The small earthquake starts a lamppost vibrating back-and-forth. The amplitude of the vibration of the top of the lamp post is 6.8 cm at the moment the quick stops and 9.0s later it is 1.9cm

A) what is the time constant for the damping of the oscillation

B) what is the amplitude of oscillation 4.5 seconds later after the earthquake stopped

An electron (charge -e) is at rest in a region of electric potential that varies as a function of position. When released it will move A. into a region of lower potential.

Since the electric potential varies as a function of position, there will be regions of higher and lower potential energy. The electron will move from a region of higher potential energy to a region of lower potential energy. Therefore, the electron will move into a region of lower potential The direction of the electric field is perpendicular to the equipotential lines. Therefore, the electron will move in the direction of the electric field if the equipotential lines are not parallel to the electric field.

If the equipotential lines are parallel to the electric field, the electron will move perpendicular to the electric field. In summary, the electron will move into a region of lower potential while following the direction of the electric field or moving perpendicular to it depending on the orientation of the equipotential lines. So therefore the correct answer is An electron (charge -e) is at rest in a region of electric potential that varies as a function of position. When released it will move A. into a region of lower potential.

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Answer:

0.1 m

Explanation:

From the question given above, the following data were obtained:

Mass (m) of ball = 4 Kg

Acceleration due to gravity (g) = 9.8 m/s²

Energy (E) = 4 J

Height (h) =?

The height (h) can be obtained by using the following formula:

E = mgh

4 = 4 × 9.8 × h

4 = 39.2 × h

Divide both side by 39.2

h = 4 / 39.2

h = 0.1 m

Thus, the value of h is 0.1 m

Answer:-4410 m

Explanation:

Displacement = velocity*time

Displacement = -98 m/s * 45 s

Displacement = -4410 m

The amount of charge flowing through the third light bulb over the course of 9.80 minutes is 6.069C.

Since we know the relation between current and charge and also current is same in case of series connection and here three bulb connected in series.

I = q / t

given:

I = ?
q = 2.06 C

t = 2.59 minutes = 155.4 sec

I = 2.06 / 155.4 A

We have to find charge flow in 7.63 minutes

q = I x t

q = 2.06 / 155.4 x 7.63 x 60

q = 6.069C

In the field of physics, charge refers to a fundamental property of matter that describes the amount of electrical force that an object possesses. Charge is quantized, meaning that it comes in discrete units, and it can be either positive or negative. Objects that have the same type of charge (either positive or negative) repel each other, while objects with opposite charges attract each other. This is the basis for the behavior of electrical circuits, as well as the functioning of electronic devices.

Charge is also conserved, meaning that it cannot be created or destroyed, only transferred from one object to another. This is why electrical devices are designed to use energy efficiently, as any charge lost due to resistance in the circuit will be converted into heat and cannot be recovered.

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Answer:

50.176m ; 31.36m/s ; 31.36m/s

Explanation:

Given the following :

Time (t) = 3.2s

Height(s) of the building

The initial velocity (u) will be 0

Using the equation:

S = ut + 0.5at^2

Acceleration due to gravity (a) = g = +9.8m/s^2 (downward)

S = 0*t + 0.5(9.8)(3.2^2)

S = 0 + 50.176

S = 50.176m

B.) speed impact when it touches the ground:

v^2 = u^2 + 2aS

where v is the final Velocity

v^2 = 0^2 + 2(9.8)(50.176)

v^2 = 0 + 983.4496

v = √983.4496

v = 31.36m/s

C) Speed of throw from the ground to reach the top of the building

Here we need the initial velocity

Height (s) = 50.176m

Acceleration due to gravity g = a = - 9.8m/s ( upward)

Using the third equation of motion:

S = ut + 0.5at^2

50.176 = u*3.2 + 0.5(-9.8)(3.2^2)

50.176 = 3.2u - 50.176

50.176 + 50.176 = 3.2u

100.352 = 3.2u

u = 100.352 / 3.2

u = 31.36m/s

Answer:

There are three laws of newton

hope this helps.........

Answer:

When an object is in contact with another object, it creates friction.

Answer:

Explanation:

Mixtures containing substances that are attracted by magnets can be separated using a magnet. We can separate iron from a mixture of sand and iron, as only the iron is attracted to the magnet.

The correct statements are:

a) The t ratios are used to test if the estimated slope is different from zero.

d) If the UV reading is increased by 1 Dobson unit, the yield is expected to increase by 0.0463 kg.

e) The estimated yield is 3.98 kg when the UV reading is 0 Dobson units.

Statement b is incorrect because it provides a specific prediction for the yield at a certain UV reading, without any indication of how this was calculated or what model was used.

Statement c is incorrect because it implies a negative relationship between yield and UV reading, which contradicts the positive relationship suggested by statement d.

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Answer:

Time

Explanation:

As

   Speed = distaance / time

        S = d/t

     t  =  d/s

Answer:

111.4 m

Explanation:

PE = m x g x h

349,300 = 320 x 9.8 x h

h = 349300 : 3136

h = 111,384 m

Answer:

true

Explanation:

i think it's true I'm not exactly sure

Answer:

B. unsaturated​

Explanation:

The static friction value is the value from zero to the minimum force required to initiate motion. The formula for calculating static friction is:

Static Friction = Normal Force x Static Friction Coefficient.

The maximum or limit of friction between two surfaces is FMAX=μR F MAX = μR. where μ is the coefficient of friction and R is the normal reaction between two surfaces. The coefficient of friction is a measure of surface roughness, with rougher surfaces having higher values. Therefore, as the car makes a circular motion, the necessary centripetal force is provided by the frictional force. Therefore, the coefficient of static friction between a car tire and the road surface is 0.53.

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Answer:

2.5 joules

Explanation:

The amount of energy stored in a spring can be calculated using the formula:

E = 1/2 kx^2

where E is the energy stored, k is the spring constant, and x is the displacement of the spring from its equilibrium position.

In this case, the spring constant is 20 N/m and the displacement is 0.5 m (since the spring is compressed). Plugging these values into the formula, we get:

E = 1/2 * 20 N/m * (0.5 m)^2 = 2.5 J

Therefore, the amount of energy stored in the spring is 2.5 joules.

If you measured the apparent brightness of two stars just like the sun and found that star A appears four times brighter than star B, it means that star A has a higher luminosity than star B. This is because the apparent brightness of a star depends on both its luminosity (intrinsic brightness) and its distance from Earth.

The apparent brightness of star A is four times that of star B, indicating that star A is either closer to Earth or has a higher luminosity. However, if we assume that both stars are at the same distance from Earth, then the difference in their apparent brightness is solely due to their intrinsic brightness. Therefore, star A has a luminosity four times that of star B.

Explanation: The apparent brightness of a star is the amount of light that reaches Earth from the star per unit area per unit time. It is measured in units of flux (energy per unit time per unit area) and depends on the star's luminosity and its distance from Earth. The luminosity of a star is its intrinsic brightness, or the amount of energy it emits per unit time, and is measured in units of power (energy per unit time).

In this scenario, we are comparing the apparent brightness of two stars that are just like the sun, meaning they have the same intrinsic brightness. If we measure their apparent brightness and find that star A appears four times brighter than star B, then we can conclude that star A has a higher luminosity than star B. This is because the apparent brightness of a star is inversely proportional to the square of its distance from Earth, and if we assume that both stars are at the same distance, then the difference in their apparent brightness is solely due to their intrinsic brightness.

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Answer: Explanation:

A number used to multiply a variable. Example: 6z means 6 times z, and "z" is a variable, so 6 is a coefficient. ... Example: In ax^2 + bx + c, "x" is a variable, and "a" and "b" are coefficients.

The work and potential energy the book has after it has been lifted to a height of 5 meters is determined as 147 J.

The amount of work required to lift the book to a height of 5 meters is equal to the potential energy and it is calculated as follows;

P.E = mgh

where;

P.E = 29.4 N x 5 m = 147 J

Thus, the potential energy of the object at the given height is equal to the work done in raise the object to the said height due to law of conservation of energy.

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To find the resultant force we will first find the component force of the forces given, to do this, we need to remember that any vector can be express in component form by:

For force u we notice that its magnitude is 280 N and its angle is zero, then we have:

For force v we know that its magnitude is 135 N and its angle is 45°, then we have:

Now that we have both vectors in component form we add them to get the resultant in component form:

Once we have the resultant force in component form we can find its magnitude and direction if we remember that they are given by:

Plugging the values we found for the components we have:

and

Therefore, the magnitude of the resultant force is 387.41 N and the direction is 14.27°

The pump delivers 8.36 J of kinetic energy to the water every second.

To calculate the kinetic energy delivered by the pump to the water every second, we first need to determine the power output of the solar panel. Power is defined as the rate at which energy is transferred, so we can calculate it by multiplying the voltage and current:

Power = Voltage x Current

Power = 10 V x 0.25 A

Power = 2.5 W

Next, we need to take into account the efficiency of the pump, which is 30%. This means that only 30% of the power input to the pump is converted into the kinetic energy of the water. Kinetic energy is defined as 1/2 x mass x \(velocity^2\). Assuming the mass of the water being pumped is constant, we can calculate the velocity of the water by dividing the power output of the solar panel by the power required to operate the pump at its 30% efficiency:

Power required = Power output / Pump efficiency

Power required = 2.5 W / 0.3

Power required = 8.33 W

Now we can use the power required to calculate the velocity of the water:

Power required = 1/2 x mass x \(velocity^2\)

8.33 W = 1/2 x mass x \(velocity^2\)

Rearranging the equation, we get:

velocity = sqrt(8.33 W / (1/2 x mass))

Assuming the mass of the water being pumped is 1 kg, the velocity of the water is:

velocity = sqrt(8.33 W / (1/2 x 1 kg))

velocity = 4.08 m/s

Finally, we can calculate the kinetic energy delivered by the pump to the water every second:

Kinetic energy = 1/2 x mass x \(velocity^2\)

Kinetic energy = 1/2 x 1 kg x \((4.08)^2\)

Kinetic energy = 8.36 J

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Answer:

The answer is C

Explanation:

Testable meaning experiments can be conducted to support or refute the hypothesis. This is done through data.

Answer : The amount of riboflavin extracted is 8.685 mg. Given:Mass of cereal taken for grinding, m = 1.526 gVolume of water used, V = 40.0 mLVolume of acetic acid used, v = 0.25 mLVolume of extraction solution taken, V1 = 275 µlVolume of pH 7.0 phosphate buffer used for dilution, V2 = 10 mLFluorescence intensity measured, y = 153.00 a.u.

External standard calibration curve equation (fluorescence intensity v. concentration in ppb), y = 4.00 x + 26.7We are to find the concentration of the extraction solution in ppm and the amount of riboflavin extracted.

1. Calculation of the concentration of the extraction solution in ppm. We know that the fluorescence intensity, y is given by the equation:y = 4.00x + 26.7, where x is the concentration of riboflavin in ppb. Substituting the given value of y, we get:153 = 4.00x + 26.7 ⇒ 4.00x = 153 - 26.7 = 126.3⇒ x = 31.575 ppb. Since, 1 ppb = 1 µg/L,

hence, 31.575 ppb = 31.575 µg/L = 31.575 mg/L = 31.575 ppm. Therefore, the concentration of the extraction solution in ppm is 31.575 ppm.

2. Calculation of the amount of riboflavin extracted.To calculate the amount of riboflavin extracted, we can use the following formula:

Amount of riboflavin extracted = Concentration of riboflavin x Volume of extraction solution taken for dilution. We know that the volume of extraction solution taken for dilution, V1 = 275 µl = 0.275 mL. Also, the concentration of riboflavin in the extraction solution, C = 31.575 ppm.

Therefore  Amount of riboflavin extracted = 31.575 ppm x 0.275 mL= 8.685 mg. Therefore, the amount of riboflavin extracted is 8.685 mg.

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When a light source is turned on, it emits photons that scatter in different directions and hit every object that is present around it.

This is referred to as the path in which electric current can flow around and comprises of some components such as resistors, bulb etc. There are two types which include open and closed circuit.

When the light source is turned on, the circuit is closed and there is complete flow of electrons which powers up the bulb and gives rise to the emission of the photons which hits objects around it thereby giving rise to the illumination of the area.

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Answer:

Las estrellas se forman debido a la unión de pequeños elementos y partículas como el hidrógeno y el helio que experimentan una fusión nuclear en el núcleo debido a la intensa presión para formar un nuevo átomo (como dos hidrógeno que se combinan para formar un átomo de helio) que es un proceso. que requiere una gran cantidad de energía para comenzar, por lo que cada reacción de fusión produce una gran cantidad de energía que puede mantener la reacción y equilibra la fuerza gravitacional que atrae las masas de las partículas hacia el centro de la estrella

A medida que la energía de la estrella se irradia, la superficie de la estrella cede la energía en forma de calor y luz de manera que debido a la alta temperatura de las partículas de los átomos de los elementos se mueven muy rápida y energéticamente para emitir fotones rápidamente. (alta frecuencia) que se ve como el alto brillo de la estrella

Explanation: