The top and the bottom of the slide are level with the ground, which has a slope of 0.

A picture shows a slide. The bottom of the slide is 18 inches above the ground and the top of the slide is 8 feet above the ground. The distance between the bottom of the slide and the top of the slide is marked as “12 feet”. Starting from the bottom of the slide, the slide is horizontal with length “1 foot”, a ramp, and horizontal at the top of the slide with length “1 foot”.



a. What is the slope of the main portion of the slide?
.
Question 2
b. Describe the change in the slope when the bottom of the slide is only 12 inches above the ground. Explain your reasoning.

By the polynomial remainder theorem the remainder is equal to \(f(a)\)

The area of the parallelogram is given as 20cm square

To calculate the area of a parallelogram, you can use the formula:

Area = base * height

Here are the steps to follow:

Identify the base: The base of a parallelogram is one of the sides of the shape. It is typically a horizontal side, but any side can be considered the base.

Measure the base: Using a ruler or measuring tool, determine the length of the base and make a note of the measurement.

The height is given as 5cm, the base is given as 4 cm

Hence 5cm * 4 cm

= 20cm²

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The equation of a vertical asymptote to the graph of y = sec(6x - π) is x = π/6. Hence, option a is correct.

The function y = sec(6x - π) has vertical asymptotes at the values of x where the denominator of sec(6x - π) becomes zero. The reciprocal of sec(θ) is cos(θ). Because the cosine function has the values π/2, 3π/2, 5π/2, we will insert such an input that we get 0 in denominator.

6x - π = π/2

Solving for x,

6x = π/2 + π

6x = 3π/2

x = (3π/2) / 6

x = π/6

Therefore, the equation of a vertical asymptote to the graph of y = sec(6x - π) is x = π/6.

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There are 472 more buttons bought by Vance than beads.

For the stated question table is made.

So,

Total number of beads bought by Vance = Number of beads(2 packages of large beads) + Number of beads(1 package of medium beads).

= (2 × 96) + (1 × 64)

= 2 × (90 + 6) + 64

= (2 × 90) + (2 × 6) + 64

= 180 + 12 + 64

= 256 beads

Now,

Total number of buttons bought by Vance = Total number of buttons (2 packages of large buttons) + Number of buttons (2 packages of medium buttons)

= (2 × 56) + (2 × 38)

= 2 × (50 + 6) + 2 × (30 + 8)

= (2 × 50) + (2 × 6) + (2 × 30) + (2 × 8)

= 100 + 12 + 600 + 16

= 728 buttons

Thus,

Difference for the number of buttons and beads

= 728 – 256

= 472 beads

So,

Therefore, there are 472 more buttons bought by Vance than beads.

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This value represents the present worth below which the probability is 0.5, indicating a negative present worth.

To estimate the probability that the present worth is negative using the NORM.INV function in Excel,

we need to calculate the present worth of the project and then determine the corresponding probability using the normal distribution.

The present worth of the project can be calculated by finding the sum of the present values of the annual receipts over the 10-year period, minus the initial investment. The present value of each annual receipt can be calculated by discounting it back to the present using the minimum attractive rate of return (MARR).

Using the given information, the present value of the initial investment is $10,000. The present value of each annual receipt is calculated by dividing the expected return of $1,800 by \((1+MARR)^t\),

where t is the year. We then sum up these present values for each year.

We can use the NORM.INV function in Excel to estimate the probability of a negative present worth. The function requires the probability value, mean, and standard deviation as inputs.

Since we have a mean and standard deviation for the present worth,

we can calculate the corresponding probability of a negative present worth using NORM.INV.

This value represents the present worth below which the probability is 0.5. By using the NORM.INV function,

we can estimate the probability that the present worth is negative based on the given data and assumptions.

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Answer:

Where is the question?

The Yule-Walker equations relate the autocovariance function of a stationary time series to its autocorrelation function. In this case, we are interested in finding the autocovariance function.

The Yule-Walker equations for an AR(2) process can be written as follows:

r_X(0) = Var(X_t) = σ^2

r_X(1) = ρ_X(1) * σ^2

r_X(2) = ρ_X(2) * σ^2 + ρ_X(1) * r_X(1)

Here, r_X(k) represents the autocovariance at lag k, ρ_X(k) represents the autocorrelation at lag k, and σ^2 is the variance of the white noise innovation process e_t.

In our case, we are given that V(e_t) = 4, so σ^2 = 4. Now we need to find the autocorrelations ρ_X(1) and ρ_X(2) to compute the autocovariances.

Since X_t is an AR(2) process, we can rewrite the Yule-Walker equations in terms of the AR parameters as follows:

1 = φ_1 + φ_2

0.5 = φ_1 * φ_2 + ρ_X(1) * φ_2

0 = φ_2 * ρ_X(1) + ρ_X(2)

Solving these equations will give us the values of ρ_X(1) and ρ_X(2), which we can then use to compute the autocovariances r_X(0), r_X(1), and r_X(2).

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Answer:

1a is 165

1b is 990

Step-by-step explanation:

So the first one is basically asking the possibility of each member being chosen for one of each role.

While the second one is asking the possibility of the person being in one specific role and making that be considered a possibility.

In other words, it's basically easier to get into one of the three roles rather than being in one specific role.

Answer:

The answer is D

Step-by-step explanation:

jwjwjsjksjdjdjrjrjdi

Answer:

1.4.3

2.0.25

3.6.2

4.0.875

Answer:

reflection, rotation and translation.

Step-by-step explanation:

We can use Coulomb's law to calculate the magnitude of the electric field at a distance r away from a point charge Q:

E = k * Q / r^2

where k is Coulomb's constant, Q is the charge of the point charge, and r is the distance from the point charge.

In this problem, we have a point charge Q of -10 nC located at (1.2 cm, 0 cm), and we want to find the x-component of the electric field at a distance r = 5.3 cm away at position (-4.1 cm, 0 cm).

To find the x-component of the electric field, we need to use the cosine of the angle between the electric field vector and the x-axis, which is cos(180°) = -1.

So, the x-component of the electric field at position (-4.1 cm, 0 cm) is:

E_x = - E * cos(180°) = - (k * Q / r^2) * (-1)

where k = 9 x 10^9 N*m^2/C^2 is Coulomb's constant.

Substituting the given values, we get:

E_x = - (9 x 10^9 N*m^2/C^2) * (-10 x 10^-9 C) / (0.053 m)^2

E_x ≈ -30,566.04 N/C

Rounding this to two significant figures and including the appropriate units, we get:

The x-component of the electric field is about -3.1 x 10^4 N/C (to the left).

The cost function for a drug manufacturer producing a generic drug is c(y) = 3\(y^{3}\) - 10\(y^{2}\) + 200y

The cost function is a cubic function with positive coefficients for the \(y^{3}\) term and negative coefficients for the \(y^{2}\) term, indicating increasing costs at a decreasing rate. The y term represents variable costs, such as raw materials and labor, while the constant term represents fixed costs, such as overhead expenses.

The shape of the cost function suggests that as the number of doses produced and sold increases, the costs initially rise rapidly due to the cubic term but start to increase at a slower rate due to the decreasing quadratic term. Eventually, the cost curve may reach a point where it starts to increase more rapidly again.

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Yes, you can still get from one city to another even if a road is closed for maintenance.

How is it feasible to get from one city to another if one road is closed for repairs?

It is sufficient to show that even with route AB closed, we can still get from point A to point B. In the connected component that contains vertex A, all the vertices would be even if this weren't the case.

When a connected component has exactly one odd vertex, the "A graph must have an even number of odd vertices" condition is violated.

Therefore, even if one of the roads is closed for maintenance, it is still possible to go from Point A to Point B by another road or city.

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The given question is improper. Proper question is given below;

in a certain country, 40 roads lead out of each city. when all roads are open, it is possible to travel from any city to any other. each road leads from one city to another; there are no dead end roads. if one road is closed for repairs, is it still necessarily possible to travel from any city to any other? prove your answer.

Answer:

41

Step-by-step explanation:

A prime number is a whole number (bigger than 1) that is divisible only by itself and 1.

The first 6 prime numbers are 2, 3, 5, 7, 11 and 13.

2 + 3 + 5 + 7 + 11 + 13 = 41.

Answer: 41

Step-by-step explanation: We know that the first 6 prime numbers are 2, 3, 5, 7, 11, 13. We add them all and get 41!

Answer:

Step-by-step explanation:

-5x + 7y = -34     ⇒  -5x = -34  - 7y

    -5x + 3y = -6

-34  - 7y + 3y = -6

-34 - 4y = -6          {add 34 to both sides}

  -4y = 28             {divide both sides by (-4)}

     y = - 7

-5x + 3y = -6

-5x + 3(-7) = -6

-5x - 21 = -6        {add 21 to both sides}

-5x = 15            {divide both sides by (-5)}

  x = -3

Answer:

64

Step-by-step explanation:

Answer:

on the red ? is 32 and on the blue ?is16

Answer:

C) 187 1/2 miles

Step-by-step explanation:

We can start by using the formula for converting between scale measure and actual measure:

actual measure = scale measure * (actual distance / scale distance)

Here, the scale measure is 3/4 inch and the scale distance is 1 1/2 inches, so:

actual measure = (3/4) * (n / 250)

Rearranging the equation, we can isolate n:

n = (actual measure * 250) / (3/4)

Substituting in the actual measure of 3/4 inch, we find:

n = (3/4 * 250) / (3/4) = 250 miles

So the answer is C) 187 1/2 miles.

If we consider all possible mixed strategies for player 2, then the number of strategies that player 2 has is infinite.

In the extensive-form game provided, player 2 has two decision points where they can choose between two actions, C and F in the first decision point and G and not-G in the second decision point. Therefore, player 2 has 2 x 2 = 4 pure strategies.

However, player 2 can also mix their strategies in each decision point, choosing a probability distribution over the available actions. For example, in the first decision point, player 2 can play a mixed strategy where they choose C with some probability and F with the complementary probability. Similarly, in the second decision point, player 2 can mix their strategies by choosing to play G with some probability and not-G with the complementary probability.

So, if we consider all possible mixed strategies for player 2, then the number of strategies that player 2 has is infinite.

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In the extensive-form game that follows, how many strategies does player 2 have?

Answer:

E

Step-by-step explanation:

Here, we want to find the area of the shaded portion on the graph.

That would be P(-1.2<z<0.85)

we complete this by checking these values on the standard score table as follows;

P( z< 0.85) - P(z<-1.2) = 0.68727

Answer:

it is 15.6ft because you need to add 7.8+7.8= 15.6ft

Answer:

z = 106°

As a straight line has total 180°

Find the top inside angle:

t + 142° = 180°

t = 180° - 142°

t = 38°

Two opposite angles sum up to exterior angle.

Now find z:

68° + 38°

106°

Solution:

It should be noted:

This means that:

Simplify the LHS.

Subtract 106 both sides.

Subtract 180 both sides.

Divide both sides by -1.

The measure of ∠z is 106°.

Answer:

83

Step-by-step explanation:

...........................

Yao Ming was 24 inches taller than Earl Boykins, as 7 feet is equal to 84 inches and 5 feet 5 inches is equal to 65 inches. Therefore, 84 - 65 = 19 inches, and Ming was 19 inches taller than Boykins.

Yao Ming, standing at 7'5" (7 feet 5 inches), was significantly taller than Earl Boykins, who was 5'5" (5 feet 5 inches) tall in the NBA in 2003. To calculate the difference in height, first convert their heights to inches: Yao Ming = (7 * 12) + 5 = 89 inches and Earl Boykins = (5 * 12) + 5 = 65 inches. Now subtract Boykins' height from Ming's: 89 - 65 = 24 inches. Yao Ming was 24 inches taller than Earl Boykins.

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