The tray dispenser in your cafeteria has broken and is not repairable. The custodian knows that you are good at design-ing things and asks you to help him build a new dispenser out of spare parts he has on his workbench. The tray dispenser supports a stack of trays on a shelf that is supported by four springs, one at each corner of the shelf. Each tray is rectangu-lar, with dimensions 45.3 cm by 35.6 cm. Each tray is 0.450 cm thick and has a mass of 580 g. The custodian asks you to design a new four-spring dispenser such that when a tray is removed, the dispenser pushes up the remaining stack so that the top tray is at the same position as the just-removed tray was. He has a wide variety of springs that he can use to build the dispenser. Which springs should he use

Answer:

a. the second choice of leisurely walking at 3 km/h burn up more energy, which is equal to 2.436 MJ

b. Due to more time

Explanation:

a.

FOR 10 km/h SPEED:

First, we find time taken to reach physics lab:

S₁ = V₁t₁

t₁ = S₁/V₁

where,

t₁ = time = ?

S₁ = Distance = 7 km

V₁ = Speed = 10 km/h

Therefore,

t₁ = (7 km)/(10 km/h)

t₁ = (0.7 h)(3600 s/1 h) = 2520 s

Now, we calculate the energy burnt:

P₁ = E₁/t₁

E₁ = P₁ t₁

where,

E₁ = Energy Burnt = ?

P₁ = Power Used = 700 W

t₁ = 2520 s

Therefore,

E₁ = (700 W)(2520 s)

E₁ = 1.764 MJ

FOR 3 km/h SPEED:

First, we find time taken to reach physics lab:

S₂ = V₂t₂

t₂ = S₂/V₂

where,

t₂ = time = ?

S₂ = Distance = 7 km

V₂ = Speed = 3 km/h

Therefore,

t₂ = (7 km)/(3 km/h)

t₂ = (2.333 h)(3600 s/1 h) = 8400 s

Now, we calculate the energy burnt:

P₂ = E₂/t₂

E₂ = P₂ t₂

where,

E₂ = Energy Burnt = ?

P₂ = Power Used = 290 W

t₂ = 8400 s

Therefore,

E₂ = (290 W)(8400 s)

E₂ = 2.436 MJ

Hence, the second choice of leisurely walking at 3 km/h burn up more energy, which is equal to 2.436 MJ

b.

The more intense exercise burn up less energy than the less intense exercise, because it is performed for a longer period of time.

The energy burnt:

E₁ = (700 W)(2520 s)

E₁ = 1.764 MJ

Thus, For 10km/h speed the energy burn are 1.764MJ.

The energy burnt:

The second choice of leisurely walking at 3 km/h burn up more energy, which is equal to 2.436 MJ

The more intense exercise burn up less energy than the less intense exercise, because it is performed for a longer period of time.

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Answer:

Female non-athletes, using for apperarance and social  

Explanation

Answer:

A) Male athletes

Explanation:

Boys are more likely to use steroids while girls gravitate more toward BSDs. Although male athletes are still the largest group of steroid abusers in high school campuses, the non-athletes are catching up fast

The point where the object's speed is one-half its final speed may located at 3/4 of the initial height of the object, the answer would be "lower than the midpoint of the path."

Assuming the object is subject to a constant acceleration due to gravity, the speed of the object at any given point can be described by the following equation:

v² = u² + 2as

Where:

v = final velocity

u = initial velocity

a = acceleration due to gravity (approximately 9.8 m/s² near the Earth's surface)

s = distance traveled

Let's suppose the object is dropped from rest at a height h above the ground. Then its initial velocity is u=0, and the equation simplifies to:

v² = 2gh

where g is the acceleration due to gravity and h is the initial height of the object.

To find the point at which the object's speed is one-half its final speed, we can set v = 1/2 * √(2gh) and solve for s:

1/2 * √(2gh) = √(2gh - 2gs)

Simplifying this equation, we get:

1/4 * 2gh = 2gh - 2gs

s = 3/4 * h

This means that the point where the object's speed is one-half its final speed is located at 3/4 of the initial height of the object. Therefore, the answer is "lower than the midpoint of the path."

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We can deduce here that the maximum horizontal force that you can apply to the box is 150 pounds. Thus, the heaviest box that you can push up the ramp at a constant speed is 75 pounds.

Given the following:

Maximum horizontal force = 150 pounds

Coefficient of kinetic friction = 0.50

Weight of the box = 150 pounds

Angle of the ramp = 60°

Normal force = Weight of the box * Cosine of the angle of the ramp

= 150 pounds × Cos(60°)

= 75 pounds.

Force of friction = Coefficient of kinetic friction × Normal force

= 0.50 × 75 pounds

= 37.5 pounds

Maximum force that can be applied to the box = Weight of the box × Cosine of the angle of the ramp - Force of friction

= 150 pounds × Cos(60°) - 37.5 pounds

= 75 pounds

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24 volts is the voltage drop across each of the resistors in the parallel configuration.

When resistors are connected in parallel, they share the same voltage across them. Therefore, the voltage drop across each resistor in this scenario would be the same.

Given:

Power supply voltage (V) = 12 V

Resistance of each resistor (R) = 30 Ω

Since the resistors are in parallel, the total resistance (R_total) can be calculated using the formula:

1/R_total = 1/R1 + 1/R2

Substituting the values:

1/R_total = 1/30 Ω + 1/30 Ω

1/R_total = 2/30 Ω

R_total = 15 Ω

Now, we can find the current flowing through the resistors (I) using Ohm's Law:

I = V / R_total

I = 12 V / 15 Ω

I = 0.8 A

Since the voltage drop across each resistor is the same, we can find it using Ohm's Law:

V_drop = I * R

V_drop = 0.8 A * 30 Ω

V_drop = 24 V

Therefore, the voltage drop across each of the resistors in the parallel configuration is 24 volts.

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Answer:

Magnitude of Paula’s acceleration\($a=39 \cdot 8m/sec^{2}$.\)

Explanation:

• An object is said to be accelerated if there is a change in its velocity. At any point on a trajectory, the magnitude of the acceleration is given by the rate of change of velocity in both magnitude and direction at that point.

• To find the magnitude of her acceleration, use the formula:                               \($${v^2} = {u^2} + 2as$$\)

Where, is final velocity, is initial velocity, is acceleration and is displacement.

• Placing the value of the given initial velocity, \($u=0m/s$\), displacement, \($s = 0 \cdot 201m$\) and the final velocity,\($v = 4m/s$\) in the above formula.

\(\[\begin{align}& \therefore{v^2} = {u^2} + 2as \\& \Rightarrow {\left( 4 \right)^2} = 0+ 2\left( a \right) \left( { 0 \cdot 201} \right) \\& \Rightarrow 16 = 0 \cdot 402a \\& \Rightarrow a = 39 \cdot 8m/sec^{2} \\\end{align}\]\)

\(\[& \therefore{v^2} = {u^2} + 2as \\& \Rightarrow {\left( 4 \right)^2} = 0+ 2\left( a \right) \left( { 0 \cdot 201} \right) \\& \Rightarrow 16 = 0 \cdot 402a \\& \Rightarrow a = 39 \cdot 8m/sec^{2} \\\]\)

• Hence, magnitude of her acceleration, \($a=39 \cdot 8m/sec^2$\)

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The third equation of free fall can be applied to determine the acceleration. So that Paola's acceleration during the flight is 39.80 m/\(s^{2}\).

Acceleration is a quantity that has a direct relationship with velocity and also inversely proportional to the time taken. It is a vector quantity.

To determine Paola's acceleration, the third equation of free fall is appropriate.

i.e \(V^{2}\) = \(U^{2}\) ± 2as

where: V is the final velocity, U is the initial velocity, a is the acceleration, and s is the distance covered.

From the given question, s = 20.1 cm (0.201 m), U = 4.0 m/s, V = 0.

So that since Poala flies against gravity, then we have:

\(V^{2}\) = \(U^{2}\) - 2as

0 = \((4)^{2}\) - 2(a x 0.201)

  = 16 - 0.402a

0.402a = 16

a = \(\frac{16}{0.402}\)

  = 39.801

a = 39.80 m/\(s^{2}\)

Therefore Paola's acceleration is 39.80 m/\(s^{2}\).

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Answer:

Explanation:

a) Maximum height id expressed as;

H = u²sin² theta/2g

H = 36.6²(sin42.2)²/2(9.8)

H = 1,339.56(0.6717)/19.6

H = 899.81/19.6

H = 45.91m

Hence the maximum height is 45.91m

b) The Time of flight is the total time in air expressed as;

T = 2usin theta/g

T = 2(36.6)sin42.2/9.8

T = 73.2sin42.2/9.8

T = 49.17/9.8

T = 5.017secs

Hence the total time in air is 5.017scs

c) Range = U²sin2(theta)/g

Range = 36.6²sin2(42.2)/9.8

Range = 1,339.5(0.9952)/9.8

Range = 1,333.11/9.8

Range = 136.03m

Hence the range is 136.03m

d) USing the rime of flight formula;

T =2Usintheta/g

1.5 = 2Usin42.2/9.8

2Usin42.2 =1.5*9.8

2Usin42.2 = 14.7

U = 14.7/2sin42.2

U = 14.7/1.3434

U = 10.94m/s

Hence the speed of the projectile is 10.94m/s

Answer:

1. 90N

2. 200N

3. 400N

4.20w

5.7200N

Explanation:

1.F=ma

30 * 3 = 90

2.W=FD

50 * 4=200

4. P=W/t

300/15=20

5.W= Pt. 2minutes = 120sec

60*120 = 7200

Answer:

(1,)

Explanation:

Answer:

magnitude: 21.6; direction: 33.7°

Explanation:

In circular motion, the total acceleration has two components: the centripetal acceleration (a_c) and the tangential acceleration (a_t). The centripetal acceleration is directed towards the center of the circle, while the tangential acceleration is directed along the tangent to the circle at the point of interest.

θ = tan^(-1)(a_c/a_t) or θ = tan^(-1)(a_t/a_c)

1. If you define the angle (θ) between the total acceleration vector (a) and the tangential acceleration (a_t), you should use:

2. If you define the angle (θ) between the total acceleration vector (a) and the centripetal acceleration (a_c), you should use:

Radius of wire is not used to determine the magnetic force on a current-carrying wire in a magnetic field

A magnetic field is a region in space where magnetic forces can be detected. It is created by the motion of electric charges, such as the movement of electrons in an electric current or the spinning of electrons in an atom.

A magnetic field is represented by lines of force that can be visualized using magnetic field lines. These lines indicate the direction of the magnetic field at each point in space and the strength of the magnetic field is indicated by the density of the lines.

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Answer:

During an eccentric contraction, when an active muscle, fiber or myofibril is actively stretched, its force increases substantially during the stretch.

Answer:

fiction i think

Explanation:

We want to find the motion equations for two bacteria, and use these to see when the two bacteria will meet again.

We will see that the bacteria meet again after 26.67 seconds.

Let's call bacteria number 1 at the one that moves with an initial velocity of 20 μm/s and that accelerates at 5 μm/s^2.

Remember that the acceleration is the rate of change of the velocity, then the velocity equation of this bacteria is:

\(v_1(t) = (5 \mu m/s^2)*t + 20 \mu m/s\)

The position equation is given by the integration of the above equation:

\(p_1(t) = (1/2)* (5 \mu m/s^2)*t^2 + (20 \mu m/s)*t + p0\)

Where p0 is the constant of integration, this is the initial position of the bacteria number one. We can define this equal to zero, because we can decide where the zero of our axis is.

\(p_1(t) = (1/2)* (5 \mu m/s^2)*t^2 + (20 \mu m/s)*t\)

Similarly, for the other bacteria we can write the equations:

\(v_2(t) = (-2 \mu m/s^2)*t + 60 \mu m/s\)

Again we integrate to get the position equation:

\(p_2(t) = (1/2)* (-2 \mu m/s^2)*t^2 + (60 \mu m/s)*t\)

a) We want to see when the bacteria meet again, then we just need to solve:

\(p_1(t) = p_2(t)\)

\((1/2)* (5 \mu m/s^2)*t^2 + (20 \mu m/s)*t = (1/2)* (-2 \mu m/s^2)*t^2 + (60 \mu m/s)*t\\\\(1/2)*(5 \mu m/s^2)*t^2 + (1/2)*(2 \mu m/s^2)*t^2 + (20 \mu m/s)*t - (60 \mu m/s)*t = 0\)

We will get a quadratic equation, simplifying the above we get:

\((1.5 \mu m/s^2)*t^2 - (40 \mu m/s)*t = 0\\\\(1.5 \mu m/s^2)*t - (40 \mu m/s) = 0\\\\(1.5 \mu m/s^2)*t = (40 \mu m/s) \\\\t = (40 \mu m/s)/(1.5 \mu m/s^2) = 26.67s\)

We can conclude that the bacteria will meet again after 26.67 seconds.

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Answer:

reaction force is 3N

Explanation:

The question is not complete.

From estudyassistant, I've gathered that the action force pushing the air out of the balloon is -3N.

Now,from Newton's third law of motion, it says, for every action, there is an equal and opposite reaction.

Thus, the reaction force will be equal and opposite in direction to the action force.

Thus, reaction force is 3N

Answer:

3n

Explanation:

edge 2021

Answer:

Waves can transfer energy over distance without moving matter the entire distance. For example, an ocean wave can travel many kilometers without the water itself moving many kilometers. The water moves up and down—a motion known as a disturbance. It is the disturbance that travels in a wave, transferring energy.

Explanation:

Answer:

6/7 kg

Explanation:

We are given:

Mass of the object (m) = 14 kg

Force applied (F) = 12 N

Acceleration of the Object:

From newton's second law of motion, we know that:

F = ma

Replacing the variable with the given values

12 = 14 * m

m = 12 / 14                                                        [dividing both sides by 14]

m = 6/7 kg

Hence, the Object has a mass of 6/7 kg

Answer:

1, 2, 3, 4 on edge 2020

Explanation:

Answer:

1234

Explanation:

Answer:In this lesson, the mathematical relationship between the tube's length, the speed of sound through air, and the ... Thus, the length of the air column is equal to one-half of the wavelength for the first harmonic. ... Determine the fundamental frequency (1st harmonic) of an open-end air column that has a length of 67.5 cm.

Explanation:

Answer:

Explanation:

Given:

d = 33.9 cm

f = 8.57

___________

F - ?

G - ?

The focal length of the lens:

F = d*f / (d + f) = 33.9*8.57 / (33.9 + 8.57) ≈ 6.84 cm

The magnification of the object:

M = f / d = 8.57 / 33.9 ≈ 0.25

Answer:

189 m/s

Explanation:

The pilot will experience weightlessness when the centrifugal force, F equals his weight, W.

So, F = W

mv²/r = mg

v² = gr

v = √gr where  v = velocity, g = acceleration due to gravity = 9.8 m/s² and r = radius of loop = 3.63 × 10³ m

So, v = √gr

v = √(9.8 m/s² × 3.63 × 10³ m)

v = √(35.574 × 10³ m²/s²)

v = √(3.5574 × 10⁴ m²/s²)

v = 1.89 × 10² m/s

v = 189 m/s

Answer:

Solids have a definite shape and volume. Liquids have a definite volume.Gases have no definite volume.

Given data

*The given radius of the circle is r = 7 ft

The formula for the diameter of the circle is given as

Substitute the values in the above expression as

Hence, the diameter of the circle is d = 14 ft

Answer:

17280 J and 1080 J

Explanation:

Given :

R= 40 ohm

I=1.2A

t= 5 min=60×5=300 sec

Now,

Total energy can be calculated as:

\(E=I^{2} Rt\\E=(1.2)^{2} *40*300\\E=17280 J\)

Now,

V=12V

R=40 Ohm

\(E=\frac{V^{2} }{R} *t\\E=\frac{(12)^{2} }{40} *300\\E=1080 J\)

Total energy  is 17280 J and 1080 J

Considering the Coulomb's Law, the magnitude of the charge on each particle is 4.2426 C.

Coulomb's law or law of electrostatics is the relationship between the interactions of electric charges, that is, it explains the force experienced by two electric charges at rest.

This law says that the electric force with which two point charges at rest attract or repel each other is directly proportional to the product of the magnitude of both charges and inversely proportional to the square of the distance that separates them, expressed mathematically as:

\(F=k\frac{Qq}{d^{2} }\)

where:

The force is attractive if the charges are of opposite sign and repulsive if they are of the same sign.

In this case, you know that:

Replacing in the Coulomb's Law:

\(1.8x10^{-8} N=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{Qq}{(0.3 m)^{2} }\)

Being Q=q:

\(1.8x10^{-8} N=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{q^{2} }{(0.3 m)^{2} }\)

Solving:

1.8×10⁻⁸ N÷ 9×10⁹ \(\frac{Nm^{2} }{C^{2} }\)= q²÷ (0.3 m)²

2×10⁻¹⁸ C²/m²= q²÷ (0.3 m)²

2×10⁻¹⁸ C²/m²= q²÷ 0.09 m²

2×10⁻¹⁸ C²/m² ×0.09 m²= q²

1.8×10⁻¹⁹ C²= q²

√1.8×10⁻¹⁹ C²= q

4.2426 C= q= Q

Finally, each charge has a value of 4.2426 C.

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Answer:

total sum of all numbers/ number of items in the set

Explanation:

Answer:

 m = 876.71 kg

Explanation:

This is an exercise of Archimedes' principle, which states that the thrust on a body is equal to the weight of the dislodged liquid  

        B = ρ g V  

therefore the load that the balloon can lift is  

       B - W_structure - w_load = 0

       w_load = B - W_structure

The volume of the balloon is  

      v = 4/3 π r³

let's substitute  

      w_carga = rho g 4/3 π r³ - m_structure g  

the air density at T = 25ºc is ρ = 1.18 kg / m³

let's calculate  

     w_load = 1.18 9.8 4/3 π 7.15³ - 930 9.8  

     w_load = 17705,77 - 9114  

     w_ load = 8591.77 N

this corresponds to a mass of  

   w_load = m g  

   m = w_load / g  

   m = 8591.77 / 9.8  

   m = 876.71 kg

Our muscles need more oxygen to make energy (in the form of ATP) while we workout.

When the respiratory rate picks up to fulfill this need, more oxygen can enter the body and more carbon dioxide can be exhaled.

Student 3 is breathing more forcefully than usual in this situation because of the high temperature and physical activity.

The respiratory system is the organ system engaged in this process.

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# complete question:

A group of students were playing basketball together during recess. The temperature outside was 30.5 oC (87 oF) and the sun was out. The students ran, shot baskets, and dribbled the ball for 30 minutes. When they finished their game some of the students made the following comments:

Student 1: Wow! I am so hot and sweaty! I need some water to cool down.

Student 2: My cheeks are really red.

Student 3: I am breathing so hard, I can barely catch my breath!

Explain what is happening to the students and how their bodies are trying to maintain homeostasis. Be sure to include any of the organ systems involved with each student.

Answer:

speed

Explanation:

The wave equation says that a waves speed is equal to its wavelength times is frequency.