The radius of the galaxy is 3x1020 m. how fast would a spaceship have to move to cross from one edge of the galaxy to the opposite edge in 300 years as measured by a clock onboard the spaceship?

Answer:

An ammeter.

Explanation:

The electric current in one part of a circuit is measured with an ammeter, which gives a reading in ampere.

When palladium-102, 102/46Pd, undergoes β+ decay, the daughter nucleus contains 47 protons and 36 neutrons, which is ruthenium-102, 102/47Ru.

The decay equation for this process is:

102/46Pd -> 102/47Ru + β+ + νe

During the decay, a proton in the palladium-102 nucleus undergoes a transformation, changing its charge from positive to neutral. This is accompanied by the emission of a positron, which is a positively charged electron, and a neutrino, which is a neutral subatomic particle.

The resulting daughter nucleus, ruthenium-102, has 47 protons, reflecting the increase in proton count due to the conversion, and 36 neutrons, maintaining the overall mass number of 102. This β+ decay process plays a significant role in nuclear physics and radioactive decay, contributing to the understanding of fundamental particles and the stability of atomic nuclei. Hence, the correct option is 47 protons and 36 neutrons.

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Plutonium= Pu, 94, 244,94,94

Chromium= Cr, 24,52, 24,24

Neon = Ne, 10,20,10,10

Gold= Au, 79,197,79,79

Radon = Ra ,86,222,86,86

The power used by the weight lifter to lift the barbell to a height of 2 m in 3 seconds is 400 watts

We know already that power is the rate at which work is done. It is expressed

Power (P) = work (W) / time (t)

But

Work = force (F) × distance (d)

Therefore,

Power (P) = force (F) × distance (d) / time (t)

Using the above formula, we can obtain the power used to lift the barbell as follow:

Power (P) = force (F) × distance (d) / time (t)

Power = (600 × 2) / 3

Power = 1200 / 3

Power = 400 watts

Thus, the power used to lift the barbell is 400 watts

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Answer:

Wavelength.

Explanation:

1 period, or wavelength, is measured from one crest to another or from one trough to another.

It would take 1.556 seconds for the barrier to crumple and safely slow down the person with a force of 1180 N.

To calculate the time required to crumple the barrier and safely slow down the person, we can use the concept of impulse.

The impulse, denoted by J, is defined as the product of force and time, and it represents the change in momentum of an object. In this case, the impulse required to safely slow down the person can be calculated using the maximum force and the person's initial momentum.

The momentum of a person is given by the product of their mass and velocity:

Momentum = mass × velocity

Given that the person's mass is 68 kg and their velocity is 27 m/s, the initial momentum is:

Initial momentum = 68 kg × 27 m/s

To safely slow down the person, the impulse provided by the barrier should be equal to the change in momentum.

Therefore, we have:

Impulse provided by barrier = Final momentum - Initial momentum

Since the person is brought to rest, the final momentum is zero. Thus, we have:

Impulse provided by barrier = -Initial momentum

Now we can express the impulse in terms of force and time:

Impulse provided by barrier = Force × Time

Plugging in the known values, we can solve for time:

-Initial momentum = Force × Time

68 kg × 27 m/s = 1180 N × Time

Simplifying the equation, we find:

Time = (68 kg × 27 m/s) / 1180 N

Evaluating the expression:

Time = 1836 kg·m/s / 1180 N

Finally, converting kg·m/s to seconds, we get:

Time ≈ 1.5559 seconds

Therefore, it would take approximately 1.556 seconds for the barrier to crumple and safely slow down the person with a force of 1180 N.

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The phenomenon of interference occurs when two wave pulses are traveling along a string toward each other. Option D is correct.

The result of two or more wave trains flowing in opposite directions on a crossing or coinciding pathways. This phenomenon is known as the interference of waves.

The effect is the sum of the individual wave amplitudes at each site where more than one wave is present.

When two wave pulses are traveling along a string toward each other. They meet and the phenomenon is occur known as interference.

Hence the phenomenon of interference occurs when two wave pulses are traveling along a string toward each other.

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The tangential speed on the outer edge of a rotating carousel is dependent on the carousel's rotational speed and the distance from the center of rotation to the outer edge.

It can be calculated using the formula: tangential speed = radius × angular speed

Where the radius is the distance from the center of rotation to the outer edge, and the angular speed is the rate of rotation measured in radians per second.

The carousel's rotational speed of a carousel refers to the rate at which it completes one full revolution, and it is usually measured in units of revolutions per minute (RPM) or radians per second (rad/s). The faster the carousel rotates, the higher the outer edge's tangential speed. The rotational speed of a carousel can be controlled by adjusting the power source that drives it, such as an electric motor.

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A more elliptical orbit would cause changes in the average insolation value, and depending on whether it is increased or decreased, it would lead to global warming or cooling respectively.

The change in the average insolation during a time when the Earth's orbit is very elliptical (oval-shaped) would result in a higher or lower value than 340.4 W/m2. Since the shape of the orbit affects the distance between the Earth and the Sun, a more elliptical orbit would mean that the Earth is closer to the Sun at some points in the orbit and farther away at others. This would lead to variations in the amount of solar radiation reaching the earth's surface.

If the average insolation value is increased, it would lead to global warming as more solar radiation is absorbed by the Earth, increasing the overall temperature. Conversely, if the average insolation value is decreased, it would lead to cooling as less solar radiation is absorbed, resulting in lower temperatures.

To summarize, a more elliptical orbit would cause changes in the average insolation value, and depending on whether it is increased or decreased, it would lead to global warming or cooling respectively.

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Answer:

here ya go.

Explanation:

I'm not very good and science or math, but I try my best.

For the designing of differential amplifier following were found out :

the small-signal gain is zero.

the transconductance (gm) and output resistance (ro) of the NMOS transistors are  -640 * (W/L) μA/V and 1 / (8 * (W/L)) kΩ respectively.

the transconductance (gm) and output resistance (ro) of the PMOS transistors are -320 * (W/L) μA/V and  respectively.

NMOS transistor: Wn = 0.03 μm, L = 0.2 μm

PMOS transistor: Wp = 0.0075 μm, L = 0.2 μm

Bias current: Itail = 1 mA

Resistance: R = 0.3 kΩ

To design the differential amplifier according to the given specifications, we will follow these steps:

Step 1: Calculate the small-signal gain (Av)

Step 2: Determine the transconductance (gm) and output resistance (ro) of the NMOS transistors

Step 3: Determine the transconductance (gm) and output resistance (ro) of the PMOS transistors

Step 4: Calculate the tail current (Itail) based on the specified Iss

Step 5: Determine the resistance (R) value

Step 6: Calculate the width (Wp) of the PMOS transistor

Step 7: Calculate the width (Wn) of the NMOS transistors

Now let's go through each step in detail.

Step 1: Calculate the small-signal gain (Av)

Given: Av = 10, VOP = VON = 3.5V

Av = (vop - von) / (vip - vin)

10 = (3.5 - 3.5) / (0.1)

10 = 0 / 0.1

Since the numerator is zero, the small-signal gain is zero.

Step 2: Determine the transconductance (gm) and output resistance (ro) of the NMOS transistors

Given: unCox = 400 μA/V², Vtn = 0.8V, n = 0.02 V^(-1), L = 0.2 μm

gm = 2 * unCox * (W/L) * (Vgs - Vtn)

ro = 1 / (lambda * unCox * (W/L))

We need to design the amplifier for DC operation (Vin = Vbias), where the differential voltage (vgs = Vin - Vbias) should be zero to operate the transistors in the saturation region.

For the NMOS transistors:

Vgs = 0 (since Vin = Vbias)

gm = 2 * unCox * (W/L) * (Vgs - Vtn)

  = 2 * 400 μA/V² * (W/L) * (0 - 0.8)

  = -640 * (W/L) μA/V

ro = 1 / (lambda * unCox * (W/L))

  = 1 / (0.02 V^(-1) * 400 μA/V² * (W/L))

  = 1 / (8 * (W/L)) kΩ

Step 3: Determine the transconductance (gm) and output resistance (ro) of the PMOS transistors

Given: upCox = 200 μA/V², Vtp = -0.8V, p = 0.04 V^(-1), L = 0.2 μm

Similarly, for the PMOS transistors, we need to design the amplifier for DC operation (Vin = Vbias), where the differential voltage (vsg = Vbias - Vin) should be zero to operate the transistors in the saturation region.

For the PMOS transistors:

Vsg = 0 (since Vin = Vbias)

gm = 2 * upCox * (W/L) * (Vtp - Vsg)

  = 2 * 200 μA/V² * (W/L) * (-0.8 - 0)

  = -320 * (W/L) μA/V

ro = 1 / (lambda * upCox * (W/L))

  = 1 / (0.04 V^(-1) * 200 μA/V² *

  = 1 / (5 * (W/L)) kΩ

Step 4: Calculate the tail current (Itail) based on the specified Iss

Given: Iss = 2 mA

Itail = Iss / 2

= 2 mA / 2

= 1 mA

Step 5: Determine the resistance (R) value

Given: Vs = 0.3 V, VDD = 5 V

We can calculate the resistance (R) value using Ohm's Law:

Vs = Itail * R

0.3 V = 1 mA * R

R = 0.3 kΩ

Step 6: Calculate the width (Wp) of the PMOS transistor

To calculate Wp, we'll use the equation for the tail current:

Itail = 2 * upCox * (Wp/L) * (VDD - Vtp)^2

1 mA = 2 * 200 μA/V² * (Wp/0.2 μm) * (5 V + 0.8 V)^2

1 mA = 2 * 200 μA/V² * (Wp/0.2 μm) * (5.8 V)^2

Solving for Wp:

Wp = (1 mA * 0.2 μm) / (2 * 200 μA/V² * (5.8 V)^2)

Wp = 0.01 μm / (2 * 200 μA/V² * 33.64 V^2)

Wp ≈ 0.0075 μm

Step 7: Calculate the width (Wn) of the NMOS transistors

Given: Wn = 4 * Wp

Wn = 4 * 0.0075 μm

Wn = 0.03 μm

So, the design parameters for the differential amplifier are as follows:

the small-signal gain is zero.

the transconductance (gm) and output resistance (ro) of the NMOS transistors are  -640 * (W/L) μA/V and 1 / (8 * (W/L)) kΩ respectively.

the transconductance (gm) and output resistance (ro) of the PMOS transistors are -320 * (W/L) μA/V and  respectively.

NMOS transistor: Wn = 0.03 μm, L = 0.2 μm

PMOS transistor: Wp = 0.0075 μm, L = 0.2 μm

Bias current: Itail = 1 mA

Resistance: R = 0.3 kΩ

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Answer:

D. Ohm

Explanation:

Ohm is an SI-derived unit of resistance and can be expanded to its base units of m²·kg·s¯³·A¯².

The farthest distance the particle reaches from the center of the planet is 14/3 times the radius of the planet.

When the particle is fired with a speed equal to 3/4 the escape speed, its initial kinetic energy will be half of the gravitational potential energy at the surface of the planet:

\(1/2 mv^2 = GMm/R\)

where m is the mass of the particle, v is its speed, G is the gravitational constant, and M and R are the mass and radius of the planet, respectively.

Solving for v, we get:

v = sqrt(2GM/R) × sqrt(1/2)

The escape speed from the surface of the planet is given by:

vesc = sqrt(2GM/R)

Therefore, the initial speed of the particle is:

v = 3/4 × vesc

Substituting this in the expression for v, we get:

v = sqrt(2GM/R) × sqrt(1/2) × 3/4

v = sqrt(GM/R) × sqrt(3/8)

The particle will follow a parabolic trajectory with the planet at the focus of the parabola. The farthest distance it reaches (measured from the center of the planet) occurs when it reaches the vertex of the parabola. The distance of the vertex from the focus is equal to the distance of the focus from the directrix, which is 2R.

Therefore, the farthest distance the particle reaches is:

d = 2R + r

where r is the distance of the focus from the vertex of the parabola. The distance r can be calculated using the equation for the parabolic trajectory:

\(r = 2GM/v^2\)

Substituting the expression for v, we get:

r = 8R/3

Therefore, the farthest distance the particle reaches is:

d = 2R + r = 8R/3 + 2R = 14R/3

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The value of the diameter of the washer so that 45% of the diameters are greater is approximately 0.0161. The problem states that the diameter of a washer is normally distributed with a mean (μ) of 0.012 and a standard deviation (σ) of 0.0024.

We want to find the value of the diameter that corresponds to the top 45% of the distribution.

To find this value, we need to calculate the z-score corresponding to the top 45% of the distribution. The z-score represents the number of standard deviations a value is from the mean. We can use the z-table or a statistical calculator to find the z-score associated with a cumulative probability of 0.45.

In this case, the z-score is approximately 1.645. Using the formula z = (x - μ) / σ, we can rearrange it to solve for x (the diameter we are looking for).

x = μ + (z * σ)
x = 0.012 + (1.645 * 0.0024)
x ≈ 0.0161

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Answer:

Initial velocity = 4 m/s

Explanation:

Acceleration, a = 1.2 m/s²

Final velocity, v = 16 m/s

Initial velocity, u = ?

Time, t = 10 seconds

So, we must use the formula:

v = u + at

Insert all the values into the formula.

16 = u + 1.2 × 10

16 = u + 12

Make 'u' the subject of the equation, and solve to find the value of u.

u = 16 - 12

u = 4 m/s

Answer:

There is an inverse relationship between distance and light intensity - as the distance increases, light intensity decreases. This is because as the distance away from a light source increases,..

Explanation:

The light intensity decreases as magnification increases. There is a fixed amount of light per area, and when you increase the magnification of an area, you look at a smaller area. So you see less light, and the image appears dimmer. Image brightness is inversely proportional to the magnification squared.

Answer:

it's A

Explanation:

Answer:

d ............................

The force of the SUV's bumper on the truck's bumper would be 18,000 N.

The bumper on the truck is pushing the bumper of the SUV, which is acting as a reaction force back on the truck's bumper. According to Newton's Third Law, if the truck applies a forward force to the SUV, the SUV will apply an equal and opposite force back on the truck. Therefore, at this acceleration the force of the SUV's bumper on the truck's bumper would be the same as the forward force applied by the truck, which is 18,000 N.This is because the two vehicles are in contact with each other, so the force applied by one is equal and opposite to the force applied by the other.

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The expected ratio of free-hanging earlobes to attached earlobes in the offspring is 1:2.

The diagram depicts a Punnett square used to predict the earlobe shape of two parents' offspring. The capital A represents free-hanging earlobes, while the lowercase a represents attached earlobes.

The Punnett square is a square diagram used to predict genotypes of a specific cross or breeding experiment. It is named after Reginald C. Punnett, who invented it in 1905. Biologists use the diagram to calculate the likelihood of an offspring having a specific genotype.

In this case, the genotype rato based on the attached diagram is 1:2.

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Answer:

0.1962N.

Explanation:

Weight is a force, so we use newtons second law which states F=ma. So the weight of a watermelon on earth is 2kg x 9.81m/s², which is 19.62N (newtons). On the moon it weighs 2 x 1.63 which is 3.26N.

The weight of the pen is 0.02 x 9.81, which is 0.1962N. If the pen is not to fall the frictional force needs to be equal to this force,

so the answer is 0.1962N.

(Hope this helps can I pls have brainlist (crown)☺️)

Answer:

7.61 m/s

Explanation:

Given:

Δx = 87.4 m

v = 21.0 m/s

t = 6.11 s

Find: v₀

Δx = ½ (v + v₀) t

87.4 m = ½ (21.0 m/s + v₀) (6.11 s)

v₀ = 7.61 m/s

71.6

Δx = 87.4 m

v = 21.0 m/s

t = 6.11 s

Find: v₀

Δx = ½ (v + v₀) t

87.4 m = ½ (21.0 m/s + v₀) (6.11 s)

v₀ = 7.61 m/s

Answer: They orbit the galactic center with many different inclinations, while disk stars all orbit in nearly the same plane. ... They have vertical motions out of the plane, making them appear to bob up and down, but they never get "too far" from the disk.

Explanation:

Heya!!

For calculate force, lets applicate Hooke's law:

                                                \(\boxed{F=k * x}\)

                                                 Δ   Being   Δ

                                                 F = Force = ?

                                         k = Constant = 105 N/m

                                          x = Elongation = 0,1 m

⇒ Let's replace according the formula:

\(\boxed{F=105\ N/m * 0,1\ m}\)

⇒ Resolving

\(\boxed{F = 10,5 \ N }\)

Result:

The force is 10,5 Newtons (N).

Good Luck!!

Answer:

3.68 m/s

Corrected question;

Chef Andy tosses an orange in the air, then catches it again at the same height. The orange is in the air for 0.75 s. We can ignore air resistance. What was the orange's velocity at the moment it was tossed into the air?

Explanation:

Applying the equation of motion;

v = u + at. ....1

Where

u = initial speed

v = final speed

a = acceleration

t = time taken

Given;

Total time of flight t = 0.75s

Acceleration due to gravity g = 9.8 m/s^2

Considering the first phase of flight, during the upward motion to the maximum height. The final velocity at the maximum height is zero and the time of flight of the phase is equal to half of the total flight time.

v1 = 0

t1 = t/2 = 0.75/2 =0.375s

From equation 1;

v1 = u - gt1

Substituting the values;

0 = u - 9.8(0.375)

Solving for u;

u = 9.8(0.375)

u = 3.675

u = 3.68 m/s

Initial velocity = 3.68 m/s

Explanation:

jouleeeee is the unit kinetic energy is measured in and kinetic energy formula is 1/2mv (square)

Answer:

D    Exothermic and Endothermic

Explanation:

Answer:

D

Explanation:

I just took test