Answers
The energy of the electron in the given region is 9.38 eV.
The given parameters:
Probability, e = 0.8%Height of barrier, U₀ = 10 eVWidth of the barrier, w = 0.6 nmWhen can electron penetrate a barrier?When a particle of energy E less than the potential cannot penetrate inside that region.
The exponential factor is calculated as follows;
\(T = e^{-2 \alpha a} \\\\ 0.008 = e^{-2(0.6 \times 10^{-9})\alpha}\\\\ -2(0.6 \times 10^{-9})\alpha = ln(0.008)\\\\ -2(0.6 \times 10^{-9})\alpha = -4.828\\\\ \alpha = \frac{-4.828}{-2(0.6 \times 10^{-9})} \\\\ \alpha = 4.023 \times 10^9\)
The energy of the electron is calculated as follows;
\(\alpha = \sqrt{\frac{2m(U_0 -E)}{h^2} } \\\\ 4.023 \times 10^9 = \sqrt{\frac{2 ( 9.11 \times 10^{-31} kg)(10 \ eV -E) \ \times 1.6\times 10^{-19} \ J/eV}{(1.055 \times 10^{-34} \ J.s)^2 } } \\\\ (4.023 \times 10^9)^2 = \frac{2 ( 9.11 \times 10^{-31} kg)(10 \ eV -E) \ \times 1.6\times 10^{-19} \ J/eV}{(1.055 \times 10^{-34} \ J.s)^2 }\\\\ 2 ( 9.11 \times 10^{-31} )(10 \ eV -E) 1.6\times 10^{-19} = (4.023 \times 10^9)^2 (1.055 \times 10^{-34} \ )^2\\\\ \)
\(10eV - E = \frac{(4.023 \times 10^9)^2\times (1.055 \times 10^{-34} \ )^2}{2 ( 9.11 \times 10^{-31} ) \times 1.6\times 10^{-19}} \\\\ 10eV - E = 0.62 \ eV\\\\ E = 10 \ eV - 0.62\ eV\\\\ E = 9.38 \ eV\)
Thus, the energy of the electron in the given region is 9.38 eV.
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Related Questions
Please help me solve The temperature coefficient of silver is 0.0038 / degree Celsius
Answers
Given:
The resistance of the silver wire is R = 4.6 ohm
The temperature is
\(T\text{ = 17 }^{\circ}C\)The temperature coefficient of the silver wire is
\(\alpha\text{ = 0.0038 }^{\circ}C^{-1}\)Required: The resistance of the wire when the temperature is
\(T^{\prime}\text{ = 53}^{\circ}C\)Explanation:
The resistance of the wire can be calculated by the formula
\(R^{\prime}=R[1-\alpha(T^{\prime}-T)]\)On substituting the values, the resistance of the wire will be
\(\begin{gathered} R^{\prime}=4.6[1-0.0038(53-17)] \\ =3.97\text{ }\Omega \end{gathered}\)Final Answer: The resistance of the wire is 3.97 ohm when the temperature is 53 degrees Celsius.
how much energy is possessed by 1 mole of nitrogen atoms moving at 35.0 m/s ?
Answers
1 mole of nitrogen atoms moving at 35.0 m/s possesses approximately 27.8 joules of energy.
To calculate the energy possessed by 1 mole of nitrogen atoms moving at 35.0 m/s, we need to consider both the kinetic energy and the molecular mass of nitrogen.
The kinetic energy (KE) of an object is given by the equation KE = 1/2 * m * v^2, where m is the mass and v is the velocity.
The molar mass of nitrogen (N₂) is approximately 28.0134 g/mol, which can be converted to kilograms by dividing by Avogadro's number (6.022 × 10^23). This gives us a mass of approximately 4.65 × 10^(-26) kg for one nitrogen atom.
Plugging in the values, we have KE = 1/2 * (4.65 × 10^(-26) kg) * (35.0 m/s)^2.
Evaluating the equation, we find that the kinetic energy possessed by one nitrogen atom is approximately 4.62 × 10^(-23) joules.
Since we are considering 1 mole of nitrogen atoms, we need to multiply this value by Avogadro's number to get the energy possessed by 1 mole. Avogadro's number is 6.022 × 10^23, so the total energy is approximately 2.78 × 10^1 joules, or 27.8 J.
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Short, difficult activities that push your body are called
A.
aerobic activity
B.
anaerobic activity
C.
muscle strength
D.
exercise
Answers
Answer:
B. is your answer
Explanation:
Have a good day
Sincerly, lipor
Short, difficult activities that push your body are called anaerobic activities. Option b is correct
They are high-intensity exercises that do not require oxygen and primarily use stored energy sources within the muscles. Examples include weightlifting or sprinting.
Short, difficult activities that push your body are called anaerobic activity. Anaerobic activities are high-intensity exercises that do not require oxygen and primarily use stored energy sources within the muscles, such as weightlifting or sprinting. These activities help build muscle strength and improve power and speed.
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Pls help and explain how to get the answer
Answers
(a) The magnitude of the gravitational force on the rock is 64.68 N and on the pebble is 5.488 x 10⁻³ N.
(b) The acceleration of each object is equal to acceleration due to gravity, = 9.8 m/s².
What is the gravitational force exerted on each object?The gravitational force exerted on each object is calculated by applying Newton's law of universal gravitation as follows;
Fg = Gm₁m₂ / R²
where;
G is universal gravitation constantm₁ is the mass of the rockm₂ is the mass of pebbleThe acceleration of each object will be constant and equal to acceleration due to gravity, the force on each object is calculated by using Newton's second law of motion.
Force on the rock;
F = mg
where;
g is acceleration due to gravityF = 6.6 kg x 9.8 m/s²
F = 64.68 N
The force on the pebble;
F = mg
F = 5.6 x 10⁻⁴ x 9.8
F = 5.488 x 10⁻³ N
Thus, the acceleration of each object is equal to acceleration due to gravity, = 9.8 m/s².
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A substance takes three minutes in cooling from 50°C to 45°C and takes five minutes and cooling from 45°C to 40°C what is the temperature of the surrounding how much time will it take to cool the substances from 40°C to 35°C
Answers
Answer:
The ambient temperature is 35°C.
It takes 15 minutes to cool the substance from 40°C to 35°C.
Explanation:
Using Newton's Law of Cooling to answer the given problem.
\(\boxed{\left\begin{array}{ccc}\text{\underline{Newton's Law of Cooling:}}\\\\ \frac{dT}{dt} =-k(T-T_a)\end{array}\right}\)
Given:
The time it takes to cool from 50°C to 45°C = 3 minutes
The time it takes to cool from 45°C to 40°C = 5 minutes
Find:
Time ambient temperature and the time it takes to cool the substance from 40°C to 35°C
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
(1) - Using first initial condition:
\(\text{Avg temp =} \ \frac{50+45}{2}=\boxed{47.5 \textdegree C}\\\\\Longrightarrow \frac{50-45}{3}=-k(47.5-T_a) \\\\\Longrightarrow \boxed{ \frac{5}{3}=-k(47.5-T_a)}\)
(2) - Using the second initial condition:
\(\text{Avg temp =} \ \frac{45+40}{2}=\boxed{42.5 \textdegree C}\\\\\Longrightarrow \frac{45-40}{5}=-k(42.5-T_a) \\\\\Longrightarrow \boxed{1=-k(42.5-T_a)}\)
(3) - Now we have a system of equations.
\(\left \{ \frac{5}{3}=-k(47.5-T_a)}} \atop {1=-k(42.5-T_a)}}} \right.\)
(4) - Solve the system by dividing the top equation by the bottom equation.
\(\Longrightarrow \frac{\frac{5}{3}=-k(47.5-T_a)}{1=-k(42.5-T_a)} \\\\\Longrightarrow\frac{5}{3}=\frac{47.5-T_a}{42.5-T_a}\\ \\ \Longrightarrow 5(42.5-T_a)=3(47.5-T_a)\\\\\Longrightarrow 212.5-5T_a=142.5-3T_a\\\\\Longrightarrow 2T_a=70\\\\\therefore \boxed{T_a=35 \textdegree C}\)
Thus, the ambient temperature is 35°C.
(5) - Find the value of "k" using either of the two previous equations
\(1=-k(42.5-T_a)\\\\\Longrightarrow 1=-k(42.5-35)\\\\\Longrightarrow 1=-7.5k\\\\\Longrightarrow \boxed{ k \approx -0.133}\)
(6) - Now finding "dt"
\(\text{Avg temp =} \ \frac{40+35}{2}=\boxed{37.5 \textdegree C}\\\\\Longrightarrow \frac{40-35}{dt}=0.133(37.5-35) \\\\\Longrightarrow \frac{5}{dt}=0.3325\\\\\therefore \boxed{dt \approx15 \ min}\)
Thus, it take 15 minutes to cool the substance from 40°C to 35°C.
A 4 newton lamp
is lifted 2 meters.
How much work
was done?
Answers
Answer:
The answer is 8 JExplanation:
The work done by an object can be found by using the formula
workdone = force × distanceFrom the question we have
workdone = 4 × 2
We have the final answer as
8 JHope this helps you
Ferdinand the frog is hopping from lily pad to lily pad in search of a good fly
for lunch. If the lily pads are spaced 2.4 m apart, and Ferdinand jumps with a
speed of 5.4m/s, taking 0.60 s to go from lily pad to lily pad, at what angle
must Ferdinand make each of his jumps?
Answers
Answer:
θ = 33°
Explanation:
Here, we can use the formula for the total time of flight of a projectile to calculate the launch angle of frog:
\(T = \frac{2\ u\ Sin\theta}{g} \\\\Sin\theta = \frac{Tg}{2u}\)
where,
θ = launch angle = ?
T = Total time of flight = 0.6 s
g = acceleration due to gravity = 9.81 m/s²
u = launch speed = 5.4 m/s
Therefore,
\(Sin\theta = \frac{(0.6\ s)(9.81\ m/s^2)}{(2)(5.4\ m/s)}\\\\\theta = Sin^{-1}(0.545)\)
θ = 33°
Hello! Please help me! I will give brainliest! An engineering company needs to solve a design problem.
It is designing a high-speed train to transport passengers
between Boston and Atlanta
Which statement is a constraint for this project?
A. The train must meet a strict set of safety guidelines.
B. The train must be able to operate during rainy weather.
C. The train must provide a smooth ride for passenger comfort.
D. The train design must be completed in 12 months
Answers
Answer:
The train company has to consider the speed of the design
Explanation:
in the question it says it's designing a high-speed train so the speed takes priority because that's the main goal
Answer:
D
Explanation:
expert to teach me how to calculate half life in physics
Answers
The half-life of a radioactive substance is defined as the time required for the substance to reduce to half of its initial number of atoms.
The half-life is given by,
\(t_{\frac{1}{2}}=\frac{ln2}{\lambda}\)Where λ is the decay constant.
The figure illustrates flow through a pipe with diameters of 1.0 mm and 2.0 mm and with different elevations. Px is the pressure in the pipe, and Vx is the speed of a non-viscous incompressible fluid at locations x = Q,R,S,T, or U. Options are: Greater than, Less than, Equal to
PU is ... PQ
VU is ... 2VT
PR is ... PU.
VR is ... VS
VQ is ... VU
PR is ... PS
Answers
a.
i. PU is greater than PQ.ii. VU is Greater than 2VTb.
i. PR is Equal to PU.ii. VR is Equal to VSc.
i. VQ is Equal to VUii. PR is Greater than PS.What is pressure?Pressure is the force per unit area on a surface.
What is speed?Speed is the distance moved per unit time.
Pressure
Since pressure, P = hρg where
h = depth, ρ = density of liquid and g = acceleration due to gravity.Since ρ and g are constant
P ∝ h
So, we see that pressure is directly proportional to depth.
a. i. Pressure between R and USince U is lower than Q, Pressure at U is greater than pressure at Q.
So,PU is greater than PQ.
ii. Speed between U and TUsing the continuity equation
VUAU = VTAT where
VU = speed at U, AU = cross-sectional area at U = π(dU)² where dU = diameter at U = 1.0 mmVUT= speed at T, AT = cross-sectional area at T = π(dT)² where dT = diameter at T = 2.0 mmSo, VUAU = VTAT
VUπ(dU)² = VTπ(dT)²
VU = VT(dT)²/(dU)²
VU = VT(2.0)²/(1.0)²
VU = VT(4)
VU = 4VT
Since VU = 4VT,VU is Greater than 2VT
b i. Pressure between R and USince R is at the same depth as U, Pressure at R is equal to pressure at U.
So,PR is Equal to PU.
ii. Speed between R and SUsing the continuity equation
VRAR = VSAS where
VR = speed at R, AR = cross-sectional area at R = π(dR)² where dR = diameter at R = 2.0 mmVS= speed at S, AS = cross-sectional area at S = π(dS)² where dS = diameter at S = 2.0 mmSo, VRAR = VSAS
VRπ(dR)² = VSπ(dS)²
VR = VS(dS)²/(dS)²
VR = VS(2.0)²/(2.0)²
VR = VS(1)
VR = VS
Since VR = VS,VR is Equal to VS
c. i. Speed between Q and UUsing the continuity equation
VQAQ = VUAU where
VQ = speed at Q, AQ = cross-sectional area at Q = π(dQ)² where dQ = diameter at Q = 1.0 mmVU = speed at U, AU = cross-sectional area at U = π(dU)² where dU = diameter at U = 1.0 mmSo, VQAQ = VUAU
VQπ(dQ)² = VUπ(dU)²
VQ = VU(dU)²/(dQ)²
VQ = VU(1.0)²/(1.0)²
VQ = VU(1)
VQ = VU
Since VQ = VU, VQ is Equal to VU
Ii. Pressure between R and SSince R is lower than S, Pressure at R is greater than pressure at S.
So,PR is Greater than PS.
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1. How would the forces from a header with such a light soccer ball cause a concussion? Draw
Two free body diagrams showing how the amount of peak force on the head would compare
to the amount of peak force on a soccer ball in a header that causes a collision.
Answers
Answer:
soccer when the ball hits an unprepared player in the head. He also gave examples of concussions occurring when players accidentally knock their heads into other players while attempting to head the ball, particularly if they are attempting to flick the ball backwards.
Explanation:
Heading in soccer can increase your risk of concussions. Over time, repeated subconcussive injuries can also accumulate and cause brain damage.
What average net force is required to accelerate a 375 kg motorcycle initially at rest to a speed of 25.5 m/s over a distance of 174 m?
Answers
Answer:
700.7N
Explanation:
m = 375
x = 174
v = 25.5
a = ?
\( {v}^{2} = 2ax\)
F = ma
We substitute a
F = m * (v^2 /(2x))
F = 375 * 25.5^2/(2*174)
F = 700.7 N
Average net force is required to accelerate a 375 kg motorcycle initially at rest to a speed of 25.5 m/s over a distance of 174 m is 700.7 N
What is force?The push or pull on a mass-containing item changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.
Given in the question motorcycle of mass, m = 375 kg covers a distance of x = 174 m have initial velocity zero and final velocity, v = 25.5 m/sec then the acceleration a,
\(v^{2} = 2ax\)
\(a= v^{2} / 2x\)
Force required to accelerate,
F = ma
substitute a
F = m * \((v^2 /(2x))\)
F = 375 * \(25.5^2/(2*174)\)
F = 700.7 N
So the average net force required to accelerate motorcycle, F = 700.7 N.
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Describe the setup of the electromagnet. Why does the wire need to be a conductive material?
Answers
An electromagnet consists of a conductive wire wrapped around a magnetic core, creating a magnetic field when an electrical current is passed through it.
An electromagnet is a type of magnet that is created by running an electrical current through a wire. The setup of an electromagnet involves a few basic components. First, there must be a wire that is conductive, meaning that it can conduct electricity. This wire is usually wrapped around a core, which is often made of iron, steel, or another magnetic material. When an electrical current is run through the wire, it creates a magnetic field around the wire. This magnetic field then magnetizes the core, creating an even stronger magnetic field. The strength of the electromagnet can be controlled by adjusting the amount of current that is run through the wire. The wire must be a conductive material because it needs to be able to carry the electrical current that creates the magnetic field. If the wire were not conductive, then the electrical current would not be able to flow through it, and the magnetic field would not be created. In summary, the setup of an electromagnet involves a conductive wire wrapped around a magnetic core, which is magnetized by the electrical current running through the wire. The wire must be conductive to carry the electrical current and create the magnetic field.For more questions on electromagnet
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(Figure 1) is the potential-energy diagram for a 500 g particle that is released from rest at A . What is the particle's speed at B ?
Answers
Answer:
Explanation:
according to the graph at B the potential energy of the particle is 2J
therefore we can use the kinetic energy equation to calculate the particle's velocity or speed.
\(E_{k} =1/2mv^{2}\)
2J= 1/2*1/2kg*v^2
8=v^2
v= 2√2 ms-1
I need help with this please
Answers
Answer:
Rahman was a little bit 5AM but I think he was just try and the guy was the one who just got a a??ze and you know how are you to me that you
Would you rather live but never be treated right or pass away and let others you love be treated right and have a good life?
Answers
Answer:I would say live but not be treated right.
Explanation: My opinion.
Answer:
I would rather pass away and let my love ones have a good life
Explanation:
Water flows through a valve with inlet and outlet velocities of 3 m/s. If the loss coefficient of the valve is 2.0, and the specific weight of water is 9800 N/m3, the pressure drop across the valve is most nearly:
Answers
Answer:
The value is \(\delta P = 9000 \ Pa\)
Explanation:
From the question we are told that
The inlet and outlet velocity is \(v = 3 \ m/s\)
The loss coefficient is \(k = 2\)
Th specific weight of water is \(w = 9800 \ N/m^3\)
Generally the pressure drop across the valve is mathematically represented as
\(\delta P = \frac{1}{2} * k * \rho * v^2\)
Here \(\rho\) is the density which is mathematically represented as
\(\rho = \frac{w}{g}\)
=> \(\rho = \frac{9800}{9.8}\)
=> \(\rho = 1000 \ kg/m^3\)
So
\(\delta P = \frac{1}{2} * 2* 1000 * 3^2\)
\(\delta P = 9000 \ Pa\)
Describe 2 ways in which a giant boulder by the ocean may change over time.
Answers
Answer:
I'm not sure if they're right but...
1. It would erode because of the water
2. It would probably become a home for the ocean creatures
The two (2) ways in which a giant boulder by the ocean may change over time are:
1. The ocean water would change the boulder's appearance and texture.
2. The giant boulder would be transformed into sediments due to erosion and weathering through dissolution.
A boulder can be defined as a large (giant) rounded mass of rock fragment that is formed through its detachment from a parent consolidated rock, especially due to erosion and weathering.
Basically, the size of a boulder is greater than 256 millimeters (25.6 centimeters or 10.1 inches) in diameter.
The reason why giant (large) boulders are present in steep mountain streams or oceans is mainly because they are usually too heavy for them to be moved by the body of water.
This ultimately implies that, water cannot move a giant (large) boulder that is present in an ocean because of its size and weight.
However, a giant (large) boulder that is present in an ocean would be affected in these two (2) ways:
Ocean water would change the boulder's appearance and texture. The giant boulder would be transformed into sediments due to the actions of erosion and weathering through dissolution.
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A team of dogs is pulling a person in a sled in the snow. The dogs are attached by a harness that is parallel to the ground. The combined mass of the person and the sled is 62.5 kg.The coefficient of kinetic friction is 0.190 ,and the harness tension is 180.0 N. Determine the sled’s acceleration.
Answers
The acceleration of the sled of combined mass 62.5 kg is 1.018 m/s².
What is acceleration?Acceleration is the rate of change of velocity.
To calculate the acceleration of the sled, we use the formula below.
Formula:
a = (T-mgη)/m............... Equation 1Where:
a = Acceleration of the sledm = Mass of the person and the sledT = Tension pn the hernessg = Acceleration due to gravityη = Coefficient of kinetic frictionFrom the question,
Given:
T = 180 Nm = 62.5 kgg = 9.8 m/s²η = 0.19Substitute these values into equation 1
a = [180-(62.5×9.8×0.19)]/62.5a = (180-116.375)/62.5a = 1.018 m/s²Hence, the acceleration of the sled is 1.018 m/s².
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Match the Erikson stage with the example and the Piaget stage with example. This is a little harder but will be good practice for
your exam.
✓identity vs role confusion
✓ concrete operational stage
✓ sensorimotor stage
✓integrity vs despair
✓ intimacy vs isolation
A. Mo does not know what he wants to do after graduation.
Maybe join the army, maybe go to Wake Take?
B. Mo is an older adult and is questioning all of the
accomplishments he completed in life.
C. Mo is beginning to acquire motor skill and develop object
permanence.
D. Mo is developing healthy friendships but is still struggling
with forming a relationship with a significant other.
E. Mo can think logically and has mastered the law on
conservation.
Answers
A. Identity vs role confusion: Mo's uncertainty about post-graduation plans.
B. Integrity vs despair: Mo's questioning of life accomplishments as an older adult.
C. Sensorimotor stage: Mo's development of motor skills and object permanence.
D. Intimacy vs isolation: Mo's struggle with forming relationships.
E. Concrete operational stage: Mo's ability to think logically and understand conservation.
A. The example matches with the Erikson stage of "identity vs role confusion." During this stage, individuals go through a period of exploration and self-discovery to establish a sense of identity and determine their roles and goals in life. Mo's uncertainty about what he wants to do after graduation reflects the challenges and decision-making processes associated with identity formation.
B. The example matches with the Erikson stage of "integrity vs despair." This stage occurs in late adulthood, where individuals reflect on their life choices, accomplishments, and experiences. Mo, as an older adult questioning his accomplishments, is facing the task of finding a sense of integrity and satisfaction with the life they have lived or experiencing feelings of despair and regret.
C. The example matches with the Piaget stage of "sensorimotor stage." This stage occurs in infancy, where children develop coordination and motor skills and begin to understand object permanence, which is the understanding that objects continue to exist even when they are out of sight. Mo's acquisition of motor skills and developing object permanence aligns with the characteristics of the sensorimotor stage.
D. The example matches with the Erikson stage of "intimacy vs isolation." This stage occurs during early adulthood, where individuals seek to form deep and meaningful relationships with others. Mo's struggle with forming a relationship with a significant other reflects the challenges and conflicts associated with the intimacy vs isolation stage.
E. The example matches with the Piaget stage of "concrete operational stage." This stage occurs in middle childhood, where children develop logical thinking and can grasp the concept of conservation. Mo's ability to think logically and understand the law of conservation aligns with the characteristics of the concrete operational stage.
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Compare and contrast, in detail, at least two types of pluralism. Do you think the United States is becoming more pluralistic? Why or why not? How do ethnic enclaves relate to pluralism in the US?
Answers
a. There are two main types of pluralism: cultural and political
b. Yes, the United States is becoming more pluralistic
c. Ethnic enclaves can be both a positive and negative aspect of pluralism in the US.
a. Pluralism refers to the coexistence of multiple cultures, religions, and ethnicities within a society. There are two main types of pluralism: cultural and political. Cultural pluralism emphasizes the preservation of distinct cultural traditions, while political pluralism emphasizes the equal representation of different groups within the political system.
Cultural pluralism is often associated with the idea of multiculturalism, which recognizes and celebrates the diversity of different cultures. This type of pluralism acknowledges the importance of cultural differences and encourages individuals to maintain and express their cultural identities. In contrast, political pluralism emphasizes the importance of equal representation of different groups within the political system. This can take the form of proportional representation in government or equal access to political power for different groups.
b. The United States is becoming more pluralistic, as the population becomes more diverse and the importance of multiculturalism and political pluralism is increasingly recognized. The country is home to many different ethnic and cultural groups, and these groups are increasingly visible in politics and society. This is evident in the increasing number of ethnic and cultural enclaves, which are areas where different ethnic groups live in close proximity to one another.
c. Ethnic enclaves can be both a positive and negative aspect of pluralism in the US. On the one hand, they allow individuals to maintain their cultural traditions and create supportive communities. On the other hand, they can also lead to segregation and exclusion, as different groups may be reluctant to interact with one another. In order to promote a positive form of pluralism, it is important to encourage interaction and understanding between different groups, while also respecting and celebrating their distinct cultural identities.
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Can someone please help me I don’t understand this please show work plus I got it wrong it’s not C
Answers
The 25 N and 5 N force are acting in the same direction so we can add them together, but the 10 N force acts in the opposite direction so you subtract it.
25 N + 5 N - 10 N = 20 N
depth of a pond seems shallower than real depth,why?
Answers
Answer:
The refraction of light at the surface of water makes ponds and swimming pools appear shallower than they really are. A 1m deep pond would only appear to be 0.75 m deep when viewed from directly above. When light emerges from glass or water into air it speeds up again.
Explanation:
Answer:
The property of light is the refraction of light because when light travels from a denser medium to rarer medium it bends away from the normal. The apparent depth of water is always less than the real depth of the water. Hence, water appears to be shallower than the real depth.
What is the medium of the wave shown in the photograph?
A. The water
B. Kinetic energy
C. The duck
D. Gravity
Answers
Answer:
A. The water
Explanation:
i got it right on A-P-E-X
______________________ are hardy and survive freezing and relatively high temperatures and chlorination up to 10 ppm.
Norovirus
Salmonella
E. coli
Listeria
Answers
Norovirus is correct option that are hardy and survive freezing and relatively high temperatures and chlorination up to 10 ppm.
The most typical reason for gastroenteritis is norovirus, sometimes known as the winter vomiting illness. Vomiting, non-bloody diarrhoea, and stomach discomfort are signs of infection. There may also be a fever or a headache. After exposure, symptoms often appear 12 to 48 hours later, and recovery normally takes one to three days. Dehydration is a common complication, particularly in children, the elderly, and people who already have other health issues.The fecal-oral pathway is typically used to disseminate the virus. This could happen as a result of tainted food, water, or interpersonal interaction. It can also spread through the air from an infected person's vomit or through contaminated surfaces. Unhygienic food preparation and close quarters sharing are risk factors. Symptoms are typically used to make a diagnosis. Although confirmation testing is not frequently accessible, public health organisations may carry it out during epidemics.
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a 250.0 g snowball of radius 4.00 cm starts from rest at the top of the peak of a roof and rolls down a section angled at 30.0 degrees
Answers
Answer:
The response to this question is as follows:
Explanation:
The whole question and answer can be identified in the file attached, please find it.
The force diagram of all the forces acting on the snowball include the normal force acting upwards, the weight of the snowball acting downwards and the frictional force acting horizontal.
The given parameters;
mass of the snow ball, m = 250 gradius of the snow ball, r = 4 cmangle of inclination of the plane, θ = 30 ⁰The force diagram of all the forces acting on the snowball is calculated as follows;
↑ N
⊕ → F
↓ W
Where;
N is the normal force on the snowballF is the frictional force on the snowballW is the weight of the ballThus, the force diagram of all the forces acting on the snowball include the normal force acting upwards, the weight of the snowball acting downwards and the frictional force acting horizontal.
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A Student 330 m 990m from another tall flip between the the Student stands Sound Interval beteeen cliff is cliff from of 1 st and 630 tall Hip which speed of 330 if the 330 m/s 2nd eh what is echo?
Answers
The interval between the first and second echo is 7 seconds. This means that after the initial sound wave reaches the first cliff, it takes a total of 7 seconds for the sound to travel to the second cliff and then return to the student as the second echo.
To determine the interval between the first and second echo, we need to consider the time it takes for sound to travel from the student to the first cliff, and then from the first cliff to the second cliff, and finally back to the student.
Let's break down the distances and calculate the time for each part of the journey:
Distance from the student to the first cliff: 330 meters
Time taken: t₁ = distance / speed = 330 m / 330 m/s = 1 second
Distance from the first cliff to the second cliff: 990 meters
Time taken: t₂ = distance / speed = 990 m / 330 m/s = 3 seconds
Distance from the second cliff back to the student: 990 meters
Time taken: t₃ = distance / speed = 990 m / 330 m/s = 3 seconds
Now, we can calculate the total interval between the first and second echo by adding up the individual times:
Interval between first and second echo = t₁ + t₂ + t₃ = 1 s + 3 s + 3 s = 7 seconds
Therefore, the interval between the first and second echo is 7 seconds. This means that after the initial sound wave reaches the first cliff, it takes a total of 7 seconds for the sound to travel to the second cliff and then return to the student as the second echo.
It's important to note that this calculation assumes a straight path for the sound waves and neglects factors such as air temperature and wind that can affect the speed of sound. Additionally, it assumes perfect reflection of sound waves off the cliffs, which may not be the case in real-world scenarios.
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Note the complete questions is:
A student stands 330m from a tall cliff which is 990m from another tall cliff. If the speed of sound between the cliffs is 330m/s.What is the interval between the first and second echo?
Two cars start moving from the same point. One travels south at 60 miyh and the other travels west at 25 miyh. At what rate is the distance between the cars increasing two hours later?
Answers
Answer:
65 m/h
Explanation:
Let the distance of the car moving south be y.
Let the distance of the car moving west be x.
Let the distance between the two cars be a.
These three distances can be represented as a right angled triangle. So we can say:
\(a^2 = x^2 + y ^2\)
Let us differentiate with respect to time, since the distances are changing with respect to time:
\(2a\frac{da}{dt} = 2x\frac{dx}{dt} + 2y\frac{dy}{dt} \\\\=>a\frac{da}{dt} = x\frac{dx}{dt} + y\frac{dy}{dt}\)__________(1)
da/dt = rate of change of distance between two cars
The speed of the car moving south (dy/dt) is 60 m/h and the speed of the car moving west (dx/dt) is 25 m/h.
Therefore:
dy/dt = 60 m/h and dx/dt = 25 m/h
After two hours, the distance of the two cars will be:
y = 2 * 60 = 120 miles
x = 2 * 25 = 50 miles
Therefore:
\(a^2 = 50^2 + 120^2\\\\a^2 = 2500 + 14400 = 16900\\\\a = \sqrt{16900}\\ \\a = 130 miles\)
From (1):
130(da/dt) = 50(25) + 120(60)
130(da/dt) = 1250 + 7200 = 8450
da/dt = 8450/130 = 65 m/h
Therefore, after two hours, the distance between the two cars is changing at a rate of 65 m/h.
A 4 kg box is at rest on a table. The static friction coefficient u, between the box and table is 0.30, and
the kinetic friction coefficient Hi is 0.10. Then, a 10 N horizontal force is applied to the box.
Answers
Answer:
The box will not move from its position.
Explanation:
First, we will calculate the static frictional force that is stopping the box to move from its position:
\(f = \mu R = \mu W=\mu mg\)
where,
f = static frictional force = ?
μ = coefficient of static friction = 0.3
m = mass of box = 4 kg
g = acceleration due to gravity = 9.81 m/s²
Therefore,
\(f = (0.3)(4\ kg)(9.81\ m/s^2)\\f=11.77\ N\)
Since the frictional force (11.77 N) is greater than the applied force (10 N).
Therefore, the box will not move from its position.
The hockey stick hits the puck forward. Give the reaction force
Answers
I think the puck pushes the stick backwards