The sum of 3 times a number and 16 is more than 25. Write an inequality and solve it.

Answer:

true

Step-by-step explanation:

Answer:

im doing the test rn and i believe the other person is correct :)

Step-by-step explanation:

Answer:

5.6

Step-by-step explanation:

11*7=77

11.8*7= 82.6

82.6-77=5.6

a. 1/4 of the accidents in May were serious.

b. 1/3 of the accidents in June were serious.

c. June had a higher proportion of serious accidents than May.

A fraction is represented as a numerical indication of a part of a whole that represents a rational numeral.

a. To find the fraction of accidents in May that were serious, we divide the number of serious accidents by the total number of accidents:

Fraction of serious accidents in May = 3/12

Simplifying the fraction in the simplest form as:

3/12 = (3 ÷ 3) / (12 ÷ 3) = 1/4

Therefore, 1/4 of the accidents in May were serious.

b. To find the proportion of accidents in June that were serious, we divide the number of serious accidents by the total number of accidents:

The proportion of serious accidents in June = 5/15

Simplifying the fraction in the simplest form as:

5/15 = (5 ÷ 5) / (15 ÷ 5) = 1/3

Therefore, 1/3 of the accidents in June were serious.

c. The proportion of serious accidents in May and June, we can compare the fractions we obtained in parts (a) and (b).

1/4 is less than 1/3, which means that June had a higher proportion of serious accidents than May.

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Given :

Distance of bird from sea level, \(d_1 = 3\dfrac{5}{8} = \dfrac{29}{8}\ feet\) .

Distance between fish and sea level, \(d_2=5\dfrac{1}{3}=\dfrac{16}{3}\ feet\) .

To Find :

Distance between bird and fish.

Solution :

Distance between bird and fish is given by :

\(D=d_1+d_2\\\\D = \dfrac{29}{8}+\dfrac{16}{3}\\\\D=8.958\ feet\)

Therefore, distance between bird and fish is 8.958 feet.

Hence, this is the required solution.

Answer:

C

Step-by-step explanation:

EDGE2021

The value should be used for n, the number of periods over which the loan is repaid in 60 periods.

The value of the monthly payment is given by;

P = PV × i / 1-(1+i)⁻ⁿ

Where,

PV is the present value or the amount of the loan.

i is the interest rate per period and is calculated by dividing the yearly percent rate by 100 and by the number of periods in a year.

n is the total number of periods and is calculated as the product of the number of periods in a year times the number of years.

Therefore,

The value should be used for n, the number of periods over which the loan is repaid;

n = 6 years × 12 months/year = 60 months = 60 periods.

Hence, The value should be used for n, the number of periods over which the loan is repaid in 60 periods.

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The Gauss' divergence theorem states that the flux of a vector field through a closed surface is equal to the triple integral of the divergence of the vector field over the region enclosed by the surface. By calculating the flux of the vector field E(x, y, z) = xi + 12yj + 3zk through the surface of the given box B = {(x, y, z) | 1 ≤ x ≤ 3, 0 ≤ y ≤ 1, 3 ≤ z ≤ 5}, we can verify the theorem.

To apply Gauss' divergence theorem, we need to calculate the flux of the vector field E through the closed surface of the box B and the triple integral of the divergence of E over the region enclosed by the surface.

First, we calculate the flux of E through the surface of the box B by evaluating the surface integral of the dot product between E and the outward unit normal vector of each face of the box. This involves calculating the flux through the six individual faces of the box and summing them.

Next, we compute the triple integral of the divergence of E over the region enclosed by the surface. The divergence of E is found by taking the partial derivatives of each component of E with respect to its corresponding variable and summing them.

If the flux of E through the surface matches the value obtained from the triple integral of the divergence of E, then Gauss' divergence theorem is verified for the given vector field and surface.

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Answer: 360

Step-by-step explanation:

done

The dissociation curve is a graphical representation of the relationship between the fractional saturation of hemoglobin (Y-axis) and the partial pressure of oxygen (X-axis) under specific conditions. It provides important information about the binding and release of oxygen by hemoglobin.

The dissociation curve for hemoglobin exhibits a sigmoidal (S-shaped) shape. At low partial pressures of oxygen, such as in tissues, hemoglobin has a low affinity for oxygen and only binds a small amount. As the partial pressure of oxygen increases, hemoglobin's affinity for oxygen increases, resulting in a rapid increase in the binding of oxygen molecules. However, once the hemoglobin becomes nearly saturated with oxygen, the curve levels off, indicating that further increases in partial pressure have minimal effects on oxygen binding.

To calculate the fractional saturation of hemoglobin at a given partial pressure of oxygen, you can use the Hill equation:

Y = [O2]^n / ([O2]^n + P50^n)

Where:

Y is the fractional saturation of hemoglobin,

[O2] is the partial pressure of oxygen,

P50 is the partial pressure of oxygen at which hemoglobin is 50% saturated,

n is the Hill coefficient, which represents the cooperativity of oxygen binding.

To determine the P50 value experimentally, the partial pressure of oxygen at which hemoglobin is 50% saturated, you can plot the dissociation curve and identify the point where the curve reaches 50% saturation.

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Answer:

-1

Step-by-step explanation:

\(x + 3xy \\ x = 2 \\ y = - \frac{1}{2} \)

Substitute the values into the equation

\(2 + 3(2)( - \frac{1}{2} ) \\ 2 + 6( - \frac{1}{2} ) \\ 2 - 3 \\ = - 1\)

Answer:

12

Step-by-step explanation:

Type Into Calculator:

SAT-EDIT-TYPE IN X VALUES AND Y VALUES (FROM ORDERED PAIR)-STAT-CALC-4-ENTER

The derivative dy/dx of the equation ysin(x^2) = xsin(y^2) is given by (sin(y^2) - ycos(x^2)2x) / (sin(x^2) - 2yxcos(y^2)).

In the given equation, y and x are both variables, and y is implicitly defined as a function of x. To find dy/dx, we differentiate each term using the chain rule and product rule as necessary.

Differentiating the left-hand side of the equation, we apply the product rule to ysin(x^2). The derivative of ysin(x^2) with respect to x is dy/dxsin(x^2) + ycos(x^2)*2x.

Differentiating the right-hand side of the equation, we apply the product rule to xsin(y^2). The derivative of xsin(y^2) with respect to x is sin(y^2) + x*cos(y^2)2ydy/dx.

Now we have two expression for the derivative of the left and right sides of the equation. To isolate dy/dx, we can rearrange the terms and solve for it.

Taking the derivative of ysin(x^2) = xsin(y^2) with respect to x using implicit differentiation yields:
dy/dxsin(x^2) + ycos(x^2)2x = sin(y^2) + xcos(y^2)2ydy/dx.

By rearranging the terms, we can solve for dy/dx:
dy/dx * (sin(x^2) - 2yxcos(y^2)) = sin(y^2) - y*cos(x^2)*2x.

Finally, we can obtain the value of dy/dx by dividing both sides by (sin(x^2) - 2yxcos(y^2)):
dy/dx = (sin(y^2) - ycos(x^2)2x) / (sin(x^2) - 2yxcos(y^2)).

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Answer:

\(\large \boxed{\sf \ \ 70\% \ \ }\)

Step-by-step explanation:

Hello,

We assume that the year is 52 weeks, and we note r the interest rate we are looking for. The rate is expressed in percent and is annually, meaning that the investment is, after the first week :

   \(1000\cdot (1+\dfrac{r\%}{52})=1000\cdot (1+\dfrac{r}{5200})\)

For the second week

   \(1000\cdot (1+\dfrac{r}{5200})^2\)

After 52 weeks

   \(1000\cdot (1+\dfrac{r}{5200})^{52}\)

and we want to be equal to 2000 so we need to solve:

\(1000\cdot (1+\dfrac{r}{5200})^{52}=2000\\\\\text{*** divide by 1000 both sides ***}\\\\(1+\dfrac{r}{5200})^{52}=\dfrac{2000}{1000}=2\\\\\text{*** take the ln **}\\\\52\cdot ln(1+\dfrac{r}{5200})=ln(2)\\\\\text{*** divide by 52 ***}\\\\ln(1+\dfrac{r}{5200})=\dfrac{ln(2)}{52}\\\\\text{*** take the exp ***}\\\\\displaystyle 1+\dfrac{r}{5200}=exp(\dfrac{ln(2)}{52})=2^{(\dfrac{1}{52})}=\sqrt[52]{2}\\\\r = 5200\cdot (\sqrt[52]{2}-1)=69.77875...\)

Rounded to the nearest percent, the solution is 70%.

If you want to double your capital in one year with weekly compounding you need an interest rate of 70% !!

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

Answer:

4%

Step-by-step explanation:

The sum of the first 20 terms of the arithmetic sequence is 1220

The number of terms (n) = 20

The first term (a) = 4

The common difference (d)= 10-4= 6

The formula for calculating the number of terms in an arithmetic sequence is

(a + L)*n/2

The first step is to calculate the value of L

L = a + (n - 1)*d

L= 4 + (20 - 1)6

L= 4 + 19(6)

L= 4 + 114

L= 118

The sum of the first 20 terms is

(a + L)*n/2

(4 + 118) × 20/2

= 122 × 10

= 1220

Hence the sum of the first 20 terms of the arithmetic sequence is 1220

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Answer: 90 mm cubed

Step-by-step explanation:

Formula = (L*W*H) / 2

5 * 12 * 3 = 60 * 3 = 180

180 / 2 = 90

Answer:

e

Step-by-step explanation:

2x + 4 = 8

2x = 8 - 4

2x = 4

divide both sides by 2

x = 2 ( x is less than or equal to 2 )

The line is supposed to be like this X<-----------------------•2

Answer:

y^ -2

Step-by-step explanation:

We know that a^b^c = a^(b*c)

(y^-1/2)^4

y^(-1/2*4)

y^ -2

Answer:

Step-by-step explanation:

Answer:

1

Step-by-step explanation:

17 + (-8) + (-8) = 17 + (-16)

                      = 1

If two numbers have same sign, then add and put the sign.

So, add (-8)and (-8), the result will have the sign (-).  -16

If two numbers have different sign, subtract and the result will have the sign of the bigger number.

17 and (-16) have different sign and the bigger number sign is +

So, the result is 1

Easy :PP

1

-8 + -8

=

-16

-16 + 17

=

1

When x = 11, the value of y is approximately 8.276. We are given that the relationship between x and y is given by \(y = Ax^n\)where A and n are constants.

We are also given the values of A and n:

\(A = e^0.5\)

n = 3/8

We can substitute these values into the equation to get:

\(y = e^0.5 x^(3/8)\)

Now, we are asked to find the value of y when x = 11. To do this, we substitute x = 11 into the equation:

\(y = e^0.5 x^(3/8)\)

\(y = e^0.5 (11)^(3/8)\)

We can use a calculator to evaluate this

First, we evaluate the exponent (3/8) using the exponent rules:

\((11)^(3/8) = (11^(1/8))^3 = 1.706\)

Next, we substitute this value back into the equation:

\(y = e^0.5 x^(3/8)\)

\(y = e^0.5 (11)^(3/8)\)

\(y = e^0.5 (1.706)\)

Using a calculator, we can evaluate this expression to get:

y ≈ 8.276

Therefore, when x = 11, the value of y is approximately 8.276.

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The given sentences expressed in algebraic expressions are:

1. "sum of 6 and t" is represented as: 6 + t

2. "product of s and 12" is represented as: 12s

3. "difference of 6 from 10" is represented as: 10 - 6 = 4

4. "quotient of 6 divided by t" is represented as: 6/t

5. "17 less than 20" is represented as: 20 - 17 = 3

6. 2s + s

7. 10 - r

8. 4s + 7x

9. (17 - 12)/2 = 5/2

10. (2)(x - 10)

11. (7)(2/2) = 7

12. (8)(6) - x = 48 - x

Thus, the following sentences given can be expressed as follows:

1. "sum of 6 and t" is represented as: 6 + t

2. "product of s and 12" is represented as: 12s

3. "difference of 6 from 10" is represented as: 10 - 6 = 4

4. "quotient of 6 divided by t" is represented as: 6/t

5. "17 less than 20" is represented as: 20 - 17 = 3

6. 2s + s

7. 10 - r

8. 4s + 7x

9. (17 - 12)/2 = 5/2

10. (2)(x - 10)

11. (7)(2/2) = 7

12. (8)(6) - x = 48 - x

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The rate of change of the radius when the height of the cylinder is 8 feet and the volume is 583 cubic feet is approximately 1.854 feet per second.

Suppose that the radius of considered right circular cylinder be 'r' units.

And let its height be 'h' units.

Then, its volume is given as;

\(V = \pi r^2 h \: \rm unit^3\)

Right circular cylinder is the cylinder in which the line joining center of top circle of the cylinder to the center of the base circle of the cylinder is perpendicular to the surface of its base, and to the top.

We are given that;

dh/dt = -4 ft/s and dV/dt = 476 ft^3/s. We need to find dr/dt when h = 8 ft and V = 583 ft^3.

Now,

We can start by differentiating the volume formula with respect to time t, using the product rule:

dV/dt = d/dt (πr^2h)

= πh d/dt (r^2) + πr^2 d/dt (h)

= 2πrh (dr/dt) + πr^2 (dh/dt)

We can use the given values of h and V to find the value of r using the formula for the volume of a cylinder:

V = πr^2h

583 = πr^2(8)

r^2 = 583/(8π)

r ≈ 3.031

Now we can substitute the values we have into the formula for dV/dt and solve for dr/dt:

476 = 2π(8)(3.031)(dr/dt) + π(3.031)^2(-4)

dr/dt = (476 + 36π(3.031)^2) / (16π(3.031))

dr/dt ≈ 1.854

Therefore, by the given volume the answer will be 1.854 feet per second.

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The 99% confidence interval for the population proportion p is 0.833< p < 0.863.

Given that,

x = 3059

n = 3604

Point estimate = sample proportion = x / n =3059/3604=0.848

\(1 - \hat p\)  = \(1-0.848 =0.152\)

At 99% confidence level the z is ,

\(\alpha\) = 1 - 99% = 1 - 0.99 = 0.01

\(\alpha\)/ 2 = 0.01 / 2 = 0.005

\(Z\alpha\)/2 = \(Z*0.005\) = 2.576  (  Using z table   )

Margin of error = E = \(Z\alpha / 2 * (\sqrt(((\hat p * (1 - \hat p)) / n)\)

                              = \(2.576* (\sqrt((0.848*0.152) /3604 )\)

                               =0.015

A 99% confidence interval for population proportion p is ,

\(\hat p - E < p < \hat p + E\)

0.848-0.015< p <0.848+ 0.015

0.833< p < 0.863

Hence, the 99% confidence interval for the population proportion p is 0.833< p < 0.863.

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The given statement “when adjusting an estimate for time and location, the adjustment for location must be made first” is true.

Location, in the field of estimating, relates to the geographic location where the project will be built. The estimation of construction activities is influenced by location-based factors such as labor availability, productivity, and costs, as well as material accessibility, cost, and delivery.

When estimating projects in various geographical regions, location-based estimation adjustments are required to account for these variations. It is crucial to adjust the estimates since it aids in the determination of an accurate estimate of the project's real costs. The cost adjustment is necessary due to differences in productivity, labor costs, and availability, and other factors that vary by location.

Hence, the statement when adjusting an estimate for time and location, the adjustment for location must be made first is true.

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Answer:

10 months

Step-by-step explanation:

30x = 22x + 80

8x = 80

x = 10