To calculate the difference in volume of air in the shop when the temperature changes from 20.0 Celsius to 0 Celsius, we can use the ideal gas law.
The ideal gas law states that PV = nRT, where P is pressure, V is volume, n is the number of moles of gas, R is the ideal gas constant, and T is temperature in Kelvin.
First, we need to convert the temperatures from Celsius to Kelvin:
20.0 Celsius + 273.15 = 293.15 Kelvin
0 Celsius + 273.15 = 273.15 Kelvin
Next, we assume that the pressure and the number of moles of gas remain constant. Therefore, we can rearrange the ideal gas law equation to solve for the volume ratio:
V1 / V2 = T1 / T2
V1 = 500 m^3 (volume at 20.0 Celsius)
V2 = Unknown volume at 0 Celsius
T1 = 293.15 Kelvin (temperature at 20.0 Celsius)
T2 = 273.15 Kelvin (temperature at 0 Celsius)
Plugging in the values, we have:
500 m^3 / V2 = 293.15 K / 273.15 K
Now we can solve for V2:
V2 = (500 m^3 * 273.15 K) / 293.15 K
Calculating this equation gives us the volume at 0 Celsius:
V2 ≈ 467.21 m^3
Therefore, the difference in volume when the temperature changes from 20.0 Celsius to 0 Celsius is approximately:
500 m^3 - 467.21 m^3 = 32.79 m^3
Jack plays floor hockey. He moves with a velocity of 7.5 m/s [East] for 2.25 seconds. What is his displacement during this time? show your work below.
Answer:
16.875 m [East]
Explanation:
In a velocity time displacement problems
displacement is given by
displacement of moving body = velocity of the that body * time
displacement will be in the direction of velocity of body.
Given
velocity = 7.5 m/s [East]
time = 2.25 seconds
displacement = 7.5 m/s [East] *2.25 seconds
displacement = 16.875 m [East]
Thus, displacement of jack is 16.875 m [East].
Help me with this please
Submit the assignment following the instructions in the lesson assessment 01.05 measuring physical properties
Answer:jeff gordon is a boss
Explanation: i am so cool thats how i know its correct
. A car starts to move from rest has an acceleration of 3m/s².what will be the velocity and distance travelled by the car after 50sec.
Sure! Here are the steps for calculating the velocity and distance traveled by the car after 50 seconds :
Step 1: Calculate the velocity using the equation:
\(v = u + at\)
where:
- \(v\) is the final velocity
- \(u\) is the initial velocity (0 m/s, as the car starts from rest)
- \(a\) is the acceleration (3 m/s²)
- \(t\) is the time (50 seconds)
Substituting the values into the equation:
\(v = 0 + (3 \, \text{m/s²}) \times (50 \, \text{s})\)
Step 2: Calculate the distance traveled using the equation:
\(s = ut + \frac{1}{2}at^2\)
where:
- \(s\) is the distance traveled
- \(u\) is the initial velocity (0 m/s)
- \(a\) is the acceleration (3 m/s²)
- \(t\) is the time (50 seconds)
Substituting the values into the equation:
\(s = 0 \times (50 \, \text{s}) + \frac{1}{2} \times (3 \, \text{m/s²}) \times (50 \, \text{s})^2\)
Now, let's simplify these equations:
\(v = 3 \times 50\)
\(s = \frac{1}{2} \times 3 \times 50^2\)
Calculating the results:
\(v = 150\) m/s
\(s = 3750\) meters
Therefore, after 50 seconds, the car will have a velocity of 150 m/s and would have traveled a distance of 3750 meters.
A rocket initially traveling straight up at a speed of 20. 0 m/s undergoes constant acceleration in the direction of travel to a speed of 30. 0 m/s over a distance of 40. 0 m. What is the magnitude of the rocket's acceleration?
0. 125
2. 50
6. 50
12. 5
The magnitude of the rocket's acceleration is 12.5 m/s².To find the magnitude of the rocket's acceleration, we can use the equation of motion: \(v^2 = u^2 + 2as\)
The above equation has v is the final velocity, u is the initial velocity, a is the acceleration, and s is the distance traveled. Rearranging the equation, we have \(a = (v^2 - u^2) / (2s)\).Given that the initial velocity (u) is 20.0 m/s, the final velocity (v) is 30.0 m/s, and the distance traveled (s) is 40.0 m, we can substitute these values into the equation:
a = (30.0² - 20.0²) / (2 * 40.0)
= (900 - 400) / 80
= 500 / 80
= 6.25 m/s².
Therefore, the magnitude of the rocket's acceleration is 6.25 m/s².
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How does the period affects the centripetal force?
Un bloque de 30.0 kg esta sobre un plano inclinado 28 grados con respecto a la horizontal, si el coeficiente de fricción cinética es 0.200, calcula la fuerza paralela al plano que se debe ejercer sobre el bloque para que suba con velocidad constante.
Responder:
229.17NExplicación:
Las fuerzas que actúan paralelas al plano son la fuerza de movimiento y la fuerza de fricción.
La fuerza de movimiento Fm = Wsinθ y la fuerza de fricción Ff = nR donde;
W es el peso del objeto = mg = 30.0 * 10
W = 300N
θ es el ángulo de inclinación = 28 °
n es el coeficiente de fricción = 0,20
R es la reacción normal = Wcosθ
La fuerza paralela al plano que se debe ejercer sobre el bloque para que se eleve con rapidez constante será la suma de la fuerza de movimiento y la fuerza frictioal (son las dos fuerzas que empujarán el cuerpo hacia arriba del plano)
Fuerza total requerida = Fm + Ff
Fuerza total requerida = Wsinθ + n (Wcosθ)
Fuerza total requerida = 300sin28 ° + 0.2 (300cos28 °)
Fuerza total requerida = 140,84 + 52,98
Fuerza total requerida = 229.17N
Por tanto, la fuerza paralela al plano que se debe ejercer sobre el bloque para que se eleve con rapidez constante es aproximadamente 229,17 N
Light and sound waves both share what characteristic?
A: they both exhibit the doppler effect
B: light and sound are both transverse waves
C: they both move fastest in water
D: light and sound both require medium in which to travel
Answer i know they both exhibit the doppler effect, so i believe it is this one.
Explanation:
Simplifying the given expressions below,which of the following will give a negative result?
A.-19 + 0
B.-8 (-12)
C.26 -4
D.-10 - (-15)
Answer:
a.-19
b.-20
c.22
d.5
Explanation:
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I AM TIMED !! 30 POINTS Which is the smallest possible particle of an element?
O molecule
O atom
O compound
O matter
Answer:
atoms
Explanation:
they are the smallest
A block of gold (density 19300 kg/m3), a block of concrete (density 2000 kg/m3), and a block of ice (density 920 kg/m3) are all submerged in the same fluid where all three blocks have the same volume. Which block experiences the greatest buoyant force?.
All three experience the same uboyant force.
What is buoyant force?
Upthrust, often known as buoyancy, is an upward force applied by a fluid against the weight of an object that is partially or completely submerged. The weight of the fluid on top causes pressure in a fluid column to rise with depth.
All three objects experience the same buoyant force because their volumes are equal the buoyant force on an object in a liquid depends on the volume of the submerged object, the density of the liquid, and the acceleration caused by gravity but not on the density of the object.
Hence, all will experience the same buoyant force.
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If the diameter of a youth softball is 3. 5 inches and the diameter of an adult softball is 3. 8 inches, what is the approximate difference in their volumes? Use 3. 14 for Pi. Round to the nearest tenth of a cubic inch. Recall the formula Sphere Volume = four-thirds pi r cubed. 6. 3 cubic inches 51. 1 cubic inches 67. 0 cubic inches 409. 2 cubic inches.
The approximate difference in volumes of the youth and adult softballs is 6.3 cubic inches.
To find the volumes of the two spheres, we need to use the formula for sphere volume, which is V = (4/3)πr^3. We are given the diameters of the youth and adult softballs, so we can find their radii by dividing by 2. Thus, the radius of the youth softball is 1.75 inches, and the radius of the adult softball is 1.9 inches.
Plugging these values into the formula, we get V(youth) ≈ 22.8 cubic inches and V(adult) ≈ 29.1 cubic inches. The difference in volumes is then V(adult) - V(youth) ≈ 6.3 cubic inches, which is our final answer rounded to the nearest tenth. Therefore, the approximate difference in volumes of the youth and adult softballs is 6.3 cubic inches.
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An object with height 4.00 mm is placed 28.0 cm to the left of a converging lens that has focal length 8.40 cm. A second lens is placed 8.00 cm to the right of the converging lens.
a. What is the focal length of the second lens if the final image is inverted relative to the 4.00-mm-tall object and has height 5.60 mm?
b. What is the distance between the original object and the final image?
The focal length of the second lens is -17.7 cm.
The distance between the original object and the final image is 2.56 cm to the left of the first lens.
What is the distance between the original object and the final image?To find the focal length of the second lens, we can use the thin lens equation:
1/f = 1/do + 1/di
where f is the focal length of the lens, do is the object distance, and di is the image distance.
For the first lens, we have:
1/f1 = 1/do + 1/di1
where f1 = 8.40 cm, do = -28.0 cm (since the object is to the left of the lens), and di1 is the image distance produced by the first lens.
Using the thin lens equation, we can solve for di1:
1/8.40 = 1/-28.0 + 1/di1
di1 = 11.76 cm
The image produced by the first lens is located 11.76 cm to the right of the first lens.
Now, we can use the image produced by the first lens as the object for the second lens:
do2 = di1 = 11.76 cm
We also know that the final image height is 5.60 mm and is inverted relative to the object, so the image distance produced by the second lens, di2, must be negative.
Using the thin lens equation again, we can solve for the focal length of the second lens, f2:
1/f2 = 1/do2 + 1/di2
where do2 = 11.76 cm and di2 = -? (to be determined).
We can solve for di2:
1/f2 = 1/11.76 + 1/di2
di2 = -6.08 cm
Now we can solve for f2:
1/f2 = 1/11.76 - 1/6.08
f2 = -17.7 cm
Therefore, the focal length of the second lens is -17.7 cm (negative because it is a converging lens, as required to produce an inverted image).
what is the distance between the original object and the final image?The distance between the original object and the final image can be found by adding the object distance for the first lens, the image distance for the first lens, the distance between the two lenses (8.00 cm), the object distance for the second lens, and the image distance for the second lens:
dtotal = do1 + di1 + d12 + do2 + di2
were d12 = 8.00 cm
Substituting the values we found earlier, we get:
dtotal = -28.0 + 11.76 + 8.00 + 11.76 - 6.08
dtotal = -2.56 cm
Therefore, the distance between the original object and the final image is 2.56 cm to the left of the first lens.
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The linear speed of a rotating wheel of radius 2 feet is 200f(t)/(m)in. What is the angular speed of the wheel in radians per minute? Round your answer to two decimal places. i
The angular speed of the wheel is **100π** radians per minute.
The linear speed of a rotating wheel is the distance traveled by a point on the circumference of the wheel per unit time. In this case, the linear speed is given as 200f(t)/(m)in, where f(t) represents an arbitrary function of time and m represents an arbitrary unit of measurement.
To find the angular speed of the wheel, we need to convert the linear speed into angular speed. Angular speed is defined as the rate at which an object rotates or travels around a circular path. It is measured in radians per unit time.
To convert the linear speed into angular speed, we need to relate the linear speed to the circumference and radius of the wheel. The circumference of a circle is given by 2π times the radius. In this case, the radius of the wheel is given as 2 feet.
Since the linear speed is the distance traveled per unit time, we can calculate the distance traveled in one minute by multiplying the linear speed by 60. Dividing this distance by the circumference of the wheel gives us the number of revolutions per minute. To convert this into radians per minute, we multiply the number of revolutions by 2π.
In summary, to calculate the angular speed of the wheel, we take the given linear speed and convert it into the number of revolutions per minute. We then multiply this value by 2π to obtain the angular speed in radians per minute.
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acceleration can occur when a car is moving at a constant speed. what must cause this acceleration?
Is a structure stable when force is applied in a certain direction?
Answer:
It can be, but no, mostly it won't be, and it will fall.
Explanation:
When you put force on a structure it will most likely fall unless, it's a big statue.
If the force acting on a cart doubles, what happens to the carts acceleration?
Answer:
If the force on a cart doubles, the acceleration of the cart doubles.
Explanation:
For this problem, we need to consider the following equation:
Force = Mass x Acceleration
We can reasonably assume that the cart will have constant mass in the given force system. With this assumption we can say the following relationship:
Force is directly proportional to Acceleration within the system.
Given that our force on the cart is doubled, then our acceleration of the cart must also be doubled. You can mathematically express this as follows:
F = MA
2F = M * 2A
Hence, if force doubles, the acceleration doubles.
Cheers.
Which has more Inertia?
A. Large Truck
B. Motorbike
C. Small car
D. Bicycle
What is the level of variable input where the Law of Diminishing Marginal Physical Product sets in?
The Law of Diminishing Marginal Physical Product sets in when the level of variable input increases to a point where each additional unit of input leads to a smaller increase in output. This occurs due to limited resources, inefficiencies, and diminishing returns.
The Law of Diminishing Marginal Physical Product states that as more units of a variable input are added to a fixed input, holding other inputs constant, the marginal physical product of the variable input will eventually decrease. In simpler terms, it means that after a certain point, adding more of a variable input will result in smaller increases in output.
This phenomenon occurs due to several factors. Firstly, as more units of the variable input are employed, the fixed input may become a constraint, limiting the potential increase in output. Additionally, inefficiencies and diminishing returns come into play. As more of the variable input is added, the efficiency of utilizing each additional unit may decrease, leading to smaller productivity gains.
The exact point at which the Law of Diminishing Marginal Physical Product sets in depends on various factors such as the nature of the production process, the quality of inputs, and technological factors. It is crucial for producers to understand this concept as it helps them optimize their production decisions and resource allocation, ensuring efficiency and avoiding diminishing returns.
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mass does not vary from place to place why?
Answer:
It is always constant unlike weight
You shine a LASER from the air into water. What happens to light?
A. It bends away from the normal
B. It bends towards the normal
C. It slows down
D. It travels in a straight line
E. It speeds up
Two answers are correct.
5. What is one difference between landslides and mudflowes?
A. Mudflows are caused by gravity.
B. Landslides can occur on gental slopes.
C. Mudflows can occur on gentle slopes.
D. Landslides occur suddenly.
The difference between landslides and mudflows is mudflows are caused by gravity. The correct option is option A.
LandslidesLandslides are caused by disturbances in the natural stability of a slope. A landslide is defined as the movement of a mass of rock, debris, or earth down a slope.
The impact of a landslide can be extensive, including loss of life, destruction of infrastructure, damage to land and loss of natural resources. Landslide material can also block rivers and increase the risk of floods.
MudflowsIt is a form of mass wasting involving fast moving flow of debris and dirt that has become liquefied by the addition of water. A river of liquid and flowing mud on the surfaces of normally dry land areas, as when earth is carried by a current of water.
They can happen after heavy rains, droughts, earthquakes or volcanic eruptions.
They are both examples of natural disaster.
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How much work is done by an applied force to lift a 15 Newton block 3.0 meters vertically at a constant speed?5 J4500 J4 J45 J
The work done is 45 J.
Given data:
• The applied force is F=15 N.
,• The distance traveled is d=3.0 m.
The work done can be calculated as,
\(\begin{gathered} W=Fd \\ W=(15)(3) \\ W=45\text{ J} \end{gathered}\)Thus, the work done by the force is 45 J.
An x-ray tube is an evacuated glass tube that produces electrons at one end and then accelerates them to very high speeds by the time they reach the other end. The acceleration is accomplished using an electric field. The high-speed electrons hit a metal target at the other end, and the violence of the collision converts their kinetic energy into high-energy light rays, commonly known as x-rays.
A. through what potential difference should electrons be accelerated so that their speed is 2.1 % of the speed of light when they hit the target?
B. What potential difference would be needed to give protons the same kinetic energy as the electrons?
C. What speed would this potential difference give to protons?
D. Express the speed calculated in Part C as a percentage of the speed of light.
A) Electrons should be accelerated through a potential difference of 51.6 kV
B) 117.3 MV would be needed to give protons the same kinetic energy as the electrons. C)117.3 MV would give protons a speed of 0.999 times speed of light. D)v/c x 100% ≈ 99.9%
What is kinetic energy?Energy an object has because of its motion is known as kinetic energy.
A.) Kinetic energy of an electron accelerated through a potential difference of V volts is : KE = eV
KE = (γ - 1)mc²
γ is Lorentz factor, m is rest mass of the electron, and c is speed of light.
eV = (γ - 1)mc²
V = (γ - 1)mc² / e
V = (1.021 - 1) x 9.11 x 10⁻³¹ kg x (3.00 x 10⁸ m/s)² / (1.60 x 10⁻¹⁹ C)
V ≈ 51.6 kV
Therefore, the electrons should be accelerated through a potential difference of approximately 51.6 kV to reach a speed of 2.1% of the speed of light when they hit the target.
B.) KE = eV
e is charge on the proton
(γp - 1)mpc² = (γe - 1)mec²
γp is Lorentz factor of the proton, mp is rest mass of the proton, and me is rest mass of the electron.
V = [(γp - 1)mpc² - (γe - 1)mec²] / e
V = [(1 - v²/c²\()^{(-1/2)\) - 1] x 1.67 x 10⁻²⁷ kg x (3.00 x 10⁸ m/s)² / (1.60 x 10⁻¹⁹ C)
[(1 - v²/c²\()^{(-1/2)\) - 1] x 1.67 x 10⁻²⁷ kg x (3.00 x 10⁸ m/s)² / (1.60 x 10⁻¹⁹ C) = 51.6 x 10³ V
(1 - v²/c²\()^{(-1/2)\) - 1 = 3.07 x 10⁻¹¹
(1 - v²/c²\()^{(-1/2)\) = 1 + 3.07 x 10⁻¹¹
1 - v²/c² = (1 + 3.07 x 10⁻¹¹)⁻²
v = c x √(1 - (1 + 3.07 x 10⁻¹¹)⁻²
V = [(1 - (1 + 3.07 x 10⁻¹¹\()^{(-1)\)) x 1.67 x 10⁻²⁷kg x (3.00 x 10⁸ m/s)²] / (1.60 x 10⁻¹⁹ C)
V ≈ 117.3 MV
Therefore, a potential difference of approximately 117.3 MV would be needed to give protons the same kinetic energy as the electrons.
C. γp = V / (mc²/e)
= 117.3 x 10⁶ V / [(1.67 x 10⁻²⁷ kg) x (3.00 x 10⁸ m/s)² / (1.60 x 10⁻¹⁹ C)]
γp ≈ 1.85 x 10⁸
(1 - v²/c²\()^{(-1/2)\) = 1.85 x 10⁸
v = c x √(1 - 1/(1.85 x 10⁸)²)
v ≈ 0.999c
Therefore, the potential difference of 117.3 MV would give protons a speed of approximately 0.999 times the speed of light.
D. Expressing the speed as a percentage of the speed of light, we get: v/c x 100% ≈ 99.9%
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Parts of the mixer become hot because some of the electrical energy is changed into
Parts of the mixer become hot because some of the electrical energy is converted into heat energy.
When electrical energy flows through a wire, it encounters resistance, which causes the wire to heat up. In a mixer, the electric motor converts electrical energy into mechanical energy to rotate the blades, but some of the electrical energy is lost as heat due to resistance in the motor's winding and other electrical components. This heat energy can accumulate in the mixer's parts and cause them to become hot. In many electrical devices, heat is an undesirable byproduct of energy conversion and can lead to reduced efficiency, damage, or safety hazards.
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--The complete Question is, Fill in the blanks. " Parts of the mixer become hot because some of the electrical energy is changed into____"--
What are the properties of different types of electromagnetic waves?
Answer:
1. All electromagnetic waves travelS at 3×10⁸m/s in vacuum
2.They are transverse in nature.
3.they can travel through vacuum.( doesn't require any materials for their transmission.
4.They under go phenomena of diffraction,reflection, refraction, interference and polarization.
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Se lanza una piedra de 3.00 N verticalmente hacia arriba desde el suelo. Se observa que, cuando está 15.0 m sobre el suelo, viaja a 25.0 m/s hacia arriba. Use el teorema trabajo-energía para determinar a) su rapidez en el momento de ser lanzada. b) su altura máxima
Answer:
(a). The speed at the moment of being thrown is 30.41 m/s.
(b). The maximum height is 47.18 m.
Explanation:
Given that,
Weight of stone = 3.00 N
Height = 15 m
Speed = 25.0 m/s
(a). We need to calculate the speed at the moment of being thrown
Using work energy theorem
\(W=\dfrac{1}{2}m(v_{2}^2-v_{1}^2)\)
\(-mg\times d=\dfrac{1}{2}m(v_{2}^2-v_{1}^2)\)
Put the value into the formula
\(-9.8\times15=\dfrac{1}{2}\times(v_{2}^2-v_{1}^2)\)
\(-2\times9.8\times15=25^2-v_{1}^2\)
\(-v_{1}^2=-300-25^2\)
\(v_{1}=\sqrt{925}\)
\(v_{1}=30.41\ m/s\)
(b). We need to calculate the maximum height
Using work energy theorem
\(\(W=\dfrac{1}{2}mv_{2}^2-\dfrac{1}{2}mv_{1}^2\)
\(mg\times d=\dfrac{1}{2}mv_{2}^2-\dfrac{1}{2}mv_{1}^2\)
Here, \(\dfrac{1}{2}mv_{2}^2\)=0
\(-(mg)\times d=\dfrac{1}{2}mv_{1}^2\)
\(d=\dfrac{v_{1}^2}{2g}\)
Put the value into the formula
\(d=\dfrac{30.41^2}{2\times9.8}\)
\(d=47.18\ m\)
Hence, (a). The speed at the moment of being thrown is 30.41 m/s.
(b). The maximum height is 47.18 m.
you asked to find the area of a room that measures 24.5 meters by 21 meters. How many significant digits should the answer have?
Answer:
A= l*w
Explanation:
When performing multiplication or division, the result should have the same number of significant digits as the measurement with the fewest significant digits.
In this case, the measurements are:
- Length = 24.5 meters (3 significant digits)
- Width = 21 meters (2 significant digits)
When multiplying these measurements to find the area, the answer should have the same number of significant digits as the measurement with the fewest significant digits, which is 2 significant digits in the width.
So, the area calculation and the final answer should have 2 significant digits.
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a matieral through which charges can flow through easily is known as what?
Answer:
the answer would be an electrical conductor
Please select the word from the list that best fits the definition
Is equal to mass multiplied by velocity
Answer:
Hi... Your answer is impulse