The specific heat capacity of water is 4,200 J/kg °C.
Calculate the thermal energy that must be
absorbed by 1.4 kg of water to increase its
temperature by 25 °C.
help TvT
A positive charge enters a uniform magnetic field directed to the right, and is headed upward. What is the direction of the magnetic force
The direction of the magnetic force on the positive charge would be perpendicular to both the direction of the velocity of the charge (upward) and the direction of the magnetic field (to the right), in accordance with the right-hand rule. Therefore, the magnetic force would be directed out of the page (or into the screen) in this scenario.
Step 1: Place your right hand flat with your fingers extended.
Step 2: Point your thumb in the direction of the positive charge's motion (upward).
Step 3: Point your fingers in the direction of the magnetic field (to the right).
Step 4: Curl your fingers in the direction of the magnetic field.
Step 5: Your palm will now be facing the direction of the magnetic force.
Following these steps, the direction of the magnetic force on the positive charge is out of the plane, towards you.
to know more about the magnetic field here:
brainly.com/question/14848188
#SPJ11
1.
David is 10% taller than Peter and Peter is 5% shorter than John. It is given that the height of Peter
is 171 cm.
(a) Find the height of John.
Iso
(2 marks)
(b) David claims that he is the tallest person among the three. Do you agree? Explain your answer.
(2 marks)
Answer:
I don't know if I can help you with that
A vertical U-shaped nibe is filled with a liquid of density p and the right end of the rube is sealed with a copper, as shown in the left figure. Some of the liquid is removed from the left column with a syringe and the left column descends a distance d, while the right column remains as it was. Refer to the right figure UE B 50% Part (a) Three students are debating Student A The pressure at level C must now be greater than the atmospheric pressure because liquid there is being pushed up against the stopper. Student B: I think the pressure at level B must be the same as at level A, because they are at the same level Both are at atmospheric pressure So the pressure at level C must be lower than atmospheric, because pressure decreases as you ascend Student C. But the liquid is denser than air, so the pressure at C cannot be less than atmospheric pressure. With which student(s) should you agree? B V Correct! D A 50%% Part (b) Calculate the pressure difference, in pascals, between levels C and A. AP - PC - PA. for p = 0.8/: 10' kgym and d - 4 cr Grade Summary
The liquid is being forced up against the stopper, Student A correctly asserts that the pressure at level C must be higher than air pressure.
Thus, The right column pulls down on the stopper when the liquid is taken from the left column, adding pressure to the liquid at level C.
The pressure at level C rises above atmospheric pressure as a result of this increased force.
Student C also presents a convincing argument when he claims that because the liquid is denser than air, the pressure at level C cannot be lower than atmospheric pressure. Pressure in a fluid rises with depth because of the weight of the fluid above.
ΔP = P_C - P_A, where P_C denotes the pressure at level C and P_A is the pressure at level A, and P denotes the pressure difference. Since the pressures at levels C and A are equal because they are at the same height, there is no pressure difference (P = 0). As a result, there is no pressure difference between level C and level A.
Thus, The liquid is being forced up against the stopper, Student A correctly asserts that the pressure at level C must be higher than air pressure.
Learn more about Pressure, refer to the link:
https://brainly.com/question/29341536
#SPJ4
A rock is dropped from a bridge and hits the water 1.5 seconds later. How high is the bridge?
Given the electric flux density determine a) rhov using the differential form of Gauss's Law. b) The total charge Q enclosed in a cube 2 m located in the first quadrant with one of its corners at the origin using the results of part a), and c) The total charge Q in the cube using the integral form of Gauss's Law. Dx(x,y):=4⋅(x+y)⋅C/m^2
Dy(x,y):=(3⋅x−1⋅y)⋅C/m^2
The electric flux density is given as Dx(x, y) = \(4(x + y) C/m^2$ and Dy(x, y) = (3x - y) C/m^2.\) Using Gauss's Law, the price density ρv is discovered to be ε * 3.
The general charge enclosed in a cube may be calculated by integrating ρv over the quantity of the cube. The critical form of Gauss's Law relates the electric flux Φ thru a closed surface to the overall charge Q enclosed.
To clear up the hassle, we will use the differential and indispensable varieties of Gauss's Law. Let's pass step by step:
a) Using the differential form of Gauss's Law, which states that the divergence of the electric flux density (D) is identical to the charge density (ρv) divided by using the permittivity of the medium (ε):
∇ · D = ρv / ε
Given the electric flux density components:
\(Dx(x, y) = 4(x + y) C/m^2\\Dy(x, y) = (3x - y) C/m^2\)
We can discover the fee density ρv by means of taking the divergence of D:
∇ · D = ∂Dx/∂x + ∂Dy/∂y
∂Dx/∂x = 4
∂Dy/∂y = -1
∇ · D = 4- 1 = 3
Therefore, ρv = ε * (∇ · D) = ε * 3
b) To discover the whole fee Q enclosed within the dice, we want to integrate the fee density ρv over the volume of the dice. Since the cube has a side length of 2 m and is placed in the first quadrant with one nook at the foundation, its volume is \((2 m)^3= 8m^3\). Thus:
Q = ∫∫∫ ρv dV
Q = ∫∫∫ ε * 3 dV
Q = ε * 3 * ∫∫∫ dV
Q = ε * 3* (extent of the cube)
Q = ε * 3* 8m³
c) Using the fundamental form of Gauss's Law, which states that the electrical flux (Φ) through a closed floor is equal to the entire charge (Q) enclosed divided with the aid of the permittivity of the medium (ε):
Φ = Q / ε
We can rewrite this equation as:
Q = Φ * ε
To discover the electric flux Φ, we want to assess the floor essential of the electric flux density (D) over a closed surface enclosing the dice. Since the electric flux density is given, we are able to calculate:
Φ = ∫∫ D · dA
wherein dA is a vector detail of the floor place.
Finally, we can calculate the total charge Q the usage of Q = Φ * ε.
To know more about integration,
https://brainly.com/question/30215870
#SPJ4
xy+4z=
X=2
Y=2
Z=3
Solve for
Answer:
x×y=2×2=4. 4×z=4×3=12. 4+12=16
an object is located 85 cm from a convex lens the focal point is 25 cm what is the average distance is the image real or virtual brainly
The image is real and is found at a distance of 33.33cm.
What is a convex lens?The term lens is used to describe any refracting surface. We know that a lens could be concave or convex in nature. Given that fact, we are to find the nature of the image that is formed by the convex lens.
Also;
1/f = 1/u + 1/v
1/v = 1/f - 1/u
f = focal length
u = object distance
v = image distance
1/v = 1/25 - 1/85
1/v = 0.04 - 0.001
v = 33.33cm
The image is real and is found at a distance of 33.33cm.
Learn ore about image distance:https://brainly.com/question/12629638
#SPJ1
A stone falls freely from rest for 8.0s what is it final velocity
The work function for metallic cesium is 2.14eV. Calculate the kinetic energy and the speed of the electrons ejected by light of wavelength: a) 740 nm b) 350 nm
Answer: (a) The speed is zero.
(b) The speed of the electrons ejected by light of wavelength 350 nm is 6.0 × 10⁵ m/s.
a) Let's find out the energy of the incident light by using E = hc/λ
where E is the energy, h is Planck's constant, c is the speed of light, and λ is the wavelength of the light. Here we have λ = 740 nm = 7.4 × 10⁻⁷m
So, E = hc/λ
= (6.63 × 10⁻³⁴ J.s × 3 × 10⁸ m/s)/(7.4 × 10⁻⁷m)
= 2.69 × 10⁻¹⁹ J.
Since the work function is given in electron volts, we need to convert the energy into eV.1 eV = 1.6 × 10⁻¹⁹ J2.69 × 10⁻¹⁹ J = (2.69 × 10⁻¹⁹ J / 1.6 × 10⁻¹⁹ J/eV) = 1.68 eVThe kinetic energy of the ejected electron can be calculated as the difference between the energy of the incident light and the work function.KE = E - Φ = 1.68 eV - 2.14 eV = -0.46 eV. Since the electron has a negative kinetic energy, it is not ejected. Therefore, the speed is zero.
b) To find the speed, we can use the formula: KE = 1/2 mv²
v = √(2KE/m)
The mass of the electron is 9.11 × 10⁻³¹ kg. So,
v = √(2 × 1.41 eV × 1.6 × 10⁻¹⁹ J/eV / 9.11 × 10⁻³¹ kg)= 6.0 × 10⁵ m/s.
Therefore, the speed of the electrons ejected by light of wavelength 350 nm is 6.0 × 10⁵ m/s.
Learn more about wavelength : https://brainly.com/question/10750459
#SPJ11
You can use the following questions to probe student understanding of the online resources and to transition back to the microwave oven phenomenon.
Microwaves are very efficient at heating water, but all electromagnetic waves can cause matter to heat up. Why is this?
The transfer of energy causes atoms and molecules to vibrate more rapidly, which in turn causes matter to heat up.
Why do all electromagnetic waves cause matter to heat up?All electromagnetic waves, including microwaves, are forms of energy that oscillate at specific frequency. When waves interact with matter, they transfer their energy to atoms and molecules within that matter. This transfer of energy causes atoms and molecules to vibrate more rapidly, which causes the matter to heat up.
Microwaves are particularly efficient at heating water because frequency is in the range that matches natural resonance frequency of water molecules. This means that they transfer energy more efficiently to water molecules, which results in faster heating as compared to other forms of electromagnetic waves.
To know more about electromagnetic waves, refer
https://brainly.com/question/25847009
#SPJ4
cold weather can increase tire pressure, so you should always deflate them a bit before driving. true false
The given statement "cold weather can increase tire pressure, so you should always deflate them a bit before driving. " is False.
In general, cold weather can cause the air inside tires to contract, which can result in a decrease in tire pressure. However, in some cases, cold weather can actually increase tire pressure. This is because the air inside the tires becomes denser in colder temperatures, and denser air can result in an increase in tire pressure.
It's important to note that tire pressure is critical for safe driving. Underinflated tires can affect handling and increase the risk of a blowout, while overinflated tires can reduce traction and increase the risk of hydroplaning. Therefore, it's essential to check tire pressure regularly and adjust it as needed, regardless of the weather conditions.
If you're unsure whether the cold weather has caused an increase or decrease in tire pressure, the best course of action is to check the tire pressure with a gauge and adjust it as needed based on the manufacturer's recommended pressure for your vehicle. Deflating the tires without first checking the pressure can lead to underinflation, which can be just as dangerous as overinflation.
To know more about temperatures refer here
https://brainly.com/question/31056486#
#SPJ11
Movement of a body part around a central point or axis is known as:
a) Flexion
b) Extension
c) Rotation
d) Abduction
The movement of a body part around a central point or axis is known as rotation.
Rotation refers to the circular movement of a body part around its axis or a fixed point. It involves the turning or twisting motion of a body segment without changing its position in space.
Flexion (a) is the movement that decreases the angle between two body parts, typically bending or decreasing the joint angle. The extension (b) is the opposite movement, increasing the angle between two body parts, typically straightening or increasing the joint angle. Abduction (d) refers to the movement of a body part away from the midline of the body.
During rotation, the body part or segment moves around an imaginary line called the axis. This axis can be within the body itself or located externally. For example, when we rotate our head from side to side, the axis of rotation is an imaginary line passing through the neck.
To know more about rotation, visit:
https://brainly.com/question/29255792
#SPJ11
a single-turn circular loop of radius 9.6 cm is to produce a field at its center that will just cancel the earth's field of magnitude 0.7 g directed at 70degrees below the horizontal north direction. find the current in the loop.
The current required in the loop depends on the Earth's magnetic field and the size of the loop.
The Earth's magnetic field goes in all directions, and one way to cancel out its force is to create a loop with an electric current flowing through it. To create a field of 0.7 g at the center of a single-turn circular loop of radius 9.6 cm, a certain amount of current must flow through its wire.
While exact calculation of the exact amount of current requires complex math, it can be determined through the use of the right-hand rule and an understanding of magnets and magnetic fields. Using this rule, one can find out the direction of the current-induced field created by the loop and its magnitude, and if the magnitude and direction of the current-induced field is the same as the Earth's magnetic field, then the forces will cancel out.
know more about current here
https://brainly.com/question/15141911#
#SPJ11
1 2 3 4 5 6 7 8 9 10 Physical activity and exercise typically lead to __________. A. increased stress B. depression C. higher energy levels D. reduced quality of life Please select the best answer from the choices provided. A B C D
Physical activity and exercise typically lead to higher energy levels (C).
What is physical activity and exercise?Physical activity and exercise refer to any bodily movement that requires energy expenditure by the muscles. This can include activities such as walking, running, cycling, swimming, weightlifting, and team sports, among others.
Physical activity and exercise are important for maintaining good health and well-being, as they can help to improve cardiovascular fitness, muscular strength and endurance, flexibility, and overall body composition.
Physical activity and exercise are known to stimulate the production of endorphins, which are natural mood elevators. This can lead to increased energy levels and a general feeling of well-being.
Learn about exercise here https://brainly.com/question/13490156
#SPJ1
a roller coaster containing three cars is accelerating at 10 m/s2 before it comes to an abrupt stop at the end of the ride. the mass of one car is 300 kg. how much force was exerted on the roller coaster to bring it to a stop?
The roller coaster needs to be stopped with a force of 9000 N.
What is force and example?The term force refers to the tendency of a body to modify or change its state as a result of an outside factor. Additionally, a force applied to the body can cause it to change in size, shape, and direction. Like kicking a ball, opening and closing doors, or kneading dough, for instance.
The magnitude of acceleration of car a is = 10m/s²
The mass of each car is, m = 300kg
According to Newton's second law, force is calculated as the sum of an object's mass and acceleration. The force applied to each car is then,
F = ma
And the roller coaster is subject to the following force,
F' = 3F
F' = 3×300×10
F' = 9000N
Therefore, we can say that the roller coaster required 9000 N of force to stop.
To know more about force visit:
https://brainly.com/question/17945621
#SPJ4
What is the magnitude of the force F on the 1.0 nC charge in the figure ?
The magnitude of the force F on the 1.0 nC charge in the figure is the positive charge and force F is 8 x 10^9 N (8 Giga Newtons).
The force F on the 1.0 nC charge in the figure can be calculated using Coulomb's law, which states that the force between two point charges is proportional to the inversely proportional to the square of the distance between the charges and a product of the charges. The magnitude of the force can be calculated using the following formula:
|F| = k x |q1| x |q2| / r^2
where k is the Coulomb constant (9 x 10^9 Nm^2/C^2), q1 and q2 are the charges (in Coulombs), and r is the distance between the charges (in meters).
In this case, q1 = 1.0 nC = 1.0 x 10^-9 C and q2 = -1.0 nC = -1.0 x 10^-9 C (since the charges are opposite and the force is attractive) and r = 0.1 m.
So, the magnitude of the force F can be calculated as:
|F| = k x |q1| x |q2| / r^2 = (9 x 10^9 Nm^2/C^2) x (1.0 x 10^-9 C) x (-1.0 x 10^-9 C) / (0.1 m)^2 = 8 x 10^9 N
The magnitude of the force F is 8 x 10^9 N (8 Giga Newtons)
It's important to note that the direction of the force is from the positive charge.
To know more about force please refer: https://brainly.com/question/13191643
#SPJ4
define equilibrium position, displacement and amplitude as they relate to a wave
The equilibrium position is the undisturbed state of a medium, displacement is the change in position of a particle due to the wave, and amplitude is the maximum displacement of a particle from its equilibrium position, indicating the energy carried by the wave.
The equilibrium position, displacement, and amplitude are essential terms related to wave motion. Let's define each term as it relates to a wave:
1. Equilibrium position: The equilibrium position is the undisturbed or rest position of a medium or a particle when no wave is passing through it. In other words, it is the point at which the medium is not experiencing any net force, and no energy is being transmitted through it. When a wave propagates through the medium, the particles oscillate about this equilibrium position.
2. Displacement: Displacement refers to the change in the position of a particle in a medium as it oscillates due to the wave passing through it. It is the distance between the current position of the particle and its equilibrium position. Displacement can be measured both horizontally and vertically, depending on the type of wave (transverse or longitudinal).
3. Amplitude: Amplitude is the maximum displacement of a particle from its equilibrium position as it oscillates due to the wave passing through it. It is a measure of the wave's energy, as a wave with a larger amplitude carries more energy than a wave with a smaller amplitude. The amplitude can be observed as the height of a crest or the depth of a trough in a transverse wave, or as the maximum compression or rarefaction in a longitudinal wave.
Learn more about equilibrium:
https://brainly.com/question/517289
#SPJ11
Chelsea is riding in a bike-a-thon. the total distance for the bike-a-thon is 38.7 miles. so far, chelsea has completed 1/10 (one tenth) of the bike-a-thon. how many miles is that?
Chelsea has completed 3.87 miles so far in the bike-a-thon. The term "miles" is a unit of length or distance that used in various systems of measurement. The most common use of "miles" refers to the statute mile, which is used in the United States and several other countries and the symbol for the mile is "mi."
The bike-a-thon is a total of 38.7 miles. Chelsea has completed 1/10 of the bike-a-thon. To find out how many miles she has completed, we need to divide the total distance by 10 (since she has completed one tenth).
38.7 miles ÷ 10 = 3.87 miles
Therefore, Chelsea has completed 3.87 miles so far in the bike-a-thon.
To know more about miles, refer
https://brainly.com/question/29806974
#SPJ11
explain it if u know please
Answer: B
Explanation: The straight line shows the theoretical average of the actual velocity and the curved line show that it is less than the average velocity of the object within 6 seconds.
straight line:
3. 3,80
6. 6,160
curved line:
1,22,173,324,605,1006,160A.K.A.-- the only place where the straight line and the curved line meet at is only at coordinate 6,160.
A box having a mass of 1.5 kg is accelerated across a table at 1.5 m/s2. The coefficient of friction on the box is 0.3. What is the force being applied to the box? If this force were applied by a spring, what would the spring constant have to be in order for the spring to be stretched to only 0.08 m while pulling the box?
Why is figure 5 an unhelpful visualization tool for this data set?
Please help!
Explanation:
Because the temperature and the radiation are not correlated, they're not represented as functions of each other, they're represented as independent variables thus using graph 5 you cannot figure out how one affect another
Answer:
It doesn’t show how temperature and radiation relate to each other. It’s difficult to draw conclusions from data that’s separated this way.
Hola cómo están todos
Classify each of the following activities as unit level, batch level, product level, or facility level for a manufacturer of tennis balls
Unit Level means assembling the individual components of a tennis ball, such as the felt and rubber pieces. Batch Level indicates testing a batch of tennis balls for quality control.
1. Receiving felt shipments - Batch Level: Receiving shipments of felt is a batch-level activity because it involves specific batches of felt that are associated with a particular production run.
2. Cutting felt - Unit Level: Cutting felt is a unit-level activity because it involves cutting individual pieces of felt for use in the production process.
3. Forming rubber cores - Unit Level: Forming rubber cores is a unit-level activity because it involves creating individual pieces of rubber for use in the production process.
4. Reducing electricity usage - Facility Level: Reducing electricity usage is a facility-level activity because it involves the entire facility, not just the production of tennis balls.
5. Calibrating machines - Facility Level: Calibrating machines is a facility-level activity because it involves ensuring that all of the machines in the facility are operating correctly and efficiently.
6. Planning production - Facility Level: Planning production is a facility-level activity because it involves determining how the facility will operate in order to meet production goals.
To learn more about electricity click here https://brainly.com/question/12791045
#SPJ4
complete question: Classify each of the following activities as unit level, batch level, product level, or facility level for a manufacturer of tennis balls. Activity level: 1. Receiving felt shipments 2. Cutting felt 3. Forming rubber cores 4. Reducing electricity usage 5. Calibrating machines 6. Planning production.
I
WILL GIVE BRAINLIST JUST PLZ HURRY!!! Read about Manny's investigation then answer the questions.
1. What is a benefit of Manny's electromagnet?
2. What are two things Manny could do to increase the strength of the electromagnetic force?
; 3. Look at the picture closely. What evidence is there that the electromagnet exerts a force on the
paper clips, even though they are not touching?
4. Many detaches the two wires from the battery and reattaches them to the opposite terminals.
Explain how this changes the current and magnetic field.
5. Suppose you pull the paperclips away from the nail. Explain how the potential energy between
the paperclips and the nail changes.
Answer:
1.The main advantage of an electromagnet over a permanent magnet is that the magnetic field can be quickly changed by controlling the amount of electric current in the winding. However, unlike a permanent magnet that needs no power, an electromagnet requires a continuous supply of current to maintain the magnetic field.
a 41 g particle is moving to the left at 27 m/s . how much net work must be done on the particle to cause it to move to the right at 47 m/s ?
The net work required to cause the particle to move to the right at 47 m/s is 30.102 Joules.
To determine the net work required to change the particle's velocity from moving left at 27 m/s to moving right at 47 m/s, we can use the work-energy principle.
The work-energy principle states that the net work done on an object is equal to the change in its kinetic energy.
The kinetic energy of a particle is given by the equation:
KE = (1/2) * m * v^2
where m is the mass of the particle and v is its velocity.
Let's calculate the initial kinetic energy (KE_initial) and final kinetic energy (KE_final) of the particle.
Given:
Mass of the particle (m) = 41 g = 0.041 kg
Initial velocity (v_initial) = -27 m/s (negative sign indicates motion to the left)
Final velocity (v_final) = 47 m/s
Calculate the initial kinetic energy:
KE_initial = (1/2) * m * v_initial^2
= (1/2) * 0.041 * (-27)^2
= 0.5 * 0.041 * 729
= 14.9575 J
Calculate the final kinetic energy:
KE_final = (1/2) * m * v_final^2
= (1/2) * 0.041 * 47^2
= 0.5 * 0.041 * 2209
= 45.0595 J
Calculate the net work done:
Net work = KE_final - KE_initial
= 45.0595 - 14.9575
= 30.102 J
Therefore, the net work required to cause the particle to move to the right at 47 m/s is 30.102 Joules.
To learn more about work, click here:
https://brainly.com/question/18094932
#SPJ11
A uniformly charged rod (length = 2.0 m, charge per unit length = 3.0 nC/m) is bent to form a semicircle. What is the magnitude of the electric field at the center of the circle? Select one: O a. 64N/C b. 85N/C c. 34N/C 3 d. 133Njc -j e.48N/C
Answer:
The magnitude of the electric field at the center of the circle is 85 N/C
The correct option is b. 85 N/C
Explanation:
Please see the attachments below
What is the force that causes a 8 kg object to accelerate at 4 m/s^2
Answer: F = 32 N
Explanation:
F= m x a
m = 8 kg
a = 4 m/s²
F = 8 kg x 4 m/s² = 32 kg m /s² = 32 Newton
How can a person best reduce the risk of sustaining permanent injuries?
- Wear protective clothing while sleeping at home.
- Secure a seat belt only when riding in the front seat.
- Wear a cracked bicycle helmet while riding a bicycle.
- Put away guns in a lockbox that is secure and in a discrete location.
Answer:
Put away guns in a lockbox that is secure and in a discrete location
Explanation: Took the test. Trust me ;)
Answer:
Put away guns in a lockbox that is secure and in a discrete location
Explanation: Just Trust Me
you have a positive test charge brought near a negatively charged bal. describe what is happening if you move the test charge even closer.
If you move a positive test charge closer to a negatively charged ball, the electric field between the two charges will become stronger. As the electric field strength increases, the force of attraction between the two charges also increases, causing the test charge to be pulled towards the ball.
As the test charge moves closer to the ball, the electric field will become more intense and the force of attraction between the two charges will become even stronger. This can cause the test charge to accelerate towards the ball at an increasing rate, until it comes into contact with the ball and is attracted to it.
If the test charge is moving very slowly, it may take some time for it to be attracted to the ball, and it may seem as though the force of attraction is gradually increasing as it gets closer. However, as the test charge gets closer to the ball, the electric field will become stronger and the force of attraction will become more powerful, causing the test charge to be pulled towards the ball more rapidly.
Learn more about test charge Visit: brainly.com/question/22380358
#SPJ4