Answer:
About 65%
hope this helps a little
For the following word problems, create a system of equations and solve by using the substitution method.
We will solve as follows:
*We have the equations:
\(9.50A+27.00B=4000\)&
\(A+B=200\)We solve then for the second equation [Either for A or B], that is:
\(A=200-B\)Now, we replace in the first equation and solve for B:
\(9.50(200-B)+27.00B=400\Rightarrow1900-9.50B+27.00B=4000\)\(=17.5B+1900=4000\Rightarrow17.5B=2100\)\(\Rightarrow B=120\)Now, we replace the value of B in the second equation:
\(A=200-(120)\Rightarrow A=80\)So, the investor has 80 shares on stock A and 120 shares on stock B.
Which of these shapes will tessellate without leaving gaps? A. Hexagon B. Octagon C. Pentagon D. Circle
The shape that can tessellate without leaving gaps is the hexagon (option A).
The shapes that can tessellate without leaving gaps are shapes that can be repeated to completely cover a flat surface without any overlaps or gaps. Among the options provided, the shape that will tessellate without leaving gaps is the hexagon (option A).
A hexagon is a six-sided polygon with equal sides and angles. It is a regular polygon, which means all of its sides and angles are equal. A regular hexagon can be arranged and repeated in a pattern to fill a plane without any gaps or overlaps. Bees' honeycombs are a real-world example of hexagonal tessellation.
On the other hand, octagons (option B) and pentagons (option C) do not tessellate by themselves without gaps. While they can be used in combination with other shapes to create tessellations, they cannot tessellate on their own.
A circle (option D) cannot tessellate without leaving gaps. A circle is a curved shape, and it cannot form a repeating pattern that completely covers a flat surface without overlaps or gaps.
In summary, the shape that can tessellate without leaving gaps is the hexagon (option A).
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Order these numbers from least to greatest 7.15 , 7 18/25 , 7.134 , 77/10
Parallelogram ABCD will be translated so that D' will be located at (1, 2). What would be the location ofpoint B'?BD(5,0)OO (-2,5)
The original coordinate of point D is D(4,3)
The new coordinate of point D' is (-1,2).
The translation about the x axis is 4-(-1)=5
The translation about the y axis is 3-2=1
The original coordinate of point B is (2,5)
The new coordinate of e of
HELP URGENT PLEASSSSSSSSSSSSSSEEEEEEEEEEEEEEEE
Answer:
1 4/5 pounds each
Step-by-step explanation:
9/5 = 1 4/5
what is 2.5 x 12.34 give a good explanation
Answer:
30.85
Step-by-step explanation:
1. Put the 12.34 on top to make things simpler
then just multiply each number as if the decimals weren't there to begin with.
Your answer should look way too big, but when you finish multiplying count how many decimal places were in the two numbers, for this it would be 3 since there is a 5, 3, and 4 behind the decimal places.
You have to count 3 decimal places in your final answer to get the right solution! Any 0's trailing behind can be removed as well.
Hope this helps!!!
Answer: 30.85
Step-by-step explanation:
This is the answer because you have to straight up your decimal so you can multiply your numbers up right and every time you get ready to add you suppose to add a extra zero.
Need help with this equation 8x²+10x-3
Answer:
Step-by-step explanation:
You have to use the quadratic formula
x = -b +/- \(\sqrt{(b^{2} -4ac)/2a\)
and then you can simplify both answers so the first one would be -13/2 and the second would be -27/2
you usually have to reject an answer but since there is no equal sign in the question, you should be fine
2.1. Provide a general rule to describe the relationship between the dates of spread and number of people infected infected.
The relationship between the dates of spread and the number of people infected can vary depending on various factors such as the infectiousness of the disease, the effectiveness of containment measures, population density, and individual behaviors.
However, there is a general rule that can describe the relationship:As the dates of spread progress, the number of infected individuals tends to increase initially, reaching a peak, and then gradually decreasing over time.
This pattern is often referred to as the epidemic curve or the epidemiological curve. In the early stages of an outbreak, the number of cases may grow rapidly as the disease spreads through a susceptible population. This rapid increase is often influenced by factors such as the contagiousness of the disease, population density, and social interactions.
As containment measures, such as vaccination campaigns, public health interventions, and behavioral changes, are implemented, the rate of new infections may start to decline. This can lead to a peak in the number of cases, after which the curve gradually decreases as the disease is brought under control and fewer susceptible individuals remain.
It's important to note that the specific shape, duration, and magnitude of the epidemic curve can vary significantly depending on the disease and the effectiveness of the response measures implemented. Additionally, emerging variants, changes in behavior, and other factors can impact the trajectory of the epidemic curve.
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A coffee merchant sells two blends of coffee. Each pound of blend A contains 80% Mocha Java and 20% Jamaican and sells for $3 a pound. Each pound of blend B contains 35% Mocha Java and 65% Jamaican and sells for $2.25 a pound. The merchant has available 1000 pounds of Mocha Java and 600 pounds of Jamaican. Let x be the number of pounds of blend A and y be the number of pounds of blend B. The merchant will try to sell the amount of each blend that maximizes her Revenue. Let X be the number of pounds of blend A and Y be the number of pounds of blend B.
a. In the situation above, the objective function is: ___________
b. Since the merchant above has available 1000 pounds of Mocha Java, one constraint that must be satisfied is:
c. Since the merchant above has available 600 pounds of Jamaican, one constraint that must be satisfied is:
M = I1+I₂ 31 +32 2 Now let's substitute in our given values. (-2 , 2) = ((-5 Find 2 and y2 We will now set up two equations to solve for our two unknowns of x2 and y₂. (-5 X2 (-5+₂) -5+22), (7+)) 2 - +₂)/2 = We will first want to multiply by 2 on both sides and will get −5+₂= -4 Adding 5 to both sides we get = 7 This is the coordinate of point B. Now we will set up the equation to solve for y2 +y2)/2 =
The coordinates of point B are (-3, 17).
The given equation is M = I₁ + I₂ = 31 + 32.
Now let's substitute in our given values:
(-2, 2) = ((-5 + x₂) / 2, (-5 + 2 + y₂) / 2)
We will now set up two equations to solve for our two unknowns, x₂ and y₂:
Equation 1: (-5 + x₂) / 2 = -4
Multiply both sides by 2:
-5 + x₂ = -8
Add 5 to both sides:
x₂ = -3
This gives us the x-coordinate of point B.
Equation 2: (-5 + 2 + y₂) / 2 = 7
Simplify:
(-3 + y₂) / 2 = 7
Multiply both sides by 2:
-3 + y₂ = 14
Add 3 to both sides:
y₂ = 17
This gives us the y-coordinate of point B.
Therefore, the coordinates of point B are (-3, 17).
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A 95% confidence interval was computed around a sample mean of 10. The resulting confidence interval is (5, 11). Does this appear to be a valid confidence interval
Answer: No
Step-by-step explanation:
A confidence interval gives the range of values in which the true population parameter lies.It is computed by considering sample mean in the center.
But here 10 does not lie in the center of (5, 11), as distance between 10 and 5 = 5 units but distance between 10 and 11 = 1 unit
2 different margin of errors cannot be possible.
Hence, the given confidence interval is not valid.
If x = 35°, which two lines can be proven parallel?
a)n and o
b)l and m
c)n and l
d)m and o
Answer:
a) n and o
Step-by-step explanation:
by the concept of corresponding angles, angles that are equal when a line intersects 2 parallel lines .
l is the line that intersects n and o, and since x = 35, theyre corresponding angles resulting in n and o being parallel
Answer:
a) n and o
Step-by-step explanation:
Corresponding angles
Yesterday, drove 44 and 1 half
miles. used 1 and 1 fourths
gallons of gasoline. What is the unit rate for miles per gallon?
Answer:
The unit rate for miles per gallons is 35.6 miles per gallon used by him.
Step-by-step explanation:
In the given condition he drove 44 and 1/2 miles and used a total of 1 and 1/4 gallons of gasoline.
Now, we have to calculate the number of miles he travelled in each gallon.
So, 44 and 1/2 miles can be written as 44.5 miles.
And 1-1/4 gallons can be written as 1.25 gallons.
Now, we need to form an equation from the above condition;
=> 44.5 = 1.25
=> x = 1 (here, x is the number of miles per gallon)
Now, after cross multiplying the equation;
=> 44.5 × 1 = 1.25 × x
=> 44.5 = 1.25 x
=> 44.5 / 1.25 = x
=> x = 35.6 miles per gallon
Therefore, the unit rate for miles per gallons is 35.6 miles per gallon used by him.
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Erica has 7 square feet of garden space to plant carrots beans pepper and lettuce. Supposed she gives each vegetable an equal amount of space. How much space will each vegetable get?
What is the scale factor? Question 4 options: 6 3 1/3 1/6
The scale factor is discussed below.
What is scaling? How is it done?Scaling is defined as the process of changing the dimensions of the original figure as per some specific proportional rule.If the initial length is equivalent to {a}. Then, after the scaling by the scale factor of {K}, the length becomes {Ka}. Similarly, if the initial coordinates are (x, y) then after scaling the coordinates would be {Kx, Ky}.Given is the scale factor.
Scale factor is a dimensionless quantity that tells by how much time a specific dimension of a figure is enlarged or reduced. Mathematically, it is the ratio of two similar quantities. In case of length scaling, we can write -
K = L{final}/L{initial}
Therefore, the scale factor is discussed above.
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in how many ways can people be lined up to get on a bus if specific persons always insist on following each other (that is the persons are in a group)? (enter an integer answer.) hint: the queue order matters. e.g., suppose the 5 individuals are denoted as a,b,c,d,e. then, queue abcde is not the same as edcba.
There are two approaches which include mathematical concept permutation and combination and another approach is the inclusion-exclusion principle.
If there are n people, the total number of ways they may be organized to board the bus is n! This is because the first location in the line has n possibilities, the second has n-1 possibilities, and so on until the last position has just one possibility.
Combinatorics is another option. This entails counting the number of potential person pairings for each category. For example, if a group consists of three persons, there are three potential combinations (abc, acb, bac).
The number of viable combinations grows exponentially as the number of persons in each group grows.
Finally, a more advanced technique is to employ the inclusion-exclusion principle.
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Mid-West Publishing Company publishes college textbooks. The company operates an 800 telephone number whereby potential adopters can ask questions about forthcoming texts, request examination copies of texts, and place orders. Currently, two extension lines are used, with two representatives handling the telephone inquiries. Calls occurring when both extension lines are being used receive a busy signal; no waiting is allowed. Each representative can accommodate an average of 15 calls per hour. The arrival rate is 30 calls per hour.
How many extension lines should be used if the company wants to handle 90% of the calls immediately?
fill in the blank 1
lines should be used
What is the average number of extension lines that will be busy if your recommendation in part (a) is used? Round your answer to four decimal places.
L = fill in the blank 2
What percentage of calls receive a busy signal for the current telephone system with two extension lines? Round your answer to two decimal places.
fill in the blank 3
%
The various answers to the question are:
To answer 90% of calls instantly, the organization needs four extension lines.The average number of extension lines that will be busy is FourFor the existing phone system with two extension lines, 34.25 % of calls get a busy signal.How many extension lines should be used if the company wants to handle 90% of the calls immediately?a)
A number of extension lines needed to accommodate $90 in calls immediately:
Use the calculation for busy k servers.
\($$P_{j}=\frac{\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}}{\sum_{i=0}^{k} \frac{\left(\frac{\lambda}{\mu}\right)^{t}}{i !}}$$\)
The probability that 2 servers are busy:
The likelihood that 2 servers will be busy may be calculated using the formula below.
\(P_{2}=\frac{\frac{\left(\frac{20}{12}\right)^{2}}{2 !}}{\sum_{i=0}^{2} \frac{\left(\frac{20}{12}\right)^{t}}{i !}}$$\approx 0.3425$\)
Hence, two lines are insufficient.
The probability that 3 servers are busy:
Assuming 3 lines, the likelihood that 3 servers are busy may be calculated using the formula below.
\(P_{j}=\frac{\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}}{\sum_{i=0}^{2} \frac{\left(\frac{\lambda}{\mu}\right)^{i}}{i !}}$ \\\\$P_{3}=\frac{\frac{\left(\frac{20}{12}\right)^{3}}{3 !}}{\sum_{i=0}^{3} \frac{\left(\frac{20}{12}\right)^{1}}{i !}}$$\approx 0.1598$\)
Thus, three lines are insufficient.
The probability that 4 servers are busy:
Assuming 4 lines, the likelihood that 4 of 4 servers are busy may be calculated using the formula below.
\(P_{j}=\frac{\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}}{\sum_{i=0}^{k} \frac{\left(\frac{\lambda}{\mu}\right)^{t}}{i !}}$ \\\\$P_{4}=\frac{\frac{\left(\frac{20}{12}\right)^{4}}{4 !}}{\sum_{i=0}^{4} \frac{\left(\frac{20}{12}\right)^{7}}{i !}}$\)
Generally, the equation for is mathematically given as
To answer 90% of calls instantly, the organization needs four extension lines.
b)
The probability that a call will receive a busy signal if four extensions lines are used is,
\(P_{4}=\frac{\left(\frac{20}{12}\right)^{4}}{\sum_{i=0}^{4} \frac{\left(\frac{20}{12}\right)^{1}}{i !}} $\approx 0.0624$\)
Therefore, the average number of extension lines that will be busy is Four
c)
In conclusion, the Percentage of busy calls for a phone system with two extensions:
The likelihood that 2 servers will be busy may be calculated using the formula below.
\(P_{j}=\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}$$\\\\$P_{2}=\frac{\left(\frac{20}{12}\right)^{2}}{\sum_{i=0}^{2 !} \frac{\left(\frac{20}{12}\right)^{t}}{i !}}$$\approx 0.3425$\)
For the existing phone system with two extension lines, 34.25 % of calls get a busy signal.
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Negative 3 (8 minus 5) squared minus (negative 7) = negative 3 (3) squared minus (negative 7) = negative 3 (9) minus (negative 7) = 27 minus (negative 7) = 34.
What was Huda’s error?
Huda evaluated (3) squared incorrectly.
Huda found the product of –3 and 9 as positive.
Huda subtracted –7 from 27 incorrectly.
Huda did not follow the order of operations.
Huda's error in evaluating (3) squared incorrectly led to the incorrect final result.
The correct answer should be -20, not 34.
Huda's error was that she evaluated (3) squared incorrectly.
Instead of calculating 3 squared as 9, she mistakenly considered it as 3. This error led to incorrect subsequent calculations and the final result of 34, which is not the correct answer.
To evaluate the expression correctly, let's go through the steps:
Negative 3 (8 minus 5) squared minus (negative 7) \(= -3(3)^2 - (-7)\)
First, we simplify the expression within the parentheses:
\(-3(3)^2 - (-7) = -3(9) - (-7)\)
Next, we evaluate the exponent:
-3(9) - (-7) = -3(9) + 7
Now, we perform the multiplication and addition/subtraction:
-3(9) + 7 = -27 + 7 = -20
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help me pls? it will mean a lot
Answer:
48 boys
Step-by-step explanation:
ratio girls to boys = 5:4
There are 60 girls
60/5 = 12
4 x 12 = 48
There are 48 boys
If my answer is incorrect, pls correct me!
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-Chetan K
15. Jim had 103 red and blue marbles. After giving of his blue marbles and 15 of his red marbles
to Samantha, Jim had as many red marbles as blue marbles. How many blue marbles did he
originally have?

This question above is incomplete
Complete Question
Jim had 103 red and blue marbles. After giving 2/5 of his blue marbles and 15 of his red marbles to Samantha, Jim had 3/7 as many red marbles as blue marbles. How many blue marbles did he have originally?
Answer:
70 Blue marbles
Step-by-step explanation:
Let red marbles = R
Blue marbles = B
Step 1
Jim had 103 red and blue marbles.
R + B = 103.......Equation 1
R = 103 - B
Step 2
After giving 2/5 of his blue marbles and 15 of his red marbles to Samantha, Jim had 3/7 as many red marbles as blue marbles
2/5 of B to Samantha
Jim has = B - 2/5B = 3/5B left
He also gave 15 red marbles to Samantha
= R - 15
The ratio of what Jim has left
= Red: Blue
= 3:7
= 3/7
Hence,
R - 15/(3/5)B = 3/7
Cross Multiply
7(R - 15) = 3(3/5B)
7R - 105 = 3(3B/5)
7R - 105 = 9B/5
Cross Multiply
5(7R - 105) = 9B
35R - 525 = 9B............ Equation 2
From Equation 1, we substitute 103 - B for R in Equation 2
35(103 - B) - 525 = 9B
3605 - 35B - 525 = 9B
Collect like terms
3605 - 525 = 9B + 35B
3080 = 44B
B = 3080/44
B = 70
Therefore, Jim originally had 70 Blue marbles.
What is 56048 divided by 543
Step-by-step explanation:
56048 divided by 543= 103.219153
Answer:
its 103.2
Step-by-step explanation:
Tom and John are engaged in buying and selling certain products A and B. Tom BUYS 5 of product A but SELLS twice as much of product B. John on the other hand SELLS three times what Tom BOUGHT of product A and BUYS 13 of product B. At the end of the business day, John banks Ksh 110,000/- while Tom banks Ksh 230,000. Under the assumption that the sale prices for product A and B are the same for the two men, and the costs prices for the products A and B are also the same for the two men, obtain the following: a) The price for product A and the price for product B
ANSWER QUICK!!!!!!!!
Answer:
y=15
DE=11
GF=17
Step-by-step explanation:
y*2=5*6
2y=30
y=15
5+6=11
15+2=17
can you do problem 9 with steps
Answer:
x = 4
Step-by-step explanation:
Two tangent segments drawn to a circle from the same point outside the circle are congruent.
7x - 3 = 5x + 5
Subtract 5x from both sides.
2x - 3 = 5
Add 3 to both sides.
2x = 8
Divide both sides by 2.
x = 4
Suppose that, starting at a certain time, batteries coming off an assembly line are examined one by one to see whether they are defective (let D = defective and N = not defective). The chance experiment terminates as soon as a nondefective bettery is obtained.a. Give five possible outcomes for this chance experiment.b. What can be said about the number of outcomes in the sample space?c. What outcomes are in the event E, that the number of battery examined is an number?
Answer:
a. Possible outcomes for this chance experiment are:
NDNDDNDDDNDDDDN(Here, D means a defective battery, and N means a nondefective battery.)
b. The number of outcomes in the sample space is infinite, as the experiment could potentially continue indefinitely. However, in practice, we can define a maximum number of batteries that could be examined before the experiment is stopped.
c. The event E, that the number of batteries examined is a number, would include outcomes where the experiment stopped at a particular number of batteries. For example, if the experiment stopped after examining three batteries (i.e., the fourth battery was nondefective), then the outcome would be DDDN, and it would be included in event E. However, outcomes where the experiment continued indefinitely (e.g., DDDDD...) would not be included in event E.
please answer thank you !
The volume of the squared pyramid is 9 cubic yards, so the correct option is D.
What is the volume of the ice pyramid?For a square pyramid of sidelength S (S is the sidelength of the square base), the volume is given by the formula:
V = (1/3)*S^3
Here we want to find the volume if S = 3 yards, so we just need to replace that in the formula above to get the volume of the sculpture, we will get:
V = (1/3)*(3 yd)^3
V = (1/3)*(27 yd^3)
V = 9 yd^3
The volume is 9 cubic yards, then the correct option is D.
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11. x and Y are complementary angles and Tan x = 3√3. Find the value of
\( \frac{1}{2 - tan \: y\\ } \)
Hence rationalise the surd
Answer:
\(\frac{1}{2-tan(y)} = \frac{3\sqrt{3}}{6\sqrt{3}-1}\)
After Rationalising:
\(\frac{1}{2-tan(y)} = \frac{54 +3\sqrt{3}}{107}\)
Step-by-step explanation:
tan(x) = 3√3
x + y = 90 (complimentary angles)
⇒ x = 90 - y
tan(\(\frac{\pi}{2}\) - θ) = cot(θ)
⇒ tan(90 - θ) = cot(θ)
⇒ tan(90 - y) = cot(y)
⇒ tan(x) = cot(y)
⇒ cot(y) = 3√3
⇒ \(\frac{1}{tan(y)}\) = 3√3
⇒ tan(y) = \(\frac{1}{3\sqrt{3}}\)
\(2-tan(y) = 2 - \frac{1}{3\sqrt{3}} \\\\= \frac{2*3\sqrt{3} -1}{3\sqrt{3} } \\\\= \frac{6\sqrt{3} -1}{3\sqrt{3} }\\\\\\\implies \frac{1}{2-tan(y)} \\\\= \frac{3\sqrt{3}}{6\sqrt{3}-1}\)
Multiply and divide by : 6(√3) + 1
\(\frac{3\sqrt{3}}{6\sqrt{3}-1}\frac{6\sqrt{3}+1}{6\sqrt{3}+1}\\ \\= \frac{(3*6*\sqrt{3}*\sqrt{3}) + 3\sqrt{3}}{6^2 * (\sqrt{3})^2 -1^2}\\\\= \frac{18*3 +3\sqrt{3}}{36*3 -1}\\\\= \frac{54 +3\sqrt{3}}{108-1}\\\\= \frac{54 +3\sqrt{3}}{107}\)
When writing 7–√979 as 7n7n, which statement is true about the value of n?
\((\sqrt[9]{7} = 7^{1/9}\) is true about the value of n in polynomial.
What is a polynomial, simply put?
Using mathematical operations like addition, subtraction, multiplication, and division, a polynomial is an equation made up of variables, constants, and exponents (No division operation by a variable).
A polynomial function is a function that can be expressed in the form of a polynomial. The definition can be derived from the definition of a polynomial equation. A polynomial is generally represented as P(x). The highest power of the variable of P(x) is known as its degree.
the value of n is 1/9 because (\((\sqrt[9]{7} )^{9}\) = 7¹
and ( \((7^{1/9})^{9}\) = 7¹
\((\sqrt[9]{7} = 7^{1/9}\)
is correct option .
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Personal finance 9.2
Answer:
nice!
Step-by-step explanation:
24. This week, Cristina eamed P594.65 from selling burgers for 35 days. How much he will earn in 5 days?
A. P84.95
B. P94.95
C. P104.95
D. P114.95
25. You have four quizzes in your math subject in a quarter. You got 88.75 for the first quiz, 85.5, 90.5, and 87.25 in the second, third and fourth quizzes, respectively. What is your average in the four quizzes this quarter?
A. 86.5
B. 88
C. 89.5
D. 90 26. Amberich put P580.00 into a savings account for one year. The rate of interest on the account was 6.5%. How much was the interest for one year in pesos and centavos?
A. P67.70
B. P37.70
C. P57.70
D. P17.70
24. This week , Cristina eamed P594.65 from selling burgers for 35 days . How much he will earn in 5 days ?
A. P84.95
B. P94.95
C. P104.95
D. P114.95
25. You have four quizzes in your math subject in a quarter . You got 88.75 for the first quiz , 85.5 , 90.5 , and 87.25 in the second , third and fourth quizzes , respectively . What is your average in the four quizzes this quarter ?
A. 86.5
B. 88
C. 89.5
D. 90
26. Amberich put P580.00 into a savings account for one year . The rate of interest on the account was 6.5 % . How much was the interest for one year in pesos and centavos ?
A. P67.70
B. P37.70
C. P57.70
D. P17.70
Question 24 :
P594.65 : 35 days
P594.65/7 : 35/7 days
P84.95 : 5 days
⇒ A. P84.95
Question 25 :
88.75 + 85.5 + 90.5 + 87.25 / 4
352/4
88
⇒ B. 88
Question 26 :
I = P × r × t
I = 580.00 × 0.065 × 1
I = P37.70
⇒ B. P37.70