There are 18 cans of peas in a case. each can of peas is 12 ounces. if a case of peas costs $14.22, what is the unit price per can of peas? a. $0.07 b. $0.08 c. $0.79 d. $1.19 please select the best answer from the choices provided a b c d

Answer:

96 dollars.

Step-by-step explanation:

Given that Ella earns some extra christmas shopping money baby elf-sitting but after stocking up on wrapping paper she only has a third of her earnings left.

Let Ella earnings = E

Third of her earning left = E/3

She also spent $12 on a stylish new santa hat.

That is, E/3 - 12

What were her elf-sitting earnings if she only has $20 left?

Then,

E/3 - 12 = 20

Collect the like terms

E/3 = 20 + 12

E/3 = 32

Cross multiply

E = 32 × 3

E = 96 dollars

Therefore, her elf-sitting earnings is 96 dollars.

Answer:

The awnser to this equation is 120 cents

The cost of using a 200-watt television for 30 days, turned on for 2 hours per day, would be $1.20.  

To calculate the cost of using a 200-watt television for 30 days with 2 hours of daily usage at 10 cents per kilowatt-hour, we need to find the total energy consumption and then multiply it by the cost per kilowatt-hour.

First, let's find the total energy consumption:

1. Daily energy usage: 200 watts * 2 hours = 400 watt-hours
2. Monthly energy usage: 400 watt-hours * 30 days = 12,000 watt-hours

Now, we need to convert watt-hours to kilowatt-hours:
3. Monthly energy usage in kilowatt-hours: 12,000 watt-hours / 1,000 = 12 kWh

Finally, let's calculate the cost:
4. Cost of using the television for 30 days: 12 kWh * 10 cents per kWh = 120 cents

So, the cost of using a 200-watt television for 30 days with 2 hours of daily usage at 10 cents per kilowatt-hour is 120 cents.

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A management conundrum is an issue or difficulty that a manager faces that necessitates a choice. This difficulty or challenge frequently defines the study question and motivates researchers to conduct research to discover a solution that is the given statement is true.

Mathematics research is the long-term, open-ended investigation of a series of connected mathematical issues, the answers to which connect to and build upon one another. Because students always come up with new questions to ask based on their observations, problems are open-ended. Mathematics research is the long-term, open-ended investigation of a series of connected mathematical issues, the answers to which connect to and build upon one another. Because students always come up with new questions to ask based on their observations, problems are open-ended. Student research also has the following characteristics: Students create questions, tactics, and outcomes that are, at least for them, unique. Students employ the same broad techniques as research mathematicians. They go through data collection, visualization, abstraction, conjecture, and proof cycles.

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Answer:

first blank: 15

second blank: 90

Step-by-step explanation:

Obviously, sin and cos are related, but they are not the same thing. In order for them to be equal:

sin(____) = cos(75)

the angles have to add up to 90 (complementary)

What + 75 is 90?

Do a tiny calc:

90 - 75 is 15

The second question is stating the rule generically.

x + (90 - x) is 90

After using the formula for the sum of an infinite geometric series, we conclude that the given infinite series does not converge to 1.

To prove that the infinite series ∑(i=1 to ∞) 2^(i-1) equals 1, we can use the formula for the sum of an infinite geometric series.

The sum of an infinite geometric series with a common ratio r (|r| < 1) is given by the formula:

S = a / (1 - r)

where 'a' is the first term of the series.

In this case, our series is ∑(i=1 to ∞) 2^(i-1), and the first term (a) is 2^0 = 1. The common ratio (r) is 2.

Applying the formula, we have:

S = 1 / (1 - 2)

Simplifying, we get:

S = 1 / (-1)

S = -1

However, we know that the sum of a geometric series should be a positive number when the common ratio is between -1 and 1. Therefore, our result of -1 does not make sense in this context.

Hence, we conclude that the given infinite series does not converge to 1.

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Without considering the agency's opinion, the recommended decision is to sell the pilot to the competitor (d2) as it has a higher expected value of $100,000.

a) Decision tree for the problem: \(\downarrow\)

b) Recommended decision if the agency opinion is not used:
When agency opinion is not used, the expected profit values for alternatives d1 and d2 are as follows:

Expected value of d1 = -100*0.20 + 50*0.30 + 150*0.50= $70,000Expected value of d2 = 100*0.20 + 100*0.30 + 100*0.50= $100,000
As we can see that d2 has a higher expected profit of $100,000 in comparison to d1, so the recommended decision is to sell the rights to a competitor.

c) Expected value of perfect information:

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The (1, 4), (1, 5), (1, 6), (3, 4), (3, 5), (3, 6), (4, 4), (4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 4), (6, 5), (6, 6)Out of these possible outcomes, there are only 11 such outcomes where X1 ≠ 2 and X2 ≥ 4: (1, 4), (1, 5), (1, 6), (3, 4), (3, 5), (3, 6), (4, 4), (4, 5), (4, 6), (5, 4), (5, 5)P(X1 ≠ 2 and X2 ≥ 4) = 11/36

Probability that X2 = 4:Since we rolled a fair dice, so the probability of getting a number 4 on the dice would be 1/6.P(X2 = 4) = 1/6b) Probability that X1 + X2 = 7:Now we know that the sum of the outcomes of two fair dices rolled is 7, this can be obtained by the following possibilities:(1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1)Since each outcome is equally likely, so each of these outcomes has a probability of 1/36.P(X1 + X2 = 7) = 6/36 = 1/6c) Probability that X1 ≠ 2 and X2 ≥ 4:

If we look at the possible outcomes of X1 and X2 then we have the following possibilities:(1, 4), (1, 5), (1, 6), (3, 4), (3, 5), (3, 6), (4, 4), (4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 4), (6, 5), (6, 6)Out of these possible outcomes, there are only 11 such outcomes where X1 ≠ 2 and X2 ≥ 4: (1, 4), (1, 5), (1, 6), (3, 4), (3, 5), (3, 6), (4, 4), (4, 5), (4, 6), (5, 4), (5, 5)P(X1 ≠ 2 and X2 ≥ 4) = 11/36

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Answer:

Yes

Step-by-step explanation:

The constant of proportionality k is given by k=y/x where y and x are two quantities that are directly proportional to each other. Once you know the constant of proportionality you can find an equation representing the directly proportional relationship between x and y, namely y=kx, with your specific k.

Answer:

1, 3, 5 are correct

Step-by-step explanation:

1. (3.4a – 1.7b) + (2.5a – 3.9b) = 5.9a - 5.6b

2. (2.5a + 1.6b) + (3.4a + 4b) =   5.9a + 5.6b

3. (–3.9b + a) + (–1.7b + 4.9a) = 5.9a - 5.6b

4. –0.4b + (6b – 5.9a) = 5.9b - 5.6a

5. 5.9a – 5.6b = 5.9a – 5.6b

the two siblings at present age are Son = 7 years old Daughter = 21 years old.

Therefore, if it's his child, it should be younger than him. That means both age groups are above 42. The number of one must also be three times the number of the other. 7 * 3 = 21, both of which he is under 42, is your answer.

If the age-group sums are X and Y, and the ratio of each age-group is p:q, then you can find the age of Y using the following formula: Age of Y = ratio of Y / total ratio x total years. Age of Y = q/ (p+q) x A.

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x amount they spend each day

4x<1200-585

4x< 615

x< 615/4

if my asnwer helps please mark as brainliest

Answer:

7^12

Step-by-step explanation:

When dividing two exponents by the same base, it is the same as subtracting the power (14-2).

Answer:

( x + 2 )² + ( y - 6 )² = 49

Step-by-step explanation:

→ Write the form of an equation of a circle

( x - a )² + ( y - b )² = r²

→ Substitute in the centre remembering to switch the signs

( x + 2 )² + ( y - 6 )² = r²

→ Substitute in radius

( x + 2 )² + ( y - 6 )² = 49

The value of the corresponding effect size r square is 0.3025

We have correlation to be given as  0.55

Then r squared = 0.55

Then we would have

r = 0.55 x 0.55

= 0.3025

Hence we conclude that if A researcher finds a correlation of 0.55 between an x and a y variable. assume alpha = .05 and a one-tailed test, the value of the corresponding effect size is 0.3025.

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Answer:

see explanation

Step-by-step explanation:

(a)

Given y is directly proportional to x then the equation relating them is

y = kx ← k is the constant of proportion

To find k use the condition when x = 3, y = 18 , then

18 = 3k ( divide both sides by 3 )

6 = k

y = 6x ← equation of proportion

(b)

(i)

when x = 12 , then

y = 6 × 12 = 72

(ii)

when y = 42

42 = 6x ( divide both sides by 6 )

7 = x

TCP provides error checking to ensure reliable data delivery, making option A the correct answer. Only the propagation delay is not caused by the store-and-forward strategy employed by switching devices.

TCP (Transmission Control Protocol) provides error checking as part of its services. It ensures reliable data delivery by using acknowledgments and sequence numbers to detect and recover from packet loss, errors, or out-of-order delivery. When a TCP receiver receives data, it sends an acknowledgment (ACK) back to the sender to confirm the successful reception of packets. If the sender does not receive an ACK for a particular packet within a specified timeout period, it assumes the packet was lost or damaged and retransmits it.

TCP provides error checking to ensure reliable data delivery, making option A the correct answer.

The propagation delay is the time it takes for a signal to travel from the source to the destination. It is determined by the physical distance between the devices and the speed of signal propagation in the transmission medium. The propagation delay is an inherent characteristic of the medium and cannot be eliminated by switching devices or other strategies.

The other three options—processing delay, queuing delay, and transmission delay—are all caused by the store-and-forward strategy used by switching devices. Processing delay refers to the time taken to examine and process the packet headers. Queuing delay occurs when packets have to wait in a queue before being transmitted. Transmission delay is the time it takes to push the bits onto the transmission medium.

Among the given options, only the propagation delay is not caused by the store-and-forward strategy employed by switching devices.

3. The correct answer is A. The system is very well-engineered.

In a statistical multiplexing system, the queuing delay is the delay experienced by packets waiting in a queue before being transmitted. If the average queuing delay is very close to zero, it indicates that the system is well-engineered and efficiently managing its resources. A well-designed system can minimize or eliminate queuing delays by appropriately allocating resources and ensuring efficient scheduling algorithms.

Traffic intensity, which represents the ratio of the average traffic load to the transmission capacity, does not directly determine the queuing delay. It is possible to have low queuing delays even with high traffic intensity if the system is well-designed.

When the average queuing delay is close to zero, it suggests that the system is well-engineered and efficiently utilizing its resources, as stated in option A.

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Answer:

the aswer is 154

Step-by-step explanation:

multiple

Answer:

3 and half

Step-by-step explanation:

half of seven is 3.5

The similar triangles in the question, with proportional sides indicates;

4. The proportion that must be true is the option G

G. 4/6 = 7/x

Similar triangles are triangles are triangles that have the same shape but may have different sizes.

The possible triangles in the question includes two triangles with specified side lengths AB = 6 inches, AC = 7 inches, DE = 4 inches, DF = x inches

The definition of similar triangles indicates that we get;

DE/AB = EF/BC

DF/AC = DE/AB

DF/AC = EF/BC

Therefore;

(x/7) = 4/6

The correct option which indicates the proportion that must be true, therefore is option G

G. 4/6 = x/7

Part of the question includes two triangles, please see attached diagram created with MS Excel

The possible proportions, from which to select the proportion that must be true are;

F (7/x) = (4/6)

G 4/6 = x/7

H 6/4 = x/7

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The total cost of producing the first 220 dresses can be found by integrating the marginal cost function over the interval [0, 220]. The total cost is $10166.67 (rounded to the nearest cent).

To find the total cost of producing the first 220 dresses, we need to integrate the marginal cost function over the appropriate range. The marginal cost function is given as C'(x) = -3/25x + 57, where x represents the number of dresses produced.

Since we want to find the total cost for the first 220 dresses, we need to integrate the marginal cost function from 0 to 220. The integral of C'(x) with respect to x will give us the total cost function, denoted as C(x).

Integrating C'(x) = -3/25x + 57 with respect to x, we get:

C(x) = (-3/25)×(1/2)x² + 57x + C1

To determine the constant of integration, C1, we can use the fact that the total cost is zero when no dresses are produced (C(0) = 0). Plugging in x = 0 into the total cost function, we get:

0 = (-3/25)×(1/2)×(0)² + 57×(0) + C1

C1 = 0

Now we have the total cost function:

C(x) = (-3/50)x² + 57x

To find the total cost of producing the first 220 dresses, we evaluate C(x) at x = 220:

C(220) = (-3/50)×(220)² + 57×(220)

C(220) ≈ 10166.67

Therefore, the total cost of producing the first 220 dresses, disregarding any fixed costs, is approximately $10166.67.

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The solution of the expression will be 3, -2, and -22 respectively.

The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

Given that the expressions are:-

2x²−3x−2 if x is less than or equal to -1

E = 2x²−3x−2

E = 2 (-1) ² - 3 x -1 -2

E = 2 + 3 - 2

E = 3

E = −x²+2x+1 if -1

E = -(-1)² + 2 x -1 + 1

E = -1 - 2 + 1

E = -2

E = −2x²−x−1

E = -2 ( 3 )² - 3 - 1

E = -18 - 3 - 1

E = -22

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(a) If A is an invertible matrix, then A is an invertible matrix. - True

Explanation:

If A is invertible, then A has an inverse matrix A^(-1).

(b) If A is an invertible matrix, then A+ A is an invertible matrix. - False

Explanation:

A+ A = 2A is invertible if and only if A is invertible.

Therefore, this statement is false.

(c)

If A and B are n x n matrices, such that AB is invertible, then it follows that B is invertible. - False

Explanation:

Even if AB is invertible, it is not always true that B is invertible.

For instance, if A = [1 0], B = [0 1],

then AB = [0 1] which is invertible, but B is not invertible.

(d)

If A and B are n x n invertible matrices, then it follows that A - B must be an invertible matrix. - False

Explanation:

If A = [2 0], B = [0 1], then both A and B are invertible, but A - B = [2 -1] is not invertible.

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Answer:

9?

Step-by-step explanation:

Answer:

I don't want to be silly here, but....

if x > 9 and < 13...

there is only one answer that is >9 and < 13

that is answer "A" (11)

Step-by-step explanation:

Answer:

A. 11

Step-by-step explanation:

Hi there!

We're given the trapezoid EBFD, with bases (the parallel sides) EB and DF, which equal 9 and 13 respectively

AC is a segment that belongs to EBFD, and has the measure of x

AC is a midsegment, which is a segment that connects the midpoints of 2 sides

the midpoint divides a segment to create create two congruent segments

In this example, point A is a midpoint, as it divides ED into the congruent segments EA and AD (you can tell they are congruent by their markings)

C is also a midpoint, as it divides BF into the congruent segments BC and CF

line segment AC connects the points A and C together

anyway, the measure of a midsegment in a trapezoid is the average of the bases

in other words, the midsegment (AC, or x) is equal to (EB+DF)/2

since we know the measures of EB and DF, we can substitute them into the expression above to find x

x=(EB+DF)/2

x=(9+13)/2

add the numbers on the numerator

x=22/2

divide

x=11

So the answer is A

Hope this helps! :)

Estuary, Living things: Mangroves, Fish, Crabs, Birds, Shellfish, Non-living things: Water, Sediments, Rocks, Sand, Tidal movements. Intertidal Zone, Living things: Barnacles, Seaweed, Crabs, Anemones, Mussels, Non-living things: Rocks, Tide pools, Sand, Shells, Waves.

Living things found in the Estuary:

Mangroves - Various species of mangrove trees can be found in the estuary, such as Rhizophora, Avicennia, and Sonneratia.

Fish - Estuaries are rich in fish species, including mullets, gobies, and mudskippers.

Crabs - Different types of crabs, such as fiddler crabs and mud crabs, inhabit the estuary.

Birds - Estuaries attract a variety of bird species, including herons, egrets, and kingfishers.

Shellfish - Estuaries provide a habitat for shellfish like oysters and clams.

Non-living things found in the Estuary:

Water - The primary component of the estuary is water, which is essential for its functioning.

Sediments - Estuaries are characterized by a mix of fresh and saltwater, resulting in sediment accumulation.

Rocks - Rocky formations along the estuary shorelines provide structure and shelter for various organisms.

Sand - Sandy beaches and flats are commonly found in estuaries.

Tidal movements - The rise and fall of tides are a significant non-living factor that influences the estuary ecosystem.

Living things found in the Intertidal Zone:

Barnacles - Barnacles attach themselves to rocks and other surfaces in the intertidal zone.

Seaweed - Different types of seaweed, such as kelp and bladderwrack, can be found in the intertidal zone.

Crabs - Interstitial crabs and various types of shore crabs inhabit the intertidal zone.

Anemones - Sea anemones are commonly found in the intertidal zone, attached to rocks or other substrates.

Mussels - Intertidal zones are home to mussels that attach themselves to rocks or intertidal structures.

Non-living things found in the Intertidal Zone:

Rocks - Rocky shores provide the substrate for attachment and shelter for intertidal organisms.

Tide pools - These small pools are formed during low tide and contain a variety of marine life.

Sand - Sandy intertidal areas are common, providing a different type of habitat for certain organisms.

Shells - Empty shells of various marine organisms can be found along the intertidal zone.

Waves - The constant action of waves crashing against the shore is a significant non-living factor in the intertidal zone.

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Answer:

Rate = (4C)cars/3(H)hrs

Step-by-step explanation:

The expression of the above formula for C fraction of 4 cars and H fraction of 3 hours will be 4(C)/3(H) since he can tune 4 cars every 3 hours

Answer:

The answer is  on the quantity they produce per hour.

Step-by-step explanation:

If they produce more, they will be paid more, based on the rate per finished item

Answer:

20 inches wide and 30 inches tall

Step-by-step explanation:

if the height went from 6 to 30 that means it grew by 5 so the poster would be

20 inches wide and 30 inches tall

Answer:

Start Fraction 4/6

End Fraction  20/30