The mean time between collisions for electrons in a gold wire is 25 fs, where 1 fs 1 femtosecond 10-^15. what is the electron drift speed in a 60 mv/m electric field?

magnetic field caused by the combination of wires to cancel out, the current will flow in a direction . The current will therefore move in the other direction,. The outside wire is experiencing a 15.83 A current.

The electric current formula, I=V/R, can be used to determine how much current is flowing. The "current equation," as it is commonly known, is derived from Ohm's Law. The variable "I" denotes current, "V" denotes voltage, and "R" denotes resistance.

Electron movement is referred to as electron current. The positive terminal receives electrons that are released by the negative terminal. Traditional current, usually referred to as just current, exhibits behavior consistent with positive charge carriers being the source of current flow. A positive terminal receives normal current, which then travels to a negative terminal.

To know more about current visit:

https://brainly.com/question/3110787

#SPJ4

Here are the positive instructions corresponding to the given negative instructions:

1. Please refrain from jumping on the sofa.

2. I would like you to walk instead of running now.

3. Could you please pick up your toys?

4. Please avoid pushing him off the slides.

5. Could you go to your room and clean up the mess?

6. Please keep your legs off the table.

7. Let's stop throwing the crayons.

8. I would prefer if you didn't sit near the door.

9. Let's lower our voices and avoid shouting.

10. Please wait for your turn to speak and avoid interrupting me.

Decrease

The mathematical relationship between heat, internal energy and work done by the system is given as:

△U = Q + W

where △U is the change in the internal energy

W is the workdone by the system

Q is the heat energy in the system

Since the workdone by the system is negative, when a system does work, there is a depletion in the amount of energy possessed by the system.

Due to this loss of energy by the system as a result of the workdone, the internal energy decreases.

Yes, an object can have zero velocity and nonzero acceleration at the same time.

Velocity is a vector quantity that includes both magnitude (speed) and direction. When the velocity of an object is zero, it means the object is at rest and not moving in any direction.Acceleration, on the other hand, is the rate of change of velocity. It describes how quickly an object's velocity is changing, regardless of its initial velocity. An object can have nonzero acceleration if its velocity is changing, even if its initial velocity is zero.For example, consider an object at rest on a frictionless surface. If a constant force is applied to the object, it will experience nonzero acceleration while remaining at rest. The force causes the object's velocity to increase from zero, resulting in nonzero acceleration.So, in certain situations, an object can have zero velocity (at rest) and nonzero acceleration simultaneously, indicating that its velocity is changing even though it is not currently in motion.

To know more about acceleration, click here https://brainly.com/question/12550364

#SPJ11

Answer:

gravity

Explanation:

The larger mass, 2m, will experience a net force of 2f as it moves around the curve of radius r at the same constant speed as the smaller mass, m.

This is because the centripetal force required to keep an object moving in a circle is directly proportional to its mass and the square of its speed. Therefore, for two objects of different masses moving at the same speed around the same curve, the one with the greater mass will require a greater centripetal force, which is equal to its net force. This means that the larger mass will experience a net force that is twice as large as the net force acting on the smaller mass. It is important to note that the speed at which the masses are moving around the curve is a constant, so it does not affect the net force experienced by the masses.

To learn more about speed click here https://brainly.com/question/28224010

#SPJ11

Answer:

12.3°C should be the correct answer

Answer:

12.3

Explanation:

Explanation:

Momentum = mass × speed

p = (30 kg) (3 m/s)

p = 90 kg m/s

The minimum force (Fmin) required to move the block up the ramp is 12.7 N.

Mass of the block (m) = 3.3 kg

Angle of the ramp (θ) = 37°

Coefficient of friction between the block and the ramp (μg) = 0.44

Coefficient of kinetic friction between the block and the ramp (uk) = 0.30

Step 1: Resolve the forces acting on the block.

The weight of the block (mg) can be resolved into two components:

- The force acting parallel to the incline (mg*sinθ)

- The force acting perpendicular to the incline (mg*cosθ)

Step 2: Calculate the force of friction.

The force of friction can be calculated using the equation:

Force of friction (Ff) = μg * (mg*cosθ)

Step 3: Determine the minimum force required.

To move the block up the ramp, the applied force (Fapplied) must overcome the force of friction.

Thus, the minimum force required (Fmin) is given by:

Fmin = Ff + Fapplied

Step 4: Substitute the given values and calculate.

Ff = μg * (mg*cosθ)

Fmin = Ff + Fapplied

Now, let's calculate the values:

Ff = 0.44 * (3.3 kg * 9.8 m/s² * cos(37°))

Ff ≈ 12.717 N

Fmin = 12.717 N + Fapplied

Therefore, the minimum force (Fmin) required to move the block up the ramp is approximately 12.7 N.

To know more about friction, refer here:

https://brainly.com/question/13000653#

#SPJ11

Answer:

i. 170 m

ii. 850 m

Explanation:

Question

Arjun and his son Arav were standing ‘x’ m away from each other. They are equidistant (Y m) from a vertical cliff. Arjun burst a balloon and Arav heard the direct sound 0.5 seconds later and the echo after 2 seconds. If the speed of sound in air is 340m/s ,calculate

i. the distance between Arjun and Arav

ii. the distance between the cliff and Arjun

The parameters given are;

The time for the sound to reach Arav, \(t_D\) = 0.5 s

Time for the echo to echo to reach Arav, \(t_E\) = 2 s

The distance between Arjun and Arav = \(D_D\)

The distance between Arav and the cliff = \(D_E\)

The speed of sound in air, s = 340 m/s

The formula for speed, s, is \(s = \dfrac{Distance, D}{Time, t}\), therefore;

\(s = \dfrac{D_D}{t_D} = \dfrac{D_D}{0.5} = 340\)

\(D_D\) = 0.5 s × 340 m/s = 170 m

The distance between Arjun and Arav = 170 m

ii. Since Arav hears the direct sound before the echo, he is closer to the cliff than Arjun, therefore, we have;

\(s = \dfrac{D_E}{t_E} = \dfrac{D_E}{2} = 340\)

\(D_E\) = 2 s × 340 m/s = 680 m

Therefore, the distance between Arav and the cliff = 680 m

Which gives the distance between the cliff and Arjun, \(D_{cliff}\) = The distance between Arav and the cliff + The distance between Arjun and Arav

\(D_{cliff}\) = 680 + 170 = 850 m.

To find the image distance formed by a concave mirror, we can use the mirror equation:

1/f = 1/di + 1/do

Where:

f is the focal length of the mirror,

di is the image distance,

and do is the object distance.

In this case, the object distance (do) is given as 12.0 cm, and the focal length (f) is given as 15.0 cm. We can rearrange the equation to solve for the image distance (di):

1/di = 1/f - 1/do

Substituting the given values:

1/di = 1/15 - 1/12

To simplify this expression, we need to find a common denominator:

1/di = (12 - 15)/(12 * 15)

1/di = -3/180

Now, we can invert both sides to find di:

di = 180/-3

di = -60 cm

Therefore, the image distance is -60 cm. The negative sign indicates that the image is formed on the same side as the object (in this case, it is a virtual image).

Answer:

60 cm

Explanation:

the U (obj. distance)  =   12  as it is a concave mirror then u  =  -12cm

the f = -15cm

by mirror formula

1/v  +  1/u =  1/f

by substituting values

1/v  +  (1/-12)  =  1/-15

1/v = 1/-15 -(1/-12)

1/v = 1/-15 + 1/12

by taking L C M  60

1/v = -(4/60)  +  5/60

1/v = 1/60

so V = 60 cm

Answer:

rrrrrrrrrrrr42rtwqr

Explanation:

ddddddddddddddddddddddddddeqret

Answer:

Only about 12%–30% of the energy from the fuel you put in a conventional vehicle is used to move it down the road, depending on the drive cycle. The rest of the energy is lost to engine and driveline inefficiencies or used to power accessories. Therefore, the potential to improve fuel efficiency with advanced technologies is enormous.

Answer:

KE = 54450 J

Explanation:

Data:

Use the formula:

Replace and solve:

A kinetic energy of 54450 Newtons is imparted to it.

Greetings.

Answer:

75m

Explanation:

Given parameters:

Distance covered by the boat = 15m

Time taken = 8s

Unknown:

Distance covered by the boat in 40s  = ?

Solution:

To solve this problem, we need to find the speed of the boat first;

    Speed = \(\frac{distance}{time}\)

Insert the parameters and solve;

    Speed  =\(\frac{15}{8}\) m/s

Now;

The boat will travel;    

    Distance  = speed x time

    Distance =   \(\frac{15}{8}\)  x 40  = 75m

The magnitude of the friction force on the box is 36N.

The force applied by the man to push the box of mass 80kg is 180N.

the acceleration of the block is 1.80m/s².

Now, we know,

Acceleration = Net force/mass

A = F/M

Now, the net force will be applied force minus frictional force.

So, if the frictional force is Fr and the applied force is F, then we can write,

a = F-Fr/M

Putting values,

1.80 = 180-Fr/80

Fr = 36N.

So, the frictional force is 36N in magnitude.

To know more about friction, visit,

https://brainly.com/question/24338873

#SPJ4

Answer:

With regards to NASA's ambition to send humans to Mars, is an encouraging idea.  Also, the aim of sending food supply by unmanned spacecraft before the 2030 project though noble is filled with constraints and design problems.

For the constraints,

1. The spacecraft could be lost on the space before it reaches its destination being Mars. This is because, lack of communication between the control unit on earth and the spacecraft signify it being lost forever.

2. The food supply is bound to spoil on Mars since it would be stored unrefrigerated. This is as a result of the actions of the micro organisms acting on them.

For the criteria for the engineering design problem:

1. The distance between earth and Mars is very far

2. Not factoring in the preservation method into the unmanned aircraft.

Explanation:

Answer: A. When half the parent nuclei in a sample have become daughter nuclei

Explanation:

a) Planet X needs to be pointed to hit the castle is 25.61 degrees. b) If the cannon fired at less than 48.9m/angle to reach the target would be greater than 90 degrees.

To determine the angle at which the cannon on Planet X needs to be pointed to hit the castle 2 km away, we can use the range formula for projectile motion.

The range formula is given by: R =\((v^2 * sin(2θ)) / g\) where: R is the range (2 km in this case) v is the initial velocity of the ball (150 m/s in this case) θ is the angle at which the cannon is pointed g is the acceleration due to gravity. First, let's calculate the value of g on Planet X. Since Planet X has half the density of Earth, we can assume its acceleration due to gravity is also half of Earth's value, which is approximate \(9.8 m/s^2\).

Now, let's substitute the given values into the range formula and solve for θ: 2 km = \((150^2 * sin(2θ)) / (0.5 * 9.8)\) Simplifying the equation, we get: 2000 = \((22500 * sin(2θ)) / 4.9\) Cross multiplying, we have: \(2000 * 4.9 = 22500 * sin(2θ) 9800 = 22500 * sin(2θ) sin(2θ) = 9800 / 22500 sin(2θ) ≈ 0.4356\)

To find the value of 2θ, we take the inverse\(sine (sin^-1) of 0.4356: 2θ ≈ sin^-1(0.4356)\) Using a calculator, we find that 2θ ≈ 25.61 degrees.

Therefore, the angle at which the cannon on Planet X needs to be pointed to hit the castle is approximately 25.61 degrees. If the cannon fired at less than 48.9 m/s, it would not be able to hit the castle because the required angle to reach the target would be greater than 90 degrees. This is because the initial velocity is not sufficient to overcome the gravitational pull and reach the target 2 km away.

Learn more about the Projectile motion:

https://brainly.com/question/24216590

#SPJ11

The schools in Uganda and Minneapolis are similar because both are places where students learn and neither has a large enough room.

Due to poor economic conditions and management, the schools of Uganda and Minneapolis have small rooms in which students sit to learn. Both are the places where students comes to learn and make better their economic condition so we can conclude that option C and F are correct.

Learn more about Uganda here: https://brainly.com/question/25641436

Answer:

False

Explanation:

Electrons

Answer:

i my though may it is auestion no B i am not correct may its write

Explanation:

B

Answer/Explanation:

Part 1: 13 chromosomes.

Reproductive cell, male or female, whose nucleus contains only one chromosome of each pair (they are said to be haploid n = 13) and which unites with the gamete of the opposite sex (fertilization) to give birth to an egg (zygote 2n = 26 ) diploid resulting from the association of the two gametes with each his half of the genetic capital.

2. The process of creating a new flower is called reproduction.

Human reproduction is the process by which a man and a woman engender a new individual. It is a method of sexual reproduction.

Sexual reproduction requires:

Sure! Here are the steps for calculating the velocity and distance traveled by the car after 50 seconds :

Step 1: Calculate the velocity using the equation:

\(v = u + at\)

where:

- \(v\) is the final velocity

- \(u\) is the initial velocity (0 m/s, as the car starts from rest)

- \(a\) is the acceleration (3 m/s²)

- \(t\) is the time (50 seconds)

Substituting the values into the equation:

\(v = 0 + (3 \, \text{m/s²}) \times (50 \, \text{s})\)

Step 2: Calculate the distance traveled using the equation:

\(s = ut + \frac{1}{2}at^2\)

where:

- \(s\) is the distance traveled

- \(u\) is the initial velocity (0 m/s)

- \(a\) is the acceleration (3 m/s²)

- \(t\) is the time (50 seconds)

Substituting the values into the equation:

\(s = 0 \times (50 \, \text{s}) + \frac{1}{2} \times (3 \, \text{m/s²}) \times (50 \, \text{s})^2\)

Now, let's simplify these equations:

\(v = 3 \times 50\)

\(s = \frac{1}{2} \times 3 \times 50^2\)

Calculating the results:

\(v = 150\) m/s

\(s = 3750\) meters

Therefore, after 50 seconds, the car will have a velocity of 150 m/s and would have traveled a distance of 3750 meters.

Dual convex lenses follow a set of rules that govern their behavior when light passes through them. These rules include:

1. The incoming light rays are refracted (bent) at the first lens surface, causing them to converge towards the optical axis.

2. The converging light rays then pass through the second lens surface and are refracted again, causing them to diverge away from the optical axis.

3. The point where the refracted light rays converge or diverge is known as the focal point.

4. The distance between the lens and the focal point is known as the focal length.

5. The magnification of the image formed by the lens is determined by the ratio of the distance between the object and the lens (object distance) to the distance between the image and the lens (image distance).

Overall, dual convex lenses are powerful tools for bending and focusing light, and they play a crucial role in many fields, from medicine to astronomy.

To know more about convex lenses visit:-

https://brainly.com/question/10095978

#SPJ11

The new gravitational force between the two heavenly bodies is six times the original gravitational force.

The gravitational force between two heavenly bodies can be calculated using Newton's law of universal gravitation;

F1 = G × (m1 × m2) / r²...eq (1)

gravitational constant = G

mass 1 = m1

mass 2 = m2

radius = r

distance between them constant,

we can calculate the new gravitational force F2 using the formula:

F2 = G × (m1 × m2) / r²; where

gravitational constant = G

mass 1 = 2m1 (doubled)

mass 2 = 3m2 (tripled)

radius = r

on substitution,

F2 = G × (2m1 × 3m2) / r²

= G × (6m1m2) / r²

= 6 × G × (m1m2) / r²

⇒ (G × (m1 × m2) / r² = F1 )...from eq. (1)

= 6 × F1

⇒ F2 = 6F1

Therefore, the new gravitational force will be six times the original gravitational force when one mass is doubled and the other mass is tripled.

Learn more about gravitational force from the given link.

https://brainly.com/question/32609171

If one of the masses in a gravitational system is doubled and the other mass is tripled while keeping the distance between the bodies constant, then the new gravitational force will increase by a multiple of:

6 (2 x 3 = 6)

We know from Newton's Law of Gravitation that the gravitational force between two objects is:

F = G * (m1 * m2) / r^2

Where:

F = Gravitational force

G = Universal gravitational constant

m1 = Mass of first object

m2 = Mass of second object

r = Distance between the objects

Since the distance (r) between the two bodies remains constant in the given scenario, it drops out when calculating the change in force.

We are only concerned with how the change in masses affects the force.

Based on the equation, we can see that the gravitational force is directly proportional to the product of the two masses (m1 * m2).

If one mass doubles and the other mass triples, their product will increase by a multiple of 2 x 3 = 6.

Therefore, the new gravitational force between the two heavenly bodies will increase by a factor of 6, compared to the original gravitational force when only one mass was doubled and the other mass tripled, while keeping the distance constant between them.