There are 130 people in a sport centre, 73 people use the gym, 62 people use the swimming pool, 58 people use the track, 22 people use the gym and pool, 29 people used the pool and track, 25 people use the gym and track, 11 people use all three facilities, how many people use at least two facilities

Answer:

-13

Step-by-step explanation:

Adding a negative means that you subtract the number as + (-) = -

This means that the equation is -4-9=-13.

Answer:

-13

Step-by-step explanation:

The probability that the student will be a student who lives on campus is 0.24

In math the term probability is referred as the branch of mathematics that studies the possible outcomes of given events together with the outcomes' relative likelihoods and distributions.

Here we have given that one full-time student who is a freshman or sophomore is selected at random.

Here we need to find the probability that the student will be a student who lives on campus.

Here we know that the probability that a student is a sophomore is calculated as,

=> P(S) = 19/42 = 0.45.

Whereas the probability that a student has a freshman is calculated as,

=>P(H)=25/42=0.6.

Then the probability that the student will be a student who lives on campus is calculated as,

=> P(H∩S)=P(S)+P(H)−P(S∪H)

Apply the values then simplify this one then we get,

=> 0.45+0.6−(42−8)/42=0.24

Complete Question:

Suppose that a certain college class contains 42 students and then if one full-time student who is a freshman or sophomore is selected at random, what is the probability that the student will be a student who lives on campus?

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We can estimate that about 31.5% + 43% = 74.5% of the observations are between 50 and 90.

To find out what percent of the observations are between 50 and 90, we need to first calculate the interquartile range (IQR).

The IQR is the difference between the third quartile (Q3) and the first quartile (Q1). We can calculate Q1 and Q3 using the five-number summary:

Q1 = 35 + 0.25(50-35) = 42.5
Q3 = 70 + 0.25(90-70) = 77.5

So the IQR is: IQR = Q3 - Q1 = 77.5 - 42.5 = 35

Now we can use the IQR to estimate what percent of the observations are between 50 and 90. Since the data is roughly symmetric and follows a normal distribution, we can assume that about 50% of the data falls within one standard deviation of the mean. In this case, the IQR represents about one standard deviation of the data.

Therefore, we can estimate that about 68% of the observations fall within one IQR of the mean. Since the IQR spans from 35 to 77.5, we can estimate that about 68% of the observations fall between these values.

To estimate the percent of observations between 50 and 90, we need to determine how many standard deviations away from the mean these values are.

50 is (50 - 60)/35 = -0.29 standard deviations away from the mean.
90 is (90 - 60)/35 = 0.86 standard deviations away from the mean.

Using the empirical rule, we can estimate that about 63% of the observations fall within one standard deviation of the mean. Since 50 is less than one standard deviation away from the mean, we can estimate that less than 31.5% of the observations fall between 50 and the mean.

Similarly, we can estimate that about 86% of the observations fall within two standard deviations of the mean. Since 90 is less than two standard deviations away from the mean, we can estimate that less than 43% of the observations fall between the mean and 90.

Therefore, we can estimate that about 31.5% + 43% = 74.5% of the observations are between 50 and 90.

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Answer:

As the number of pegs added increases, the number of moves required decreases.

The extra pegs allow for more places to move disks, reducing the number of intermediate stacking steps.

An example would be three disks with four pegs. This requires 5 moves to solve, instead of 7.

Step-by-step explanation:

Answer:

As the number of pegs added increases, the number of moves required decreases.

The extra pegs allow for more places to move disks, reducing the number of intermediate stacking steps.

An example would be three disks with four pegs. This requires 5 moves to solve, instead of 7.

Step-by-step explanation:

Answer:

X = 3

3 x 3 x 3 = 27

27 - 3 =24

Hope this helps!

Answer:

25/144

Step-by-step explanation:

The probability of it occurring once is 5/12, which means that the probability of it occurring twice is (5/12 x 5/12) = 25/144.

Answer:

D 11/18 11:18 11 to 18

Step-by-step explanation:

Because there are eleven technicians, our numerator is 11. Then, because there are 18 total helpers our denominator is 18.

Solomon's study on circadian rhythms in a sample of 45 pregnant women admitted to a hospital in the first 6 months of 2021 due to severe preeclampsia is an example of consecutive sampling.

Consecutive sampling, also known as continuous or complete sampling, is a non-probability sampling method.

In this approach, researchers collect data from every subject that meets the eligibility criteria within a specific time frame.

In Solomon's study, the eligibility criteria were pregnant women admitted to the hospital with severe preeclampsia during the first 6 months of 2021.

By including all eligible subjects during this period, Solomon ensured that the sample was representative of the population under study.

The consecutive sampling method has several advantages, including ease of implementation and the potential for a relatively large sample size.

Additionally, it can provide a comprehensive view of the population during the specified time frame.

However, it may be susceptible to biases if there is a change in the population over time, or if the subjects who meet the eligibility criteria within the given period are not representative of the overall population.

In summary, Solomon's study on circadian rhythms in pregnant women with severe preeclampsia used consecutive sampling, a non-probability sampling method that involves collecting data from every subject meeting the eligibility criteria within a specific time frame.

This method is straightforward to implement and can yield a large sample size, but it may be susceptible to biases if the sample is not representative of the overall population.

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Answer:

Step-by-step explanation:

\(\dfrac{9}{1}*4=9*4\) which does not represent the identity property of multiplication.

Rest all represents the identity property of multiplication.

\(\dfrac{55}{55}*3 = 1*3 = 3\\\\\\17*1=17\\\\\\\dfrac{11}{11}*4=1*4=4\)

Answer:

\(150( {1.01}^{12} ) - 150 = 19.02\)

The account will earn $19.02 interest in 12 months.

Answer:

Step-by-step explanation:

To determine the future value of the savings account after 12 months, we can use the formula for compound interest:

A = P(1 + r/n)^(nt)

Where:

A = the future value of the account

P = the principal or initial value of the account (in this case, $150)

r = the annual interest rate (1% per month or 0.01)

n = the number of times the interest is compounded per year (12)

t = the time period in years (1)

Plugging in these values, we get:

A = 150(1 + 0.01/12)^(12*1)

A = 150(1.0075)^12

A = $162.89

Therefore, the savings account will be worth approximately $162.89 after 12 months with 1% monthly interest. It is important to note that this is only an estimate, as the actual amount could vary depending on any additional deposits or withdrawals made during the year, and the interest rate could also change.

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Step-by-step explanation:

Our coordinates are (6, 0) and (0, -3).

We can use the formula (y₂-y₁)/(x₂-x₁) to find the slope-intercept form (y=mx+b)

Now, we plug the coordinates into the formula and solve.

(0-(-3))/(6-0)

=3/6

=\(\frac{1}{2}\)

So, the slope is \(\frac{1}{2}\).

Now, we have to find the y-intercept, which is the point where the line on the graph intersects with the y-axis.

We can find the y-intercept (which is represented by b) by plugging the information we already know into the formula.

We can use either pair of coordinates for the formula, so I'll use (6, 0).

y=mx+b

0=\(\frac{1}{2}\)(6)+b

Now, we can solve.

0=3+b

Subtract 3 from both sides.

-3=b

The y-intercept is -3.

Answer:

y=\(\frac{1}{2}\)x-3

Answer:x − x^{2} − 1.

Step-by-step explanation:

.

Given:

Loss of 17 yards.

To find:

The integer for given situation.

Solution:

Integers are the complete numbers without a decimal or fractional value. Integers can be positive, negative or zero.

Zero : No change.

Negative integers : Decrease in any value.

Positive integers : Increase in any value.

Loss of 17 yards means decrease in value by 17 yards.

So, required integer for the situation is -17. Here, negative sign is used for  decrease in yards.

Therefore, the required integer is -17.

The P-value for the appropriate test of significance is approximately 0.0013 (a).

To calculate the P-value, we can use a one-sample t-test. Given that the sample mean IQ is 110 and the standard deviation is 10, we can calculate the test statistic using the formula:

t = (sample mean - hypothesized mean) / (standard deviation / sqrt(sample size))

In this case, the hypothesized mean is 112, the sample mean is 110, the standard deviation is 10, and the sample size is 25. Plugging these values into the formula, we get:

t = (110 - 112) / (10 / sqrt(25))

 = -2 / (10 / 5)

 = -1

Next, we need to determine the degrees of freedom for the t-distribution, which is equal to the sample size minus 1. In this case, the degrees of freedom is 25 - 1 = 24.

Using the t-distribution table or statistical software, we can find the P-value associated with a t-statistic of -1 and 24 degrees of freedom. The P-value turns out to be approximately 0.0013.

Therefore, the P-value for the test of significance is approximately 0.0013 (a), indicating strong evidence against the hypothesis that the true mean IQ of all Canadian adults is 112.

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Answer:

5:25

Step-by-step explanation:

Borrow 1 hour from 6 hours, change it to 60 minutes, and add it to 9 minutes.

6:09 is the same as 5:69.

6:09 = 5:69

Now subtract 44 minutes from 69 minutes.

5:69 = 0:44 = 5:25

Answer: 5:25

Answer:

5:25

Step-by-step explanation:

Borrow 1 hour from 6 hours, change it to 60 minutes, and add it to 9 minutes.

6:09 is the same as 5:69.

6:09 = 5:69

Now subtract 44 minutes from 69 minutes.

5:69 = 0:44 = 5:25

Answer: 5:25

Answer:

if i counted correctly its 15

Step-by-step explanation:

Answer:

15

Step-by-step explanation:

Ok, so on this chart, each blue dot represents one person, so add up all the dots, and we get 15.

The equation of Line 1 in the form y=-12x+28

A measurable path between two places is referred to as a line segment. Line segments may make up the sides of any polygon since they have a set length.

Coordinates of Line 2 M(4,5) and N(6,-19)

Slope of Line 2 is =(-19-5)/(6-4)

=-24/2=-12

Slope of line 1 and line 2 are same

Cordinate of Line 1 is D(2,4)

D(2,4) must pass through line 1, so it must satisfy the equation

y=mx+b

4=2(-12)+b

4+24=b

b=28

the equation of Line 1 in the form y=-12x+28

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After analyzing all the critical paths  the maximum possible reduction in the project duration is 1 week. The correct option is d. 1 week.

To determine the maximum possible reduction in the project duration within the given budget, we need to analyze the critical paths and crashing costs.

The crashing cost per week for activity A is $540 in the first week and $1080 per week from the second week onwards. For activity E, it is $545 in the first week and $1350 per week thereafter. For all other activities, the crashing cost is $135 per activity per week in the first week and $405 per activity per week thereafter.

Considering the crashing budget of $2300, let's calculate the maximum reduction for each critical path:

A-B-C-D-E: The total crashing cost for this path is $1350 (for A and E) + $405 (for B, C, and D) = $1755 per week. With a budget of $2300, this path can be crashed for a maximum of $2300 / $1755 = 1.31 weeks. Therefore, the maximum reduction for this path is 1 week.

A-F-E: The total crashing cost for this path is $1350 (for E) + $405 (for F) = $1755 per week. With the given budget, this path can be crashed for a maximum of $2300 / $1755 = 1.31 weeks. Hence, the maximum reduction for this path is 1 week.

A-B-H-J-K-E: The total crashing cost for this path is $1350 (for A and E) + $810 (for B, H, J, and K) = $2160 per week. This path can be crashed for a maximum of $2300 / $2160 = 1.06 weeks. Thus, the maximum reduction for this path is 1 week.

A-S-T-E: The total crashing cost for this path is $1350 (for A and E) + $540 (for S and T) = $1890 per week. This path can be crashed for a maximum of $2300 / $1890 = 1.22 weeks. Hence, the maximum reduction for this path is 1 week.

After analyzing all the critical paths, we observe that the maximum possible reduction in the project duration is 1 week.

The correct option is d. 1 week.

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Answer:

Option D, 140 sq. units

Step-by-step explanation:

Area of the rectangle part, 11*5 = 55 sq. units

Area of the pentagon part (3.4*5)*5/2 = 42.5 sq. units

Total area,

55+2*42.5 sq. units (since there are two pentagons)

= 55+85 sq. units

= 140 sq. units

The proof for the Base Angles Theorem is explained below:

A triangle's opposite angles are congruent if its two sides are congruent. We shall build the angle bisector through the vertex angle of an isosceles triangle in order to demonstrate the Base Angles Theorem. We created two congruent triangles by building the angle bisector, and then we utilized CPCTC to prove that the base angles are congruent. Base angles: The angles that include the base of an isosceles triangle are known as the "base angles."

Any triangle with at least two congruent sides is said to be isosceles. Legs are the isosceles triangle's congruent sides. The base is the other side. Base angles are the angles formed between the base and the legs.

Given: \(\bar{ LM}\)≅ \(\bar{LN}\)

Prove: ∠M≅∠N

According to the figure,

Given,

\(\bar{ LM}\)≅ \(\bar{LN}\)

By the definition of mid-point,

O is the mid-point of \(\bar{MN}\)

Now, by joining the two points determine and draw a line of \(\bar{LO}\)

Now, Again by the definition of mid-point

\(\bar{MO}\)≅\(\bar{NO}\)

Now, by using reflexive property,

\(\bar{LO}\)≅ \(\bar{LO}\)

By SSS rule,

ΔLMO≅ΔLNO

By CPCTC rule,

∠M≅∠N

Hence proved.

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(a)The marginal profit when x = 10 units can be found by taking the derivative of the profit function P(x) and evaluating it at x = 10.

(b)The marginal average can be found by taking the derivative of the profit function P(x), dividing it by x, and then evaluating it at x = 10.

(a) 1. Find the derivative of the profit function P(x) with respect to x:

  P'(x) = -2x + 55

2. Evaluate the derivative at x = 10:

  P'(10) = -2(10) + 55 = 35

Therefore, the marginal profit when x = 10 units is 35.

(b) 1. Find the derivative of the profit function P(x) with respect to x:

  P'(x) = -2x + 55

2. Divide the derivative by x to get the marginal average:

  M(x) = P'(x) / x = (-2x + 55) / x

3. Evaluate the expression at x = 10:

  M(10) = (-2(10) + 55) / 10 = 3.5

Therefore, the marginal average when x = 10 units is 3.5.

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The probability that the sample mean of 46 racing cars would be greater than 116.9 gallons is 0.0043, or 0.43%.

To solve this problem, we can use the central limit theorem, which states that the sampling distribution of the sample means approaches a normal distribution as the sample size increases.
First, we need to calculate the standard error of the mean, which is the standard deviation of the population divided by the square root of the sample size:
standard error = 7 / sqrt(46) = 1.032
Next, we can standardize the sample mean using the formula:
z = (sample mean - population mean) / standard error
In this case, the population mean is 114 and the sample mean we're interested in is 116.9. So:
z = (116.9 - 114) / 1.032 = 2.662
Finally, we can use a standard normal distribution table or calculator to find the probability that a z-score is greater than 2.662. This probability is approximately 0.0043, rounded to four decimal places.
Therefore, the probability that the sample mean of 46 racing cars would be greater than 116.9 gallons is 0.0043, or 0.43%.

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Answer:

10

Step-by-step explanation:

Use the distance formula to determine the distance between two points.

Answer:

9^9

Step-by-step explanation:

12 - 3 = 9

so 9 to the 9th power

Given in 2020, the university realized a drop in revenue of 50%. The business and the engineering schools have a combined revenue decrease of 45%. Since the policy is not triggered, there is no insurance payout to be made.

Assuming that in 2020, the university realized a drop in revenue of 50%.

The business and the engineering schools have a combined revenue decrease of 45%.

Of this decrease, 37% is revenue lost from fewer Chinese students enrolling in the two schools.

Given that information, we need to calculate the total amount of premiums paid by the two schools and determine whether the policy would be triggered in If it's triggered, we need to calculate the total insurance payout.

The policy would be triggered if the total revenue loss was greater than or equal to the deductible. Assuming that the deductible is $1,000,000, we can calculate the total revenue loss using the following formula:

Total revenue loss = Combined revenue decrease - Revenue lost from fewer Chinese students

Total revenue loss = 45% - (37% x 45%)

Total revenue loss = 28.35%

Since the total revenue loss is less than the deductible, the policy would not be triggered in 2020.

Now, let's calculate the total amount of premiums paid by the two schools.

Assuming that the premium rate is 2%, we can calculate the total premiums paid using the following formula:

Total premiums paid = Total revenue x Premium rate

Total revenue = Combined revenue of business and engineering schools = 45%

Total premiums paid = 45% x 2%

Total premiums paid = 0.9%

Finally, if the policy were triggered, the total insurance payout would be the difference between the total revenue loss and the deductible.

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Answer:

Step-by-step explanation:

The word "sine" (Latin "sinus") comes from a Latin mistranslation by Robert of Chester of the Arabic jiba, which is a transliteration of the Sanskrit word for half the chord, jya-ardha.

Answer:

\(x = 10 \: and \: y \: = 70.\)

Step-by-step explanation:

\(if \: from \: the \: sine - cosine \: rule : \\ \sin( \beta ) = \cos(90 - \beta ) \\ \cos( \beta ) = \sin(90 - \beta ) \\ then \: if : \\ sin(x+20)°=cos(y−10)° \\ let \: x + y = 80 \\ if \: x = 10. \\ y = 70. \\ \)

Answer:

cost of old motor bike =$5675

he spent on repair =$453

cost that he sold =$7265

profit he made=$7265-$5675+$453

=$7265-$6128

=$1137

Step-by-step explanation:

Answer:

142.32

Step-by-step explanation:

Answer:

-8.4 and 2 2/9

Step-by-step explanation:

p/1.2=-7 /×1.2

p=-8.4

20/30=3/10y /×10/3

20/9=y=2 2/9

Answer:

I think its D also

Step-by-step explanation: