there are 22 fourth grade students and 26 fifth grade students each cheerleading group will have 8 members what equation can be used to find out how many groups can be made

Answers

Answer 1

Answer:

(22 + 26) ÷ 8 = g (or groups)

Step-by-step explanation:

Answer 2

Answer:(26 + 22)/8 = z

Step-by-step explanation:


Related Questions

what is the ratio of boys and girls in a classroom of 18 girls and 27 boys

Answers

Answer:

2:3

Step-by-step explanation:

\(18\: girls \\ 27 \:boys\\\\Girls\:: Boys\\18 \: \:\:\:\:\:\:: 27\\\\Use\:3\:to\:divide\:through\\6:9 = 2:3\\\)

an urn contains 12 balls, ten of which are red. the selection of a red ball is desired and is therefore considered to be a success. if a person draws three balls from the urn, what is the probability of two successes?

Answers

the likelihood of getting two triumphs (i.e., two reddish balls) when drawing three balls from the urn is for the most part 0.1042, or 10.42%. 

To discover the likelihood of two triumphs, we'll utilize the binomial likelihood condition:

P(X = k) = (n select k) * p^k * (1 - p)^(n - k)

where:

P(X = k) is known as the likelihood of getting k triumphs

n is known as  the number of trials (in this case, drawing three balls)

k is known as  the number of triumphs we need to be had (in this case, two)

p is the likelihood of triumph on each trial (in this case, the likelihood of drawing a red ball)

To discover p, we have to calculate the degree of red balls interior the urn:

p = 10/12 = 5/6

By and by arranged to plug interior the values:

P(X = 2) = (3 select 2) * (5/6)^2 * (1 - 5/6)^(3 - 2)

= 3 * (25/36) * (1/6)

= 0.1042

In this way,

the likelihood of getting two triumphs (i.e., two reddish balls) when drawing three balls from the urn is for the most part 0.1042, or 10.42%. 

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Let X denote the amount of time for which a book on 2-hour reserve at a college library is checked out by a randomly selected student and suppose that X has density function kx, if 0 ≤ x ≤ 1 f(x) = otherwise. a. Find the value of k. Calculate the following probabilities: b. P(X1), P(0.5 ≤ x ≤ 1.5), and P(1.5 ≤ X)

Answers

a. The value of k is 2

b.  The probabilities of the given P are

P(X ≤ 1) = 1.P(0.5 ≤ X ≤ 1.5) = 2. P(1.5 ≤ X) = ∞

a. To find the value of k, we need to integrate the density function over its entire range and set it equal to 1 (since it represents a probability distribution):

∫(0 to 1) kx dx = 1

Integrating the above expression, we get:

[kx^2 / 2] from 0 to 1 = 1

(k/2)(1^2 - 0^2) = 1

(k/2) = 1

k = 2

So, the value of k is 2.

Now, let's calculate the probabilities:

b. P(X ≤ 1):

To find this probability, we integrate the density function from 0 to 1:

P(X ≤ 1) = ∫(0 to 1) 2x dx

= [x^2] from 0 to 1

= 1^2 - 0^2

= 1

Therefore, P(X ≤ 1) = 1.

P(0.5 ≤ X ≤ 1.5):

To find this probability, we integrate the density function from 0.5 to 1.5:

P(0.5 ≤ X ≤ 1.5) = ∫(0.5 to 1.5) 2x dx

= [x^2] from 0.5 to 1.5

= 1.5^2 - 0.5^2

= 2.25 - 0.25

= 2

Therefore, P(0.5 ≤ X ≤ 1.5) = 2.

P(1.5 ≤ X):

To find this probability, we integrate the density function from 1.5 to infinity:

P(1.5 ≤ X) = ∫(1.5 to ∞) 2x dx

= [x^2] from 1.5 to ∞

= ∞ - 1.5^2

= ∞ - 2.25

= ∞

Therefore, P(1.5 ≤ X) = ∞ (since it extends to infinity).

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Learning Task 5 : In your answer sheet , prove the theorem , using the given below . if a quadrilateral is inscribed in a circle , then its opposite angles are supplementary." Given : Quadriateral ABCD is inscribed in OE Prove : ∠ABC and ∠ABC are supplementary ∠DAB and ∠DCB are supplementary

Answers

Answer: quadrilateral is inscribed in a circle , then supplementary . " its opposite angles are Given : Quadriateral ABCD is inscribed in OE Prove : ABC

Step-by-step explanation:

(a) Find all the extreme points and extreme directions of the following polyhedral set. S = {(x1,x2): 2 xi + 4 x2 > 4, -x] + x2 < 4, xi 20, x2 > ...

Answers

The extreme points of the polyhedral set S are {(2, 1), (2, 2), (3, 1), (3, 2), (4, 1), (4, 2)}. There are no extreme directions in this case.

To find the extreme points and extreme directions of the polyhedral set S, we need to analyze the given inequalities.

The inequalities defining the polyhedral set S are:

2x1 + 4x2 > 4

-x1 + x2 < 4

x1 > 0

x2 > 0

Let's solve these inequalities step by step.

2x1 + 4x2 > 4:

Rearranging this inequality, we get x2 > (4 - 2x1) / 4.

This implies that x2 > (2 - x1/2).

-x1 + x2 < 4:

Rearranging this inequality, we get x2 > x1 + 4.

Combining the above two inequalities, we can determine the range of values for x1 and x2. We can draw a graph to visualize this region:

         x2

          ^

          |

     +    |   +

          |

     +----|---------+

          |

     +    |   +

          |

     +----|---------+----> x1

          |

          |

         

From the graph, we can see that the polyhedral set S is a bounded region with vertices at (2, 1), (2, 2), (3, 1), (3, 2), (4, 1), and (4, 2). These are the extreme points of S.

However, in this case, there are no extreme directions since the polyhedral set S is a finite set with distinct vertices. Extreme directions are typically associated with unbounded regions.

Therefore, the extreme points of S are {(2, 1), (2, 2), (3, 1), (3, 2), (4, 1), (4, 2)}, and there are no extreme directions in this case.

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Which of the following statement is (are) correct?
This question has multiple correct options
A For an exothermic reactions, sum Delta*H ( ts )<5 < sum Delta*H_{f} (reactants).
Delta*H_{f} of C*O_{2}(g) is same as the Delta H comb of carbon graphite.
c All exothermic reactions have a free energy change negative.
of the following statemen
D
For a reaction N 2(g) +O 2(g) longrightarrow2NO (g)) the heat at constant pressure and the
heat at constant volume at a given temperature are same.

Answers

The correct statement(s) are:

C. All exothermic reactions have a negative free energy change.

Let's analyze each statement to determine which one(s) are correct:

A. For an exothermic reaction, sum DeltaH (ts) < sum DeltaHf (reactants).

This statement is incorrect. In an exothermic reaction, the sum of the enthalpy changes of the products (DeltaH) will be negative, indicating the release of heat. The sum of the enthalpy changes of the reactants (DeltaHf) may or may not be negative, depending on the specific reactants involved.

B. DeltaHf of CO2(g) is the same as the Delta H comb of carbon graphite.

This statement is incorrect. DeltaHf (standard enthalpy of formation) refers to the enthalpy change when one mole of a compound is formed from its constituent elements in their standard states. The Delta H comb (standard enthalpy of combustion) refers to the enthalpy change when one mole of a substance undergoes complete combustion. The enthalpy change for the formation of CO2 from carbon graphite is different from the enthalpy change for the combustion of carbon graphite.

C. All exothermic reactions have a negative free energy change.

This statement is correct. In an exothermic reaction, heat is released, indicating a decrease in the system's internal energy. Since the free energy change (Delta G) is related to the system's internal energy change (Delta U) and the change in entropy (Delta S) through the equation Delta G = Delta H - T * Delta S, a negative Delta H (exothermic) will result in a negative Delta G if the temperature (T) remains constant.

D. For the reaction N2(g) + O2(g) -> 2NO(g), the heat at constant pressure and the heat at constant volume at a given temperature are the same.

This statement is incorrect. The heat at constant pressure (q_p) and the heat at constant volume (q_v) are not the same for a given reaction. The heat at constant pressure (q_p) considers the enthalpy change (Delta H) of the reaction and is measured under constant pressure conditions. On the other hand, the heat at constant volume (q_v) corresponds to the internal energy change (Delta U) and is measured under constant volume conditions. These two quantities are generally different unless there are no non-expansion work terms involved.

In summary, the correct statement(s) are:

C. All exothermic reactions have a negative free energy change.

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Find the angle between (-2,-1) and (3,-6). The angle between (-2,-1) and (3,-6) is (Round to the nearest tenth as needed.) ***

Answers

To find the angle between the vectors (-2, -1) and (3, -6), you can use the dot product and absolute value formulas. The angle between vectors is approximately 137.9 degrees.  

You can use the dot product of two vectors to find the angle between them. Denote the vectors as A = (-2, -1) and B = (3, -6). The inner product formula states that A · B = |A|. |B| cos θ, where |A| and |B| are the magnitudes of vectors A and B, and θ is the angle between them.

First we need to calculate the magnitude of the vector. \(|A| = \sqrt{((-2)^2 + (-1)^2)} = \sqrt{5}\) and |B| =\(\sqrt{(3^2 + (-6)^2) } = \sqrt{(9 + 36)} = \sqrt{45} = 3\sqrt{5}\). Then compute the dot product of A and B. A B = (-2)(3) + (-1)(-6) = -6 + 6 = 0.

Now we can rearrange the dot product formula to find the angle θ. \(0 = \sqrt{5} (3\sqrt{5} ) cosθ\). Simplification: cosθ = 0 / (\(\sqrt{5}) (3\sqrt{5} )\)) = 0. The cosine of θ is 0, so the angle θ is 90 degrees, or \(\pi\)radians. Therefore, the angle between vectors (-2, -1) and (3, -6) is approximately 90 degrees, or\(\pi\) radians.

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Suppose that a motorboat is moving at 83 ft/s when its motor suddenly quits, and that 1 s later the boat has slowed to 23 ft/s. Assume that the resistance it encounters while coasting is proportional to the square of its velocity so that dv/dt =-kv^2 where k > 0. How far will the boat coast in the first 2 minutes after its motor quits?

Answers

The boat will coast approximately 16752.9 feet (or about 3.17 miles) in the first 2 minutes after its motor quits.

From the problem statement, we know that the velocity of the boat, v, changes from 83 ft/s to 23 ft/s over a period of 1 second. Therefore, we can write:

\(dv/dt = -k v^2\)

Separating variables and integrating from v = 83 at t = 0 to v = 23 at t = 1, we get:

\(∫83^23 dv / v^2 = ∫0^1 -k dt\)

=> [1/83 - 1/23] = k

So the equation for the velocity of the boat as it coasts is:

\(dv/dt = -[(1/83 - 1/23)] v^2\)

The differential equation is separable:

\(dv/v^2 = -[(1/83 - 1/23)] dt\)

Integrating both sides, we get:

-1/v = [(1/83 - 1/23)] t + C

where C is an integration constant. Using the initial condition v(0) = 83, we get:

C = -1/83

Substituting this back, we have:

-1/v = [(1/83 - 1/23)] t - 1/83

Solving for v, we have:

v(t) = 83 / [1 + (83/23 - 1) t]

To find the distance traveled, we integrate v(t) from t = 0 to t = 120:

s =\(∫0^120 v(t) dt\)

Substituting v(t) and simplifying, we have:

s = 23 ln(1 + 3.6087t) + 60.391t + C

where C is another integration constant. Using the initial condition s(0) = 0, we get:

C = 0

Therefore, the distance traveled by the boat in the first 2 minutes after its motor quits is:

s = 23 ln(1 + 3.6087t) + 60.391t

Evaluating this expression at t = 120 seconds, we get:

s = 23 ln(433.044) + 7246.92 ≈ 16752.9 ft

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Jason had 246 dollars to spend on 6 books.after buying them he had 12 dollars. How much did each book cost?

Answers

Answer:

1 book = 41 dollars.

Step-by-step explanation:

If you divide your whole by your part, then you will get how much 1 book is.

how i did it:

246 divided by 6 = 41.

1 book = 41 dollars

amelia started with $54, and spent $6 each day at camp. she has $18 left.write and solve an equation that can be used to find in how many days, d she has left at camp.which equation can be used to determine how many days d she was at camp?

Answers

Amelia was at camp for 6 days. The equation used to determine how many days(D) she was at camp is C x D = 6D and S - (C x D) = E

Given data:

S = initial amount = $54

D = the number of days

C = the cost per day = $6

E: the ending amount = $18

Amelia started with S=$54 and spent C=$6 each day at camp.

Therefore, the total amount she spent at camp is given in an algebraic expression that states the product of two variables:

C x D = 6D

Next, she ended with E=$18. So, the equation can be written in algebraic expression that states the difference between the variable:

S - (C x D) = E

Substituting the values in the equation we get:

54 - 6D = 18

54 - 18 = 6D

36 = 6D

D = 6

Therefore, Amelia was at camp for 6 days.

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Put the following equation of a line into slope-intercept form, simplifying all
fractions.
9x + 3y = -9

Answers

Answer:

y=-3x-3

Step-by-step explanation:

9x+3y=-9

This is currently in standard form, or ax+by=c.

To get it to slope-intercept form, (y=mx+b) first subtract 9x to both sides.

3y=-9x-9

Divide both sides by 3.

y=-3x-3

Y=-3x-3

This is the answer hope this helped

which of the following is true for this image?
a. CD is the perpendicular bisector of AB
b. Neither line segment is a perpendicular bisector.
c. AB is the perpendicular bisector of CD
d. both line segments are perpendicular bisectors.

which of the following is true for this image? a. CD is the perpendicular bisector of AB b. Neither line

Answers

We have that  Options That are correct are given as

ACD

From the question we are told

Which of the following is true for this image?

a. CD is the perpendicular bisector of AB

b. Neither line segment is a perpendicular bisector.

c. AB is the perpendicular bisector of CD

d. both line segments are perpendicular bisectors.

Generally

CD is the perpendicular bisector of AB

This is True Because CD Cuts Across AB at angle 90 in the middle

Neither line segment is a perpendicular bisector.

This is Untrue Because CD Cuts Across AB at angle 90 in the middle

AB is the perpendicular bisector of CD

This is True Because AB Cuts Across CD at angle 90 in the middle

Both line segments are perpendicular bisectors.

This is True

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Please help me if you know the answer please

Please help me if you know the answer please

Answers

Part a: 240/15=16
16 x 15=240
The length of the land is 16 yards

Part b: 15+15+16+16= 62
The perimeter of the land is 62 yards.

Question 10 (15 points) Suppose a product has a log_linear demand given by:In(Q) = A - Bln (p) dQ a. Express Q as a function of p and show that: = dp -BQ P dQ b. Express "p" as a function of Q and fin

Answers

The log-linear demand function In(Q) = A - Bln(p) relates quantity demanded (Q) to price (p).

a. Q as a function of p:

Q = e^A / p^B

dp/dQ = -B * e^A / p^(B+1)

b. p as a function of Q:

p = e^(A/B) / Q^(1/B)



To solve this problem, let's start with the given demand function: In(Q) = A - Bln(p), where Q represents the quantity demanded, p is the price of the product, A and B are constants.

a. Express Q as a function of p:

To find the relationship between Q and p, we need to exponentiate both sides of the equation to remove the natural logarithm. By taking the exponential function, we get:

e^(In(Q)) = e^(A - Bln(p))

Using the property e^(A - Bln(p)) = e^A / e^(Bln(p)) = e^A / p^B, the equation becomes:

Q = e^A / p^B

Now, let's differentiate both sides of this equation with respect to p:

dQ/dp = d/dp(e^A / p^B)

To differentiate e^A / p^B, we can use the quotient rule:

dQ/dp = [e^A * (-B) * p^(B-1) - e^A * p^B * 0] / (p^B)^2

Simplifying this expression, we have:

dQ/dp = -B * e^A / p^(B+1)

b. Express "p" as a function of Q:

To find the relationship between p and Q, we can rearrange the equation Q = e^A / p^B:

p^B = e^A / Q

Now, taking the B-th root of both sides:

p = (e^A / Q)^(1/B)

Simplifying further:

p = e^(A/B) / Q^(1/B)

So, we have expressed "p" as a function of Q.

In summary, for the log-linear demand function In(Q) = A - Bln(p):

a. Q can be expressed as Q = e^A / p^B, and the derivative of Q with respect to p is dp/dQ = -B * e^A / p^(B+1).

b. p can be expressed as p = e^(A/B) / Q^(1/B).

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A marathon runner travels 2/3 in 10 minutes. What is the runners rate in miles per hour ?

Answers

The runner's rate in miles per hour is D * 4/3 miles per hour.

Describe Distance?

Distance is a measure of the physical space between two objects or points. It is the length of the shortest path between two points in space. Distance can be measured in different units, such as meters, kilometers, miles, feet, or inches, depending on the scale of the objects or the purpose of the measurement.

In geometry, the distance between two points in a Euclidean space can be calculated using the Pythagorean theorem or the distance formula. The distance formula is expressed as:

d = sqrt((x2 - x1)^2 + (y2 - y1)^2)

where d is the distance between two points (x1, y1) and (x2, y2) in a two-dimensional plane. This formula can be extended to three dimensions by adding a third term to the equation.

Distance can also be calculated using other methods, such as GPS (Global Positioning System) or by measuring the time it takes for an object to travel from one point to another, using the speed of light or sound.

In everyday life, distance is a fundamental concept used in various contexts, such as navigation, transportation, sports, and communication. It plays a significant role in determining the time and effort required to travel between two points and is often used as a basis for making decisions.

We can use the formula:

rate = distance / time

where distance is the distance traveled by the runner and time is the time taken to travel that distance.

Given that the runner travels 2/3 of the marathon distance in 10 minutes, we can find the total distance of the marathon by dividing the distance traveled by 2/3:

total distance = distance traveled / (2/3) = distance traveled * 3/2

Let's denote the total distance of the marathon as D. Then:

D = distance traveled * 3/2

distance traveled = D * 2/3

We know that the time taken to travel 2/3 of the distance is 10 minutes. Let's convert this to hours:

10 minutes = 10/60 hours = 1/6 hours

Now we can calculate the runner's rate:

rate = distance / time = (D * 2/3) / (1/6) = (D * 4/3) / 1 = D * 4/3

So the runner's rate in miles per hour is D * 4/3 miles per hour.

Note that we don't have a specific value for the total distance D of the marathon, so we cannot give a numerical answer. We can only express the runner's rate in terms of D as:

runner's rate = D * 4/3 miles per hour

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find the zeros of the polynomial function calculator with steps

Answers

equal your quadratic formula to 0 and solve
EX. 0= x^+2x+4
solve by quadratic equation for right answer
Quadratic formula= -b+- (square root) b^2-4ac all of it over 2a

The zeros of a polynomial function can be found using different methods such as factoring, the quadratic formula, and synthetic division. Factoring is used when the polynomial can be easily factored, the quadratic formula is used for quadratic polynomials that cannot be factored, and synthetic division is used for higher degree polynomials.

Finding zeros of a polynomial function

To find the zeros of a polynomial function, we need to solve the equation f(x) = 0, where f(x) represents the polynomial function.

There are different methods to find the zeros of a polynomial function, including:

 

Each method has its own steps and calculations involved. It is important to choose the appropriate method based on the degree of the polynomial and the available information.

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a circle is centered at the vertex of the angle, and 1/360th of the circumference is 0.04 cm long. what is the length of the arc subtended by the angle's rays?

Answers

The length of the arc subtended by the angle's rays is 0.02 times the radius of the circle



To find the length of the arc subtended by the angle's rays, we need to know the angle measure. Since we know that 1/360th of the circumference is 0.04 cm long, we can find the circumference by multiplying 0.04 cm by 360, which gives us 14.4 cm.

Now, we need to find the angle measure. Since the circle is centered at the vertex of the angle, the angle measures half the arc it subtends. Thus, we can find the angle measure by dividing the circumference by 2 and then multiplying by 1/360.

Angle measure = (14.4/2) x (1/360) = 0.02 radians

Finally, we can find the length of the arc subtended by the angle's rays by multiplying the angle measure by the radius of the circle.

Length of arc = 0.02 x radius


The length of the arc subtended by the angle's rays is 0.02 times the radius of the circle. The given information of 1/360th of the circumference being 0.04 cm long helped us find the circumference and subsequently the angle measure.

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A population of crabs is growing according to the logistic growth equation, with r=1.1 and carrying capacity of 500crabs. At which population size will the population grow the fastest? In a year tracking a population of widowbirds, you recorded that 150 individuals were born, 75 birds died. If λ=2, how many birds were there when you started tracking the population?

Answers

The population will grow the fastest at half of the carrying capacity, which is 250 crabs.

In the logistic growth equation, the population growth rate is highest when the population is at half of the carrying capacity. This is because, at this point, there is a balance between birth rates and death rates, maximizing the net population growth.

For the given logistic growth equation with a carrying capacity of 500 crabs, the population will grow the fastest at half of the carrying capacity, which is 250 crabs.

Regarding the second question, to determine the initial population size of widowbirds when tracking started, we can use the equation λ = (births - deaths) / initial population.

Given that 150 individuals were born and 75 birds died during the tracking period, and λ is equal to 2, we can solve the equation for the initial population.

2 = (150 - 75) / initial population

Multiplying both sides by the initial population:

2 * initial population = 150 - 75

2 * initial population = 75

Dividing both sides by 2:

initial population = 75 / 2

initial population = 37.5

Since population size cannot be a decimal, we round down to the nearest whole number.

Therefore, when tracking the population of widowbirds, the initial population size would be approximately 37 birds.

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A middle school art teacher wishes to teach his class about costume design. He divides the class into three groups at random, each of which is tasked with designing a mascot costume for a fictional sports team, with a prize going to the best design. The student teams then spend a week designing and building their mascot costumes. Several weeks later, the teacher is surprised to discover that a rivalry has formed between the various teams, who have formed cliques even outside the classroom. What explains the reason that this rivalry has formed

Answers

The reason that this rivalry has formed is that a common goal has been set for a greater number of groups than the one that could obtain a positive result, generating a competition between these that implies a constant desire to overcome the other groups.

Thus, the existence of these common objectives makes competition take place, and generates tensions between the groups.

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Need help with 5 hurry I have to go somewhere in 5 minutes

Need help with 5 hurry I have to go somewhere in 5 minutes

Answers

Answer:

c. What is your favorite book?

Explanation:

A question is said to be biased when it is asked in such a way that it leads or skews people intentionally to a particular answer.

Looking at the given questions in the options, we can see that three of them have a particular person or thing mentioned in the question. These are examples of biased questions.

But the question, "What is your favorite book?" does not suggest a name of a particular book to the respondent which could influence their responses. This type of question is not biased.

PLEASE HELP OR IM GET F

PLEASE HELP OR IM GET F

Answers

(8+15+8+3+12)/2+1=24th number will be median

So median is gonna be 21

Answer:

15

Step-by-step explanation:

Order the numbers from least to greates

3,8,8,12,15,15,18,21,28,33

The middle number is the median

In this case it is the two 15

Now you have to find the mode of 15 and 15

To find teh mode add 15 and 15 to get 30 then divided 30 by two to get 15

Your median is 15


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PLEASE ANSWER QUICK THIS IS DUE TODAY!!

-6+7m = 6m - m

Answers

Answer:

m = 3

Step-by-step explanation:

Hello!

We can solve for m by isolating the variable.

Solve for m-6 + 7m = 6m - m-6 + 7m = 5m                 => Simplify7m = 5m + 6                  => Add 6 to both sides2m = 6                           => Simplifym = 3                             => Divide by 2

The value of m is 3.

Verify that each given function is a solution of the differential equation (each 10 pts).1. y"-4y = 0;1) y(t) = e2t,2) y(t) = cosht2. y" + 2y - 3y= 0;1) y(t) = e-31,2) y(t) = et3. 12y" + 5ty' + 4y = 0, t> 0; 1) y(t) = t2,2) y(t) = t2n t4. y" + y = sect; 0

Answers

To verify if each given function is a solution of the differential equation, we need to substitute the function into the differential equation and check if the equation holds true.

For the differential equation y" - 4y = 0:

a) Substitute y(t) = e^(2t):

y" = (e^(2t))'' = 4e^(2t)

4y = 4e^(2t)

The equation y" - 4y = 0 holds true.

b) Substitute y(t) = cosh(t):

y" = (cosh(t))'' = cosh(t)

4y = 4cosh(t)

The equation y" - 4y = 0 holds true.

For the differential equation y" + 2y - 3y = 0:

a) Substitute y(t) = e^(-3t):

y" = (-3e^(-3t))

2y = 2e^(-3t)

The equation y" + 2y - 3y = 0 holds true.

b) Substitute y(t) = e^(t):

y" = e^(t)

2y = 2e^(t)

The equation y" + 2y - 3y = 0 holds true.

For the differential equation 12y" + 5ty' + 4y = 0, t > 0:

a) Substitute y(t) = t^2:

y" = 2

y' = 0

5ty' = 0

12y" + 5ty' + 4y = 12(2) + 0 + 4(t^2) = 24 + 4t^2

The equation 12y" + 5ty' + 4y = 0 holds true.

b) Substitute y(t) = t^2:

y" = 2

y' = 0

5ty' = 0

12y" + 5ty' + 4y = 12(2) + 0 + 4(t^2) = 24 + 4t^2

The equation 12y" + 5ty' + 4y = 0 holds true.

For the differential equation y" + y = sec(t):

a) Substitute y(t) = sec(t):

y" = sec(t)tan(t)

y = sec(t)

The equation y" + y = sec(t) holds true.

b) Substitute y(t) = sec(t):

y" = sec(t)tan(t)

y = sec(t)

The equation y" + y = sec(t) holds true.

Therefore, each given function is a solution to its respective differential equation.

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Question 1
Tell whether the angles are adjacent or vertical. Then find the value of x.

Question 1Tell whether the angles are adjacent or vertical. Then find the value of x.

Answers

Step-by-step explanation:

The angles are vertical because they are opposite to each other

75 = 4x -25 vertical angles

100 = 4x

x= 25° Algebra

Answer:

X = 25 degrees

Definitions:

Vertical: Opposite angles/angles that share a common side.

Adjacent: Congruent meaning same measure.

Step-by-step explanation:

This equation would be vertical because they are opposite from eachother:

Our equation would look like this:

75 = 4x - 25

Then add 75 and 25 to get 100:

75 + 25 = 100

Now our equation would look like this:

100 = 4x

Lastly, divide 100 with 4:

100 ÷ 4 = 100

Side note: 25 x 4 = 100

Your answer would be x = 25 degrees.

            Hope this helps!

      ~Hocus Pocus

Find the length of side x.
Give answer to 1dp.

Find the length of side x.Give answer to 1dp.

Answers

Answer:

Set your calculator to degree mode.

Use the Law of Cosines.

x^2 = 18^2 + 15^2 - 2(18)(15)(cos 105°)

x^2 = 688.7623

x = 26.2 cm

the correct answers.
Which expressions are in simplest form?
O a√60b
O 49√a
O9a²b√5ab
√28a³b8
O4a²√6³

Answers

The expression that is in simplest form is: 49√a

Two cars travel at the same speed to different destinations. Car A reaches its destination in 12 minutes. Car B reaches its destination in 18 minutes. Car B travels 4 miles farther than Car A. How fast do the cars travel? Write your answer as a fraction in simplest form.

Answers

Answer:

chatGPT

Step-by-step explanation:

Let's denote the speed of each car as v, and the distance that Car A travels as d. Then we can set up two equations based on the information given:

d = v * (12/60) (since Car A reaches its destination in 12 minutes)

d + 4 = v * (18/60) (since Car B travels 4 miles farther than Car A and reaches its destination in 18 minutes)

Simplifying the equations by multiplying both sides by 60 (to convert the minutes to hours) and canceling out v, we get:

12v = 60d

18v = 60d + 240

Subtracting the first equation from the second, we get:

6v = 240

Therefore:

v = 240/6 = 40

So the cars travel at a speed of 40 miles per hour.

1. Differentiate the function f(x) = ln (81 sin^2 (x)) f’(x) 2. Differentiate the function P(t) = in ( √t2 + 9) p' (t) 3. if x2 + y2 + z2 = 9, dx/dt = B, and dy/dt = 4, find dz/dt when (x,y,z) = (2,2,1)
dz/dt =

Answers

First you will get 4dz

Use the following scenario to solve for questions 59 and 60 The population of a small town can be modeled by the equation P = 3750(0.88)', where is the population and t is the number of years since 2000 1 pts According to the model, approximately how many people will be in the town in 2020? 1 In what year will the population drop below 100?

Answers

According to the model, the population of the town in 2020 will be approximately 236 people. The population will drop below 100 in the year 2037.

To find the population of the town in 2020, we can substitute t=20 into the equation P=3750(0.88)^t. This gives us P=3750(0.88)^20=236. Therefore, according to the model, the population of the town in 2020 will be approximately 236 people.

To find the year in which the population will drop below 100, we can solve the equation P=100 for t. This gives us t=log(100)/log(0.88)=37. Therefore, the population will drop below 100 in the year 2037.

It is important to note that this is just a model, and the actual population of the town may not follow this trend.

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Which of the following shows the correct first step to solve x^2-18x=-45

A x^2 - 18x + 18= -45 + 18
B. x^2 - 18x + 9 = -45 + 18
C. x^2 -18x + 81 = -45
D. X^2 -18 + 81 = -45 + 81

Answers

Answer:

D, X^2 -18 + 81 = -45 + 81

Step-by-step explanation:

it is complating squer method that used for solving x in a quadratic equetion . in this step you will add

(y/2)^2 if y is the cofitient of x .

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