the temperature at midnight is -3 degrees the weatherman predicts the temperature to be 25 degrees warmer by noon the next day.find the temperature at noon

Answer: The measure of ∠RTS is 102°. The answer is (d).

Step-by-step explanation:

We know that the sum of the angles in a quadrilateral is 360°. Therefore, we have:

∠R + ∠T + ∠Q + ∠S = 360°

Since RP and QS are diameters, we have ∠R = ∠P = 90° and ∠Q = ∠S = 90°. Substituting these values, we get:

90° + ∠T + 90° + ∠S = 360°

Simplifying the equation, we get:

∠T + ∠S = 180°

Now we use the fact that the measure of ∠RTQ is 12° less than the measure of ∠RTS, which can be written as:

∠RTQ = ∠RTS - 12°

Substituting this into the equation above, we get:

∠T + ∠RTS - 12° = 180°

Simplifying, we get:

∠T + ∠RTS = 192°

We can now solve for ∠RTS by substituting ∠T + ∠S = 180° into the equation above:

∠RTS = 192° - ∠T

Substituting this into the equation for ∠RTQ above, we get:

∠RTQ = (192° - ∠T) - 12° = 180° - ∠T

Since the sum of the angles in triangle RTQ is 180°, we have:

∠RTQ + ∠T + ∠R = 180°

Substituting the values for ∠R and ∠RTQ, we get:

90° + ∠T + (180° - ∠T) = 180°

Simplifying, we get:

∠T = 90°

Substituting this value into the equation for ∠RTS above, we get:

∠RTS = 192° - ∠T = 102°

Therefore, the measure of ∠RTS is 102°. The answer is (d).

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The "n" in the formula for calculating degrees of freedom for a correlation coefficient represents the sample size. The correct option is a.

Explanation: In statistics, the correlation coefficient measures the strength and direction of the linear relationship between two variables. When calculating the degrees of freedom for a correlation coefficient, the "n" represents the sample size. Degrees of freedom (df) refers to the number of independent observations in a statistical analysis. It represents the number of values that are free to vary after certain restrictions or conditions have been imposed.

In the context of correlation, the formula for degrees of freedom is given by (n - 2), where "n" is the sample size. The subtraction of 2 is because the calculation of the correlation coefficient involves estimating the parameters of the line that best fits the data, which requires two degrees of freedom. Subtracting 2 ensures that the degrees of freedom accurately reflect the number of independent observations available for analysis.

Therefore, the correct answer is (a) sample size. The larger the sample size, the greater the degrees of freedom, which generally improves the reliability and precision of the correlation coefficient estimate.

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Answer:

3      5  =  16

 3        =  3      16

       6  =   16

       6   = -4

        x =  -4/6

each line has the number of boxes to be filled

Answer:

Each person should  .875 of the sandwich.

Step-by-step explanation:

Answer:

im Nevaeh but everyone calls me vaeh and im 14 in 9th grade

a. The equation of circle  in x and y is given by: (y - 3)² + x² = 100

b. The curve is generated anticlockwise starting at (10,3) and ending at (-10,3).

a. We are given,

x = 10cos(t)  a

nd

y = 3 + 10sin(t)

To eliminate the parameter to obtain an equation in x and y.

Thus we know,

cos(t) = x/10

and

sin(t) = (y-3)/10

Now we can express

sin(t)² + cos(t)² = 1 as

(y-3)²/100 + x²/100 = 1

Thus the equation in x and y is given by:

(y - 3)² + x² = 100

b. The given equations are

x = 10cost,

y = 3 + 10sint;

0 ≤ t ≤ 2π.

From (a) we know that

(y - 3)² + x² = 100,

which is the equation of circle with center (0, 3) and radius 10.

So the curve is a circle, with center at (0, 3) and radius 10. It is oriented in the positive sense.

Thus, the curve is generated anticlockwise starting at (10,3) and ending at (-10,3).

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Answer:

It's all of the above, since natural numbers are counting numbers, and whole numbers are numbers without a decimal or fraction. 20 is also an integer since integers are numbers that do not contain a fraction or decimal, an integer and whole number are the same.

Step-by-step explanation:

This exercise is about creating two-dimensional shapes. The resulting shape is a quadrilateral - Square. See the attached for the lines drawn.

What was noticed about the two lines drawn?

When two lines intersect with one another such that they create a right angle, perpendicularity has occurred and both lines are said to be perpendicular to one another.

Hence:

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Overloading in object-oriented programming enables class methods with different parameter lists and return types to perform distinct tasks based on input parameters, improving readability and reducing code complexity.

In the object-oriented model, if class methods have the same name but different parameter lists and/or return types, they are said to be Overloaded.

In object-oriented programming (OOP), overloading refers to the ability of a function or method to be used for a variety of purposes that share the same name but have different input parameters (a parameter is a variable that is used in a method to refer to the data that is passed to it).In object-oriented programming, method overloading allows developers to use the same method name to perform distinct tasks based on the input parameters. The output of the method is determined by the input parameters passed. This enhances the readability of the program and makes it easier to use because it minimizes the number of method names used for distinct tasks.The overloaded method allows the same class method to be used to execute a variety of operations.

It's a great feature for developers because it lets them write fewer lines of code. Overloaded methods are commonly employed when the same task can be completed in multiple ways based on the input parameters.

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Answer:

72

Step-by-step explanation:

The probability that the average number of hours of overtime worked last month by a random sample of 140 employees in the city exceeds 20 hours is approximately 0.9564, or 95.64%.

To find the probability that the average number of hours of overtime worked by a random sample of 140 employees exceeds 20 hours, we can use the Central Limit Theorem (CLT). The CLT states that for a large enough sample size, the sampling distribution of the sample mean approaches a normal distribution, regardless of the shape of the population distribution.

Given that the population mean is 18.9 hours and the population standard deviation is 7.8 hours, we can calculate the standard error of the mean using the formula: standard error = population standard deviation / sqrt(sample size).

For this problem, the sample size is 140, so the standard error is 7.8 / sqrt(140) ≈ 0.659.

To calculate the probability, we need to standardize the sample mean using the z-score formula: z = (sample mean - population mean) / standard error.

In this case, the sample mean is 20 hours, the population mean is 18.9 hours, and the standard error is 0.659. Plugging these values into the formula, we get z = (20 - 18.9) / 0.659 ≈ 1.71.

Now, we can use a standard normal distribution table or calculator to find the probability associated with a z-score of 1.71. Looking up this value in the table, we find that the probability is approximately 0.9564.

Therefore, the probability that the average number of hours of overtime worked last month by a random sample of 140 employees in the city exceeds 20 hours is approximately 0.9564, or 95.64%.

Here's a sketch to visualize the calculation:

                  |

                  |

                  |

                  |       **

                  |      *  *

                  |     *    *

                  |    *      *

                  |   *        *

                  |  *          *

                  | *            *

-------------------|--------------------------

      18.9        |       20

The area under the curve to the right of 20 represents the probability we're interested in, which is approximately 0.9564 or 95.64%.

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Answer:

Exponential decay

Step-by-step explanation:

Because the values are exponentially decreasing.

The solution is, 1) f+g =3x^3+x^2+2x-9 and, 2)  f+g = x^2-6x +2√(x-2)+17

Addition is a way of combining things and counting them together as one large group. ... Addition in math is a process of combining two or more numbers.

here, we have,

given that,

            g(x) = x^2+8x-9

so, f+g

=3x^3+x^2+2x-9

and,

             g(x)=2√(x-2)+10

so, f+g

= x^2-6x +2√(x-2)+17

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The old price at which dora bought 20 liters of petrol is $0.30 per liter.

Given, dora bought 20 liters of petrol at old price.

The cost of petrol rises by 2 cents later.

Then she bought 10 liters at the new price.

Altogether the petrol costs = $9.20

old price for 1 liter = ?

let the old price for 1 liter of petrol be x.

Based on the conditions , we formulate:

20x+10(x+2)=920

20x+10x+20=920

30x+20=920

30x=920-20

30x=900

x=900/30

x=30

x=$0.30

hence the old price of the petrol is $0.30 per liter.

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x=224/8

x=25+3=28

So: 28

Answer:

12 times 1

Step-by-step explanation:

The segment lengths for this triangle are given as follows:

Similar triangles are triangles that share these two features given as follows:

There are three triangles in this problem, all of which are similar.

The length of segment PX can be obtained with triangles PQR and PXY, as follows:

PX/30 = 10/40

PX/30 = 1/4

4PX = 30

PX = 7.5.

The length of segment XQ is found applying the segment addition postulate, as follows:

PQ + XQ = 30

7.5 + XQ = 30

XQ = 22.5.

The length of segment XY can also be obtained with the similarity of triangles PXY and PQR, as follows:

XY/36 = 10/40

XY/36 = 1/4

4XY = 36

XY = 9.

The length of segment ZW is obtained with the similarity of triangles PZW and PQR, as follows:

ZW/36 = 24/40

ZW/36 = 0.6.

ZW = 36 x 0.6

ZW = 21.6.

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The domain of g(x) is all real numbers, and the range is (61, ∞) and the range is (61, ∞).

The domain of a function is the set of all possible input values for which the function is defined, while the range is the set of all possible output values.

For the given function g(x) = -1/4 (x−17)² + 61, the domain is all real numbers since there are no restrictions on the input values.

To find the range, we can use the fact that the vertex of the parabola is at (17, 61) and the coefficient of the squared term is negative, indicating a downward opening parabola.

Thus, the maximum value of the function occurs at the vertex and is 61, which is also the minimum possible value. Therefore, the range is (61, ∞).

In summary, the domain of g(x) is all real numbers, and the range is (61, ∞).

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9514 1404 393

Answer:

  (a) 6² +3² +1² +1² = 47

  (b) 5² +4² +2² +1² +1² = 47

  (c) 3³ +4² +2² = 47

Step-by-step explanation:

It can work reasonably well to start with the largest square less than the target number, repeating that approach for the remaining differences. When more squares than necessary are asked for, then the first square chosen may need to be the square of a number 1 less than the largest possible.

The approach where a cube is required can work the same way.

(a) floor(√47) = 6; floor(√(47 -6^2)) = 3; floor(√(47 -45)) = 1; floor(√(47-46)) = 1

__

(b) floor(√47 -1) = 5; floor(√(47-25)) = 4; ...

__

(c) floor(∛47) = 3; floor(√(47 -27)) = 4; floor(√(47 -43)) = 2

Answer:

  (c)  (1, 3)

Step-by-step explanation:

The solution to the system of equations shown on the graph is the point where the lines intersect.

__

The coordinates of the point of where the lines cross are (1, 3).

The solution to the system of equations is (x, y) = (1, 3).

The reduced cost matrix for travelling salesperson problem in the given instance is shown below. The Travelling Salesperson Problem (TSP) is a classical combinatorial optimization issue that belongs to the category of NP-Hard problems.

This problem can be resolved using a branch and bound algorithm or by using dynamic programming.The reduced cost matrix for the given travelling salesperson problem instance The computation of the reduced cost matrix for travelling salesperson problem involves two steps: Identify the smallest element of each row and subtract the value from all the values in the row.

Identify the smallest element of each column and subtract the value from all the values in the column.In the given instance, the smallest element of each row is highlighted in bold. Therefore, after performing Step 1 the matrix becomes the matrix becomes Hence, the reduced cost matrix for the travelling salesperson problem is obtained.

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Probability that a teacher prefer projector & is female candidate is =

Total Female prefer whiteboard/Total people = 28/75 = 0.373

Given that the information below:

Male people prefer projector - 22

Female people prefer projector - 28

Total people prefer projector - 50

Male people prefer Whiteboard - 10

Female people prefer whiteboard - 15

Total people prefer whiteboard - 25

Total number of Male people - 32

Tota lnumber of  Female people - 43

Total number of people - 75

Here the solution given below :

Probability that a teacher prefer projector & is female candidate is =

Total Female prefer whiteboard/Total people = 28/75 = 0.373

The correct option of this question is  B) 0.373. Explation is given above.

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Answer:

a = 31°

b = 149°

c = 149°

d = 31°

Answer:

see explanation

Step-by-step explanation:

Since there are 3 parallel lines, then

a and 31° are corresponding angles and congruent, thus

a = 31°

b and 31° are same- side interior angles and supplementary, thus

b = 180° - 31° = 149°

c and b are vertical angles and congruent, thus

c = 149°

d and 31° are alternate angles and congruent, thus

d = 31°

a = 31°, b = 149°, c = 149°, d = 31°

The intermediate value theorem guarantees that the function q(x) = 2x^3 - 13x^2 - 13x + 18 has at least one zero on each of the intervals [1, 2], [2, 3], [3, 4], and [4, 5].

To determine whether the intermediate value theorem guarantees that the function q(x) = 2x^3 - 13x^2 - 13x + 18 has a zero on each of the given intervals, we need to evaluate the function at the endpoints of each interval and check if the function changes sign between them.

(a) Interval: [1, 2]

Evaluate q(1) and q(2):

q(1) = 2(1)^3 - 13(1)^2 - 13(1) + 18 = -4

q(2) = 2(2)^3 - 13(2)^2 - 13(2) + 18 = 4

Since q(1) is negative and q(2) is positive, the function q(x) changes sign between 1 and 2. By the intermediate value theorem, there must be a zero of the function on the interval [1, 2].

(b) Interval: [2, 3]

Evaluate q(2) and q(3):

q(2) = 4 (from the previous calculation)

q(3) = 2(3)^3 - 13(3)^2 - 13(3) + 18 = -1

Since q(2) is positive and q(3) is negative, the function q(x) changes sign between 2 and 3. Therefore, by the intermediate value theorem, there must be a zero of the function on the interval [2, 3].

(c) Interval: [3, 4]

Evaluate q(3) and q(4):

q(3) = -1 (from the previous calculation)

q(4) = 2(4)^3 - 13(4)^2 - 13(4) + 18 = 54

Since q(3) is negative and q(4) is positive, the function q(x) changes sign between 3 and 4. Hence, by the intermediate value theorem, there must be a zero of the function on the interval [3, 4].

(d) Interval: [4, 5]

Evaluate q(4) and q(5):

q(4) = 54 (from the previous calculation)

q(5) = 2(5)^3 - 13(5)^2 - 13(5) + 18 = -47

Since q(4) is positive and q(5) is negative, the function q(x) changes sign between 4 and 5. Therefore, by the intermediate value theorem, there must be a zero of the function on the interval [4, 5].

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The sample area for flipping a coin and rolling a die is 12 square inches.

To complete the table, combine the outcomes of rolling the die with flipping the coin.

Every coin result (H for heads and T for tails) is coupled with every die result (1, 2, 3, 4, 5, 6).

The completed table:

    Die              Coin

       1                  H

       1                  T

       2                  H

       2                  T

       3                  H

       3                  T

       4                  H

       4                  T

       5                  H

       5                  T

       6                  H

       6                  T

Now, let's count the number of outcomes in the sample space.

There are 12 rows in the completed table, so the size of the sample space is 12.

Consequently, the sample space has a 12 x 12 size.

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Answer: 288

Step-by-step explanation:

Word explanation: if for one student he must spend 12$ then he must spend $12 24 times so you must multiply 12 by 24 to get 288 :)

Expression form: 12 x 24 = 288

To find the displacement and total distance traveled by the object from t=0 to t=6, we need to integrate the velocity function over the given time interval.

The displacement can be found by integrating the velocity function v(t) with respect to t over the interval [0, 6]. The integral of v(t) represents the net change in position of the object during this time interval.

The total distance traveled can be determined by considering the absolute value of the velocity function over the interval [0, 6]. This accounts for both the forward and backward movements of the object.

Now, let's calculate the displacement and total distance traveled using the given velocity function v(t) = t^2 - (1/t) - 12 over the interval [0, 6].

To find the displacement, we integrate the velocity function as follows:

Displacement = ∫[0,6] (t^2 - (1/t) - 12) dt.

To find the total distance traveled, we integrate the absolute value of the velocity function as follows:

Total distance = ∫[0,6] |t^2 - (1/t) - 12| dt.

By evaluating these integrals, we can determine the displacement and total distance traveled by the object from t=0 to t=6.

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Given that the equation of the lane passing through points A and B is -7x + 3y = -21.5, we need to find the equation of the central street PQ. Among the provided options, we need to determine which equation represents the central street.

To find the equation of the central street PQ, we need to identify the relationship between the central street and the given lane passing through points A and B. Since the streets in the game are depicted as either perpendicular or parallel lines, the central street must be perpendicular to the given lane.

To determine the equation of a line perpendicular to -7x + 3y = -21.5, we can use the fact that the slopes of perpendicular lines are negative reciprocals of each other. The given line has a slope of (coefficient of x / coefficient of y) = -7/3. The slope of the perpendicular line will be the negative reciprocal of this slope, which is 3/7.

Now, let's analyze the provided answer choices:

A. -3x + 4y = 3: This equation does not have a slope of 3/7 and therefore does not represent a line perpendicular to the given lane. It can be eliminated.

B. -1.5x − 3.5y = -31.5: This equation also does not have a slope of 3/7 and is not perpendicular to the given lane. It can be eliminated.

C. 2x + y = 20: This equation does not have a slope of 3/7 and is not perpendicular to the given lane. It can be eliminated.

D. -2.25x + y = -9.75: This equation has a slope of 2.25, which is the negative reciprocal of the slope of the given lane (-7/3). Therefore, this equation represents a line that is perpendicular to the given lane and can be considered as the equation of the central street.

Thus, the correct answer is D. -2.25x + y = -9.75, which represents the equation of the central street PQ.

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