The number of electrons in the outermost shell of the Sodium (Na) atom is (aka valence electrons) (Hint: check the “A” group # on your Periodic Table)
2 points
6
2
1
4

Answer:

NaO2

Explanation:

Solutions are mixtures that are homogenous and comprise solutes and solvents. Methyl alcohol will react with solid sodium chloride to form a solution. Thus, option D is correct.

The solutions are the mixtures of the solute and the solvent. The solute and the solvent are capable of forming a solution only if they both are either polar or nonpolar.

Here, chlorine is a gas, and sodium superoxide is a solid that cannot react with solid sodium chloride to make a solution and hence is eliminated. As sodium chloride is polar it cannot react with nonpolar carbon tetrachloride.

Methyl alcohol is polar and so is sodium chloride. They will react together as,

CH₃OH + NaCl → CH₃Cl + NaOH

Therefore, option D. CH₃OH will react to form a solution.

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Only reactions B and C would be spontaneous at 298 K.

Spontaneous reactions are reactions that occur naturally and do not require external energy input to proceed. This can be determined by calculating the Gibbs free energy of the reaction at a given temperature and pressure. Gibbs free energy can be calculated using the equation ΔG = ΔH - TΔS, where ΔH is the enthalpy change of the reaction, ΔS is the entropy change of the reaction, T is the temperature in Kelvin, and ΔG is the change in free energy of the reaction.
A spontaneous reaction will have a negative ΔG, meaning that the reaction is exergonic and releases energy. Therefore, the products of the reaction are more stable than the reactants. If ΔG is positive, the reaction is endergonic and requires energy input to proceed.
In order to determine which of the following reactions would be spontaneous at 298 K, we must calculate the ΔG of each reaction and determine if it is positive or negative. The reactions are:
A. 2H2O(l) → 2H2(g) + O2(g) ΔH = 484 kJ/mol, ΔS = 69.9 J/K mol
B. CO2(g) + H2(g) → CO(g) + H2O(g) ΔH = 41 kJ/mol, ΔS = -102.6 J/K mol
C. Fe2O3(s) + 2Al(s) → Al2O3(s) + 2Fe(l) ΔH = -850 kJ/mol, ΔS = -243 J/K mol
To calculate ΔG at 298 K, we will use the equation ΔG = ΔH - TΔS. The temperature in Kelvin is 298 K, or 25°C.
A. ΔG = (484,000 J/mol) - (298 K) x (69.9 J/K mol) = +4165 J/mol (positive, non-spontaneous)
B. ΔG = (41,000 J/mol) - (298 K) x (-102.6 J/K mol) = -2874 J/mol (negative, spontaneous)
C. ΔG = (-850,000 J/mol) - (298 K) x (-243 J/K mol) = -42600 J/mol (negative, spontaneous)

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Answer: Insufficient amount of work provided.

Explanation:

Answer:

4.002 mol is in 68.16 grams of NH3

Answer:

Explanation:

The molar mass (MM) of Ca₃(PO₄)₂ can be calculated as follows:

Now we can convert 934.32 g of Ca₃(PO₄)₂ into moles:

The concentration of the solution is obtained as 7.3 * 10^-6 M.

We know that one of the ways by which we are able to obtain the concentration of substances especially those that are colored is by the use of spectrophotometry. In a spectrophotometer, there is a wavelength of maximum absorption that could be used to measure the concentration of the solution as we can see in the question.

By the use of the Beer Lambert's law we have;

A = εcl

A = Absorption

ε = molar absorptivity

c = concentration

l = path length

Thus we would have;

0.2 = 27400 M-1cm-1 * c * 1.00 cm

c = 0.2/27400 M-1cm-1 *  1.00 cm

c = 7.3 * 10^-6 M

We would have from the calculation that we have a solution whose concentration is 7.3 * 10^-6 M.

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The ΔS° value for the reaction KCl(s) → K+(aq) + Cl−(aq) is ΔS° > 0, as the products have a higher degree of disorder than the reactant due to an increase in the number of particles in solution. Hence the correct option is (C) ΔS° > 0.

The ΔS° value for a reaction represents the change in the entropy of the system, which is a measure of the disorder or randomness of the system. The reaction KCl(s) → K+(aq) + Cl−(aq) involves a solid compound breaking down into two separate aqueous ions, which means that the products have a higher degree of disorder than the reactant. This increase in the number of particles in solution results in an increase in entropy, which means that ΔS° > 0. Option (A) is incorrect because the reaction involves a change in state, which results in an increase in entropy. Option (B) is incorrect because it represents the relationship between enthalpy and entropy, not the ΔS° value for this particular reaction. Option (D) is incorrect because the reaction results in an increase in entropy, not a decrease. Option (E) is incorrect because the given information is sufficient to predict the sign of ΔS°.

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In Zeff periodicity of valence electrons, the change from aluminum (Al) to silicon (Si) involves an increase in the effective nuclear charge (Zeff) and a change in the valence electron configuration.

Effective nuclear charge (Zeff) refers to the net positive charge experienced by the valence electrons in an atom.

As one moves across a period in the periodic table from left to right, the atomic number increases, resulting in a higher Zeff.

Aluminum (Al) has an atomic number of 13 and has three valence electrons in the 3s and 3p orbitals. The Zeff experienced by these valence electrons is relatively low due to the shielding effect of the filled inner electron shells.

On the other hand, silicon (Si) has an atomic number of 14 and it has four valence electrons in the 3s and 3p orbitals. As we move from aluminum to silicon, the number of protons in the nucleus increases by one, resulting in a higher effective nuclear charge (Zeff).

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Answer:

cool

Explanation:

The final concentration of the chloride ions is  0.32 M.

We know that we have to obtain the number of moles of the iron II chloride that was reacted in the solution and then we would have;

Number of moles of iron II chloride = 4.08g /127 g/mol = 0.032 moles

Given the fact that there are two chloride ions hence the amount of the chloride ions is 0.016 moles

The concentration of the silver nitrate = 50/1000  *  0.60 M

= 0.03 moles

Thus we would have a final concentration of 0.016 moles/ 0.05

= 0.32 M

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1. The IUPAC name of N is nitrogen.

2. Nitrogen dioxide

3.The IUPAC name of O is oxygen

4.The IUPAC name of OH is hydroxyl.

The IUPAC name of ·0 is a radical. It is commonly found in organic chemistry and plays an important role in many reactions.

IUPAC names for the given compounds are:1.1. N: Nitrogen

The IUPAC name of N is nitrogen.

It is a non-metal and belongs to group 15 in the periodic table. It has an electronic configuration of 1s2 2s2 2p3.1.2. NO2: Nitrogen dioxide

Explanation: NO2 is a chemical compound that is formed by the combination of nitrogen and oxygen. It is a reddish-brown gas that has a pungent odor.

The IUPAC name of NO2 is nitrogen dioxide.1.3. O: Oxygen

Explanation: The IUPAC name of O is oxygen.

It is a non-metal and belongs to group 16 in the periodic table. It has an electronic configuration of 1s2 2s2 2p4.

X: UnknownExplanation: No IUPAC name can be given to an unknown compound as the structure and composition are not known.

Y: Hydroxyl Explanation: The IUPAC name of OH is hydroxyl.

It is a functional group that is composed of an oxygen atom and a hydrogen atom (-OH). It is commonly found in alcohols and phenols. ·0: RadicalExplanation: A radical is a molecule or an ion that contains an unpaired electron.

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Note: The complete question is given below

Provide the IUPAC names for the following compounds:

\(CH_3CH_2CH(CH_3)CH_2CH_2CH_2CH_3\)

C6H5CH(CH3)2

H2NCH2CH2CH2CH2CH2NH2

CH3CH2CH2CH2CH2OH

CH3CH2CH2CHOHCH3

Answer:

https://www.quora.com/What-is-the-difference-between-HNO3-and-H2SO4

Explanation:

HNO3 is a protic acid and H2SO4 is a diprotic acid, this means that while HNO3 donates a single H+ H2SO4 donates 2 H+ ions.

HNO3 is highly volatile as compared to H2SO4.

The components are different, the molecular weights and melting point and boiling points are different.

H2SO4 is dubbed the king of acids because it has a variety of reactions, while HNO3 has quite a few reactions it is not comparable to H2SO4’s

Refer to the figure showing the structure of methyl acetate. why this compound can form hydrogen bonds with water but not with itself because This compound lacks a hydrogen atom in a highly polar bond.

Methyl acetate, also known as MeOAc, acetic acid methyl ester or methyl ethanoate, is a carboxylate ester with the formula CH3COOCH3. It is a flammable liquid with a characteristically pleasant smell reminiscent of some glues and nail polish removers. Methyl acetate is occasionally used as a solvent, being weakly polar and lipophilic, but its close relative ethyl acetate is a more common solvent being less toxic and less soluble in water. Methyl acetate has a solubility of 25% in water at room temperature. At elevated temperature its solubility in water is much higher. Methyl acetate is not stable in the presence of strong aqueous bases or aqueous acids. Methyl acetate is not considered a VOC in the USA.

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Answer:

two of the above

Explanation:

cK-12 Bond Polarity

Answer:

40/220 ×100=18.6 is all I got I know that by heart so um yea

Explanation:

Answer:

Radiation is energy that comes from a source and travels through space at the speed of light.

Explanation:

Radiation is energy that comes from a source and travels through space at the speed of light. This energy has an electric field and a magnetic field associated with it and has wave-like properties. You could also call radiation “electromagnetic waves”

Hope this helps :)

Empirical formula of Carbon dioxide :

The correct answer based on relative electronegativity would be:

Br > P > C > Mg

What is Electronegativity?

Electronegativity is a measure of an element's tendency to attract a bonding pair of electrons towards itself when it forms a chemical bond with another element. It is a property of elements that reflects their ability to attract and hold onto electrons in a chemical bond.

Electronegativity is a measure of an element's tendency to attract a bonding pair of electrons. In general, electronegativity increases from left to right across a period in the periodic table and decreases from top to bottom within a group. Therefore, Bromine (Br) would have the highest electronegativity among the given options, followed by Phosphorus (P), Carbon (C), and Magnesium (Mg) with the lowest electronegativity.

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Answer:

The empirical formula of the compound is C2H5O.

OTs is a functional group formed by losing hydrogen of p-toluene sulphonic acid. This is a good leaving group, because of the presence of a stable resonance structure.

Here when CH3-CH2-CH2-CH2-OTs reacts with NaBr, a substitution reaction happens. The OTs group is substituted by Br and tosylate is released. DMF or dimethyl formamide used as solvent in such reactions. The main reaction of substitution of bromine to tosylate group is that the conjugate base is quite stable because of the three resonance structures.

Alcohols usually are not prone to substitution reactions. So it is converted to a tosyl or mesyl substitute, so that it is easier to convert it into an alkyl halide. The main benefit of such reactions is that it can be carried out without drastic pH conditions.

So, tosylate acts as a good leaving group in halide substitution reactions.

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The calculated formula masses to 133.5 amu, we find that the substance with a formula mass closest to 133.5 amu is (d) AlCl3. Therefore, the answer is option D.

To identify the substance with a formula mass of 133.5 amu, we need to calculate the formula mass of each given substance and compare it to 133.5 amu.

(a) MgCl2:

The formula mass of MgCl2 can be calculated by adding the atomic masses of magnesium (Mg) and chlorine (Cl).

Mg: atomic mass = 24.31 amu

Cl: atomic mass = 35.45 amu

Formula mass of MgCl2 = (24.31 amu) + 2(35.45 amu) = 95.21 amu

(b) SCl:

The formula mass of SCl can be calculated by adding the atomic masses of sulfur (S) and chlorine (Cl).

S: atomic mass = 32.07 amu

Cl: atomic mass = 35.45 amu

Formula mass of SCl = 32.07 amu + 35.45 amu = 67.52 amu

(c) BCl:

The formula mass of BCl can be calculated by adding the atomic mass of boron (B) and chlorine (Cl).

B: atomic mass = 10.81 amu

Cl: atomic mass = 35.45 amu

Formula mass of BCl = 10.81 amu + 35.45 amu = 46.26 amu

(d) AlCl3:

The formula mass of AlCl3 can be calculated by adding the atomic mass of aluminum (Al) and 3 times the atomic mass of chlorine (Cl).

Al: atomic mass = 26.98 amu

Cl: atomic mass = 35.45 amu

Formula mass of AlCl3 = 26.98 amu + 3(35.45 amu) = 133.78 amu. Option D

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Answer:

Idon't know if this helps but I think it is a linear structure and if I am wrong I am so sorry

Answer:

We need more? What else is in the question? This is unanswerable.

Explanation:

Answer:

He proposed a model of the atom that consisted of a positively charged sphere with negatively charged electrons embedded in it. This model was later called the plum pudding model. Thomson’s discovery of the electron showed that atoms were not indivisible, as previously thought, but composed of smaller subatomic particles. His model also explained some phenomena such as cathode rays and electric currents. Thomson’s work helped advance our understanding of the structure and nature of the atom.

Explanation:

Answer:

Explanation:

a) The mass of the reactants is 2.36 grams, and the mass of the products is 1.57 grams plus the mass of the carbonic acid. Thus, using the law of conservation of mass, we get the mass of the carbonic acid is 2.36 - 1.57 =  0.79 grams.

b) The gram-formula mass of sodium bicarbonate is 84.006 g/mol, meaning that 2.36/84.006 = 0.028 moles were consumed. Thus, this means that in theory, 0.014 moles of carbonic acid should have been produced, which would have a mass of (0.014)(62.024)=0.868 grams. Thus, the percentage yield is (0.79)/(0.868) * 100 = 91%

Answer: The concentration for pH is 4 but, for pOH it is 10.

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The equation for the equilibrium constant (K) of the reaction studied in this exercise can be written as follows: K = ([\(CI_20\), 2-] * [\(H_20\)(1)]) / ([\(C0_4^ 2\)-] * [Ht])

In this equation, the concentrations of the species involved in the reaction are represented by the square brackets [ ]. The subscripts indicate the stoichiometric coefficients of each species in the balanced chemical equation.

The reaction being studied involves the following species:

\(C0_4^ 2\)- (ag) + 2Ht (ag) = \(CI_20\), 2- (ag) + \(H_20\)(1)

In the equilibrium constant expression, the concentration of \(CI_20\), 2- is multiplied by the concentration of \(H_20\)(1) and divided by the product of the concentrations of \(C0_4^ 2\)- and Ht. The stoichiometric coefficients in the balanced equation are used as exponents for the concentrations of the respective species.

It is important to note that the concentrations used in the equilibrium constant expression should be in molar units (mol/L) or expressed as partial pressures for gases.

Additionally, the equilibrium constant is specific to a given temperature, and its value provides information about the relative amounts of reactants and products at equilibrium.

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The concentration of the new potassium permanganate, KMnO solution is 0.06 M.

To find the concentration of the new solution, we can use the formula,

C₁V₁ = C₂V₂,

C₁ = 0.75,

V₁ = 20.0 mL,

V₂ = 250.0mL

C₂ is what we have to find. Plugging in the values we know, we get,

0.75 M x 20.0 mL = C₂ x 250.00 mL

Solving for C₂, we get the final concentration of the potassium permanganate.

C₂ = (0.75 M x 20.0 mL) / 250.00 mL

C₂ = 0.06 M

Therefore, the concentration of the solution has changed to 0.06 M from 0.75M.

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Answer: The value of the equilibrium constant for this reaction is \(2.8\times 10^{-5}\)

Explanation:

To calculate the moles, we use the equation:

\(\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}\)

Moles of  \(Ni(CO)_4\) = \(\frac{0.597g}{170.7g/mol}=0.0035moles\)

Moles of  \(Ni\) =  \(\frac{12.7g}{58.7g/mol}=0.216moles\)

Moles of  \(CO\) =  \(\frac{1.98g}{28.01g/mol}=0.071moles\)

Volume of solution = 2.7 L

Equilibrium concentration of \(Ni(CO)_4\) = \(\frac{0.0035mol}{2.7L}=1.29\times 10^{-3}M\)

Equilibrium concentration of \(Ni\) = \(\frac{0.216mol}{2.7L}=0.08M\)

Equilibrium concentration of \(CO\) = \(\frac{0.071mol}{2.7L}=0.026M\)

The given balanced equilibrium reaction is,

                            \(Ni(CO)_4\rightleftharpoons Ni+4CO\)

The expression for equilibrium constant for this reaction will be,

\(K_c=\frac{[Ni]^1\times [CO]^4}{[Ni(CO_4]^1}\)

Now put all the given values in this expression, we get :

\(K_c=\frac{(0.08)^1\times (0.026)^4}{(1.29\times 10^{-3})^1}\)

\(K_c=2.8\times 10^{-5}\)

Thus the value of the equilibrium constant for this reaction is \(2.8\times 10^{-5}\)