The x- and y-components of a vector are given. Fx = +0.250 kN,
Fy = −0.600 kN Find the magnitude of the vector. F = kN

To answer your question, we need to use the conservation of momentum and conservation of energy principles. Since the collision between the two pendula is elastic, the total momentum and total energy before and after the collision remains the same.

Let's assume that the initial velocity of the bowling ball pendulum is v and the final velocity of both pendula after the collision is v'. According to conservation of momentum,
(m_bowlingball * v) = (m_bowlingball * v') + (m_golfball * v')
where m_bowlingball and m_golfball are the masses of the bowling ball and golf ball pendula respectively.
Similarly, using conservation of energy,
(1/2 * m_bowlingball * v^2) = (1/2 * m_bowlingball * v'^2) + (1/2 * m_golfball * v'^2) + m_golfball * g * h
where g is the acceleration due to gravity and h is the maximum height reached by the golf ball after the collision.
Solving these two equations for v' and h, we get:
v' = (m_bowlingball - m_golfball)/(m_bowlingball + m_golfball) * v
h = (m_bowlingball^2/(m_bowlingball + m_golfball)^2) * (v^2/2g)
Substituting the values given in the problem, we get:
v' = (16/21) * v
h = (256/441) * (v^2/2g)
Therefore, the approximate maximum height that the golf ball reaches after the collision is (256/441) * (v^2/2g), which is approximately 0.58 times the height from which the bowling ball was released.
Note: The exact height reached by the golf ball may vary slightly due to friction and air resistance.

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Answer:

a

Explanation:

Answer:

Catapult on the ground: Normal, gravity

Catapult (I'm assuming launching marshmallow): Reaction of Force Applied

Marshmallow: Force Applied

Explanation:

This is the forces that act on a stationary object and a launched object. The catapult may also experience a force friction if your teacher is taking a more practical sense.

Answer:

As altitude increases and atmospheric pressure decreases, the boiling point of water decreases.

there was once a crab name mr crabs who had to go to the docter one day . mr crabs is a an animal in the arthropods phylum which was not surpising since he has 10 jointed legs

Traditional classifications of arthropods place them in the Trilobitomorpha (Trilobites), Chelicerata, Crustacea, Myriapoda, and Hexapoda subphyla.

Arthropod species make up more than 80% of all known extant animal species, with estimates ranging from 170,000 to 5–10 million.

On Earth, arthropods are regarded as the most successful creatures.

Arthropods, however, are also in charge of a number of helpful human functions, including crop pollination, honey production, devouring or parasitizing insect pests, garbage decomposition, and serving as food for various birds, fish, and mammals. Beneficial arthropods flourish in agricultural areas.

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Answer: Examples of Newton's third law of motion are ubiquitous in everyday life. For example, when you jump, your legs apply a force to the ground, and the ground applies and equal and opposite reaction force that propels you into the air. Engineers apply Newton's third law when designing rockets and other projectile devices.

Explanation: hope this helps :)

Answer:

3000g

hope this helps<3

Answer:

C

Explanation:

Because I said so

When a sound source approaches us, it sounds like more pushed towards the observer with a decreased wavelength and increasing frequency. As its frequency increases, its energy and intensity increases.

A wave's frequency changes in response to an observer moving in respect to the wave source, which is known as the Doppler effect or Doppler shift. 

The apparent pitch increases as one gets closer to a blowing horn until they reach it, then decreases as they pass it. This is an example of the Doppler effect.

Similar to how a star's light changes as seen from earth by moving toward the red end of the spectrum that is lower frequency or longer wavelength when the Earth and star are moving apart, and toward the violet end of the spectrum when they are drawing nearer. Therefore, option D  is correct.

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Answer:

Assumption: the acceleration of this vehicle is constant until it comes to a stop.

Acceleration: \((-2)\; \rm m\cdot s^{-2}\).

The acceleration of this vehicle is negative because the velocity of this vehicle is decreasing over time.

Explanation:

Assume that the acceleration of this vehicle, \(a\), is constant. The SUVAT equations would apply.

The time \(t\) required for braking is neither given nor required. Hence, make use of the SUVAT equation \(v^{2} - u^{2} = 2\, a\, x\) to relate \(u\), \(v\), \(a\), and \(x\!\).

Rearrange this equation to find an expression for \(a\), the acceleration of this vehicle:

\(\begin{aligned}a &= \frac{v^{2} - u^{2}}{2\, x} \\ &= \frac{(0\; \rm m\cdot s^{-1})^{2} - (10\; \rm m \cdot s^{-1})^{2}}{2\times (25\; \rm m)} \\ &= \frac{0^{2} - 10^{2}}{2 \times 25}\; \rm m \cdot s^{-2} \\ &= -2\; \rm m\cdot s^{-2}\end{aligned}\).

Acceleration is the rate at which velocity changes over time.

The velocity of the vehicle in this question is getting smaller over time. Hence, the rate of change of the velocity of this vehicle (that is, the acceleration of this vehicle) would be a negative number.

The acceleration experienced by the crate is approximately 0.844 m/s

Weight of the crate:

Weight = mass × acceleration due to gravity

Weight = 114 kg × 10 m/s^2

Weight = 1140 N

Force of friction:

Force of Friction = coefficient of friction × normal force

Force of Friction = 0.541 × 1140 N

Force of Friction ≈ 616.74 N

Net force:

Net Force = Applied Force - Force of Friction

Net Force = 713 N - 616.74 N

Net Force ≈ 96.26 N

Acceleration:

Acceleration = Net Force / mass

Acceleration = 96.26 N / 114 kg

Acceleration ≈ 0.844 m/s

Therefore, the acceleration experienced by the crate is approximately 0.844 m/s

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Answer:

The answer should be 650,000 years

Explanation:

The air bubbles are extracted by melting, crushing or grating the ice in a vacuum. This method provides detailed records of carbon dioxide, methane and nitrous oxide going back over 650,000 years[6].

Answer:

800,00 im currently taking this quiz i hope its right

Explanation:

To determine the greatest distance you can be from the base camp at the end of the third displacement, regardless of direction, we need more specific information about the magnitudes and directions of the displacements.

Displacement is a vector quantity that has both magnitude and direction. The distance covered during multiple displacements depends on the individual magnitudes and directions of each displacement. Without specific values, it is not possible to determine the exact greatest distance from the base camp.

If you provide the magnitudes and directions of the three displacements, I can help you calculate the total distance and determine the maximum possible distance from the base camp at the end of the third displacement.

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cant really answer here with text but at the top of the slide it should br positives and towards the bottom its negative.

This is because you go faster at the top of the slide than the bottom and when your at the bottom you slow down

By integrating the given equation, we can find the potential ϕ as a function of z.

Let's consider a point P along the positive z-axis with coordinates (0, 0, z). To find the potential at point P, we integrate the Green function G_D(r, r') with respect to the charge distribution over the surface of the conducting sphere.

The potential ϕ at point P can be calculated using the following integral:

ϕ(P) = ∫∫ G_D(r, r') σ(r') dS

Here, σ(r') represents the charge density on the surface of the sphere, and dS represents the differential surface element.

Since we are interested in the potential along the positive z-axis, we can simplify the integral by considering the symmetry of the problem. Due to symmetry, the potential ϕ will only depend on the radial distance r from the z-axis. Thus, we can rewrite the integral as:

ϕ(P) = 2π∫ G_D(r, r') σ(r') r' dr'

Now, we need to express the charge density σ(r') in terms of the potential difference V and the radius R. The charge density on the upper hemisphere is V/(4πR^2), and on the lower hemisphere, it is -V/(4πR^2). Therefore, we can write:

ϕ(P) = (V/R^2) ∫ (r^2 + r'^2 - 2rr')/(r-r')^2 r' dr'

This integral can be evaluated using appropriate techniques of integration.

By integrating the above equation, we can find the potential ϕ as a function of z.

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Explanation:

A lightning rod (US, AUS) If lightning hits the structure:-

It will preferentially strike the rod and be conducted to ground through a wire.

Instead of passing through the structure, where it could start a fire or cause electrocution.

The parts of a lightning protection system are air terminals (lightning rods or strike) and all of the connectors and supports to complete the system.

The initial velocity of the car as it slow to rest with an acceleration of -5 m/s² is 11.5 m/s.

This can be defined as the ratio of displacement to the time of a body

To calculate the initial velocity of the car, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence the initial velocity of the car is 11.5 m/s

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Answer:

The x - component of the normal force is equal to 1706.45 N.

Explanation:

To solve the problem, and since there is no additional information, we can safely assume that the x-axis is parallalel to the hill surface and the y-axis is perpendicular to the x-axis. Knowing that, we can calculate the components of the normal force (or weight for this case), using the following formulas:

\(N

x

=W∗Sin(α)=mg∗Sin(α)\)

\(N

y

=W∗Cos(α)=mg∗Cos(α)\)

Now, using the given information, we have:

\(mass=m=1150Kg\)

\(a=8.70\)

\(g=9.81 \frac{m}{ {s}^{2} } \)

Calculating, we have:

\(N_{x}=mg*Sin(\alpha)\)

\( \: \: \: \: \: \: \: \: \: N_{x}=1150Kg*9.81\frac{m}{s^{2}}*Sin(8.70\°)\)

\(N

x =11281.5

s

2

Kg.m

∗Sin(8.70\°) = \\ \\ 1706.45

s

2

Kg.m

=1706.45.23N\)

Hence, we have that the x-component of the normal force is equal to 1706.45 N.

Answer:

zero

Explanation:

fx=

Answer: = 25. 5 m

Explanation:

Solve for C using Pythagorean theorem:

1. \(\sqrt{a^{2}+b^{2} }=c\)

2.  \(\sqrt{22.2 m ^{2} +12.6m^{2} } =c\)

3. \(25.52646 m= c\)

∴ Magnitude of the vector is 25.5 m

A discordant igneous intrusion cuts across bedding planes. Here is the detailed explanation of the given question:Explanation:The Discordant igneous intrusion is the formation of an igneous rock mass when magma is injected into a host rock and cools there.

This form of igneous intrusion does not conform to the stratification or layering of the existing rock mass because it cuts across it.Therefore, a discordant igneous intrusion cuts across bedding planes.Option (a) is correct. It is the only option that describes the features of discordant igneous intrusion. Hence, the correct answer is option (a).

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Answer:

3.85 V

Explanation:

The potential difference between two points can be calculated using the following equation

Where E is the energy and Q is the charge. So, replacing E = 250 J and Q = 65 C, we get:

Therefore, the potential difference is 3.85 V

Explanation:

it would be 198.4

you're welcoms

When a shaft of light approaches a smooth polished face and the light shaft bounces back, it's called the reflection of light. The incident light shaft which lands upon the face is said to be reflected off the face. The shaft that bounces back is called the reflected shaft.

When light is reflected on a aeroplane face the angle of reflection is equal to the angle of prevalence i.e. θr = θi.

Angle of prevalence is the angle between the incident shaft and the reflecting face.

Angle of reflection

This is the angle between the reflected shaft and the normal shaft on a reflecting face.

Angle of reflection is analogous to angle of prevalence.

Thus, the reflection of light is the shaft that hits the face and reflects back to the atmosphere.

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Answer:

1.) A

2.) B

4.) A

17.) B

Explanation:

Im sure tama ako nasagot kona

to ehh

Answer:

Explanation:

F = ma = (2 kg)(9.8 m/s²) = 19.6 N

a = F/m = 25 N / 2 kg = 12.5 m/s²

The machine's efficiency is 81.61%, indicating that it converts 81.61% of the input energy into useful output energy, while the remaining percentage is lost as waste or dissipated in the process.

To calculate the efficiency, we can use the formula:

Efficiency = (Actual Output / Design Capacity) × 100

Given:

Actual Output = 7,407

Design Capacity = 9,050

Substituting the values into the formula:

Efficiency = (7,407 / 9,050) × 100

          = 0.817 × 100

          = 81.61%

Therefore, the efficiency of the machine is 81.61%.

Efficiency is a measure of how effectively a machine or system is utilizing its available capacity. In this case, the machine has a design capacity of 9,050 units, but it only produced an actual output of 7,407 units.

By dividing the actual output by the design capacity and multiplying by 100, we find that the machine's efficiency is 81.61%. This indicates that the machine is operating at approximately 81.61% of its full capacity.

A higher efficiency percentage would indicate a more optimal utilization of the machine's capacity, while a lower percentage suggests room for improvement in maximizing output.

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To identify the intervals where the acceleration is positive, we need to examine the slope of the position-time graph since the slope represents the velocity, and the change in velocity over time gives us the acceleration.

Velocity is a vector quantity that indicates how fast an object is moving. The magnitude of this vector is called speed and is expressed in meters per second. Velocity or speed: the quotient between the distance traveled and the time interval. Velocity or speed is a scalar quantity. Speed ​​or velocity is the quotient of the displacement with the time interval. Speed ​​or velocity is a vector quantity.

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The United States faced international and domestic challenges between 1968 and 1974, and President Richard Nixon's administration responded with a diplomatic initiatives, domestic policies, and political strategies.

What is political strategies?

Political strategies refer to deliberate plans and tactics employed by individuals, organizations, or political parties to achieve their goals within the realm of politics. These strategies involve navigating the complex landscape of political systems, influencing public opinion, gaining support, and achieving desired outcomes.

During this period, the United States confronted several significant challenges. Internationally, the ongoing Vietnam War dominated the agenda, with anti-war protests and public discontent growing. Nixon pursued a policy of Vietnamization, gradually withdrawing U.S. troops while increasing the responsibility of South Vietnamese forces.

Additionally, the United States faced tensions with the Soviet Union and China during the Cold War, and Nixon's administration employed a strategy of détente, seeking to improve relations and reduce tensions through diplomatic negotiations and arms control agreements.

Domestically, the country grappled with social unrest, racial tensions, and economic issues. The civil rights movement continued to advocate for equality, while urban areas experienced riots and protests.

Nixon pursued a policy of "law and order," emphasizing crime control and support for local law enforcement. Economically, the administration implemented measures such as wage and price controls to address inflation and attempted to stimulate economic growth.

Overall, Nixon's administration employed a combination of diplomatic efforts, domestic policies, and political strategies to address the challenges faced by the United States during this period. The effectiveness and consequences of these responses remain a topic of historical debate and analysis.

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The minimum gap between the automobiles is 16.9 feet, according to the supplied statement, in order to prevent a collision.

The size or extent of the displacement between two points is referred to as distance. Keep in mind that perhaps the difference between two and indeed the distance travelled between them are not the same. The length of the entire journey taken to go from one point to another is the distance travelled.

For B;

\(\begin{aligned}(\rightarrow) \quad v & =v_0+a_c t \\v_B & =60-12 t \\(\rightrightarrows) & s=s_0+v_0 t+\frac{1}{2} a_c t^2 \\s_B & =d+60 t-\frac{1}{2}(12) t^2\end{aligned}\)

For A;

\(\begin{aligned}& (\stackrel{\rightarrow}{\rightarrow}) \quad v=v_0+a_c t \\& v_A=60-15(t-0.75), \quad[t > 0.75] \\& (\text { 土 }) \quad s=s_0+v_0 t+\frac{1}{2} a_c t^2 \\& \qquad s_A=60(0.75)+60(t-0.75)-\frac{1}{2}(15)(t-0.75)^2, \quad[t > 0.74]\end{aligned}\)

Require \(V_{A} = V_{B}\) the moment of closest approach

60 - 12t = 60 - 15 ( t- 0.75)

t = 3.75 s

The worst case scenario without contact is when \(S_{A} = S_{B}\)

At t = 3.75 s, from eq. (1) and (2),

60(0.75) + 60(3.75 - 0.75) - 7.5(3.75 - 0.75)² = d + 60(3.75) = 6(3.75)²

157.5 = d + 140.62

d = 16.9 ft

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Answer:

Friction

Explanation:

As the toy cars rolls away, more friction is created. The more friction there is, the more friction on surface rubs against another which creates friction which in-term slows it down. Hope this helps.