The wire A and B are made of copper. Both w
wires are in
long but wire A is 1mm thick and wire B is 2mm thick, the
specific resistance is
a) more than A
b) more than B
c) same for both
d) cannot compared​

Answer:

Resistance is proportional to length and inversely proportional to area.

L1 =  5 cm

L2 = 10 cm

L3 = 15 cm

A1 = k * (.50 cm)^2

A2 = k * (.25 cm)^2 = 1/4 A1

A3 = k * (.05 cm)^2= 1/100 A1

R1 = 1 * 1 = 1

R2 = 2 * 4 = 8 R1

R3 = 3 * 100 = 300 R1

R3 has greatest resistance

Dressing suitably for different situations, using appropriate language, and maintaining good personal hygiene are all ways to demonstrate self-representation.

A person taking the charge of the organization and leading a team under him is known as a leader.

"The complete question is"Dressing suitably for different situations, using appropriate language, and maintaining good personal hygiene are all ways to demonstrate _______________. An employee will display _______________ by adhering to professional standards of the workplace and encouraging co-workers to do the same."

Options:

First Blank: work ethic

First Blank: self-representation

First Blank: diversity awareness

Second Blank: leadership skills

Second Blank: nonverbal skills

Self-representation may be shown through dressing appropriately for diverse settings, speaking politely, and keeping up with personal cleanliness.

By upholding the workplace's ethical norms and encouraging others to do the same, an employee will demonstrate leadership qualities.

Dressing suitably for different situations, using appropriate language, and maintaining good personal hygiene are all ways to demonstrate self-representation.

An employee will display leadership skills by adhering to the professional standards of the workplace and encouraging co-workers to do the same.

Hence, self-representation and leadership skills are the correct answer.

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Answer:

The two main factors that affect kinetic energy are mass and speed.

Explanation:

Kinetic energy is the energy that is caused by the motion. The kinetic energy of an object is the energy or force that the object has due to its motion. Your moving vehicle has kinetic energy; as you increase your vehicle's speed, your vehicle's kinetic energy increases.

Have a great day! :D

the magnitude of the friction force on the disk is approximately 1.16 N.

We can use the conservation of energy to find the friction force on the disk. The initial kinetic energy of the wheel is equal to the work done by the friction force on the disk:

K_i = W_friction

The initial kinetic energy of the wheel can be found from its moment of inertia and angular velocity:

K_i = (1/2) I \(ω^2\)

where I is the moment of inertia, ω is the angular velocity, and the factor of 1/2 comes from the rotational kinetic energy formula.

The final kinetic energy of the wheel is zero, since it comes to a stop. The work done by the friction force can be found from the distance over which it acts:

W_friction = F_friction d

where F_friction is the friction force and d is the distance over which the pads act on the disk. We can find the distance from the angular displacement of the wheel:

θ = ω t

where θ is the angle through which the wheel rotates, t is the time for the wheel to come to a stop, and the factor of 1/2π converts from rotations to radians. The distance over which the pads act is then:

d = r θ = 0.071 m × (5/2π) ≈ 0.562 m

Now we can put everything together:

K_i = W_friction

(1/2) I \(ω^2\) = F_friction d

We can solve for the friction force:

F_friction = (1/2) I \(ω^2\) / d

Plugging in the given values:

F_friction = (1/2) ×\(0.097 kg⋅m^2\) × \((5/2.2π rad/s)^2\) / 0.562 m ≈ 1.16 N

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The compressive stress in the steel column is found to be approximately 397.6 MPa.

The formula for calculating the area of a circle can be used to determine the steel column's cross-sectional area (A),

A = π*(d/2)², diameter of the column is d,

A = π*(0.4/2)²

A = 0.1257m²

The compressive stress (σ) in the column can be calculated using the formula, σ = F/A, F is the load carried by the column is F.

σ = 50 MN/0.1257m²

σ = 397.6 MPa

Therefore, the compressive stress in the steel column is approximately 397.6 MPa.

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Answer:

B

Explanation:

A tractor is the heaviest

This question involves the concepts of work done and the frictional force.

a. Work done by the person is "692.82 N".

b. Work done by the frictional force is "490.5 N".

a.

Work done by the person can be given by the following formula:

\(W=FdCos\theta\)

where,

W = work done by the person = ?

F = Force applied by the person = 80 N

d = distance traveled = 10 m

θ = angle between force and motion = 30°

Therefore,

\(W=(80\ N)(10\ m)Cos30^o\)

W = 692.82 N

b.

Work done by the frictional force is given by the following formula:

\(W_f=fd\\W_f=\mu mgd\)

where,

\(W_f\) = work done by the frictional force = ?

μ = coefficient of friction = 0.5

g = acceleration due to gravity = 9.81 m/s²

Therefore,

\(W_f=(0.5)(10\ kg)(9.81\ m/s^2)(10\ m)\)

\(W_f=490.5\ N\)

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Let the circumference of the circle be 10L.

A moves at 10L/2 = 5L per hour

B moves at 10L/5 = 2L per hour

Therefore it takes 10L/(5L+2L) = 10/7 hours

A white-hot iron piece has internal motion energy due to constant particle movement at the atomic and molecular levels, as per scientists. Thermal energy or heat energy is motion. Higher temperature means more kinetic energy and faster motion of atoms and molecules.

White-hot iron vibrates atoms and molecules at high temperatures. Kinetic theory states that all matter is made up of moving particles. Motion occurs at the microscopic level, beyond eye view. Higher temperature = greater particle energy.

When a scientist refers to white-hot iron, they recognize its high temperature corresponds to increased kinetic energy and motion. Motion and energy at the atomic level are not visible like a bowling ball, but are fundamental traits of matter.

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The time taken by the cars to meet is 5.4 x 10³ s.

Speed of car A, v₁ = 45 km/h = 12.5 m/s

Speed of car B, v₂ = 55 km/h = 15.27 m/s

Distance between the cars, d = 150 km = 15 x 10⁴m

The expression for the time taken by the cars to meet can be given as,

Time = Distance/Average speed

t = d/(v₁ + v₂)

Applying the values of d, v₁ and v₂.

t = 15 x 10⁴/(12.5 + 15.27)

t = 15 x 10⁴/27.77

t = 5.4 x 10³ s

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Answer:

Explanation:

Conservation of angular momentum

2(2000) + 5(-100) = (2 + 5)ω

ω = 500 rad/s

as the result is positive, the direction is in the same direction as the originally 2000 rad/s motion which we had assumed as the positive direction

Vehicles need to be serviced for several reasons such as preventing costly repairs and improving fuel economy.

First, regular maintenance can help to prevent costly repairs down the road. Second, maintenance can help to improve fuel economy and emissions. Third, maintenance can help to keep your vehicle safe and reliable.

The servicing requirements for petrol/diesel and electric vehicles differ in a number of ways. Petrol/diesel vehicles require oil changes more frequently than electric vehicles. This is because petrol/diesel engines use oil to lubricate the moving parts, while electric motors do not. Petrol/diesel vehicles also require tune-ups more frequently than electric vehicles.

This is because petrol/diesel engines have more moving parts that need to be synchronized, while electric motors have fewer moving parts.

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Answer:

B. A student asking others to join the leadership club.

Explanation:

A parent isn't a peer, therefore can't be peer pressure. Drinking is negative for your body, therefore not positive peer pressure. A teacher isn't a peer, therefore the only answer left is B.

Answer:

2,400kg * m/s

Explanation:

You are missing some information in the question but the rest could be found some where else.

The question gives the masses and starting velocity of each car.

Car 1: m = 600kg and sv = 4m/s

Car 2: m 400kg and sv = 0m/s

Find the momentum of both cars.

Car 1: 600 * 4 = 2400

Car 2: 400 * 0 = 0

Add both.

2400 + 0 = 2400

Best of Luck!

Answer: answer C

Explanation:

Your welcome

Answer:

they will move away from each other

Answer:

Kf = 470 mJ

Explanation:

       \(W_{net} = F_{net} * \Delta X = 0.56 N * 0.84 m = 0.47 J = 470 mJ (1)\)

Answer:

\(T_2 = 0.592\)

Explanation:

Given

\(T_1 = 1.48s\)

See attachment for connection

Required

Determine the time constant in (b)

First, we calculate the total capacitance (C1) in (a):

The upper two connections are connected serially:

So, we have:

\(\frac{1}{C_{up}} = \frac{1}{C} + \frac{1}{C}\)

Take LCM

\(\frac{1}{C_{up}} = \frac{1+1}{C}\)

\(\frac{1}{C_{up}}= \frac{2}{C}\)

Cross Multiply

\(C_{up} * 2 = C * 1\)

\(C_{up} * 2 = C\)

Make \(C_{up}\) the subject

\(C_{up} = \frac{1}{2}C\)

The bottom two are also connected serially.

In other words, the upper and the bottom have the same capacitance.

So, the total (C) is:

\(C_1 = 2 * C_{up}\)

\(C_1 = 2 * \frac{1}{2}C\)

\(C_1 = C\)

The total capacitance in (b) is calculated as:

First, we calculate the parallel capacitance (Cp) is:

\(C_p = C+C\)

\(C_p = 2C\)

So, the total capacitance (C2) is:

\(\frac{1}{C_2} = \frac{1}{C_p} + \frac{1}{C} + \frac{1}{C}\)

\(\frac{1}{C_2} = \frac{1}{2C} + \frac{1}{C} + \frac{1}{C}\)

Take LCM

\(\frac{1}{C_2} = \frac{1 + 2 + 2}{2C}\)

\(\frac{1}{C_2} = \frac{5}{2C}\)

Inverse both sides

\(C_2 = \frac{2}{5}C\)

Both (a) and (b) have the same resistance.

So:

We have:

Time constant is directional proportional to capacitance:

So:

\(T\ \alpha\ C\)

Convert to equation

\(T\ =kC\)

Make k the subject

\(k = \frac{T}{C}\)

\(k = \frac{T_1}{C_1} = \frac{T_2}{C_2}\)

\(\frac{T_1}{C_1} = \frac{T_2}{C_2}\)

Make T2 the subject

\(T_2 = \frac{T_1 * C_2}{C_1}\)

Substitute values for T1, C1 and C2

\(T_2 = \frac{1.48 * \frac{2}{5}C}{C}\)

\(T_2 = \frac{1.48 * \frac{2}{5}}{1}\)

\(T_2 = \frac{0.592}{1}\)

\(T_2 = 0.592\)

Hence, the time constance of (b) is 0.592 s

The temperature gradient in the flow of direction is 294525 W.

A temperature gradient is the gradual variance in temperature with distance. The slope of the gradient is consistent within a material. A gradient is established anytime two materials at different temperatures are in physical contact with each other.

Q= T/( L/ KA)

Q= ( 1500 − 450) / 0.15 / 9.35v * 4.35)

   = 294525 W

Units of measure of temperature gradients are degrees per unit distance, such as °F per inch or °C per meter.

Many temperature gradients exist naturally, while others are created. The largest temperature gradient on Earth is the Earth itself. Q= T/Ka.

Therefore, The temperature gradient in the flow of direction is 294525 W.

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The minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

To maintain equilibrium, the torques acting on the meter stick must balance each other. The torque is given by the formula:

τ = r * F * sin(θ)

where τ is the torque, r is the distance from the pivot point to the point where the force is applied, F is the force applied, and θ is the angle between the force vector and the lever arm.

In this case, the meter stick is in equilibrium when the torques on both sides of the pivot point cancel each other out. The torque due to the weight of the meter stick itself is acting at the center of mass of the meter stick, which is at the 50.0 cm mark.

Let's denote the mass to be placed on the 0.00 cm mark as M. The torque due to the weight of M can be calculated as:

τ_M = r_M * F_M * sin(θ)

where r_M is the distance from the pivot point to the 0.00 cm mark (which is 30.0 cm), F_M is the weight of M, and θ is the angle between the weight vector and the lever arm.

Since the system is in equilibrium, the torques on both sides of the pivot point must be equal:

τ_M = τ_stick

r_M * F_M * sin(θ) = r_stick * F_stick * sin(θ)

Substituting the given values:

30.0 cm * F_M = 20.0 cm * (0.0400 kg * 9.8 m/s^2)

Solving for F_M:

F_M = (20.0 cm / 30.0 cm) * (0.0400 kg * 9.8 m/s^2)

F_M = 0.0264 kg * 9.8 m/s^2

F_M = 0.25872 N

Finally, we can convert the force into mass using the formula:

F = m * g

0.25872 N = M * 9.8 m/s^2

M = 0.0264 kg

Therefore, the minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

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Answer:

Separation of the Earth into layers (crust, mantle, inner core, and outer core) was largely caused by gravitational differentiation (separating different constituents at temperature where materials are liquid or plastic, owing to differences in density) early in Earth's history.

Explanation:

hoped it helped!!

Answer:

Explanation:

Force of friction acting on the body = μ mg cosθ

= .4  x 70 x 9.8 x cos30

= 237.63 N

component of weight = mgsinθ

= 70 x 9.8 x sin30

= 343 N  

Net upward force = 600 - mgsinθ - μ mg cosθ

= 600 - 343 - 237.63

= 105.37 N

acceleration in upward direction = 105.37 / 70

= 1.5 m /s²

s = ut + 1/2 a t²

= 0 + .5 x 1.5 x 3²

= 6.75 m .

The crate will move at a distance of 1.215 m in 3 seconds.

Given that the mass m of the crate is 70 kg and the angle above the horizontal is 30°. External force F on the crate is 600 N and the coefficient of friction is 0.4.

The friction force applied to the crate is calculated as given below.

Friction force = \(\mu mgcos \theta\)

Where \(\mu\) is the friction constant, g is the gravitational acceleration and \(\theta\) is the angle above the horizontal.

Friction Force = \(0.4\times 70\times 9.8\times cos30^\circ\)

Friction force = 237.63 N.

There is a force applied on the crate due to its weight is calculated as given below.

Force (weight component) = \(mgsin\theta\)

Force (weight component) = \(70\times 9.8\times sin 30^\circ\)

Force (weight component) = 343 N.

The net force applied to the crate is given below.

Net force = External force - friction force - force (weight component)

Net force F' = \(600 - 237.63 - 343\)

Net force F' = 19.37 N.

The acceleration of the crate can be calculated as given below.

\(a = \dfrac {F'}{m}\)

\(a =\dfrac {19.37}{70}\)

\(a = 0.27 \;\rm m/s^2\)

Hence the distance traveled by the crate in 3 seconds is calculated by the formula given below.

\(s = ut + \dfrac {1}{2} at^2\)

Where, s is the distance, u is the initial velocity, a is the acceleration and t is the time of motion of the crate.

\(s = 0\times 3 + \dfrac {1}{2} \times 0.27 \times 3^2\)

\(s = 1.215\)

Hence we can conclude that the crate will move a distance of 1.215 m in 3 seconds.

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Answer:

D. X-rays have more energy than ultraviolet waves.

Answer:

so i would say 11.4 i dont have work only this link

Explanation:

https://flexbooks.ck12.org/cbook/ck-12-physics-flexbook-2.0/section/11.4/primary/lesson/wave-speed-ms-ps

Wavelength = speed / frequency.

Wavelength = 3x10^8 m/s / 30 hz

Wavelength = 10 million meters

1/2 wavelength = 5 million meters

(that's about 3,100 miles)

I'm pretty sure the frequency is wrong in the question.

I think it's actually 30 kHz, not 30 Hz.

That makes the antenna about 3.1 miles long.

Answer:

(B)False is the answer.

Explanation:

Answer:

it is A

Explanation:

Velocity of the asteroid is (-9.10 x 10³ m/s, 3.90 x 10³ m/s, -15.00 x 10³ m/s).

A minor planet of the inner Solar System is Asteroid.

Let the position vectors of the asteroid at times 18.2 s and 19.2 s after launch time as r1 and r2, respectively. Then, velocity of the asteroid can be calculated as: v = (r2 - r1) / (19.2 - 18.2)

= (< -2.10 x 10³, 0.90 x 10³, -5.00 x 10³> - < 7.00 x 10³, -3.00 x 10³, 10.00 x 10³>) / (19.2 - 18.2)

= (-9.10 x 10³, 3.90 x 10³, -15.00 x 10³) / 1.0

= (-9.10 x 10³ m/s, 3.90 x 10³ m/s, -15.00 x 10³ m/s)

So, the velocity of the asteroid is (-9.10 x 10³ m/s, 3.90 x 10³ m/s, -15.00 x 10³ m/s).

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Note: The question given on portal is incomplete. Here is the complete question.

Question: The crew of a stationary spacecraft observe an asteroid whose mass is 4.00 x 10¹⁷ kg. Taking the location of the spacecraft as the origin, the asteroid is observed to be at location < 7.00 x 10³, -3.00 x 10³, 10.00 x 10³> m at a time 18.2 s after launch time. At a time 19.2 s after launch time, the asteroid is observed to be at location < -2.10 x 10³, 0.90 x 10³, -5.00 x 10³> m. What is the velocity of the asteroid?

Answer:

A- 12 km

B- 42 minutes

C- 17.14 km per hour

Explanation:

A- The displacement of the total trip is 12 kilometers, which emerges by adding the 10 kilometers traveled by car to the 2 kilometers traveled on foot.

B- The trip, in total, took 42 minutes, which arises from adding the 30 minutes of the journey on foot, plus 12 minutes of travel by car at 72 km / h (72/60 x 10 = 12).

C- While 12 km were covered in 42 minutes, the average speed of the trip was 17.14 km / h. This arises from the following calculation:

42 = 12

60 = X

(60 x 12) / 42 = X

17.14 = X