Answer:
it does show the objects position
Two balls of equal mass collide and stick together as shown in the figure. The initial velocity of ball B is twice that of ball A. a. Calculate the angle above the horizontal of the motion of mass A + B after the collision. b. What is the ratio of the final velocity of the mass A + B to the initial velocity of ball A, /? c. What is the ratio of the final energy of the system to the initial energy of the system, /? Is the collision elastic or inelastic?
The angle above the horizontal of the motion of mass A + B after the collision. as well as others are mathematically given as
\(\theta f = 26.3 \deg\)vf/vA= 0.942vf^2 / 5vA^2 = 0.35What is Collison equilibrium?
According to the collision hypothesis of chemistry, chemical reactions happen when two molecules or atoms collide.
Generally, the equation for Collison equilibrium is mathematically given as
For horizontal motion
mvAx+m2vAx = 2mvfx
For vertical motion
-mvAy+m2vAy = 2mvfy
vfy = 1/2 vAy
\(\tan \theta f = vfy/vfx \\\\\tan \theta f = 1/3 vAy/vAx \\\\\tan \theta f = vAy/vAx \\\\\theta f = tan-1 ( 1/3 tan (56) )\\\\\)
\(\theta f = 26.3 \deg\)
(b)
\(v fy = vf sin \theta f\\\\vAy = vA sin theta i\\\\vf/vA = vfy/vAy sin( \theta i)/sin(\theta f)\\\\vf/vA = 1/2 sin(56)/sin(26.3) \\\\\)
vf/vA= 0.94
(c)
\(Ef/Ei = \frac{(1/2 * (2m) * (vf)^2) }{ (1/2 * m * (vA)^2) + 1/2*m*(2vA)^2) ]}\)
2vf^2 / 5vA^2 = 0.35
In conclusion, The angle above the horizontal of the motion of mass A + B after the collision. as well as others
\(\theta f = 26.3 \deg\)
vf/vA= 0.94
2vf^2 / 5vA^2 = 0.35
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an object is thrown straight up. which of the following is true abought the sign of workdone by the force of gravity on the object, while the object moves up and then down
Answer:
Upward: Negative
Downward: Positve
Explanation:
Let upward be positive
We want to find the work done on the object upwards.
The equation of work done due to gravity is
\(f _{g}d \cos( \alpha ) \)
It is read as force of gravity times displacement times cos of the angle between the force and displacement.
Since gravity is happening down of the center of mass and the displacement is upwards, the angle is 180° so
\(f_{g}d \cos(180) \)
Cosine of 180 is -1
so
\( - f_{g}d \)
If we go downwards, the sign will be positive because cos(0)=1
Select the correct answer.
What is the basic unit of all matter?
O A neutron
OB. atom
OC. electron
OD. proton
OE nucleus
\(\large\mathcal{QUESTION:}\)
What is the basic unit of all matter?\(\large\mathcal{CHOICES:}\)
OA neutronOB. atomOC. electronOD. protonOE. nucleus\(\large\mathcal{ANSWER:}\)
B. Atom_____
Atom is the smallest, indivisible unit of a chemical element and the fundamental unit of matter. It consists of a nucleus (neutrons + protons) surrounded by an electron cloud. The atom is the smallest unit of matter that cannot be divided chemically and is a building block with its own set of properties.#ProvideUniqueAnswersAnswer:
A Atom
Explanation:
If the 100 g mass is replaced by a 200 g mass, which variables in Tnet = la change, and which
remains constant? Justify your answer.
The moment of inertia (I) will changes and net torque (Tnet) will also change, while the angular acceleration (a) remains constant.
What is the changed variable in the equation?The formula for net torque acting on an object is given as;
T(net) = Ia
where;
a is the angular accelerationI is the moment of inertiaT(net) is the net torqueThe moment of inertia of an object is given as;
I ∝ MR²
where;
M is the massR is the radius of the objectSo mass, M changes, the moment of inertia (I) changes and net torque will also change, while the angular acceleration remains constant.
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Waves can travel but the medium does not "travel" with it, even though they may move up and down.
False
True
Answer:
TRUE
Explanation:
The statement "Waves can travel but the medium does not "travel" with it, even though they may move up and down." is a true statement
Option A is correct
What are Waves?A wave is simply defined as a disturbance in a medium that carries energy from point to point and can take the form of elastic deformation, a change in pressure, magnetic strength, electric potential, or temperature.
In conclusion, Mediums are the pathways or channel for travelling waves
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The efficiency of the power station is 0.38(38%). Its electrical power output is 1.9x10^9 W. Calculate the input to the power station
The input to the power station is 5x10^9 W. This means that the power station requires an input of 5x10^9 watts to produce an electrical power output of 1.9x10^9 watts with an efficiency of 38%.
The efficiency of a power station is defined as the ratio of its output power to input power. Therefore, we can use the efficiency and the electrical power output of the power station to calculate its input power as follows:
Efficiency = Output power / Input power
Solving for input power, we get:
Input power = Output power / Efficiency
Substituting the given values, we get:
Input power = 1.9x10^9 W / 0.38
Input power = 5x10^9 W (to two significant figures)
The rest of the input power is lost as heat due to inefficiencies in the power generation process.
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How do the interactions between the two atoms change when the atoms get closer than the balanced point?
Answer:
The strong attraction of each shared electron to both nuclei stabilizes the system, and the potential energy decreases as the bond distance decreases. If the atoms continue to approach each other, the positive charges in the two nuclei begin to repel each other, and the potential energy increases.
The interaction that lies between two atoms change should be considered as the stabilizes the system.
Reason for two atoms change:Since there is a strong attraction for every shared electron for both nuclei stabilizes the system and potential energy should be reduced due to this, the bond distance should be reduced.
In the case when the atom should continue to approach each other so here the positive charges in the two nuclei started to repel each other.
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1) How much work is done when a force of 50N
pulls a wagon 20 meters?
Answer:
100J
Explanation:
50N*20m=100J
N*m=J(joule)
1) Marty (m = 8 kg) is sitting still in a small fishing boat (40 kg) when he decides to go for a swim. Marty
jumps off of the boat, which causes the boat to have a velocity of 1 m/s. What is the velocity of Marty's
jump?
Answer:
the velocity of the Marty's Jump is 5 m/s.
Explanation:
Given;
mass of Marty, m₁ = 8 kg
mass of the boat, m₂ = 40 kg
velocity of the boat, u₂ = 1 m/s
Let the velocity of the Marty's Jump = u₁
Apply the principle of conservation of momentum;
m₁u₁ = m₂u₂
u₁ = m₂u₂/m₁
u₁ = (40 x 1) / (8)
u₁ = 5 m/s.
Therefore, the velocity of the Marty's Jump is 5 m/s.
calculate how much heat is released when 500g of platinum is cooled from 250.0K to 240.0K
Answer:
Q = 665 J
Explanation:
Given:
m = 500 g = 0.5 kg
T₁ = 250.0 K
T₂ = 240.0 K
c = 133 J / ( kg*⁰K) - Specific heat capacity of platinum
___________
Q - ?
Heat is released:
Q = c*m*( T₁ - T₂) = 133*0.5*(250.0 - 240.0) =
= 133*0.5*10 ≈ 665 J
If sound waves travel at 350 m/s on a warm humid day. And you are submerged underwater. Is the sound you hear while below the surface traveling faster, slower or at the same rate as the sound you hear above the water? Explain your answer
ANSWER:
Sound waves are faster in water
STEP-BY-STEP EXPLANATION:
Sound travels differently in water than it does in air.
Sound waves travel faster in denser substances because neighboring particles will more easily collide with each other.
Water is denser than air, which means that sound waves travel much faster in water than in air.
Although they travel faster in water, we must keep in mind that the human ear evolved to hear sounds in the air and is not as useful when submerged in water.
Thomas the Train chugs along at 2 m/s. Thomas needs to go faster so more coal is shoveled into his engine and he accelerates for 10 seconds until he is going 4.33 m/s. What is Thomas' acceleration?
The acceleration of Thomas is 0.233 m/s^2.
Acceleration is the rate of change of velocity. Thomas the Train chugs along at a velocity of 2 m/s.
Thomas needs to go faster so more coal is shoveled into his engine and he accelerates for 10 seconds until he is going 4.33 m/s.
We are to find the acceleration of Thomas.
The formula for acceleration is given as :
acceleration = (final velocity - initial velocity) / time
In the given problem, the initial velocity of Thomas, u = 2 m/s.
The final velocity of Thomas, v = 4.33 m/s The time for which Thomas accelerates, t = 10 s.
Therefore, the acceleration of Thomas will be given as:
a = (v - u) / ta = (4.33 - 2) / 10s => 2.33 / 10s => 0.233 m/s^2
Thus, the acceleration of Thomas is 0.233 m/s^2.
To summarize, the acceleration of Thomas is 0.233 m/s^2.
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what's the definition energy?
Why must humans limit their exposure to X-rays and gamma rays?
A. The rays can change molecules and atoms in the body into ions.
B. Exposure can cause the human body to give off heat.
O C. Even a small amount of radiation can burn the skin.
D. These rays act similarly to microwaves on the human body.
Answer:
A. The rays can change molecules and atoms in the body into ions.
If the thrust was cut in half, what would the new acceleration of the space shuttle be? SHOW
WORK
If the thrust was cut in half, the new acceleration of the spare shuttle would be half of its original acceleration.
How to calculate the new acceleration of the space shuttle?Assuming that the mass of the space shuttle remains constant, the new acceleration of the space shuttle would be half of its original acceleration.
The formula for acceleration is:
a = F/m
where,
a = acceleration
F = force applied
m = mass of the object
If the force is cut in half, the new acceleration can be calculated as follows:
a' = (F/2)/m
where,
a' = new acceleration
Simplifying this equation, we get:
a' = F/2m
Since we know that a = F/m, we can substitute this expression into the equation above to obtain:
a' = a/2
So, the new acceleration of the space shuttle would be half of its original acceleration.
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Kiran drove from Tortula to Cactus, a distance of 250 mi. She increased her speed by 10 mi/h for the 360-mi trip from Cactus to Dry Junction. If the total trip took 11 h, what was her speed from Tortula to Cactus
Kiran's average speed from Tortula to Cactus was 58.78 miles per hour.
Let's use "x" miles per hour as Kiran's speed from Tortula to Cactus.
The time it takes Kiran to traverse the 250 miles between Tortula and Cactus is calculated as follows: time = distance / speed time = 250 / x
We also know that she upped her speed by 10 miles per hour throughout the 360-mile distance from Cactus to Dry Junction.
For that portion of the journey, let's designate her new speed "x+10" mi/h.
Her trip time is calculated as follows: time = distance / speed
time = 360 / (x+10)
Given that the entire journey lasted 11 hours, we can construct the following equation:
Time from Dry Junction to Cactus plus the time from Cactus to Tortula equals 11
250/x + 360/(x+10) = 11
We can now determine x:
250(x+10) + 360x = 11x(x+10)
0 - 400 - 2500 = 250x + 2500 + 360x = 11x2 + 110x
The quadratic equation is as follows: x = [400 sqrt(4002 - 4(11)(-2500))]
/ (2(11)) x = [400 ± sqrt(176000)]
/ 22
Speed cannot be negative, so we can disregard the negative result. Therefore, x = [400 + sqrt(176000)]
/ 22\sx ≈ 58.78
Kiran travelled between Tortula and Cactus at a speed of almost 58.78 miles per hour.
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Determine from the following diagram a. The spring constant of the bowb. The Elastic Potential Energy storedc. What will be the initial velocity of the arrow once the bow is released?
F= 300 N
d = 0.6m
m = 30g = 0.03 kg
• a.
Apply Hooke's law formula:
F = k x
k= F/ x
Where:
k= spring constant
F= force = 300N
x = distance = 0.6 m
k = 300N/0.6m = 500N/m
• b.
PE = 1/2 k (x)^2
PE = 1/2 (500 N/m) (0.6)^2 = 90 J
• c.
KE = 1/2 m v^2
KE = kinetic energy = PE = potential energy
v = √KE/ (1/2*m) = √2KE/m = √ (2* 90 / 0.03 ) = 77.46 m/s
Answers:
a = 500 N/m
b= 90 J
C = 77.46 m/s
1. At which point is potential energy the greatest?
1. At which point is kinetic energy the greatest?
Answer:
A ,C
Explanation:
Shows
Select the correct answer.
A boat moves 60 kilometers east from point A to point B. There, it reverses direction and travels another 45 kilometers toward point A. What are the total
distance and total displacement of the boat?
O A.
OB.
O C.
O D.
The total distance is 105 kilometers and the total displacement is 45 kilometers east.
The total distance is 60 kilometers and the total displacement is 60 kilometers east.
The total distance is 105 kilometers and the total displacement is 15 kilometers east.
The total distance is 60 kilometers and the total displacement is 45 kilometers east.
The total distance is 105 kilometers and the total displacement is 15 kilometers east. Option C
How to solve for the total distanceTo calculate the total distance, we add the distances traveled in each leg of the journey: 60 kilometers (from A to B) + 45 kilometers (from B back to A) = 105 kilometers.
However, displacement refers to the change in position of an object in a straight line from its starting point to its ending point. In this case, since the boat starts and ends at the same point (A), the total displacement is zero.
Hence The total distance is 105 kilometers and the total displacement is 15 kilometers east.
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An earth satellite travels in a circular orbit at 20,000 mph if the radius of the orbit is 4,300 mi what angular velocity is generated?
Answer:
0.00129rad/s
Explanation:
The angular velocity is expressed as;
v = wr
w is the angular velocity
r is the radius
Given
v = 20,000 mph
r = 4300mi
Get w;
w = v/r
w = 20000* 0.44704/4300*1609.34
w = 8940.8/6,920,162
w = 0.00129rad/s
Hence the angular velocity generated is 0.00129rad/s
Write the dimensional formula speed
Explanation:
speed is given by the following formula
speed (v) = displacement (s) / time (t)
V=S/t
Let's put the dimension of displacement and time
[V] = [S/t]
[V] = L/T
so [V] = LT-¹NOTE : Seven base quantities and dimensions .....
Time : T
length : L
mass : M
electric current : I
thermodynamic temperature : θ (theta)
amount of substance : N
luminous intensity : J ( not sure )
Velocity time graph and how to draw it
Answer:
Velocity time graph
Explanation:
Draw on graph paper two straight lines originating at the same point and perpendicular to each other. This is the x-y axis. The x-axis is the horizontal line and the y-axis is the vertical line.
Mark appropriate equally-spaced time intervals on the x-axis so that you can easily graph the time values from the table.
Mark appropriate velocity increments on the y-axis so that you can easily graph the velocity values from the table. If you have negative velocity values, extend the y-axis downward.
Find the first time value from the table and locate it on the x-axis. Look at the corresponding velocity value and find it on the y-axis.
Put a dot where a straight line vertically drawn up through the x-axis value and a straight line horizontally drawn through the y-axis value intersect.
Plot in similar fashion for all other velocity-time pairs in your table.
Draw a straight line with a pencil, connecting each dot you have put down on the graph paper, going from left to right
Answer #49 please and thank you
when Force (N) is 10.0 Length (m) is 0.60
when Force (N) is 8.0 Length (m) is 0.40
when Force (N) is 4.0 Length (m) is 0.20
when Force (N) is 4.0 Length (m) is 0.20
when Force (N) is 2.0 Length (m) is 0.10
chatgpt
49. To find the length of a pendulum that has a period of 2.3 seconds on the Moon, where the gravitational acceleration (g) is 1.6 N/kg, we can use the formula:
Period (T) = 2π√(Length (L) / g)
Substituting the given values:
2.3 = 2π√(L / 1.6)
To solve for L, we can rearrange the formula:
L = (2.3 / (2π))^2 * 1.6
L ≈ 0.781 meters (or 78.1 centimeters)
So, the pendulum must be approximately 0.781 meters (or 78.1 centimeters) long to have a period of 2.3 seconds on the Moon.
50. Ranking Task:
To rank the pendulums according to their periods, we need to consider both the length and mass of each pendulum.
Ranking from least to greatest period:
1. A: 10 cm long, mass = 0.25 kg
2. C: 20 cm long, mass = 0.25 kg
3. B: 10 cm long, mass = 0.35 kg
There is a tie between pendulums A and C, as they have the same length but different masses.
8.
A skier coasts down a 3.5° slope at constant speed. Find the coefficient of kinetic friction
between the skis and the snow covering the slope.
The coefficient of kinetic friction between the skis and the snow covering the slope is 0.7.
What is coefficient of kinetic friction?
The coefficient of kinetic friction is the ratio of the kinetic friction force of contacting surfaces to the normal force.
The coefficient of kinetic friction between the skis and the snow covering the slope is calculated by applying the following formula.
μ = Ff/N
μ = mgsinθ/mg cosθ
μ = tanθ
where;
θ is the angle of inclination of the slopeFf is frictional forceμ = tan(35)
μ = 0.7
Thus, the coefficient of friction is determined from the ratio of kinetic friction and normal force.
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A stuntman sitting on a tree limb wishes to drop vertically onto a horse galloping under the tree. The constant speed of the horse is 13.5 m/s, and the man is initially 3.55 m above the level of the saddle. Find a - What must be the horizontal distance between the saddle and limb when the man makes his move? Find b - How long is he in the air?
(a) the horizontal distance between the saddle and limb when the man makes his move is approximately 11.386 meters.
(b) the man is in the air for approximately 0.843 seconds.
To determine the horizontal distance between the saddle and limb when the man makes his move, we need to consider the horizontal velocity of the man when he drops from the tree limb.
Given:
Speed of the horse (constant velocity), v = 13.5 m/s
Vertical distance between the limb and saddle, h = 3.55 m
a) To find the horizontal distance, we can use the formula:
horizontal distance = horizontal velocity × time
Since the man drops vertically, his initial horizontal velocity is zero. The only horizontal velocity he will have is due to the motion of the horse.
The time taken by the man to fall can be determined using the equation for free fall:
h = (1/2) × g × t²
Where g is the acceleration due to gravity (approximately 9.8 m/s²) and t is the time.
Rearranging the equation, we get:
t = √(2h / g)
Substituting the given values:
t = √(2 × 3.55 / 9.8) ≈ 0.843 s
Now, we can find the horizontal distance:
horizontal distance = v × t
horizontal distance = 13.5 × 0.843 ≈ 11.386 m
Therefore, the horizontal distance between the saddle and limb when the man makes his move is approximately 11.386 meters.
b) The time the man is in the air can be calculated using the same equation for free fall:
t = √(2h / g)
Substituting the given value of h:
t = √(2 × 3.55 / 9.8) ≈ 0.843 s
Thus, the man is in the air for approximately 0.843 seconds.
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A wheelbarrow is pushed 10 meters with a force of 75 N for 30 seconds. What is the work done?
How much power is needed?
my assignment says: a1= 8 and the common difference is 7 find the 9th term
ANSWER
a9 = 64
EXPLANATION
The formula to find the nth term of an arithmetic sequence is,
\(a_n=a_1+d(n-1)\)Where a1 is the first term of the sequence and d is the common difference.
In this problem, the first term is a1 = 8 and the common difference is d = 7, so the formula for the nth term is,
\(a_n=8+7(n-1)\)If we want to find the 9th term, we have to replace n by 9 in the equation above,
\(a_9=8+7\cdot(9-1)\)\(a_9=8+7\cdot8=8+56=64\)Hence, the 9th term of the sequence is 64.
A 25,000 kg jet is sitting still on the runway (O
m/s). If the jet goes to take off and reaches 80
m/s in 10 seconds, how much force was required
to get it there?
Answer:
The force required to get it there is 200000 N.
Explanation:
The force can be calculated by the second Newton's law:
\( F = ma \)
Where:
m: is the mass = 25000 kg
a: is the acceleration
The acceleration is given by:
\( a = \frac{v}{t} \)
Where:
v: is the velocity = 80 m/s
t: is the time = 10 s
\( a = \frac{v}{t} = \frac{80 m/s}{10 s} = 8 m/s^{2} \)
Hence, the force is:
\( F = ma = 25000 kg*8 m/s^{2} = 200000 N \)
Therefore, the force required to get it there is 200000 N.
I hope it helps you!
A car has a mass of 1,200 kg. What is its acceleration when the engine exerts a force of 600 N? (Formula: F=ma)
O 0.5 m/s2
2 m/s2
O 600 m/s2
1,800 m/s2
Answer:
Option (a)
Explanation:
Given that,
Mass of a car, m = 1200 kg
Force exerted by the engine, F = 600 N
Noe force,F = ma
a is the acceleration of the engine
\(a=\dfrac{F}{m}\\\\a=\dfrac{600\ N}{1200\ kg}\\\\a=0.5\ m/s^2\)
So, the acceleration of the car is 0.5 m/s².
Answer:
0.5 m/s^2
Hope it works!
Explanation:
Currently, the labels for the Pfizer-BioNTech COVID-19 Vaccine, including the EUA label in the U.S., state that the vaccine must be stored in an ultra-cold freezer at about (minus) -75ºC. It can remain stored at this temperature for up to 6 months. Convert this temperature to Farenheit.
Given:
The temperature of the freezer is T = -75 degrees Celsius
To Find: Conversion of temperature from degrees Celsius to Fahrenheit
Explanation:
The formula to convert temperature from degrees Celsius to Fahrenheit is
\(^{\circ}F\text{ =}\frac{9}{5}\times^{\circ}C+32\)Substituting the values, the temperature in degrees Fahrenheit will be
\(\begin{gathered} T(in^{\circ}F)\text{ =}\frac{9}{5}\times(-75^{\circ}C)+32 \\ T=-103^{\circ}F \end{gathered}\)Final Answer: The temperature of ultra-cold Freezer is -103 degrees F