The model of a certain mass-spring-damper system is given as follows:10x¨+cẋ+20x=f(t)where f(t) is the input force applied to the mass m and x(t) is the displacement of the mass from its equilibrium position at time t.
The resonant frequency of the mass-spring-damper system can be found using the following formula:ωr=ωn√(1-2ζ^2)where,ωn=√(k/m) = natural frequency of the systemζ = damping ratio of the system, and c = 2ζωn m, where m = mass of the system.r = ωn√(1-2ζ^2)Given that ζ=0.1, we can find the resonant frequency as follows:r = ωn√(1-2ζ^2)Let's find the natural frequency of the system first.k = 20, m = 10, andωn=√(k/m)=√(20/10)=√2Thus,ωn=√2c = 2ζωn m = 2(0.1)(√2)(10) = 4√2Thus,c=4√2Substituting the values of ωn and ζ, we get:r = ωn√(1-2ζ^2)r = (√2)√(1-2(0.1)^2)r = 1.38 rad/sThus, the resonant frequency of the mass-spring-damper system is 1.38 rad/s.The peak magnitude M of the mass-spring-damper system can be found using the following formula:M = f0/2ζωnwhere f0 is the amplitude of the input force applied to the mass m.When the system is subjected to an input force of f0 = 1, we can find the peak magnitude of the system as follows:M = f0/2ζωn=1/2(0.1)(√2)(10)=1.78Thus, the peak magnitude of the mass-spring-damper system is 1.78.
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A machine tool produces 26 components for an assembled product. These are the only partsproduced by the machine. To keep in-process inventories low, a batch size of 75 units is produced for each component. Demand for the product is 900 units/yr. Production downtime costs $120/hr. Changeover time between batches is 1.5 hr, and average cycle time per part 4.0 min. The annual holding cost for each of the 26 parts is $1.60/pc. (a) Determine total annual inventory cost for the 26 parts. (b) Is the given production schedule feasible for a one shift operation? That is, can 900 units of each of the 26 components be completed in 2000hours? If so, how many idle hours of machine time occur in the 2000 hours? If not, how many overtime hours must be authorized during the year?
Total annual inventory cost for the 26 parts is 196.6
What is the annual inventory cost?The cost of purchasing, ordering, and storing inventory is added together. TC is the total cost and is calculated as follows: TC = PC + OC + HC, where PC stands for purchase cost, OC for ordering cost, and HC for holding cost.
The sum of the regular cost and the supplemental yearly cost is referred to as the total annual cost.
PC is the purchase cost, OC is the ordering cost, and HC is the holding cost.
TC = PC + OC + HC,
1.60 + 75+ 120 = 196.6
Total annual inventory cost for the 26 parts is 196.6
The given production schedule feasible for a one shift operation.
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Find the turning point of y= x^3/3-x^2/2-2x+5
There are two turning points (-1,6.167) and (2,1.617) in the graph of the given function y = x³/3-x²/2-2x+5.
What are the turning points?Turning points are locations on a graph when the direction shifts from downward to upward.
The graph for the given function y = x³/3-x²/2-2x+5 is attached please have a look at it. Here the turning point is at the minimum point in the graph of a given function.
As per the given graph,
There are two turning points (-1,6.167) and (2,1.617) in the graph
Thus, there are two turning points (-1,6.167) and (2,1.617) in the graph of the given function y = x³/3-x²/2-2x+5.
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While entering an angled parking spot, when you can see down the ______ of the parking space line closest to your vehicle, turn your wheels and slowly enter the space.
When entering an angled parking spot, it is important to take caution and make sure that you are able to safely enter the spot.
One helpful tip is to look down the line closest to your vehicle to make sure that there are no obstructions or hazards in the way. If you are able to see down the line, you can then turn your wheels and slowly enter the space. This allows for more control and precision when parking your vehicle.
Additionally, it is important to make sure that you are parking within the lines of the spot and leaving enough room for other vehicles to park nearby. By following these guidelines, you can ensure that you are safely and effectively parking in angled parking spots.
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Which option justifies the choice made in the following scenario?
Eli is an environmental engineer. He has recently designed a printer. Instead of plastic, a nonrecyclable material, he has chosen to design the printer using types of metal. It is more costly, but he plans to set up a recycling program where parts from the printer can be reused in the production of future printers.
✔️The material he chose is renewable but will increase costs with his recycling program.
✔️The material he chose is nonrenewable but can be used in future products to reduce costs.
✔️The material he chose is nonrenewable and will increase costs with his recycling program.
✔️The material he chose is renewable and is much better for the environment.
The fact that Eli plans to set up a recycling program made him choose D. The material he chose is renewable and is much better for the environment.
What is recycling?It should be noted that recycling simply means the process of collecting and processing materials that can be turned into another product.
Therefore, the material he chose is renewable and is much better for the environment and thus influenced his decision.
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.Which of the following is an example of using an external integration tool?
A) Creating a Gantt chart
B) Including user representatives as active members of the project team
C) Creating a PERT chart
D) Using portfolio analysis
E) Developing a scoring model
D) Using portfolio analysis is an example of using an external integration tool.
Using an external integration tool refers to utilizing a tool or software that is external to the organization or project to facilitate integration processes. Among the options provided, portfolio analysis is an example of using an external integration tool.
Portfolio analysis is a strategic management technique that involves assessing and analyzing a portfolio of projects, investments, or resources. It helps organizations make decisions regarding resource allocation, risk management, and prioritization of projects or initiatives.
In order to conduct portfolio analysis effectively, organizations often employ specialized software or tools designed specifically for this purpose. These external integration tools enable the organization to consolidate data, perform analysis, and generate insights to support decision-making.
In contrast, the other options provided (creating a Gantt chart, creating a PERT chart, including user representatives as active members, developing a scoring model) do not necessarily require external integration tools. These activities can typically be carried out using internal resources and tools available within the organization.
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What is the maximum number of points a player can score during a frame of snooker while curving around at a 45 degree angle going at a speed of 2 miles per hour with the wind speed of 2 mph on a rug coated snooker table?
In snooker, the maximum number of points that can be scored during a single frame is 147. This is achieved by potting all 15 red balls, each worth 1 point, and subsequently potting the colored balls in sequence: yellow (2 points), green (3 points), brown (4 points), blue (5 points), pink (6 points), and black (7 points). Each color is then returned to its original position and can be potted again for additional points.
The angle and wind speed mentioned in your question are not relevant to determining the maximum number of points in a snooker frame. The speed and direction of the balls are controlled by the player's shots, and the rug coating on the table doesn't affect the scoring.
So, regardless of the angle, wind speed, or table surface, the maximum number of points that can be scored in a frame of snooker is 147.
Which technical practice incorporates build-time identification of security vulnerabilities in the code?
Technical practice incorporates build-time identification of security vulnerabilities in the code is Penetration testing.
What is Penetrating Testing?A penetration test, sometimes referred to as a pen test or ethical hacking, is a legitimate simulated cyberattack on a computer system that is carried out to analyze the system's security. This is distinct from a vulnerability assessment.
In order to identify and illustrate the financial effects of a system's vulnerabilities, penetration testers employ the same tools, strategies, and procedures as attackers. Reconnaissance, scanning, vulnerability assessment, exploitation, and reporting are the five stages of a penetration test.
Penetration testing is a technical activity that includes build-time discovery of security vulnerabilities in the code.
Penetration tests are essential to an organization's security because they teach staff members how to respond to any kind of intrusion from a malicious party. Pen tests are a method of determining whether a company's security procedures are actually effective.
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What happens to the generated voltage, if a more powerful magnet is used?
1) The generated voltage gets higher
2) the generated voltage gets lower
3) the amount of voltage generated stay the same
protons of energy 6.0 mev are incident on a silver foil of thickness 3.3 10-6 m. what fraction of the incident protons is scattered at the following angles?
A proton has a mass of mc2 = 938 MeV. The proton can have a maximum momentum of Pc = 448.5 MeV.
The Coulomb interaction, which represents the elastic scattering of charged particles, is the foundation of the Rutherford scattering model. According to this hypothesis, the alpha particle, when it gets sufficiently close to the nucleus, is strongly repulsed at large angles.
If the difference is greater than 10°, that works out to 4.41 times standing -3. I'm really sorry; I've made a mistake here. It should be 3.37 times and -5 for this uh 90. More than five degrees can also be requested. We'll just repeat the process this time by changing the angle around this, which comes out to be 1.77. B measures 155 cm at this angle, and the fraction of scatters by about five degrees. Apparently, it's 1.77 times 10 to the -2. You asked us to calculate the events between, say, five and ten but less than. The main distinction between five and ten is that.
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A major tennis manufacturer is undertaking a test program for shoes, tennis balls, and tennis strings. Develop a test plan for the situations described below. In each case provide details for how the test should be conducted, and describe expected difficulties in interpreting the results. In each case the tests are to be conducted during college tennis matches. Four teams of six players each are to test the products under match (as opposed to practice) conditions. A tennis team consists of six players, and a match consists of six singles matches and three doubles matches.
a. Tennis shoes: Two different sole designs and materials are to be wear tested. The life of the soles are known to be strongly affected by court surface and playing style.
b. Tennis strings: A new tennis string material is to be tested for durability. String failure occurs due to breakage or due to loss of tension. String life is a function of the racquet, the player's style, and string tension.
c. Tennis balls: Two tennis balls are to be play tested for durability. The condition of a tennis ball can be described by the coefficient of restitution, and the total weight (since the cover material actually is lost during play). A player's style and the court surface are the primary determining factors on tennis ball wear.
Answer:
4 balls
Explanation:
First, we find out how many tennis balls are there altogether.
There are 8 cans and each can has 3 tennis balls.
Total numberThese balls are shared with 6 players. So we divide the total quantity by 6 to find out how many tennis balls each player gets.
Each player = 24 ÷ 6 = 4
of balls = 8 x 3 = 24
A 4-m-high and 6-m-long wall is constructed of two large 2-cm-thick steel plates (k 5 15 w/m·k) separated by 1-cm-thick and 20-cm wide steel bars placed 99 cm apart. the remaining space between the steel plates is filled with fiberglass insulation (k 5 0.035 w/m·k). if the temperature difference between the inner and the outer surfaces of the walls is 22°c, determine the rate of heat transfer through the wall. can we ignore the steel bars between the plates in heat transfer analysis since they occupy only 1 percent of the heat transfer surface area?
The rate of heat transfer through the wall is approximately 130 W.
No, we cannot ignore the steel bars between the plates in the heat transfer analysis because they contribute to the overall thermal resistance of the wall.
While they may only occupy a small percentage of the heat transfer surface area, they still have an impact on the rate of heat transfer through the wall.
By including the thermal resistance of the steel bars in the analysis, we can obtain a more accurate estimate of the heat transfer rate.
To calculate the heat transfer rate, we can use the formula Q = (kAΔT)/d, where Q is the heat transfer rate, k is the thermal conductivity, A is the area of heat transfer, ΔT is the temperature difference, and d is the thickness of the wall.
By applying this formula to the given data, we can calculate that the rate of heat transfer through the wall is approximately 130 W.
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Aerotron Electronics is considering purchasing a water filtration system to assist in circuit board manufacturing. The system costs $32,000. It has an expected life of 7 years at which time its salvage value will be $5,000. Operating and maintenance expenses are estimated to be $2,000 per year. If the filtration system is not purchased, Aerotron Electronics will have to pay Bay City $13,000 per year for water purification. If the system is purchased, no water purification from Bay City will be needed. Aerotron Electronics must borrow 1/2 of the purchase price, but they cannot start repaying the loan for 2 years. The bank has agreed to 3 equal annual payments, with the 1st payment due at the end of year 2. The loan interest rate is 8.5 % compounded annually. Aerotron electronics’ MARR is 12.5 % compounded annually.
Required:
a. What is the present worth of this investment? (Carry all interim calculations to 5 decimal places and then round your final answer to the nearest dollar. The tolerance is £10.)
b. What is the decision rule for judging the attractiveness of investments based on present worth?
c. Should Aerotron Electronics buy the water filtration system?
Answer:
Explanation:
a) Present worth of the system:
First step :
Calculation of bank installment:
We are given:
·nitial costs = $32,000
Borrow amount = ½ of purchase price
Payment of borrow amount = EOY 2 to EOY 4 (3 Equal installments)
Bank loan interest = 8.5% = 8.5/100 = 0.085
Assume the installment amount is F. They will be paid at end of year 2 to end of year 4. Their present value must be equal to borrow amount.
Present value of cost to be incurred in future can be calculated by below formula:
F P (1 + i)
F= Future cost
i = Rate of interest
n = time (in years)
Therefore,
F F $32,000 2 F (1 +0.085)2 (1 +0.085) 3 (1 +0.085) + +
.: 2.35394F = 16,000 or F = 16,000 2.35394 - $6,797.11
Step 2: Present worth of the system:
Given Data:
Initial costs = $32,000
Expected life = 7 years
Salvage value = $5,000
O&M Costs = $2,000 per year
MARR = 12.5%
= 12.5/100
= 0.125
Present value of uniform recurring payments is given by below formula:
P=A (1 + i) - 1 i(1+i)n 72
Where,
P = Present Value
A = Recurring payments per annum
i = rate of interest
n = time (in years)
Hence present value of O&M costs,
P1 = -2,000 x (1 + 0.125) 7-1 0.125 x (1 + 0.125) 7 -$8,984.60
Present worth of the system calculated in below table:
Description
F ($)
MARR (i)
per year
n (years)
P ($)
Initial investment (1/2 of purchase price)
-16,000.00
0.125
0
-16,000.00
Bank installment EOY2
-6,797.11
0.125
2
-5,370.56
Bank installment EOY3
-6,797.11
0.125
3
-4,773.83
Bank installment EOY4
-6,797.11
0.125
4
-4,243.40
Salvage value
5,000.00
0.125
7
2,192.31
O&M Costs
-8,984.60
0.125
0
-8,984.60
The current worth of the new system
-37,180.07
Part b) Decision rule of judgment:
Assuming current value of costs is lower than current value of benefit, an alternative is known to be economic to use based on current worth analysis.
Part c) Decision for the water filtration system:
Given Data:
· Annual savings from filtration system (A) = $13,000 per year
· Expected life (n) = 7 years
· MARR = 12.5%
= 12.5/100
= 0.125
Present value of benefits = 13,000 X (1 + 0.125)7 - 1 0.125 x (1 + 0.125) 7 $58,399.91
Since current value of costs is less than current value of benefit, this is an worthwhile system and has to be be purchased.
For the following production environments, indicate whether the preferred production system is more likely to be a job shop (process layout), production line (product layout), batch process (group technology layout), or hybrid. Provide support for your answer.
a. Manufacturer of Clothes: makes many styles (shirts, pants, coats, rain jackets, etc.) and sells to small specialty stores.
b. Manufacturer of Gaskets: makes styles for 4-5 engine blocks: sells to GM and Ford (i.e., high volume).
c. Independent Automobile Service Shop: body work, general service, engine repair, serving many makes of automobiles.
d. Producer of Pharmaceutical Drugs: make approximately 50-75 drugs in tablet form: sell to pharmacies nationwide.
Answer:
A) Batch shop production
B) Batch shop production
C) Job shop production
D) production line
Explanation:
A)The preferred production system here will be Batch shop production because the manufacturer produces different styles of clothing and sells to small specialty stores hence producing in Batches can help meet up the needs
B) The preferred production system here will be Batch shop production because the manufacturer produces Gaskets and they are of different styles hence he needs to produce them in batches
C) Job shop production
D) production here is streamlined to a particular ( tablet form ) hence the production system here would be a Production line system of production
Q. How are you informed of what to do in the event of an on-site emergency?
Answer:
I don't know
Explanation:
sorry I am answering this for points
please follow and mark as brainliest for me I will also do same
Answer:
Adapting this case to a work environment, especifically an industry, there should be a security and health brigade in charge of response against emergencies within the organization. Said brigade has the duty of giving direction to all people that could be hurt in any way by a negative event caused by the emergency These directions are given orally in the case of emergencies. Also, emergency services personnel, such as police, firefighters, and paramedics, are certified professionals who have the responsibility of protecting people against harm, and this includes giving guidance during emergencies.
the coil polarity in a waste spark system is determined by the direction in which the coil is wound (left hand rule for conventional current flow) and cant be changed. for example if a V8 engine has a firing order of 18436527 and number one cylinder is on compression which cylinder would be on the exhaust stroke?
A V-8 engine that posses a firing order of 18436572 with number 1 cylinder on compression, the cylinder which would be on the exhaust stroke is number: A. 6.
What is an injector?An injector can be defined as a mechanical device that is designed and developed for the introduction of fuel into the internal combustion system of an engine, especially under pressure.
The types of fuel injection system.In Engineering, there are two (2) main types of fuel injection system and these include the following:
Simultaneous fuel injection.Sequential fuel injection.What is a sequential fuel injection?A sequential fuel injection is typically designed and developed to spray fuel into the internal combustion system of an engine based on the firing order that is configured within it by the manufacturer.
As a general rule, one of the two-paired spark plugs within the internal combustion system of an engine is always designed to have a negative polarity while the other spark plug is designed to have a positive polarity always.
In this context, we can infer and logically deduce that a V-8 engine that posses a firing order of 18436572 with number 1 cylinder on compression, the cylinder which would be on the exhaust stroke is number 6.
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Complete Question:
The coil polarity in a waste-spark system is determined by the direction in which the coil is wound (left-hand rule for conventional current flow) and can't be changed. for example, if a v-8 engine has a firing order of 18436572 and number 1 cylinder is on compression, which cylinder will be on the exhaust stroke?
A. 6
B. 4
C. 8
D. 2
What signal propagation phenomena causes the diffusion, or the reflection in multiple different directions, of a signal?
In the radio communication system, multipath is the propagation phenomenon that causes diffusion or reflection in multiple different directions of a signal.
Multipath is a propagation mechanism that impacts the propagation of signals in radio communication. Multipath results in the transmission of data to the receiving antenna by two or more paths. Diffusion and reflection are the causes that create multiple paths for the signal to be delivered.
Diffraction occurs when a signal bends around sharp corners; while reflection occurs when a signal impinges on a smooth object. When a signal is received through more than one path because of the diffraction or reflection, it creates phase shifting and interference of the signal.
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A civil engineer tested two different types (A and B) of a special reinforced concrete beam. He made nine test beams (five A 's and 4 B's) and measured the strength of each. From the following strength data (in coded units) he wants to decide whether there is any real difference between the two types.
Type A 67 80 106 83 89
Type B 45 71 87 53
Use Wilcoxon-Mann-Whitney test to answer this question.
Use unpaired t-test, assuming equal variances between groups, to answer this question.
Use unpaired t-test, assuming unequal variances between two groups, to answer this question.
The Wilcoxon-Mann-Whitney test is a non-parametric statistical test used to test the null hypothesis that two independent groups come from the same distribution. To carry out this test, we need to take the following steps:First, we rank the observations from lowest to highest.
We combine the ranks and then calculate the sum of the ranks for each group. We will then use these sums to calculate the test statistic (W). The sum of the ranks for group A is:67, 80, 106, 83, 89 = 5 + 6 + 9 + 7 + 8 = 35The sum of the ranks for group B is:45, 71, 87, 53 = 1 + 4 + 8 + 2 = 15The test statistic (W) is given by the equation:W = n1n2 + n1(n1 + 1)/2 - R1where n1 and n2 are the sample sizes of the two groups, R1 is the sum of the ranks for group A, and N is the total number of observations.
W = (5)(4) + (5)(6)/2 - 35 = 5The critical value for W is 1 at the 5% level of significance. Since W = 5, we can reject the null hypothesis that the two groups come from the same distribution.In order to use the t-test to compare the mean strengths of the two groups, we need to first check the normality assumption and equal variances. The normality assumption can be checked using a normal probability plot or a histogram.
The equal variance assumption can be checked using a boxplot or Levene's test.Assuming equal variances between groups, the null hypothesis is that the mean strengths of the two groups are equal.
The alternative hypothesis is that the mean strengths are different.Using the t-test, we obtain the following results:t = (mean A - mean B) / (s / sqrt(n))where s is the pooled standard deviation given by:s = sqrt(((n1 - 1)s1^2 + (n2 - 1)s2^2) / (n1 + n2 - 2))t = (mean A - mean B) / (s / sqrt(n)) = (85 - 64) / (14.11 / sqrt(9)) = 3.58The degrees of freedom for the t-test is given by df = n1 + n2 - 2 = 9 - 2 = 7The critical value for a two-tailed test with df = 7 at the 5% level of significance is 2.365. Since t = 3.58 > 2.365, we can reject the null hypothesis that the mean strengths of the two groups are equal.Therefore, we conclude that there is a real difference between the two types of special reinforced concrete beams.
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True or false
Consumer is the end user
Client is usually a company
Consumer is usually a company
Client is the end user
Consumer is the end user
Client is usually a company
Consumer is usually a company
Client is the end user
Answer:
Explanation:
a) True
b) False
c) False
d) False
e) True
f) False
g) False
h)False
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Choose the term that matches the definition. : a programming language that uses instructions that are close to everyday English
The term that matches the definition is "high-level programming language."
In a high-level programming language, the instructions and syntax are designed to be close to everyday English, making it easier for programmers to read, write, and understand the code. High-level programming languages abstract away many low-level details and complexities of computer hardware, providing a more intuitive and human-friendly approach to programming.
These languages utilize a vocabulary and syntax that resemble natural language, with keywords and constructs that align with common concepts and actions.
For example, high-level languages may use keywords such as "if," "while," and "for" to represent conditional statements, loops, and iteration. Variables and functions are often named using descriptive words or phrases, allowing for more expressive and self-explanatory code.
By using a high-level programming language, developers can focus on the logical aspects of their programs rather than getting lost in intricate machine-level details. This abstraction enables faster development, better code readability, and increased productivity.
Examples of high-level programming languages include Python, Java, C++, and JavaScript. These languages provide extensive libraries, frameworks, and tools that simplify complex tasks and provide a wide range of functionalities. The use of natural language-like syntax in these languages enhances the programmer's ability to communicate intentions and ideas effectively.
In contrast, low-level programming languages, such as assembly or machine code, use instructions that directly correspond to the underlying hardware architecture, offering more control but requiring a deep understanding of computer internals. High-level languages bridge this gap and make programming more accessible and user-friendly for developers.
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Avapor mixture containing 50.0 mole % benzene and 50.0 mole % toluene at 1 atm is cooled isobarically in a closed container from an initial temperature of 115°C. Use the Tsy diagram below to answer the following questions. 115 110 1400 1300 105 100 Vapor 1200 95 Temperature (°C) 90 Liquid 1100 1000 900 Pressure (mm Hg) Liquid 85 800 Vapor 80 700 75 70 600 500 0 1.0 65 0 10 0.2 0.4 0.6 0.8 Mole fraction henvene Polarm 0.2 0.4 0.6 0.8 Mole fraction benzene 7100 First Condensation Your answer is partially correct. At what temperature does the first drop of condensate form? 104 °C What is its composition? 0.20 mol benzene/mol
Last Condensate Your answer is partially correct. At what temperature does the last bubble of vapor condense? °C 98 What is its composition? 0.53 mol benzene/mol
Answer:
105°touch sensce what I could wathskb
it takes at least an hour for the temperature inside a vehicle to rise over 20 degrees. T/F
Answer: TRUE
Explanation: The temperature inside your vehicle can rise almost 20º F in just 10 minutes, and almost 30º F in 20 minutes. The longer you wait, the higher it goes. At one hour, your vehicle's inside temperature can be more than 40 degrees higher than the outside temperature.
True. It is well known that temperatures inside a parked car can quickly become dangerously hot, especially during hot summer months.
In fact, research has shown that temperatures inside a car can rise by as much as 20 degrees Fahrenheit within the first 10 minutes of being parked. Moreover, even when it's just 70 degrees Fahrenheit outside, the temperature inside a car can quickly reach 90 degrees Fahrenheit or more within an hour. This is due to the fact that a car's interior can trap heat and sunlight, leading to rapid temperature increases. Therefore, it's essential to never leave children, pets, or anyone else inside a parked car, even for just a few minutes. The consequences can be deadly.
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Compute the volume percent of graphite, VGr, in a 3.2 wt% C cast iron, assuming that all the carbon exists as the graphite phase. Assume densities of 7.9 and 2.3 g/cm3 for ferrite and graphite, respectively.
Answer:
The volume percentage of graphite is 10.197 per cent.
Explanation:
The volume percent of graphite is the ratio of the volume occupied by the graphite phase to the volume occupied by the graphite and ferrite phases. The weight percent in the cast iron is 3.2 wt% (graphite) and 96.8 wt% (ferrite). The volume percentage of graphite is:
\(\%V_{gr} = \frac{V_{gr}}{V_{gr}+V_{fe}} \times 100\,\%\)
Where:
\(V_{gr}\) - Volume occupied by the graphite phase, measured in cubic centimeters.
\(V_{fe}\) - Volume occupied by the graphite phase, measured in cubic centimeters.
The expression is expanded by using the definition of density and subsequently simplified:
\(\%V_{gr} = \frac{\frac{m_{gr}}{\rho_{gr}} }{\frac{m_{gr}}{\rho_{gr}}+\frac{m_{fe}}{\rho_{fe}}}\times 100\,\%\)
Where:
\(m_{fe}\), \(m_{gr}\) - Masses of the ferrite and graphite phases, measured in grams.
\(\rho_{fe}, \rho_{gr}\) - Densities of the ferrite and graphite phases, measured in grams per cubic centimeter.
\(\%V_{gr} = \frac{1}{1+\frac{\frac{m_{fe}}{\rho_{fe}} }{\frac{m_{gr}}{\rho_{gr}} } }\times 100\,\%\)
\(\%V_{gr} = \frac{1}{1 + \left(\frac{\rho_{gr}}{\rho_{fe}} \right)\cdot\left(\frac{m_{fe}}{m_{gr}} \right)} \times 100\,\%\)
If \(\rho_{gr} = 2.3\,\frac{g}{cm^{3}}\), \(\rho_{fe} = 7.9\,\frac{g}{cm^{3}}\), \(m_{gr} = 3.2\,g\) and \(m_{fe} = 96.8\,g\), the volume percentage of graphite is:
\(\%V_{gr} = \frac{1}{1+\left(\frac{2.3\,\frac{g}{cm^{3}} }{7.9\,\frac{g}{cm^{3}} } \right)\cdot \left(\frac{96.8\,g}{3.2\,g} \right)} \times 100\,\%\)
\(\%V_{gr} = 10.197\,\%V\)
The volume percentage of graphite is 10.197 per cent.
Following are the solution to the given points:
\(\to C_{Gr} = 100\\\\ \to C_{\alpha}= 0\)From \(Fe-F_{\frac{e}{3}} c\) diagram.
\(\to W_{\alpha} =\frac{C_{Gr}-C_{o}}{C_{Gr}-C_{\alpha}}\)
\(= \frac{100-3.6}{100-0} \\\\= \frac{100-3.6}{100} \\\\= \frac{96.4}{100} \\\\=0.964\)
Calculating the weight fraction of graphite:
\(\to W_{Gr}=\frac{C_0 - c_d}{C_{Gr} -c_d}\)
\(= \frac{3.6-0}{100-0} \\\\ = \frac{3.6}{100} \\\\= 0.036\)
Calculating the volume percent of graphite:
\(\to V_{Gr}=\frac{\frac{W_{Gr}}{P_{Gr}}}{\frac{w_{\alpha}}{P_{\alpha}}+ \frac{W_{Gr}}{P_{Gr}}}\)
\(=\frac{\frac{0.036}{2.3}}{\frac{0.964}{7.9}+\frac{0.036}{2.3}}\\\\=0.11368 \times 100\%\\\\=11.368\%\)
Therefore, the final answer is "0.964, 0.036, and 11.368%"
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A man who lived on the top floor of a twenty story building had to go up and down daily for work, and of course, for food and the other necessities. On most days he could only ride the elevator to the fifteenth story, and he would have to walk the rest of the way. When it rained, however, he could ride all the way up to the twentieth story. Why?.
Main Answer:
On most days he could only ride the elevator to the fifteenth story, and he would have to walk the rest of the way
sub heading:
explain elevator?
Explanation:
1.elevator, also called lift, car that moves in a vertical shaft to carry passengers or freight between the levels of a multistory building.
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Shaft AB has a 30-mm diameter and is made of a steel with an allowable shearing stress of 100 MPa; shaft BC has a 50-mm diameter and is made of an aluminum alloy with an allowable shearing stress of 60 MPa. Neglecting the effect of stress concentrations, determine the largest torque T that can be applied at A.
Answer: The largest torque that can be applied at A is the smaller of both
Tᵇc and Tᵃᵇ
which is (Tᵃᵇ = 530.14376 Nm)
Explanation:
First we take a look at Torque formula
T = M × Shear stress
T = π/2 × (d/2)³ × shear stress
{ where M = π/2 × (d/2)³ = π/2 × d³/8
For Shaft AB
d = 30mm = 30 × 10⁻³m
shaft stress = 100Mpa = 100 × 10⁶ N/m²
now Torque at A due to AB
Tᵃᵇ = π/2 × (d/2)³ × shear stress
Tᵃᵇ = π/2 × (30 × 10⁻³)³/2³ × 100 × 10⁶
Tᵃᵇ = π/2 × (0.000027 / 8) × 100 × 10⁶
Tᵃᵇ = 530.14376 Nm
For Shaft BC
the value for M is changed
M = π/2 × { (d₂/2)⁴ - (d₁/2)⁴}
d₁ = 30mm = 30 × 10⁻³m
d₂ = 50mm = 50 × 10⁻³m
M = π/2 × { (50 × 10⁻³/2)⁴ - (30 × 10⁻³/2)⁴}
M = 5.34 × 10⁻⁷
Torque formula is also changed which is
T = M × share stress / (d₂/2)
shear stress = 60Mpa = 60 × 10⁶ N/m²
so Torque A due to BC is
Tᵇc = (5.34 × 10⁻⁷ × 60 × 10⁶) / ( 50 × 10⁻³ / 2
Tᵇc = 1281.6 Nm
Therefore the largest torque that can be applied at A is the smaller of both
Tᵇc and Tᵃᵇ
which is (Tᵃᵇ = 530.14376 Nm)
An Otto cycle with air as the working fluid has a compression ratio of 8.2. Under cold air standard conditions, what is the thermal efficiency of this cycle?
Answer:
Under cold air standard conditions, the thermal efficiency of this cycle is 56.9 percent.
Explanation:
From Thermodynamics we remember that thermal efficiency of the ideal Otto cycle (\(\eta_{th}\)), dimensionless, is defined by the following formula:
\(\eta_{th} = 1-\frac{1}{r^{\gamma-1}}\) (Eq. 1)
Where:
\(r\) - Compression ratio, dimensionless.
\(\gamma\) - Specific heat ratio, dimensionless.
Please notice that specific heat ratio under cold air standard conditions is \(\gamma = 1.4\).
If we know that \(r = 8.2\) and \(\gamma = 1.4\), then thermal efficiency of the ideal Otto cycle is:
\(\eta_{th} = 1-\frac{1}{8.2^{1.4-1}}\)
\(\eta_{th} = 0.569\)
Under cold air standard conditions, the thermal efficiency of this cycle is 56.9 percent.
the most notable aspect in managing C/N for downlink designs is
Answer:
Explanation:
In satellite communications, downlink is the establishment of a communications link from an orbiting satellite down to one or more ground stations on Earth. Contrast with uplink.
what effect does the periodicity doubling have on the dfs?
The effect of periodicity doubling on the Discrete Fourier Transform (DFS) is that it increases the frequency resolution of the transformed signal.
Here is a step-by-step explanation:
1. Periodicity refers to the repetition of a signal pattern over a specific interval of time or space.
2. When periodicity doubling occurs, it means that the periodicity of the signal has been increased by a factor of two.
3. In the context of DFS, it involves increasing the number of sample points by a factor of two while keeping the duration of the signal the same.
4. This increase in the number of sample points allows for better frequency resolution in the transformed signal, as the frequency bins in the frequency domain will be narrower.
5. With higher frequency resolution, it becomes easier to distinguish between closely spaced frequency components in the signal, resulting in a more accurate representation of the original signal in the frequency domain.
In summary, periodicity doubling improves the frequency resolution of the DFS, allowing for a more accurate representation of the original signal in the frequency domain.
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Teaching points require an open program and
To make a point teaching , you need a community and an open program.
How many years are there in a teacher's course?In order to prepare students to teach high school, the Bachelor of Secondary Education (BSED) curriculum lasts four years. A high school teacher needs a certain set of knowledge and abilities, which the curriculum teaches students by combining theory and practice. finishing a teacher education program that has been approved by the state. A background check that was successful. passing the required general teacher certification or licensing test.
A teacher is what kind of person?A teacher, who may also be referred to as a schoolteacher or an educator in official capacity, is a person who, by the act of teaching, aids students in acquiring knowledge, skills, or virtues.
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Create a decision matrix that can be used to decide the changes that could be implemented in the design of an automobile, and explain how an engineer might find it useful.
Answer:
An engineer using a decision matrix to determine which one of his/her solution ideas meets the established criteria and constraints.
If the same type of thermoplastic polymer is being tensile tested and the strain rate is increased, it will: g
Answer:
It would break I think need to try it out
Explanation: