the observed rotation of a solution of 1.2 g of a compound in 10 ml of water is 1.3 degrees. if the pathlength is 10 cm, what is the specific rotation of the compound?

Answer:

A chemical reaction occurs when a substance is rearranged to form a new substance. It is possible to identify if this has taken place from one of the five signs of chemical change. These changes include color change, temperature change, precipitate formation, gas production and light emission.

Explanation:

hope it helps :))

Answer:

A chemical reaction occurs when a substance is rearranged to form a new substance. It is possible to identify if this has taken place from one of the five signs of chemical change. These changes include color change, temperature change, precipitate formation, gas production and light emission.

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Answer:

Molar mass is 325.33

Explanation:

Molar mass is 325.33

Answer:

A.

Explanation:

the gradual movement of the continents across the earth's surface through geological time.

Answer:

a

Explanation:

Based on the given information, the true statement about the time indicated by the blue arrow is: (c) The rate of the forward reaction (N₂O₄ formation) is equal to the rate of the reverse reaction (NO₂ formation).

The graph shows the relative amounts of NO₂ and N₂O₄ over time, and the point indicated by the blue arrow represents a state of equilibrium. In an equilibrium state, the forward and reverse reactions occur at equal rates.

The concentrations of NO₂ and N₂O₄ reach a constant value, indicating that the conversion of NO₂ to N₂O₄ and the conversion of N₂O₄ to NO₂ are occurring at the same rate.

Option a suggests that NO₂ molecules are no longer reacting, which is incorrect as the reaction is still ongoing at equilibrium. Option b suggests that the reactant has been completely used up, which is not the case in an equilibrium state. Option d refers to the activation energy, which is unrelated to the equilibrium state. Therefore, option c is the correct choice.

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The amount of heat needed to raise the temperature of 355 g of ethanol by 63°C is 53,568 joules (J).

To calculate the amount of heat required to raise the temperature of a substance, we can use the formula:

q = m × c × ΔT

Where:

q = heat energy (in joules)

m = mass of the substance (in grams)

c = specific heat capacity of the substance (in J/g°C)

ΔT = change in temperature (in °C)

Given:

Mass of ethanol (m) = 355 g

Specific heat capacity of ethanol (c) = 2.4 J/g°C

Change in temperature (ΔT) = 63°C

Using the formula, we can calculate the heat energy (q):

q = 355 g × 2.4 J/g°C × 63°C

q = 53568 J

Therefore, the amount of heat needed to raise the temperature of 355 g of ethanol by 63°C is 53,568 joules (J).

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Answer:

a

Explanation:

salt and energy can cause reactions to produce electricity

Answer: The answer is A

Explanation:  An electrolyte solution has the ability to conduct electricity because when a salt dissolves, its dissociated ions can move freely in solution, allowing a charge to flow. Electrolyte solutions are normally formed when a salt is placed into a solvent such as water. (Google  Source If needed)

Answer:

E

Explanation:

A combination reaction is one in which two elements or two compounds react to give a new single compound

Hence, what we are expecting on the reactant side is only a single product and not a mixture of products

For the first reaction, we had two elements giving a single product

For the second reaction, we had same

For the third, we had same

For the fourth, we had two compounds reacting to give a singe new product

While in the last, we had two different products which means it does not follow the definition of a combination reaction and that makes it our answer

Answer:

V = 5.74 L

Explanation:

Given data:

Volume of carbon dioxide produced = ?

Temperature and pressure = standard

Mass of calcium carbonate = 25.6 g

Solution:

Chemical equation:

CaCO₃      →        CaO + CO₂

Number of moles of calcium carbonate:

Number of moles = mass / molar mass

Molar mass of calcium carbonate = 100 g/mol

Number of moles = 25.6 g/ 100 g/mol

Number of moles = 0.256 mol

Now we will compare the mole of calcium carbonate with carbon dioxide.

                       CaCO₃           :            CO₂

                            1                :             1

                         0.256          :         0.256

Volume of  CO₂:

PV = nRT

R = general gas constant = 0.0821 atm/L / mol.K

By putting values,

1 atm× V = 0.256 mol × 0.0821 atm/L / mol.K× 273.15 K

V = 5.74 atm/L / 1 atm

V = 5.74 L

1) The intermolecular forces   for \(Br_{2}\) is Dispersion forces

2) The intermolecular forces   for  HCl - Hydrogen bonding

3) The intermolecular forces   for \(H_{2} O\)- Hydrogen bonding

4) The intermolecular forces   for He - Dispersion forces

5) The intermolecular forces   for \(CH_{3} Cl\) -  Dipole-dipole

The term  intermolecular forces has to do with the forces that holds the molecules of a substance together. These are the kind of forces that determine the physical properties of the substance that is under consideration.

We know that the helium molecules and the bromine molecules are both held together by the dispersion forces alone. All the other substances have a mixture of other kinds of forces in them.

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electronic configuration of Ge is 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p2. Thus, the orbital diagram of Ge is: G2 G1 | G2 | G3 G3 G3 G3 4 11 1

Ne:

The electronic configuration of Ne is 1s2 2s2 2p6. Thus, the orbital diagram of Ne is:

G2 G1 | G2 | G3 G3 G3 G3

I:

The electronic configuration of I is 1s2 2s2 2p6 3s2 3p6. Thus, the orbital diagram of I is:

G2 G1 | G2 | G3 G3 G3 G3 5

Sr:

The electronic configuration of Sr is 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6. Thus, the orbital diagram of Sr is:

G2 G1 | G2 | G3 G3 G3 G3 11

Ge:

The electronic configuration of Ge is 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p2. Thus, the orbital diagram of Ge is:

G2 G1 | G2 | G3 G3 G3 G3 4 11 1

Br:

The electronic configuration of Br is 1s2 2s2 2p6 3

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Heat required = Q = 40 kcal

Given

mass of 500 g ice

Required

Heat required

Solution

The heat to change the phase can be formulated :  

Lf=latent heat of fusion  

Lv=latent heat of vaporization  

Lf for water = 334 kj/kg=6.01 kJ/mol = 80 cal/g

Phase change(ice to water)

Q=  500 g x 80 cal/g

Q = 40 kcal

2.67 × 10^19

Explaination:

The volume of the gas is 1c.c = 10^ - 3L

∴ Number of moles of the gas is=22.4 × 10^-3

Now,

Number of molecules = n × 6.022 × 10^23

∴ Number of Nitrogen Molecules

= 10^-3/22.4 × 6.023 × 10^23

  = 2.67 × 10^19

Answer:

6.02 x 10²⁰ molecules

Explanation:

Given parameters:

Volume of nitrogen  = 120cm³

Unknown:

Mass of Nitrogen = ?

Number of molecules present in it = ?

Solution:

At STP;

       1 mole of a substance contains 22.4dm³ particles

      100cm³ = 1dm³

     24cm³ will give 0.024dm³

        22.4dm³ of particles are in 1 mole of substances at STP

         0.024dm³ of particles will contain  \(\frac{0.024}{24}\)   = 0.001mole

Mass of Nitrogen  = Number of moles x molar mass

  molar mass of nitrogen  = 14g/mol

   Mass of nitrogen  = 0.001 x 14  = 0.014g

Number of molecules present;

      1 mole of a substance contains 6.02 x 10²³ molecules

     0.001 mole of Nitrogen will contain 0.001  x  6.02 x 10²³ = 6.02 x 10²⁰

         6.02 x 10²⁰ molecules

Answer:

14cm

Explanation:

s x s=area

s²=200cm²

s=14.1421356237cm

s=14cm

Answer:

the correct answer is C.

Explanation:

Zn3(PO4)2 is the chemical formula for Zinc phosphate.

The chemical formula for zinc (II) phosphate is Zn₃(PO₄)₂. Therefore, option C is correct.

Zinc (II) phosphate is an inorganic compound. It is composed of zinc cations (Zn²⁺) and phosphate anions (PO₄³⁻). The Roman numeral "II" in the compound name indicates that the oxidation state of the zinc ion is +2.

Zinc (II) phosphate is a white crystalline solid that is insoluble in water. It is commonly used in various applications, including as a corrosion inhibitor in coatings and paints, as a component in dental cement, and as a nutrient supplement in some fertilizers.

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The binding of the amino acid in aminoacyl-tRNA involves the formation of an ester bond.  Option b

Aminoacyl-tRNA is a complex molecule that plays a crucial role in protein synthesis. It consists of a tRNA molecule covalently linked to an amino acid. The amino acid is attached to the 3' end of the tRNA molecule through an ester bond.

An ester bond is formed between the carboxyl group (-COOH) of the amino acid and the hydroxyl group (-OH) of the ribose sugar at the 3' end of the tRNA molecule. This ester bond is also referred to as an ester linkage. The formation of the ester bond is catalyzed by the enzyme aminoacyl-tRNA synthetase.

The ester bond in aminoacyl-tRNA is essential for protein synthesis. During translation, the aminoacyl-tRNA molecule carries the specific amino acid to the ribosome, where it is incorporated into the growing polypeptide chain. The ester bond is later hydrolyzed, releasing the amino acid for further use in protein synthesis.

In summary, the binding of the amino acid in aminoacyl-tRNA involves the formation of an ester bond between the carboxyl group of the amino acid and the hydroxyl group of the ribose sugar in the tRNA molecule.

Option b

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The cation formed when a sodium atom loses an electron is called the sodium ion, which is represented by the symbol Na+.

This ion is commonly found in many chemical compounds and is important for various biological processes. When sodium atoms react with nonmetals, such as halogens, they form ionic compounds called sodium halides.

The loss of an electron by sodium creates a positively charged ion, which is attracted to negatively charged ions or molecules.

This attraction forms strong ionic bonds that hold the compound together. The correct answer to the given question is option d.

It is important to note that the terms "sodate ion", "sodide ion", and "soda ion" are not used to describe the cation formed by the loss of an electron from a sodium atom.

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Answer:

andariamos flotando

Explanation:

Answer:

271

Explanation:

1+10+15+20+25+30+35+40=45+50=

By following serial dilution method, you can achieve the desired concentrations using small volumes while ensuring accurate dilution ratios. It is essential to handle the small volumes carefully and accurately to maintain the desired concentrations throughout the dilution process.

To perform a serial dilution with small volumes, such as in this case where measuring less than 1µL is not possible, we can use a stepwise dilution approach.

Start with the initial concentration of 14.2mM in 1mL of stock media.

To prepare the first dilution of 10µM, transfer 1µL from the stock solution and add it to 99µL of a diluent (such as water or buffer). This results in a 100µL solution with a concentration of 10µM.

For subsequent dilutions, repeat the same process. Take 1µL from the previous dilution and add it to 99µL of diluent.

Repeat step 3 for each desired concentration. For example, to obtain a concentration of 5µM, take 1µL from the 10µM solution and add it to 99µL of diluent.

Continue this stepwise dilution process until you reach the final desired concentrations: 2.5µM, 1µM, 750nM, 500nM, 250nM, 100nM, 50nM, and 10nM.

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Answer:

K2S2O8

Explanation:

The method is attached above.

Answer:

174 kPa

Explanation:

Given that,

Initial temperature, T₁ = 25° C = 25+273 = 298 K

Final temperature, T₂ = 225°C = 225 + 273 = 498 K

Initial pressure, P₁ = 104 kPa

We need to find the new pressure. The relation between the temperature and pressure is given by :

\(\dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}\)

So,

\(P_2=\dfrac{P_1T_2}{T_1}\\\\P_2=\dfrac{104\times 498}{298}\\\\P_2=173.79\ kPa\)

or

P₂ = 174 kPa

So, the new pressure is 174 kPa.

The mass of methane is required to produce 1.130 kg of carbon dioxide during combustion is 0.40 kg.

The balanced equation is given as :

CH₄   +   2O₂   ----->   CO₂  +  2H₂O

mass of carbon dioxide = 1.130 kg = 1130 g

moles of carbon dioxide = mass / molar mass

                                         = 1130 / 44

                                         = 25.6 mol

1 mole of carbon dioxide produce by 1 mole of methane

moles of methane = moles of carbon dioxide

mass of CH₄ = moles × molar mass

                     = 25.6 × 16

                    = 409.6 g = 0.40 kg

Thus, The mass of methane is required to produce 1.130 kg of carbon dioxide during combustion is 0.40 kg.

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Answer:

1.4 L.

Explanation:

Applying Charles law,

V/T = V'/T'....................... Equation 1

Where V = Initial volume, V' = Final volume, T = Initial Temperature in Kelvin, T' = Final Temperature in Kelvin.

Make V' the subject of the equation

V' = (V/T)T'..................... Euqation 2

Given: V = 1.5 L, T = 295 K, T' = 2 °C = (2+273) K = 275 K

Substitute these values into equation 2

V' = (1.5/295)275

V' = 1.398

V' ≈ 1.4 L

Answer:

(B) SECONDARY ALKYL HALIDE

Answer:

2.18 × 10³L

Explanation:

2178 litres of CO2 is produced in the combustion reaction.

HOW TO CALCULATE VOLUME

Density = mass ÷ volume

no of moles. = 5.9 × 10²⁵ ÷ 6.02 × 10²³

no. of moles = 5.9/6.02 × 10²

no. of moles = 0.98 × 10²moles

= 98moles

Moles = mass ÷ molar mass

Mass of CO2 = moles × molar mass

Molar mass of CO2 = 12 + 16(2) = 44g/mol

Mass of CO2 = 98 × 44

Mass of CO2 = 4312g = 4.312kg

Volume = 4.312kg ÷ 1.98kg/m³

Volume = 2.178m³

Since 1m³ = 1000L

2.178m³ = 2.178 × 1000

= 2178 liters.

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Answer:

the mass number

Explanation:

Isotopes are numerous forms of one single element. In simple terms, atomic weights are different for the isotopes. Isotopes refer to the atoms that have the same number of protons but different neutron numbers. The physical properties of the isotopes vary because these properties also based on mass. These variations can be used to distinguish isotopes of an element from each other by applying methods such as fractional distillation and diffusion.

Answer:

The mass number  (D) would be correct.

Explanation:

Get ready, you should catch it.

Answer:

As an object falls, its gravitational potential energy decreases as its speed—and therefore its kinetic energy—increases.

Explanation:

Study Island

The final pressure in the heated can is 2.51 atm

From the question given above, the following data were obtained:

Initial temperature (T₁) = 25 °C = 25 + 273 = 298 K

Initial pressure (P₁) = 1 atm

Final temperature (T₂) = 475 °C = 475 + 273 = 748 K

The final pressure can be obtained as illustrated below:

\( \frac{P_1}{T_1} = \frac{P_2}{T_2} \\ \\ \frac{1}{298} = \frac{P_2}{748} \\ \\ cross \: multiply \\ \\ 298 \times P_2 = 1 \times 748 \\ \\ divide \: both \: side \: by \: 298 \\ \\ P_2 = \frac{748}{298} \\ \\ P_2 = 2.51 \: atm\)

Therefore, the final pressure in the heated can is 2.51 atm

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An sample of coal is assayed for its sulfur content. If a 5.57 g sample of coal contains 0.028 g of sulfur. The percent sulfur in the ore is 0.5023%.

To calculate the percentage of sulfur in the coal sample, we need to divide the mass of sulfur by the mass of the coal sample and multiply by 100 to get the result as a percentage.

Mass of sulfur = 0.028 g

Mass of coal sample = 5.57 g

Percent sulfur = (mass of sulfur / mass of coal sample) x 100

Percent sulfur = (0.028 g / 5.57 g) x 100

Percent sulfur = 0.502 % (rounded to three significant figures)

Therefore, the percent sulfur in the coal sample is 0.5023 %.

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Bar graph is the best type of graph to use if you are trying to compare quantities for four separate options that are not related to the dependent or independent variables and that are not measured over time.

Bar graphs are the type of graph that can be used when the data measurement between different variable are not continuous or not measured over time.

The advantages of bar graphs include the following:

Therefore, Bar graph is the best type of graph to use if you are trying to compare quantities for four separate options that are not related to the dependent or independent variables and that are not measured over time.

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