The square below represents one whole.
What percent is represented by the shaded area?
Pls

Answer:

p = 19 ft

hope it's helpful

The Original figure and its dilated image are plotted on the graph and attached with the answer.

Scale factor is used to compare 2 quantities, indicating by how much one quantity is greater than the other. It is denoted by K. Mathematically-

K = a/b.

If a coordinate point (x, y) is dilated by a scale factor of [k], then the coordinate point after dilation will be - (kx, ky).

Given are the vertices of a figure QRTU and the scale factor by which it is dilated.

We have the following coordinates of the vertices of the figure QRTU.

Q(-3, 0)

R(-3, 6)

T(4, 6)

U(4, 0)

The given scale factor is [K] = 1/3

Now, we know - If a coordinate point (x, y) is dilated by a scale factor of [k], then the coordinate points after dilation will be - (kx, ky).

The new coordinates will be -

Q'(1/3 x -3 , 1/3 x 0) = Q'(-1, 0)

R'(1/3 x -3 , 1/3 x 6) = R'(-1, 2)

T'(1/3 x 4, 1/3 x 6) = T'(4/3, 2)

U'(1/3 x 4, 1/3 x 0) = U'(4/3, 0)

Graph the given coordinates to get a dilated figure. Refer to the graph attached. Red graph represents the original figure and the blue graph represents its dilated image.

Therefore, the Original figure and its dilated image are plotted on the graph and attached with the answer.

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[The question is not complete. The image attached after the graph represents the complete question]

Given:

Brian and Ali take turns picking a jelly bean without looking

Required: Dependent or independent event

Explanation:

Brian picked a jelly bean first and after Ali picked second. The probability of Ali picking up depends on the jelly bean.

Hence the events are depndent.

Final Answer: Dependent events

The condition for the equation (∂U/∂V)T = (∂U/∂P)T = (∂H/∂V)T = 0 to be true is that the system described must be in a state of mechanical, thermal, and chemical equilibrium.

Let's break down the conditions for each partial derivative:

1. (∂U/∂V)T = 0: This condition implies that the internal energy of the system does not change with respect to volume at constant temperature.

It indicates mechanical equilibrium, where the system is in balance and no work is being done on or by the system due to volume changes.

2. (∂U/∂P)T = 0: This condition suggests that the internal energy of the system does not change with respect to pressure at constant temperature.

It indicates thermal equilibrium, where the system is in balance and there is no transfer of energy as heat due to pressure changes.

3. (∂H/∂V)T = 0: This condition implies that the enthalpy of the system does not change with respect to volume at constant temperature.

It also indicates mechanical equilibrium, where the system is in balance and there is no work being done on or by the system due to volume changes.

In summary, the condition (∂U/∂V)T = (∂U/∂P)T = (∂H/∂V)T = 0 is true when the system is in a state of mechanical, thermal, and chemical equilibrium, where there are no changes in internal energy, pressure, and enthalpy with respect to volume at constant temperature.

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• The statement "A = {x | IkeN,1<=x<=10}" is True , • The statement "-(p UCF q) = -p ^ FL" is False.

The statement "A = {x | IkeN,1<=x<=10}" can be interpreted as follows: Set A consists of elements x such that x is a natural number and lies between 1 and 10, inclusive. This set would include the numbers 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10. Therefore, the statement is True.

Now, let's analyze the second statement "-(p UCF q) = -p ^ FL." To understand this, we need to break it down.

The expression "-(p UCF q)" represents the negation of the union of sets p and q. It implies that any element that is not in the union of sets p and q will be included. On the other hand, "-p ^ FL" represents the negation of p and the intersection with set FL. This implies that elements that are not in set p but are in set FL will be included.

Based on the definitions above, we can see that these two expressions are not equivalent. The negation of the union of sets p and q is not the same as the negation of p and the intersection with FL. Therefore, the statement is False.

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Answer:

x intercept = -5.33

y intercept = 8

Step-by-step explanation:

The given equation is ,

⇒ -6x + 4y = 32 ,

The standard form of the Intercept form is ,

⇒ x/a + y/b = 1 , where

• Converting the equation :-

⇒ 2( -3x + 2y ) = 32

⇒ -3x + 2y = 16

⇒ -3x + 2y / 16 = 1

⇒ (-3x)/16 + 2y/16 = 1

⇒ -3x/16 + y/8 = 1

⇒ x/-5.33 + y/8 = 1 .

Therefore ,

The two families do not pay the same amount. The Manuel's family pay more.

Let c represent the cost of children's ticket.

Cost of adult ticket = $4 + c

Cost of senior ticket = $3 + c

Total cost = 3(c) + 2(4 + c)

= 3c + 8 + 2c

= 5c + 8

Total cost = 2(c) + 4 + c + 2(3 + c)

2c + 4 + c + 6c + 2

9c + 8

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Answer:

D

Step-by-step explanation:

The area (A) of the sector is calculated as

A = area of circle × fraction of circle

   = πr² × \(\frac{80}{360}\)

   = π × 0.9² × \(\frac{8}{36}\)

   = 0.81π × \(\frac{2}{9}\)

   = 0.09π × 2

   = 0.18π in² → D

Answer:

First on is 0.75

Second is 22/52 (not sure about this one though)

Step-by-step explanation:

For the first one:

P(aUb) = p(a) + p(b) - p(a^b)

0.6 = 0.4 + 0.5 - p(a^b)

p(a^b) = 0.3

P(a/b)= p(a^b)/p(a)

P(a/b)= 0.3/0.4

P(a/b)= 0.75

For the second one:

Total of the cards are 52

Diamonds are 13 out of that 52

Face cards are 12 out of that 52

Diamond OR face cards means p(aUb)

And that equals p(a)+p(b)-p(a^b)

p(a^b) means the intersection between the two, there are three common cards between diamonds and face cards, so p(a^b)=3

13/52 + 12/52 - 3/52= 22/52

Answer:

The common ratio is -2.0

Step-by-step explanation:

I did the test and got it right

a. The probability of drawing a red ball from Box 1 is 30%.

b. If a red ball is drawn from Box 1, the probability of drawing another red ball from Box 2 on the second round is 60%.

c. If the first draw from Box 1 was black, the conditional probability of drawing a red ball from Box 3 on the second draw is 80%.

d. The probability of drawing two red balls at both draws, without any prior information, is 46%.

e. The probability of drawing a red ball at the first draw and a black ball at the second draw, without any prior information, is 21%.

a. The probability of drawing a red ball from Box 1 can be calculated by dividing the number of red balls in Box 1 by the total number of balls in Box 1. Therefore, the probability is 3/(3+7) = 3/10 = 0.3 or 30%.

b. Since a red ball was drawn from Box 1, we only consider the balls in Box 2. The probability of drawing a red ball from Box 2 is 6/(6+4) = 6/10 = 0.6 or 60%. Therefore, the probability of drawing another red ball when the first ball drawn from Box 1 is red is 60%.

c. If the first draw from Box 1 was black, we only consider the balls in Box 3. The probability of drawing a red ball from Box 3 is 8/(8+2) = 8/10 = 0.8 or 80%. Therefore, the conditional probability of drawing a red ball from Box 3 when the first ball drawn from Box 1 was black is 80%.

d. Before any draws, the probability of drawing two red balls at both draws can be calculated by multiplying the probabilities of drawing a red ball from Box 1 and a red ball from Box 2. Therefore, the probability is 0.3 * 0.6 = 0.18 or 18%. However, since there are two possible scenarios (drawing red balls from Box 1 and Box 2, or drawing red balls from Box 2 and Box 1), we double the probability to obtain 36%. Adding the individual probabilities of each scenario gives a total probability of 36% + 10% = 46%.

e. Before any draws, the probability of drawing a red ball at the first draw and a black ball at the second draw can be calculated by multiplying the probability of drawing a red ball from Box 1 and the probability of drawing a black ball from Box 2 or Box 3. The probability of drawing a red ball from Box 1 is 0.3, and the probability of drawing a black ball from Box 2 or Box 3 is (7/10) + (2/10) = 0.9. Therefore, the probability is 0.3 * 0.9 = 0.27 or 27%. However, since there are two possible scenarios (drawing a red ball from Box 1 and a black ball from Box 2 or drawing a red ball from Box 1 and a black ball from Box 3), we double the probability to obtain 54%. Adding the individual probabilities of each scenario gives a total probability of 54% + 10% = 64%.

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Answer:

factors

Step-by-step explanation:

The formula for the volume of a cone is:

V = (1/3)πr²h

where r is the radius of the base, h is the height of the cone, and π is pi.

In this case, the slant height is given as 17 cm, which we can use with the radius to find the height of the cone using the Pythagorean theorem:

h² = s² - r²

h² = 17² - 8²

h² = 225

h = 15

Now that we have the height, we can plug in the values for r and h into the formula for the volume:

V = (1/3)π(8²)(15)

V = (1/3)π(64)(15)

V = (1/3)(960π)

V = 320π

Therefore, the volume of the cone is 320π cubic cm. Answer: 320π.

The driver would have needed 76 feet to come to a complete stop after she saw the cow assuming she stayed on the road.

Stopping distance can be defined as a measure of the distance between the time when a brake is applied by a driver to stop a vehicle that is in motion and the time when the vehicle comes to a complete stop (halt).

In this scenario, we can infer that the driver would have needed 76 feet to come to a complete stop after she saw the cow assuming she stayed on the road.

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The value of k in the equations is 2/3

From the question, we have the following parameters that can be used in our computation:

y = 9kx - 1

kx + 4y = 12

This can be expressed as

y = 9kx - 1

y = -kx/4 + 3

The slopes of perpendicular lines are opposite reciprocal

This means that

9k * -k/4 = -1

So, we have

k^2 = 4/9

Evaluate

k = 2/3

Hence, the value of k is 2/3

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If you need to writing it in slope intercept form it’ll be : w = −4/3m+24

If you are looking for the x and y intercepts it will be: m (which will be the x intercept in this case) = (18,0) and w (which will be the y intercept) = (0,24)

I hope this helps

The Roman numeral for the number 9 is IX.

Roman numerals are a numeral system that originated in ancient Rome and were used throughout the Roman Empire. Instead of using a base 10 system like the one we use today, Roman numerals use a combination of letters to represent numbers. The basic symbols in Roman numerals are I, V, X, L, C, D and M.

The numeral I represents the number 1, and the numeral X represents the number 10. To represent 9, we can represent 1 before 10 which is I before X.

It's important to note that Roman numerals have a strict set of rules for how to use the symbols correctly. For example, a numeral can only be repeated up to three times in a row, and numerals can only be subtracted from the next highest numeral that is at least 10 times larger.

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The perimeter of the triangle is 21

A perimeter is a closed path that encompasses, surrounds, or outlines either a two dimensional shape or a one-dimensional length.

The perimeter of the triangle is found by adding all the sides

The vertices of the triangle ABC are (-1,1), (-3, -4), and (5,-2). let A be (-1,1), B be (-3, -4) and C be (5,-2).

The distance between And B = √ (-3-(-1))²+( -4-1)²

Line AB = √ 2²+-5²

AB = √ 4+25

AB =√29 = 5.4

line AC = √5-(-1)² + (-2-1)²

AC = √ 6²+3²

AC = √ 36+9

AC = √ 45

AC = 6.7

The distance between B and C = √( -3-5)² + (-4-(-2)²

BC = √ 8²+4²

BC =✓64+16

BC = √80

BC = 8.9

Therefore the perimeter of the triangle is AB+ BC + AC = 5.4+6.7+8.9 = 21

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Answer:

\(y=-3x+5\)

Step-by-step explanation:

Hi there!

What we need to know:

1) Determine the slope (m)

\(y= -3x -5\)

With the given line, we can identify clearly that -3 is in the place of m, making it the slope. Because parallel lines have the same slopes, the slope of the line we're currently solving for would also be -3. Plug this into \(y=mx+b\):

\(y=-3x+b\)

2) Determine the y-intercept (b)

\(y=-3x+b\)

Plug in the given point (1,2) and isolate b

\(2=-3(1)+b\\2=-3+b\)

Add 3 to both sides

\(2+3=-3+b+3\\5=b\)

Therefore, the y-intercept of the line is 5. Plug this back into \(y=-3x+b\):

\(y=-3x+5\)

I hope this helps!

Answer:

1 in 10, or 10% because there is a 90% chance she will choose the wrong number.

Answer:

\(\frac{1}{10}\)

Step-by-step explanation:

1-10 is 10 numbers, only one of which is the correct one.

The resulting proportion is:

\(\frac{1}{10}\)

Answer:

13 meters below sea level.

Step-by-step explanation:

she started at -15m.

Then she went up 7m, making it -8m.

Then down 5m, making it -13m.

the equation would look like this: -15+7-5. All the best, -Crispin

Answer:

on the same dot but on the left sid

Step-by-step explanation:

Answer:A

Step-by-step explanation:

got right in quiz

The expression that represents the maximum weight in tons of all the whales in the oceans is 150y tons.

A variable in mathematics is a symbol or letter that designates a value that is subject to variation or change. In algebraic equations and expressions, variables are used to represent unknown numbers or quantities with a range of possible values. Typically, variables are represented by letters like x, y, and z or a, b, and c. The variable is frequently placed on one side of the equal sign in an equation, and the value that the variable equals is denoted by the expression on the other side of the equal sign.

Given that, the weight of one single whale = 150 tons.

Now,

Maximum weight = 150y tons

Hence, the expression that represents the maximum weight in tons of all the whales in the oceans is 150y tons.

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Answer:

\(9\frac{21}{25}\)

Step-by-step explanation:

Simplify the 0.84. It is 84/100, or divided by 4, it is 21/25.

Hope this helped! :))

Answer:

Step-by-step explanation:

Mixed numbers are a whole number and a fraction together

sooo  9.84=  9 84/100   but we can reduce 84 /100 to 42/50 and that can be reduced to 21/25

so write 9 21/25

In August 2016, the Compounding Department had 6,000 equivalent units for the beginning work in process and 102,000 equivalent units for the units started. The total equivalent units were 108,000.


To calculate the equivalent units, we consider the work in process at the beginning and the units started during the period. The beginning work in process was 6,000 pounds at 60% processed, which gives us 6,000 x 0.60 = 3,600 equivalent units. The units started were 102,000 pounds, which are considered 100% processed, resulting in 102,000 equivalent units.

Adding the equivalent units from the beginning work in process and the units started, we get a total of 3,600 + 102,000 = 105,600 equivalent units. However, since the ending work in process was 90% processed, we need to multiply it by 0.90 to calculate the additional equivalent units. This gives us 96,000 x 0.90 = 86,400 equivalent units. Finally, we add the additional equivalent units to the total, resulting in 105,600 + 86,400 = 192,000 equivalent units for the Compounding Department in August 2016.

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