Answers
Answer:
268.22m/s
Explanation:
Given;
10mile/min to m/s
We need to convert between the two units;
Using the dimensions;
1 mile = 1609.34m
60s = 1min
Now;
10 x \(\frac{mile}{min}\) x \(\frac{1min}{60s}\) x \(\frac{1609.34m}{1mile}\)
= 268.22m/s
Related Questions
Each of the following figures shows a person (not to scale) located on Earth at either 40°N or 40°S latitude. Rank the figures based on how much time the person spends in daylight during each 24-hour period, from most to least. To rank items as equivalent, overlap them.
Answers
The ranking is based on the tilt of the Earth's axis and its orbit around the Sun. The figure at 40°N in June receives the most daylight because it is located at a high latitude during the summer solstice in the Northern Hemisphere. The Earth's axis tilts towards the Sun, resulting in longer days and shorter nights. The figure at 40°S in December receives a moderate amount of daylight as it is located at a lower latitude during the summer solstice in the Southern Hemisphere.
The figure at 40°N in December experiences less daylight because it is located at a high latitude during the winter solstice in the Northern Hemisphere, with shorter days and longer nights. Lastly, the figure at 40°S in June receives the least amount of daylight as it is located at a lower latitude during the winter solstice in the Southern Hemisphere, where the days are shortest and the nights are longest. Based on the information given, the ranking of figures based on the amount of daylight they experience in a 24-hour period, from most to least.
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A merry-go-round rotates at the rate of
0.14 rev/s with an 100 kg man standing at
a point 2.1 m from the axis of rotation.
What is the new angular speed when the
man walks to a point 0 m from the center?
Consider the merry-go-round is a solid 83 kg
cylinder of radius of 2.1 m.
Answer in units of rad/s.
part2: What is the change in kinetic energy due to
this movement?
Answer in units of J.
Answers
Part 1: The angular speed increases to a new value is 0rad/s. Part 2: the change in kinetic energy is given by Delta -31205.7J.
What is angular speed?Angular speed is a measure of the angular displacement of a rotating object over a period of time. It is measured in revolutions per minute (RPM) or radians per second (rad/s).
Part 1:
The angular speed of the merry-go-round is determined by the rotational inertia of the cylinder, which is given by \(I = 1/2 mr^2,\)
where m is the mass and r is the radius of the cylinder. Since the mass of the cylinder is given,
we can calculate the rotational inertia as \(I = 83 kg * (2.1 m)^2 / 2 = 352.41 kg m^2.\)
The angular speed of the merry-go-round is given by w = (Torque) / (Inertia).
Since the torque is due to the man's weight, we can calculate the torque as T = mgd,
where m is the mass of the man, g is the gravitational acceleration and d is the distance from the axis of rotation.
In this case, the torque is given by \(T = 100 kg * 9.81 m/s^2 * 2.1 m = 2041.1 Nm.\)
The angular speed of the merry-go-round with the man at a distance of 2.1 m from the axis of rotation is then \(w = T / I = 2041.1 Nm / 352.41 kg m^2 = 5.78 rad/s.\)
When the man moves to a point 0 m from the center, the torque is reduced to zero and the angular speed increases to a new value given by \(w = T / I = 0 Nm / 352.41 kg m^2 = 0 rad/s.\)
Part 2:
The change in kinetic energy due to the man's movement is given by Delta \(KE = KE_{final} - KE_{initial}\),
where KE is the kinetic energy of the merry-go-round.
The kinetic energy is given by KE = 1/2 I \(\omega^2\),
where I is the rotational inertia and omega is the angular speed. In this case,
the change in kinetic energy is given by Delta \(KE = 1/2 * 352.41 kg m^2 * (0 - 5.78 rad/s)^2 = -31205.7 J.\)
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Zach performed several experiments related to gravity. At the end of one experiment, Zach concluded that the gravitational force between two objects is directly proportional to the masses of the objects.
Which set of data did Zach use to form this conclusion?
A.
Distance Mass 1 Mass 2 Force
10 m 10 kg 15 kg 1.0 × 10-10 N
10 m 15 kg 15 kg 1.5 × 10-10 N
10 m 10 kg 30 kg 2.0 × 10-10 N
10 m 20 kg 20 kg 2.7 × 10-10 N
10 m 20 kg 30 kg 4.0 × 10-10 N
B.
Distance Mass 1 Mass 2 Force
5 m 10 kg 10 kg 2.7 × 10-10 N
10 m 10 kg 10 kg 6.7 × 10-11 N
15 m 10 kg 10 kg 3.0 × 10-11 N
20 m 10 kg 10 kg 1.7 × 10-11 N
25 m 10 kg 10 kg 1.1 × 10-11 N
C.
Distance Mass Acceleration Time
5 m 5 kg 9.8 m/s2 1.0 s
10 m 5 kg 9.8 m/s2 1.4 s
15 m 5 kg 9.8 m/s2 1.7 s
20 m 5 kg 9.8 m/s2 2.0 s
25 m 5 kg 9.8 m/s2 2.3 s
D.
Distance Mass Acceleration Time
5 m 5 kg 9.8 m/s2 1.0 s
10 m 10 kg 9.8 m/s2 1.4 s
15 m 15 kg 9.8 m/s2 1.7 s
20 m 20 kg 9.8 m/s2 2.0 s
25 m 25 kg 9.8 m/s2 2.3 s
Answers
Answer:
Group A.
Explanation:
The masses and forces all fit the equation
F = 6.67x10⁻¹¹•m₁•m₂ / 100
where 100 = d²
A block of mass 0.1 kg is attached to a spring of spring constant 15 N/m on a frictionless track. The block moves in simple harmonic motion with amplitude 0.22 m. While passing through the equilibrium point from left to right, the block is struck by a bullet, which stops inside the block. The velocity of the bullet immediately before it strikes the block is 42 m/s and the mass of the bullet is 3 g. If the simple harmonic motion after the collision is described by x = B sin(ω t + φ), what is the new amplitude B? Answer in units of m.
Answers
The new amplitude B is 0.22 m.
Mass of block = M =0.1 kg
Spring constant = k = 15 N/m
Amplitude = A = 0.22 m
Mass of bullet = m = 3 g = 0.003 kg
Velocity of bullet = vᵇ = 42 m/s
Angular frequency of S.H.M is given by = ω₀ = \(\sqrt{\frac{k}{M}}\)
= \(\sqrt{\frac{15}{0.1} }\)
= 12.24 rad/sec
Speed of the block immediately before the collision:
Displacement of Simple Harmonic Motion is given as:
x= A Sin(ωt+Ф)
After differentiating:
v = A ω₀cos(ω₀t+Ф)
As bullet strikes at equilibrium position,
φ = 0
t= 2nπ
⇒ cos (ω₀t + φ) = 1
⇒ v= A ω₀
⇒ v= (0.22)(12.24)
⇒ \(v=2.692 ms^{-1}\)
If the simple harmonic motion after the collision is described by x = B sin(ωt + φ), new amplitude B:
S.H.M after collision is given as :
x= B Sin(ωt+Ф)
To find B, consider law of conservation of energy,
\(KE = PE\\KE =\frac{1}{2}(m+M)v^{2} \\PE= \frac{1}{2}kB^{2}\\\frac{(m+M)v^{2}}{k}=B^{2} \\B=\sqrt{\frac{(m+M)}{k}} v\\B= \sqrt{\frac{0.003+0.1}{15} } (2.69)\)
\(B= 0.22 m\)
Therefore, the new amplitude B is 0.22 m.
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A material that reflects or absorbs all the light that strikes it is
A. opaque.
B. transparent.
C. translucent.
D. primary.
Answers
Answer:
b. transparent
Explanation:
Photons interact with an object by some combination of reflection, absorption and transmission. Some materials, such as plate glass and clean water, transmit much of the light that falls on them and reflect little of it; such materials are called optically transparent.
How are magnetic fields like vectors?
Answers
Answer:Magnetic fields from two sources add up as vectors at each point, so the strength of the field is not necessarily the sum of the strengths1. Magnetic fields are vectors, which means they have direction as well as size. Therefore, the sum of two magnetic fields is not simply the sum of their magnitudes2.
Explanation:
Convert 5 Liter in to cubic meter.convert 5 litre into cubic metre
Answers
Explanation:
To convert liters to cubic meters, multiply the liter value by 0.001 or divide by 1000
A thin half ring with a radius of R = 10 cm is uniformly charged with a linear density of = 1 Mikrokulon/m and located in a vacuum. Determine the force F of interaction between the half ring and a point charge q = 20 nC located at the center of curvature. (don't use chatgpt please)
Answers
Answer:
Explanation:
F = k * q * lambda * R * π * (1 - √2/2)
Substituting the given values of q, lambda, R, and k, we get:
F = (9 x 10^9 N*m^2/C^2) * (20 x 10^-9 C) * (1 x 10^-6 C/m) * (0.1 m) * π * (1 - √2/2)
F ≈ 8.58 x 10^-4 N
Therefore, the force of interaction between the half ring and the point charge is approximately 8.58 x 10^-4 N.
I need help with this assignment
Answers
two lenses are combined together . if the power of one of the lenses is +5D and combined focal length is 0.4m.What is the power of the second lens
Answers
Answer:
-0.4D(maybe)
Explanation:
combined focal length (f)= 0.4m
D1 = 5D
Then f1= 1/D1
= 1/5 = 0.2 m
1/f=1/f1+1/f2
1/0.4=1/0.2+1/f2
f2= -5/2
D2=1/f2= -0.4D
What is the displacement (in miles, with direction) from the
Aquarium to the Cemetery?
Answers
Look up "Everything You Need To Know About Math In One Big Fat Notebook pdf." It's the best thing I've ever been given, I have it with me in math class all the time and I've aced every test. I have it with me right now and it has everything I've ever been taught about math in it so it might help you.
A 925 N crate is being pulled across a level floor
by a force F of 325 N at an angle of 25 above the
horizontal. The coefficient of kinetic friction is
0.25. Find the magnitude of the acceleration of
the crate.
Answers
The friction = 0.25 x 925 = 231.25 N
The horizontal component of the force = 925 x Cos 25 = 838.3 N
The net force = 838.3 - 231.25 = 607 N
acceleration = 607 / (925/9.8) = 6.4 m/s^2
The magnitude of the acceleration of the crate is 1.033 m/s².
The given parameters;
weight of the crate, W = 925 Nhorizontal force applied to the carte, F = 325 Nangle of inclination of the force, θ = 25⁰the coefficient of friction, μ = 0.25The mass of the crate is calculated as;
W = mg
\(m = \frac{W}{g} \\\\m = \frac{925}{9.8} \\\\m = 94.388 \ kg\)
The normal force on the crate is calculated as;
Fₙ = 925 - 325 x sin(25)
Fₙ = 925 - 137.35
Fₙ = 787.65 N
The frictional force on the object is calculated as follows;
\(F_k = \mu F_n\\\\F_k = 0.25 \times 787.65\\\\F_k = 196.91 \ N\)
The magnitude of the crates acceleration is calculated from the net horizontal force on the crate;
\(\Sigma F_x = 0\\\\Fcos (\theta) - F_k = ma\\\\325\times cos(25) \ - \ 196.91 = ma\\\\97.54 = ma\)
\(a = \frac{97.54}{94.388} \\\\a = 1.033 \ m/s^2\)
Thus, the magnitude of the acceleration of the crate is 1.033 m/s².
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Write the properties of Non Metals and the families containig non Metals.
Answers
Non-Malleable and Ductile: Non-metals are very brittle, and cannot be rolled into wires or pounded into sheets. Conduction: They are poor conductors of heat and electricity. Luster: These have no metallic luster and do not reflect light.
Group 15, the nitrogen family, contains two nonmetals: nitrogen and phosphorus. These non-metals usually gain or share three electrons when reacting with atoms of other elements. Group 16, the oxygen family, contains three nonmetals: oxygen, sulfur, and selenium.
Elements: Nitrogen; Oxygen; Phosphorus; Selenium...
An electron with a velocity of 14.4 m/s in the positive y-direction enters a region where there is a uniform electric field of 201 N/C in the positive x-direction. The mass of the electron is 9.109 × 10−31 kg.
What is the y-component of the electron’s displacement 2.40 μs after entering the electric-field region if no other forces act on it in μm?
What is the x-component of the electron’s displacement 2.40 μs after entering the electric-field region if no other forces act on it in m?
Answers
1. The electron experiences acceleration and moves independently in the y-direction.
2. The y-component of the electron's displacement after 2.40 μs in the electric field is -8.11 μm.
3. The x-component of displacement remains zero.
To calculate the y-component and x-component of the electron's displacement, we need to consider the motion of the electron in the electric field. Let's break it down step by step:
1. Acceleration of the Electron:
The electric field causes a force on the electron given by the equation: F = qE, where F is the force, q is the charge of the electron, and E is the electric field.
Since the charge of an electron is -1.6 × \(10^-^1^9\) C, and the electric field is 201 N/C, we can calculate the force:
F = (-1.6 × \(10^-^1^9\)C) * (201 N/C)
= -3.216 × \(10^-^1^7\) N
Using Newton's second law, F = ma, we can find the acceleration (a) of the electron:
a = F / m
= (-3.216 × \(10^-^1^7\) N) / (9.109 ×\(10^-^3^1\) kg)
= -3.530 × \(10^1^3 m/s^2\)
2. Displacement in the y-direction:
Since no other forces act on the electron, its motion in the y-direction is independent of the electric field. The equation for displacement (y) under constant acceleration is:
y = (1/2) * a *\(t^2\)
Substituting the values, where the time (t) is 2.40 μs (2.40 ×\(10^-^6\) s), we can calculate the y-component of displacement:
y = (1/2) * (-3.530 ×\(10^1^3 m/s^2\)) * (2.40 ×\(10^-^6 s)^2\)
= -8.11 μm
Therefore, the y-component of the electron's displacement 2.40 μs after entering the electric-field region is -8.11 μm.
3. Displacement in the x-direction:
Since the electron's velocity is only in the y-direction initially, the x-component of the displacement remains zero. Without any forces acting in the x-direction, the electron continues to move in the y-direction without changing its x-position.
Hence, the x-component of the electron's displacement 2.40 μs after entering the electric-field region is 0 meters.
Please note that the calculations provided are based on the given values and the provided formulas for displacement and acceleration.
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Use the force diagrams below to determine whether the cart is not moving, moving at a constant speed speeding up or slowing down
Answers
a) Cart is speeding up ; b) cart is slowing down and c) cart is not moving.
What do you understand by force and friction?Force of friction is a contact force whereas friction is the force that resists motion when surface of one object comes in contact with surface of another. Example is the force of friction between two stones rubbed with each other.
Static friction magnitude is directly proportional to normal force magnitude and the roughness between sliding surfaces. The ratio of magnitude of frictional force divided by normal force magnitude is called as coefficient of friction. Friction takes place at the point of contact between two bodies.
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Which region is located between 60-90N and 60-90S?
Group of answer choices
Tropics
Tropical Rainforest
Polar
Mid-Lats
Answers
Answer:
Polar
Explanation:
Took the test
An electromagnetic wave has a frequency of 5.0 x 1014 Hz. What is the
wavelength of the wave? Use the equation 2 = and 3.0 x 108 m/s for the
speed of light.
A. 1.7 x 10-8 m
О
B. 6.0 x 1022 m
O C. 6.0 x 10-7 m
O D. 1.7 x 105 m
Answers
Answer:
c
Explanation:
wavelength = speed of light/ frequency
= (3x 10^8 m/s)/(5.0 x 10^14 Hz)
= 6.0 x 10^-7 m
Is a bike being pedaled potential or kinetic?
Answers
Answer:
Since there is no motion yet, there is no kinetic energy. This means that the work needed to get up the hill is the potential energy at the top. Once you have coasted down the hill and are at the bottom, all of the energy is kinetic.
Explanation:
.
If the weight of the ruler is one Newton ,Gc cannot have a value more than 25cm
Answers
If the length of the ruler is 50 cm, the center of gravity cannot be greater than 25 cm.
The given parameters:
Weight of the ruler = 1 NWhat is center of gravity (CG)?Center of gravity is the point at which the weight of an object is concentrated.Let the length of the ruler = L
The center of the gravity of the ruler is calculated as follows;
\(X_{CG} = \frac{W(L_0) + W(L -X_{CG})}{W} \\\\X_{CG} = \frac{1(0) + 1(L -X_{CG})}{1}\\\\X_{CG} = L - X_{CG}\\\\X_{CG } + X_{CG} = L\\\\2X_{CG} = L\\\\X_{CG} = \frac{L}{2} \\\\when , \ L = 50 \ cm\\\\X_{CG} = \frac{50}{2} \\\\X_{CG} = 25 \ cm\)
Thus, if the length of the ruler is 50 cm, the center of gravity cannot be greater than 25 cm. This may change if the length of the ruler changes because the center of gravity of uniform ruler depends on the length of the ruler.
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The 7.4 N weight is in equilibrium under
the influence of the three forces acting on it.
The F force acts from above on the left at
an angle of a with the horizontal. The 5.9 N
force acts from above on the right at an angle
of 44° with the horizontal. The force 7.4 N
acts straight down.
Ĵ
44°
5.9 N
7.4 N
What is the magnitude of the force F?
Answer in units of N.
part 2 of 2
What is the angle a of the force F as shown
in the figure?
Answers
a) Magnitude of force is 5.37N
b) Angle of force is - 37.88°
What is force?In physics, we define a force is an influence that can change the motion of object. A force can cause an object with mass to change to accelerate.
Given force from above is 5.9N
∑Fₓ = F₁ₓ + F₂ₓ+F₃ₓ = 0
F₂ cos 44° + Fₓ = 0
Fₓ = - 5.9 cos44°
= - 4.24 N
Given force that acts downward as 7.4N
∑Fy= Fy1+ Fy2 +Fy3 =0
Fy+ 5.9 sin 44° - 7.4= 0
F = 3.30 N
F =√Fₓ² +Fy²
= 5.37 N
b) angle of force= tan⁻¹ (3.30/-4.24)
= - 37.88°
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Bromine has two naturally occurring isotopes (Br-79 and Br-81).
a. Use the periodic table to find the atomic mass of bromine.
b. If the natural abundance of Br-79 is 50.69%, what is the natural abundance of Br-81?
c. If the mass of Br-81 is 80.9163 amu, what is the mass of Br-79?
Answers
Answer:
The relative atomic mass of \({\rm Br}\) is \(79.904\).
The natural abundance of \({\rm Br}\text{-}79\) would be approximately \(49.31\%\).
The mass of \({\rm Br}\text{-}79\) would be approximately \(78.919\).
Explanation:
The natural abundance of all naturally occurring isotopes of an element (e.g., bromine) should add up to \(1\). Since the relative abundance of \({\rm Br}\text{-}81\) is \(50.69\%\) (\(0.5069\),) the relative abundance of \({\rm Br}\text{-}79\) (the only other naturally occurring isotope of bromine) should be approximately \(1 - 0.5069 = 0.4931\).
The relative atomic mass of an element is the average of the mass of all its isotopes, weighted by the relative abundance of each isotope. It is given that the atomic mass of \({\rm Br}\text{-}81\) is \(80.9163\). If the atomic mass of \({\rm Br}\text{-}79\) is \(x\), the relative atomic mass of \({\rm Br}\) would be:
\((0.5069)\, x + (1 - 0.5069)\, (80.9163)\).
The expression above should be equal to the relative atomic mass of \({\rm Br}\) on the periodic table of elements, \(79.904\). Thus:
\(0.5069\, x + (1 - 0.5069)\, (80.9163) = 79.904\).
Solving for \(x\) gives:
\(\begin{aligned} x &= \frac{79.094 - (1 - 0.5069)\, (80.9163)}{0.5069} \approx 78.919 \end{aligned}\).
Hence, the relative atomic mass of \({\rm Br}\text{-}79\) would be approximately \(78.919\).
How are the parts of birds and fish similar in structure and function?
Answers
Answer:
Birds and fish both have a backbone structure, which makes them structurally and functionally similar.
Explanation:
The scale on the horizontal axis is 8 s per division and on the vertical axis 5 m per division. What is the time represented by the third tic mark on the horizontal axis
Answers
Answer:
24 s
Explanation:
8 s / tic * 3 tic = 24 sec from origin
fill in the blanks waves can travel through ____ .air granite rock molten magma water sandstone mudstone
Answers
Waves can travel through the air, granite rock, water, sandstone, and mudstone. Waves can also travel through molten magma, but only in certain conditions.
What is a wave?In physics, a wave is a disturbance that travels through space and time, usually accompanied by the transfer of energy. Waves can be characterized by their amplitude, wavelength, frequency, and speed.
Here,
Waves can travel through the air, granite rock, water, sandstone, and mudstone. Waves can also travel through molten magma, but only in certain conditions.
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PLEASE HELP ANYONE?!!!!!
Answers
Answer:
for question 3 the answer is A.
Explanation:
Pulse is not a part of the body but rather a measurement, same as with strength.
Brainliest?
Brittleness, malleability, ductility, and viscosity fall into the
category of physical properties of matter.
TRUE
FALSE
Check it
SCRATCHPAD
Improve this question
Answers
Answer:
TRUE
Which sample of water will contain the smallest amount of heat energy?
10 g at 10°C
20 g at 10°C
20 g at 20°C
20 g at 40°C
Answers
Answer:
10 g at 10°C
Explanation:
Answer:
10 g at 10°C
Explanation:
Heat energy is directly proportional to the mass and the temperature of a substance. When comparing two samples of the same substance, the one with higher mass contains more heat energy. Similarly, a substance with higher temperature contains more heat energy compared to the same substance with a lower temperature.
In this case, the smallest amount of heat energy would be in the sample of 10g at 10°C. This is because it has the lowest mass and temperature compared to the other three options.
ALLEN
Can you help with these physics questions about motion? Please!!!!
Answers
Answer:
Explanation:
5-) in the 1st system the right side is heavier, the system is moving in that way with a 9.8k m^2/s
in the 2nd system right side is heavier too, the system is moving in that way with a 9.8k m^2/s
in the 3rd system both sides got the same weight so the system isn't moving in anyway. 0 m^2/s
A man is standing away from the School
Building at a distance of
300m . He claps his hands and hears an echo calculate the time interval of him hearing his echo
Answers
The time interval between the man clapping and hearing his echo is approximately 1.75 seconds.
What do you mean by echo?An echo is a repetition or reflection of a sound or signal. It can be caused by sound waves bouncing off a surface, signal interference, or the repetition of a message in communication.
The speed of sound in air at room temperature is approximately 343 meters per second. When a person claps, the sound waves propagate outward in all directions and reach the school building, where they bounce off and return to the person as an echo. The time it takes for the sound to travel the distance to the building and back to the person is the time interval between the clap and the echo.
To calculate the time interval, we can use the following formula:
time = distance / speed
where distance is the total distance traveled by the sound (twice the distance from the person to the school building), and speed is the speed of sound in air.
distance = 2 x 300m = 600m
speed = 343 m/s
time = 600m / 343 m/s = 1.75 seconds (rounded to two decimal places)
Therefore, the time interval between the man clapping and hearing his echo is approximately 1.75 seconds.
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What is the main organ of the circulatory system?
veins
arteries
heart
capillaries
Answers
It is the heart
if not im sorry