v = λ / (ρ^(1/3)) This formula relates the speed of sound (v) in a medium to the wavelength (λ) and the density (ρ) of the medium.
To derive a formula for the speed of sound in a medium using analysis, we need to consider the relevant variables and their dimensions. Let's denote the variables as follows:
Speed of sound: v
Wavelength: λ
Young's modulus: E
Density: ρ
The dimensions of these variables are:
Speed of sound: [v] = [L][T]⁻¹ (length per time)
Wavelength: [λ] = [L] (length)
Young's modulus: [E] = [M][L][T]⁻² (mass per length per time squared)
Density: [ρ] = [M][L]⁻³ (mass per length cubed)
Using dimensional analysis, we can equate the dimensions on both sides of the equation to derive the formula for the speed of sound:
[v] = [E]^x * [ρ]^y * [λ]^z
Comparing the dimensions:
[L][T]⁻¹ = ([M][L][T]⁻²)^x * ([M][L]⁻³)^y * [L]^z
Equating the dimensions of mass, length, and time on both sides, we get the following system of equations:
x = 0
1 - 2x - 3y = 0
-1 + z = 0
From the first equation, x is zero. Plugging this value into the second equation, we find y = -1/3. Similarly, from the third equation, z = 1.
Therefore, the formula for the speed of sound in a medium can be derived using dimensional analysis as:
v = E⁰ * ρ^(-1/3) * λ¹
Simplifying, we get:
v = λ / (ρ^(1/3))
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What is the kinetic energy of a 2000kg boat moving at 5m/s?
Answer:
25000 J or 25 kJ
Explanation:
K = 1/2 mv^2
where mass is in kilograms kg
and velocity is in metres per seconds m/s
Here, m = 2000, v = 5
v^2 = 5*5 = 25
1/2 mv^2 = 1/2 * 2000 * 25
= 50000/2
= 25000
Hope it helps!
how do velocity and acceleration differ? average acceleration can be measured but average velocity cannot. they are the same thing. velocity has direction but acceleration does not. velocity is the rate at which acceleration changes. acceleration is the rate of change of velocity, while velocity is the rate of change of displacement
The rate of change of displacement is velocity, while the acceleration is the rate of change of velocity, acceleration can have positive or negative values but velocity has zero as a value, along with positive and negative values.
What is displacement?It is visually depicted as an arrow that points from the initial location to the final position and has both a direction and a magnitude. A change in an object's position is referred to as displacement, which is a vector quantity.
What is acceleration?Acceleration is the rate at which an object's velocity with respect to time changes. They are vector quantities and the direction of the net force acting on an object determines the direction of its acceleration.
Hence, the rate of change of displacement is velocity, while acceleration is the rate of change of velocity, acceleration can have positive or negative values but velocity has zero as a value, along with positive and negative values.
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PLEASE HELP ASAP!!
Earthquakes have two kinds of waves, P waves and S waves. These waves may someday help scientists develop an early warning system for earthquakes. The P wave (also called the primary wave) is the first wave, and the S wave (secondary wave) travels after it. Scientists can find the location of an earthquake’s epicenter by subtracting the time that elapses between the P and S waves. A convenient way to find the epicenter is to use a graph like the one shown here.
Suppose that scientists record a P wave on a seismic device at 10 minutes. An S wave reaches the device at 15 minutes (5 minutes later). What is the distance between the recording device and the epicenter of the earthquake? Use the graph to determine your answer.
Okay, let's break this down step-by-step using the information given and the graph provided:
1) The P wave was recorded at 10 minutes.
2) The S wave arrived 5 minutes after the P wave, at 15 minutes.
3) According to the graph, the P wave travels at a speed of about 5 km/s.
4) The S wave travels at a speed of 3 km/s, which is slower than the P wave.
5) To find the distance to the epicenter, we need to use the difference in travel time between the P and S waves, which is 5 minutes.
6) Since the P wave speed is 5 km/s, in 5 minutes it will travel a distance of 25 km (5 km/s * 5 min).
7) The S wave speed is 3 km/s, so in 5 minutes it will travel 15 km (3 km/s * 5 min).
8) Therefore, the total distance to the epicenter is 25 + 15 = 40 km.
9) So the distance between the recording device and the earthquake epicenter is 40 km.
Does this make sense? Let me know if you have any other questions! I can also re-explain anything if needed.
There are roughly 1500 Km between the earthquake's epicenter and the recording device.
How to find distance?Using the graph, the time difference between the P wave and the S wave corresponds to a distance on the vertical axis. The distance is given in kilometers, convert minutes to seconds before using the graph.
5 minutes is equal to 300 seconds (since there are 60 seconds in a minute). So, see the point on the graph that corresponds to a time difference of 300 seconds (or 5 minutes). This point is located at a distance of approximately 1500 km.
Therefore, the distance between the recording device and the epicenter of the earthquake is approximately 1500 km.
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pls helppp thanks you for respond :))))
6) What is the definition of a simple machine? What are the two most basic ones?
7) Is it possible to get more work out of a machine than you put in? Why?
8) What is the official definition of heat energy? What is the source of that energy?
9) Compare and contrast heat with temperature. Explain using a bathtub of warm bath water and a tea-cup of boiling water.
10) Explain what specific heat is. How does it differ from both heat and temperature?
11) What is Latent heat? List all 3 physical constants of water.
Answer:
8) Heat energy is the form energy that is transferred from one object to another with different temperatures. Sun is the source of heat energy.
Force (N) = 250
Mass (kg) = 221
Acceleration (m/s^2) = ?
Answer:
The required acceleration is \(a=1.1\) m/s²
Explanation:
Given
Force F = 250 NMass m = 221 kgTo determine
Acceleration a = ?
We know that acceleration is produced when a force is applied to a body.
The acceleration can be determined using the formula
\(F = ma\)
where
F is the force m is the mass a is the accelerationnow substituting F = 250 , and m = 221 in the formula
\(F = ma\)
\(250 = 221 (a)\)
switch the equation
\(221(a) = 250\)
Divide both sides by 221
\(\frac{221a}{221}=\frac{250}{221}\)
simplify
\(a=\frac{250}{221}\)
\(a=1.1\) m/s²
Therefore, the required acceleration is \(a=1.1\) m/s²
A charged particle is moving to the right between 2 plates. The plate on the left has a voltage of −70 V and the plate on the right has a voltage of −50 V. The initial speed of the charge is 90,000 m/s. The particle slows down as it moves toward the right plate. The plates are separated by .002 m a) Is the particle a proton or electron? b) What is its speed just as it gets to the second plate?
On Earth, the parallax angle measured for the star Vega is 0.129 arcseconds. If you were to measure Vega's parallax angle on Pluto, what would the parallax angle be?
Answer: 7.75pc
Explanation:
Given data:
p = 0.129arcseconds.
Solution:
D = 1/p
D = 1/0.129
D = 7.75pc
The Vega is 7.75parsecs from Pluto.
An airplane accelerates with a constant rate of 3.0 m/s2
starting at a velocity of 21 m/s. If the final velocity is 60 m/s,
what is the displacement during this period?
Answer:527 m
Explanation:
The displacement or distance travelled by the airplane during the given period is 526.5m
Given the data in the question;
constant acceleration; \(a = 3.0m/s\)
Initial velocity; \(u = 21m/s\)
Final velocity; \(v = 60m/s\)
Displacement or distance; \(s = ?\)
To find the displacement or distance the plane has travelled during the given period, we use the Third Equation of Motion:
\(v^2 = u^2 + 2as\)
Where v is the final velocity, u is the initial velocity, a is the acceleration and s is the displacement.
Lets make "s" the subject of the formula
\(s = \frac{v^2-u^2}{2a}\)
We substitute our given values into the equation
\(s = \frac{(60m/s)^2 - (21m/s)^2}{2 \ *\ 3m/s^2} \\\\s = \frac{(3600m^2/s^2) - (441m^2/s^2)}{6m/s^2}\\\\s = \frac{3159m^2/s^2}{6m/s^2}\\\\s = 526.5m\)
Therefore, The displacement or distance travelled by the airplane during the given period is 526.5m
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Jessica is riding on a merry-go-round on an outer horse that sits at a distance
of 8.0 m from the center of the ride. Jessica's sister, Julie, is on an inner horse
located 6.0 m from the ride's center. The merry-go-round turns around once
every 40.0 s. a) Explain which girl is moving with the greater linear speed.
b) What is the centripetal acceleration of Julie and her horse?
a. Jessica's has a greater linear speed.
b. The centripetal acceleration of Julie and her horse is 0.148 m/s².
a) Explain which girl is moving with the greater linear speed.Jessica's has a greater linear speed.
To answer the question, we need to know what Linear speed is.
What is linear speed?This is the tangential speed at which an object in circular motion moves. It is given by v = rω where
r = distance of object from center of circle and ω = angular speed.Now, given that Jessica is riding on a merry-go-round on an outer horse that sits at a distance of 8.0 m from the center of the ride and Jessica's sister, Julie, is on an inner horse located 6.0 m from the ride's center. Also, the merry-go-round is moving at constant angular speed.
Since Linear speed v = rω and ω = constant,
So, v ∝ r.
So, the girl with the greater distance from the center of the merry-go-round would have the greater linear speed.
Since
Jessica is at r' = 8.0 m and Julie is at r" = 6.0 m.Since
v ∝ r, and r' = 8.0 m > r" = 6.0 m,So, Jessica's has a greater linear speed.
b) What is the centripetal acceleration of Julie and her horse?The centripetal acceleration of Julie and her horse is 0.148 m/s².
Centripetal acceleration a = rω² where
r = distance of Julie from center of merry-go-round = 6.0 m and ω = angular speed of merry go round.Since the merry-go-round turns once every 40.0 s, we have that ω = 2π/40.0 s
= π/20.0 s
= 0.157 rad/s
Since a = rω²
Substituting the values of the variables into the equation, we have
a = rω²
a = 6.0 m × (0.157 rad/s)²
a = 6.0 m × 0.0247 rad²/s²
a = 0.148 m/s²
So, the centripetal acceleration of Julie and her horse is 0.148 m/s².
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How high up is a cliff with 45 kg boulder if the boulder has a potential energy of 90,000 j
The height of the cliff is 200 meter where potential energy of the boulder is measured.
What is potential energy?Potential energy in physics is the energy that an item retains as a result of its position in relation to other objects, internal tensions, electric charge, or other elements.
The gravitational potential energy of an item, the elastic potential energy of a stretched spring, and the electric potential energy of an electric charge in an electric field are examples of common types of potential energy.
The height of the cliff is = 90,000 ÷ (45 ×10) meter = 200 meter.
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a rock with a mass of 10.0kg falls 25.0m to the ground. what is the work done by the gravitational force if the weight of the ball is 98.0n?
The work done by the gravitational force on the rock can be calculated using the formula W = Fd, where W is the work done, F is the force applied, and d is the distance over which the force is applied. In this case, the gravitational force is acting on the rock as it falls 25.0m to the ground. The weight of the rock is given as 98.0N, which is the force of gravity acting on it.
To calculate the work done by the gravitational force, we need to convert the mass of the rock from kg to N using the formula F = mg, where F is the force, m is the mass, and g is the acceleration due to gravity. Substituting the values, we get F = 10.0kg x 9.81m/s^2 = 98.1N. This means that the force of gravity acting on the rock is 98.1N, not 98.0N as given.
Using the formula W = Fd, the work done by the gravitational force can be calculated as W = 98.1N x 25.0m = 2452.5J. This means that the gravitational force has done 2452.5 Joules of work on the rock as it falls to the ground.
In conclusion, the work done by the gravitational force on a 10.0kg rock falling 25.0m to the ground is 2452.5J. This calculation shows how work is done by a force as it acts over a distance, and how the weight of an object can be used to determine the force of gravity acting on it.
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The James Webb Space Telescope is positioned around 1.5 million kilometres from the Earth on the side facing away from the Sun. The telescope remains at this distance and orbits around the Sun with the Earth’s orbital velocity.
--Determine the angular velocity ω of the telescope as it orbits around the Sun.
--The centrifugal Fω and gravitational force FG are acting on objects orbiting the Sun: F =Fω−FG. Based on this, how much should the telescope accelerate towards or away from the Sun?
--Why is the orbit of the telescope stable nonetheless? What other forces need to be considered?
The angular velocity depends on the length of the orbit and the orbital
speed of the telescope.
Response:
First question:
The angular velocity of the telescope is approximately 0.199 rad/sSecond question:
The telescope should accelerates away by approximately F = 0.0005·mThird question:
The pulling force between the Earth and the satelliteWhat equations can be used to calculate the velocity and forces acting on the telescope?The distance of the James Webb telescope from the Sun = 1.5 million kilometers from Earth on the side facing away from the Sun
The orbital velocity of the telescope = The Earth's orbital velocity
First question:
\(Angular \ velocity = \mathbf{\dfrac{Angle \ turned}{Time \ taken}}\)
The orbital velocity of the Earth = 29.8 km/s
The distance between the Earth and the Sun = 148.27 million km
The radius of the orbit of the telescope = 148.27 + 1.5 = 149.77
Radius of the orbit, r = 149.77 million kilometer from the Sun
The length of the orbit of the James Webb telescope = 2 × π × r
Which gives;
r = 2 × π × 149.77 million kilometers ≈ 941.03 million kilometers
Therefore;
\(Angular \ velocity = \dfrac{29.8}{941.03}\times 2 \times \pi \approx 0.199\)
The angular velocity of the telescope, ω ≈ 0.199 rad/sSecond question:
Centrifugal force force, \(F_{\omega}\) = m·ω²·r
Which gives;
\(F_{\omega} = m \cdot \dfrac{28,500^2 \, m^2/s^2}{149.77 \times 10^9 \, m} \approx 0.0054233 \cdot m\)
\(Gravitational \ force, F_G = \mathbf{G \cdot \dfrac{m_{1} \cdot m_{2}}{r^{2}}}\)
Universal gravitational constant, G = 6.67408 × 10⁻¹¹ m³·kg⁻¹·s⁻²
Mass of the Sun = 1.989 × 10³⁰ kg
Which gives;
\(F_G = 6.67408 \times 10^{-11} \times \dfrac{1.989 \times 10^{30} \times m}{149.77 \times 10^9} \approx 0.00592 \cdot m\)
Which gives;
\(F_{\omega}\) < \(F_G\), therefore, the James Webb telescope has to accelerate away from the Sun
F = \(\mathbf{F_{\omega}}\) - \(\mathbf{F_G}\)
The amount by which the telescope accelerates away is approximately 0.00592·m - 0.0054233·m ≈ 0.0005·m (away from the Sun)
Third part:
Other forces include;
The force of attraction between the Earth and the telescope which can contribute to the the telescope having a stable orbit at the given speed.Learn more about orbital motion here:
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a 3000.0 kg car's center of mass is located 1.00 m from the front axle and the two axles are 4.00 m apart. what is the force on each front wheel
The force on each front wheel of the car is 7500 N.
To determine the force on each front wheel of the car, we need to consider the distribution of weight and the position of the center of mass.
The weight of the car acts downward and can be considered as a single force acting at the center of mass. In this case, the weight of the car can be calculated as the product of its mass (m) and the acceleration due to gravity (g):
Weight = m * g.
Given that the mass of the car is 3000.0 kg and the acceleration due to gravity is approximately 9.8 m/s², the weight of the car is:
Weight = 3000.0 kg * 9.8 m/s² = 29400 N.
Since the center of mass is located 1.00 m from the front axle and the two axles are 4.00 m apart, we can determine the distribution of weight between the front and rear axles.
The weight distribution is proportional to the distance from the center of mass to each axle. Therefore, the weight on each front wheel can be calculated as:
Weight on front wheels = (distance to front axle / distance between axles) * Weight.
Using the given values:
Weight on front wheels = (1.00 m / 4.00 m) * 29400 N,
Weight on front wheels = 0.25 * 29400 N,
Weight on front wheels = 7350 N.
Since the force on each wheel is equal to the weight on each wheel, the force on each front wheel of the car is 7350 N.
The force on each front wheel of the car is 7500 N. This result is obtained by considering the weight distribution based on the position of the center of mass and calculating the weight on each front wheel accordingly. The weight on each wheel is equal to the force on each wheel, and in this case, it is determined to be 7350 N.
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Help me please 80 points!
Differentiate the three mechanisms by which thermal energy is transferred through the Earth's systems: radiation,
conduction and convection.
Mary Carskadon and her colleagues' research on adolescent sleep patterns found that:
A. increased sleepiness in adolescents during the day was primarily due to academic work or social pressures.
B. when given the opportunity, adolescents will sleep an average of 9 hours and 25 minutes a night.
C. adolescents' biological clocks undergo a shift as they get older, so that older adolescents start to feel sleepy an hour earlier than younger adolescents.
D. younger adolescents tend to be sleepier during the day than older adolescents.
This shift in the biological clock is a natural part of the adolescent development process, but it can be exacerbated by external factors such as academic work or social pressures. Despite this, when given the opportunity, adolescents will sleep an average of 9 hours and 25 minutes a night, which is important for their overall health and well-being.
Mary Carskadon and her colleagues' research on adolescent sleep patterns found that adolescents' biological clocks undergo a shift as they get older, so that older adolescents start to feel sleepy an hour earlier than younger adolescents. This means that younger adolescents tend to stay up later and have difficulty waking up early, while older adolescents may have an easier time falling asleep earlier but struggle with staying asleep throughout the night.
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when you switch the appliances in a house, the current supplied to the house increases .State whether the appliances connected to the house is parallel or in series
parallel circuits is used in the house.
For household circuits, parallel circuits are always used because: In parallel circuits, all other electrical appliances continue to operate correctly even if one electrical appliance stops functioning for whatever reason. In a parallel circuit, each electrical appliance has its own switch, allowing it to be switched on or off independently without impacting other appliances. In a parallel circuit, every electrical device receives the same voltage as the power supply line.
When electrical devices are linked in parallel, the overall resistance of the home circuit is decreased, causing a large current to flow from the power source.
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Which of the following is/are not one of Kelper's law
a) Law of orbits b) Law of attraction c) Law of radius d) Law of areas
Law of attraction and Law of radius does not come in Kelper's law.
In astronomy, Kepler's legal guidelines of planetary movement, published via Johannes Kepler between 1609 and 1619, describe the orbits of planets across the solar. The laws changed the heliocentric theory of Nicolaus Copernicus, changing its circular orbits and epicycles with elliptical trajectories, and explaining how planetary velocities vary.
The elliptical orbits of planets were indicated through calculations of the orbit of Mars. From this, Kepler inferred that different our bodies within the solar device, including those farther far from the sun, additionally have elliptical orbits, the 2nd one law allows to set up that when a planet is toward the solar, it travels faster. The 3rd law expresses that the farther a planet is from the sun, the slower its orbital pace, and vice versa.
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You own a geotechnical engineering firm in central California and your company has been hired to conduct a slope stability analysis. Consider a 10.0 m-thick mass of regolith (note that this is already measured perpendicular to the slope – so pay attention where you might change the cosine term) sitting on top of a bedrock surface with a slope of 14 degrees. A home is located at the top of this slope (and set back from the edge only 20 m). Upon an initial visit, you determine that the regolith is unsaturated. You also estimate the following additional parameters for this site:
regolith cohesion = 1100 N/m2
regolith angle of internal friction = 15 degrees
density of regolith = 2200 kg/m3 (density of water = 1000 kg/m3 )
a. What is the value for the Factor of Safety? Show your work. Would you consider the slope currently stable? Explain your answer. 4 pts
b. How does the factor of safety change if the water depth increases by 2 m? Does the slope become more or less stable, and by how much? How does this compare to the example above (Part a.)? 3 pts
c. How does the factor of safety change if the angle of internal friction increases by a factor of 2 (this would be the equivalent of changing the material from loose sand to semi-consolidated sediment)? Does the slope become more stable or less stable? 3 pts
d. How does the factor of safety change if the slope is steeper by a factor of 2? Does the material become more or less likely to fail? 3 pts
e. What advice would you give to the homeowners regarding the safety of their home? What remediation can you suggest if any is needed? 3 pts
The factor of safety for the slope stability analysis needs to be determined for a regolith slope in central California. The parameters provided include regolith cohesion, angle of internal friction, and regolith density. The analysis involves evaluating the stability of the slope under different conditions, such as changes in water depth, angle of internal friction, and slope steepness. Recommendations for the homeowners regarding the safety of their homes and potential remediation measures will also be provided.
To calculate the factor of safety, we need to consider the forces acting on the slope. The driving force is the weight of the regolith, which can be calculated by multiplying the density of the regolith by the volume of the slope. The resisting force is the shear strength of the regolith, which is determined by the cohesion and angle of internal friction. The factor of safety is the ratio of the resisting force to the driving force.
a. To determine the factor of safety, we can use the given parameters and calculate the driving force and resisting force. By dividing the resisting force by the driving force, we can obtain the factor of safety. If the factor of safety is greater than 1, it indicates that the slope is stable. If it is less than 1, the slope is considered potentially unstable.
b. If the water depth increases by 2 m, it adds additional weight to the slope, increasing the driving force. This decrease in the factor of safety suggests a less stable slope compared to the initial scenario.
c. If the angle of internal friction increases by a factor of 2, it enhances the shear strength of the regolith. This increase in the factor of safety indicates a more stable slope.
d. If the slope becomes steeper by a factor of 2, it increases the driving force. This decrease in the factor of safety suggests a less stable slope.
e. Based on the analysis, it is important to advise the homeowners that the slope is currently unstable, considering the factor of safety is less than 1. Remediation measures may include slope stabilization techniques such as installing retaining walls, soil reinforcement, or drainage systems to manage water infiltration and reduce driving forces. It is recommended to consult with a geotechnical engineer to develop a comprehensive slope stability plan for the safety of the home.
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determine the overall charge on each complex ion. tetrachloridocuprate(ii) ion:
The overall charge on the tetrachloridocuprate(II) ion is 2-.
In different wording: What is the net charge on the tetrachloridocuprate(II) ion?The tetrachloridocuprate(II) ion, also known as CuCl4^2-, consists of a central copper atom (Cu) coordinated to four chloride ions (Cl-) in a tetrahedral arrangement. Each chloride ion carries a charge of -1, resulting in a total negative charge of -4 contributed by the chloride ligands. Since the overall charge of the tetrachloridocuprate(II) ion is 2-, it means the copper ion must have a charge of +2 to balance the negative charges from the chloride ions. This indicates that the copper ion has lost two electrons to achieve stability and form the complex ion.
Complex ions: Complex ions are formed when a central metal atom or ion is surrounded by ligands, which are usually ions or molecules that donate electrons to the metal. The overall charge on a complex ion is determined by balancing the charges of the ligands with the charge of the central metal atom or ion.
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how can the momentum of a speeding bullet be the same as the momentum of a supertanker moving toward a dock
Mass in motion is quantified by momentum, which is the measure of how much weight is moving. It typically has the sign math
What does motion mean in mathematics?
In mathematics, movement, distance, velocity, impulse, and speed are used to explain motion. By securing a reference point to the environment or the observer, a body's motion can be seen. A body's motion is quantified by tracking how its location changes in relation to the perspective it occupies.
What types of motion may an object make?
The force acting on a body determines how it moves. These are some examples of various motion types. Translational: When an item goes along a route across all 3 components, it is of this type. Rotational: This sort of movement involves an object moving in a circular motion around a fixed axis.
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A boy is twirling a model airplane on a string 4 feet long. if he twirls the plane at 0.25 revolutions per minute, how far does the plane travel in 4 minutes? round to the nearest tenth.
Answer:
25.13 ft
Explanation:
r = 4 feet
ω=0.25 revolution per minute
=1 revolution in 4 minutes
total number of revolution N = 1 (in 4 minutes )
v=rω
distance traveled = 2×N×π×r
=2×1×π×4
=8π
= 25.13ft in 4mins
.. I rode my bicycle to grandmother's house at 6 km/h in a flat road for 5 min before reach a hill. I went at 2 km/h up the hill for 3minutes. I met a friend and stopped to talk for 5 minutes. I went on at 2 km/h to my grandmother's house. Draw (plot) the v against t graph for this motion.3
Answer:
The velocity-time graph is illustrated and it shows the speed and direction that's traveled by the bicycle.
A velocity-time graph simply shows the speed and the direction that an object travels over a particular period of time.
It should be noted that they're also known as the speed-time graph. On the vertical axis is the velocity of the object.
Since 60 minutes = 1 hour 3 minutes will be converted to hour. This will be:
= 3/60 = 1/20 hour.
5 minutes will be changed to hour. This will be: = 5/60 = 1/12 hours.
Explanation:
according to the avogadros' law, when we keep pressure and temperature constant, what happens to the volume of a gas when we increase the mass of the gas by adding more particles?
When the mass of a gas is increased by adding more particles while keeping pressure and temperature constant, the volume of the gas will also increase proportionally.
Determine the Avogadro's law?According to Avogadro's law, at constant temperature and pressure, equal volumes of gases contain an equal number of particles (molecules or atoms). This implies that the volume of a gas is directly proportional to the number of particles present.
When more particles are added to a gas system while maintaining constant temperature and pressure, the total number of particles in the system increases. As a result, the volume of the gas also increases to accommodate the additional particles. The gas expands to occupy a larger space to maintain the same pressure and temperature.
This behavior can be explained by the ideal gas law, which combines Boyle's law, Charles's law, and Avogadro's law. According to the ideal gas law, PV = nRT, where P represents pressure, V represents volume, n represents the number of particles (moles), R is the gas constant, and T represents temperature.
Since, pressure and temperature are constant, increasing the number of particles (n) will cause the volume (V) to increase proportionally.
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A uniform electric field of magnitude 380 N/C pointing in the positive x-direction acts on an electron, which is initially at rest. The electron has moved 2.90 cm.(a) What is the work done by the field on the electron?
(b) What is the change in potential energy associated with the electron?
(c) What is the velocity of the electron?
(a) The work done by the field on the electron is -1.04 x 10^-18 J.
(b) The change in potential energy associated with the electron is 1.04 x 10^-18 J.
(c) The velocity of the electron is 1.22 x 10^6 m/s.
(a) The work done by a uniform electric field on a charge is given by the equation W = qEd, where W is the work done, q is the charge, E is the electric field, and d is the distance moved by the charge in the direction of the field. In this case, the charge is an electron with charge -1.6 x 10^-19 C, the electric field is 380 N/C in the positive x-direction, and the distance moved is 2.90 cm = 0.0290 m in the same direction. Substituting these values into the equation gives W = (-1.6 x 10^-19 C)(380 N/C)(0.0290 m) = -1.04 x 10^-18 J.
(b) The change in potential energy associated with the electron is given by the equation ΔU = qΔV, where ΔU is the change in potential energy, q is the charge, and ΔV is the change in potential. Since the electron moves in the direction of the electric field, the change in potential is ΔV = Ed. Substituting the values of q, E, and d from part (a) into the equation gives ΔU = (-1.6 x 10^-19 C)(380 N/C)(0.0290 m) = 1.04 x 10^-18 J.
(c) The work done on the electron by the electric field is equal to the change in the electron's kinetic energy. Using the work-energy theorem, the kinetic energy of the electron can be calculated as KE = W = -1.04 x 10^-18 J. The kinetic energy of the electron is also given by the equation KE = (1/2)mv^2, where m is the mass of the electron and v is its velocity. Solving for v, we get v = √(2KE/m) = 1.22 x 10^6 m/s, where m is the mass of the electron, which is 9.11 x 10^-31 kg.
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The equation for free fall at the surface of some planet (s in meters, t in seconds) is s=1.33t^(2). How long does it take a rock falling from rest to reach a velocity of 27.2(m)/(s) on this planet?
To increase the boiling temperature of 2051 g of water by 1.500 °C, approximately 3.431 grams of NaCl would need to be added.
Explanation:
The boiling point elevation is determined by the molality of the solute in the solution. The equation for boiling point elevation is:
ΔTb = Kb * m
Where:
ΔTb is the boiling point elevation,
Kb is the boiling point elevation constant for water (0.5100 °C/m),
m is the molality of the solute.
To calculate the molality, we can use the formula:
m = (moles of solute) / (mass of solvent in kg)
Given that we want to increase the boiling temperature by 1.500 °C, and the Kb value is 0.5100 °C/m, we can rearrange the equation to solve for the molality:
m = ΔTb / Kb
m = 1.500 °C / 0.5100 °C/m
m ≈ 2.941 m
To convert molality to mass, we need to know the molecular weight of NaCl. The molecular weight of NaCl is approximately 58.44 g/mol.
Using the formula:
mass of solute = molality * molecular weight of solute * mass of solvent in kg
mass of solute = 2.941 m * 58.44 g/mol * 2.051 kg
mass of solute ≈ 3.431 g
Therefore, approximately 3.431 grams of NaCl would need to be added to 2051 g of water to increase the boiling temperature of the solution by 1.500 °C.
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The equation for free fall at the surface of some planet (s in meters, t in seconds) is s=1.33t^(2), the long it take a rock falling from rest to reach a velocity of 27.2(m)/(s) on this planet is 1.414 seconds.
Free fall is a type of movement that an object undergoes when it falls freely under the effect of gravity. Gravity is a force that acts on every object and makes it move towards the center of the earth or any other celestial body. The acceleration due to gravity is expressed as g, and it is equal to 9.8 m/s² on earth. The time it takes a rock falling from rest to reach a velocity of 27.2 m/s on this planet can be calculated by equating the acceleration due to gravity with the given velocity.
The formula for velocity is given by V=U+at, where V is the final velocity, U is the initial velocity, a is the acceleration, and t is the time taken to reach the final velocity. Under free fall, the initial velocity is zero; therefore, the formula can be simplified to V = at.
Substituting the given values in the formula, we get 27.2=1.33t² × g or 27.2=1.33t² × 9.8.
We can simplify this equation to t² = (27.2)/(1.33 × 9.8) or t² = 2.
The square root of 2 is 1.414. Therefore, the time taken for the rock to reach a velocity of 27.2 m/s on this planet is 1.414 seconds.
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It takes a person 22 seconds to swim in a straight line from the south end of
a pool to the north end of the pool, a distance of 28 meters. What is the
swimmer's velocity?
Answer:
1.27 m/s.
Explanation:
The following data were obtained from the question:
Displacement (D) = 28 m
Time (t) = 22 secs
Velocity (v) =?
Velocity is simply defined as the rate of change of displacement of an object with time. It can be represented mathematically as:
Velocity (v) = Displacement (D) /Time (t)
v = D/t
With the above formula, we can obtain the swimmer's velocity as follow:
Displacement (D) = 28 m
Time (t) = 22 secs
Velocity (v) =?
v = D/t
v = 28/22
v = 1.27 m/s
Therefore, the swimmer's velocity is 1.27 m/s.
Answer:
1.3 m/s north
Explanation:
what are metalloids?
Answer:
a type of chemical element whose properties are intermediate between those of metals and nonmetals.
Under what condition does the addition of two simple harmonic motions produce a resultant, which is also simple harmonic?
Answer:
Explanation:
The addition of two simple harmonic motions will produce a result that is also simple harmonic if the two simple harmonic motions have the same frequency and phase.
When two simple harmonic movements attain their maximum or lowest values at the same moment, they are said to be in phase. If the amplitudes of two simple harmonic movements have the same frequency and are in phase, the amplitude of the resulting motion may be calculated. This indicates that the combined system's motion will still oscillate at the same frequency as the separate movements and will be sinusoidal in form, as is the distinguishing feature of simple harmonic motion. As a result, adding two simple harmonic movements with the same frequency and phase results in a consequent motion that is likewise simple harmonic.
The greater the mass of an object.
Answer:
Mass is the measure of an object's matter (what it's made up of). The greater an object's mass, the greater its gravitational force. The earth has a strong attracting force for objects with smaller mass (including the moon), and the sun has an attracting force on the earth and other planets in our solar system.
A sound wave traveling in water at 144m/s has a wavelength of 0.5m determine the frequency of the wave
Heya!!
For calculate frequency, lets applicate formula:
\(\boxed{f=v/\lambda}\)
Δ Being Δ
f = Frequency = ?
v = Velocity = 144 m/s
\(\lambda\) = Wavelenght = 0,5 m
⇒ Let's replace according the formula:
\(\boxed{f = 144\ m/s / 0,5\ m }\)
⇒ Resolving
\(\boxed{f = 288\ Hz}\)
Result:
The frequency of that wave is 288 Hertz
Good Luck!!
Answer:
sadasdsadasd
Explanation: