The product of two numbers is 144 and their difference is 10 what are the numbers​

Answers

Answer 1

Answer:

26

Step-by-step explanation:

let the two numbers be X and Y

XY = 144

X - Y = 10

(X + Y)^2 = ( X - Y)^2 + 4 XY

= 100 + 576 = 676

(X+Y) = √676

X + Y = 26


Related Questions

Please Help me - You will get 60 points for the rapid reply- Use isosceles trapezoid ABCD to determine the following measurements-

Please Help me - You will get 60 points for the rapid reply- Use isosceles trapezoid ABCD to determine

Answers

Answer:

1) AD = 9 in

2) DE = 9.25 in

3) ∠EDC = 36°

4) ∠AEB = 108°

5) 11.5 in

Step-by-step explanation:

1) AD = BC = 9in

2) AC = BD (diagonals are equal)

⇒ BD = 14.25

⇒ BE + DE = 14.25

⇒ 5 + DE = 14.25

DE = 9.25

3) Since AB ║CD,

∠ABE = ∠EDC = 36°

4) ∠ABE = ∠BAE = 36°

Also ∠ABE + ∠BAE + ∠AEB = 180 (traingle ABE)

⇒ 36 + 36 + ∠AEB = 180

∠AEB = 108

5) midsegment = (AB + CD)/2

= (8 + 15)/2

11.5

Suppose K⊆Rn is compact, f:K→R is continuous, and ϵ>0. Show that there is a number A>0 such that
|f(x)−f(y)|≤A∥x−y∥+ϵ,∀x,y∈K.

Answers

By using the concept of compact set, it can be proved that

|f(x)−f(y)|≤A∥x−y∥+ϵ,∀x,y∈K.

What is compact set?

A set K is said to be compact if every open cover of K has a finite subcover.

Let K⊆Rn is compact  f:K→R is continuous, and ϵ>0

Let there exist \(x_n, y_n\) ∈ K such that |f(\(x_n\))−f(\(y_n\))| > n∥\(x_n\)−\(y_n\)∥+ϵ,

Since K is compact there is a subsequence \(x_{nk}\) and \(y_{nk}\) of \(x_n, y_n\) respectively such that \(x_{nk}\) converges to x and \(y_{nk}\) converges to y.

So,  |f(\(x_{nk}\))−f(\(y_{nk}\))| > \(n_k\)∥\(x_{nk}\)−\(y_{nk}\)∥+ϵ,

Since f is continuous,

We can write

|f(x)−f(y)| > \(n_k\)∥x - y∥+ϵ,

This is true for infinite many \(n_k\)

So ||x - y|| = 0

|f(x) - f(y)| > ϵ, a contradiction since f is continuous

So,  there is a number A>0 such that

|f(x)−f(y)|≤A∥x−y∥+ϵ,∀x,y∈K.

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consider the grid of points shown here. suppose that, starting at the point labeled a, you can go one step up or one step to the right at each move. this procedure is continued until the point labeled b is reached. how many different paths from a to b are possible?

Answers

The following is an excerpt from A First Training in Probability by Sheldon Ross. (74) = 35 is the right response.

Total moves required are 7, as follows:

Three steps up as well as four steps right.

Remember that perhaps the number of paths equals the number of arranged 7-tuples with 3 U's and 4 R's. As instance, the word URRURRU indicates to travel up, right, up, right, right, up.

There are 7 ways to arrange these letters, 7 ways to arrange the corresponding Us, and 7 ways to arrange the comparable Rs, for a total of 7!3!4! (74).

For each NxN grid, we may write the following as a generalization of our formula: It should be noted that there's a simpler method of writing this: D = N! / (K! * (N-K))! additionally known as the binomial coefficient.

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Help !!!! heres the picture for it

Help !!!! heres the picture for it

Answers

Using the proportional rule of Similar Triangles, the length of SD is 12 m.

Given a truss bridge.

From it,

The triangles BCD and RSD are similar.

For similar triangles, corresponding sides are proportional.

Corresponding sides are,

BC and RS, CD and SD, BD and RD.

BC / RS = CD / SD = BD / RD.

Consider BC / RS = CD / SD.

2 / 1 = 24 / SD

2 (SD) = 24

SD = 12

Hence the length of SD is 12 m.

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compute the complement 0.87

Answers

The complement of 0.87 is calculated by subtracting the given number from 1. Mathematically, this can be expressed as 1 - 0.87 = 0.13.

The complement of any number x is calculated by subtracting x from 1. This means that the complement of 0.87 is 0.13.

The complement of a number is used to find the remaining portion of a whole. For example, if the given number is 0.87, then the complement of 0.87 is 0.13. This means that 0.87 is 87% of the whole and 0.13 is the remaining 13%. Thus, the complement of 0.87 is 0.13.

Complements can also be used to find the probability of something happening. For example, if the probability of an event occurring is 0.87, then the probability of it not occurring is 0.13. This is because the sum of the probabilities must equal 1 (100%). Therefore, the complement of 0.87 is 0.13.

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Line segment ON is perpendicular to line segment ML. Line segment OM=14 units in length. What is the length of chord ML? Round your answer to the nearest hundredth

Line segment ON is perpendicular to line segment ML. Line segment OM=14 units in length. What is the

Answers

Step-by-step explanation:

i don't know

I don't have a calculator

i will put brailly helpppppppppppppppppppppppppppppppppppppppppp

i will put brailly helpppppppppppppppppppppppppppppppppppppppppp

Answers

Answer:

1. Even Chance

2. Even Chance

3. No Chance

4. No Chance

5. Even Chance

(NOT SURE)

(but im sure)

Consider a continuous random variable x, which is uniformly distributed between 65 and 85. The probability of x taking on a value between 75 to 90 is ________.

Answers

We will see that the probability of x taking on a value between 75 to 90 is P = 0.5

How to get the probability?

We know that x is a continuous random variable uniformly distributed between 65 and 85.

This means that the probability that x value y in the range is such that:

1 = P(y)*(85 - 65) = P(y)*20

1/20 = P(y).

Now, the probability of x taking a value between 75 and 85 is:

P(75 to 85) = (1/20)*(85 - 75) = 10/20 = 0.5

And the probability between 85 and 90 is zero (because the maximum value that x can take is 85, so this part does not affect).

Then we conclude that the probability of x taking a value between 75 to 90 is:

P(75 to 90) = P(75 to 85) + P(85 to 90) = 0.5 + 0 = 0.5

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Rewrite the function by completing the square.
f(x) = x2 – 2x – 95

Rewrite the function by completing the square.f(x) = x2 2x 95

Answers

f(x) = x^2 - 2x - 95
solving by completing the square: f(x) = ( x - 1 ) ^2 - 96,

Find the area of the region inside the circle r=4cos(theta) and outside the circle r=2.

Answers

Area of the region inside the circle r=4cos(theta) and outside the circle r=2 is 4π/3 + 2√3

What is the polar curve?

A form created using the polar coordinate system is called a polar curve. Points on polar curves have varying distances from the origin (the pole), depending on the angle taken off the positive x-axis to calculate distance. Both well-known Cartesian shapes like ellipses and some less well-known shapes like cardioids and lemniscates can be described by polar curves.

r = 1 − cosθsin3θ

Polar curves are more useful for describing paths that are an absolute distance from a certain point than Cartesian curves, which are good for describing paths in terms of horizontal and vertical lengths. Polar curves can be used to explain directional microphone pickup patterns, which is a useful application. Depending on where the sound is coming from outside the microphone, a directional microphone will take up sounds with varied tonal characteristics. A cardioid microphone, for instance, has a pickup pattern like a cardioid.

The area between two polar curves can be found by subtracting the area inside the inner curve away from the area inside the outer curve.

The figure attached shows the bounded region of the two graphs. The red curve is  r=4cos⁡(θ) and the blue curve is r=2.

The points of intersection of the two curves are

θ = π/3 and 5π/3

The area is calculated as follows:

Since the bounded region is symmetric about the horizontal axis, we will find the area of the top region, and then multiply by 2, so as to get the total area.

A = 2 \(\(\int_{0}^{\pi /3}\) ½ (4 cos (θ)² − ½ (2)² dθ

  =  \(\(\int_{0}^{\pi /3}\) 16 cos2 (θ) − 4dθ

  = \(\(\int_{0}^{\pi /3}\) 8 (1+cos(2θ)) − 4dθ

  =\(\(\int_{0}^{\pi /3}\) 4 + 8 cos (2θ) dθ

  = [4θ + 4sin (2θ)] \(\(\int_{0}^{\pi /3}\)

  = 4π/3 + 2√3

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Find the area of the region inside the circle r=4cos(theta) and outside the circle r=2.

(1 point) Compute the double integral slo 4xy dx dy ' over the region D bounded by = 1, 2g = 9, g" = 1, y = 36 = - -> in the first quadrant of the cy-plane. Hint: make a change of variables T :R2 +

Answers

The double integral of 4xy dx dy over the region D, bounded by x = 1, 2x + y = 9, y = 1, and y = 36 in the first quadrant of the xy-plane, can be computed using a change of variables. The final answer is 540.

To perform the change of variables, let's define a new coordinate system u and v such that:

u = x

v = 2x + y

Next, we need to determine the new limits of integration in terms of u and v. From the given boundaries, we have:

For x = 1, the corresponding value in the new system is u = 1.

For 2x + y = 9, we can solve for y to get y = 9 - 2x. Substituting the new variables, we have v = 9 - 2u.

For y = 1, we have v = 2u + 1.

For y = 36, we have v = 2u + 36.

Now, let's calculate the Jacobian determinant of the transformation:

J = ∂(x, y) / ∂(u, v) = ∂x / ∂u * ∂y / ∂v - ∂x / ∂v * ∂y / ∂u

  = 1 * (-2) - 0 * 1

  = -2

Using the change of variables, the double integral becomes:

∫∫(4xy) dxdy = ∫∫(4uv)(1/|-2|) dudv

           = 2∫∫(4uv) dudv

           = 2 ∫[1,9] ∫[2u+1,2u+36] (4uv) dvdx

           = 2 ∫[1,9] [8u^3 + 35u^2] du

           = 2 [(2u^4/4 + 35u^3/3)]|[1,9]

           = 2 [(8*9^4/4 + 35*9^3/3) - (2*1^4/4 + 35*1^3/3)]

           = 2 (7776 + 2835 - 1 - 35/3)

           = 540

Therefore, the double integral of 4xy dx dy over the given region D is equal to 540.

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in short bingo, a $5\times5$ card is filled by marking the middle square as wild and placing $24$ other numbers in the remaining $24$ squares. specifically a card is made by placing $5$ distinct numbers from the set $1-10$ in the first column, $5$ distinct numbers from $11-20$ in the second column, $4$ distinct numbers $21-30$ in the third column (skipping the wild square in the middle), $5$ distinct numbers from $31-40$ in the fourth column and $5$ distinct numbers from $41-50$ in the last column. one possible short bingo card is: to play short bingo, someone names numbers, chosen at random, and players mark those numbers on their cards. a player wins when he marks $5$ in a row, horizontally, vertically, or diagonally. how many distinct possibilities are there for the values in the first column of a short bingo card? (the placement on the card matters, so the order of the numbers matters, so $5~4~3~2~1$ is to be considered different from $1~2~3~4~5$, for instance.)

Answers

The number of distinct possibilities for the values in the first column of a short bingo card is = 10000

According to the data given in the question,

The middle square is contained with the word = WILD

Number of remaining squares = 24

Total number of choices given to an individual = 4

Number of options provided for each choice made = 10

Let N denote the number of choices,

In order to find the number of choices we will use the following formula,

N = \(Number of options^{Number of choices}\)

N = \(10^{4}\)

N = 10000

Therefore, the number of distinct possibilities for the values in the first column of a short bingo card is = 10000

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in short bingo, a $5\times5$ card is filled by marking the middle square as wild and placing $24$ other

if a sample of 7 keyboards is randomly selected, what is the probability that at least 6 of these will have a mechanical defect? (round your answer to four decimal places.) 0.0134 incorrect: your answer is incorrect.

Answers

The probability that at least 6 of these will have a mechanical defect is 0.1612.

What is referred as the combination?The combination formula is used when we need to discover the number of ways to select a group of items from the a higher proportion of items. If n is the amount of items in the pool and r is the amount of items to be chosen from the pool, then nCr gives the number of ways to do this, which can be calculated as; nCr = n!/r!(n-r)!.

For the given question;

At least six of the seven chosen has to have a mechanical defect.

So we add this same cases with exactly 6 mechanical defects and the cases with exactly 7 mechanical defects.

Number of possible approaches = ⁶C₂ + ¹⁹C₇ = 6!/2!4! + 19!/7!2!

= 27132 + 50388

= 77, 520

Calculated the total number of options to pick the seven keyboards as;

²⁵C₇ = 25!/7!18!

²⁵C₇ = 480,700.

As a result, the necessary probability = 77, 520/480,700 = 0.1612.

Thus, the probability that at least 6 of these will have a mechanical defect is 0.1612.

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The complete question is-

Computer keyboard failures can be attributed to electrical defects or mechanical defects. A repair facility currently has 25 failed keyboards, 6 of which have electrical defects and 19 of which have mechanical defects.

If a sample of 7 keyboards is randomly selected, what is the probability that at least 6 of these will have a mechanical defect? (Round the answer to four decimal places.)

Stone runs 1 mile five times a week. How many miles does 4 he run each week? Write the equation you would use to solve. Then, fill in the grid with your answer. Tip: Fill in your answer as a fraction greater than 1.

Answers

The number of miles in 4 weeks is 20 mules

How to determine the number of miles

From the question, we have the following parameters that can be used in our computation:

Stone runs 1 mile five times a week

This means that the rate is

Rate = 1 mile * 5 per week

So, we have

Rate = 5 miles per week

For 4 weeks, we have

Distance = 5 * 4

Evaluate

Distance = 20 miles

Hence, the distance is 20 miles

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Consider the plate dealt with in Example 8.1. Plot has a function of the angle of inclination of the plate as the hot side is tilted both upward and downward over the range +90°. Note that you must make do with discontinuous formulæ in different ranges of 0.

Answers

The question refers to the plot of the plate's function of the angle of inclination. When the hot side is tilted both upward and downward over the range of +90°, the discontinuous formulas must be used in different ranges of 0.

It refers to the plot of the function of the angle of inclination of a plate. It is a graph that shows the relationship between the angle of inclination and the plate's function. A plate is tilted on its hot side both upward and downward over a range of +90°. The graph shows that different discontinuous formulas are needed for different ranges of 0. A discontinuous formula refers to a formula that consists of two or more parts, each with a different equation. The two or more parts of a discontinuous formula have different ranges, such that each range requires a different equation. These formulas are used in cases where the same equation cannot be applied throughout the entire range.

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Zaheer, a boy of height 1.5m was watching the entire programme. Initially he observed the top of theflagpoleat an angle of elevation 300 . When he moved 10 m towards the flag post the angle of elevation of the top of the flagpole increased to 450. What is the height of the flag pole?

Answers

Answer:

\(h = 15.163\ meters\)

Step-by-step explanation:

(Assuming the correct angles are 30° and 45°)

We can use the tangent relation of the angle of elevation to find two equations, then we can use these equations to find the height of the pole.

Let's call the initial distance of the boy to the pole 'x'.

Then, with an angle of elevation of 30°, the opposite side to this angle is the height of the pole (let's call this 'h') minus the height of the boy, and the adjacent side to the angle is the distance x:

\(tan(30) = (h - 1.5) / x\)

Then, with an angle of elevation of 45°, the opposite side to this angle is still the height of the pole minus the height of the boy, and the adjacent side to the angle is the distance x minus 10:

\(tan(45) = (h - 1.5) / (x - 10)\)

So rewriting both equations using the tangents values, we have that:

\(0.5774 = (h - 1.5) / x\)

\(1 = (h - 1.5) / (x - 10) \rightarrow (h - 1.5) = (x - 10)\)

From the first equation, we have that:

\(x = (h - 1.5) / 0.5774\)

Using this value of x in the second equation, we have that:

\(h - 1.5 = \frac{ (h - 1.5) }{0.5774} - 10\)

\(h + 8.5 = \frac{ (h - 1.5) }{0.5774}\)

\(0.5774h + 4.9079 = h - 1.5\)

\(0.4226h = 6.4079\)

\(h = 15.163\ meters\)

solvable problems for which no polynomially bounded algorithms exist are called ____.

Answers

Solvable problems for which no polynomially bounded algorithms exist are called NP-hard problems.

In computer science, the class of problems known as NP (nondeterministic polynomial time) consists of decision problems that can be verified in polynomial time, meaning that the time it takes to verify a solution to the problem grows at most polynomially with the size of the input. NP-hard problems are a subset of NP that are at least as hard as the hardest problems in NP.

An algorithm for an NP-hard problem is considered polynomially bounded if the time it takes to solve the problem grows at most as a polynomial function of the size of the input. This means that for large inputs, the running time of the algorithm does not increase too quickly. NP-hard problems are of particular interest because, although they may not have a polynomial time solution, they can be used to model many real-world problems and can provide insights into the complexity of computational problems.

Examples of NP-hard problems include the traveling salesman problem, the subset sum problem, and the knapsack problem. These problems have been shown to be NP-hard through a process called reduction, in which a problem can be transformed into another problem that is known to be NP-hard. By showing that the original problem can be reduced to an NP-hard problem, it can be concluded that the original problem is also NP-hard.

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−8tan 1+tan2x Use appropriate identities to rewrite the following expression in terms containing only first powers of sine

Answers

By using Pythagorean identities the expression can be written as

         -8 (sin ( x ) + 1 -sin 2x)

The Pythagorean identity is an important identity in trigonometry derived from the Pythagorean theorem. These identities are used to solve many trigonometric problems where, given a trigonometric ratio, other ratios can be found. The basic Pythagorean identity, which gives the relationship between sin and cos, is the most commonly used Pythagorean identity:

sin2θ + cos2θ = 1 (gives the relationship between sin and cos)

There are two other Pythagorean identities as follows :

sec2θ - tan2θ = 1 (gives the relationship between sec and tan)

csc2θ - cot2θ = 1 (gives the relationship between csc and cot)

Given expression is:

-8tanx/ 1 +tan2x

we know that:

By the Pythagorean Theorem:

1 + tan²x = sec²x

and tan x = sin x/cos x

and, sec x = 1/cos x

Now, we can write as:

   -8tanx / 1 +tan²x

= -8 tan x / sec²x

= -8 sin x /cos x ÷ 1/cos²x

= -8 sin x/cos x × cos²x/1

= -8 (sin ( x ) + 1 -sin 2x)

Complete Question:

Use appropriate identities to rewrite the following expression in terms containing only first powers of sine:

−8tan 1 + tan2x.

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find angle A and angle B..​

find angle A and angle B..

Answers

Step-by-step explanation:

\(\sf{\bold{\blue{\underline{\underline{Given}}}}}\)

\(\tt{\angle{c}=110°}\)

and,

\(\tt{BC=AC}  \)

⠀⠀⠀⠀

\(\sf{\bold{\red{\underline{\underline{To\:Find}}}}}\)

☆Find the \(\angle{B} ~and~\angle{A}  \)

\(\sf{\bold{\purple{\underline{\underline{Solution}}}}}\)

Here,

BC =AC

so,

⠀⠀⠀

\(\angle{A}=\angle{B}  \)

we know that,

\(\tt{\boxed{\pink{\angle{A}+\angle{B}+\angle{C}=180°}}}  \)

But \(\angle{C}=110°  \)(Ģìvéñ)

so..

\(\angle{A}+\angle{B}+110°=180°  \)

\(\angle{A}+\angle{A}+110°=180°  \)

\(\because{\angle{A}=\angle{B} }  \)

\(2\angle{A}=180°-110°  \)

\(2\angle{A}=70°  \)

\(\angle{A}=\dfrac{70°}{2}  \)

\(\boxed{\orange{\angle{A}=35°}}  \)

But...

\(\angle{A}=\angle{B}  \)

soo,

\(\boxed{\orange{\angle{B}=35°}}  \)

\(\sf{\bold{\green{\underline{\underline{Answer}}}}}\)

⠀⠀⠀⠀

\(\boxed{\green{\angle{A}=35°}}  \)

\(\boxed{\green{\angle{B}=35°}}  \)

Determine if the question posed is a statistical question (yes) or not (no). What is 2 plus 2?

Answers

Answer:yes?

Step-by-step explanation:

it has #s in it lol

Answer:

no it isnt

Step-by-step explanation:

9m-m+3=-2(m+1)
this thing wants 20 characters so..HI!

Answers

Answer:

m = -1/2

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Equality Properties

Step-by-step explanation:

Step 1: Define

9m - m + 3 = -2(m + 1)

Step 2: Solve for m

Combine like terms:                    8m + 3 = -2(m + 1)Distribute -2:                                8m + 3 = -2m - 2Add 2m on both sides:                10m + 3 = -2Isolate m term:                             10m = -5Isolate m:                                      m = -1/2

pls answer not the first bit but second tyy

dont answe a b c d e do 2nd bit plss

pls answer not the first bit but second tyy dont answe a b c d e do 2nd bit plss

Answers

The nth term for a, b, c, d, e, are 2n+13, -3n + 18, 15- n, -2n, -5n respectively.

Describe Arithmetic Progression?

Arithmetic progression, also known as arithmetic sequence, is a series of numbers in which each term is obtained by adding a constant value, called the common difference (d), to the previous term. The constant difference can be either positive, negative, or zero. An arithmetic progression is denoted by {a, a + d, a + 2d, a + 3d, ...}, where 'a' is the first term and 'd' is the common difference.

For example, the following sequence is an arithmetic progression: {1, 3, 5, 7, 9, 11, ...}, where 'a' = 1 and 'd' = 2, since we are adding 2 to each previous term to obtain the next term.

Arithmetic progressions have several important properties. The nth term of an arithmetic progression can be calculated using the formula: a + (n-1)d, where 'a' is the first term, 'd' is the common difference, and 'n' is the term number. The sum of the first 'n' terms of an arithmetic progression can be calculated using the formula: Sn = (n/2)(2a + (n-1)d), where 'a' is the first term, 'd' is the common difference, and 'n' is the number of terms.

a) 15, 13, 11, 9, 7, ...

nth term: 2n + 13

b) 15, 12, 9, 6, 3, ...

nth term: -3n + 18

c) 15, 14, 13, 12, 11,...

nth term: 15 - n

d) -2, -4, -6, -8, -10, ...

nth term: -2n

e) -5, -10, -15, -20, -25, ...

nth term: -5n

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to determine the relative effectiveness of different study strategies for the sat, suppose three groups of students are randomly selected: one group took the sat without any prior studying; the second group took the sat after studying on their own from a common study booklet available in the bookstore; and the third group took the sat after completing a paid summer study session from a private test-prep company. the means and standard deviations of the resulting sat scores from this hypothetical study are summarized below: since we are comparing more than 2 groups, we will use anova to test whether the data provide evidence that sat score is related to study strategy. one of the conditions that allows us to use anova safely is that of equal (population) standard deviations. can we assume that this condition is met in this case?

Answers

We have to make a suspicion based on the given data. The standard deviations of the three bunches are not given within the address, so we cannot straightforwardly decide whether the condition of equal standard deviations is met. Be that as it may, ready to make a few taught surmises based on what we know almost each gather.

The primary gather, which did not think about, is likely to have a bigger change in scores than the other two bunches since understudies with shifting levels of arrangement and capacity took the test. Subsequently, we might anticipate the standard deviation of this group to be bigger than that of the other two bunches.

It is conceivable that the condition of rise to standard deviations isn't met. In case the condition of equal standard deviations isn't met, we may require to utilize an altered adaptation of ANOVA, such as Welch's ANOVA, which does not expect a rise in changes. 

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Which value is an input of the function?
O-14
O-2
O0
O 4

Which value is an input of the function?O-14O-2O0O 4

Answers

I have corona for real this is scary what if o dyeee will u miss me

Also answer is 04
Hope this helps
Hey
What’s wrong
The answer is 04 by they way this function stuff is hard

Which theorem proves that the two triangles are congruent?

Which theorem proves that the two triangles are congruent?

Answers

Answer: Side-Angle-Side Theorem (SAS)

Step-by-step explanation:

The Side-Angle-Side Theorem (SAS) states that if two sides and the angle between those two sides of a triangle are equal to two sides and the angle between those sides of another triangle, then these two triangles are congruent.

What is SSS congruence rules?

Answers

SSS congruence rules states that if three sides of one triangle are equal to the three sides of another triangle, then the two triangles are congruent.

The SSS (Side-Side-Side) congruence rule states that if three sides of one triangle are equal to the three sides of another triangle, equal, and the two triangles share the same dimensions then the two triangles are congruent. This means that all of the angles and sides of the two triangles are In order for two triangles to be congruent according to the SSS congruence rule, the lengths of the three corresponding sides of the two triangles must be equal. If all three of these conditions are met, then the two triangles are congruent and can be used to solve a variety of geometric problems.

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The SSS congruence rule is rule that is used to prove two triangles congruent . Its full form is Side-Side-Side Congruence .

The Two Triangles can be called as  Congruent Triangles if their sides have same length and the angles also have the same measure.

One of the 4 rules in proving the triangles congruent is SSS .

The SSS Congruence Rules also called as (Side-Side-Side) Rule means that if all the three sides of one triangle are equal to the corresponding three sides in the other triangle ,

then we can say that the two triangles are congruent by SSS (Side-Side-Side) Rule .

Therefore , The SSS Congruence rule means Side-Side-Side Congruence .

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Which expression shows how to convert 60 hours to days? StartFraction 60 hours Over 1 EndFraction times StartFraction 1 hour Over 24 days EndFraction StartFraction 60 hours Over 1 EndFraction times StartFraction 1 day Over 24 hours EndFraction StartFraction 60 hours Over 1 EndFraction times StartFraction 24 hours Over 1 day EndFraction StartFraction 60 hours Over 1 EndFraction times StartFraction 24 days Over 1 hour EndFraction

come one people 5 points

Answers

Answer:

60/24

Step-by-step explanation:

Answer:

StartFraction 60 hours Over 1 EndFraction times StartFraction 24 days Over 1 hour EndFraction

Step-by-step explanation:

I'm sorry if this is wrong

Suppose A< - 1 what must be true about the value of b so that ab< a

Answers

Answer:

b must be positive

Step-by-step explanation:

if a is less than -1

that means to get smaller numbers

b needs to be positive

so that when a is multiplied by b you would have

numbers that are more negative

Answer:

b > 1

Step-by-step explanation:

Given:

a < -1 ab < a

Substituting a = -1 into ab < a

⇒ (-1)b < -1  

⇒ -b < -1

⇒ b > 1

If a < -1 then a is negative.  If ab < a then ab is also negative.  

In order for ab to be negative (when a is negative) b must be positive.

For ab < a then b > 1.

Proof

If b = 0.5 and a = -1.5 then ab = -0.75

As -0.75 > -1.5 then ab > a so this cannot be true.

If b = 1.5 and a = -1.5 then ab = -2.25

As -2.25 < -1.5 then ab < a so this is true.

Therefore b > 1

pls answer urgent x Sam needs to figure out how much purple paint to buy. Calculate for her the total area, in square feet, of the four walls. She will not paint the door or windows.

pls answer urgent x Sam needs to figure out how much purple paint to buy. Calculate for her the total

Answers

Answer:

total area of the house and walla and stuff is 322ft²

Step-by-step explanation:

Answer:

wall area to be painted = 322 ft²

Step-by-step explanation:

The front wall and back wall have the same length and width.

The left wall and the right wall have the same length and width.

We need to add 2 times the area of the front wall plus 2 times the area of the left wall and then subtract the areas of the door and windows.

wall area to be painted =

= 2 × 12 ft × 8 ft + 2 × 10 ft × 8 ft - 22 ft² - 2 × 2 ft × 2 ft

= 192 ft² + 160 ft² - 22 ft² - 8 ft²

= 322 ft²

I need help with problem 9

I need help with problem 9

Answers

Answer: The triangles are not congruent.

Step-by-step explanation:

We are given that the two triangles both contain a congruent angle and two congruent sides. The triangles have two congruent sides with a non-included congruent angle among them.

However, because the two triangles only have two congruent sides, and the angle shared by each triangle is not included between the two sides, the triangle would be "congruent" by SSA, which is not a triangle congruency theorem or postulate.

Therefore, the two triangles are not congruent.

I hope this helps!

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