This is a sign of a chemical reaction that involves the production of bubbles or fizzing

Answer:

a) high pressure

that is the answer i got, but wait for a few more answers before you write the answer

Answer:

The empirical formula is the simplest form;

Given:

Oxygen O at 94.1% and

H at 5.9%

Assume 100grams.

94% = 0.941 x 100gm. = 94.1 gm x 1mole/16gm. = 5.88 moles of O

5.9% = 0.059 x 100gm. = 5.9gm. X 1moleH/1.002gm. = 5.88 moles of H

There is one mole of O for each mole of H so the empirical formula is \(O_1H_1\)

and written as OH.

Explanation:

\(given \: that \: oxygen \: by \: 94.1\% (.941)\\ hydrogen \: by5.9\%(.059) \\ in \: 100gram \: \\ oxygen = 100 g\times .941 = 94.1 \times \frac{1(mol)}{16g} \\ = 5.88moles \: of \: oxygen \\ in \: hydrogen \: = .059\times 100 = 5.9 \times \frac{1mol}{1.002gram} \\ = 5.88mole \: of \: hydrogen \\ \: so \: here \: \: both \: oxygen \: andhydrogen = 5.88 \\their \: ratio = 1 \: 1 \\ so \: emparical \: formula = oh \\ thank \: you\)

There are 0.017 mm volume  hydrogen are formed at 715 mm hg and 19.0 deg c if 12.8 g of al react

The relationship between an object's mass and volume seems to be straightforward. The object's mass rises directly proportionately to its volume.

The given reaction is:

2 Al + 6 HCl → 2 alcl3 + 3 h2

It can be seen that, 3 mol of hydrogen is formed during the reaction.

Number of moles of hydrogen = 3

Mass = 12.8 g

d = 715 mmHg

Volume of hydrogen can be calculated as:

Density = mass /volume

Volume = mass / density

Put the values of given data in above expression.

Volume = 12.8 g  / 715 mm hg

Volume = 0.017 mm

Thus, volume of the hydrogen will be 0.017 mm

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Considering the structure of the atom, neutrons and protons are the two subatomic particles found in an element's nucleus.

All atoms are made up of:

In summary, protons and neutrons are part of their nucleus and electrons revolve around them. Protons are positively charged, neutrons are neutrally charged, and electrons are negatively charged.

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The same fertilizer should be applied to all types of soil, which is false as different soils have different nutrient compositions and physical properties and therefore require different fertilizers to support plant growth.

Sandy soils tend to be low in nutrients and require fertilizers with high nitrogen content, while clay soils retain more nutrients and may require fertilizers with less nitrogen and more phosphorus and potassium. Additionally, different plants have different nutrient requirements, so the type of fertilizer needed will also depend on the crop being grown. Therefore, it is important to test the soil and determine its nutrient needs before applying any fertilizer to ensure the best possible growth and yields.

Hence, the same fertilizer should be applied to all types of soil, which is false as different soils have different nutrient compositions and physical properties and therefore require different fertilizers to support plant growth.

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Answer:

I think it is iron conducts electricity and heat

Answer:

C. Iron combines with oxygen to form rust.

Explanation:

The correct answer is "C" because it refers to the ability to rust, a chemical property, because rusting is a chemical change.

Answer choice "A" is incorrect because it refers to malleability, the ability to be flattened or pressed into sheets, a physical property. After being flattened, the iron would have gone through a physical change, not chemical.

Answer choice "B" is incorrect because it refers to conductivity, the ability to conduct electricity and heat, a physical property. The iron does not experience a chemical change while conducting.

Answer choice "D" is incorrect because it refers to ductility, the ability to be made into wire, a physical property. The iron is not going through a chemical change as wire.

Granite and slate could be weathered in separate locations. Then transported and deposited in the same location. Mineral elements would hold the grains together.

A very light-colored igneous rock, granite. Large and visible to unassisted eyes, its grains are noticeable. Feldspar, silica, and quartz are the primary components of granite, with trace amounts of mica and amphiboles.

In fact, granite is not always found in one hue and may also be found in white, grey, or pink. If we talk about the light colour of granite, it is primarily owing to the significant amount of silica present in it. However, in most cases, the light colour results from the high silica concentration, which makes it extremely transparent and light.

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Answer:

everything can be found in the picture

Answer:

Explanation:

Chemical equation

1) Mixtures involves substances that are mixed together.

2) Colloids , suspensions and solutions are types of mixtures.

We know that the term mixture can be used to describe any two substances that are not chemically combined together. In other words, the term mixture has to do with the putting together of substances that would not lead to any change in the individual properties of the substances that have been mixed together. Two common examples of mixtures are blood and air.

There are various types of mixtures that we have and these include;

Solutions: A solution is a mixture because there is no interaction that is going on chemically between the solute and the solvent.

Colloid: A colloid is a kind of mixture that is made up solutes that can still be seen with the optical eye. That is, the solutes are still large enough

Suspension: A suspension is a kind of mixture in which a solute is scattered in the solvent.

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On the basis of classification, electrolytic cells use non-spontaneous reactions which require an external power source in order to proceed.

On the other end, galvanic cells are spontaneous reaction, meaning it occurs with no outside intervention

A chemical change or reaction simply refers to a change which is not easily reversed and in which no new substance is formed.

So therefore, On the basis of classification, electrolytic cells use non-spontaneous reactions which require an external power source in order to proceed.

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According to the research, the correct option is B. They increase the OH- concentration in solution is a property of all bases.

It is the substance that has alkalinity that, when in solution, increases the concentration of hydroxyl ions (OH-) and establishes combinations with acids for the development of salts.

They are soluble in water and usually have a bitter taste and by providing hydroxyl ions to the medium, they are capable of neutralizing acids.

Therefore, we can conclude that according to the research, the correct option is B. They increase the OH- concentration in solution is a property of all bases.

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To combine ions to form ionic compounds, we need the combine in such a way that it gets neutral charge.

We can combine each anion with each cation to get the 4 compounds we need.

To combine SO₄²⁻ with Pb⁴⁺ we first find the Least Common Multiple of their charges, 2 and 4.

They have the factor 2 in common, so the LCM is 4. This is the final charge of each that will cancel out.

To get 4+, we only need 1 Pb⁴⁺.

To get 4-, we need 2 SO₄²⁻.

So, the formula is:

Pb(SO₄)₂

To combine SO₄²⁻ with NH₄⁺ is easier because one of them has single charge. In this case, we can simply pick one of the multiple charge ion and the same amount that will cancel its charge of the single charged one.

So, we picke 1 SO₄²⁻, ending with 2-.

And we picke 2 NH₄⁺, ending with 2+.

The formula:

(NH₄)₂SO₄

To combine C₂H₃O₂⁻ with Pb⁴⁺ we do the same, because the anion is single charged.

Pick 1 Pb⁴⁺, ending with 4+.

Pick 4 C₂H₃O₂⁻, ending with 4-.

The formula:

Pb(C₂H₃O₂)₄

To combine C₂H₃O₂⁻ with NH₄⁺, both have same charge, so we just need one of each and their charges will cancel out.

The formula:

NH₄C₂H₃O₂

So, the formulas are:

Pb(SO₄)₂

(NH₄)₂SO₄

Pb(C₂H₃O₂)₄

NH₄C₂H₃O₂

Answer:

Explanation:yo what is you talkin about

We know that evaporation is a process that occurs in the environment and in this the liquid or water turns into vapour. So after the rain as the water drains up because of the water is absorbed by the ground and it get vaporise by the sunlight.

Yakutsk  is a place were it it almost cold through out the year. the warm season or the summer lasts only for four months. Precipitation or rainy season lasts around five months, even though it  rains they have drier seasons around seven months. precipitation occurs in a mixed way that is there will be rainfall, snowfall and a mix of both.

the moisture level will be high and it creates a dryness.

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Since the samples are all at room temperature, the substance which is most likely the most dense is: D. silver.

Density can be defined as a ratio of mass to the volume of a physical substance such as chlorine, oxygen, bromine, silver, etc.

Mathematically, the density of a physical substance can be calculated by using this formula:

D = M/V

Where:

At room temperature, the density of the given physical substances in an ascending order are as follows:

In this context, we can reasonably and logically deduce that silver is the most dense among the given physical substances.

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The pH of a 0.150 M piperidine solution (C5H10NH) with a Kb of 1.3x10^-3 is 11.72. This indicates that the solution is basic.

To calculate the pH of a 0.150 M piperidine (C5H10NH) solution with Kb = 1.3 x 10^-3, we'll first determine the pOH and then find the pH. Piperidine is a weak base and will undergo an equilibrium reaction with water:
C5H10NH + H2O ↔ C5H10NH2+ + OH-
We can use the Kb expression:
Kb = [C5H10NH2+][OH-] / [C5H10NH]
Since the initial concentration of piperidine is 0.150 M, we'll assume x mol/L of it reacts to form C5H10NH2+ and OH- ions. The equilibrium concentrations will be:
[C5H10NH] = 0.150 - x
[C5H10NH2+] = x
[OH-] = x
Now, substitute these values into the Kb expression:
1.3 x 10^-3 = (x)(x) / (0.150 - x)
Solve for x to find the concentration of OH- ions:
x ≈ 0.0053 M
Now, calculate the pOH:
pOH = -log10[OH-] = -log10(0.0053) ≈ 2.28
Finally, find the pH using the relationship:
pH + pOH = 14
pH = 14 - 2.28 ≈ 11.72
So, the pH of the 0.150 M piperidine solution is approximately 11.72.

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The reaction becomes non-spontaneous at temperatures above 1513 K. The standard free energy change for the given reaction can be calculated using the formula: ΔG° = ΣnΔGf°(products) - ΣnΔGf°(reactants)

Where ΔGf° is the standard free energy of formation of the species and n is the stoichiometric coefficient.

ΔGf°(S) = 0 kJ/mol (since elemental sulfur is in its standard state)

ΔGf°(H2O) = -237.2 kJ/mol

ΔGf°(H2S) = -33.6 kJ/mol

ΔGf°(SO2) = -300.4 kJ/mol

ΔG° = (3 x 0) + (2 x (-237.2)) + (2 x (-33.6)) - (-300.4)

ΔG° = -556.4 kJ/mol

Since the calculated value of ΔG° is negative, the reaction is spontaneous at 25°C.

To estimate the temperature at which the reaction becomes non-spontaneous, we can use the equation:

ΔG = ΔH - TΔS

where ΔH is the enthalpy change of the reaction, ΔS is the entropy change of the reaction, and T is the temperature in Kelvin.

At the temperature where ΔG = 0, the reaction is at equilibrium, and the temperature is known as the equilibrium temperature.

Since the reaction becomes nonspontaneous at high temperatures, we can assume that the equilibrium temperature is greater than 25°C. Therefore, we can rearrange the equation to solve for T:

T = ΔH/ΔS

To calculate ΔH and ΔS, we can use standard enthalpies of formation and standard entropies from Appendix B:

ΔH° = ΣnΔHf°(products) - ΣnΔHf°(reactants)

ΔS° = ΣnS°(products) - ΣnS°(reactants)

ΔH° = (3 x 0) + (2 x (-241.8)) + (2 x (-20.1)) - (-296.8)

ΔH° = -482.2 kJ/mol

ΔS° = (3 x 31.8) + (2 x 69.9) + (2 x 205.0) - (2 x 248.1)

ΔS° = 318.4 J/K/mol

Now we can calculate the temperature at which the reaction becomes nonspontaneous:

T = ΔH/ΔS

T = (-482.2 x 10^3 J/mol) / (318.4 J/K/mol)

T = 1513 K

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Y-ray photons with a wavelength of 2.45×10-5 nm.  energy of photon is 8.11 × 10⁻¹²J.

given data is as follows :

wavelength = 2.45 × 10⁻⁵ nm

energy of photon is given by  the following formula , we get :

E = hf

where E = energy of photon

h = Planck constant = 6.63 × 10⁻³⁴ j.s

f = frequency

and frequency = c / λ

the formula will be:

E = h c / λ

c = speed of light = 3 × 10⁸ m/s

E = (6.63 × 10⁻³⁴ × 3 × 10⁸ ) / 2.45 × 10⁻⁵ × 10⁻⁹

E = 8.11 × 10⁻¹²J

Thus, Y-ray photons with a wavelength of 2.45×10-5 nm.  energy of photon is 8.11 × 10⁻¹²J.

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Answer:

Explanation:

The conditions before Storm 1 were likely more conducive to rainfall due to higher temperatures and higher levels of atmospheric moisture. Warmer temperatures allow the air to hold more moisture, which can lead to an increase in rainfall. Additionally, higher levels of atmospheric moisture increase the chances of rainfall, as the droplets of water vapor in the air are able to coalesce and form larger drops. These larger drops are more likely to reach the ground as rain.

Answer:

Protein.

Explanation:

Chains of polypeptides make up a protein molecule.

The combustion of 0.87 gallons of octane produces approximately 6.98 kg of CO₂ and 3.21 kg of H₂O.

To calculate the amount of CO₂ and H2O produced in the combustion of octane, we need to first convert the volume of octane from gallons to moles using its density and molar mass.

The density of octane is around 0.703 g/mL and its molar mass is 114.23 g/mol. One gallon is approximately 3.785 liters.

So, the amount of moles of octane in 0.87 gallons is:

moles of octane = (0.87 gallons) x (3.785 L/gallon) x (0.703 g/mL) / (114.23 g/mol) = 19.8 moles

The balanced chemical equation for the combustion of octane is:

2 C₈H₁₈ + 25 O₂ → 16 CO₂ + 18 H₂O

From this equation, we see that 2 moles of octane reacts with 25 moles of oxygen to produce 16 moles of CO₂ and 18 moles of H₂O.

Using stoichiometry, we can calculate the amount of CO₂ and H₂O produced from 19.8 moles of octane:

To convert moles to grams, we can use the molar mass of each compound:

Therefore, the combustion of 0.87 gallons of octane produces approximately 6.98 kg of CO₂ and 3.21 kg of H₂O.

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To convert the amide to the carboxylic acid, the following reagents can be used: \(LiAlH_4\) in dry ether or THF, Hydrogen gas \((H_2)\) and a metal catalyst such as palladium on carbon (Pd/C), Bromine (Br2) in acetic acid \((CH_3COOH)\).

It is important to note that each reagent may have different reaction conditions and selectivity.

To determine the missing reagents for the conversion of the amide to the carboxylic acid, you can use the following reagents: Reagent 1 is hydroxylamine \((NH_2OH)\), and an additional reagent is needed for this transformation, which is Reagent 2: an aqueous solution of a strong acid, such as hydrochloric acid \((HCl)\).

Step-by-step explanation:

By following these steps, the amide will be successfully converted to the carboxylic acid using the mentioned reagents.

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The product that donates electrons to the electron transport chain is NADH.

The electron transport chain (ETC) is a series of chemical reactions that occur within the inner mitochondrial membrane. It's a process that generates adenosine triphosphate (ATP), which is the energy currency of the cell. NADH is produced during the process of glycolysis and the citric acid cycle. It is a molecule that carries electrons and hydrogen ions (H+) to the electron transport chain in the mitochondria.

During the process of cellular respiration, NADH donates electrons to the electron transport chain, which facilitates the pumping of H+ ions across the inner mitochondrial membrane .This results in a concentration gradient of H+ ions, which powers the ATP synthase enzyme. This enzyme converts ADP (adenosine diphosphate) to ATP by adding a phosphate group. The donation of electrons by NADH to the electron transport chain is a crucial step in the process of cellular respiration.

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(i) The initial reaction rate is \(2*10^{-4} mol litre^{-1} sec^{-1.\)

(ii) The half-life period of the reaction is 1386 seconds.

(iii) The time taken to complete 75% of the reaction is approximately 2772 seconds.

We can use the first-order rate equation:

Rate = k[N2O5]

Where:

Rate is the reaction rate,

k is the rate constant,

[N2O5] is the concentration of N2O5.

Given:

Rate constant (k) = \(5*10^{-4} sec^{-1}\)

Initial concentration of N2O5 =\(0.4 mol litre^{-1}\)

(i) To find the initial reaction rate:

Substitute the given values into the rate equation:

Rate = k[N2O5]

Rate = \((5*10^{-4} sec^{-1})(0.4 mol litre^{-1})\)

Rate = \(2*10^{-4} mol litre^{-1} sec^{-1}\)

The initial reaction rate is \(2*10^{-4} mol litre^{-1} sec^{-1}\).

(ii) To find the half-life period:

The half-life of a first-order reaction is given by the equation:

t(1/2) = (0.693 / k)

Substitute the given value of k into the equation:

t(1/2) = \((0.693 / 5*10^{-4} sec^{-1})\)

t(1/2) = 1386 sec

The half-life period of this reaction is 1386 seconds.

(iii) To find the time taken to complete 75% of the reaction:

The time required to complete a certain percentage of a reaction can be found using the equation:

t = (ln(1 / (1 - x)) / k)

Where x is the fraction of the reaction completed (in this case, 75%).

Substitute the given values into the equation:

t =\((ln(1 / (1 - 0.75)) / 5*10^{-4} sec^{-1})\)

t = 2772 sec

The time taken to complete 75% of the reaction is approximately 2772 seconds.

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Answer: a coarse-grained, dark-colored, intrusive igneous rock. It is usually black or dark green in color and composed mainly of the minerals plagioclase and augite.

Explanation: I hope that helped. HAVE HOPE

A pH of 4 has a higher concentration of H+ ions compared to option B with a pH of 5. Therefore, option A is a stronger acid.

pH is a measure of the concentration of hydrogen ions (H+) in a solution. Acids are substances that can donate H+ ions, and the strength of an acid depends on the concentration of H+ ions in solution. The lower the pH, the higher the concentration of H+ ions, and the stronger the acid. In this case, option A with a pH of 4 has a higher concentration of H+ ions compared to option B with a pH of 5. Therefore, option A is a stronger acid because it has a greater ability to donate H+ ions in solution compared to option B.

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