The standard unit for measuring the angular position of a rotating object is _____.

Answers

Answer 1

The standard unit for measuring the angular position of a rotating object is the radian (rad).

The radian is a unit of measurement that quantifies angles in terms of the ratio of the arc length along the circumference of a circle to its radius. Specifically, one radian is defined as the angle subtended at the center of a circle by an arc that is equal in length to the radius of the circle.

Using radians as the unit of angular position has several advantages. Firstly, it is a dimensionless unit, meaning it does not have any physical dimensions associated with it. This makes it a mathematically convenient unit to work with in calculations involving angles.

Secondly, radians provide a direct relationship between the angle and the arc length along the circumference of a circle. For example, an angle of 1 radian corresponds to an arc length equal to the radius of the circle. This relationship simplifies many calculations involving circular motion, such as determining displacements, velocities, and accelerations.

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Related Questions

beyond the formation of iron, nuclear energy can be produced only by

Answers

Answer:

Beyond the formation of iron, nuclear energy can be produced only by fission of heavy nuclei back toward lighter ones

In 2-3 sentences, summarize the evidence for the big bang theory. Include the following vocab words in your response: Redshift, Galaxies, Expansion, Cosmic microwave background.

Answers

The Big Bang theory is supported by experimental evidence obtained by astronomical observations. Scientists observing light emitted from galaxies did not match light spectra produced in experiments on earth - they were shifted to a longer wavelength, a phenomenon known as redshift. The only way that light could have been redshifted while it was traveling from the galaxies was if the galaxies were moving away from us by the universe’s expansion. Another observation is the faint electromagnetic radiation being emitted from the far reaches of the universe; this cosmic microwave background essentially provides a snapshot of the universe when the temperature dropped low enough for fundamental particles to form.

Hope this helps!

The amplitude of a particle executing simple harmonic motion is 5cm, while its angular velocity is 10 rads -1 . Calculate the magnitude of the maximum acceleration of the particle.

Answers

Answer:

a_max = 50 cm/s^2

Explanation:

To find the magnitude of the maximum acceleration of the particle, you take into account the equation of motion in a simple harmonic motion:

\(x=Acos(\omega t)\)

ω: angular velocity = 10 rad/s

A: amplitude = 5 cm

The acceleration is given by:

\(a=\omega^2 x\)

and the maximum acceleration is obtained when the cosine function is maximum, that is, when cos(wt) = 1. Then, you have:

\(a_{max}=\omega^2 x_{max}=\omega^2A\)

Then, you replace the values of w and A in order to calculate a_max:

\(a_{max}=(10rad/s)^2(5cm)=50\frac{cm}{s^2}\)

hence, the maximum acceleration is 50 cm/s^2

a large room is filled with mousetraps, each trap set with two plastic balls on the arm of the trap. a single plastic ball is thrown into the room, setting off one trap. this causes three plastic balls to be in the air, which then land and set off three other traps, and so on. how could this be evaluated as a model for fission?

Answers

The mousetrap model demonstrates a chain reaction, similar to fission, where the release of energy from one reaction triggers subsequent reactions.

In the mousetrap model, the initial trigger sets off a chain reaction where each reaction leads to multiple subsequent reactions. Similarly, in nuclear fission, the release of energy from one nucleus splitting triggers the splitting of neighboring nuclei, resulting in a self-sustaining chain reaction.

While the specific mechanisms and energy scales differ, the concept of a chain reaction in the mousetrap model provides a simplified analogy for understanding the basic principle of energy release and propagation in fission reactions.

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describe relative motion with an examples​

Answers

Answer:

The measurement of an object's motion with respect to any other object that is moving or stationary is called Relative Motion.

which stereo microphone technique works only from level differences produced by off-axis attenuation and not from difference in time delay

Answers

The stereo microphone technique that works only from level differences produced by off-axis attenuation is called Mid-Side (M-S) stereo recording.

Mid-Side (M-S) stereo recording technique utilizes two microphones, one of which is pointed directly at the sound source and the other pointing 90 degrees to the left or right. The result is two channels of audio which are then combined in the mixing process to create a full stereo image. The two signals have a 3 dB difference in level between them, with the off-axis microphone being the lower of the two. This level difference produces the stereo image and is the only factor used in M-S stereo recording. Time delays are not used in this technique, as the level differences are sufficient to create the stereo image.

M-S stereo recording has a number of benefits, such as being able to adjust the width of the stereo image in the mixing process, and allowing for mono compatibility. It is therefore a great choice for stereo recordings that need to be heard in both mono and stereo, such as live broadcasts or online streams.

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Use the vocabulary in the Word Bank to complete the following explanation.

Answers

Where’s the vocabulary?

i’m about to end my life over this class I have a 46.9% right now :) do not take physics. i repeat if you’re seeing this DO NOT EVER TAKE PHYSICS.

Answers

yeah i made that mistake last year lol

How is total magnification calculated?

Answers

Calculating total magnification involves multiplying the power of the objective and ocular lenses.

How is a microscope's magnification determined?

The microscope's magnification is relatively simple to determine. Just double the eyepiece's magnification by the objective lens's magnification. Nearly invariably, the barrel (objective) or top of a microscope's eyepieces and objectives are inscribed with the instrument's magnification (eyepiece).

In other words, the total magnification of a microscope is calculated by multiplying the objective lens's magnification by the optical lens' magnification.

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How far is the sun, alpha centauri A, Sirius B, Bernard's Star, Sirius A, and Proxima Centauri from the earth in light years

Answers

The distance of sun, alpha centauri A, Sirius B, Bernard's Star, Sirius A, and Proxima Centauri from the earth is 1.578 * \(10^{-5}\), 4.367, 8.611, 5.978, 8.611 and 4.264 light years.

The distance of the planet Earth from other celestial bodies are as mentioned below:

Sun = 1.578 * \(10^{-5}\) Light yearsAlpha Centauri A = 4.376 Light yearsSirius B = 8.611 Light yearsBernard's Star = 5.978 Light yearsSirius A = 8.611 Light yearsProxima Centauri = 4.264 Light years

A light year is measure of distance. It is distance covered by a light particle in a period of one year. Light travels at the speed of 3 * \(10^{8}\) m / s. So one light year will be equal to a distance of 9.46 trillion kilometers.

Therefore, the distance from Earth to

Sun = 1.578 * \(10^{-5}\) Light yearsAlpha Centauri A = 4.376 Light yearsSirius B = 8.611 Light yearsBernard's Star = 5.978 Light yearsSirius A = 8.611 Light yearsProxima Centauri = 4.264 Light years

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What is a vector?
A. A quantity that does not indicate a direction. B. The direction of a vector. C. A quantity with magnitude and a direction. D. A measurement of distance.

Answers

Answer:

C. A quantity with magnitude and a direction.

Explanation:

A vector can be defined as a quantity with magnitude and direction. Some examples of vector quantities are velocity, position, displacement, force, torque, acceleration.

For example, given the following data;

Time, t = 18.5secs

Final velocity = 78m/s

Initial velocity = 0

Substituting into the equation;

\(a = \frac{78 - 0}{18.5}\)

\(a = \frac{78}{18.5}\)

Acceleration, a = 4.22m/s²

Therefore, the acceleration of the object is 4.22m/s² due North.

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.

Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.

Mathematically, acceleration is given by the equation;

\(Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}\)

\(a = \frac{v - u}{t}\)

Where,

a is acceleration measured in \(ms^{-2}\)

v and u is final and initial velocity respectively, measured in \(ms^{-1}\)

t is time measured in seconds.

Answer:

C. A quantity with magnitude and a direction.

Explanation:

Vector Quantity

A physical Quantity, which has magnitude, direction and units But must follow the traingle law of vector addition

What is E equal to in relativity? ​

Answers

\( \huge \underline \mathtt \colorbox{cyan}{E=mc squared}\)

(E=mc^2)

Where:

m is mass

And c is a constant for speed of light

Answer:

One of the most famous and well-known equations in all of human history, E = mc^2, translates to "energy is equal to mass times the speed of light squared." In other words, wrote PBS Nova, energy (E) and mass (m) are interchangeable. They are, in fact, just different forms of the same thing.

Explanation:

this is right answer

Please help!!!!!!!!!!!!!!!!!!!!!

Please help!!!!!!!!!!!!!!!!!!!!!

Answers

Answer:

im gonna go with C

Explanation:

Calculate the wavelength (in nm) of visible light emitted by a hydrogen atom when its excited electron drops from n = 6 to n = 2.

Answers

After considering the given data we conclude that the wavelength of visible light emitted by a hydrogen atom when its excited electron drops from n = 6 to n = 2 is approximately 102.55 nm.

To evaluate the wavelength (in nm) of visible light emitted by a hydrogen atom when its excited electron drops from n = 6 to n = 2, we can apply the Rydberg formula:
\(1/\lambda = R(1/n_1^{2} - 1/n_2^{2} )\)
Here:
λ = wavelength of the emitted light
R = Rydberg constant \((1.097 *10^7 m^{-1} )\)
\(n_1\) and \(n_2\) = initial and final energy levels of the electron
Applying substitution of the given values, we get:
\(1/lambda = (1.097 * 10^7 m^{-1} )(1/6^{2} - 1/2^{2} )\)
Evaluating for λ, we get:
λ = 102.55 nm
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The red glow of a neon sign is due to the excitation of protons in the nuclei of neon atoms. True or false?.

Answers

The red glow of a neon sign is due to the excitation of protons in the nuclei of neon atoms is true statement.

Neon is a noble or rare gas that belongs to the periodic table's group 0/8 and period 2 elements. Since there are only two electron shells in its electron orbit and it has an atomic number of 10, it has an 8-valence electron configuration.

The production of a crimson glow of neon, which indicates that protons have left a neon gas's nucleus, occurs when an extremely high voltage is technically given to any electrode that ionises a tube holding neon gas. In conclusion, it may be correctly inferred that a red glow forms when a neon gas is subjected to a high potential of volts.

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A toy boat moves horizontally in a pond. The horizontal position of the boat in meters over time is shown below. What is the displacement of the boat between 0s and 16s? What is the distance traveled by the boat between 0s and 16s?

Answers

Answer:

displacement=-21

distance=39

Explanation:

Put yourself in usual bolts running shoes-how would you feel about breaking your own world record ?

Answers

Answer:

Honestly if I broke MY OWN record, I would be shocked.

Explanation:

Breaking your own record means either nobody has succeeded your record therefor its still YOUR record, or nobody had thought to even try to break your record. It would be great to push yourself to further limits and break a record you once made. You should be very proud if you did, because not only did no one break your record yet, you broke it yourself.

If putting yourself in Usain Bolt running shoes, when you break your own record, it either means that no one has ever beaten it.  

What is the world record by Usain Bolt?

100 m in 9.58 seconds is the world record by Usain Bolt at the 2009 IAAF World Championships,

They predict that times will begin to plateau and that it will get harder and harder to beat the record.

Although the sub-nine seconds are on, they think: "It's safe to say that someone will break the nine-second barrier – not necessarily in our lifetime, but it will happen one day."

It would be fantastic to challenge yourself and surpass a previous record.

Therefore, if you did, you should be extremely proud because not only has no one else yet broken your record, but you also accomplished it yourself.

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PLEASE HELP ASAP ILL GIVE U BRAINLIEST

An object is pulled to the left by a force of 100 N and to the right by a force of
80N. What is the net force acting on the object?

Answers

Answer: 20 N

Explanation: Net force is the sum of all forces acting on an object. For example, in a tag of war, when one team is pulling the tag with a force of 100 N and the other with 80 N, the net force would be 20 N at the direction of the first team (100 N - 80 N = 20 N).

PLEASE ANSWER ASAP!
How much work is done on a bookshelf being pulled 5.00 m at an angle
of 37.0° from the horizontal? The magnitude of the component of the
force that does the work is 43.0 N.

Answers

Answer:

Explanation:

Since work = magnitude of the force times the displacement, then

W = 43.0(5.00) so

W = 215 N*m

To solve this, we must be knowing each and every concept related to fundamental force. Therefore,  215 Nm is the work done on a bookshelf being pulled 5.00 m at an angle of 37.0° from the horizontal.

What is fundamental force?

Nature is governed by four fundamental or universal forces. All stuff in the universe would disintegrate in the absence of these forces. Any pull or push that causes an item to change its physical condition is referred to as force (in terms of motion or deformity).

Mathematically, the formula for work can be given as

work = force × displacement× cos(Θ)

W = F × D × cos(Θ)

force= 43.0 N

Θ=37.0°

displacement=5.00 m

substituting all the given values in the above equation, we get

W =  43.0  × 5.00  × cos(37.0°)

W = 215 Nm

Therefore,  215 Nm is the work done on a bookshelf being pulled 5.00 m at an angle of 37.0° from the horizontal.

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A cylindrical beaker of mass 50kg, cross sectional area 25cm3 and height 10cm is filled with oil of density 0.8g/cm3.(i):what is the total mass. (ii) A piece of aluminum of mass 66g and density 2.2g/cm3, is lowered carefully into the beaker. What volume of oil overflows?. (iii) What is the final mass of the beaker and its contents after the outside has been wipe to remove overflow liquid?​

Answers

Answer:

(i) The volume of the cylindrical beaker is given by:

V = A x h = (25 cm^2) x (10 cm) = 250 cm^3

The mass of the oil in the beaker is given by:

m_oil = density x volume = (0.8 g/cm^3) x (250 cm^3) = 200 g

The total mass of the beaker and oil is therefore:

m_total = m_beaker + m_oil = 50 kg + 0.2 kg = 50.2 kg

(ii) The volume of the aluminum is given by:

V_aluminum = m_aluminum / density = 66 g / (2.2 g/cm^3) = 30 cm^3

When the aluminum is lowered into the beaker, it displaces an equal volume of oil. Therefore, the volume of oil that overflows is 30 cm^3.

(iii) The final mass of the beaker and its contents is the sum of the mass of the beaker, the mass of the oil remaining in the beaker, and the mass of the aluminum:

m_final = m_beaker + m_oil + m_aluminum = 50 kg + 0.17 kg + 0.066 kg = 50.24 kg

To calculate the mass of the remaining oil, we need to subtract the volume of aluminum from the volume of the beaker and multiply by the density of the oil:

V_remaining_oil = (A x h) - V_aluminum = (25 cm^2 x 10 cm) - 30 cm^3 = 220 cm^3

m_remaining_oil = density x V_remaining_oil = 0.8 g/cm^3 x 220 cm^3 = 176 g

Therefore, the final mass of the beaker and its contents after the overflow liquid has been wiped off is 50.24 kg, and there is 176 g of oil remaining in the beaker

A beaker containing ice and water is placed on a warm hotplate. What type of change would you expect
the ice to undergo​

Answers

Answer:

Solid to liquid

Explanation:

Ice cubes are solid, adding heat to the beaker will melt the ice cubes to water.

A bicycle has a momentum of 25.00 kg·m/s and a velocity of 2.5 m/s. What is the bicycle’smass?

Answers

Answer:

10 kg

Explanation:

p=ma

25=2.5m

m=25/2.5

m=10 kg

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During a baseball game, a baseball is struck at ground level by a batter. The ball leaves the baseball bat with an initial speed v0 = 38 m/s at an angle θ = 34° above horizontal. Let the origin of the Cartesian coordinate system be the ball's position the instant it leaves the bat. Air resistance may be ignored throughout this problem.

Answers

Answer:

The horizontal distance is 136.6 m.

Explanation:

Given that,

Initial speed = 38 m/s

Angle = 34°

Suppose, Calculate the horizontal distance \(x_{max}\) in meters the ball has traveled when it returns to ground level.

We need to calculate the horizontal distance

Using formula of range

\(R=\dfrac{v_{0}^2\sin(2\theta)}{g}\)

Where, v= speed

g = acceleration due to gravity

Put the value into the formula

\(R=\dfrac{(38)^2\sin(2\times34)}{9.8}\)

\(R=136.6\ m\)

Hence, The horizontal distance is 136.6 m.

a scaffold of mass 60 kg and length 5.0 m is supported in a horizontal position by a vertical cable at each end. a window washer of mass 80 kg stands at a point 1.5 m from one end. what is the tension in (a) the nearer cable and (b) the farther cable?

Answers

(a) The tension in the nearer cable is 941 N, and (b) the tension in the farther cable is 1373 N.

We need to find the tension in both the nearer and farther cables supporting the scaffold with a window washer on it.

a) To find the tension in the nearer cable, we must first calculate the total torque acting on the system, keeping in mind that the torque must be zero for the system to be in equilibrium. The torque contributions are:

1. The torque due to the window washer's weight (80 kg * 9.81 m/s²) acting at a distance of 1.5 m from the nearer cable.


2. The torque due to the scaffold's weight (60 kg * 9.81 m/s²) acting at the midpoint of the scaffold, which is 2.5 m from each cable.

Now, we can set up the torque equation:

T_near * 5.0 m = (80 kg * 9.81 m/s² * 1.5 m) + (60 kg * 9.81 m/s² * 2.5 m)

Solve for T_near:

T_near = ((80 kg * 9.81 m/s² * 1.5 m) + (60 kg * 9.81 m/s² * 2.5 m)) / 5.0 m
T_near ≈ 941 N

b) To find the tension in the farther cable, we can use the fact that the sum of the tensions in both cables must equal the total weight of the system (scaffold + window washer):

T_far + T_near = (80 kg + 60 kg) * 9.81 m/s²

Solve for T_far:

T_far = (140 kg * 9.81 m/s²) - T_near
T_far ≈ 1373 N

Therefore,  the tension in the nearer cable (a) is approximately 941 N, and the tension in the farther cable (b) is approximately 1373 N.

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What is the change in internal energy if 30 J of heat are released from a
system and the system does 50 J of work on its surroundings?
Use AU = Q-W.
A. 80 J
B. -80 J
C. 20 J
D. -20 J

Answers

I think it would be B- -80 J

Answer:

Explanation:

Given:

Q =  30J   (The system did not prepare energy, but allocated)

W =  + 50 J  (System operation)

__________________

ΔU - ? (Change in internal energy)

ΔU = Q - W =  30 - (50)  = - 20J

Zorn and Porsha are ice skating. Porsha has a mass of 60 kg, and Zorn has a mass of 40 kg. As they face each
other, Porsha pushes off Zorn with a force of 168 N. Assume the friction between the skaters and the ice is
negligible.

Answers

Assuming the friction between the skaters and the ice is  negligible, the magnitude of Porsha's acceleration is 2.8m/s².

Missing part of the question: determine the magnitude of Porsha's acceleration.

Given the data in the question;

Mass of Porsha; \(m_{porsha} = 60kg\)Mass of Zorn; \(m_{zorn} = 40kg\)Force of Porsha push; \(F_{porsha} = 168N\)

Magnitude of Porsha's acceleration; \(a = \ ?\)

To determine the magnitude of Porsha's acceleration, we use Newton's second laws of motion:

\(F = m*a\)

Where m is the mass of the object and a is the acceleration.

We substitute the mass of Porsha and the force he used into the equation

\(168N = 60kg * a\\\\a = \frac{168kg.m/s^2}{60kg}\\\\a = 2.8m/s^2\)

Therefore, assuming the friction between the skaters and the ice is  negligible, the magnitude of Porsha's acceleration is 2.8m/s².

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Can someone help me please

Can someone help me please

Answers

3200m
80m/s * 40s = 3200m
seconds cancel out

HELP PLEASE OMG !!

(VIEW PHOTO)


ACCELERATION CHART
Objects
Acceleration
Mass
Force
m/s²
kg
N
1
1
1
1
2
2
10
20
3
10
10
20
20
5
0.5
20
10
6
2
50
?
5. Based on the chart, if the mass of an object remains the same and the force moving it is
doubled, what happens to the acceleration?
A. the acceleration is doubled
B. the acceleration decreases
C. the acceleration remains the same
D. the acceleration is reduced to zero

HELP PLEASE OMG !!(VIEW PHOTO)ACCELERATION CHARTObjectsAccelerationMassForcem/skgN111122102031010202050.520106250?5.

Answers

Answer:

A

Explanation:

Look at the second and third lines

the mass stays at 10   but the   force  is doubled   from line 3 to line 2

   then look the acceleration heading....the acceleration is doubled from line 3 to line 2


30.) We observe motion by using a *blank* of *blank*. ​

Answers

Answer:

Point of Reference

Explanation:

A coin is dropped off of a building landing on its side. It hits with a pressure of 400/2 It hits with a force of 0.1 Calculate the area of the coin?

Answers

Complete Question:

A coin is dropped off of a building landing on its side. It hits with a pressure of 400 N/m². It hits with a force of 0.1N. Calculate the area of the coin?

Answer:

Area = 0.00025 m²

Explanation:

Given the following data;

Pressure = 400N/m²

Force = 0.1N

To find the area of the coin;

Pressure = Force/area

Area = Force/pressure

Substituting into the equation, we have;

Area = 0.1/400

Area = 0.00025 m²

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