The polynomial x^2 – x – 12 factors as (x – 4) (x + 3). What is the quotient of (x^2 – x – 12) / (x – 4). Select one:a. ( x - 4)b. (x + 3)c. (x + 3)d. (x + 4)

The speed is proportional to the elapsed time. It doesn't depend on the mass. a)Mg/c is the limit and b)gt is the limit

What is speed?

a) lim t-->∞  v = mg/c
  mg/c is the limit
2)It is the speed the object approaches as time goes on.
b) lim c-->0^(+)   v = gt.

  gt is the limit
3)The speed is proportional to the elapsed time. It doesn't depend on the mass. The longer the object falls the faster it will fall because same acceleration g it will not depend on mass.

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We can see here that the total weight of candy in a 5/6 pound bag site is 377 grams.

Weight is a measure of the force exerted by gravity on an object. It is the measure of how heavy an object is. Weight is typically expressed in units such as pounds or kilograms. The weight of an object can vary depending on the gravitational force acting on it.

There are 16 ounces in a pound.

Thus, a 5/6 pound bag of candy weighs

5/6 × 16 = 13.3 ounces.

If you want to know the weight in grams, 13.3 ounces is equal to 377 grams.

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Answer:     point

Step-by-step explanation:

Answer:

$10 to rent shoes for 9 people

Step-by-step explanation:

Total amount of the party = $140

A bowling lane = $50

$140 - $50 = $90

$90 divided by 9 = 10

$10 to rent shoes for 9 people

The graphs have been correctly dragged to the table to show the image of the triangle after it is reflected over the x-axis, the y-axis, and the line y = x.

By applying a reflection over the x-axis to the coordinates of this triangle, we have the following coordinates of the image triangle;

(x, y)                →      (x, -y)

(1, -3)             →      (1, -(-3)) = (1, 3)

(3, -2)             →      (3, -(-2)) = (3, 2)

(4, -5)             →      (4, -(-5)) = (4, 5)

By applying a reflection over the y-axis to the coordinates of this triangle, we have the following coordinates of the image triangle;

(x, y)                →      (-x, y)

(1, -3)             →        (-1, -3)

(3, -2)             →      (-3, -2)

(4, -5)             →      (-4, -5)

By applying a reflection over the line y = x to the coordinates of this triangle, we have the following coordinates of the image triangle;

(x, y)                →      (y, x)

(1, -3)             →        (-3, 1)

(3, -2)             →      (-2, 3)

(4, -5)             →      (-5, 4)

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Answer:

  d = 23 1/3

Step-by-step explanation:

You want to solve the proportion (0.3d -1)/(3 1/3) = (0.84)/(7/15).

  \(\dfrac{0.3d-1}{3\dfrac{1}{3}}=\dfrac{0.84}{\dfrac{7}{15}}\qquad\text{given}\\\\\\\dfrac{3(0.3d-1)}{10}=\dfrac{15(0.84)}{7}\qquad\text{invert and multiply}\\\\0.09d -0.3=1.8\qquad\text{simplify}\\\\0.09d = 2.1\qquad\text{add 0.1}\\\\d=\dfrac{2.10}{0.09}=\dfrac{70}{3}\qquad\text{divide by 0.09}\\\\\boxed{d=23\dfrac{1}{3}}\)

__

Check

  (0.3·(70/3) -1)/(3 1/3) = 0.84/(7/15)

  (7 -1)/(10/3) = 1.8

  6(3/10) = 1.8 . . . . . . true

Answer: 23 1/3

Step-by-step explanation:

Hi there!

Given an equation in point-slope form, explain how to determine the coordinates of its y-intercept.

Given an equation or graph of a line, describe how to write an equation of a parallel line that goes through a given point.

Given an equation or graph of a line, describe how to write an equation of a perpendicular line that goes through a given point.

I hope this helps!

Answer:

\(g(x) = 3.5^{x} -2\)

Step-by-step explanation:

This is the answer because, the y-intercept has decreased by -2. After you graph the original equation, you will find that the intercept is 1. So if the new one has a y-interceptn of -1, it decreased by 2. So, it is \(g(x) = 3.5^{x} -2\)

Step-by-step explanation:

Recall that the first derivative of an equation gives us the SLOPE for the tangent line.

So first, we should find the first derivative.

\(\frac{dy}{dx} = 6 - 3x^2\)

With the first derivative, we can solve for the SLOPE of the tangent line at (1,5).

Using x = 1.

\(slope = 6 - 3(1)^2\)

A tangent line is a line. And has the form \(y = mx +b\)

Where m is the SLOPE of the line. and b is the y-intercept.

To get to this equation, let's use the point-slope technique.

\(y-y_1 = m(x-x_1)\)

\(y - 5 = m(x-1)\)

Solve for slope, substitute it into this equation for m and solve. That is the equation of the tangent line at the point (1,5).

Answer:

The answer is A

Step-by-step explanation:

5m=505m=505,m equal, 50

Answer:

1.75 * 0.84

Step-by-step explanation:

1.74 * 0.84 = 1.4616

1.79 * 0.69 = 1.2351

Answer:

1.74 x 0.84 is greater

Step-by-step explanation:

1.74 x 0.84 = 1.4616

while

1.79 x 0.69 = 1.23509

The rate of the speeding car is 0.493.

We have,

The police car is at 80 mph and it is 44 yards from the intersection, is increasing at 45 mph, while the other car is 117 yards away from the intersection.

So, Rate of speeding car

= (45- 80)/ (117- 44)

= -35/(-73)

= 35/73

= 0.493

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Answer:

false

Step-by-step explanation:

quadratic equations are written as ax² + bx + c

the equation must have a number with an exponent.

the equation given, y = mx + 6 has not exponent and can therefore not be the equation of a quadratic relation

Answer:

16

Step-by-step explanation:

16+19=35

19-16=3

16 green peppers

The area of the segment is 9( π-2) units²

The area of a figure is the number of unit squares that cover the surface of a closed figure.

A segment is the area occupied by a chord and an arc. A segment can be a major segment or minor segment.

Area of segment = area of sector - area of triangle

area of sector = 90/360 × πr²

= 1/4 × π × 36

= 9π

area of triangle = 1/2bh

= 1/2 × 6²

= 18

area of segment = 9π -18

= 9( π -2) units²

therefore the area of the segment is 9(π-2) units²

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The solution set of the system of equations graphed on the grid is

{(1, -4), (4, -1)}. Hence, option B is the right choice.

The solution set to a system of equations is the set of all points that satisfies every equation in the given system.

We are asked to find the apparent solution set of the system of equations graphed on the grid.

The solution set will be the set of common points on the graph as they satisfy both the equations in the given system.

The common points are (1, -4) and (4, -1), as the equations pass through these points simultaneously.

∴ The solution set of the system of equations graphed on the grid is

{(1, -4), (4, -1)}. Hence, option B is the right choice.

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hello

we have two equations given and we solve them simultaneously to know how many solutions it has

let's rearrange equation 2

now let's solve from equation 1

put equation 3 into equation 2

put y = - 3/4 into either equation 1 or 2

from equation 2

from the calculations above, the system of equations have two solutions.

9514 1404 393

Answer:

  -1

Step-by-step explanation:

Your calculator can help with this.

  24 -5² = 24 - 5·5 = 24 -25 = -1

Answer:

A. Slope: 4; y-intercept: (0-7)

Step-by-step explanation:

The equation given is in slope-intercept form, y =mx+b, where m is the slope and b is the y-intercept.

Our equation is y=4x -7,

Where m = 4 b = -7

If m = to the slope and b = to the y-intercept, our slope would be 4/1 or 4, and our y-intercept would be (0,-7).

The answer, A would be the best for the question.

Hope it helps!

Answer:A school bus provides a safe way of transportation for your child. Learn resources to talk to your child about school bus and bus stop safety.

Step-by-step explanation:

The z-score is an estimate of the the standard normal distribution

The z-score for the given shaded region under the standard normal distribution is -0.64

From the complete question, we have:

P( z > Z) = 0.26

Using the complemen rule, the above equation becomes

1 - P( z <= Z) = 0.26

Collect like terms

P( z <= Z) = 1 - 0.26

Evaluate the difference

P( z <= Z) = 0.74

From z-score of probability, we have:

z = -0.64

Hence, the z-score is -0.64

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Answer:

the cheeseburgers were purchased by micky

Answer:

Cost for each pound of jelly beans:  $2.75

Cost for each pound of almonds:  $3.75

Step-by-step explanation:

Let J be the cost of one pound of jelly beans.

Let A be the cost of one pound of almonds.

Using the given information, we can create a system of equations.

Given 3 pounds of jelly beans and 5 pounds of almonds cost $27:

\(\implies 3J + 5A = 27\)

Given 9 pounds of jelly beans and 7 pounds of almonds cost $51:

\(\implies 9J + 7A = 51\)

Therefore, the system of equations is:

\(\begin{cases}3J+5A=27\\9J+7A=51\end{cases}\)

To solve the system of equations, multiply the first equation by 3 to create a third equation:

\(3J \cdot 3+5A \cdot 3=27 \cdot 3\)

\(9J+15A=81\)

Subtract the second equation from the third equation to eliminate the J term.

\(\begin{array}{crcrcl}&9J & + & 15A & = & 81\\\vphantom{\dfrac12}- & (9J & + & 7A & = & 51)\\\cline{2-6}\vphantom{\dfrac12} &&&8A&=&30\end{array}\)

Solve the equation for A by dividing both sides by 8:

\(\dfrac{8A}{8}=\dfrac{30}{8}\)

\(A=3.75\)

Therefore, the cost of one pound of almonds is $3.75.

Now that we know the cost of one pound of almonds, we can substitute this value into one of the original equations to solve for J.

Using the first equation:

\(3J+5(3.75)=27\)

\(3J+18.75=27\)

\(3J+18.75-18/75=27-18.75\)

\(3J=8.25\)

\(\dfrac{3J}{3}=\dfrac{8.25}{3}\)

\(J=2.75\)

Therefore, the cost of one pound of jelly beans is $2.75.

Answer:

Y-intercept is (0,8)

Step-by-step explanation:

The line of an equation is y=mx+b. M in this case is 1 and "b" is the y intercept. since in the place of b is positive 8 the y-intercept is 8

The function f(x) = -2(4)ˣ⁺¹ +140 represents the number of tokens a child has x hours after arriving at an arcade. The practical domain and range of the function are x ≥ 0 and The practical range of the situation is [140, ∞).

The given function is f(x) = -2(4)ˣ⁺¹+ 140, which represents the number of tokens a child has x hours after arriving at an arcade.

To determine the practical domain and range of the function, we need to consider the constraints and limitations of the situation.

For the practical domain, we need to identify the valid values for x, which in this case represents the number of hours the child has been at the arcade. Since time cannot be negative in this context, the practical domain is x ≥ 0, meaning x is a non-negative number or zero.

Therefore, the practical domain of the situation is x ≥ 0.

For the practical range, we need to determine the possible values for the number of tokens the child can have. Looking at the given function, we can see that the term -2(4)ˣ⁺¹represents a decreasing exponential function as x increases. The constant term +140 is added to shift the graph upward.

Since the exponential term decreases as x increases, the function will have a maximum value at x = 0 and approach negative infinity as x approaches infinity. However, due to the presence of the +140 term, the actual range will be shifted upward by 140 units.

Therefore, the practical range of the situation will be all real numbers greater than or equal to 140. In interval notation, we can express it as [140, ∞).

To summarize:

- The practical domain of the situation is x ≥ 0.

- The practical range of the situation is [140, ∞).

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The graph of the translated function is g ( x ) = ( x + 5 )² + 2

Given data ,

Let the parent function be represented as f ( x )

Now , the value of f ( x ) is

f ( x ) = x²

On simplifying , we get

The function is translated 5 units to the horizontal left direction:

And , when the function is translated 2 units in the vertical upward direction:

So , the translated function is

g ( x ) = ( x + 5 )² + 2

Now , the vertex of the function g ( x ) = ( x + 5 )² + 2 is (-5, 2)

Hence , the graph of the function is plotted and g ( x ) = ( x + 5 )² + 2

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For each variable, the possible values are:

a) T = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

b) X = {-4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6}

c) U = {0, 1, 2, 3, 4, 5, 6}

d) Z = {0, 1, 2}

Item a:

In total, there are 10 pumps, hence the possible values are all integers from 0 to 10, that is:

T = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

Item b:

In the first, there are 6 pumps, and in the second 4, hence, the difference ranges from -4 to 6, that is:

X = {-4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6}

Item c:

The maximum number in a station is 6 pumps, hence this variable ranges from 0 to 6.

U = {0, 1, 2, 3, 4, 5, 6}

Item d:

Either none of the stations has exactly two pumps in use, or one has or both, hence the variable ranges from 0 to 2.

Z = {0, 1, 2}

The question is incomplete. The complete question is:

"The number of pumps in use at both a six-pump station and a four-pump station will be determined. Give the possible values for each of the following random variables. (Enter your answers in set notation.)

a. T = the total number of pumps in use

b. X = the difference between the numbers in use at stations 1 and 2.

c. U = the maximum number of pumps in use at either station

d. Z = the number of stations having exactly two pumps in use"

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Answer: The range is 20, Standard Deviation, σ: 6.8702256149271

Step-by-step explanation:

I hope it helped!

<3

100 miles in a day the truck should have to cover so that the rental costs for company A and company B are same

Company A rented a truck for  ​$70 a day and $.5 per mile will be added accordingly. Similarly, Company B rented a truck for  ​$30 a day and $.9 per mile will be added as per distance covered.

Let the number of miles travelled by the truck be x.

Then, we can depict the given information in terms of equation and will equate them further to solve according to the question need.

So, total rent to be pay to company A = ​$(70+0.5x)

and total rent to be pay to company B = ​$(30+0.9x)

Now, the number of miles in a day at which the rental costs for Company A and Company B are the same will be

70+0.5x = 30+0.9x .............(1)

Now, solve equation (1) in order to calculate the value of x.

70-30 = 0.9x-0.5x

40 = 0.4x

40/0.4 = x

400/4 = x

100 = x

∴ x = 100

Hence, 100 miles in a day the truck should have to cover so that the rental costs for company A and company B are same.

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The multiplication fact that can help you find 24 divided by 4 is 4 x 6.