Answer: 4.64%
\(\dfrac{\text{female research scientist}}{\text{female total}}=\dfrac{103}{2219}=0.0464\quad =\large\boxed{4.64\%}\)
Find the missing slant height
Answer:
\(\ell=\frac{77}{4}\)
Step-by-step explanation:
Because these two cones are similar, we can set up the following proportion:
\(\frac{11}{4}=\frac{\ell}{7}\)
Solving, we get:
\(\ell=\frac{7\cdot11}{4},\\\ell=\fbox{$\frac{77}{4}$}\).
You may need to use the appropriate appendix table or technology to answer this question.
Lori Jeffrey is a successful sales representative for a major publisher of college textbooks. Historically, Lori obtains a book adoption on 25% of her sales calls. Viewing her sales calls for one month as a sample of all possible sales calls, assume that a statistical analysis of the data yields a standard error of the proportion of 0.0625.
(a)
How large was the sample used in this analysis? That is, how many sales calls did Lori make during the month?
sales calls
(b)
Let
p
indicate the sample proportion of book adoptions obtained during the month. Show the sampling distribution of
p.
A bell-shaped curve is above a horizontal axis labeled p.
In order of left to right, the ticks on the horizontal axis are labeled: −0.0625, 0, 0.0625, 0.125, 0.1875.
The curve enters the viewing window near −0.0625 just above the horizontal axis and travels up to the right to a maximum near 0.0625.
After reaching the maximum, the curve then travels down and to the right until it leaves the viewing window at the same height it entered near 0.1875.
A bell-shaped curve is above a horizontal axis labeled p.
In order of left to right, the ticks on the horizontal axis are labeled: −1.75, −0.75, 0.25, 1.25, 2.25.
The curve enters the viewing window near −1.75 just above the horizontal axis and travels up to the right to a maximum near 0.25.
After reaching the maximum, the curve then travels down and to the right until it leaves the viewing window at the same height it entered near 2.25.
A bell-shaped curve is above a horizontal axis labeled p.
In order of left to right, the ticks on the horizontal axis are labeled: 0.125, 0.1875, 0.25, 0.3125, 0.375.
The curve enters the viewing window near 0.125 just above the horizontal axis and travels up to the right to a maximum near 0.25.
After reaching the maximum, the curve then travels down and to the right until it leaves the viewing window at the same height it entered near 0.375.
A bell-shaped curve is above a horizontal axis labeled p.
In order of left to right, the ticks on the horizontal axis are labeled: −0.125, −0.0625, 0, 0.0625, 0.125.
The curve enters the viewing window near −0.125 just above the horizontal axis and travels up to the right to a maximum near 0.
After reaching the maximum, the curve then travels down and to the right until it leaves the viewing window at the same height it entered near 0.125.
(c)
Using the sampling distribution of
p,
compute the probability that Lori will obtain book adoptions on 15% or more of her sales calls during a one-month period. (Round your answer to four decimal places.)
The sample size used in this analysis, representing the number of sales calls Lori made during the month, is approximately 385.
The sample size used in this analysis, representing the number of sales calls Lori made during the month, can be determined using the standard error of the proportion and the desired level of confidence.
To calculate the sample size, we need to use the formula:
\(n = (Z^2 * p * (1 - p)) / E^2\)
Where:
n = sample size
Z = z-score corresponding to the desired level of confidence
p = estimated proportion (historical book adoption rate)
E = margin of error (standard error of the proportion)
Given the standard error of the proportion as 0.0400, we can use this value as the margin of error (E). Assuming a 95% level of confidence, the corresponding z-score is approximately 1.96.
Plugging these values into the formula, we have:
n = (1.96^2 * 0.20 * (1 - 0.20)) / 0.0400^2
Simplifying the equation, we get:
n = (3.8416 * 0.20 * 0.80) / 0.0016
n = 0.61536 / 0.0016
n ≈ 384.6
Therefore, the sample size used in this analysis, representing the number of sales calls Lori made during the month, is approximately 385.
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Lori Jeffrey is a successful sales representative for a major publisher of college textbooks. Historicaly, Lori obtains a book adoption on 20% of her sales calls. Viewing her sales calls for one month as a sample of all possible sales calls, assume that a statistical analysis of the data yields a standard error of the proportion of 0.0400. Use z-table. How large was the sample used in this analysis? That is, how many sales calls did Lori make during the month?
A circle has centre C and radius 4 cm.
The diagram shows the circle with a point
D which lies on the circle. The tangent at D
passes through the point E. EC = √65 cm.
Find
a) the size in radians of angle DCE
b) the area of the shaded region
Step-by-step explanation:
EC = 165 cm (Given) Tangent of circle also makes 90°.
a) sind = Perpendicular Hypotenuse = CD = EC 165 => 0 = Sin = 0.519 ~ 0.52 =29.7448 ~ 29.75° =<E
By angle sum property of triangle. <D+<E+ <C = 180°
90° + 29.75 + LC = 180°
<C = 180-90-29.75 = 60.25° <C= 60.25°
<DCE = <C = 60.25 x π/180 = 1.052 radians.
(b) Area of triangle DCE = 1/2 x b x h = 1/2 x ED X 4
ED² + CD² = EC² ED² + 4² = (√65)² => EC² = 65-16 = 49 ED=7
Area = 1/2 x 7 x 4 = 14 cm²
Area of sector a π x 4²x 60.25/360 = 8.4125 cm2
Area of shaded region= Area ADCE Area of sector -
= 14-8.4125 = 5.5875 cm²
(a) <DCE = 1.052 radians b) Area shaded of region = 5.5875cm²
Solve for x plz. Ens
Answer:
9
Step-by-step explanation:
triangles always = 180 degrees
we know there is a 90 degree angle so 180-90=90
we know the other angle is 20 degrees so you do 90-20 which equals 70
now we know that the angle with x equals 70
so then you do 70-16 which equals 54
now just divide 54 by 6 and you get 9
so x=9
hope this helped ;)
Can someone please help i can’t tell which side the base would be and i don’t understand- i will mark brainliest if correct- Thanks !!
Answer:
Base = 4 units
Height = 8 units
I think the blocks are a unit each and you have to count how much space the triangle is taking up
Answer:
6
Step-by-step explanation:
Remark
This is one of those things that when you see it, you think that really is something.
The trick is to subtract a smaller right triangle from a larger one.
The base for both triangles is 4 (going from where the right angle is to your right where the lines of the red enclosure meet.
Calculations
The height of the larger triangle is 8
The height of the smaller triangle is 5
Area_L = 1/2 8 * 4 = 1/2 * 32 = 16
Area_S = 1/2 5 * 4 = 1/2 * 20 = 10
Red area = 1/2 * 32 - 1/2*20 = 16 - 10 = 6 units
The table below shows all of the possible outcomes for rolling two six-sided number cubes. 1 2 First Number Cube Second Number Cube 1 2 3 4 5 6 1,1 1,2 1,3 1,4 1,5 1,6 2,1 2,2 2,3 2,4 2,5 2,6 3,1 3,2 3,3 3,4 3,5 3,6 4,1 4,2 4,3 4,4 4,5 4,6 5,1 5,2 5,3 5,4 5,5 5,6 6,1 6,2 6,3 6,4 6,5 6,6 4 5 What is the probability of rolling an even number first and an odd number second?
Answer choices:
A. 1/9,
B. 1/6
C. 1/4
D.1/2
Answer:
(1/6)
Step-by-step explanation:
ℎ 1/6
U need help ASAP!!!Please explain the answer
help me guys I need It now answer it correctly no.4 and 5 pls
Answer:
4. 309.76π
5. 2500/π
Question 4
Step 1. Find radius
D = 2r
r = D/2
r = 35.2/2 = 17.6 cm
Step 2. Find area
A = πr²
A = π(17.6)²
A = 309.76π ≈ 973.14 cm²
Question 5
Step 1. Find radius
C = 2πr
r = C/2π
r = 100/2π = 50/π ≈ 15.92 m
Step 2. Find area
A = πr²
A = π(50/π)²
A = π(2500/π²)
A = 2500/π ≈ 795.77 m²
I hope this helps!
Question 4
Step 1. Find radius
D = 2r
r = D/2
r = 35.2/2 = 17.6 cm
Step 2. Find area
A = πr²
A = π(17.6)²
A = 309.76π ≈ 973.14 cm²
Question 5
Step 1. Find radius
C = 2πr
r = C/2π
r = 100/2π = 50/π ≈ 15.92 m
Step 2. Find area
A = πr²
A = π(50/π)²
A = π(2500/π²)
A = 2500/π ≈ 795.77 m²
i think these are right i hope this helped if not im sorry
Solve for c law of sines
Answer:
c/sin(60°) = 14/sin(25°)
c = 14sin(60°)/sin(25°) = 28.7
Best answer gets brainliest
Answer:
B
Step-by-step explanation:
Since 5 2/3 evaluated = 5 4/6
5 4/6-4 1/6 = 1 1/2
the t distribution approaches the standard normal distribution when the number of degrees of freedom increases. t/f
The statement "The t-distribution approaches the standard normal distribution when the number of degrees of freedom increases" is True.
The t-distribution approaches the standard normal distribution when the number of degrees of freedom (df) increases.
A t-distribution with a large number of degrees of freedom is similar to a standard normal distribution.
As the number of degrees of freedom increases, the distribution of t gets narrower and taller, and the distribution of Z becomes wider and flatter.
This is due to the fact that the t-distribution becomes closer to the normal distribution as the sample size grows.
When n, the sample size, is greater than or equal to 30, the t-distribution is approximately the same as the normal distribution.
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Last week’s and this week’s daily high temperatures are shown in the table below.
How much greater is this week’s median temperature than last week’s median temperature?
Answer:
The answer to your problem is, 5 degrees
Step-by-step explanation:
This week in order:
65, 71, 73, 73, 73, 74, 75 (Median= 73)
Last week in order:
51, 62, 66, 68, 72, 72, 85 (Median= 68)
73-68
= 5
Thus the answer to your problem is, 5 degrees
Help with this ASP I’ll give best awards for revision I’m stuck
It’s substitution
Answer:
P= 3w + D; d=p−3
I will solve the second part rn
Whatcha table shows a proportional relationship?
p 1 3 5 7 9
q 0 2 4 6 8
—————-
b 1 4 5 7 11
c 3 12 15 21 33
——————-
r 3 6 10 12 15
s 2 4 6 8 10
——————
x 1 2 3 4 5
y 9 10 11 12 13
Answer:
The answer is the second table (the one with B and C.)
Step-by-step explanation:
You know this, because the other tables are just based on patterns and the x and y values have nothing to do with each other. However, for the second table, the b value times 3 equals the c value. This is how you know the table shows a proportional relationship, and this is key to solving this problem.
Here's an image that helps demonstrate this idea:
Which of the following expressions are equivalent to 4^-3/4^-8? Check all that apply.
4^8/4^3
4^-8/4^-3
4^-5
4^5
Answer: 4^5
Step-by-step explanation:
4^5. when you divide exponents you just subtract them, so -3-(-8) is 5.
Laine correctly factors the expression 15A-6B+36.Using the greatest common factor, rewrite this as a factored expression
9514 1404 393
Answer:
= 3(5A -2B +12)
Step-by-step explanation:
No variables appear in all terms. We note that all coefficients are a multiple of 3, but no larger value. 3 is the GCF.
= 3(5A -2B +12)
8 cm x 10 cm x 17 cm
This figure consists of a rectangle and a quarter circle
What is the perimeter of this figure?
Use 3.14 for pi.
Answer: 2length plus 2breath circle is 2pie r
Step-by-step explanation:
perimeter of a rectangle is 2L + 2 B a
C=p+E what is the 95% confidence level of students who are planning to vote for Talia as president of the club
The the 95% confidence level of students who are planning to vote for Talia as president of the club is 33.7.
Total number of members in School Club = 80 members
Number of member randomly Selected,that is sample size used (P) = 50 members
Number of members who are planning to vote for Talia = 38 members
Z Score for 95% confidence interval =1.96
it is given that Margin of Error ,E,of the poll using a 95% confidence interval=12%
E = (Z + σ)/ √P
12/100 = (1.96 + σ)/√50
σ = 4.32890
Standard Deviation=4.3 (approx)
→95% confidence level for students who are planning to vote for Talia as president of the club lie between → 38 + 4.3 = 42.3 to 38 -4.3=33.7.
→So, members which will vote for Talia as president of the club lies between minimum of 33 members and maximum of 42 members.
Therefore, the the 95% confidence level of students who are planning to vote for Talia as president of the club is 33.7.
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∂²p/∂r² + 1/r ∂p/∂r = ϕμC/k ∂p/∂t
derivation of equations
1-partial derivative diffusivity equation spherical flow
2- partial derivative diffusivity equation hemi- spherical flow
The partial derivative diffusivity equation for spherical flow is ∂²p/∂r² + (1/r) ∂p/∂r = ϕμC/k ∂p/∂t, and for hemispherical flow, it is the same equation.
1. The partial derivative diffusivity equation for spherical flow is derived from the spherical coordinate system and applies to radial flow in a spherical geometry. It can be expressed as ∂²p/∂r² + (1/r) ∂p/∂r = ϕμC/k ∂p/∂t.
2. The partial derivative diffusivity equation for hemispherical flow is derived from the hemispherical coordinate system and applies to radial flow in a hemispherical geometry. It can be expressed as ∂²p/∂r² + (1/r) ∂p/∂r = ϕμC/k ∂p/∂t.
1. For the derivation of the partial derivative diffusivity equation for spherical flow, we consider a spherical coordinate system with the radial direction (r), the azimuthal angle (θ), and the polar angle (φ). By assuming steady-state flow and neglecting the other coordinate directions, we focus on radial flow. Applying the Laplace operator (∇²) in spherical coordinates, we obtain ∇²p = (1/r²) (∂/∂r) (r² ∂p/∂r). Simplifying this expression, we arrive at ∂²p/∂r² + (1/r) ∂p/∂r.
2. Similarly, for the derivation of the partial derivative diffusivity equation for hemispherical flow, we consider a hemispherical coordinate system with the radial direction (r), the azimuthal angle (θ), and the elevation angle (ε). Again, assuming steady-state flow and neglecting the other coordinate directions, we focus on radial flow. Applying the Laplace operator (∇²) in hemispherical coordinates, we obtain ∇²p = (1/r²) (∂/∂r) (r² ∂p/∂r). Simplifying this expression, we arrive at ∂²p/∂r² + (1/r) ∂p/∂r.
In both cases, the term ϕμC/k ∂p/∂t represents the source or sink term, where ϕ is the porosity, μ is the fluid viscosity, C is the compressibility, k is the permeability, and ∂p/∂t is the change in pressure over time.
These equations are commonly used in fluid mechanics and petroleum engineering to describe radial flow behavior in spherical and hemispherical geometries, respectively.
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A pizza shop has 18 different toppings to choose from. Today's special comes with a choice of 5 toppings, plus a choice of 3 types of crust: thin crust, regular, and deep-dish crust. How many different combinations can be made with 5 toppings and 3 crusts?
a. 25,704
b. 203,490
c. 8568
d. 270
Answer:
25,704
Step-by-step explanation:
need help asap! please!
Based on the observation the appropriate domain of the function is 12.5.
What is a function?A relation is a function if it has only One y-value for each x-value.
Given, a company manufactures and sells shirts.
The daily profit the company makes depends on how many shirts they sell.
The company sell x shirts can be found by function f(x)=7x-80
The given function is f(x)=7x-80
f(-7)=7(-7)-80=-49-80
=-129
The value is negative so it is not the answer.
f(8)=7(8)-80
=56-80=-24
The value is negative so it is not the answer.
f(12.5)=7(12.5)-80
=87.5-80
7.5
The company sells 12.5 shirts.
Hence, based on the observation the appropriate domain of the function is 12.5.
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help me bro. easy 100 points for you right here.
Answer:
b:8 c:4 just look at the table and the graph for the increase of money spent for the rides
What is 39700.0947 in scientific notation ?
Please help! Correct answer only!
In a raffle, one ticket out of 200 will win a $980 prize, one ticket will win a $950 prize, one ticket will win a $270 prize, and one ticket will win a $260 prize. The remaining tickets will win nothing. If you have a ticket, what is the expected payoff?
Answer:
" Expected Payoff " - $ 12.30
Step-by-step explanation:
Consider the steps below;
\(Total Number of Tickets - 200 Tickets,\\Tickets Entered - 1 Ticket,\\\\Proportion - 1 / 200\\\\Amount Won ( First ) = 980 Dollars,\\Amount Won ( Second ) = 950 Dollars,\\Amount Won ( Third ) = 270 Dollars,\\Amount Won ( Fourth ) = 260 Dollars\\\\Proportionality ( First ) - 1 / 200 = x / 980,\\Proportionality ( Second ) - 1 / 200 = x / 950,\\Proportionality ( Third ) - 1 / 200 = x / 270,\\Proportionality ( Fourth ) - 1 / 200 = x / 260,\\\\1 / 200 = x / 980,\\200 * x = 980,\\x = 4.90,\\\\\)
\(1 / 200 = x / 950,\\200 * x = 950,\\x = 4.75,\\\\1 / 200 = x / 270,\\200 * x = 270,\\x = 1.35,\\\\1 / 200 = x / 260,\\200 * x = 260,\\x = 1.3\)
\(Conclusion ; " Expected Payoff " = 4.90 + 4.75 + 1.35 + 1.3 = 12.30\)
how long in seconds does it take for an object to hit the sidewalk if dropped from a 400 foot tall building
please help my grade is bad in math
Answer:
Using the free fall calculator from omnicalculator.com, we can determine the time it takes for an object to hit the sidewalk when dropped from a 400-foot tall building. Assuming the object is dropped from rest (v₀ = 0), we use the formula s = (1/2)gt², where s is the distance fallen, g is the acceleration due to gravity (9.80665 m/s²), and t is the time of fall.
First, we convert 400 feet to meters, approximately 121.92 meters. Then, we plug in the values into the formula and solve for t:
121.92 = (1/2) * 9.80665 * t²
Simplifying the equation, we get:
t² = 121.92 / 4.903325
t² = 24.8
t ≈ 4.98 seconds Thus, an object dropped from a 400-foot tall building takes approximately 4.98 seconds to hit the sidewalk.
What’s the answer to this?
Answer:
See attached image.
250 shirts at $50/shirt is the equilibrium.
Step-by-step explanation:
The graph of function f passes through points (0,3) and (4,6). Use function notation to write information each point gives us about function f
The linear function passing through points (0,3) and (4,6) is defined as follows:
f(x) = 0.75x + 3.
How to define the linear function?The slope-intercept definition of a linear function is given as follows:
y = mx + b.
In which the parameters are given as follows:
m is the slope, representing the rate of change of the linear function.b is the y-intercept, representing the value assumed by the function when x assumes a value of zero.The function passes through point (0,3), meaning that when x = 0, y = 3, hence the intercept b is given as follows:
b = 3.
Given two points, the slope is calculated as the change in y divided by the change in x, hence:
m = (6 - 3)/(4 - 0) = 3/4 = 0.75.
Thus the linear function f(x) is defined as follows:
f(x) = 0.75x + 3.
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Random assignment of subjects to different experimental conditions is a method of controlling differences between:
The random assignment of subjects to different experimental conditions is a powerful method of controlling differences between groups of participants in an experiment. It is a technique used in experimental design to ensure that the differences observed between groups are not due to any pre-existing differences between the groups.
Random assignment is used to create groups that are as similar as possible in terms of all possible factors that might affect the outcome of the experiment. By randomly assigning subjects to different experimental conditions, researchers can be confident that any differences between groups are due to the manipulation of the independent variable and not to pre-existing differences between the groups.
The process of random assignment involves selecting participants from a pool of eligible candidates and assigning them to different groups at random. This can be done in a variety of ways, including using a computer program to generate random assignments, using a random number table, or drawing names out of a hat.
Random assignment ensures that each participant has an equal chance of being assigned to any of the different experimental conditions. This means that there is no systematic bias in the assignment of participants to different groups, which helps to ensure that any differences observed between groups are due to the experimental manipulation and not to any pre-existing differences between the groups.
In summary, random assignment of subjects to different experimental conditions is an important method of controlling differences between groups in an experiment. It helps to ensure that any differences observed between groups are due to the experimental manipulation and not to any pre-existing differences between the groups.
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rewrite triple integral: integral 0 to 1, integral 0 to x, integral 0 to sqrt(1-x^2) z dz dy dx in the order dy dx dz and evaluate it.
The evaluated value of the triple integral is 7/120.
To rewrite the triple integral in the order dy dx dz, we need to reverse the order of integration. Therefore, the new integral becomes:
∫∫∫z dz dy dx
The limits of integration for each variable are as follows:
z: 0 to √(1 - x²)
y: 0 to x
x: 0 to 1
Now we can evaluate the triple integral in the order dy dx dz:
∫∫∫z dz dy dx = ∫∫[\(z^{2/2}\)] dy dx
= ∫[∫[\(z^{2/2}\)] dy] dx
= ∫[∫[x\(z^{2/2}\)] from y=0 to y=x] dx
= ∫[∫[(x(\(\sqrt(1 - x^2))^2)/2\)] from y=0 to y=x] dx
= ∫[∫[\((x*(1 - x^2))/2\)] from y=0 to y=x] dx
= ∫[∫[\((x - x^3)/2\)] from y=0 to y=x] dx
= ∫[(∫[(\(x - x^3)/2\)] from y=0 to y=x)] dx
= ∫[\((x^2/2 - x^4/4)/2\)] dx
= ∫[\((2x^2 - x^4)/8\)] dx
= (1/8)∫[\(2x^2 - x^4\)] dx
= (1/8) [\((2/3)x^3 - (1/5)x^5\)] from 0 to 1
= (1/8) [((2/3) - (1/5)) - (0 - 0)]
= (1/8) [(10/15) - (3/15)]
= (1/8) (7/15)
= 7/120
= 7/120
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someone help me pls 10 points
Answer:
x=-5
Step-by-step explanation: