Answer:
12 boys
Step-by-step explanation:
Set up a proportion: \(\frac{3}{4} = \frac{x}{16}\) Cross multiply, then divide: 3 × 16 = 48, 48 ÷ 4 = 12I hope this helps!
Answer:
12
Step-by-step explanation:
prove that if all of the 2n subsets of a set containing 2n 1 are equal, then all elements of set n are equal
when multiplicity is removed, you get 2^(2n+1)/2 members, which is 2^(2n).
Take the power set. It has 2^(2n+1) members.
Replace any member which has n+1 or more elements with its complements.
Now the power set has members, which have n or fewer elements, and each such member appears twice.
Therefore, when multiplicity is removed, you get 2^(2n+1)/2 members, which is 2^(2n).
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Estimate σA and σB using the loan allocation deviation formula.
A. σ(A) = 12.25% ; σ(B) = 14.14%
B. σ(A) = 17.32% ; σ(B) = 20.0%
C. σ(A) = 16.33% ; σ(B) = 14.14%
D. σ(A) = 14.14% ; σ(B) = 16.33%
The formula for allocation deviation is as follows:σA = (w1σ1^2 + w2σ2^2 + … + wσn^2)^(1/2)σB = (w1σ1^2 + w2σ2^2 + … + wσn^2)^(1/2)
Here,
σ1 = 15%
σ2 = 10%
w1 = 50%,
w2 = 50%
Substituting the values in the above formula:
σA = (0.5 × 0.15^2 + 0.5 × 0.10^2)^(1/2)
= (0.0225 + 0.0100)^(1/2)
= 0.0158 = 1.58%σB
= (0.5 × 0.15^2 + 0.5 × 0.10^2)^(1/2)
= (0.0225 + 0.0100)^(1/2)
= 0.0158
= 1.58%
Hence, the correct option is
D. σ(A) = 14.14%;
σ(B) = 16.33%.
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what is the total change in the cat weights for all three months
Answer:
-0.5
Step-by-step explanation:
-0.7 + 0.5 - 0.3 = -0.5
Evaluate the expression,
2(x + 3y) - 4
Answer:
2x+6y-4
Step-by-step explanation:
First distribute x and 3y
2 times x is 2x
2 times 3 is 6y
(2x+6y) -4
2x+6y-4
Hope this helps!
Answer:
2(x+3y-2)
Step-by-step explanation:
See the steps below:)
Sixty-four percent of voters in a very large electorate support candidate Smith in an upcoming election. A student employee working the evening shift at a telephone survey facility calls voters at random and asks them which candidate they prefer. a. What is the probability that, among five voters the student calls, exactly one supports candidate Smith? b. What is the probability that, among five voters the student calls, at least one supports candidate Smith? c. What is the probability that the first voter supporting candidate Smith is reached on the fifth call, i.e., what is the probability that it takes the student five calls to reach the first voter who supports candidate Smith? d. What is the probability that the third voter supporting candidate Smith is reached on the fifth call, i.e., what is the probability that it takes the student five calls to reach three voters who supports candidate Smith?
The probabilities are calculated assuming independence of each call and that the success probability remains constant throughout the calls.
a. The probability that, among five voters the student calls, exactly one supports candidate Smith can be calculated using the binomial probability formula. With a success probability of 64% (0.64) and exactly one success (k = 1) out of five trials (n = 5), the probability can be calculated as follows:
\[
P(X = 1) = \binom{5}{1} \times (0.64)^1 \times (1 - 0.64)^4
\]
The calculation results in approximately 0.369, or 36.9%.
b. The probability that, among five voters the student calls, at least one supports candidate Smith can be calculated as the complement of the probability that none of the voters support Smith. Using the binomial probability formula, with a success probability of 64% (0.64) and no success (k = 0) out of five trials (n = 5), the probability can be calculated as follows:
\[
P(X \geq 1) = 1 - P(X = 0) = 1 - \binom{5}{0} \times (0.64)^0 \times (1 - 0.64)^5
\]
The calculation results in approximately 0.997, or 99.7%.
c. The probability that the first voter supporting candidate Smith is reached on the fifth call can be calculated as the probability of not reaching a Smith supporter in the first four calls (0.36) multiplied by the probability of reaching a Smith supporter on the fifth call (0.64):
\[
P(\text{{First Smith Supporter on Fifth Call}}) = (1 - 0.64)^4 \times 0.64
\]
The calculation results in approximately 0.014, or 1.4%.
d. The probability that the third voter supporting candidate Smith is reached on the fifth call can be calculated as the probability of reaching two Smith supporters in the first four calls (0.64 for the first call, 0.36 for the second call, and 0.36 for the third call) multiplied by the probability of reaching a Smith supporter on the fifth call (0.64):
\[
P(\text{{Third Smith Supporter on Fifth Call}}) = (0.64)^2 \times (1 - 0.64) \times 0.64
\]
The calculation results in approximately 0.147, or 14.7%.
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The probabilities are calculated assuming independence of each call and that the success probability remains constant throughout the calls. The calculation results in approximately 0.369, or 36.9%.
a. The probability that, among five voters the student calls, exactly one supports candidate Smith can be calculated using the binomial probability formula. With a success probability of 64% (0.64) and exactly one success (k = 1) out of five trials (n = 5), the probability can be calculated as follows:
[P(X = 1) = \binom{5}{1} \times (0.64)^1 \times (1 - 0.64)^4\]
The calculation results in approximately 0.369, or 36.9%.
b. The probability that, among five voters the student calls, at least one supports candidate Smith can be calculated as the complement of the probability that none of the voters support Smith. Using the binomial probability formula, with a success probability of 64% (0.64) and no success (k = 0) out of five trials (n = 5), the probability can be calculated as follows:
[P(X \geq 1) = 1 - P(X = 0) = 1 - \binom{5}{0} \times (0.64)^0 \times (1 - 0.64)^5\]
The calculation results in approximately 0.997, or 99.7%.
c. The probability that the first voter supporting candidate Smith is reached on the fifth call can be calculated as the probability of not reaching a Smith supporter in the first four calls (0.36) multiplied by the probability of reaching a Smith supporter on the fifth call (0.64):
\[
P(\text{{First Smith Supporter on Fifth Call}}) = (1 - 0.64)^4 \times 0.64
\]
The calculation results in approximately 0.014, or 1.4%.
d. The probability that the third voter supporting candidate Smith is reached on the fifth call can be calculated as the probability of reaching two Smith supporters in the first four calls (0.64 for the first call, 0.36 for the second call, and 0.36 for the third call) multiplied by the probability of reaching a Smith supporter on the fifth call (0.64):
\[
P(\text{{Third Smith Supporter on Fifth Call}}) = (0.64)^2 \times (1 - 0.64) \times 0.64
\]
The calculation results in approximately 0.147, or 14.7%.
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what is 12.5% of 10 kg in grams
Answer:
1250 g
Step-by-step explanation:
12.5% of 10 kg
12.5% of 10000 g
.125 of 10000 g
.125 * 10000 g
1250 g
Answer:
1250 gramsStep-by-step explanation:
\( \frac{12.5}{100} \times 10kg = x \: grams\)
\(1.25kg = 1250 \: grams\)
POSP(3,-4)M(1,3)Qi??)ºpThe midpoint M and one endpoint of PQ are given.Find the coordinates of the other endpoint.Q1
P = (3,-4)
M = (1,3)
Q = (Qx,Qy)
Midpoint = (x1+x2)/2 , (y1+y2)/2
Mx = (Px+Qx) /2
1= (3+Qx) /2
Solve for Qx
1 (2) = 3+Qx
2 = 3 +Qx
2-3 = Qx
Qx= -1
My = (y1+y2) /2
3 = (-4+Qy) /2
Solve for QY
3 (2) = -4+Qy
6= -4 + Qy
6+4 = Qy
10 = Qy
Coordinates of the Endpoint Q:
Q = (-1,10)
I need to show the work. Please help
Answer:
18
Step-by-step explanation:
125 = 7x - 1 ...... because if the two lines are parallel alternate interior angles are congruent
125 + 1 = 7x
126 = 7x
\( \frac{126}{7} = \frac{7x}{7} \)
x = 18
hope it helps
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Anders won $12,000 from a lottery ticket. he invests it in an account that earns 2.8% interest compounded quarterly. how much money will anders have in the account after 11 years?
Anders will have the Amount of $ 16,310.90 in his account after 11 years
Compound Interest:
Compound interest is the interest charged on a loan or deposited amount. The compound interest will depend on both the Principal amount and interest gained over the given time period. The formula for the Amount in compound interest, A = P( 1 + r/n)^tn
From given problem
The principal amount P = $12,000
Rate of interest, r = 2.8% = 2.8/100 = 0.028
Time period, t = 11 years
Number of compounds in a year = 4 [ ∵ interest compounded quarterly ]
The Amount after 11 years = 12000(1+0.028/4)^(11)(4)
= 12000(1+0.007)⁴⁴
= 12000(1.007)⁴⁴
= 16,310.90
Anders will have $ 16,310.90 in his account after 11 years
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During his hike, Milt drank 1 liter of water and 1 liter of sports drink. How many milliliters of liquid did he drink?
Answer: 2,000 milliliters.
Step-by-step explanation:
Hi, to answer this question we have to add the amount of water and the amount of sports drink that he drank:
1 liter + 1 liter = 2 liters of liquid.
Finally, we have to convert the result into milliliters.
Since 1 liter = 1000 liters
We have to multiply the liters drank by 1000.
2 x 1000 = 2,000 milliliters.
Feel free to ask for more if needed or if you did not understand something.
Please help, due soon. Use the information provided to write the standard form equation of each circle
Answer:
The answer is D
Step-by-step explanation:
the standard equation for circle is (x -h)² +(y -k)² = r² which h is the x coordinate, k is the y coordinate, r is radius. In this case, both x coordinate and y coordinate are 0, so the left side of the equation is x² + y², since the radius is √249, the r² is 249. So the equation is x² + y² = 249, and the answer is D.
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find the profit obtain by a trader by selling 50 mangoes each Rs 12.00 which bought at the price of Rs. 8 each .
How do you simplify the expression: 8u + 10u + -u - 7u
Answer:
10u
Step-by-step explanation:
Since they all have the same variable you can solve it normally.
8+10= 18
18-1=17
17-7=10
min ti x₁ = x₂-u x₂ = u -144²1 (x₁, x₂) arbitrary starting point. Let (0,0) be the Check whether situation (x₁, x₂)→ (0,0) shortest time is met. the beginning of the the coordinate. generality condition of the
It appears that the system dynamics can be manipulated through the control input u to minimize the time required for convergence to the origin (0,0).
Here, we have,
given that,
min t_i
x₁ = x₂-u
x₂ = u
-1 ≤ u ≤ 1, (x₁, x₂) are arbitrary starting point.
and origin (0,0) be the begging of the coordinate.
also given that, (x₁, x₂)→ (0,0)
so, min t_i at origin (0,0) = t
Therefore, the generality condition of the situation does not met.
so, we get,
The given system can be represented by the following equations:
x₁' = x₂ - u
x₂' = u
To analyze the behavior of the system, we can examine the dynamics of each variable separately.
For x₁:
x₁' = x₂ - u
The equation implies that the rate of change of x₁ is dependent on x₂ and the input u. The term (-u) acts as a control input that can affect the dynamics of x₁. If we choose an appropriate control input u, we can manipulate the rate of change of x₁ and potentially minimize the time required to reach the origin.
For x₂:
x₂' = u
The equation for x₂ indicates that the rate of change of x₂ is solely determined by the input u. The variable x₂ can be directly controlled by the input u, allowing us to influence its behavior and potentially expedite convergence.
Based on the given equations, it appears that the system dynamics can be manipulated through the control input u to minimize the time required for convergence to the origin (0,0).
By carefully selecting the control input, it is possible to achieve the shortest time to reach the origin from any arbitrary starting point (x₁, x₂).
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HELP ME QUICK PLEASE!!
Manny took home a couple of his friends after soccer practice. He originally had 4 gallons of gas in his car. He used 1.05 gallons of gas to take one friend home and three tenths gallon to take the other friend home. How much gas did he have left in his car after taking both friends home?
A: 1.04 gallons
B: 2.95 gallons
C: 3.70 gallons
D: 2.65 gallons
D) 2.65 gallons of gas left in his car after taking both friends home when 1.05 gallons of gas is used to take one friend home and three tenths gallon to take the other friend home.
Manny used 1.05 + 0.3 = 1.35 gallons of gas to take his friends home.
Since he originally had 4 gallons of gas, he had 4 - 1.35 = 2.65 gallons of gas left in his car after taking both friends home.
So the answer is D.
Here is the solution in more detail:
Manny started with 4 gallons of gas.
He used 1.05 gallons of gas to take one friend home.
He used 0.3 gallons of gas to take the other friend home.
The total amount of gas he used was 1.05 + 0.3 = 1.35 gallons.
Therefore, he had 4 - 1.35 = 2.65 gallons of gas left in his car.
I hope this helps! Let me know if you have any other questions.
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the population of men and women between the ages of 40-50 is approximately equal. the population of women is higher than men between the ages of 50-60. what does this likely result from?
The situation given in the question occurs due to the lower mortality rate which is seen in women of the age group 50-60.
Discrepancies between men and women's death rates and life expectancy. In general, women live longer than males. This means that, assuming everything else is equal, we should anticipate that women will make up somewhat more than half of the population.
Birth sex ratios are not equal. Males outnumber female births in every country. This means that, assuming everything else is equal, we should anticipate that men will make up somewhat more than half of the population.
The population's gender distribution can be impacted through migration. All other things being equal, we would anticipate that men would make up more than 50% of the population if some countries import a sizable amount of male-dominated labor.
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pls help
will give the crown of correct
Answer:
a) The watch is cheaper in Geneva.
b) The watch is cheaper by £20
Step-by-step explanation:
a) In which city is the watch cheaper?
Step 1. Translate Pounds into Swiss Francs.
£145 * 1.55 = 224.75 CHF
Step 2. Determine which price is higher.
224.75 is greater than 193.75.
Step 3. Always answer a Word problem in complete sentences.
The watch is cheaper in Geneva.
b) By how much is it cheaper?
224.75 - 193.75 = 31
Translate CHF to Pounds.
31 / 1.55 = 20
The watch is cheaper by £20.
12. Write the MATLAB statements required to calculate f(t) using the following equation for values of t € [-9,9] in steps of 0.5. f(t) = { (-3t² +5 t 20 3t² +5 t < 0 13. Write a MATLAB function named UniGen that generates a specified number (n) of random values that are uniformly distributed on any given interval specified by values a and b, that is, [a, b].
12. MATLAB code: `f = (-3*t.^2 + 5*t + 20).*(t < 0) + (3*t.^2 + 5*t).*(t >= 0)`
13. MATLAB function: `function random_values = UniGen(n, a, b); random_values = (b - a) * rand(n, 1) + a; end`
MATLAB code to calculate f(t) using the given equation:
t = -9:0.5:9; % Generate values of t from -9 to 9 in steps of 0.5
f = zeros(size(t)); % Initialize f(t) vector
for i = 1:numel(t)
if t(i) < 0
f(i) = -3*t(i)^2 + 5*t(i) + 20;
else
f(i) = 3*t(i)^2 + 5*t(i);
end
end
% Display the results
disp('t f(t)');
disp('--------');
disp([t' f']);
```
This code generates values of `t` from -9 to 9 in steps of 0.5 and calculates `f(t)` based on the given equation. The results are displayed in a tabular format showing the corresponding values of `t` and `f(t)`.
13. MATLAB function UniGen to generate uniformly distributed random values:
function random_values = UniGen(n, a, b)
% n: Number of random values to generate
% a: Start of the interval
% b: End of the interval
random_values = (b - a) * rand(n, 1) + a;
end
This MATLAB function named `UniGen` generates `n` random values that are uniformly distributed on the interval `[a, b]`. It utilizes the `rand` function to generate random values between 0 and 1, which are then scaled and shifted to fit within the specified interval `[a, b]`. The generated random values are returned as a column vector.
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i need help with this
The missing values in the triangle are:
∠B = 90°
AB = 20.98
CB = 16.99
How to find the missing values?First, remember that the sum of the interior angles of any triangle is always equal to 180°, then we can write:
51 + 39 + ∠B = 180
∠B = 180 - 51 - 39 = 90
So we have a right triangle.
Now, to find the values of AB and CB, we can use trigonometric relations, we know that teh hypotenuse is 27 units, then we can use:
cos(51°) = CB/27
27*cos(51°) = CB = 16.99
And:
cos(39°) = AB/27
27*cos(39°) = AB = 20.98
These are the missing values.
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Can exponential function have 1 as a base?
Yes, an exponential function can have 1 as a base.
An exponential function is a function of the form f(x) = a^x, where a is the base and x is the exponent. The base can be any real number, including 1.
When the base is 1, the exponential function is defined as f(x) = 1^x = 1 for any value of x. This function is a constant function that always equals 1.
It is important to note that when the base of an exponential function is less than 0, the domain of the function is all real numbers except for certain values of x.
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Find the exact length of the curve. y = In(sec(x)), 0≤x≤ Need Help? Read It π 4 Watch It
The curve is y = In(sec(x)) and we have to find its length. We are given the range as 0 ≤ x ≤ π/4. So, the formula for the length of the curve is given as:
To solve for the length of the curve of y = In(sec(x)), we use the formula,
`L = ∫[a,b] √[1+(f′(x))^2] dx`.Where, `a = 0` and `b = π/4`. And `f′(x)` is the derivative of `In(sec(x))`.
We know that:`f′(x) = d/dx[In(sec(x))]`
Using the formula of logarithm differentiation, we can write the above equation as:
`f′(x) = d/dx[In(1/cos(x))]`
So,`f′(x) = -d/dx[In(cos(x))]`
Therefore,`f′(x) = -sin(x)/cos(x)`
Substituting the values, we get:
`L = ∫[a,b] √[1+(f′(x))^2] dx`
`L = ∫[0,π/4] √[1+(-sin(x)/cos(x))^2] dx`
`L = ∫[0,π/4] √[(cos^2(x)+sin^2(x))/(cos^2(x))] dx`
`L = ∫[0,π/4] sec(x) dx`
Now, `L = ln(sec(x) + tan(x)) + C` where `C` is a constant.
We calculate the constant by substituting the values of `a = 0` and `b = π/4`:
`L = ln(sec(π/4) + tan(π/4)) - ln(sec(0) + tan(0))`
`L = ln(√2 + 1) - ln(1 + 0)`
`L = ln(√2 + 1)`
Thus, the exact length of the curve is `ln(√2 + 1)` units.
Thus, the exact length of the curve of y = In(sec(x)), 0≤x≤π/4 is `ln(√2 + 1)` units.
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Can someone help this please and thank you
distributive property
A cat drinks 1 3/4 l of milk from a utensil having 2 1/4 l of milk what fraction of milk did cat drink
Answer: The cat drank 7/9 of the milk in the utensil.
Step-by-step explanation:
To find the fraction of milk that the cat drank, we need to divide the amount of milk the cat drank by the total amount of milk in the utensil.
The cat drank 1 3/4 liters of milk, which is the same as 7/4 liters.
The utensil had 2 1/4 liters of milk, which is the same as 9/4 liters.
So, the fraction of milk that the cat drank is:
(7/4) ÷ (9/4) = 7/9
Therefore,
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PLEASE HELP!! Re-write the equation 3 x minus y = 4 in slope-intercept form.
a.
y = 3 x minus 4
c.
y = negative 3 x minus 4
b.
y = 3 x + 4
d.
y = negative 3 x + 4
Please select the best answer from the choices provided
A
B
C
D
Answer:
A) \(y = 3x - 4\)
Explanation:
Slope-intercept form is y = mx + b
CAN SOMEONE HELPPPPPP PLEASE?!??!!!!?
1) a child puts $1 into a piggy bank. one week later he puts $1.25. two weeks later he puts $1.50 in the bank and so on. how much money does he put in the bank on the 25th week?
omg save me and explain
Answer:kkkkkkk
Step-by-step explanation:
Try It! Write an 2. Write an equation of the line that passes through (2, -1) and (-3, 3).
Answer:
y = -4/5x - 2.6
Step-by-step explanation:
First find the slope:
m = y2-y2 / x2-x1
m = 3-(-1) / -3-2
m = 4/-5
m = -4/5
y = -4/5x + b
-1 = -4/5(2) + b
-1 = 1.6 + b
b = -2.6
y = -4/5x - 2.6
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Use the formulas to find the volume of each figure. Show your work.
The volume of the cone is 7225.66 m³ and the volume of the hemisphere is 209.44 cubic feet.
From the general formula of the volume of the cone,
Volume = πr²h
in the given case,
Radius (r) = 10 m
Height (h) = 23 m
Thus, Volume = π*10²*23
Volume = 7225.66 m³
The formula for the volume of a hemisphere is:
V = (2/3) * π * r³
where π is pi (approximately 3.14159), and r is the radius of the hemisphere.
Substituting the given value of r = 10 ft, we get:
V = (2/3) * π * (10 ft)³
= (2/3) * π * 1000 ft³
= (2/3) * 314.16 ft³
≈ 209.44 ft³
Therefore, the volume of the hemisphere is approximately 209.44 cubic feet.
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For every pound a company spends on advertising, it spends £0.75 on its website. Express the amount spent on advertising to the amount spent on its website as a ratio in its simplest form.
Answer:
the ration to the money spend on ads to website is 4:3
The amount spent on advertising to the amount spent on its website as a ratio in its simplest form is: 4: 3
Given that:
For every pound, the company spends on advertising i.e. £1the company spends £0.75 on its website.Thus, the ratio of the amount spent on the advertising and the website is computed as:
£1: £ 0.75
Since a ratio can be expressed in a fraction when solving to its simplest form, then we have:
\(\mathbf{\dfrac{1}{0.75}}\)
Let's multiply both the numerator and the denominator by 100 to shift the decimal in two places in 0.75
Then, we have:
\(\mathbf{=\dfrac{1\times 100}{0.75 \times 100}}\)
\(\mathbf{=\dfrac{ 100}{75 }}\)
Divide both sides by 5;
\(\mathbf{=\dfrac{ 20}{15 }}\)
Divide both sides by 5;
\(\mathbf{\dfrac{4}{3}}\)
Therefore, the amount spent on advertising to the amount spent on its website in ratio is 4:3
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the two congruent sides of an isosceles triangle form the
In an isosceles triangle, the two https://brainly.com/question/28412104 form the two equal angles opposite those sides.
An isosceles triangle is a type of triangle that has two sides of equal length. The two congruent sides are referred to as the legs of the triangle, while the remaining side is known as the base. The key property of an isosceles triangle is that the angles opposite the congruent sides are also equal. This means that the triangle has two equal angles formed by the congruent sides and a third angle formed by the base.
To understand why the congruent sides form equal angles, consider the following: When two sides of a triangle are equal in length, it implies that the opposite angles they form are also equal. This is known as the Isosceles Triangle Theorem. In an isosceles triangle, the two congruent sides are equal in length, which means the angles opposite those sides must also be equal. Therefore, the two congruent sides of an isosceles triangle form the two equal angles opposite them.
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