The prevailing idea about the beginnig of the universe is called?

Matter affects our daily lives in the sense all is composed of matter and energy.

Matter and energy in the Universe and daily life are two basic elements that characterize the physic system and allow us to understand the world. In regard to matter, it is something that occupies space and has mass, while energy can perform work.

Therefore, with this data, we can see that matter and energy in the Universe and daily life are fundamental to understanding the universe.

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Answer: goin at a constant rate

Explanation: goes through 0,0

Answer:

only you are in motion

Explanation:

it is because the ground causes friction to make you stop but you are the object in motion :)

When you run, your feet are pushing you forward. Friction keeps your foot in contact with the ground. According to Newton's third law, you are pushing the ground back but the earth does not change its position because the mass of the earth is huge as compared to your mass.

Newton's third law of motion explains that forces exist in pairs. It states that for every action force there exists equal and opposite reaction forces, these pairs of forces are equal in magnitude but opposite in direction.

As given in the problem when you run, your feet are pushing you forward. Friction keeps your foot in contact with the ground. According to Newton's third law, you are pushing the ground back.

Your feet propel you ahead as you run. Your foot remains in contact with the ground thanks to friction. Newton's third law states that even though you are pushing the ground back, the earth does not move since it has a much larger mass than you have.

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The magnitude of the resultant force acting on the mass is 20 N.

To find the magnitude of the resultant force acting on the mass, we must use the centripetal force. Centripetal force is given by the equation

F = (mv²)/r

where F is the centripetal force, m is the mass of the object, v is the speed of the object and r is the radius of the circular path.

The magnitude of the resultant force acting on the mass is given by the formula F = (mv²)/r, substituting the given values we have:

F = (4.0 kg)(2.0 m/s)²/0.80 m

F = 16/0.80

F = 20 N

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The average force exerted on the ball by the golf club is 490 N.

Thus,  F = p/t = 0.49 * 10³ N = 490 N.

Momentum is a metric for power and how challenging it is to stop an object. Zero momentum applies to any object that is not moving. tremendous, slow-moving objects have tremendous amounts of momentum.

A small, swiftly moving object also possesses a significant momentum. A bowling ball, for instance, has more momentum than a ping-pong ball if their velocities are equal.

This is because bowling balls are larger in mass than ping-pong balls.

Thus, The average force exerted on the ball by the golf club is 490 N.

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Answer:

556cm

Explanation:

because 5.56m × 100 = 556cm.

Answer:556

5.56*100=556

Explanation:

Answer:

A. 70 m OS the correct one

The approximate maximum height that the water balloon can reach is 13.8 m, The correct option is D.

Conservation of energy is a fundamental principle in physics that states that energy cannot be created or destroyed, only transformed or transferred from one form to another. In other words, the total amount of energy in a closed system remains constant over time. This principle is based on the idea that energy is a fundamental property of the universe, and it is a key concept in many areas of science, including physics, chemistry, and engineering. The law of conservation of energy is used to analyze and understand a wide range of physical phenomena, from the behavior of subatomic particles to the workings of the entire universe.

Here in the Question,

The maximum height that the water balloon can reach can be found using conservation of energy. The initial potential energy stored in the slingshot is transformed into kinetic energy of the water balloon as it is launched into the air, and then into potential energy at the maximum height.

The initial potential energy of the slingshot is given by:

PE = (1/2)kx^2

where k is the spring constant (60 N/m) and x is the distance pulled back (1.5 m)

PE = (1/2)(60 N/m)(1.5 m)^2

PE = 67.5 J

At the maximum height, all of the initial potential energy is converted into potential energy due to gravity:

PE = mgh

where m is the mass of the water balloon (0.5 kg), g is the acceleration due to gravity (9.8 m/s^2), and h is the maximum height.

h = PE/(mg)

h = 67.5 J/(0.5 kg)(9.8 m/s^2)

h ≈ 13.8 m

Therefore, the approximate maximum height that the water balloon can reach is 13.8 m, which is option D.

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Answer:

(B) Conduction

Explanation:

Answer:

a ) conduction

Explanation:

it's a because if u think about it a conductor keeps the heat from getting to a certain part of the metal

Answer:

1=f 2=t 3=f 4=t

Explanation:

Answer:

i) Power = Force * Velocity = 1100 * 15 = 16500 W = 16.5 kW(ii)  Find the value of k first: F = 400 + k(15^2)                                              k = 28/9    F = 400 +(28/9)(30^2) = 320

Explanation:

Answer:

\(velocity = \frac{distance}{time} \\ velocity = \frac{10}{12.20} \\ velocity = \frac{50}{61} \\ multiply \: by \: 3.6u \: can \: convert \: to \: km \: per \: hour \\ velocity = \frac{50}{61} \times 3.6 \\ v = \frac{180}{61} \\ v = 2.95 \frac{km}{h} \\ thank \: you\)

Answer:

yes!

Explanation:

The value of frictional force, using the y component of the applied force f can be found if the co- efficient of friction is known.

First split the applied force F into its vertical and horizontal components \(F_{y}\) and \(F_{x}\) respectively

\(F_{y}\) = F sin θ

Since there is no vertical movement,

Σ \(F_{y}\) = 0

\(F_{y}\) + \(F_{N}\) - mg = 0

\(F_{N}\) = \(F_{y}\) - mg

\(f_{k}\) = \((\)μ\()_{k}\)\(F_{N}\)

Therefore, the frictional force \(f_{k}\) can be found only the y components if the co-efficient is known.

Frictional force is the opposing force between two objects. It acts along the surface of the object.

Therefore, the value of frictional force, using the y component of the applied force f can be found if the co- efficient of friction is known.

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Answer:

30 m/s

Explanation:

We can first list out the 3 kinematics equations:

\(v = u + at \\ {v}^{2} = {u}^{2} + 2as \\ s = ut + \frac{1}{2} a {t}^{2} \)

Where:

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time taken

s is the displacement

With all the 3 equations, we can now list the values needed for the first part of the question which is to find the acceleration for this first part.

Given:

v = 14 m/s

u = 6 m/s

t = 8s

We can use the first kinematics equation to solve for a. (v = u + at)

14 = 6 + a x 8

14 = 6 + 8a

8a = 14 - 6

8a = 8

a =

\(1 \frac{m}{ {s}^{2} } \)

Now with this acceleration, we can find the final speed for the second part of the question by using the same kinematics equation. (v = u + at)

Given,

u = 14 m/s

t = 16 s

a =

\(1 \frac{m}{ {s}^{2} } \)

v = 14 + (1)(16) = 14 + 16 = 30 m/s

a) The motion of the object between 15 s to 30 s is increasing velocity, to a constant velocity and finally a decreasing velocity.

(b) The average velocity of the object between 0 and 15 seconds is 0.167 m/s.

(c) The position of the object at 5.0 seconds is 0.5 m.

(d) Between 30 and 40 seconds, the velocity of the object is decreasing and the object is decelerating.

(a) The motion of the object between 15 s to 30 s can be described as increasing velocity, to a constant velocity and finally a decreasing velocity.

(b) The average velocity of the object between 0 and 15 seconds is calculated as;

average velocity = total displacement / total time

average velocity = (2.5 m - 0 m ) / ( 15 s - 0 s ) = 0.167 m/s

(c) The position of the object at 5.0 seconds is calculated as follows;

at 5.0 seconds, the position of the object is traced from the graph as 0.5 m.

(d) The motion of the object between 30 and 40 seconds is calculated as;

velocity = ( 0 m - 4 m ) / ( 40 s - 30 s ) = - 0.4 m/s

Between 30 and 40 seconds, the velocity of the object is decreasing and the object is decelerating.

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Answer:

lol can u tell what to help u with. cause I didn't understood

If the distance to a star was suddenly cut in half, the star would appear 4 times brighter.

We know the expression between the intensity of star and the distance as, I ∝ 1/r²

where,

r is the distance

I is the intensity of light

Here, it is given that the distance is cut down by half, so, r becomes r/2.

Placing it in the above relation, we have, I ∝ 1/(r/2)²

⇒ I ∝ 4/r²

So, the relation says, the intensity becomes 4 times when the distance is reduced to half.

Thus, the star appears to be four times brighter.

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Both the initial amount and the kind of gas play a role.  However, the pressure and the quantity of gas present also have a role in this relationship.

Charles' Law states that a gas's volume is directly proportionate to its temperature. However, the pressure and the quantity of gas present also have a role in this relationship. Hence, we would need to know the starting volume, pressure, and number of moles of a gas sample in order to calculate its volume at 50.0 °C. The type of gas would also be a role in deciding its final volume at 50.0 °C because different gases behave differently at various temperatures.  Ideal gas perfectly obeys the gas law. Thus, the correct answer to the question is Ideal gas.

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Explanation:

The answer is in the pic above

The new angular velocity of the two disks is lower than the initial angular velocity of the first disk. This is because the moment of inertia of the combined system (the two disks) is higher than the moment of inertia of the first disk alone. When the second disk is added, the total moment of inertia increases, which means that more torque is required to maintain the same angular velocity.

However, since the system is still rotating with uniform angular velocity, the torque must remain constant. This means that the new angular velocity is lower in order to compensate for the increased moment of inertia. The exact relationship between the old and new angular velocities depends on the masses and radii of the disks, as well as the initial angular velocity of the first disk.

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Answer:

a star in andromeda

Explanation:

all of the other objects are in the milkyway (where we are) and the andromeda galaxy is 2 million light years away from us

Answer:

Perpendicular ; Parallel

Answer:

Energy and Work unit is Joules, J.

Work is the product of force and distance.

No, energy can't be created or destroyed but it can be transformed from one form to another.

Power is the amount of work done per unit time.

Time is essential to power because power can only be measured after a certain amount of time has passed.

Power unit is Watts, W.

Examples of things measured in watts are electricity, light bulb power, microwave ovens power.

Two main types of energy are Kinetic energy and Potential energy.

Kinetic energy is the energy of motion.

It comes from the Greek word kinētikos meaning of motion.

Kinetic energy depends in mass and velocity.

Kinetic energy is directly proportional to mass.

Kinetic energy is directly proportional to the square of velocity.

Bowling ball bas higher kinetic energy.

Because mass is directly proportional to kinetic energy thus the larger the mass the greater the kinetic energy.

The bowling ball with the larger mass.

Potential energy results from position or state of a body.

Gravitational potential energy depends on the mass of the body and height of an object.

P.Eg = m×h×g

Elastic potential energy is caused when objects are deformed or stretched.

Examples; Spring and coiled rubber band.

By increasing the stretch of the bow.

= P.E + K.E

There's motion involved and work is done to change an object's position off the ground.

Examples; moving car and wrecking ball.

By increasing the raising point of swinging (that is angle of elevation must be large).

Heat energy.

Molecules in an object.

Examples; Frying eggs and toasting bread.

Flowing of electrons.

Examples; current flow and lightning.

Stored in the bonds in atoms, elements, molecules or compounds.

Maximally Enhanced Signal: x = 60.6m, 56.1m, and 52.8m; Cancelled Signal: x ≈ 58.6m and 63.5m.

We can use the concept of interference of waves to solve this problem. The radio waves emitted by transmitters A and B are in-phase, which means that they have the same frequency, wavelength, and polarization. When these waves meet, they interfere with each other constructively or destructively depending on their relative phase difference.

Let's consider the point where the person is equidistant from both transmitters A and B. At this point, the waves from A and B will arrive at the same time and in-phase, resulting in constructive interference and maximum signal strength.

As the person starts walking towards transmitter B, she gets closer to it and farther away from transmitter A. This changes the path length difference between the waves from A and B, causing a phase shift between them. If the path length difference is a multiple of the wavelength, the waves will be back in-phase and constructive interference will occur again, resulting in maximum signal strength. On the other hand, if the path length difference is half of a wavelength, the waves will be out-of-phase and destructive interference will occur, resulting in minimum or zero signal strength.

Let x be the distance between the person and transmitter A. The path length difference between the waves from A and B is then given by:

ΔL = AB - (sqrt(x^2 + 50^2) - 50)

where AB is the distance between transmitters A and B, and sqrt(x^2 + 50^2) is the distance between the person and transmitter A using the Pythagorean theorem.

The wavelength of the radio waves emitted by transmitters A and B is given by:

λ = c/f

where c is the speed of light, and f is the frequency of the waves.

Substituting the given values, we get:

λ = c/f = 3.2 m

For constructive interference to occur, the path length difference ΔL must be an integer multiple of the wavelength, i.e.,

ΔL = mλ

where m is an integer.

For destructive interference to occur, the path length difference ΔL must be a half-integer multiple of the wavelength, i.e.,

ΔL = (m + 0.5)λ

where m is an integer.

Now, let's solve the problem for the given range of x values:

The condition for constructive interference is:

ΔL = mλ

Substituting the values and solving for x, we get:

AB - (sqrt(x^2 + 50^2) - 50) = mλ

11 - (sqrt(x^2 + 2500) - 50) = m(3.2)

Simplifying and solving for x, we get:

x = sqrt((11 - m(3.2) + 50)^2 - 2500)

We need to find the values of x that satisfy the given range of 50.0m ≤ x ≤ 65.0m.

For m = 0, we get:

x = sqrt((11 - 0 + 50)^2 - 2500) = 60.6 m

For m = 1, we get:

x = sqrt((11 - 3.2 + 50)^2 - 2500) = 56.1 m

For m = 2, we get:

x = sqrt((11 - 6.4 + 50)^2 - 2500) = 52.8 m

These are the only values of x that satisfy the given range and result in maximum signal strength.

The condition for destructive interference is:

ΔL = (m + 0.5)λ

Substituting the values and solving for x, we get:

AB - (sqrt(x^2 + 50^2) - 50) = (m + 0.5)λ

11 - (sqrt(x^2 + 2500) - 50) = (m + 0.5)(3.2)

Simplifying and solving for x, we get:

x = sqrt((11 - (m + 0.5)(3.2) + 50)^2 - 2500)

We need to find the values of x that satisfy the given range of 50.0m ≤ x ≤ 65.0m.

For m = 0, we get:

x = sqrt((11 - 0.5(3.2) + 50)^2 - 2500) ≈ 58.6 m

For m = 1, we get:

x = sqrt((11 - 4.7 + 50)^2 - 2500) ≈ 63.5

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The approximate average speed of the molecules in the gas If a sample of 4 mol of diatomic gas is measured to have a temperature of 290 K and the mass of the gas is 0.064 kg is 672 m/s (Option B).

To find the approximate average speed of the molecules in a sample of 4 mol of diatomic gas with a temperature of 290 K and a mass of 0.064 kg, we can use the equation:

KE_translational = (1/2)mv² = (3/2)nRT

where n is the number of moles, R is the gas constant (8.31 J/(mol·K)), and T is the temperature.

First, we find the molar mass:

molar_mass = 0.064 kg / 4 mol

= 0.016 kg/mol

Next, we solve for v²:

v² = (3 × R × T) / (molar_mass)

v² = (3 × 8.31 J/(mol·K) × 290 K) / (0.016 kg/mol)

Now, we take the square root to get the average speed:

v = √(v²)

v ≈ 672 m/s

So, the approximate average speed of the molecules in the gas is 672 m/s, which corresponds to option B.

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Answer:

255 .07N

Explanation:

F_l * d_l = F_r * d_r

F_l * 0.722 = 1250 * 0.13

F_l = 255.07

The force that holds the spring stretched at the same distance (14) is 25.76 N.

The work done in stretching a spring from its natural length to 14 beyond its natural length = W = 180 J

The stretch distance is = x = 14

Work done in stretching a spring = (1/2) k x² Where,

W = work done in stretching a spring

k = spring constant

x = distance stretched from its natural length

Therefore, the formula for finding the spring constant k is: k = (2W) / x²

From the given data, Work done = W = 180 J

Stretch distance = x = 14

Therefore, the spring constant k is: k = (2W) / x²= (2 × 180 J) / (14)²= (2 × 180) / 196= 360 / 196= 1.84 N/m

The force that holds the spring stretched at the same distance (14) is given by the formula: F = k x Where,

k = spring constant

x = stretch distance

Therefore, F = k x= 1.84 N/m × 14= 25.76 N

Therefore, the force that holds the spring stretched at the same distance (14) is 25.76 N.

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Answer:

At the critical angle the angle of refraction (outside the medium) is 90°

Ni sin θ = Na sin 90° = 1    assuming outside medium is air

sin θ = 1 / Ni            where Ni is the refractive of the medium involved