the rectangular prism is onlu partially filled with 1 unit cubes. how many unit cubes will it take to completly fill the figure?

The statement about That by increasing the sample size, the amount of sampling error will be decreased is true.

Given that,

That by increasing the sample size, the amount of sampling error will be decreased

Sampling error is inversely related to sample size. Therefore, if we expand the size of our sample, the likelihood of sampling error is reduced and the results are more trustworthy. The standard error is the term used to describe the sampling error that is most frequently utilized (SE). A measurement of the range of estimations around the "actual value" is the standard error. You get a lower return by increasing the sample size beyond what you already have because the added accuracy won't make much of a difference.

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Answer: 26 ≥ number of students

Step-by-step explanation:

with $4,000 invested, Jake has

8% × $4,000 = $320 annually.

in order to have annual interest $628, he has to get more interest $(628-320) = $308.

the rate should be:

308/2800 × 100%

= 308 /2800 × 100%

= 11%

Answer:

11%

Step-by-step explanation:

Simple Interest Formula

I = Prt

where:

Given:

To calculate the interest Jake will earn on his initial investment of $4,000 substitute the given values into the formula and solve for I:

\(\implies \sf I=4000(0.08)(1)=320\)

As he wants to have a total annual interest of $628, he must earn the following interest on his second investment:

\(\implies \sf 628-320=308\)

Given:

To calculate the interest rate for the $2,800 investment, substitute the given values into the formula and solve for r:

\(\implies \sf 308=2800(r)(1)\)

\(\implies \sf r=\dfrac{308}{2800}\)

\(\implies \sf r=0.11\)

\(\implies \sf r=11\%\)

Therefore, Jake must invest $2,800 at the rate of 11%.

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The value of y that satisfies the equation is y = -11.

An equation is a mathematical statement that expresses the equality of two expressions. It typically consists of two sides, separated by an equals sign (=), with each side containing one or more terms that may include variables, constants, and mathematical operators.

We can start by setting up the equation:

(y+1)/(y-5) + 10/(y+5) = (y+1)/(y-5) × 10/(y+5)

To solve for y, we need to simplify and manipulate the equation:

Multiply both sides by (y-5) × (y+5) to eliminate the denominators:

(y+1)(y+5) + 10(y-5) = 10 × (y+1)

Expand and simplify:

y² + 6y - 15 + 10y - 50 = 10y + 10

Combine like terms:

y² + 16y - 55 = 0

Factor the quadratic:

(y + 11)(y - 5) = 0

Solve for y:

y = -11 or y = 5

However, we need to check if either solution makes the denominators of the original equation equal to zero, since division by zero is undefined:

For y = -11, the denominators are -16 and -6, respectively, which are both nonzero. Therefore, y = -11 is a valid solution.

For y = 5, the denominator of the first fraction is 0, which is not allowed. Therefore, y = 5 is an extraneous solution and should be discarded.

Therefore, the value of y that satisfies the equation is y = -11.

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Hello friend!

The answer is: 1367

First, since x = 23, we rewrite the problem.

56(23) + 79 = ?

Now we need to figure out 56 time 23

56 times 23 = 1288

Now we have 1288 + 79.

1288 + 79 = 1367

Answer:

1,367

Explanation:

Step 1 - Input the value of x in the given expression

56x + 79

56(23) + 9

Step 2 - Multiply fifty six by twenty three

56(23) + 79

56 × 23 + 79

1,288 + 79

Step 3 - Add

1,288 + 79

1,297

Therefore, the answer to the given expression is 1,367.

The triple integral that is bounded by a paraboloid x = 4y2 4z2 given as 16.762

Parabloid, x = 4y² + 4z²

plane x = 4

x = 4y² + 4z²

x = 4

4 = 4y² + 4z²

4 = 4 (y² + z² )

1 = y² + z²

from polar coordinates

y = r cos θ

z = r sin θ

r² = y² + z²

0 ≤ θ ≤ 2π

4r² ≤ x ≤ 4

0 ≤ r ≤ 1

\(\int\limits\int\limits\int\limits {x} \, dV = \int\limits^1_0\int\limits^a_b\int\limits^c_d {x} \, dx ( rdrdz)\)

where

a = 4

b = 4r²

c = 2r

d = 0

The first integral using limits c and d gives:

\(2pi\int\limits^1_0\int\limits^a_b {xr} \, dx\)

The second integral using limits a and b

\(pi\int\limits^1_0 {16 } } \, rdr - pi\int\limits^1_0 {16r^{5} \, dx\)

\(16pi\int\limits^1_0 { } } \, rdr - 16pi\int\limits^1_0 {r^{5} \, dx\)

\(16pi\int\limits^1_0 { } } \, [r-r^{5}]dr\)

The third integral using limits 1 and 0 gives: 16.762

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The triple integral that is bounded by a paraboloid x = 4y2 4z2 given as 16.762

Integration is defined as adding small parts to form a new significant part.

Parabloid, x = 4y² + 4z²

plane x = 4

x = 4y² + 4z²

x = 4

4 = 4y² + 4z²

4 = 4 (y² + z² )

1 = y² + z²

from polar coordinates

y = r cos θ

z = r sin θ

r² = y² + z²

The limits of the integral

0 ≤ θ ≤ 2π

4r² ≤ x ≤ 4

0 ≤ r ≤ 1

\(\int\int\intxdV = \int_0_1\int_b_a\int_d_cxdx(rdrdz)\)

where

a = 4

b = 4r²

c = 2r

d = 0

The first integral using limits c and d gives:

\(2\pi\int_0^1\int_b^axydx\)

The second integral using limits a and b

\(\pi \int_0^116rdr-\pi\int_0^116r^5dx\)

\(16\pi \int_0^1rdr-16\pi\int_0^1 r^5dx\)

\(16\pi\int_0^1[r-r^5]dr\)

The third integral using limits 1 and 0 gives: 16.762

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Answer:1712

Step-by-step explanation:  is 1712

Answer:

Translation: Moving an apple from one area to another area.

Reflection: Mirrors.

Rotation: Rotating a car wheel.

Step-by-step explanation:

The quotient of the given problem using laws of exponents is; 6 * 10⁰

We want to express the quotient of the quantity 30 times ten raised to the negative twenty fourth power end quantity divided by the quantity 5 times ten raised to the negative twenty fourth power end quantity.

This is;

(30 * 10⁻²⁴)/(5 * 10⁻²⁴)

Now, we can break this down into like terms to get;

(30/5) * (10⁻²⁴/10⁻²⁴)

= 6 * 1

Now, 1 can also be written as;

10⁰ = 1

Thus, the solution of the given problem is; 6 * 10⁰

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Answer:

12c8/d2.....option 1.........

a. The hypothesis test is right-tailed.

b. The P-value is 0.2525.

c. Using a significance level of a = 0.01, we fail to reject the null hypothesis .

a) The hypothesis test is right-tailed because the alternative hypothesis is p > 0.4.

b) To find the P-value, we need to use a standard normal distribution table or a calculator. Since the test statistic is positive, we look for the area to the right of z = 0.67. Using a standard normal distribution table or a calculator, we find that the area to the right of z = 0.67 is 0.2525. This is the P-value.

c) Using a significance level of a = 0.01, we compare the P-value to the significance level. The P-value is greater than the significance level, so we fail to reject the null hypothesis . There is not enough evidence to support the claim that p > 0.4 at the 1% significance level.

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The given question is incomplete, the complete question is :

The test statistic of z = 0.67 is obtained when testing the claim that p>0.4. a. Identify the hypothesis test as being two-tailed, left-tailed, or right-tailed. b. Find the P-value. c. Using a significance level of a = 0.01, should we reject null hypothesis or should we fail to reject null hypothesis?

Answer:

D

Step-by-step explanation:

the range is D because the vertex, or maximum value of the graph is at y = -1. The graph then goes downward completely, so the range is numbers including and below -1.

Answer:

This team can form 400 pretzels in one hour

Step-by-step explanation:

How many pretzels in 9 minutes?

5(12)=60

Solve as proportion

60 pretzels = 9 minutes

x    pretzels = 60 minutes

60(60)=9x

3600=9x

Divide both sides by 9

x= 400 pretzels

This team can form 400 pretzels in 1 hour

Answer:

this team can form 30 pretzels in 1 hour

Step-by-step explanation:

60 minutes are in a hour, and 60 divided by 9 is 6.6. So that means you would have to use 6. So 9 x 6 equals 54. Now do 5 x 6 and that would equal 30.

Answer:

|-2x - 5| > 5 is x < -5 or x > 0

Step-by-step explanation:

|2y + 3| < 19:

To solve this inequality, we need to consider two cases: when the expression inside the absolute value is positive and when it is negative.

Case 1: 2y + 3 > 0

In this case, the absolute value simplifies to 2y + 3 < 19.

Solving this inequality, we get 2y < 16 and y < 8.

Case 2: 2y + 3 < 0

In this case, the absolute value simplifies to -(2y + 3) < 19.

Solving this inequality, we get -2y < 22 and y > -11.

Therefore, the solution set for the inequality |2y + 3| < 19 is -11 < y < 8.

|2s - 6| < 6:

Again, we'll consider two cases based on the sign of the expression inside the absolute value.

Case 1: 2s - 6 > 0

In this case, the absolute value simplifies to 2s - 6 < 6.

Solving this inequality, we get 2s < 12 and s < 6.

Case 2: 2s - 6 < 0

In this case, the absolute value simplifies to -(2s - 6) < 6.

Solving this inequality, we get -2s < 12 and s > -6.

Therefore, the solution set for the inequality |2s - 6| < 6 is -6 < s < 6.

|5 - x| < 4:

Case 1: 5 - x > 0

In this case, the absolute value simplifies to 5 - x < 4.

Solving this inequality, we get -x < -1 and x > 1.

Case 2: 5 - x < 0

In this case, the absolute value simplifies to -(5 - x) < 4.

Solving this inequality, we get x < 9 and x < 5.

Therefore, the solution set for the inequality |5 - x| < 4 is 1 < x < 5.

|5t - 1| > 21:

Case 1: 5t - 1 > 0

In this case, the absolute value simplifies to 5t - 1 > 21.

Solving this inequality, we get 5t > 22 and t > 4.4.

Case 2: 5t - 1 < 0

In this case, the absolute value simplifies to -(5t - 1) > 21.

Solving this inequality, we get -5t > 20 and t < -4.

Therefore, the solution set for the inequality |5t - 1| > 21 is t < -4 or t > 4.4.

|-2x - 5| > 5:

Case 1: -2x - 5 > 0

In this case, the absolute value simplifies to -2x - 5 > 5.

Solving this inequality, we get -2x > 10 and x < -5.

Case 2: -2x - 5 < 0

In this case, the absolute value simplifies to -(-2x - 5) > 5.

Solving this inequality, we get 2x > 0 and x > 0.

Therefore, the solution set for the inequality |-2x - 5| > 5 is x < -5 or x > 0.

Answer:  the number's I used were 30, 20, 40

1. 2n-1=39  = 2(20)-1=39 = 40-1=39

2. 2n-60=20 = 2(40)-60=20 = 80-60=20

3. 2n-20=40 = 2(30)-10=40 = 60-20=40

Since 7 is the smallest integer that divides 173/168, we can conclude that the sum is not a prime number.

How to solve?

To add the fractions 4/7, 1/8, and 1/3, we need to find a common denominator.

The prime factorization of 7 is 7, the prime factorization of 8 is 2²3, and the prime factorization of 3 is 3. The least common multiple (LCM) of these three numbers is 7× 2²3× 3 = 168.

So, we can rewrite the fractions with the common denominator of 168:

4/7 = 96/168

1/8 = 21/168

1/3 = 56/168

Now we can add these fractions:

96/168 + 21/168 + 56/168 = 173/168

To check if this sum is a prime number, we can use trial division by checking all the integers between 2 and the√ of 173/168 (which is approximately 1.053):

2 does not divide 173/168

3 does not divide 173/168

4 does not divide 173/168

5 does not divide 173/168

6 does not divide 173/168

7 divides 173/168 (24 times)

8 does not divide 173/168

9 does not divide 173/168

...

Since 7 is the smallest integer that divides 173/168, we can conclude that the sum is not a prime number.

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Complete question:

What is the result of adding 4/7, 1/8, and 1/3, and is the sum a prime number?

Answer: 60 cm (centimeters) = 228 m (meters)

Step-by-step explanation:

Since the scale is 5 cm = 19 m, we first multiply the cm by the amount we have (228), divided by the denominator.

\(228*5=1140\\1140 / 19 = 60\)

The answer should be 5 cm = 19 m; 60 cm = 228 m

Hope this helps

If the temperature is -5 degrees in one city and it is four degrees less in another city, the temperature in the other city would be -9 degrees.

This is because subtracting four from -5 results in a decrease of four units, giving us -9 degrees.

In the given scenario, the temperature in the other city is four degrees less than the temperature in the first city. When we subtract four from the original temperature of -5 degrees, we obtain -9 degrees.

Thus, the temperature in the other city is -9 degrees, indicating that it is colder by four degrees compared to the first city.

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The condition that is not met is that the sample size must be large enough to assume that the sample proportions are normally distributed.

Number is a mathematical object used to count, measure, and label. It is one of the fundamental building blocks of mathematics and is essential for any kind of calculation or measurement. Number is an abstract concept that is used in many different ways, from counting objects to expressing complex mathematical systems. Numbers can be used to represent anything from a single item to the entire universe. Numbers are also used to represent abstract ideas such as time, money, and probability.

With a sample size of only 25, it is not possible to assume that the sample proportions follow a normal distribution. As such, calculating a confidence interval for the population proportion of bags with too much salt is not possible.

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Complete questions as follows-
sapling a quality control inspector takes a random sample of 25 bags of potato chips from the thousands of bags filled in an hour. of the bags inspected, 3 had too much salt. which of the conditions for calculating a confidence interval for the population proportion of bags with too much salt is not met?

Answer:46.15% or rounded 46% of pulling a card higher than 8.

Step-by-step explantwenty. Well there are 6 cards higher than 8, which include 9, 10, jack, queen, king, and ace. There is 4 diffrent suites so do 6×4=24. Then do 24/52=0.4615

Answer: 46.15%

Answer:

thank you

Step-by-step explanation:

Answer:

Step-by-step explanation:

<3

The area of the bigger sector and the smaller sector of the circle are 100.53 km² and 50.265 km² respectively.

The area of a sector of a circle is given by the formula A = (θ/360)πr², where θ is the central angle of the sector and r is the radius of the circle. For the bigger sector with a central angle of 225 degrees, the area is,

A₁ = (225/360)π(8 km)² ≈ 100.53 km²

To find the area of the smaller sector, we need to subtract the area of the bigger sector from the total area of the circle, which is,

A_circle = πr² = π(8 km)² ≈ 201.06 km²

The central angle of the smaller sector is,

θ₂ = 360 - 225 = 135 degrees

So the area of the smaller sector is,

A₂ = (135/360)π(8 km)² ≈ 50.265 km²

Therefore, the area of the bigger sector is approximately 100.53 square kilometers and the area of the smaller sector is approximately 50.265 square kilometers.

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Answer:

322 beavers

Step-by-step explanation:

280 × 1.15 = 322

Answer:

322

Step-by-step explanation:

15% of 280=42

280+42=322 beavers

In question 27, the price elasticity of supply for shampoo is given as 20, and the price of shampoo increases by 0.7%. The expected change in the quantity of shampoo supplied can be determined using the concept of price elasticity of supply. However, the specific percentage change in quantity supplied is not provided, so a precise answer cannot be given based on the given information.

In question 20, an inferior good in which the income effect dominates the substitution effect is referred to as a Giffen good. It is not classified as a normal good, luxury good, mass-produced good, or favored good.

In question 30, the cross elasticity of demand measures the responsiveness of the quantity demanded of a particular good to changes in the prices of its substitutes and complements. The correct answer is that the cross elasticity of demand measures the responsiveness to changes in both substitutes and complements.

In question 27, without the specific percentage change in quantity supplied, we cannot determine the exact outcome based on the given information. The price elasticity of supply of 20 suggests that the quantity supplied is highly responsive to changes in price, but the specific percentage change in quantity supplied cannot be calculated without additional data.

In question 28, the relationship between pasta being a Giffen good and other characteristics is not specified. While pasta being a Giffen good indicates that the quantity demanded increases as the price increases, it does not imply whether pasta is a normal good, luxury good, or how price changes affect quantity demanded.

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The concentration of antifreeze in the compartment over time, C(t) is obtained by solving the differential equation, dC (100+2t) +4C(t) = 4Cin dt given that Qin = 4cls- and Q out = 2 ds- and the initial amount of liquid in the compartment is Vo = 100 cL.

For solving the differential equation, we need to first write it in the standard form, i.e.,

 dC/dt + (4/(100+2t))C = 4Cin/(100+2t). Here, integrating factor is I(t) = e^∫(4/(100+2t)) dt = e^(2ln(100+2t)) = e^ln(100+2t)^2 = (100+2t)^2.

On multiplying the given differential equation with I(t), we get

(100+2t)^2dC/dt + 4(100+2t)C = 4Cin(100+2t).

Integrating both sides with respect to t, we get:

∫(100+2t)^2 dC/dt dt + ∫4(100+2t) C dt = ∫4Cin(100+2t) dt.

On solving the integrals, we get:

(1/3)(100+2t)^3C - (1/3)(100+2t)^3Co + 2Cln(100+2t) - 2Coln(100) = 2Cin(t+ln(100)) + k .

Where, k is the arbitrary constant and Cin = 4cls- and Co = C(0) are given constants. The value of the arbitrary constant k can be obtained using the initial condition that the concentration of antifreeze in the compartment is Co when t = 0.

Therefore, we have C(0) = Co.(1/3)(100)^3C - (1/3)(100)^3Co - 2Coln(100) = 2Cinln(100) + k.

∴ k = (1/3)(100)^3(C - Co) - 2Co ln(100) + 2Cinln(100).

Substituting this value of k in the above equation, we get:

(1/3)(100+2t)^3C - (1/3)(100+2t)^3Co + 2Cln(100+2t) - 2Coln(100) = 2Cin(t+ln(100)) + (1/3)(100)^3(C - Co) - 2Co ln(100) + 2Cinln(100).

This is the required equation for the concentration of antifreeze in the compartment over time, C(t).

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Answer:

Step-by-step explanation:

Unit rate = 26.2 ÷ 4 = 6.55

The planning value for the population standard deviation is estimated to be $3,350, and sample sizes of approximately 46, 566, and 2,262 would be needed to achieve desired margins of error of $500, $200, and $100, respectively.

(a) Desired margin of error = $500

The formula for the sample size required to estimate the population mean with a desired margin of error is:

n = (Z * σ / E)²

Where:

n = sample size

Z = Z-score corresponding to the desired confidence level (95% confidence level corresponds to a Z-score of 1.96)

σ = population standard deviation

E = desired margin of error

Since we don't have the actual population standard deviation, we can estimate it using the planning value.

Range of expected salaries = $55,400 - $42,000 = $13,400

Planning value for standard deviation = Range / 4 = $13,400 / 4 = $3,350

Substituting the values into the formula:

n = (1.96 * $3,350 / $500)² ≈ 45.96

Since we can't have a fraction of a sample, we need to round up to the nearest whole number.

Therefore, the sample size needed for a desired margin of error of $500 is 46.

(b) Desired margin of error = $200

Using the same formula:

n = (1.96 * $3,350 / $200)² ≈ 565.44

Rounding up to the nearest whole number, the sample size needed for a desired margin of error of $200 is 566.

(c) Desired margin of error = $100

Using the same formula:

n = (1.96 * $3,350 / $100)² ≈ 2,261.76

Rounding up to the nearest whole number, the sample size needed for a desired margin of error of $100 is 2,262.

(d) Would you recommend trying to obtain the $100 margin of error? Explain.

Obtaining a margin of error as low as $100 would require a sample size of 2,262. While this larger sample size may provide a more precise estimate, it also increases the cost and time required for data collection and analysis. Therefore, the decision to obtain such a small margin of error should be based on the practicality and resources available. It is important to consider the trade-off between the desired level of precision and the associated costs and efforts.

Therefore, the planning value for the population standard deviation is estimated to be $3,350, and sample sizes of approximately 46, 566, and 2,262 would be needed to achieve desired margins of error of $500, $200, and $100, respectively.

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