the speed of light in glass is group of ___answer choices: same as in a vacuum. smaller than that in air. unchanged from that in air. larger than that in air.

Answers

Answer 1

The speed of light in glass is SLOWER than that in air. Therefore, the correct answer is the second option: smaller than that in air.

The speed of light is a universal constant used and considered in many areas of physics. It is equal to  299,792,458 meters per second or 186,000 miles per second. That speed is measured in a vacuum.

Light travels faster in a medium that has a lower refractive index. Generally, the denser a medium is, the higher its refractive index is. Glass is obviously denser than air, which means it has a higher refractive index. Thus, light travels slower in glass than in air.

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Related Questions

Which of these is considered a contact force?

a the force between two magnets.
b the gravitational pull of a planet.
c the friction between an object and air.
d The force between two charged particles.

Answers

Answer:

C -) The friction between an object and air.

Explanation:

The frictional force is the force that exists between two surfaces in contact, which is opposed to the movement.

That is, this type of force exists as long as there is physical contact between surfaces.

While the other types of force always act at a separation distance between bodies.

What is the velocity of a wave that traveled 36 meters south in 6 seconds?
O 6 meters per second
O 30 meters per second
O 42 meters per second
O 216 meters per second

Answers

6 meters per second

Divide 36 by 6 and that’s how you get the answer (36/6)

Answer:

A

Explanation:

The half-life of Silver-105 is 3.57 x 106 seconds. A sample contains 5.78 x 1017 nuclei. What is the decay constant for this decay?

Answers

Answer:

The decay constant, or "lambda" (λ), is the rate at which a radioactive isotope decays. It is usually measured in units of inverse time, such as seconds. In this case, the decay constant can be calculated as follows:

16:42

λ = (ln(2)/3.57 x 106) x (5.78 x 1017) = 0.

Explanation:

N2 + 3H2 + 2NH3
What type of reaction is this

Answers

Answer:It is a combination reaction; nitrogen and hydrogen combine to form ammonia

Explanation:

This is the reaction that is used to make ammonia from hydrogen and nitrogen. In this reaction, only one product is formed. Therefore, this reaction is known as a combination reaction.

A world-class sprinter can reach a top speed (of about 11.5 m/s) in the first 20.0 m of a race

What is the average acceleration of this sprinter?
Express your answer with the appropriate units.

How long does it take her to reach that speed?
Express your answer with the appropriate units.

A world-class sprinter can reach a top speed (of about 11.5 m/s) in the first 20.0 m of a raceWhat is

Answers

(a) The average acceleration of this sprinter is 3.31 m/s².

(b) The time taken for the sprinter to reach the speed is 3.5 s.

What is the average acceleration of this sprinter?

The average acceleration of this sprinter is calculated as follows;

v² = u² + 2as

where;

v is the final velocity of the sprinter = 11.5 m/su is the initial velocity of the sprinter = 0a is the average acceleration of the sprinter = ?s is the distance travelled by the sprinter

v² = 0 + 2as

a = v² / 2s

a = ( 11.5² ) / ( 2 x 20 )

a = 3.31 m/s²

The time of motion of the sprinter is calculated as follows;

v = u + at

v = 0 + at

t = v / a

t = ( 11.5 ) / ( 3.31 )

t = 3.5 s

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A figure skater glides along a circular path of radius 3.93 m. (a) If she coasts around one half of the circle, find the magnitude of the displacement vector. (b) If she coasts around one half of the circle, find what distance she skated. (c) What is the magnitude of the displacement if she skates all the way around the circle?

Answers

The magnitude of the displacement vector refers to the length or amount of the displacement vector. Displacement is the change in position of an object. Displacement is a vector quantity, which means it has both magnitude and direction. In this question, a figure skater is gliding along a circular path of radius 3.93 m.

If she coasts around one half of the circle, we have to find the magnitude of the displacement vector. The figure skater is gliding along a circular path of radius 3.93 m. If she coasts around one half of the circle, then her final and initial position is on the same point. Therefore, the magnitude of the displacement vector is zero. Distance Skated Distance refers to the length covered by an object or an individual. In this question, the figure skater is gliding along a circular path of radius 3.93 m. If she coasts around one half of the circle, we have to find what distance she skated. The distance covered by an object or individual is determined by the formula:Distance = Circumference/2Given that the radius of the circle is 3.93 m, then:Circumference of the circle = 2πr= 2 × 3.14 × 3.93= 24.7 m.Therefore, the distance covered by the figure skater around half of the circle = 24.7 m/2 = 12.35 m. Therefore, she skated 12.35 m.Magnitude of DisplacementIf the figure skater skates all the way around the circle, then she covers the entire circumference of the circle. Therefore, the magnitude of the displacement vector is the same as the circumference of the circle, which is given as:Circumference of the circle = 2πr= 2 × 3.14 × 3.93= 24.7 mTherefore, the magnitude of the displacement vector when the figure skater skates all the way around the circle is 24.7 m.

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how do you mountaineers reduce the effects of changes in atmospheric pressure?

Answers

Essentially belly breathing with forceful exhale, the pressure breath helps to improve gas exchange across the alveoli by increasing the pressure of the lungs . The pressure breaths helps to combat the effects caused by decreasing atmospheric pressure as climbers gain altitude

At a particular instant, an electron is located at point (P) in a region of space with a uniform magnetic field that is directed vertically and has a magnitude of 5.91 mT. The electron's velocity at that instant is purely horizontal with a magnitude of 2×10^5m/s. How long will it take for the particle to pass through point (P) again?

Answers

It will take approximately \(4.86 * 10^{-8}\) seconds for the electron to pass through point (P) again.

To determine how long it will take for the electron to pass through point (P) again, we need to consider the relationship between the magnetic field, velocity, and the motion of a charged particle in a magnetic field.

The force experienced by a charged particle moving in a magnetic field is given by the equation:

F = qvB sin(theta)

Where:

F is the magnetic force,

q is the charge of the particle (in this case, the charge of an electron is -1.6 x 10^-19 C),

v is the velocity of the electron (2 x 10^5 m/s in this case),

B is the magnitude of the magnetic field (5.91 mT = 5.91 x 10^-3 T),

theta is the angle between the velocity vector and the magnetic field vector.

In this case, since the electron's velocity is purely horizontal and the magnetic field is directed vertically, the angle theta is 90 degrees, and sin(theta) = 1.

Therefore, the force acting on the electron is:

F = qvB

The force acting on the electron provides the necessary centripetal force for it to move in a circular path. The centripetal force is given by:

\(F = (mv^2) / r\)

Where:

m is the mass of the electron (9.11 x 10^-31 kg),

v is the velocity of the electron (2 x 10^5 m/s),

r is the radius of the circular path.

Setting the two equations equal to each other, we have:

\(qvB = (mv^2) / r\)

Simplifying and solving for r:

r = (mv) / (qB)

Substituting the given values, we get:

r = [(9.11 x 10^-31 kg) x (2 x 10^5 m/s)] / [(-1.6 x 10^-19 C) x (5.91 x 10^-3 T)]

Calculating the value of r, we find:

r ≈ 1.539 x 10^-2 m

The distance traveled by the electron in one complete circular path is equal to the circumference of the circle, which is 2πr.

Therefore, the time taken for the electron to pass through point (P) again is given by:

time = distance / velocity = (2πr) / v

Substituting the known values:

time ≈ (2π x 1.539 x 10^-2 m) / (2 x 10^5 m/s)

Calculating the value of time, we find:

time ≈ 4.86 x 10^-8 seconds

Hence, it will take approximately 4.86 x 10^-8\(4.86 * 10^{-8}\) seconds for the electron to pass through point (P) again.

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The time is taken for the particles to pass through point (P) with the magnetic field 5.91mT and the magnitude of 2×10⁵ m/s is 6.04ns.

The field around the magnet is called a magnetic field. The vector field describes the magnetic influence of moving charges, electric current, and magnetic field. The unit of the magnetic field is Tesla. When a magnet moves along a circular path, force is equal to centripetal force.

From the given,

magnetic field, B = 5.91T

electron's velocity, v = 2×10⁵ m/s

The magnetic force on the given charge, F=?

qVB = mv²/R

R/v = m/qB

time period, T= 2πR/v

T = 2π(R/v)

   = 2π(m/qB)

   = 2×3.14×9.1×10⁻³¹/(1.6×10⁻¹⁹×5.91×10⁻³)

   = 57.148×10⁻⁹/9.456

  = 6.04×10⁻⁹

Thus, the time period for electrons to pass through the point is 6.04ns.

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throughout the lunar cycle, the moon moves further eastward in the sky. therefore to an observer on earth

Answers

At the same time every day throughout the Lunar Cycle, the Moon will move farther (eastward, westward) in the sky. The Moon's highest point in the sky changes gradually throughout the day for an observer on Earth (earlier, later).

Why does the moon seem to shift to people on Earth?

The illuminated shape of the Moon that we can see from Earth appears to be changing constantly as the moon makes its 28-day journey around the planet. As a result of us viewing varying amounts of the illuminated surface, the moon's shape appears to have changed.

An average lunar cycle, lunation, lunar month, or synodic month has a duration of 29.53059 days and is the period of time between one new Moon and the following. In terms of time, this equals 29 days, 12 hours, 44 minutes, and 3 seconds.

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What does psychophysics study?
unusual discoveries in laboratory experimentations
the laws of physics and how believable they are
people's reactions and perceptions to stimuli

Answers

Answer:

people's reactions and perceptions to stimuli.

Explanation:

Psychophysics can be defined as the scientific study of people's reactions and perceptions to stimuli.

Stimulus can be defined as an obvious change in either the chemical or physical structure of an organism' environment (either external or internal). Thus, all living organisms (humans) respond to changes in their environment and consequently, an appropriate response or reaction is made. Also, stimulus arising from within the organism is known as internal stimulus while those from its environment are known as the external stimulus.

In organisms, the specialized cells that detect stimulus are generally known as sensory receptors while a group of these receptors is referred to as sense organ.

Hence, psychophysics is a branch of psychology and it is typically focused on determining the effects of stimuli on the mental health or processes of humans.

Answer:

study of people's reactions and perceptions to a stimulus.

Explanation:

Before the emergence of psychology, psychophysics was the more common practice. Psychophysics is the study of people's reactions and perceptions to a stimulus. For example, when you hear a bell ring, do you act startled, blink your eyes, turn your head, or do nothing? Psychophysicists were interested in people's five senses and how those senses responded to stimulation from elsewhere. Tests were administered to people to try to understand mental phenomena.Psychophysicists wanted to know what people's reactions would be. For example, if a bell rang twenty times, how well did a person hear that sound and did the person find that sound pleasant?

Classes are canceled due to snow, so you take advantage of the extra time to conduct some physics experiments. You fasten a large toy rocket to the back of a sled and take the modified sled to a large, flat, snowy field. You ignite the rocket and observe that the sled accelerates from rest in the forward direction at a rate of 13.513.5 m/s2 for a time period of 3.103.10 s. After this time period, the rocket engine abruptly shuts off, and the sled subsequently undergoes a constant backward acceleration due to friction of 4.654.65 m/s2. After the rocket turns off, how much time does it take for the sled to come to a stop

Answers

Answer:

The value is \(t_1 = 9 \ s \)

Explanation:

Generally the velocity attained by the sled after t = 3.10 s is mathematically evaluated using the kinematic equation as follows

\(v = u + at\)

Here u = 0 \ m/s

a = 13.5 \(m/s^2\)

So

\(v = 0 + 13.5 * 3.10 \)

=> \(v = 41.85 \ m/s \)

The is distance it covers at this time is

\(s = u * t + \frac{1}{2} a * t^2\)

=> \(s = + \frac{1}{2} * 13.5 * 3.10^2\)

=> \(s =64.87 \)

Now when sled stops its the final velocity is \( v_f = 0 m/s \) while the initial velocity will be the velocity after its acceleration i.e \(v = 41.85 \ m/s \)

So

\(v_f = v + a_1t_1\)

Here  \(a_1 =  - 4.65\), the negative sign shows that it is deceleration

So

           \(0  =  41.85  - 4.65 *  t_1\)

=> \(t_1 = 9 \ s \)

the distance between an object and its real image is 40 cm, if the magnification is 3, calculate the object and image distance if the focal length of the lens is 15 cm​

Answers

The object distance of the lens is 10 cm and the image distance of the lens is 30 cm.

What is the image and object distance?

The object and image distance formed by the lens is calculated by applying the following lens formula.

v + u = 40 ------- (1)

v/u = 3 ------------ (2)

v = 3u

Substitute v into equation (1);

3u + u = 40

4u = 40

u = 40/4

u = 10 cm

The image distance = 3u

= 3 x 10 cm

= 30 cm

Thus, the object distance is 10 cm and the image distance is 30 cm.

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A student graphs power (p) on the vertical axis and time (t) on the horizontal axis. The graph appears to be a hyperbola.

a) What should the student graph on each axis to test whether the relationship is actually
hyperbolic?

b) If the relationship is actually hyperbolic, what is the general equation for the relationship between power and time?

Answers

Answer: it would be daddy

Explanation:

Because I’m daddy

Plants use sunlight as energy to convert carbon dioxide and water into glucose and oxygen which best describes the reaction

Answers

The process can be described as Photosynthesis with an equation \(6CO_{2} + 6H_{2}O - > C_{6}H_{12}O_{6} + 6O_{2}\).

What is Photosynthesis?

As a means of converting light energy into chemical energy, photosynthesis is a process used by plants and other living things. This chemical energy is then released through cellular respiration to power the activity of the organism.

The process of photosynthesis is how plants produce food. Plants use the energy of light during photosynthesis to produce food. Water and carbon dioxide are transformed by plants into the sugar glucose with the help of the sun's energy.

Two reactants—carbon dioxide and water—are used in the photosynthetic process. Both oxygen and glucose are produced by these two reactants. This makes the photosynthetic reaction an endothermic reaction.

According to the photosynthetic formula:

\(6CO_{2} + 6H_{2}O - > C_{6}H_{12}O_{6} + 6O_{2}\)

Therefore, the photosynthesis reaction can be described as:\(6CO_{2} + 6H_{2}O - > C_{6}H_{12}O_{6} + 6O_{2}\)

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We can think of it as photosynthesis with an equation.

\(6CO_{2} +6CH_2}-- > C_{6}H{12}O_{6} + 6CO_{2}\)

Plants and other living things employ the process of photosynthesis to transform light energy into chemical energy. The organism's activity is subsequently powered by the chemical energy that is then released during cellular respiration.

Plants produce food through a process known as photosynthesis. During photosynthesis, plants use the energy of light to create nourishment. With the aid of the sun's energy, plants convert water and carbon dioxide into the sugar glucose.

In the photosynthetic process, carbon dioxide and water are used as reactants. These two reactants result in the production of oxygen and glucose. Because of this, the photosynthetic reaction is endothermic.

The photosynthetic equation states:

\(6CO_{2} +6CH_2}-- > C_{6}H{12}O_{6} + 6CO_{2}\)

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I need help with question 8Find the distance and displacement

I need help with question 8Find the distance and displacement

Answers

Draw a diagram to visualize the situation:

The displacement of an object is the change in its position between the starting point and the endpoint of the trajectory. On the other hand, the distance is the length of the trajectory of the object.

In this case, the total displacement can be calculated adding 5km+4km noting that both displacements were performed to the East. Then, the displacement is:

\(9\operatorname{km}\text{ to the East}\)

The total distance traveled is the same as the modulus of the displacement whenever the movement is constrained to a straight line with no changes in the direction. Then, the distance traveled is:

\(9\operatorname{km}\)

I need help with question 8Find the distance and displacement


To convert centimeters to kilometers, which conversion factors would you need?

To convert centimeters to kilometers, which conversion factors would you need?

Answers

Answer:

The last option is the only correct one if you like to multiply

The second last option is good if you like to divide.

Explanation:

Each fraction in the last two options has a value of 1

example

dividing by 1

15 cm /(100 cm/ 1 m) = 0.15 m          0.15 m / (1000 m/ 1km) = 0.00015 km

and

multiplying by 1

15 cm(1 m / 100cm) = 0.15 m         0.15m(1 km/1000m) = 0.00015 km

only one of the two fractions in each of the top two options has a value of 1.

The hour, minute, and second hands on a clock are 0.25 m , 0.31 m , and 0.34 m long, respectively.
What are the distances traveled by the tips of the hands in a 40 min interval?
Express your answers using two significant figures separated by commas.

Answers

In 1 hour, the hour hand sweeps across 1/12 of the clock's face. In 40 min, the hour hand travels (40 min)/(60 min) = 2/3 of the path it covers in an hour, so a total of 1/12 × 2/3 = 1/18 of the clock's face. This hand traces out a circle with radius 0.25 m, so in 40 min its tip traces out 1/18 of this circle's radius, or

1/18 × 2π (0.25 m) ≈ 0.087 m

The minute hand traverses (40 min)/(60 min) = 2/3 of the clock's face, so it traces out 2/3 of the circumference of a circle with radius 0.31 m:

2/3 × 2π (0.31 m) ≈ 1.3 m

The second hand completes 1 revolution each minute, so in 40 min it would fully trace the circumference of a circle with radius 0.34 m a total of 40 times, so it covers a distance of

40 × 2π (0.34 m) ≈ 85 m

The distances traveled by the tips of the hour hand, minute hand and second hand in a 40-min interval are 0.087 m, 1.3 m and 85 m respectively.

What are the hands of a clock?

In a clock, there are three hands of the clock. One is hour hand, second is minute hand and third one is second hand.

The hour hand of the clock is 0.25 m long. The hour hand sweep 1/12 of the clock face each hour (as there are 12 hours in a clock). Thus, in a 40-minute interval, it will travel the distance of,

\(d=2\pi\times\dfrac{40}{12\times60}(0.25)\\d\approx0.087\rm\; m\)

The minute hand of the clock is 0.25 m long. In a 40-minute interval, it will travel the distance of,

\(d=2\pi\times\dfrac{40}{60}(0.31)\\d\approx1.3\rm\; m\)

The second hand of the clock is 0.25 m long. In a 40-minute interval, it will travel the distance of,

\(d=2\pi\times\dfrac{40\times60}{60}(0.34)\\d\approx85\rm\; m\)

Thus, the distances traveled by the tips of the hour hand, minute hand and second hand in a 40 min interval are 0.087 m, 1.3 m and 85 m respectively

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Describe what you think energy is in physics and what does it do.

Answers

In Physics, energy can be defined as the ability and capacity to do work by an object or physical body.

What is energy?

In Physics, energy can be defined as the ability to do work. Thus, energy must be possessed or transferred to a physical object (body) before it can be used in doing a work or heating a system.

The types of energy.

Generally, there are two (2) main types of energy and these are;

Potential energy (P.E): it is an energy that is possessed by an object or body due to its height (position) above the Earth surface.Kinetic energy (K.E): it is an energy possessed by an object or body due to its motion.

For example, you require a sufficient amount of energy to move a crate of egg across a given distance.

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Answer:. It may exist in potential, kinetic, thermal, electrical, chemical, nuclear, or other various forms. There are, moreover, heat and work—i.e., energy in the process of transfer from one body to another. ... All forms of energy are associated with motion.

Explanation:. It may exist in potential, kinetic, thermal, electrical, chemical, nuclear, or other various forms. There are, moreover, heat and work—i.e., energy in the process of transfer from one body to another. ... All forms of energy are associated with motion.

Even in the most advanced circuits, we cannot oscillate electrons back and forth at that rate through wires. But we can oscillate charges back and forth quickly enough to broadcast TV using radio wave signals. At what frequency do the electronics at the TV station need to have the charges oscillate back and forth on a TV broadcast antenna to transmit a typical TV signal (say a radio wave transmission signal with a wavelength of 1 meter)

Answers

Answer:

the oscillations of the electrons must be in the 10⁸ Hz = 100 MHz range

Explanation:

The speed of a wave of radio, television, light, heat, all are manifestations of electromagnetic waves that are oscillations of electric and magnetic fields that support each other, the speed of all these waves is the same and the vacuum is equal to c = 3 108 m / s

All waves have a relationship between the speed of the wave, its frequency and wavelength

          c = λ f

          f = c /λ

for this case lam = 1 m

          f = 3 10⁸/1

          f = 3 10⁸ Hz

the oscillations of the electrons must be in the MHz range

It should be clarified that the speed of light in air is a little lower

          n = c / v

          v = c / n

the refractive index of vacuum is n = 1 and the refractive index of air is n = 1.000002

I need help, please!

I need help, please!

Answers

Answer:

can u send pictures again it's unclear.

Bone has a Young’s modulus of about
1.8 × 1010 Pa . Under compression, it can
withstand a stress of about 1.59 × 108 Pa before breaking.
Assume that a femur (thigh bone) is 0.49 m
long, and calculate the amount of compression
this bone can withstand before breaking.
Answer in units of mm.

Answers

This bone can only tolerate 0.0405 mm of compression before it snaps.

The Young's modulus.

The ratio of tensile stress to tensile strain is a feature of the material that expresses how easily it can stretch and bend.

What is the definition of a modulus?

A modulus function is a function that provides a number or variable's absolute value. It generates the size of the number of variables.

Why do we utilize modulus?

The modulus operator, which can be used with any two accessible operands, is an addition to the C arithmetic operators. In order to obtain a result, it divides the supplied numerator by the supplied denominator. In other words, it results in a remainder for the integer division.

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What is centripetal force?Define it with example.​

Answers

Answer:

Centripetal force is defined as, "the force that is necessary to keep an object moving in a curved path and that is directed inward toward the center of rotation,"

Explanation:

so if you put a small ball por grape and put it on a table and you take a wine glass and spin it around the grape the grape will continue spinning even if you stop spinning the glass hope this helped

;)

Answer:

A force acting on a moving body at an angle to the direction of motion, tending to make the body follow a circular or curved path. The force of gravity acting on a satellite in orbit is an example of a centripetal force; the friction of the tires of a car making a turn similarly provides centripetal force on the car.

Explanation:

An insulated aluminium calorimeter with a mass of 154 g, contains 90 ml of water at a temperature of 80°C 10 g of ice at -20°C is added to the water and the mixture stirred until the ice has dissolved. What is the final temperature of the water? (specific heat aluminium = 880 JkgK¹)

Answers

The final temperature of the water is approximately 19.8°C.First, we need to calculate the heat lost by the water as it cools down from 80°C to the final temperature.

What formula is used?

We can use the formula: Q = m × c × ΔT where Q is the heat lost, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature.

The mass of water in the calorimeter is:

90 ml = 90 g

The heat lost by the water is:

Q1 = 90 g × 4.18 J/g°C × (80°C - T)

Q = m × Lf + m × c × ΔT

The mass of ice added to the water is 10 g. The heat gained by the ice is:

Q2 = 10 g × 334 J/g + 10 g × 4.18 J/g°C × (T - (-20°C))

where 334 J/g is the heat of fusion of water.

Since the calorimeter is insulated, we know that the heat lost by the water must equal the heat gained by the ice. Therefore:

Q1 = Q2

90 g × 4.18 J/g°C × (80°C - T) = 10 g × 334 J/g + 10 g × 4.18 J/g°C × (T - (-20°C))

Simplifying and solving for T, we get:

T = 19.8°C

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2 2 points Taken by a member of opposing team when a foul, such as tripping, is committed. All players must be 10 yards away. Goal Kick Free Kick Drop Kick Corner Kick
I'll give brainliest​

Answers

In soccer, when a foul is committed by a member of the opposing team, the opposing team is awarded various types of kicks depending on the location of the foul.

Goal Kick: A goal kick is awarded to the defending team when the attacking team last touched the ball before it went out of bounds over the goal line, either on the ground or in the air, and not scoring a goal. It is taken from within the defending team's goal area. A goal kick does not result in any points for either team.

Free Kick: A free kick is awarded to the team that was fouled. The location of the free kick depends on the severity and location of the foul. If the foul occurred within the opposing team's penalty area, a penalty kick may be awarded, which is taken from the penalty spot, 12 yards away from the goal line.

The opposing team must be at least 10 yards away from the ball. Points can be scored directly from a free kick if the ball is kicked into the opponent's goal without touching any other player. The number of points scored depends on the rules of the competition but is typically counted as one goal.

Drop Kick: A drop kick is not typically awarded as a result of a foul. It is a type of restart used to begin or resume play after a stoppage, such as a goal being scored or a halftime break. The player drops the ball and kicks it just after it touches the ground. Points can be scored if the ball crosses the opponent's goal line and into the goal.

Corner Kick: A corner kick is awarded to the attacking team when the ball goes out of bounds over the goal line, with the defending team being the last to touch it. The kick is taken from the corner nearest to where the ball went out of play. Points can be scored directly from a corner kick if the ball is kicked into the opponent's goal without touching any other player.

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I do not understand why the radius relative to the ball is .7 cm. I do not understand how to visualize this question.

I do not understand why the radius relative to the ball is .7 cm. I do not understand how to visualize

Answers

Answer:

Explanation:

The mass of the steel ball, m₁ = 3.0 kg

The mass of the arm, m₂ = 4.0 kg

The length of the arm, r = 7 cm

r = 7/100

r = 0.7m

The angle between the shoulder and the arm = θ

The magnitude of the torque is given by the formula:

\(\tau=Fr\sin \theta\)

The force, F, is the combined weight of the steel ball and the arm

F = (m₁ + m₂)g

F = (3.0 + 4.0)(9.8)

F = 7(9.8)

F = 68.6N

a) The magnitude of the gravitational force about the athlete's shoulder if he holds his arm straight parallel to the floor

θ = 180°

\(\begin{gathered} \tau\text{ = 68.6(0.7)}\sin 180 \\ \tau=48.02(0) \\ \tau\text{ = 0}Nm \end{gathered}\)

b) 45° below horizontal

θ = 45°

\(undefined\)

Density equals 81g per cubic centimeter. What is the mass? What is the volume?

Answers

Answer:

mass = 81g

volume = 1cm^3

Explanation:

A copper wire of length L and cross-sectional area A has resistance R. A second copper wire at the same temperature has a length of 2L and a cross-sectional area of A. What is the resistance of the second copper wire?
A. 2R
B. 4R
C. R
D. 1/2 R

Answers

Answer: 4R

Explanation:R=pL/A

R second wire=p2L/1/2A

=4R

What is the amount of thermal energy that can be stored in an object depends on?

Answers

Thermal energy is the total energy of all the molecules in an object. The thermal energy of an object depends on three things: 4 the number of molecules in the object 4 the temperature of the object (average molecular motion) 4 the arrangement of the object's molecules (states of matter).

Hope this helps

PLZ HURRY IM BEING TIMED Find the charge in Coulomb of an object with 21 protons and 15 electrons.
You may include your work in the answer.
2 points

Answers

Answer:

Must include: 21

Explanation:

A 100-W (watt) light bulb has resistance R=143Ω (ohms) when attached to household current, where voltage varies as V=V0sin(2πft), where V0=110 V, f=60 Hz. The power supplied to the bulb is P=V2R J/s (joules per second) and the total energy expended over a time period [0,T] (in seconds) is

Answers

Complete Question

A 100-W (watt) light bulb has resistance R=143Ω (ohms) when attached to household current, where voltage varies as V=V0sin(2πft), where V0=110 V, f=60 Hz. The power supplied to the bulb is P=V2R J/s (joules per second) and the total energy expended over a time period [0,T] (in seconds) is \(U = \int\limits^T_0 {P(t)} \, dt\)

Compute U if the bulb remains on for 5h

Answer:

The value is  \(U = 7.563 *10^{5} \ J\)

Explanation:

From the question we are told that

   The power rating of the bulb is \(P = 100 \ W\)

   The resistance is   \(R = 143 \ \Omega\)

   The  voltage is  \(V = V_o sin [2 \pi ft]\)

   The  energy expanded is \(U = \int\limits^T_0 {P(t)} \, dt\)

   The  voltage  \(V_o = 110 \ V\)

   The frequency is  \(f = 60 \ Hz\)

    The  time considered is  \(t = 5 \ h = 18000 \ s\)

Generally power is mathematically represented as

             \(P = \frac{V^2}{ R}\)

=>          \(P = \frac{( 110 sin [2 \pi * 60t])^2}{ 144}\)

=>           \(P = \frac{ 110^2 [ sin [120 \pi t])^2}{ 144}\)

So  

     \(U = \int\limits^T_0 { \frac{ 110^2* [sin [120 \pi t])^2}{ 144}} \, dt\)

=>  \(U = \frac{110^2}{144} \int\limits^T_0 { ( sin^2 [120 \pi t]} \, dt\)

=>  \(U = \frac{110^2}{144} \int\limits^T_0 { \frac{1 - cos 2 (120\pi t)}{2} } \, dt\)

=>  \(U = \frac{110^2}{144} \int\limits^T_0 { \frac{1 - cos 240 \pi t)}{2} } \, dt\)

=>  \(U = \frac{110^2}{144} [\frac{t}{2} - [\frac{1}{2} * \frac{sin(240 \pi t)}{240 \pi} ] ]\left | T} \atop {0}} \right.\)

=>  \(U = \frac{110^2}{144} [\frac{t}{2} - [\frac{1}{2} * \frac{sin(240 \pi t)}{240 \pi} ] ]\left | 18000} \atop {0}} \right.\)

\(U = \frac{110^2}{144} [\frac{18000}{2} - [\frac{1}{2} * \frac{sin(240 \pi (18000))}{240 \pi} ] ]\)

=>   \(U = 7.563 *10^{5} \ J\)

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