The mass of solid Mg used in the lab to reduce the copper ions is in excess of the minimum required. What happens to the unused (excess) Mg (s)?

Answer:

if the negative ion ends in -ide

Explanation:

The rules for naming the ionic compounds is given as :

The negative ion (anion) is written next. The suffix is added at the end of the negative ion (anion). The suffix used is '-ide'.

Answer:

A. if the negative ion ends in -ide

Explanation:

in ionic compounds the second name in the chemical name is the negative atom, and always the second name in a chemical name has to end in -ide.

So putting those together, the negative ion (which in ionic compounds, comes SECOND) ends in -ide.

Also, I got this question correct on the edg review! :)

Thank God because he blesses us everyday!

Given what we know, we can confirm that one possible solution to the problem of flammable methane from concentrating in landfills is to use biosolids.

Biosolids are organic matter that are created by recycling waste. These biosolids can act as a cover over landfills. The bacteria present in these solids then use this methane gas to create carbon dioxide gas. Though not ideal, this product is much less harmful to the environment than methane.

Therefore, we can confirm that one possible solution to the problem of flammable methane from concentrating in landfills is to use biosolids.

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In the model of the atom, a fuzzy cloud around a hydrogen nucleus is used to represent the general region where the atom's electron is most likely located.

An atomic model is a graphic representation and/or diagram used to identify the components of atoms.

An atomic model may have into account all its components (i.e., electrons, protons, and neutrons).

In conclusion, in the model of the atom, a fuzzy cloud around a hydrogen nucleus is used to represent the general region where the atom's electron is most likely located.

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Answer:

In general, the word energy refers to a concept that can be paraphrased as "the potential for causing changes", and therefore one can say that energy is the cause of any change. The most common definition of energy is the work that a certain force (gravitational, electromagnetic, etc) can do. Due to a variety of forces, energy has many different forms (gravitational, electric, heat, etc.) that can be grouped into two major categories: kinetic energy and potential energy. According to this definition, energy has the same units as work; a force applied through a distance. The SI unit of energy, the joule, equals one newton applied through one meter, for example. Energy has no direction in space, and is therefore considered a scalar quantity. Energy is a conserved quantity, meaning that it cannot be created or destroyed, but only converted from one form into another. Thus, the total energy of the universe always remains constant. One form of energy can be readily transformed into another; for instance, a battery converts chemical energy into electrical energy.

Explanation:

Answer:

Mass of MgF₂ formed = 40.5 g

Explanation:

Given data:

Mass of NaF = 55 g

Mass of MgF₂ formed =  ?

Solution:

Chemical equation:

2NaF  +  Mg      →     MgF₂ + 2Na

Number of moles of NaF:

Number of moles = mass/molar mass

Number of moles = 55 g / 41.98 g/mol

Number of moles = 1.3 mol

now we will compare the moles of sodium fluoride with magnesium fluoride.

                     NaF       :          MgF₂

                       2          :             1

                     1.3          :        1/2×1.3 =  0.65 mol

Mass of magnesium fluoride:

Mass = number of moles × molar mass

Mass = 0.65 mol × 62.3 g/mol

Mass = 40.5 g

Answer:

yes

Explanation:

the energy released in the synthesis of water is equal to the energy absorbed in the decomposition of water. This outcome happens because the difference in energy between the reactants and the products in both cases is equal. . It follows the law of conservation of energy.

The balanced equation would be \(16Cr(s) + 3S_8(s) --- > 8Cr_2S_3 (s)\).

A balanced chemical equation will have as many atoms of different elements in the products as in the reactants. In other words, a balanced chemical equation will obey the law of conservation of atoms.

According to the law of conservation of atoms, atoms can neither be created nor destroyed but can be converted from one form to another during the course of chemical reactions.

Following this law, the balanced equation for the reaction would be \(16Cr(s) + 3S_8(s) --- > 8Cr_2S_3 (s)\)

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Answer:

Bromine gas is heavier than air due to its atomic weight. Being heavier it still floats in the air due to diffusion and collision between the particles of bromine and air molecules. The particles collide with each other, so the two different gases can mix completely with each other.

Explanation:

Answer:

Except for humans, plants and animals get all the energy they require from natural sources: from the food that they eat, or from sunshine through photosynthesis. Some organisms derive the energy they need through oxidation of inorganic compounds.

By mass, the mass of the sucrose solution containing 19 g of sucrose at a concentration of 3.3%  is 575.8 g.

To determine the mass of a sucrose solution containing 19 g of sucrose at a concentration of 3.3% by mass, we can use the following formula:

Mass of solution = Mass of solute / Percent concentration

Substituting the values given:

Mass of solution = 19 g / 0.033

Mass of solution = 575.8 g

Therefore, the mass of the sucrose solution containing 19 g of sucrose at a concentration of 3.3% by mass is 575.8 g.

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The density of the salt is 2915 kg/dm³.

To determine the density of the salt, we need to calculate the volume of the salt and then divide the mass of the salt by this volume. The volume of the salt can be found by subtracting the initial volume of oil in the graduated cylinder from the final volume after the salt was added. In this case, the initial volume was 4.02 mL and the final volume was 4.22 mL, so the volume of the salt is 0.20 mL.

To convert this volume to dm³, we multiply by the conversion factor 10^-3, resulting in 0.20 x 10^-3 dm³. Finally, we divide the mass of the salt (0.583 g) by the volume (0.20 x 10^-3 dm³) to find the density, which is 2915 kg/dm³.

Therefore, the density of the salt is determined to be 2915 kg/dm³.

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Answer:

should be half wich is 750

Explanation:

Answer:

0.502mol

Explanation:

The balanced chemical equation of the reaction described in this question is as follows:

2KClO3 → 2KCl+ 3O2

According to the equation above, 2 moles of KClO3 will produce 2 moles of KCl.

Using mole = mass/molar mass to convert mass of KClO3 to moles

Molar mass of KClO3 = 39 + 35.5 + 16(3)

= 39 + 35.5 + 48

= 122.5g/mol

mole = 61.5 g ÷ 122.5g/mol

mole = 0.502mol

Since 2 moles of KClO3 will decompose to produce 2 moles of KCl.

0.502 mol of KClO3 will decompose to produce 0.502 × 2/2

= 0.502mol of KCl.

the answers is cacih2

wjdgagqjdhdgahahdhvddvvsvshsd

Carbon NMR:Spectrum: The chemical shift of the aromatic carbons (Ph–) appears between 128 ppm and 131 ppm. The presence of the double bond (–CH=) appears in the range of 137 ppm to 142 ppm. The benzyl carbon (PhCH2–) appears between 46 ppm and 47 ppm.

The reaction of 1-phenylethylamine with Biphenyl-4-carboxaldehyde produces N-(4-phenylbenzylidene)-1-phenylethylamine. The NMR (Nuclear Magnetic Resonance) spectroscopy is a powerful tool for determining the chemical structure of organic compounds. It is used to analyze the proton and carbon environments of the compound.Here's a detailed analysis of the NMR of N-(4-phenyl benzylidene)-1-phenylethanolamine: Proton NMR:Spectrum:In the proton NMR, the presence of the hydrogen of the amine group (–NH) appears between 4.8 ppm and 5.1 ppm. The hydrogen atoms on the double bond (–CH=) appear between 7.3 ppm and 7.4 ppm. The presence of aromatic protons (Ph–) appears in the range of 7.0 ppm to 7.2 ppm and the presence of benzyl proton (PhCH2–) appears at 4.7 ppm. Carbon NMR:Spectrum:The chemical shift of the aromatic carbons (Ph–) appears between 128 ppm and 131 ppm. The presence of the double bond (–CH=) appears in the range of 137 ppm to 142 ppm. The benzyl carbon (PhCH2–) appears between 46 ppm and 47 ppm.

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Decane react with 31/2 O₂  to yield 10CO₂ and 11H₂O.

Reaction is given below:-

C₁₀H₂₂ + 31/2 O₂ → 10CO₂ + 11H₂O

Hence, Decane react with 31/2 O₂  to yield 10CO₂ and 11H₂O.

Molecular oxygen, O₂ is a diatomic molecule that is composed of two oxygen atoms held together by a covalent bond. Molecular oxygen is essential for life, as it is used for respiration by many organisms.

Diatomic means that an atom cannot exist by itself. There is no such thing as lone O atoms floating around the atmosphere. Oxygen exists as O₂ .

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[Os(CN)6]^3- is expected to have the largest CFS delta.

Crystal field splitting (CFS) is a phenomenon that occurs when transition metal ions are surrounded by ligands, resulting in the splitting of the degenerate d-orbitals into higher and lower energy levels. The size of the splitting is measured by delta (Δ), which is influenced by the electronic configuration and the identity of the ligands. The ligands' ability to cause a larger splitting is known as the spectrochemical series. The stronger the field of the ligand, the higher the CFS. Among the given ions, [Os(CN)6]^3- is expected to have the largest crystal field splitting delta. This is because cyanide (CN-) is a strong field ligand, and Os has a 5d^2 electronic configuration. The Os atom has seven d-electrons, and it has a formal charge of +3, making it more polarizable than the other Os ions. As a result, the electrons are pulled closer to the ligands, causing a greater splitting between the d-orbitals. Thus, [Os(CN)6]^3- is expected to have the largest CFS delta.

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The names and number of methyl groups for 3,3-dimethylcyclopentene, 2,2-dimethylcyclopentene, 5,5-dimethylcyclopentene, and 1,1-dimethylcyclopentene are as follows: 2,2-dimethylcyclopentene, 5,5-dimethylcyclopentene, and 1,1-dimethylcyclopentene.

The names and number of methyl groups for the compounds 3,3-dimethylcyclopentene, 2,2-dimethylcyclopentene, 5,5-dimethylcyclopentene, and 1,1-dimethylcyclopentene are as follows: 3,3-dimethylcyclopentene: two methyl groups are located at the third position on the cyclopentene ring; 2,2-dimethylcyclopentene: two methyl groups are located at the second position on the cyclopentene ring; 5,5-dimethylcyclopentene: two methyl groups are located at the fifth position on the cyclopentene ring; and 1,1-dimethylcyclopentene: two methyl groups are located at the first position on the cyclopentene ring.

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The mean wake time of 104.0 min before treatment is outside the 99% confidence interval of the mean wake time after treatment, it suggests that the drug is effective. This is further confirmed by the significant decrease in the mean wake time after treatment of 94.1 min. Therefore, it can be concluded that the drug is effective in treating insomnia in older subjects.

A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older subjects. Before treatment, 16 subjects had a mean wake time of 104.0 min.

After treatment, the 16 subjects had a mean wake time of 94.1 min and a standard deviation of 23.7 min.

Assume that the 16 sample values appear to be from a normally distributed population and construct a 99% confidence interval estimate of the mean wake time for a population with drug treatments.

The formula for the confidence interval of the mean is:

\($$\overline{X} \pm z_{\alpha/2} \frac{s}{\sqrt{n}}$$\)

Here,

\($z_{0.005} = 2.576$\) for a 99% confidence interval as

\($α/2 = 0.005$\)

and the degrees of freedom is 15 since \($n-1=15$\).

Now, substituting all the values:

\($$94.1 \pm 2.576 \times \frac{23.7}{\sqrt{16}}$$\)

The calculation gives a 99% confidence interval estimate of the mean wake time of 94.1 ± 15.4 min (rounded off to one decimal place).

The mean wake time of 104.0 min before treatment is not within the 99% confidence interval of the mean wake time after treatment. This indicates that there is a significant decrease in the mean wake time after treatment.

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Answer: A. wool

Explanation:

Your Welcome;)

Wool is the natural polymer which he most likely uses in making carpets and the polymer is prepared by polymerization reactions.

Polymerization reactions are  reactions in which large number of monomer molecules react to form polymer .The large molecules which are produced from polymerization may have linear or branched structure.

They can also form a complex three dimensional structure . There are different polymerization reactions like step-growth polymerization, chain -growth polymerization and condensation polymerization.

Polymers containing same kind of monomer are homopolymer and which contain different monomers are heteropolymers. Mechanisms which describe formation of polymers are of different types such as free radical mechanism and chain growth mechanisms.

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Answer:

96g

Explanation:

so, molar mass of C =12g/mol

C=8 moles

8x12

= 96

The consumption function based on the information in Table 5 is as follows: C = 2577 + 0.75Y. It is given, Consumption function, C = Ca + cY Where, Ca is autonomous consumption expenditure, c is marginal propensity to consume (MPC)Y is disposable income

The consumption function based on the information in Table 5 is: Table 5Income(¥ billions)

Consumption(¥ billions)100025020007526000102772750120301.

Write the consumption function in the given format. Ca = Autonomous consumption expenditure c = MPCY = Disposable Income Calculation:

We can obtain the value of Ca as follows: C = Ca + cY

Put the given values, C = 2577Ca + 0.75YAt Y = 1000 billion, C = 2577(1) + 0.75(1000)

= 8327 billion

At Y = 2000 billion, C = 2577(1) + 0.75(2000)

= 13277 billion

At Y = 3000 billion, C = 2577(1) + 0.75(3000)

= 18277 billion

At Y = 4000 billion, C = 2577(1) + 0.75(4000)

= 23277 billion

At Y = 5000 billion, C = 2577(1) + 0.75(5000)

= 28277 billion

Therefore, the consumption function based on the information in Table 5 is as follows: C = 2577 + 0.75Y.

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The density of the block in g/cm3 would be 7.11 g/cm3. and the metal's identity would be zinc.

Density = mass/volume

Mass of the metal = 1.80 x \(10^4\) mg = 1.80 x \(10^4\) mg/1000 = 18 g

Dimension of the metal = 0.5839 inches by 0.531 inches by 0.4981 inches

0.5839 inches = 0.5839 x 2.54 = 1.4831 cm

0.531 inches = 0.531 x 2.54 = 1.3487 cm

0.4981 inches = 0.4981 x 2.54 = 1.2652 cm

Volume of the metal =  1.4831x1.3487x1.2652 = 2.5307 cm3

Density of the metal = 18/2.5307 = 7.11 g/cm3

In other words, the density of the metal is 7.11 g/cm3. The metal is likely to be Zinc.

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Answer:

Explanation:

The number of atoms of potassium can be found by using the formula

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 1.65 × 6.02 × 10²³

We have the final answer as

Hope this helps you

Answer:

12d

Explanation:

Answer:

save it for future references

Explanation:

Answer:

some clothes or maybe even some makeup

The internal energy change and temperature change for the two processes involving 1 mole of an ideal monatomic gas for (a) ΔU = 3200 J, ΔT = 256.7 K and for (b) ΔU = -3200 J, ΔT = -256.7 K.

The internal energy change and temperature change for the two processes involving 1 mole of an ideal monatomic gas  can be computed using the following formula:

ΔU = Q - W

Where ΔU is the internal energy change, Q is the heat added or taken away from the gas, and W is the work done by or on the gas.

For process (a), 3200 J of heat are added to the gas and the gas does no work and no work is done on the gas. Therefore, the internal energy change is:

ΔU = Q - W = 3200 J - 0 = 3200 J

The temperature change can be computed using the following formula:

ΔT = ΔU / (n * Cv)

Where ΔT is the temperature change, ΔU is the internal energy change, n is the number of moles of gas, and Cv is the molar heat capacity at constant volume.

For an ideal monatomic gas, Cv = 3/2 R, where R is the gas constant. Therefore, the temperature change is:

ΔT = 3200 J / (1 mol * 3/2 * 8.314 J/mol*K) = 256.7 K

For process (b), 3200 J of work are done on the gas and the gas does no work and no heat is added or taken away from the gas. Therefore, the internal energy change is:

ΔU = Q - W = 0 - 3200 J = -3200 J

The temperature change can be computed using the same formula as above:

ΔT = -3200 J / (1 mol * 3/2 * 8.314 J/mol*K) = -256.7 K

Therefore, the internal energy change and temperature change for the two processes are:

(a) ΔU = 3200 J, ΔT = 256.7 K
(b) ΔU = -3200 J, ΔT = -256.7 K

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