the tense..........used to describe events that have not yet taken place​

Answer:

Claim: The chemical equation presented in the data table does NOT follow the law of conservation of matter

Evidence: Since we initially have 14.25 grams of Na and 9.5 grams of HCl

we will find the number of moles in each, to further apply stoichiometry

So,

Moles of Na: Given mass/Molar Mass = 14.25/23 = 0.62 Moles of Na

Moles of HCl: Given mass/Molar Mass = 9.5/36.5 = 0.26 Moles of HCl

Since HCl is the limiting reagent in this reaction,

0.26 Moles of Na will be consumed, which is equal to

5.98 grams of Na

Reasoning:

We are given that the total mass of the product is 22.98 grams

but through stoichiometry, we have found that only (9.5 + 5.98) = 15.48 grams of product can possibly be formed

Hence, the reaction presented in the table does NOT follow the law of conservation of matter

Answer

false

Explanation:

sorry I tbought i put false I hope I helped ....

The answer is false! All matters do not look the same, even if it had a visible look the answer would be false!

Why is the answer false?

There is lots of matters, Like liquids:

(Water, Juice, Milk, etc.)

All Water, Juice, & Milk looks different, Maybe SOME look the same, but the question is saying "All", Most of all questions is wrong.

Therefore the answer is false!

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De Broglie contributed to the development of the modern model of atoms by describing the wave properties of particles. Option E.

Louis de Broglie was a French physicist who made significant contributions to the development of quantum mechanics.

In his doctoral thesis, he proposed that particles, such as electrons, have both particle-like and wave-like properties. This idea became known as wave-particle duality and laid the foundation for the development of the modern model of the atom.

According to de Broglie's theory, particles can exhibit wave-like behavior and have a wavelength that is inversely proportional to their momentum.

This theory was later experimentally confirmed in a series of experiments that demonstrated the diffraction of electrons and other particles.

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The equilibrium constant is given by the ratio between the products and the reactants, where their stoichiometric numbers are exponents.

Observe that the molecule H2O must have a coefficient of 2 in order to balance the equation.

• [H2O] is the equilibrium concentration of the product (water).

• [H2} is the equilibrium concentration of the hydrogen molecule.

• [O2] is the equilibrium concentration of the oxygen molecule.

We must utilise the chemical formula for the reaction of iron and carbon monoxide to make iron oxide in order to respond to this question. It goes like this: CO + 2 Fe = Fe2O3. Therefore, 1 mole of CO is required for every 2 moles of Fe.

We must multiply the necessary 209.7 moles of Fe by 1/2 to determine the necessary moles of CO. We now have 104.85 moles of CO overall. We may utilise the stoichiometric coefficient for CO, which is 1, to verify our response. It is 1.

Accordingly, 1 mole of Fe2O3 is created for every mole of CO. As a result, 104.85 moles of Fe2O3 are created for every 104.85 moles of CO. because 2 moles If 104.85 moles of Fe2O3 are needed to make 1 mole of Fe2O3, then multiply that figure by two to find the amount of Fe that was created. This provides us the same quantity of Fe that we started with, or 209.7 moles, which supports our conclusion.

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Tthe initial temperature of the polystyrene sample is 39.4°C.

Given: Mass of polystyrene sample = 54.2 gSpecific heat of polystyrene = 1.880 J-g°CWater mass = 100.0 g Initial water temperature = 21.0°CWater final temperature = 34.3°CPressure remains constant at 1 atmFormula used:Heat gained by water = heat lost by polystyreneHence,Heat lost by polystyrene = Heat gained by water=> mcΔT = mcΔTwhere,m = mass of polystyrene or waterc = specific heat capacityΔT = change in temperatureThe temperature change is ΔT = 34.3°C - 21.0°C = 13.3°CNow we can use this temperature change to calculate the initial temperature of the polystyrene.Taking the water's specific heat capacity, c = 4.184 J/g°CHeat gained by water = (100.0 g)(4.184 J/g°C)(13.3°C) = 5574 JHeat lost by polystyrene = 5574 JTaking the polystyrene's specific heat capacity, c = 1.880 J/g° ) = 13.3°C Now let's calculate the mass of polystyrene using the specific heat capacity formula.5574 J = (54.2 g)(1.880 J/g°C)(13.3°C - Ti)Ti = 39.4°C

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Answer:

thunderstrom

Explanation:

it will be answer

Answer:

air mass

Explanation:

A huge volume of air with usually constant temperature and humidity is referred to as an air mass. The properties of an air mass are determined by the place from which it originates. The longer an air mass remains above its originating region, the more damage it causes.

A typical serving of the juice would provide about 29.8 milligrammes of vitamin C.

Subtract the total amount of iodine drops from the quantity of drops required to produce 1 mg of vitamin C in the reference sample. For instance, if your reference sample needed 2 drops for every 1 mg of vitamin C and your test fruit needed 10 drops of iodine, the equation would be Per ounce of fruit juice, there are 5 mg of vitamin C (10/2=10).

We need to know the volume of a normal serving in order to determine the quantity of vitamin C in the juice. Let's presume that a serving size is 250 mL.

5.45 mg / 45.7 mL = x mg / 250 mL

5.45 mg * 250 mL = 45.7 mL * x

1362.5 mg/mL = 45.7 mL * x

x = 1362.5 mg / 45.7

x = 29.8 mg

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Carbon atoms may thus form bonds to as many as four other atoms. For example, in methane (CH 4​start subscript, 4, end subscript), carbon forms covalent bonds with four hydrogen atoms

__________________________________________________________

Answer:

CaCl2--->Ca2+ + 2Cl_ so i=3

To synthesize the following cross- coupling products using Pd-catalyzed cross-coupling named reactions.

Step 1: Suzuki Cross-Coupling reaction

It is a reaction between Organo halides and organoborane. The given reaction is as follows,

A catalytic cycle including three primary stages governs the Suzuki coupling mechanism. Oxidative addition, transmetalation, and reductive elimination are the three methods.

The oxidative addition of aryl halides to the complex is the first step, which results in intermediate 1, Pd(2)   species. In transmetalation, an organoborane molecule combines with intermediate 1 under the influence of a base to produce intermediate 2. Reductive elimination is then used to produce the required product and regenerate the original species.

Step 2: Heck Cross-Coupling reaction

It is a reaction between Organohalide and Olefins. It is also a substitution reaction of alkene. The reaction is as follows,

CN pd Rocha = H₂CO.CN Х 4 / осн, Ne Ne (х= cl, % ) Bor.

The Heck reaction uses palladium as a catalyst and a base to cross-couple an organohalide with an alkene to produce a substituted alkene. The reaction starts with the aryl halide being oxidatively added to the palladium, followed by coordination and migratory insertion of the olefin into the palladium.

Bond rotation relieves steric strain by placing the two groups trans to each other, and subsequent -hydride elimination results in a trans final product. The catalyst is regenerated through base-mediated reductive elimination.

Step 3: Stille Cross-Coupling reaction

It is a coupling reaction between organohalide and oregano stannane. The reaction is as follows,

H2C0 [Pd],[]。 f,с H₂Cg sn R / си» R (x = (1, Bo, 2, 074) o x clI, R= alkyl group) eg -CH₂ , Et -Bu ehe

The organic reaction of an organohalide with an organostannane compound to yield the coupled product using a palladium catalyst is known as the Stille cross-coupling reaction. The oxidative addition of the organohalide to the complex to generate the Pd(2) complex is the first step in the mechanism.

The R group of the organostannane reagent replaces the halide anion on the palladium complex in transmetalation with the organostannane. The final coupled product is then produced by reductive elimination, which regenerates the palladium catalyst and allows the catalytic cycle to restart.

Step 4: Negishi Cross-Coupling reaction

It is a coupling reaction between organohalide and organozinc.

The reaction is as follows, 40 CH 3 не -Х x 4 4 с нс 5 е = х = с15 т, ), ( ал, мм) OTJ, GA pd1 Осн; Pe CH₃ -on) Hica сN,

The Negishi cross-coupling process, which uses a palladium or nickel catalyst, is an organic reaction in which an organohalide reacts with an organozinc molecule to produce the coupled product.

The oxidative addition of the organohalide to the Pd(0) to produce a Pd(II) complex is the first step in the palladium-catalyzed process. The R group of the organozinc reagent subsequently substitutes the halide anion on the palladium complex, resulting in a zinc(II) halide salt. The final coupled product is then produced by reductive elimination, which regenerates the catalyst and restarts the catalytic cycle.

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The ratio of molecules in sulphur dioxide and methane will be the same as the ratio of their moles. So, first of all we should find out the number of moles of sulphur dioxide in 1 gram of sulphur dioxide in 1 gram of sulphur dioxide, and the number of moles of methane in 1 gram of methane. This can be done as follows :

(i) The molecular formula of sulphur dioxide is \(SO_{2}\)

So, \(1\)  mole of \(SO_{2}\) = \(Mass\) \(of\) \(2'O'\)

\(=32+2*16\)

\(= 64\) grams

Now, \(64g\) of sulphur dioxide \(= 1\) mole

So, \(1g\) of sulphur dioxide = \(\frac{1}{64}\) mole

Thus, we have \(\frac{1}{64}\) mole of sulphur dioxide and it contains molecules in it. Now, since equal moles of all the substance contain equal number of molecules, therefore, \(\frac{1}{64}\) mole of methane will also contain x molecules of methane.

(ii) Molecular formula of methan is \(CH_{4}\)

So, 1 mole of \(CH_{4}\)  = Mass of C + Mass of 4 H

\(=12+4*12\)

Now, 16g of methane = 1 mole

So, 1 g of mathane = \(\frac{1}{16}\) mole

We know that:

\(\frac{1}{64}\) mole of methane contains = x molecules

So, \(\frac{1}{16}\)  mole of contains will contain =\(\frac{x*64}{16}\) molecules

=\(4x\) molecules

Answer:

B. amorphous

Explanation:

Examples of amorphous solids include glass, rubber, and plastics.

Answer:

9.8 joules

Explanation:

due to acceleration due to gravity

Explanation:

Zinc is the anode (solid zinc is oxidised). Silver is the cathode (silver ions are reduced).

By convention in standard cell notation, the anode is written on the left and the cathode is written on the right. So, in this cell: Zinc is the anode (solid zinc is oxidised). Silver is the cathode (silver ions are reduced).

Answer:

The volume of a 0.2 M solution containing 8.5 grams of AgNO₃ is 0.25 L

Explanation:

 Molarity (M) is a common way of expressing the concentration of solutions. It is defined as the number of moles of solute per volume of solution. The molarity of a solution is calculated by dividing the moles of the solute by the volume of the solution.

\(Molarity=\frac{number of moles of solute}{volume}\)

Molarity is expressed in units \(\frac{moles}{liter}\).

Being the molar mass of AgNO3 169.87 g / mol, then you can apply the following rule of three: if 169.87 grams are present in 1 mole of the compound, 8.5 grams will be present in how many moles?

\(amount of moles=\frac{8.5 grams*1 mole}{169.87 grams}\)

amount of moles= 0.05

So, being the molarity equal to 0.2 M, replacing in the definition of molarity:

\(0.2 M=\frac{0.05 moles}{volume}\)

and solving you get:

\(volume=\frac{0.05 moles}{0.2 M}\)

volume=0.25 L

The volume of a 0.2 M solution containing 8.5 grams of AgNO₃ is 0.25 L

Answer: 0.18

Explanation:

the molarity equation is moles of solute over L of solution:

mol (solute)/L (solution

so you need to convert 6.14g of LiNO3 into moles so:

6.14g LiNO3 • 1 mol

———— = 0.0890552 mol

68.946g LiNO3 (molar mass)

then you need to convert 505ml to L:

505/1000= 0.505

then you just follow the equation

0.0890552 mol / 0.505 L = 0.17634694 or 0.18 for sigfigs

0.18 M

hope this helps :)

Answer:

Picture:

Explanation:

Edge 2022

Answer:48

Explanation:

Answer:  3. 0.125 X 10”23 molecules

Explanation:

When two objects descend towards one another, the potential energy related to the gravitational field is released (transformed into kinetic energy).

The potential energy that a huge item has in relation to a different massive object due to gravity is known as gravitational energy and gravitational potential energy. When two objects descend towards one another, the potential energy related to the gravitational field is released (transformed into kinetic energy). Bringing two things farther apart increases the gravitational potential energy.

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Answer:

What is the mass of 1 mole of iron atoms?

Since iron has an atomic mass of 55.847 amu, one mole of iron atoms weighs 55.847 grams.

Explanation:

Got this answer from Angelo State University website.

Reagents that are entirely consumed by a chemical reaction are known as limiting reagents.

Thus, They are additionally known as limiting reactants or limiting agents. A predetermined quantity of reactants are necessary for the reaction to be completed, according to the stoichiometry of chemical reactions.

In the aforementioned reaction, 2 moles of ammonia are created when 3 moles of hydrogen gas react with 1 mole of nitrogen gas.

In most cases, this reactant dictates when the reaction will end. The reaction stoichiometry can be used to determine the precise quantity of reactant that will be required to react with another element. The limiting agent is determined by the mole ratio rather than the mass of the reactants.

Thus, Reagents that are entirely consumed by a chemical reaction are known as limiting reagents.

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The final concentration of the reactant of a first order reaction can be determined from the rate constant equation. The concentration of ammonium carbonate after 39 s will be 0.003 M.

Rate constant of a reaction is the rate of reaction when one molar concentration of the reactant is involved in the reaction. The expression for the rate constant k for first order reaction is :

k = 1/t ln (C0/Ct)

Where C0 be the initial concentration and Ct be the concentration after t seconds.

Given that C0 of ammonium nitrate = 0.957 M

rate constant = 0.196 /s

t = 39 s.

The concentration after 39 seconds is calculated as follows:

0.196 /s = 1/39s ln (0.957 M / Ct)

Ct = 0.957 / (ln⁻¹ (0.196 × 39))

    = 0.003 M.

Therefore, the concentration of ammonium carbonate after 39 seconds will be 0.003 M.

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We can measure the slope of the tangent line to the curve at a certain position on a graph to calculate the pace of a response at that time.

A reaction is a process in which one or more reactants are changed into one or more products, also known as the final products. Atoms are rearranged and chemical bonds are made and broken between the atoms during a chemical reaction, which transforms reactants into products.

The instantaneous rate of the response at that particular time is indicated by the slope of the tangent line.

If we have a graph of the quantity of product produced over time, for instance, we can choose a point on the curve that represents a certain period, draw a tangent line to the curve at that location, and then calculate the slope of the line. The pace of the reaction at that specific moment is shown by the slope of the tangent line.

The average rate of the response over a certain period of time can be calculated by repeating this method at various points on the curve to produce a series of instantaneous rates.

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Answer:

density = mass / volume

mass of iron = 9.3g

volume of iron = 29.78ml - 28.00ml = 1.78 ml

density of iron = 9.3 / 1.78 = 5.22471910112 = 5.0

Explanation:

This equation implies that there are two protons on the left side and two protons on the right side.

NaHSO3 + H2O → Na+ + HSO3- + OH-

H2SO3 + 2 H2O → H3O+ + HSO3- + OH-

1.4 x 10-2 H3O+ + 6.5 x 10-8 HSO3- → 1.4 x 10-2 OH- + 6.5 x 10-8 H3O+

NaHSO3  ->  Na+ + HSO3- (Ka1 = 1.4 x 10-2)

HSO3-  ->  H+ + SO32- (Ka2 = 6.5 x 10-8)

The complete proton balance for the system is:

NaHSO3 + H2O <=> Na+ + H3O+ + HSO3-

HSO3- + H2O <=> H+ + SO32- + H2O

NaHSO3 + H2O <=> Na+ + H3O+ + H+ + SO32-

So the proton balance is:

NaHSO3 + H2O <=> Na+ + 2 H3O+ + SO32-

NaHSO3 + H2O <=> Na+ + 2 H3O+ + SO32-

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Caffeine is more soluble in dichloromethane and the both are separated by evaporating the solvent.

Caffeine is an organic plant material which is more soluble in non-polar solvents than in polar solvents. As such, caffeine is more soluble in dichloromethane than in pure water.

In order to carry out a liquid-liquid exaction of dichloromethane from a commercial teabag, the dichloromethane is mixed with water. The caffeine is found to be more soluble in the organic dichloromethane layer than in water.

The two solvents can now be separated using a separating funnel and the solution is evaporated to obtain the caffeine.

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Answer:

That depends on the amount. Solubility is the maximum amount of salt dissolved in 100 g of water. So, if the amount is within limit, then yes. Solubility of anhydrous copper sulfate is 24.3 g/100 g water, so it is not bad. Put it in perspective, the solubility of NaCl is about 35 g/100 g water at room temperature. If the amount of copper sulfate is unknown, qualitative I'd say solid copper sulfate will dissolve in water completely.

Explanation:

If you use the pentahydrate CuSO4.5H2O then the solubility at 20°C is 20.8g/100ml H2O

If you use the anhydride, CuSO4. then the solubility at 20°C is 36.2g/100ml H2O

The equation can be balanced by using options C and E

To balance a chemical reaction equation, you need to ensure that the number of atoms of each element is the same on both sides of the equation. Balancing the equation is important because it follows the law of conservation of mass, which states that matter cannot be created or destroyed in a chemical reaction.

Start balancing with elements that appear in the fewest compounds: Begin balancing the equation by adjusting elements that appear in the fewest compounds first.

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