the motor unit ais used to elevate the 300-kg cylinder at a constant rate of 2 m/s. if the power meter bregisters an electrical input of 2.20 kw, calculate the combined electrical and mechanical efficiency eof the system

After measuring thing x and finding an instrumental uncertainty on x of 0.5 cm and a statistical uncertainty of 0.8 cm, we : "take more data".

However, there is always some degree of uncertainty in measurements, and this uncertainty can come from many different places. Uncertainty analysis, or error analysis, is the process of assessing the degree of uncertainty related to a measurement result.

Mainly two factors contribute to the uncertainty : bias (related to accuracy) and the inevitable random variation that happens when taking repeated measurements (related to precision). The question of how biases and random variation from the measured quantities "propagate" into the uncertainty of the derived quantity must be addressed because both of these phenomena are likely to exist. The "propagation of error" is a common name for uncertainty analysis.

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Answer:

D. OJ

Explanation:

The acceleration of the car is 2m/s^2.

Speed, in physics, is the rate of change of object speed in relation to time. The acceleration of an object is the sum total of any force and all that is active in an object, as defined by Newton's Second Law. The SI acceleration unit is a meter per second (m s ^ −2).

Acceleration of the vector value is defined as the rate at which an object changes speed. An object is faster when it changes its speed. Since speed is a vector model, it has direction and magnitude.

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The time constant (τ) for the given circuit is 6.125 milliseconds (ms). After a very long time, the voltage drop across the capacitor (VC) will be equal to the battery voltage (VB). The charge on the capacitor (Q) after a very long time is 192.5 microcoulombs (μC). The current (I) after a very long time is 35.455 microamps (μA). The time (t) after which the current through the resistor is one-third of its maximum value is 18.375 ms. The charge on the capacitor when the current in the resistor equals one-third its maximum value is 6.4175 μC.

The time constant (τ) for an RC circuit can be calculated using the formula τ = RC. Given the capacitance (C) as 3.5 μF and resistance (R) as 5.5 kΩ (which is equivalent to 5500 Ω), we can substitute these values into the formula to find τ. τ = (3.5 μF) * (5500 Ω) = 6.125 ms.

After a very long time, the capacitor will fully charge and reach its maximum voltage. In this case, the voltage drop across the capacitor (VC) will be equal to the battery voltage (VB). So VC = VB = 55 V.

The charge (Q) on the capacitor after a very long time can be calculated using the formula Q = VC * C. Substituting the values, we get Q = (55 V) * (3.5 μF) = 192.5 μC.

The current (I) after a very long time can be calculated using Ohm's Law, where I = VB / R. Substituting the values, we get I = (55 V) / (5500 Ω) = 35.455 μA.

To calculate the time (t) after which the current through the resistor is one-third of its maximum value, we use the formula t = 3τ. Substituting the value of τ calculated earlier, we get t = 3 * 6.125 ms = 18.375 ms.

The charge (Q) on the capacitor when the current in the resistor equals one-third its maximum value can be calculated using the formula Q = (1/3) * (VB * C). Substituting the values, we get Q = (1/3) * (55 V) * (3.5 μF) = 6.4175 μC.

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Therefore, Intramolecular forces holds atom that in same molecules together

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Answer:

Explanation:

I just did this question and this was the right answer for me. Hope this helps!

Answer:

The correction is the state of mind being for the Fahrenheit that is calculator from anarchy

Explanation:

Answer:

Si system is :kilo miligram kelvin

us system is: Fahrenheit Ounce yard inch

Explanation:

The frequency of electromagnetic waves is 10⁶ Hz or 1 MHz.

We need to know about electromagnetic waves to solve this problem. Electromagnetic waves can propagate without media. The speed of electromagnetic in vacuum media is equal to the speed of light. Hence, the wavelength and frequency can be determined as

c = λ . f

where c is the speed of light (3 x 10⁸ m/s), λ is wavelength and f is frequency.

From the question above, we know that

λ = 300 m

By substituting the given parameter, we can calculate the frequency of radiowaves

c = λ . f

f = c / λ

f = 3 x 10⁸ / 300

f = 10⁶ Hz

f = 1 MHz

Hence, the frequency of radiowaves is 10⁶ Hz or 1 MHz.

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The speed of light in a material 1.81 x 10^8 m/s; thus the absolute index of refraction of the material is 1.11.


The absolute index of refraction, also known as the refractive index, is the ratio of the speed of light in a vacuum to the speed of light in a material. In this case, the speed of light in the material is given as 1.81 x 10^8 m/s. The speed of light in a vacuum is always constant and is equal to 3 x 10^8 m/s. Therefore, the absolute index of refraction can be calculated as follows:

Absolute index of refraction = speed of light in a vacuum / speed of light in the material
Absolute index of refraction = 3 x 10^8 m/s / 1.81 x 10^8 m/s
Absolute index of refraction = 1.11

Therefore, the absolute index of refraction of the material is 1.11.

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Answer:

i think it is 45 kilograms not really sure?

Explanation:it might be wrong but i think it is right

A force of 80 newtons pushes a 50.-kilogram object across a level floor for 8.0 meters. The work done is 640 J. The option C is correct answer.

Work is defined as the product of force and displacement in the direction of the force. Work is a physical quantity that measures the amount of energy transferred to or from an object due to the application of a force. It is calculated by multiplying the magnitude of the force applied to an object by the displacement of the object in the direction of the force.

Displacement refers to the change in the position of an object, typically measured in terms of distance and direction from the starting point to the ending point. It is a vector quantity, which means it has both magnitude and direction. Therefore, the work done is:

To calculate the work done, we can use the formula:

Work = Force × Distance × cos(theta)

Where,

Force = 80 N (given)

Distance = 8.0 m (given)

theta = angle between the force and the direction of motion (assumed to be 0 degrees since the force is pushing in the same direction as the displacement)

Plugging in the values:

Work = 80 N × 8.0 m × cos(0°)

Work = 80 N × 8.0 m × 1 (cos(0°) = 1)

Work = 640 J

Therefore, the work done is 640 J, which corresponds to option (C).

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Complete Question:

A force of 80 newtons pushes a 50.-kilogram object across a level floor for 8.0 meters. The work done is

(A) 10 J

(B) 400 J

(C) 640 J

(D) 3,920 J

Answer:

true

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Answer:

True

Explanation:

A warm-up  revs up your cardiovascular system by raising your body temperature and increasing blood flow to your muscles. Warming up also helps reduce muscle soreness and it lessens your risk of injury. Cooling down after your workout allows for a gradual recovery of pre exercise heart rate and blood pressure.

We are given the following information

Mass of car = 950 kg

Initial speed of car = 16.0 m/s

Final speed of car = 9.50 m/s

Time = 1.20 s

The average force exerted on the car during braking can be found using Newton's 2nd law of motion

Where m is the mass of the car and a is the acceleration of the car.

The acceleration of the car is given by

The negative sign indicates deacceleration since the car is stopping.

So, the force is

Therefore, an average force of 5145.865 N was exerted on your car during braking.

The distance traveled by the car while braking can be found as

Let us substitute the given values

Therefore, the car traveled a distance of 15.3 m while braking.

Answer:

False

Explanation:

Because acceleration just means that the speeds getting faster he could already be going at a same rate of speed and it wouldn't be counted as acceleration because acceleration would be if he increased the speed

Answer:

1. they both act on an object in free fall

Explanation:

2. both help determine how fast the object will accelerate

The starter motor consumes 1500 watts of power.

To calculate the power consumed by the starter motor, we can use the formula:

Power (P) = Current (I) × Voltage (V)

Given that the starter motor draws 150 amperes (I) at 10 volts (V), we can substitute these values into the formula:

P = 150 A × 10 V

P = 1500 watts

Therefore, the starter motor consumes 1500 watts of power.

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Answer:

μ = 0.125

Explanation:

To solve this problem, which is generally asked for the coefficient of friction, we will use the conservation of energy.

Let's start working on the ramp

starting point. Highest point of the ramp

         Em₀ = U = m h y

final point. Lower part of the ramp, before entering the rough surface

        \(Em_{f}\) = K = ½ m v²

as they indicate that there is no friction on the ramp

          Em₀ = Em_{f}

          m g y = ½ m v²

          v = \(\sqrt{2gy}\)

we calculate

          v = √(2 9.8 0.25)

           v = 2.21 m / s

in the rough part we use the relationship between work and kinetic energy

          W = ΔK = K_{f} -K₀

as it stops the final kinetic energy is zero

          W = -K₀

The work is done by the friction force, which opposes the movement

          W = - fr x

friction force has the expression

          fr = μ N

let's write Newton's second law for the vertical axis

         N-W = 0

         N = W = m g

we substitute

            -μ m g x = - ½ m v²

           μ = \(\frac{v^{2} }{2 g x}\)

Let's calculate

           μ = \(\frac{2.21^{2}}{2\ 9.8\ 2.0}\)

           μ = 0.125

A 8.0 kg box is released from rest at a height y0 = 0.25 m on a frictionless ramp. The box slides from the ramp onto a rough horizontal surface. The box slides 2.0 m horizontally until it stops.

What is the friction coefficient of the horizontal surface?

Answer: 0.125

A graph is typically used to depict a change in motion. The link between several variables, such as time and location, time and velocity, or time and acceleration, is visually represented by a graph.

One may see the pattern and trend of the motion over time by putting the data points on a graph. A velocity-time graph, for instance, demonstrates how an object's velocity varies over time, whereas a position-time graph demonstrates how an object's location changes with regard to time.

These graphs give us a visual picture of an object's dynamics and allow us to analyse any acceleration, deceleration, or other changes in motion.

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Answer:

Explanation:

window!

The light most likely strikes on a window.

Refraction of light is defined as the bending of light when it travels from one medium to another.

Here,

When light falls on a smooth, reflecting surfaces like glass, mirror, water, it gets bounced back. This is known as the reflection of light.

But when a light ray strikes on the surface like, a window, the light will get refracted and as a result, when it passes through the glass, the path of the light is changed.

The light undergoes refraction twice, as the light enters and gets escaped from the window.

Hence,

The light most likely strikes on a window.

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Answer:

5.978 años luz

Explanation:

Hi! Your answer is: The distance between the Barnard's star and Earth is 5.978 light years.

The five pillars of safety are engineering, encouragement, enforcement, and evaluation. Your strategy to ensure that you promote a safe environment and workplace should heavily emphasize education.

By exercising your intellect beforehand, you may be able to save a life or at least lessen someone else's suffering. The three fundamental Cs are check, call, and care.

A Framework for Aligning the 14 Process Safety Management Elements. To prevent the release of extremely hazardous substances, it is essential to use related techniques to managing hazards, although it might be difficult to put Process Safety Management's operational goals into effect.

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Answer:

The scattering angle is 0.80

Explanation:

As we know  

Wave length = h/mc (1-cos α) --1

W = mc^2

m = E/c^2

Substituting this in equation 1 we get  

Wavelength = hc/E (1-cos α)

Substituting the given values, we get -  

0.95*10^-9 = [(6.626 *10^-34 * 2.998 *10^8)/5.111*1000*1.6*10^-19} (1-cos α)

(1-cos α) = 1.14 *10^-10

cos α = 1- 1.14 *10^-10

α = 0.80

Answer:

The equivalent resistance of the combination is R/100

Explanation:

Parallel Connection of Resistances

If resistances R1, R2, R3,...., Rn are connected in parallel, the equivalent resistance is calculated as follows:

\(\displaystyle \frac{1}{R_e}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}+...+\frac{1}{R_n}\)

The electric resistance of a wire is directly proportional to its length. If a wire of resistance R is cut into 10 equal parts, then each part has a resistance of R/10.

It's known the 10 parts or resistance R/10 were connected in parallel, thus the electric resistance is:

\(\displaystyle \frac{1}{R_e}=\frac{1}{R/10}+\frac{1}{R/10}+\frac{1}{R/10}+...+\frac{1}{R/10}\)

Note the sum consists of 10 equal terms. Operating on each term:

\(\displaystyle \frac{1}{R_e}=\frac{10}{R}+\frac{10}{R}+\frac{10}{R}+...+\frac{10}{R}\)

The sum of 10 identical fractions yields 10 times each fraction:

\(\displaystyle \frac{1}{R_e}=10\frac{10}{R}=\frac{100}{R}\)

Solving for Re needs to take the reciprocal of both sides of the equation:

\(R_e=R/100\)

The equivalent resistance of the combination is R/100

The fraction of observations in an ideal Gaussian distribution that lies within μ±σ is approximately 68%. Within μ±2σ, it is approximately 95%, and within μ±3σ, it is approximately 99.7%.

In a Gaussian distribution, also known as a normal distribution, the mean (μ) represents the central tendency, and the standard deviation (σ) measures the spread or dispersion of the data. The empirical rule, also known as the 68-95-99.7 rule, provides estimates for the percentage of observations within different ranges from the mean.

The first paragraph specifies that within μ±σ, which covers one standard deviation on both sides of the mean, approximately 68% of the data falls. This indicates that the majority of the observations are relatively close to the mean.

The second paragraph states that within μ±2σ, which covers two standard deviations on both sides of the mean, approximately 95% of the data lies. This broader range encompasses a higher proportion of the observations, indicating a wider spread of data points.

Finally, the third paragraph notes that within μ±3σ, which covers three standard deviations on both sides of the mean, approximately 99.7% of the data falls. This wide range includes nearly all the observations in an ideal Gaussian distribution, indicating a very large spread of data points.

These percentages are approximate and are based on the properties of a perfect or ideal Gaussian distribution. In real-world scenarios, actual distributions may deviate slightly from the ideal shape, but the empirical rule provides a useful guideline for understanding the distribution's behavior.

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