6) = -0.72

Using a t-distribution table with 5 degrees of freedom (n - 1), we find that the critical value for a one-tailed test with α = 0.05 is -2.571. Since our calculated t-value (-0.72) is greater than the critical value, we fail to reject the null hypothesis.

Therefore, there is not enough evidence to conclude that the mean time in changing a muffler is less than 13 minutes.

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Answer:

The answer is "\(22,246 \ H_z \ \ and \ \ 7.3\%\)"

Step-by-step explanation:

The sampling rate: \((f_s) = 52,500 \ \frac{samples}{sec}\)

In point a:

The sample signal frequency = f  

They recognize that the id \(\geq\) 2f sampling frequency could be returned to its original signal unless the aliase effect is detected elsewhere,  Yet under percentage =18%

\(\ sampling \ rate = 2 \times 1.18 \times f\)

\(\to f = \frac{52,500}{2 \times 1.18}\\\\\)

       \(= 22,246 \ h_z\)

In point b:

Maximum 22,242 frequency is increased by \(10 \ \%\)

\(f_a =22,246 \times 1.1\)

    \(= 24,470.6\\\\=24,471\)

\(\ sampling \ rate= x \times 2 \times 24,2471 \\\)

                    \(x= \frac{52,500}{48,942} \\\\x= 1.073\\\\\)

over sampling percentage \(= 7.3 \ \%\)

Value: 4; Case: Case 4

Case 4 matches the value 4, which is the number of days in a week.

Case 4 matches the value 4, which is the number of days in a week. This means that for any given week, there are always four days. To determine which case corresponds to which value, we must first understand the context of the cases. Case 1 is the number of sides on a square, Case 2 is the number of legs on a spider, Case 3 is the number of sides on a triangle, Case 4 is the number of days in a week, and Case 5 is the number of sides on a pentagon. By understanding the context of each case, we can easily determine which case each value matches. In this example, the value 4 matches Case 4, which is the number of days in a week.

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180°

120°

90°

hope this helps

Answer:

180°

120°

90°

Step-by-step explanation:

I don't know how to explain, but were you in RSM 6th grade honors / advanced?

Given the equation:  \(\frac{5x+4}{2} = 7\)

x = 2

Explanation:

Multiply 2 on both sides of the equation to eliminate the fraction on the left-hand side:

\(2(\frac{5x+4}{2}) = 7(2)\)

2 cancels out on the left side, leaving 5x + 4, and 14 on the right-hand side of the equation:

5x + 4  = 14

Subtract 4 from both sides of the equation:  

5x + 4 - 4 = 14 - 4  

5x = 10

Divide both sides of the equation by 5 to solve for x:

\(\frac{5x}{5} = \frac{10}{5}\) 

x = 2

These are the two transactions that are given in the question and the journalizing of these transactions are explained with the appropriate steps and accounts.

The solution for the journalizing of the given transactions can be found below:

Journalizing refers to the recording of business transactions in the journal. In the process of journalizing, all transactions are recorded in the journal in a systematic way.

Journal is the first place where every transaction is recorded systematically.

The transaction is a business exchange in which one entity provides value to another entity in exchange for a specific item, service, or asset.

Transaction

(i) is paid Rs 2000 in cash as wages on the installation of the machine. This transaction can be journalized as follows: Journal of Transactions Date Particulars LF Amount (Dr.) Amount (Cr.) DD/MM/YYYCash a/c………………………Dr.2000To wages a/c2000 (Being cash paid as wages on the installation of the machine)Transaction

(ii) sold goods to Mr. Chopra at a list price of Rs 4,000. The sale is subject to a 10% trade discount and a 5% cash discount if the payment is made immediately, Mr. Chopra availed cash discount.

This transaction can be journalized as follows: Journal of Transactions Date Particulars LF Amount (Dr.) Amount(Cr.) DD/MM/YYYMr. Chopra a/c………………………Dr.3,420To Sales a/c4,000 (Being sales made to Mr. Chopra on a discount) To Trade Discount a/c400 (Being Trade Discount allowed to Mr. Chopra) Cash Discount a/c180 (Being cash discount allowed to Mr. Chopra) To Mr. Chopra a/c180 (Being cash received from Mr. Chopra) To CGST a/c90(Being CGST charged on sales) To SGST a/c90(Being SGST charged on sales)

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Answer:

Step-by-step explanation:

It’s true

Answer:

true

Step-by-step explanation:

.8 can be converted into 8/10 which can be reduced or simplified into 4/5.

I hope this helps you and you're grade!!  

Note that as x gets larger, y gets smaller, but the product xy remains constant at 192.

In mathematics, a function is a relationship between two sets, called the domain and the range, such that each element of the domain corresponds to exactly one element of the range. A function takes an input value (or values) and produces an output value (or values) according to a specific rule or formula. The input values are the domain of the function, and the output values are the range of the function. Functions can be represented using equations, graphs, tables, or verbal descriptions. They are used to model relationships between variables in various fields of mathematics, science, engineering, economics, and many other areas.

Here,

If x and y vary inversely, this means that their product is a constant. We can use this fact to find the constant of proportionality k as follows:

k = xy

If we know that y is 24 when x is 8, we can substitute these values into the equation above to solve for k:

k = xy

= 8(24)

= 192

Now we can use this value of k to write the inverse variation function:

xy = 192

or

y = 192/x

To sketch a graph of this function for x > 0, we can plot a few points and connect them with a smooth curve. Here are some points we can use:

(x, y)

(1, 192)

(2, 96)

(4, 48)

(8, 24)

(16, 12)

(24, 8)

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Answer:

37

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Trigonometry

[Right Triangles Only] Pythagorean Theorem: a² + b² = c²

Step-by-step explanation:

Step 1: Identify

Leg a = 35

Leg b = 12

Hypotenuse c

Step 2: Solve for c

Answer:

A(-3, 4) reflected across x-axis ==>  A'(-3, -4)
A'(-3, -4)  reflected across y-axis ==> A"(3, -4)

Graph attached

Step-by-step explanation:

The point is (-3, 4) shown as point A on attached graph

When reflected across the x-axis to point A' the x-coordinate does not change but the y-coordinate is the negative of the original y-coordinate

Therefore A (-3, 4)  ⇒ A' (-3, -4)

When A' is reflected across the y-axis  to A" the x-coordinates change sign but y-coordinates stay unchanged

A'(-3, -4) ⇒ A" (3, -4)

So the final point is A"(3, -4)

log₂ 24 can be expressed as 3 + log₂ 3 in terms of prime factors, using the properties of logarithms.

To express log₂ 24 in terms of prime factors, we can use the properties of logarithms and the fact that any positive integer can be expressed as a product of prime factors.

First, let's find the prime factorization of 24.

24 can be divided by 2, so we have 24 = 2 × 12.

12 can be divided by 2, so we have 12 = 2 × 6.

6 can be divided by 2, so we have 6 = 2 × 3.

Therefore, the prime factorization of 24 is 2 × 2 × 2 × 3, or 2³ × 3.

Now, using the properties of logarithms, we can express log₂ 24 as the sum of logarithms of its prime factors.

log₂ 24 = log₂ (2³ × 3)

According to the properties of logarithms, we can separate the factors inside the logarithm as individual terms:

log₂ (2³ × 3) = log₂ 2³ + log₂ 3

Since log₂ 2³ is equal to 3, we can simplify the expression further:

log₂ (2³ × 3) = 3 + log₂ 3

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So the ordered pairs given tell us how much time has passed since the beginning at each station. If we analyze this data as a sequence we have that the terms of the sequence are given by the time and their orders are given by the station number. Then the terms of the sequence are:

As you can see the difference between consecutive terms is not always the same. This means that this is not an arithmetic sequence. So this is probably a geometric sequence. The general formula for such type of sequence is:

Where the n denotes the term order, a₁ is the first term (in this case it's 4) and r is known as the common ratio. So we know that the first term is 4 so we get:

We can use the other terms of the sequence to find r:

If we divide both sides of this equation by 4 we get the value of r:

So r=2 and the general formula looks like this:

If we take n=3 and n=4 we should get 16 and 32. Let's check this:

So r is in deed equal to 2. Then the answer to part A is that this is a geometric sequence.

In part B we have to find the term for n=5. However we have to use a recursive formula and the one I just found is explicit. A recursive formula gives you the value of a term using the value of a previous term. Now let's see the differences between consecutive terms:

So we have that the difference between consecutive terms is given by:

Then the recursive formula we have to use is given by this expression:

Then the time when Aurora completes station 5 is given by:

Then the answer to part B is 64 minutes.

For part C we just need to use the explicit formula we found in part A:

We have to take n=8:

Then the answer to part C is 512 minutes.

Answer:

1 ; 1.25 ; 0.25 ; - 0.75 ; - 1.25 ;- 0.5

Step-by-step explanation:

Given the sample observations : 15, 16, 12, 8, 6, 9

Zscore for each sample Observation :

Zscore = (x - mean) / standard deviation

(15 + 16 + 12 + 8 + 6 + 9) / 6 = 11

Mean value (m) = 11

Standard deviation (s) = 5

Sqrt[(x - m)^2 / (n - 1)]

[(15-11)^2 + (16-11)^2 + (12-11)^2 + (8-11)^2 + (6-11)^2 + (9-11)^2] / (6 - 1)

= 80/5 = 16

Sqrt(16) = 4

Zscore = (x - mean) / standard deviation

x = 15

Zscore = (15 - 11) / 4 = 1

x = 16

Zscore = (16 - 11) / 4 = 1.25

x = 12

Zscore = (12 - 11) / 4 = 0.25

x = 8

Zscore = (8 - 11) / 4 = - 0.75

x = 6

Zscore = (6 - 11) / 4 = - 1.25

x = 9

Zscore = (9 - 11) / 4 = - 0.5

Answer:

B

Step-by-step explanation:

Class and cost per class should be multipled so must be A or B. The amount of money she has should be greater than or equal to her costs or she can't afford it! So B.

Answer:

b. 146 greater than or equal to 9c + 10

Step-by-step explanation:

hope this helped :)

Few families can survive on a single salary is true statement

Many families rely on dual incomes to make ends meet, especially in areas with high living costs.

However, there are still many families that rely on a single salary to support themselves.

While it may be challenging to make ends meet on a single salary, it is still possible for families to survive and even thrive in these circumstances.

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Answer:

1.029 is greater than 1.0275

Step-by-step explanation:

Answer:

1.029

Step-by-step explanation:

What is greater 1.0275 or 1.029

.027 < .029

So, 1.029 is greater.

With regards to the function model then the true statement as per first and second derivatives is: (C) dw/dt = 1/100 W  (70 - W),

When, W = 10 then dw/dt = 6

When W = 35 then d²w/d²t = 0

where the point influx occurs, the weight of the carrying capacity is half

Therefore, 35 = a/2

Then the carrying capacity (a) = 35 x 2

a = 70

A function's sensitivity to change with respect to a change in its argument is measured by the derivative of a function of a real variable. Calculus's core tool is the derivative. It is a crucial idea that is incredibly helpful in a variety of contexts: in daily life, the derivative can inform you how fast you are driving or assist you in predicting stock market changes; in machine learning, derivatives are crucial for function optimization.

Therefore, with regards to the function model then the true statement as per first and second derivatives is: (C) dw/dt = 1/100 W  (70 - W), because the carrying capacity is 70 and the rate of change of the weight is 6 grams per hour when the weight is 10 grams.

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\(p=13^2=(13)(13)=\boxed{169}\)

The percent increase of the profit is 15%

In this question, the figures are given as

Profit in March = £2750

Profit in April = £3162.50

The percentage of the increase of the profit is then calculated using the following equation

Increase percentage = (Profit in April - Profit in March)/Profit in March * 100%

Substitute the known values in the above equation, so, we have the following representation

Increase percentage = (3162.50 - 2750)/2750 * 100%

Evaluate

Increase percentage = 15%

Hence, the increase in percentage is 15%

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For the given cylinder,

The volume of cylinder is given as,

Thus the volume of cylinder is 92 cubic feet .

The shoe sizes that will only have one dot are 5 1/2, 7, 8 and 10 1/2

From the question, we have the following parameters that can be used in our computation:

The record of shoe sizes

From the data values, we have the following shoe sizes that appear once

5 1/2, 7, 8 and 10 1/2

These are the data values that will have only one dot  if the data is recorded on a line plot

Hence, the shoe sizes that will only have one dot are 5 1/2, 7, 8 and 10 1/2

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The rate of return for the entire portfolio, given the amount allocated to each of the four securities is

The rate of return would be the expected return of the proportion of the amounts invested into the various investment vehicles and their rates of return.

The rate of return for the portfolio is therefore :

= ∑ ( proportion invested x rate of return )

= ( 25 % x 12 % ) + ( 10 % x 7 % ) + ( 35 % x 22 % ) + ( 30 % x  - 12 % )

= 7. 8 %

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Answer:

0

Step-by-step explanation:

Substitute x for -3 and y for -1:

= -2(-3) + 6(-1)

= 6 + -6 (or 6 - 6)

= 0

Answer:

Question one: 2
Question two: 3

Step-by-step explanation:

Given the following questions:

\(\frac{1}{2} \times4\)
\(\frac{3}{4} \times4\)

In order to find the answers, we need to remember that every integer has an invisible denominator of one. Then we simply multiply the numerators by the numerators and the denominators by the denominators.

Question one:
\(\frac{1}{2} \times4\)
\(4=\frac{4}{1}\)
\(\frac{1}{2} \times\frac{4}{1}\)
\(1\times4=4\)
\(2\times1=2\)
\(=\frac{4}{2}\)

Simplify by reducing:
\(\frac{4}{2}\)
\(\frac{4}{2} \div2=\frac{2}{1} =2\)
\(=2\)

Question two:
\(\frac{3}{4}\times4\)
\(4=\frac{4}{1}\)
\(\frac{3}{4} \times\frac{4}{1}\)
\(3\times4=12\)
\(4\times1=4\)
\(=\frac{12}{4}\)

Simplify by reducing:
\(\frac{12}{4}\)
\(=\frac{12}{4}\div4=\frac{3}{1} =3\)

Your answers are "2 and 3."

Hope this helps.

Answer:

um i think 8 not really but its maybe 8 or 17 not really sure