225.0 g of water releases 32.07 kJ of heat when it cools from 85.5 °C to 50.0 °C.
When water cools, it releases heat. To calculate the amount of heat that 225.0 g of water releases as it cools from 85.5 °C to 50.0 °C,
we can use the formula q = mct. In this formula, q represents the amount of heat released, m represents the mass of the water, c represents the specific heat of the water, and t represents the change in temperature.
Plugging in the values given in the question, we get:q = 225.0 g × 4.18 J/g•°C × (85.5 °C − 50.0 °C) = 32,067.75 J or 32.07 kJ
Therefore, 225.0 g of water releases 32.07 kJ of heat when it cools from 85.5 °C to 50.0 °C.
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The specific heat of water is 4.18 J/g•°C. How much heat does 225.0 g of water release when it cools from 85.5°C to 50.0°C?
Use the formula q = mC T.
Answer: B
3.34 x 10 exponent- 4 J
A penguin swimming underwater goes 20 meters in 5 seconds. What is its average speed?
Answer:
4 meters per second
Explanation:
When removing heavy objects that may change the center of gravity of a vehicle ________. Group of answer choices
Answer:
______________________________
use tall safety and position hoist arms
a car starts from the rest and accelerates at 9.54m/s for 6.5 seconds. what is the distance covered by the car
Answer:
= 201.53 meters
Explanation:
A car started from rest and accelerated at 9.54 m/s^2 for 6.5 seconds. How much distance was covered by the car?
Use the formula d = \(\frac{at^{2} }{2} ,\)
where d is the distance, t is the time and "a" is the acceleration.
\(d=\frac{9*54*6*5^{2} }{2} = 201.53 m\)
what was one mystery exhibited by the motions of the sun and a few other sky objects?
One mystery that was exhibited by the motions of the sun and a few other sky objects was the apparent retrograde motion of the planets.
In ancient times, people observed that the planets (including Mars, Jupiter, and Saturn) would sometimes appear to move backward in the sky for a few weeks or months before resuming their forward motion.
This retrograde motion was difficult to explain using the geocentric model of the universe, in which the Earth was considered to be the center of the cosmos and all the other celestial bodies revolved around it. It wasn't until the heliocentric model was proposed, with the sun at the center of the solar system, that this mystery could be explained as a result of differences in the orbital speeds and distances of the planets.
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Being interested in penguins, Paul wanted to study the effect of fast food hamburgers on the weight of penguins. After many trials of trying to get the penguins to eat the burgers, Paul became frustrated at the fact that the penguins were losing weight and not eating any of the burgers. Why was Paul's experiment not a complete waste of time and resources?
A) Paul got to spend time with the penguins. Eliminate
B) There was nothing valuable gained from this.
C) The penguins were overweight and needed to lose weight.
D) Paul found that fast food burgers cause penguins to lose weight.
Answer:
Paul found that fast food burgers cause penguins to lose weight.
Explanation:
A = (1 point) A particle is moving with acceleration a(t) = 6t + 8. its position at time t = O is s(0) = 6 and its velocity at time t = 0 is v(O) = 2. What is its position at time t = 7? =
Answer:
\(559\).
Explanation:
Integrate \(a(t)\) with respect to time \(t\) to find an expression for velocity:
\(\begin{aligned} v(t) &= \int a(t)\, d t \\ &= \int (6\, t + 8)\, d t && (\text{power rule}) \\ &= 3\, t^{2} + 8\, t + C_{v} \end{aligned}\).
Note that since this integral is indefinite, the expression for \(v(t)\) includes a constant \(C_{v}\).
Find the value of \(C_{v}\) using the fact that \(v(0) = 2\). Specifically, substitute \(t = 0\) into the expression \(v(t) = 3\, t^{2} + 8\, t + C_{v}\) and solve for \(C_{v}\!\):
\(v(0) = 3\, (0)^{2} + 8\, (0) + C_{v} = C_{v}\).
\(v(0) = 2\).
\(C_{v} = 2\).
In other words, \(v(t) = 3\, t^{2} + 8\, t + 2\).
Similarly, integrate \(v(t)\) with respect to \(t\) to find an expression for position:
\(\begin{aligned} s(t) &= \int v(t)\, d t \\ &= \int (3\, t^{2} + 8\, t + 2)\, d t\\ &= t^{3} + 4\, t^{2} + 2\, t + C_{s} \end{aligned}\).
Similarly, find the value of constant \(C_{s}\) using the fact that \(s(0) = 6\):
\(s(0) = (0)^{3} + 4\, (0)^{2} + 2\, (0) + C_{s} = C_{s}\).
\(s(0) = 6\).
\(C_{s} = 6\).
In other words, \(s(t) = t^{3} + 4\, t^{2} + 2\, t + 6\). Substitute in \(t = 7\) and evaluate to find the position of the particle at that moment:
\(s(7) = 7^{3} + 4\, (7)^{2} + 2\, (7) + 6 = 559\).
The pοsitiοn of the particle at time t = 7 is 559 units.
How tο find the pοsitiοn at time?Tο find the pοsitiοn at time t = 7, we need tο integrate the given acceleratiοn functiοn tο οbtain the velοcity functiοn and then integrate the velοcity functiοn tο οbtain the pοsitiοn functiοn.
Given:
Acceleratiοn functiοn: a(t) = 6t + 8
Initial pοsitiοn: s(0) = 6
Initial velοcity: v(0) = 2
First, let's integrate the acceleratiοn functiοn tο οbtain the velοcity functiοn:
v(t) = ∫(a(t)) dt
= ∫(6t + 8) dt
= 3t^2 + 8t + C
Tο find the cοnstant οf integratiοn (C), we can use the initial velοcity v(0) = 2:
2 = 3(0)² + 8(0) + C
C = 2
Sο, the velοcity functiοn becοmes:
v(t) = 3t² + 8t + 2
Next, let's integrate the velοcity functiοn tο οbtain the pοsitiοn functiοn:
s(t) = ∫(v(t)) dt
= ∫(3t² + 8t + 2) dt
= t³ + 4t² + 2t + C'
Tο find the cοnstant οf integratiοn (C'), we can use the initial pοsitiοn s(0) = 6:
6 = (0)³ + 4(0)² + 2(0) + C'
C' = 6
Sο, the pοsitiοn functiοn becοmes:
s(t) = t³ + 4t² + 2t + 6
Finally, we can find the pοsitiοn at time t = 7:
s(7) = (7)³+ 4(7)² + 2(7) + 6
= 343 + 196 + 14 + 6
= 559
Therefοre, the pοsitiοn at time t = 7 is 559 units.
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the work is done, but what two assumptions can be made?
Answer:
Oh for number this is the one?
A spacecraft is currently orbiting around the Earth, its position reported by optical mea- surements and its velocity reported via on-board IMU are the following: ri = 3Ro + 5 Roû = V1 = -3.2c + 2y + 2.52 km/s Determine a, e, i, N, w, r, v, y,0*, M, E, t - tp.
Edit for Anonymous Comment: if you knew orbital mechanics you would know what each represents. e is Eccentricity, E is eccentric anomaly, these are all orbital elements. I is inclination angle, argument of periapsis is lower omega, Theta star is true anomaly, etc. I don't think I need to give you what these variables mean if you know the topic.
These orbital elements can be calculated using standard methods in orbital mechanics.
How to calculate the various orbital elements for a spacecraft orbiting the Earth, using its position and velocity vectors?To determine the orbital elements and other parameters of the spacecraft, we first need to convert its position and velocity vectors from Cartesian coordinates to Keplerian elements. We can do this using the following steps:
Calculate the specific angular momentum vector h:
h = ri x Vi
where ri and Vi are the position and velocity vectors, respectively, in Cartesian coordinates.
h = (3Ro + 5Ro) (-2.52c + 2y) - (-3.2c + 2y + 2.52 km/s) (5Ro)
h = 5.2 Ro c + 15.16 km/s y
Calculate the magnitude of the specific angular momentum:
| h | = sqrt(h^2)
| h | = sqrt[(5.2 Ro c)^2 + (15.16 km/s y)^2]
| h | = 15.94 km^2/s
Calculate the inclination angle i:
i = cos^-1(hz / | h |)
where hz is the z-component of the specific angular momentum vector.
hz = 15.16 km/s
i = cos^-1(15.16 km/s / 15.94 km^2/s)
i = 3.86°
Calculate the node vector N:
N = k x h / | k x h |
where k is the unit vector in the z-direction.
k = (0, 0, 1)
N = k x h / | k x h |
N = (-15.16 km/s, 5.2 Ro c, 0) / sqrt[(5.2 Ro c)^2 + (15.16 km/s)^2]
N = (-0.888, 0.306, 0)
Calculate the argument of periapsis w:
w = cos^-1(N · e / | N |)
where e is the eccentricity vector.
e = [1/μ ((V^2 - μ/| r |) r - (r · V) V)]
where μ is the gravitational parameter of the Earth, V is the velocity vector in Cartesian coordinates, and r is the position vector in Cartesian coordinates.
μ = 3.986004418 x 10^5 km^3/s^2
| r | = sqrt[(3Ro + 5Ro)^2] = 8Ro
V = (-3.2c + 2y + 2.52 km/s)
r = (3Ro + 5Ro)
e = [1/3.986004418 x 10^5 km^3/s^2 ((2.52 km/s)^2 - (3.986004418 x 10^5 km^3/s^2 / 8Ro)) (3Ro + 5Ro) - ((3Ro + 5Ro) · (-3.2c + 2y + 2.52 km/s)) (-3.2c + 2y + 2.52 km/s)]
e = (0.715, -0.439, 0)
w = cos^-1((N · e) / | N |)
w = cos^-1((-0.888 x 0.715) + (0.306 x -0.439))
w = 135.9°
Calculate the eccentricity magnitude e:
e = sqrt(e^2)
e = sqrt(0.715^2 + (-0.439)^2)e = 0.84
Calculate the semi-major axis a:
a = (2 / | r | - (V · V))^-1
a = (2 / 8Ro - (2
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Select the frequency of light having a wavelength of 2. 4 × 1010 nm and the wavelength of light with a frequency of 2. 4 × 1010 hz. Select all that apply.
The frequency of the light is 1.3 × 10⁷ Hz and wavelength of the light is 1.3 x 10⁷ nm
What is frequency?The frequency of a repeated event is its number of instances per unit of time. In certain cases, it is also referred to as temporal frequency or ordinary frequency to underline differences with spatial and angular frequencies, respectively.
What is wavelength?A waveform signal that is carried in space or down a wire has a wavelength, which is the separation between two identical places (adjacent crests) in the consecutive cycles. This length is often defined in wireless systems in metres (m), centimetres (cm), or millimetres (mm) (mm).
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newton's second law in 1 dimension: a net force of 125 n is applied to a certain object. as a result, the object accelerates with an acceleration of 24.0 m/s2. the mass of the object is
The mass of the object when a net force of 125 n is applied to a certain object is 5.2 kg
Newton's second law in one dimension states that the net force acting on an object is equal to the product of the object's mass and its acceleration. In mathematical form, the law is expressed as:
F = ma
Where F is the net force, m is the mass of the object, and a is the acceleration of the object.
In this case, we are given that a net force of 125 n is applied to an object and that the object accelerates with an acceleration of 24.0 m/s2. We are asked to find the mass of the object.
We can solve for the mass using the equation above:
m = F / a
= 125 n / 24.0 m/s2
= approximately 5.2 kg
Therefore, the mass of the object is approximately 5.2 kg.
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Which statements describe vectors? Check all that apply. -Vectors have magnitude only. -Vectors have direction only. -Vectors have both magnitude and direction. -Vectors are drawn using a curved line. -Vectors are drawn using an arrow.
Answer:
Vectors have both magnitude and direction
Explanation:
Vectors show how strong the force in because the bigger the arrow, the stronger the force. Also, it obviously shows direction because its an arrow.
Vectors have magnitude and direction while scalars have only magnitude. Vectors are shown using an arrow above the symbol of the quantity and are often printed in bold face.
In Physics, we generally recognize two categories of quantities; vector quantities and scalar quantities.
Vector quantities have both magnitude and direction. It is normal to print vectors in bold face, with an arrow written above the symbol of the quantity. The arrow points in the direction of the vector.
The following are true regarding vectors;
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Two parallel plates have an area of
0.00100 m^2. How much charge
must you place on them to create a
1000 N/C field between the plates?
(The answer is *10^-12 C. Just fill
in the number, not the power.)
Answer:
8.85
Explanation:
The computation of the charge that must place on them in order to create 1000 N/C field between the plates is shown below:
We know that
E = (Q/A) ÷ E_o
1000 = Q ÷ 0.01×8.85× 10^-12
Q = 8.85 × 10^-12
So,
The answer is 8.85
The above formula should be applied so that the correct value could come
And, the same would be relevant
Answer:
8.85
Explanation:
acellus
20 pts) NaLi molecule (sec. 5.3, p.75) has a built-in polarization. The inter-atomic distance d=3.0A˚. If one would apply an electric field along the molecular axis to cancel the polarization, in which direction and what magnitude should the field be? Also determine the filed (direction and magnitude) to double the polarization. Use the energy levels given in the textbook (sec. 5.3), and Vss σ given in (6.6), p.95. Use V/cm for the unit of the electric field. <2∣H∣1>VssσVppσ≡∫ψ2 s(r−r2)∗Hψ2 s(r−r1)d3r=−8π2md2ℏ2,=+83π2md2ℏ2,Vspσ=+2πmd2ℏ2Vppπ=−8π2md2ℏ2
To cancel the polarization of a NaLi molecule, an electric field of magnitude 5.33 V/Å needs to be applied along the molecular axis in the direction opposite to the polarization.
To double the polarization of a NaLi molecule, an electric field of magnitude 10.66 V/Å needs to be applied along the molecular axis in the direction of the polarization.
The polarization of a NaLi molecule is due to the difference in electronegativity between sodium and lithium. Sodium is more electropositive than lithium, which means that it has a stronger affinity for electrons.
This means that the electrons in the NaLi molecule are more likely to be found closer to the sodium atom than the lithium atom.
The electric field will exert a force on the electrons in the NaLi molecule, trying to pull them away from the sodium atom and towards the lithium atom. If the electric field is strong enough, it will be able to cancel the polarization of the molecule.
The magnitude of the electric field needed to cancel the polarization of a NaLi molecule can be calculated using the following formula:
E = 2qd / e
where:
E is the magnitude of the electric field
q is the charge of an electron
d is the inter-atomic distance
e is the permittivity of free space
In this case, the magnitude of the electric field needed to cancel the polarization of a NaLi molecule is:
E = 2 * (1.602 * 10^-19 C) * (3.0 * 10^-10 m) / (8.854 * 10^-12 C^2 / N m^2) = 5.33 V/Å
To double the polarization of a NaLi molecule, the electric field would need to be twice as strong. This means that the magnitude of the electric field would need to be 10.66 V/Å.
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why is the system of si unit developed
Answer:
It allows people in different places and different countries to use the same units
Explanation:
What would be the electron configuration for an aluminum ion?.
Answer:
[Ne] 3s² 3p¹
Explanation:
Answer: 1s2 2s2 2p6
Explanation:
The aluminum ground state would be 1s2 2s2 2p6 3s2 3p1.
However, the Aluminum Ion electron configuration would be 1s2 2s2 2p6 as it has LOST 3 electrons to have the noble gas configuration of Neon (Ne)
what safety precautions do you have to keep in mind when playing invasion games?
Wear protective gear, such as helmets, protective pads, and other gear.
Warm up and cool down.
Know the rules of the game.
Watch out for others.
Don't play when you're injured.
ured length. Measurement errors are another type of uncertainty involved in single measurements. Suppose we measure the diameter of a disk. The minimum length that can be measured on the stick is 1 mm (0.1 cm). If the diameter lies somewhere between 5.1 cm and 5.2 cm, which value do we report? In such cases the value is reported as 5.15 ± 0.05 cm. Note that the uncertainty of the measurement is one half the smallest tick mark on the measuring device. This applies to all instruments. A sound experimental procedure involves several measurements of the physical quantities required in one of several ways. Once those measurements have been made, we compute the statistical quantities listed in the key concepts above to make inferences from the data obtained. Question 1 (write down answers on Report Sheets) Below are three sets of measurements of the boiling point of water at 1 standard atmosphere (atm): Measurement 1 2 3 4 5 Set A 99.8 °C 99.8 °C 99.8 °C 99.8 °C 99.8 °C Set B 100.0
Answer:
T = (99.78 ±0.05) ºC
Explanation:
This problem refers to the procedure to perform the measurements and their correct reporting.
Suppose that the thermometer used has an appreciation of 0.1ºC and the values of 5 measurements resulted in
# T (ºC)
1 99.8
2 99.7
3 99.7
4 99.8
5 99.9
the processing calculate mean value
T_average = ∑ \(T_{i}\) / n
T_average = (99.8 + 99.7 + 99.7 + 99.8 + 99.9) / 5
T_average = 99.78ºC
the absolute error or uncertainty of the measurement is half the appreciation of the instrument
ΔT = ± 0.05ºC
so the result must be written
T = (99.78 ±0.05) ºC
on the celestial sphere, which of the following terms are specific to the observer (that is, they are unique for unique observers)? (choose all that apply.) select one or more: a. celestial equator b. north celestial pole c. nadir d. meridian e. horizon f. zenith g. ecliptic
The terms specific to the observer are e, f, and g. The ecliptic is the path that the Sun appears to follow across the sky throughout the year as viewed from Earth.
The horizon is an imaginary line that marks the point where the sky and the Earth's surface seem to meet. The zenith is an imaginary point directly overhead from the observer's location.
The celestial equator is an imaginary line that runs around the celestial sphere, dividing it into two hemispheres. The north celestial pole is the point directly above the observer's north horizon. The nadir is an imaginary point directly below the observer's location.
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52 Points HELP
An arrow leaves a bow at an anitial velocity of 47.74m/s. 0.5 seconds after leaving the bow. When the arrow reaches the target its final velocity is 68.58m/s, 5 seconds later. what is the acceleration of the arrow
27.5 m/s. If the average force exerted on the arrow by the bow was increased 3 times and the arrow was accelerated over the same distance
Forensic toxicologist analyze and identify drugs that are confiscated from criminals
True
False
It is a hot summer day at the beach. From your understanding of specific heat capacity, what can you expect to be the difference between the sand and the water?
The water will gain more thermal energy than the sand
The water will heat up faster then the sand
The sand will heat up faster than the water
The sand will lose its energy more slowly than the water
Answer:
the sand will heat up faster than the water
Explanation:
water has slow heat conduction
and sand had high heat conduction
Which best describes the purpose of a controlled experiment?
A) to make sure the results of the experiment support the hypothesis
B) to prevent a dangerous condition resulting from a reaction
C) to examine whether one variable causes a change in another
B) to prevent an undesired change in a variable
Answer:
Its C
Explanation:
Answer:
C) to examine whether one variable causes a change in another
What is the acceleration of a bike which increases its speed from 0 to 40 ft/s in 4 seconds?
The acceleration of a bike which increases its speed from 0 to 40 ft/s in 4 seconds will be 3 m/s².
How do you determine the acceleration of the bike?Given, initial speed (u) = 0
Final speed (v) = 40 ft/s = 12 m/s
Time taken = 4 seconds
From the equation v = u + at, we have
12 = 0 + a x 4
12 = 4a
a = 3 m/s²
The acceleration formula is what?The equation a = v/t denotes acceleration (a), which is the change in velocity (v) over the change in time (t). This enables you to calculate the change in velocity in meters per second squared (m/s²). Since acceleration is a vector quantity, both its magnitude and its direction are included.
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When a car is going at a constant velocity down the freeway, is the net force zero or not zero assuming no friction?
Answer:
Zero
Explanation:
The net force acting on an object moving with constant velocity is zero. This is an accordance with the Newton's first law of motion.
Newton's first law of motion states that a body will continue in its state of rest or constant motion unless it is acted upon by an external force.
Since this body is moving with uniform motion, it is not accelerating. When a body is acceleration, the net force on it is not zero.
But this one is moving with uniform motion. The net force on the body is balanced and zero.
Please help and show all work!
Thank you
The cue ball's final velocity is 0.453 m/s, or 0.90 m/s.
What is velocity, for instance?The pace at which an item goes in one direction is known as its velocity. As the velocity of a car driving northward on a highway or the pace at which a rocket takes off. The vector quantity velocity (v), denoted by the formula v = s/t, quantifies deformation (or shift in position, s), over change in time (t).
What does velocities mean?The displacement that such an object or particles experiences with regards to time is expressed vectorially as velocity. The meters per second (m/s) is the accepted unit of velocity profile (sometimes known as speed).
Let "v" represent the ball's ultimate speed.
Apply the law of linear momentum conservation.
Total initial momentum is = Total final momentum
=(0.17 x 1.3) + (0.16 x 0) = (0.17 x v) + (0.16 x 0.90)
0.221 = 0.17v + 0.144
0.17 v = 0.221 - 0.144
v = (0.077) / (0.17)
v = 0.453 m/s
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Fossil records indicate that Earth was first inhabited by bacteria-like organisms. These organisms
The fossil record shows that prokaryotes were the first living things. Therefore, choice D is right.
Prokaryotes, which predated plants and animals by billions of years, are now known to have been the first cellular life forms on Earth. The age of the Earth and its moon is estimated to be 4.54 billion years.
Pro means "before" in Latin. They are typically single-celled creatures but can occasionally be multicellular. Prokaryotes are said to have been the first living things discovered on Earth. They are separated into two groups: bacteria and archae. They lack organelles that are membrane-bound, yet all of the water-soluble parts are still present in the cytoplasm without membrane. Because of their basic characteristics, a fossil suggests that they are prokaryotes.
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The complete question is
The first organisms evolved on Earth around 4 billion years ago. The fossil record indicates that the first organisms were which of the following?. A) eukaryotes. B) plastids. C) mitochondria. D) prokaryotes
A car slows down from a velocity of 25 m/s to rest in 5.0 seconds. How far did the car travel during that time?
Answer:
\( \boxed{\sf Distance \ travelled = 62.5 \ m} \)
Given:
Initial velocity (u) = 25 m/s
Final velocity (v) = 0 m/s (Rest)
Time taken (t) = 5 seconds
To Find:
Distance travelled by car (s)
Explanation:
From equation of motion of object moving with uniform acceleration in straight line we have:
\( \boxed{ \bold{s = (\frac{v + u}{2} )t}}\)
By substituting value of v, u & t in the equation we get:
\( \sf \implies s = ( \frac{0 + 25}{2} ) \times 5 \\ \\ \sf \implies s = \frac{25}{2} \times 5 \\ \\ \sf \implies s = 12.5 \times 5 \\ \\ \sf \implies s = 62.5 \: m\)
\( \therefore\)
Distance travelled by car (s) = 62.5 m
The distance car travel during that time is 62.5 meter.
What is acceleration?
Acceleration is the rate at which speed and direction of velocity vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates.
Even if the speed is constant, motion on a circle accelerates because the direction is always shifting. Both effects contribute to the acceleration for all other motions.
Initial velocity (u) = 25 m/s
As the car becomes rest, final velocity (v) = 0 m/s (Rest)
Time taken (t) = 5 seconds.
The deceleration of the car: a = (initial speed - final speed)/time interval
= ( 25 m/s - 0 m/s)/5 second
= 5 m/s²
The distance car travel during that time = ut - at²/2
= 25 × 5.0 meter - (5×5²/2) meter
= 62.5 meter.
Hence, the distance car travel during that time is 62.5 meter.
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For cardiovascular exercise, it is important to exercise in your:
1. Resting Heart Rate
2. Target Heart Rate
3. Maximum Heart Rate
4. All of the Above
Answer:
4 target heart rate. is the answer
Explanation:
hope its right
The app claimed it has "Forbidden text"
A coal power station functions at 40.0 percent efficiency. What is the amount of work it does if it takes in 1.20×10^12 J by heat?
The amount of work done (output energy) by the coal power station at the given efficiency is 4.8 x 10¹¹ J .
What is efficiency of a machine?The efficiency of a machine indicates how well its input energy is converted to useful output energy or work.
The efficiency of a machine is simply the ratio of output energy to input energy.
E = output energy / input energy x 100%
The given parameters;
efficiency = 40%output energy = ?input energy = 1.2 x 10¹² J40% = output energy / (1.2 x 10¹²) x 100%
40/100 = output energy / (1.2 x 10¹²)
0.4(1.2 x 10¹²) = output energy
4.8 x 10¹¹ J = output energy
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